A student is taking a test in which items of type A are worth 8 points and items of type B are worth 12 points. It takes 3 min to complete each item of type A and 6 min to complete each item of type B. The total time allowed is 60 min and Anna answers exactly 16 questions. How many questions of each type did she complete? Assuming that all her answers were correct, what was her score? She completed questions of type A.

Answers

Answer 1

Type A questions are worth 8 points each.

Type B questions are worth 12 points each.

it takes 3 minutes to answer a Type A question

it takes 6 minutes to answer a Type B question.

total time allowed = 60 minutes

She answered a total of 16 questions.

let

number of question answer on type A = x

number of question answered on type B = y

Therefore,

3x + 6y = 60

x + y = 16

then,

[tex]\begin{gathered} 3x+6y=60 \\ x+y=16 \\ x=16-y \\ 3(16-y)+6y=60 \\ 48-3y+6y=60 \\ 3y=60-48 \\ 3y=12 \\ y=\frac{12}{3} \\ y=4 \\ x=16-4 \\ x=12 \end{gathered}[/tex]

She answered 12 questions on type A and 4 questions on type B.

If all her answer is correct her score can be computed below

[tex]undefined[/tex]


Related Questions

Can someone help me with this math problem I have like 20 more and I really need help

Answers

We can find the x-intercept when y=0 so replacing y for 0 we have

[tex]\begin{gathered} -5x+2(0)=10 \\ -5x=10 \\ x=\frac{10}{-5}=-2 \end{gathered}[/tex]

The x-intercept is (-2,0).

Now we are going to replace x for 0 to find the y-intercept

[tex]\begin{gathered} -5(0)+2y=10 \\ 2y=10 \\ y=\frac{10}{2}=5 \end{gathered}[/tex]

The y-intercept is (0,5).

For the graph of 4x -9y=12 we have that the x-intercept is (3,0) and the y-intercept is (0,-4/3)

Given cos = 0.9528, find .

Answers

Given:

[tex]\cos \theta=0.9528[/tex]

To find the value of θ,

[tex]\begin{gathered} \cos \theta=0.9528 \\ \theta=\cos ^{-1}(0.9528) \\ \theta=17.6739^{\circ} \end{gathered}[/tex]

If a || band e l f, what is the value of y?(x + 1)[(x-3°

Answers

y = x + 1 [ alternate exterior angles ]

Last year's freshman class at State University total 5,320 students. Of those 1,262 received a merit scholarship to help offset tuition costs. The amount a student received was N($3,450 , $480). if the cost of a full tuition was $4,050 last year , what percentage of students who received a merit scholarship did not receive enough to cover full tuition ? ( Round to nearest whole percent)Percentage of students ________%

Answers

Answer: We need to find the percentage of students that received a scholarship that did not cover their full tuition:

The number of students that received a scholarship was:

[tex]1262[/tex]

The amounts that students received were:

[tex]\begin{gathered} 3,450\text{ Dollars} \\ 480\text{ Dollars} \end{gathered}[/tex]

But the actual tuition cost was:

[tex]4050\text{ Dollars}[/tex]

Therefore, none of the students that received scholarship had received enough to cover the full tuition, because:

[tex]\begin{gathered} 4050>3450 \\ 4050\text{ }>480 \end{gathered}[/tex]

So, 100% of the students that received scholarships, did not receive enough to cover their tuition.

А.
U. 3y2 +y-1
X-8
0.X-8+
G. X-3
+2x+1
D. 2k2+8k+15+
24
1. 3k +16 +-14
R X-1
Y. x2-3x +4 +
E. X+4
M. x2-8x +24 +-68
X+3
T. y2 – 8y +12
1 2 3
4 5
6 7
9
10
11
12
13 14

Answers

SOLUTION

After solving the numbers in front of the letters, we have:

A=4 ,B=14, C=2, D=6, E=1, F=15, G=17, H=27, I=33, J=3, K=40,L=22, M=5

N=19, O=11, P=16, Q=24, R=0, S=12, T=32, U=75, V=18, W=7, X=20, Y=35, Z=36

Now, we will match these numbers to the letters to form words.

4,16,0,33,22: APRIL

12,27,11,7,1,0,12: SHOWERS

5,4,35: MAY

15,22,11,7,1,0,12: FLOWERS

4,19,6: AND

1,18,1,0,35,32,27,33,19,17,12: EVERYTHING

33,19: IN

Jeremiah can drink 64 fluid ounces of coffee in 4 days. How many Quarts of coffee can he drink in 1 hour.help explain please:)

Answers

1 quart = 32 fluid ounces

Therefore, 64 fluid ounces = 2 quarts

Jeremiah can drink these 2 quarts in 4 days meaning he drinks

[tex]2\frac{\text{quarts}}{4\text{days }}=0.5\frac{\text{quarts}}{\text{days}}[/tex]

Now, there are 24 hours in a day; therefore, the number of quarts Jeremiah drinks in 1 hour is

[tex]\frac{0.5\text{quarts}}{24\text{hours}}=\frac{1}{48}\frac{\text{quarts}}{\text{days}}[/tex]

or in decimal form, this is 0.021 quarts in an hour.

In ∆QRS, q =370 cm, r =910 cm and

Answers

using cosine rule

[tex]\begin{gathered} s^2=r^2+q^2-2rq\cos S \\ s^2=910^2+370^2-2\times910\times370\cos 31 \\ s^2=828100+136900-336700\times0.8571673007 \\ s^2=965000-288608.230146 \\ s^2=676391.769854 \\ s=\sqrt[]{676391.769854} \\ s=822.430404262 \\ s=822\operatorname{cm} \end{gathered}[/tex]

Ivan took out a loan for 6700 that charges an annual rate of 9.5% compounded quarterly. Answer each part.

Answers

We will have the following:

a) The amount after one year will be:

[tex]\begin{gathered} A=6700(1+\frac{0.095}{4})^{4\ast1}\Rightarrow A=7359.53647... \\ \\ \Rightarrow A\approx7359.54 \end{gathered}[/tex]

So, the amount after 1 year will be approximately $7359.54.

b) The effective annual interest rate will be:

[tex]eair=(1+\frac{0.095}{4})^4-1\Rightarrow eair=0.0984382791...[/tex]

So, the effective annual interest rate will be approximately 9.84%.

Bob bought a $800 TV on sale for $650. What is the percent he saved?

Answers

Answer:

18.75%

Step-by-step explanation:

Since you want to know what percent he saved, first you have to figure out how much he saved.

800 - 650 = 150

Then to find the percent, find how much 150 is of 800.

[tex]\frac{150}{800} = 0.1875[/tex]

Since we're finding a percentage, multiply by a 100.

0.1875 × 100 = 18.75%

If it said to round, the answer would be 19%, but it doesn't, so keep it at 18.75%.

1 Lola collects blood donations at a clinic. 7/16 of the donations are of Type 0, 3/8 are of Type A, and 1/16 are Type AB. The remaining are Type B. What part of the blood donations are Type B?

Answers

Answer:

n=1/8

Explanation:

From the diagram, if we sum up all the parts, we have:

[tex]\frac{7}{16}+\frac{3}{8}+\frac{1}{16}+n=1[/tex]

We solve the equation above for n.

The lowest common multiple of 16 and 8 = 16

Therefore:

[tex]\frac{7+6+1}{16}+n=1[/tex]

Therefore:

[tex]\begin{gathered} \frac{14}{16}+n=1 \\ n=1-\frac{14}{16} \\ n=\frac{16-14}{16} \\ n=\frac{2}{16} \\ n=\frac{1}{8} \end{gathered}[/tex]

The value of n is 1/8.

solve each equation for y=. Without graphing, classify each system as having one solution, no solution, or infinitely many solutions.

x+y=3
y=2x-3

Answers

Answer:

The answer would be y=3, and there is only one solution.

Step-by-step explanation:

In the first expression, x+y=3, we can rearrange it to get it in terms of x so we can substitute it for x in the second expression.

x+y=3

Subtract y from both sides: x=-y+3

Substitute x=-y+3 into the second expression: y=2(-y+3)+3

Distribute the 2: y=-2y+6+3

Simplify the right side: y=-2y+9

Add 2y to both sides: 3y=9

Divide by 3: y=3

Since there is a single y coordinate, that means that there is only one solution.

Round 6,752 to the nearest ten and nearest hundred.

Answers

Given the number:

6752

i) Round to the nearest ten:

To round to nearest ten means to rou

What is the solution of 5|2x + 1| – 3 ≤ 7?

Answers

Given

5|2x + 1| – 3 ≤ 7

Find

Solve the inequality

Explanation

[tex]\begin{gathered} 5|2x+1|-3\leq7 \\ 5|2x+1|\leq7+3 \\ 5\lvert2x+1\rvert\leq10 \\ |2x+1|\leq\frac{10}{5} \\ \\ |2x+1|\leq2 \end{gathered}[/tex]

we know that

[tex]2x+1\leq2\text{ }and\text{ }2x+1>-2[/tex]

so ,

[tex]\begin{gathered} 2x+1\leq2 \\ 2x\leq1 \\ x\leq\frac{1}{2} \\ \\ and \\ \\ 2x+1\ge-2 \\ 2x\ge-2-1 \\ 2x\ge-3 \\ x\ge-\frac{3}{2} \end{gathered}[/tex]

so ,

[tex]-\frac{3}{2}\leq x\leq\frac{1}{2}[/tex]

Final Answer

Hence , the correct option is

[tex]-\frac{3}{2}\leq x\leq\frac{1}{2}[/tex]

I hope you can help me with this I can’t understand it and I’ve already had three tutors turn me down because they didn’t understand it

Answers

Given:

An angle whose supplement is 10 degrees more than twice its complement.

Required:

To write and solve the equation.

Explanation:

Let the angle be x degrees.

Supplement of this angle = 180 - x

Complement of this angle = 90 -x

Given that supplement is 10 degrees more than twice its complement.

So the equation becomes:

180- x =2(90 - x) + 10

Solve by multiplication.

180 - x = 180 - 2x +10

Solve by collectiong the like terms.

2x - x = 180 - 180 + 10

x = 10 degrees

Final Answer:

The value of the angle is 10 degrees.

The two shorter sides of a right triangle measure 18 ft and 24 ft. What is the measure in feet of the third side? 

Answers

We have that in a right triangle, the larger side is the hypothenuse since the sum of the others angles must be equal to 90. Thus, we can apply the Pythagorean Theorem to solve this question.

The legs of the triangle are a = 18 ft, b = 24 ft, and c = ?.

Then, applying the Pythagorean Theorem, we have (without using units):

[tex]c^2=a^2+b^2\Rightarrow c^2=(18)^2+(24)^2\Rightarrow c^2=324+576\Rightarrow c^2=900[/tex]

Then, taking the square root to both sides of the equation, we have:

[tex]\sqrt[]{c^2}=\sqrt[]{900}\Rightarrow c=30[/tex]

Then, the measure of the third side (hypothenuse) is c = 30 ft.

5. The function w(x) = 70x represents the number of words w(x) you can type in x minutes. SHOW ALL WORK!!a.) How many words can you type in 5 minutes?b.) How many words can you type in 8 minutes?c.) How long would it take to read 280 words?

Answers

The given function is

[tex]w(x)=70x[/tex]

Where x is minutes.

(a) To find the number of words typed in 5 minutes, we just need to replace the variable for 5 and solve

[tex]w(5)=70(5)=350[/tex]

Therefore, there are typed 350 words in 5 minutes.

(b) We do the same process for 8 minutes.

[tex]w(8)=70(8)=560[/tex]

Therefore, there are typed 560 words in 8 minutes.

(c) To find the type for 280 words, now we replace the other variable w(x), and solve for x

[tex]280=70x[/tex]

We divide the equation by 70

[tex]\frac{280}{70}=\frac{70x}{70}\rightarrow x=4[/tex]

Therefore, 280 words take 4 minutes.

5 2/5 × 0.8A. 4.32B. 5.76C.7.80D.2.75

Answers

Answer:

A. 4.32

Explanation:

First, we need to transform the mixed number 5 2/5 into a decimal number as:

[tex]5\frac{2}{5}=5+\frac{2}{5}=5+0.4=5.4[/tex]

Then, we can multiply 5.4 by 0.8, so:

[tex]5\frac{2}{5}\times0.8=5.4\times0.8=4.32[/tex]

To multiply 5.4 by 0.8, we can multiply the numbers normally without taking into account the decimal points. So 54 times 08 is equal to:

Then, 5.4 has one digit after the decimal point and 0.8 has one digit after the decimal point. So, in total, we have two digits after the decimal point. It means that the result is equal to 4.32 because we need two digits after the decimal point.

Therefore, the answer is 4.32

Victoria spends the two spinners shown 500 times solve a percent equation to predict the number of times the sum is less than or equal to 3. Enter the correct answers in the boxes.

Answers

Given t spinners :

The first has the numbers : from 1 to 5

The second has the numbers : from 1 to 3

So, the sum is less than or equal to 3 can get if the two spinners give 1 or 2

So, the probability to get 1 or 2 from the first spinner = 2/5

And the probability to get 1 or 2 from the second spinner = 2/3

So, total probability = 2/5 * 2/3 = 4/15 = 26.66%

She spends the two spinners 500 times

So, the equation will be :

[tex]26.66\%\times500=x[/tex]

Solve for x:

[tex]26.66\%\times500=133.3[/tex]

So, the number of times = 133

For the following set of data, find the number of data within 1 population standarddeviation of the mean.68, 68, 70, 61, 67, 71, 63, 67

Answers

Given the following set of numbers,

[tex]68,\text{ 68, 70, 61, 67, 71, 63, 67}[/tex]

Where the (n) number of data is 8, the mean is,

[tex]\bar{x}=\frac{x_1+x_2+..._{}+x_n}{n}=\frac{68+68+70+61+67+71+63+67}{8}=66.875[/tex]

The standard deviation is 3.36

Hence, the interval that is 1 population within the mean is given by

[tex](66.88-3.36,66.88+3.36)=(63.52,70.24)[/tex]

Of all the data only 71, 61, and 63 are not an element of the interval (63.52,70.24)

The total number of data is 8.

Hence, the total number of data within 1 standard deviation of the mean is 5

The tables of ordered pairs represent some points on the graphs of Lines F and G.

Line F
x y
2 7
4 10.5
7 15.75
11 22.75

Line G
x y
-3 4
-2 0
1 -12
4 -24

Which system of equations represents Lines F and G?

1. y=1.75x+3.5
y=-4x-8
2. same as 1 but -8 is -2
3. 1.75 and 3.5 are switched
4. 2 and 3 combined

Answers

The system of equation that represents lines F and G is (1) y = 1.75x + 3.5, y = -4x-8

To find the system of equation, we will put the values given tables in the equation given in the options.

For option (1)

y = 1.75x + 3.5   (For line F)

let's take the point (2,7) and put in the equation,

y = 1.75*2 + 3.5

  = 3.5 +0.35

  = 7

which is true.

Hence, (2,7) satisfies the equation.

y = -4x-8   (For line G)

lets take the point (-3,4) and put in the equation,

y = (-4)*(3) - 8

  = 12 - 8

  = 4

which is true.

Hence, (-3,4) satisfies the equation.

Therefore, Equation for line F is y = 1.75x + 3.5 and equation for line G is y = -4x-8.

Learn more about system of equation on:

https://brainly.com/question/24065247

#SPJ1

 

The scatter plot shows the number of hours worked, x, and the amount of money spent on entertainment, y, by each of 25 students.Use the equation of the line of best fit, =y+1.82x11.36, to answer the questions below.Give exact answers, not rounded approximations. (a) For an increase of one hour in time worked, what is the predicted increase in the amount of money spent on entertainment?$(b) What is the predicted amount of money spent on entertainment for a student who doesn't work any hours?$(c) What is the predicted amount of money spent on entertainment for a student who works 8 hours?$

Answers

Solution:

Given the scatterplot below:

where the equation of the line of best fit is expressed as

[tex]y=1.82x+11.36[/tex]

A) Predicted increase in the amount of money spent on entertainment, for an increase of one hour in time worked.

Recall that the line equation is expressed as

[tex]\begin{gathered} y=mx+c \\ where \\ m=slope \\ slope=\frac{increase\text{ in y}}{increase\text{ in x}} \end{gathered}[/tex]

By comparison with the equation of line of best fit, we see that

[tex]\begin{gathered} slope=1.82 \\ where \\ slope=\frac{increase\text{ in amout of money spent}}{increase\text{ in the number of hours worked}} \end{gathered}[/tex]

Thus, we have

[tex]\begin{gathered} 1.82=\frac{increase\text{ in amount of money spent}}{1} \\ \Rightarrow predicted\text{ increase in amount of money spent on entertainment = \$1.82} \end{gathered}[/tex]

B) Predicted amount of money spent on entertainment for a student with no number of hours worked

This implies that from the equation of the line of best fit, the value of x is zero.

By substitution, we have

[tex]\begin{gathered} y=1.82(0)+11.36 \\ =0+11.36 \\ \Rightarrow y=\$11.36 \end{gathered}[/tex]

C) Predicted amount of money spent on entertainment for a student with8 hours of work.

Thus, we have the value of x to be 8 from the equation of the line of best fit.

By substitution, we have

[tex]\begin{gathered} y=1.82\left(8\right)+11.36 \\ =14.56+11.36 \\ \Rightarrow y=\$25.92 \end{gathered}[/tex]

Solve the following exponential equation. Express irrational solutions in exact form and as a decimal rounded to three decimal places. 4^-x=2.6What is the exact answer? Select the correct choice below and, if necessary, fill in the answer box to complete your choice.A. The solution set { } (simplify your answer. type an exact answer)B. There is no solution

Answers

Given:

[tex]4^{-x}=2.6[/tex]

To solve for x:

Taking log on both sides

[tex]\begin{gathered} \log 4^{-x}=\log 2.6 \\ -x\log 4=\log 2.6 \\ -x=\frac{\log 2.6}{\log 4} \\ -x=0.689255811 \\ x=-0.689255811 \\ x\approx-0.689 \end{gathered}[/tex]

Hence, the value of x is -0.689 (rounded to three decimal places).

You are given the circumference of the circle and the measure of the central angle ACB. Find the length of arc AB.circumference = 36 feet; m ZACB= 40"The length of arc AB isfeet

Answers

the length of arc ACB is 4 ft

Explanation

the length of an arc is given by:

[tex]l=\frac{\theta}{360\text{ \degree}}2\text{ }\pi r[/tex]

where l is the length or the arc, theta is the angle in degrees, r is the radius

so

Step 1

find the radius of the circle

[tex]\begin{gathered} 2\text{ }\pi r=36 \\ \text{divide boths ides by 2}\pi \\ \frac{2\text{ }\pi r}{2\text{ }\pi}=\frac{36}{2\pi} \\ r=\frac{18}{\pi} \end{gathered}[/tex]

Step 2

now, replace in the formula

Let

angle= 40 °

[tex]\begin{gathered} l=\frac{\theta}{360\text{ \degree}}2\text{ }\pi r \\ l=\frac{40}{360\text{ \degree}}2\text{ }\pi(\frac{18}{\pi}) \\ L=\frac{40}{360}\cdot36 \\ l=4\text{ } \end{gathered}[/tex]

therefore, the length of arc ACB is 4 ft

I hope this helps you

Marisol wants to buy a backpack from the Gucci store. Gucci ishaving a sale of 45% off the regular price. If the regular price of aGucci backpack is $1375.23, then what will the new sale price beafter the discount of 45% is applied?

Answers

Regular price = $1375.23

Discount = 45% of Regular price

The discount = 45% of $1375.23

= 45/100 x $1375.23

= 0.45 x $1375.23

Discount = $ 618.85

But Sale price = Regular price - Discount

Sale price = $1375.23 - $618.85

Sale price = $756.38

Hence, the new sale price after the discount of 45% is applied is $756.38

The points (−5, -5) and (r, 1) lie on a line with slope 1/2. Find the missing coordinate r.

Answers

Solution:

The slope is expressed as

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ where \\ (x_1,y_1)\text{ and} \\ (x_2,y_2)\text{ are the coordinates of points through which the line passes} \end{gathered}[/tex]

Given that the points (-5, -5) and (r, 1) lie on the line with slope 1/2, this implies that

[tex]\begin{gathered} x_1=-5 \\ y_1=-5 \\ x_2=r \\ y_2=1 \end{gathered}[/tex]

By substituting these valus into the slope formula, we have

[tex]\begin{gathered} \frac{1}{2}=\frac{1-(-5)}{r-(-5)} \\ \Rightarrow\frac{1}{2}=\frac{1+5}{r+5} \\ cross-multiply, \\ r+5=2(1+5) \\ \Rightarrow r+5=12 \\ add\text{ -5 to both sides of the equation,} \\ r+5-5=12-5 \\ \Rightarrow r=7 \end{gathered}[/tex]

Hence, the missing coordinate r is evaluated to be

[tex]7[/tex]

the sum of 5 times a number and twice its cube

Answers

[tex]\begin{gathered} \text{Let the number be : x} \\ vetimesofthenumber\colon5x+2x^3 \end{gathered}[/tex]

I don't understand this, can you hell me solve this please?

Answers

We will investigate the angle measures and the properties involved with a pair of parallel lines.

We are given two pairs of parallel lines, namely:

[tex]\begin{gathered} L\text{ }\mleft\Vert\text{ m }\mright? \\ a\text{ }\mleft\Vert\text{ b}\mright? \end{gathered}[/tex]

The angle properties that are used in consequence of parallel lines are of the following:

[tex]\text{Alternate Angles , Complementary Angles , Supplementary Angles, Corresponding Angles}[/tex]

Each of the above property describes a relationship between two angle measures. That is how two angles are related to one another in consequence of the parallel lines.

The angle measures are classified into two types as follows:

[tex]\begin{gathered} \text{Interior Angles} \\ \text{Exterior Angles} \end{gathered}[/tex]

Given R(I, y) = (-y, z) and the point Qt1, 0), what is R(Q)?R(Q)

Answers

Given that R(x, y) = (-y, x)

This is a transformation.

We want to find R(Q)

The point Q is given as:

Q = (1, 0)

This means that x = 1 and y = 0

Therefore, for R(Q):

-y = -0 = 0

x = 1

Therefore:

R(Q) = (-y, x) = (0, 1)

$3,700 for 2% for 4 yearswhat is the simple interest?what is the total amount?

Answers

[tex]\begin{gathered} \text{simple interest = \$296} \\ \text{Amount = \$3,996} \end{gathered}[/tex]

Here, we want to get the amount on the simple interest

Mathematically, this is the sum of the amount deposited and the interest accurred

For the interest, we use the formula for simple interest as follows;

[tex]\begin{gathered} I\text{ = }\frac{PRT}{100} \\ \\ P\text{ is the amount deposited = \$3,700} \\ R\text{ is the rate which is 2\%} \\ T\text{ is time which is 4 years} \\ \text{Substituting these values;} \\ I\text{ = }\frac{3700\times2\times4}{100}\text{ = \$296} \end{gathered}[/tex]

So, we simply add this to the principal to get the amount

[tex]\begin{gathered} \text{Amount = Principal + Interest} \\ =\text{ \$3,700 + \$296 = \$3,996} \end{gathered}[/tex]

describe the domain of the function f(x;y)= ln(4-x-y)

Answers

Domain of the given function is x∈(-2,∞)

Step-by-step explanation:

The given function is y=\ln(x+2)y=ln(x+2)

Domain is the set of x values for which the function is defined.

And we know that logarithm function is defined only for values greater than zero.

Therefore, for domain we have

x + 2 >0

x > -2

Hence, the domain of the

The domain of the function

f

(

x

,

y

)

=

ln

(

4

x

y

)

is the region of the x-y plane such that the argument of logarithm function is positive,...

See full answer below.

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What Is Domain and Range in a Function?

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Chapter 7 / Lesson 3

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What are the domain and range of a function? What are the domain and range of the graph of a function? In this lesson, learn the definition of domain and range as it applies to functions as well as how it applies to graphs of functions. Moreover, there will be several examples presented of domain and range and how to find them.

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Give and graph the domain of the function f(x,y)= \sqrt {y-x^3}.

Find the domain of the function and GRAPH it. h(x,y) = ln (x + y - 5)

Find the domain of the function, given the graph below.

Find the domain of the function whose graph is given below.

Use the following graph. Find the domain of the function.

If f(x) = \frac{1 - x}{2 + x}, find {f}'(x) and its domain.

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Find the domain of the function f(x, y) = (2cos(x + y))/(sqrt(9 - x^2 - y^2)).

Find the domain of the function K(x) = f(x) \cdot g(x) \cdot h(x) , for f(x) = \ln x, \ g(x) = x 169, \text{ and } h(x) = 9x^2 .

Find the domain of the given function f(x, y) = 2 / ln (x + y - 3).

Find the domain of the following function f(x) = \frac {7}{(x+2)(x-3)}

Find the domain of the function f(x) = 30 - 7x -2x².

Find the domain of the function f(x) = \frac{\sqrt{x+4{x-3}.

Find the domain of the function f(x) = 1/(x - 2) sqrt((x - 1)/(x)).

Find the domain of the function f(x) = \frac{1}{1-3e^x}

Find the domain of the function f(x) = \dfrac{x^4}{x^2 + x - 6}.

Find the domain of the function f(x) = 3/[x/2] -5^{(cos^-1x^2) + (2x+1) / (x+1)} .

Find the domain of the function f(x) = 2x - 3.

Find the domain of the function f(x) = 2x x2-4

Find the domain of the given function f(x,y)=4x^2-3y^2.

1) Find the domain and graph the function: f(x) = \sqrt {x - 1} 2) Graph the function g(x) = (x + 3)^3

Determine and graph the domain of the function. f(x, y) = \sqrt{144-9x^2 - 16y^2}

Following is a graph of a function f(x). Determine the domain where the function is differentiable.

Find the domain of the function y = \sqrt{25 x^2} . Then graph the function.

Given f(x) = 3x + 1 and g(x) = 5x - 1. a) Find \frac{f}{g} and its domain.

Given f(x) = \frac{x+2}{x} , find f^{ 1} (x) and its domain.

Given f(x) = x^2 + 1 and g(x) = 2/x + 4 , find: (f times g) (x) = _____ Domain: _____

Given f(x) = \ln (1 - | 1-2x|) , find the domain of f

If f'(x) = \frac{2xln(-4(x^2-2.75)) + (2x^3)}{(x^2-2.75)}, find the domain.

Given f(x) = x^2 + 1 and g(x) = 2/x + 4, find: (f + g) (x) = _____ Domain: _____

1. Find a function f(x, y) and domain D are which f _{x,y} \neq f _{yx}.

If f(x) = sqrt(6 - x) and g(x) = x + 7, find the domain of (g/f)(x).

Given f(x) = \ln(13x+2) , find f'(x) and the domain of f

Determine the domain of the function f(x,y,z) = \frac{\sqrt{y{x^2 - y^2 + z^2}.

Determine the domain of the function f(x) = 9x/x^2-4.

Determine the domain of the function f(x) = \frac {4}{10x^2 - 6}.

Determine the domain for each function f(x) = 2x + 3, g(x) = x - 1.

Find f_x and f_y and graph f, f_x, and f_y with domains. f(x, y) = x^2y^3

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