List the coordinates coordinates of vertices of trapezoid ABCD after it has been rotated 90 Counterclockwise bout the origin and then reflected over the x-axis. A(-5,-3) B(-4,0),c(-2,0),D(O,-3)

List The Coordinates Coordinates Of Vertices Of Trapezoid ABCD After It Has Been Rotated 90 Counterclockwise

Answers

Answer 1

Answer:

The coordinates of the final image is;

[tex]A^{\prime\prime}(3,5),B^{\prime\prime}(0,4),C^{\prime}^{\prime}(0,2),D^{\prime}^{\prime}(3,0)[/tex]

Explanation:

From the question, the pre-image was been rotated 90 Counterclockwise bout the origin.

Which has a rule;

[tex](x,y)\rightarrow(-y,x)[/tex]

Applying the rule to the given points. we have;

[tex]\begin{gathered} A(-5,-3)\rightarrow A^{\prime}(3,-5) \\ B(-4,0)\rightarrow B^{\prime}(0,-4) \\ C(-2,0)\rightarrow C^{\prime}(0,-2) \\ D(0,-3)\rightarrow D^{\prime}(3,0) \end{gathered}[/tex]

Then the produced image was then reflected over the x-axis;

Reflection across the x-axis have the rule;

[tex](x,y)\rightarrow(x,-y)[/tex]

Applying the rule to the resulting image;

[tex]\begin{gathered} A^{\prime}(3,-5)\rightarrow A^{\prime^{}}^{\prime}(3,5) \\ B^{\prime}(0,-4)\rightarrow B^{\prime}^{\prime}(0,4) \\ C^{\prime}(0,-2)\rightarrow C^{\prime^{}}^{\prime}(0,2) \\ D^{\prime}(3,0)\rightarrow D^{\prime}^{\prime}(3,0) \end{gathered}[/tex]

Therefore, the coordinates of the final image is;

[tex]A^{\prime\prime}(3,5),B^{\prime\prime}(0,4),C^{\prime}^{\prime}(0,2),D^{\prime}^{\prime}(3,0)[/tex]


Related Questions

neeed double chedking on this

Answers

The area will be the area of the blue part minus the area of the white part:

9(8)-5(3)=72-15= 57 square centimeters

A store is having a 20% off sale on all merchandise if my buys one item and see if $13 what was the original price of a purchase

Answers

Since all merchandise has 20% off, so the original price is multiplied by 0.8 (80%).

Let's use the variable x to represent the original price. So we can write the following equation and solve it for x:

[tex]\begin{gathered} 0.8\cdot x=13 \\ x=\frac{13}{0.8} \\ x=16.25 \end{gathered}[/tex]

Therefore the original price is $16.25.

6. 5.6% of 283 is what number?7. 55% sign of 104 is what number?

Answers

To solve the exercise you can use a rule of three:

[tex]\begin{gathered} 283\rightarrow100\text{\%} \\ x\rightarrow5.6\text{\%} \end{gathered}[/tex][tex]\begin{gathered} x=\frac{5.6\text{\%}\cdot283}{100\text{\%}} \\ x=\frac{5.6\cdot283}{100} \\ x=\frac{1584.8}{100} \\ x=15.848 \end{gathered}[/tex]

Therefore, 5.6% of 283 is 15.848.

Zach puts $1000 into a savings account earning 5% compound interest for 5 years. How much
interest has Zach earned at the end of the the 5 years?
$_______
Do not enter the dollar sign as part of your answer

Answers

The amount of interest Zach earn in 5 years given the principal and interest rate compounded for 5 years is 276.3

What is the amount of interest Zach earned?

A = P(1 + r/n)^nt

Where,

A = principal + interestPrincipal, P = $1000Interest rate, r = 5% = 0.05Time, t = 5 yearsNumber of periods, n = 1

A = P(1 + r/n)^nt

= 1000(1 + 0.05/1) ^(1×5)

= 1000(1 + 0.05) ^5

= 1000(1.05)^5

= 1000(1.2762815625)

= 1,276.2815625

Approximately,

1,276.3

Hence,

A = principal + interest

1, 276.3 = 1000 + interest

1276.3 - 1000 = interest

Interest = 276.3

Therefore, the amount of interest earned in 5 years is 276.3

Read more on compound interest:

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Part B: select the box or boxes under the coordinate pairs the represent solutions for the system.

Answers

The given system of inequalities is

[tex]\begin{gathered} y>\frac{3}{2}x-2 \\ y\leq-3x-4 \end{gathered}[/tex]

The area of the solution is the area shaded by the 2 colors

Let us check the points

(-2, -5) it lies on the red dashed line

Since the line is dashed, then the points lie on it do not belong to the solution, then

(-2, -5) does not belong to the solution

(-2, -5) is not a solution

(-2, 2) it lies on the blue line

Since the line is solid, then the points that lie on it belong to the solution, then

(-2, 2) is a solution

(0, -4) it is out of the area of both colors, then

(0, -4) is not a solution

(-3, -1) it lies in the area of the common colors, then

(-3, -1) is a solution

(-1, 4) it is out the area of both colors, then

(-1, 4) is not a solution

(-20, 15) is in the area of the common colors, then

(-20, 15) is a solution

(15, 20) it is out the area of both colors, then

(15, 20) is not a solution

Then the solutions of the system are:

(-2, 2), (-3, -1), (-20, 15)

Simplify: (3x-8)+(4x-17)

Answers

Answer:

7x-25

Explanation:

Given the expression:

[tex]\mleft(3x-8\mright)+\mleft(4x-17\mright)[/tex]

First, we open the brackets

[tex]=3x-8+4x-17[/tex]

Next, we rearrange bringing like terms together.

[tex]\begin{gathered} =3x+4x-8-17 \\ =7x-25 \end{gathered}[/tex]

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.Find the side of a square whose diagonal is of the given measure.Given = ft.

Answers

see the figure below to better understand the problem

In the given square ABCD

Apply the Pythagorean Theoren in the right triangle BDC

[tex]\begin{gathered} D^2=a^2+a^2 \\ D^2=2a^2 \\ we\text{ have} \\ D=12\sqrt{10}\text{ ft} \end{gathered}[/tex]

Substitute given value

[tex]\begin{gathered} (12\sqrt{10})^2=2a^2 \\ 144(10)=2a^2 \\ 2a^2=1,440 \\ a^2=720 \\ a=\sqrt{720}\text{ ft} \end{gathered}[/tex]

Simplify

[tex]a=12\sqrt{5}\text{ ft}[/tex]

which equation , together with y=-1.5x+3 , makes a system with just on solution.y = -1.5x+6y = -1.5x2y = -3x+62y + 3x = 6y = -2x + 3

Answers

EXPLANATION

Given the equation y= -1.5x + 3

In order to get a system with just one solution, the viable options are those that allow both lines to intersect in just one point.

Those equations are:

y= -1.5x

y=-2x + 3

The system of equations y=-1.5x+3 and y=-1.5x+6 has no solution because subtracting both expressions give us the result 3=0

The system y=-1.5x+3 and 2y = -3x+6, or in the same way the system y=-1.5x+3 and 2y + 3x = 6 has no solution because they have the same expression.

Are the graphs of the equations parallel, perpendicular, or neither? y= 2x +6 and y= 1/2x +3

Answers

Given the equations:

[tex]\begin{gathered} y=2x+6 \\ y=\frac{1}{2}x+3 \end{gathered}[/tex]

The equation has the form of slope - intercept form which is like:

[tex]y=m\cdot x+b[/tex]

Where m is the slope and b is y- intercept

So,

The slope of the first equation = 2

The slope of the second equation = 1/2

The graphs of the equations are parallel when the slopes are equal

The graphs of the equations are perpendicular when the product of the slopes = -1

so,

the slopes are not equal

The product of the slopes = 2 * 1/2 = 1

So, the graphs of the equations are neither parallel nor perpendicular.

The sum of two consecutive integers is 17. Which equations could be used to find the twoconsecutive integers? Select all that are correct.A.X+X+1=17B.X+x=17C.2x=17D.2x+2=17E.X+X+2=17F.2x+1=17

Answers

hello

the answer to the question is option A

to solve a problem like this, let x represent the first number

x + (x + 1) = 17

x = first number

x + 1 = successive number

3, -9, 27, -81,..... common difference/ratiod = 3r = 9r = -3 d = 12

Answers

To find the common ratio we divide the terms by the previous one. In this case we have:

[tex]-\frac{9}{3}=-3[/tex][tex]\frac{27}{-9}=-3[/tex][tex]-\frac{81}{27}=-3[/tex]

Therefore, the common ratio is r=-3.

i need help simplifying 1/3(3n+9)

Answers

Answer:

n+3

Explanation:

Given the expression:

[tex]\frac{1}{3}(3n+9)[/tex]

To simplify, we first open the bracket.

[tex]=\frac{1}{3}(3n)+\frac{1}{3}(9)[/tex]

We can then divide common factors:

[tex]\begin{gathered} =\frac{3n}{3}+\frac{9}{3} \\ =n+3 \end{gathered}[/tex]

The simplified form is: n+3

If anyone to solve this problem it will be greatly appreciated and I will be sure to give the best possible rating

Answers

Step 1

Graph the points from the table and make a plot that can help determine the possible line of best fit.

Hence, the equation of the line of best fit with values to the nearest hundredths will be;

[tex]y=0.06x+2.57[/tex]

4) P(A) = 0.55 P(B) = 0.25 P(A and B) = ? *a.0.2b.0.21c.0.3d.0.1375

Answers

Since P (A and B) = P(A) · P(B)

Since P(A) = 0.55 and P(B) = 0.25, then

P(A and B) = 0.55 x 0.25

P(A and B) = 0.1375

The answer is d

Harold cut 18 1/2 inches off a rope that was 60 inches long. How is the length of the remaining rope written in decimals?

Answers

Substract 18 1/2 from 60 to determine the length of remaining rope.

[tex]\begin{gathered} 60-18\frac{1}{2}=60-\frac{37}{2} \\ =\frac{120-37}{2} \\ =\frac{83}{2} \\ =41.5 \end{gathered}[/tex]

So length of remaining rope is 41.5 inches.

Jessica borrowed $1,450 for three months at an annual rate of 8.75%under a single-payment plan. How much interest must she pay?a. $0.30b. $31.72c. $4,893.75d. $108.75

Answers

Given:

Principal amount (P)= $1450

Rate (R) = 8.75%

Time (T)= 3 months

The interest is given by the formula,

[tex]\begin{gathered} I=\frac{P\times R\times T}{100\times12} \\ =\frac{1450\times8.75\times3}{100\times12} \\ =31.71875 \end{gathered}[/tex]

Each table represents a proportional relationship. For each, find theconstant of proportionality, k, and write an equation that represents therelationship. Write k as a simplified proper or improper fraction and use thegiven variables.

Answers

**For the first table:

*We determine the value of k, as follows:

[tex]30=k(18)\Rightarrow k=\frac{5}{3}[/tex]

The equation that represents the table is:

[tex]f=\frac{5}{3}d[/tex]

**For the second table:

*We determine the value of k, as follows:

[tex]18=k(30)\Rightarrow k=\frac{3}{5}[/tex]

The equation that represents the table is:

[tex]d=\frac{3}{5}f[/tex]

Sketch the graphs of each of the following functions showing all steps on the same set of axe

Answers

Part D

we have the function

[tex]\begin{gathered} y=\frac{4}{-(x+1)}+3=\frac{4-3(x+1)}{-(x+1)}=\frac{4-3x-3}{-(x+1)}=\frac{1-3x}{-(x+1)}=\frac{3x-1}{x+1} \\ \\ y=\frac{3x-1}{x+1} \end{gathered}[/tex]

In this rational function

Remember that

The denominator cannot be equal to zero

so

The value of x cannot be equal to x=-1

At x=-1 there is a vertical asymptote

Find out a horizontal asymptote

Degree on Top is Equal to the Bottom

so

the horizontal asymptote is at y=3/1=3

Find out the intercepts

y-intercept (value of y when the value of x=0)

For x=0

[tex]y=\frac{3(0)-1}{0+1}=-1[/tex]

The y-intercept is (0,-1)

Find out the x-intercept (value of x when the value of y=0)

For y=0

[tex]\begin{gathered} 0=\frac{3x-1}{x+1} \\ \\ 3x-1=0 \\ 3x=1 \\ x=\frac{1}{3} \end{gathered}[/tex]

The x-intercept is (0.33,0)

With the given information

Graph the function

using a graphing tool

see the figure below

From a window 100ft above the ground in building A, the top and bottom of building B are sighted so that the angles are 70 degrees and 30 degrees respectively. Find the height of building B?

Answers

Given:-

From a window 100ft above the ground in building A, the top and bottom of building B are sighted so that the angles are 70 degrees and 30 degrees respectively.

To find:-

The height of building B.

So now, the image of the given data is,

So now we find the value of PS. so we get,

[tex]\begin{gathered} \tan \text{ 30=}\frac{100}{PS} \\ \frac{1}{\sqrt[]{3}}=\frac{100}{PS} \\ PS=100\sqrt[]{3} \end{gathered}[/tex]

So now we find the height of QS,

[tex]\begin{gathered} \tan \text{ 70=}\frac{QS}{PS} \\ 2.7474=\frac{QS}{100\sqrt[]{3}} \\ QS=100\sqrt[]{3}\times2.7474 \\ QS=475.84 \end{gathered}[/tex]

So the total height is,

[tex]100+475.84=575.84[/tex]

So the height of building B is 575.84

[the ending was select all that apply ] can somebody help me with this with an explanation on how to do it?

Answers

Answer: the goal is to isolate the variable so the answer is 12

Step-by-step explanation:

what is 19,593 in expanded form?

Answers

The extended form of the given number is:

[tex]10000+9000+500+90+3[/tex]

Kevin and Randy have a jar containing 67 coins all of which are either quarters or nickels. The total value of the coins in the jar $12.75 ... how many of each type of coin do they have?

Answers

Answer:

47quarters and 20 nickel

Explanation:

Let the number of quarters be x

Let the number of nickels be y

If there are 67 coins in the jar, then;

x + y = 67 ....1

1 quarter = 0.25x

1 nickel = 0.05y

If the total value of the coins in the jar is $12.75, then;

0.25x + 0.05y = 12.75 ....2

Multiply through by 100

25x + 5y = 1275 ....2

Solve 1 and 2 simultaneously

x + y = 67 ....1 * 25

25x + 5y = 1275 ....2 * 1

Using Elimination method

________________________

25x + 25y = 1,675

25x + 5y = 1275

Subtract

25y - 5y = 1675 - 1275

20y = 400

y = 400/20

y = 20

Substitute y = 20 into equation 1;

From 1; x + y = 67

x + 20 = 67

x = 67 - 20

x = 47

This means there are 47quarters and 20 nickel.

what is the slope - intercept form of a line that passes through points(2,12) and (4,17) ?

Answers

A line pass through points (2, 11) and (4, 17);

The slope-intercept form of a line is given as;

[tex]\begin{gathered} y=mx+c \\ \text{Where m = slope} \\ c=\text{ y-intercept} \\ \\ \text{But slope m=}\frac{y_2-y_1}{x_2-x_1} \\ \text{Where x}_1=2 \\ x_2=4 \\ y_1=11 \\ y_2=17 \\ m=\frac{17-11}{4-2}=\frac{6}{2} \\ m=3 \end{gathered}[/tex]

Also, for the y-intercept c;

[tex]\begin{gathered} \text{But when x=2, y=11} \\ \text{let's use this point to get the c} \\ 11=3(2)+c \\ c=11-6 \\ c=5 \\ \end{gathered}[/tex]

Thus, the slope intercept equation of the line is;

y = 3x + 5

help me with this question please

Answers

So,

From the graph, we can clearly state that:

In 2 mins, there were 0 calls.

In 3 mins, there was 1 call.

In 4 mins, there were 4 calls.

In 5 mins, there were 6 calls.

In 6 mins, there were 4 calls.

Then, the number of calls that were answered to in 6 mins or less were 0+1+4+6+4 = 15

it's late but I need help

Answers

Data:

X = weight of the puppy at thefirst visit

Find 5x3 + 2y2 - 9, where x = 4 and y = 2

Answers

[tex]\begin{gathered} 5x^3+2y^2\text{ - 9} \\ \text{where } \\ x\text{ = 4} \\ y\text{ = 2} \end{gathered}[/tex]

The equation can be solved when we substitute the value of x and y accordingly .

[tex]\begin{gathered} 5(4)^3+2(2)^2\text{ - 9} \\ 5\text{ }\times\text{ 64 + 2 }\times\text{ 4 - 9} \\ 320\text{ + 8 - 9} \\ =319 \end{gathered}[/tex]

Find the coordinates of the midpoint between (8, 1) and (0, - 9). F. (4, -5) G. (4, -4) H. (8, -5) J. (8, -8)

Answers

MidpointAnswer

(4, -4)

Explanation

In order to find the midpoint between two points we have to obtain the midpoint horizontally and vertically.

In this case, we have:

=O GRAPHINGFinding the next terms of an arithmetic sequence with integersThe first three terms of an arithmetic sequence are as follows.-5, -8, -11Find the next two terms of this sequence.5.-8.-11.008 OBx 6

Answers

Solution:

Given the first three terms of an arithmetic sequence as;

[tex]-5,-8,-11[/tex]

An arithmetic sequence is a sequence with a common difference d, The common difference is the difference between two consecutive terms. Where;

[tex]\begin{gathered} d=a_2-a_1 \\ \text{Where;} \\ a_2=\text{ second term;} \\ a_1=\text{first term} \end{gathered}[/tex]

Thus;

[tex]\begin{gathered} d=-8-(-5) \\ d=-8+5 \\ d=-3 \end{gathered}[/tex]

Also, the next term of the sequence can be known by adding the common difference to the previous term.

Hence, the next two terms are;

[tex]\begin{gathered} =-11+(-3) \\ =-11-3 \\ =-14 \\ \text{and } \\ =-14+(-3) \\ =-14-3 \\ =-17 \end{gathered}[/tex]

FINAL ANSWER:

[tex]-14,-17[/tex]

which point is located at (0,8)

Answers

The point (0, 8) simply means the x axis is 0 while the y axis is 8. The answer is C.

Runner A averages 5 miles per hour, and Runner B averages 6 miles per hour. At these rates, how much longer does it take Runner A than Runner B to run 15
miles?
1 hour
Shour
2.5 hours
1.5 hours
3 hours

Answers

If Runner A averages 5 miles per hour, and Runner B averages 6 miles per hour. At these rates, then it took 3 hours for runner A.

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

Given,

Runner A averages 5 miles per hour, and

Runner B averages 6 miles per hour.

The time required for A to complete 15 miles is

15/5=Time

3 hrs

Hence Runner A needs 3 hours to run 15 miles.

To learn more on Equation:

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