Use Composition of FunctionsBOX OFFICE A movle theater charges $8.50 for each of the xtickets sold. The manager wants to determine how much the movietheater gets to keep of the ticket sales If they have to glve thestudlos 75% of the money earned on ticket sales t(x). If the amountthey keep of each ticket sale is k(x), which composition representsthe total amount of money the theater gets to keep?

Use Composition Of FunctionsBOX OFFICE A Movle Theater Charges $8.50 For Each Of The Xtickets Sold. The

Answers

Answer 1

Given: The amout charged per ticket is $8.50

If x tickets are sold

Then the total revenue (amount made) will be =>

[tex]8.5\text{ x }x\text{ = \$8.50x}[/tex]

If t(x) represents how much the studio collects

and k(x) represents how much is kept

Given: t(x) = 75% then

k(x)= (100 -75)%= 25 %

So that

The total amount that will be kept will be

25% of $8.50x

=>

[tex]\frac{25}{100}\text{ x (\$8.50x) }[/tex]

[tex]\frac{25\text{ x \$8.50x}}{100}\text{ = }\frac{212.5x}{100}=\text{ \$2.125x}[/tex]

The amount that will be kept will be

= > $2.125x

Where x is the number of tickets


Related Questions

Karl borrowed $5,700 from the bank for a year at 9% simple interest. What was the amount he paid back to the bank?

Answers

Simple interest = PRT /100

where P is the principal

R is the rate

T is the time in year

From the question

P=$5700 R=9 T=1

substitute the values into the formula;

S.I = 5700 x 9 x 1 /100

=$513

Amount pay back = $5700 + $513 = $6,213

At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 32 minutes and a standard deviation of 5 minutes. What is the probability that a randomly selected customer will have to wait less than 21 minutes, to the nearest thousandth?

Answers

Given:

[tex]\begin{gathered} mean(\mu)=32 \\ Standard-deviation(\sigma)=5 \end{gathered}[/tex]

To Determine: The probability that a randomly selected customer will have to wait less than 21 minutes, to the nearest thousandth

Solution

Using normal distribution formula below

[tex]P(Z<\frac{x-\mu}{\sigma})[/tex]

Substitute the given into the formula

[tex]\begin{gathered} P(Z<\frac{21-32}{5}) \\ =P(Z<-\frac{11}{5}) \\ =P(Z<-2.2) \end{gathered}[/tex][tex]\begin{gathered} P(X<-2.2)=1-P(X>-2.2) \\ =1-0.986097 \\ =0.01390345 \\ \approx0.014(Nearest\text{ thousandth\rparen} \end{gathered}[/tex]

Hence, the probability that a randomly selected customer will have to wait less than 21 minutes, to the nearest thousandth is 0.014

etec dego BoildName4-1Amber is saving money to buy a bicycie. She saves $60 hergrandfather gave her, and plans to save an additional $5 eachweek. How much will Amber save after wweeks?Total sawingeUse a bar diagram to represent the amountAmber will save after w weeks.S60Amber will save 60Sw dollarsWeeklyvingsMoney from grandfatherafter w weeks.Reggie drives 10 miles from the airport to the highway. Once on the highway, he drives ata speed of SS miles per hour What is Reggie's total distance from the airport h hours afterreaching the highway?1. Complete the bar diagram.Total distance55 mites per hourDitanceHourly distance on highwayhụhwY

Answers

Valencia, this is the solution:

Distance Reggie will drive from the airport to the highway = 10 miles

Distance per hour once on the highway = 55 miles

Let h to represent the number of hours Reggie will drive on the highway

In consequence,

Reggie will drive a total distance of 10 + 55h miles from the airport

7. Given an arithmetic sequence, find a26if a4 = 71 and a32 = 1. 8. Given a geometric sequence, find az ifa1 = 729 and a2 = – 243.

Answers

Arithmetic sequence

a= 26

a4 = 71

a32 = 1.

an = a1 + (n-1)d

a4 = a1 + (3)*d

71 = a1 + (3)*d (I)

a32 = a1 + (31)*d

1 = a1 + 31 d (II)

to find a1 and d we subtract (II)- (I)

1 = a1 + 31 d (II)

-( 71 = a1 + (3)*d) (I)

________________

-70 = 0 28 d

-70 = 28 d

d= -70/ 28

d= -5/2

Replacing d in (I)

71 = a1 - (3)(5/2)

a1= 71 + (3)(5/2)

a1= 78.5

The arithmetic sequence is

an = a1 + (n-1)d

an = 78.5 + 2.5 (n-1)

Verifying

a4 = 78.5 - 2.5 (3) = 78.5 -7.5= 71

a32 = 78.5 +2.5 (31) =78.5 -77.5 = 1

a26 = 78.5 + 2.5 (25) = 78.5 - 62.5 = 16

Give me some minutes

______________________

Answer

a26 = 16

[tex]\displaystyle\sum_{ k = 1}^{ n } ( - 21 + 5k) = 996[/tex]Solve for "n" value.

Answers

Given an equation to solve for n:

[tex]\sum ^n_{k\mathop=1}(-21+5k)=996[/tex]

The expansion of the given sum is as follows:

[tex]\begin{gathered} -21+5(1)+(-21+5(2))+(-21+5(3))+\cdots+(-21+5n)=996 \\ -21n+(5+10+15+\cdots+5n)=996 \\ -21n+5(1+2+3+\cdots+n)=996 \\ -21n+5(\frac{n(n+1)}{2})=996 \\ -21n+\frac{5}{2}(n^2+n)=996 \\ -42n+5(n^2+n)=1992 \\ -42n+5n^2+5n=1992 \\ 5n^2-37n-1992=0 \end{gathered}[/tex]

Now, factorise the above quadratic equation:

[tex]\begin{gathered} 5n^2+83n-120n-1992=0 \\ n(5n+83)-24(5n+83)=0 \\ (5n+83)(n-24)=0 \end{gathered}[/tex]

Use zero product rule in the equation to get:

5n + 83 = 0 or n - 24 = 0 which implies n = -83/5 and n = 24.

Neglect the negative solution of the equation to get n = 24.

Thus, the answer is 24.

There are as many even counting numbers as there are counting numbers. Is this true or false?

Answers

The sets of even and odd counting numbers are both infinite in size (number of elements). However, we can map each even counting number to each odd counting number as follows:

[tex]\begin{gathered} 2\rightarrow1 \\ 4\rightarrow3 \\ 6\rightarrow5 \\ 8\rightarrow7 \\ \text{And so on}\ldots \end{gathered}[/tex]

So we have the mapping rule:

[tex]\begin{gathered} 2n\rightarrow2n-1 \\ \text{Where }n=1,2,3,\ldots \end{gathered}[/tex]

Then, we can say that there are as many even counting numbers as there are counting numbers, or equivalently, that both sets have the same cardinality.

Answer: True

Reduce to lowest terms 24/36

Answers

To reduce to the lowest terms we notice that:

[tex]\frac{24}{36}=\frac{6\cdot4}{6\cdot6}=\frac{6\cdot2\cdot2}{6\cdot2\cdot3}[/tex]

now, we can eliminate the 6 and 2 that repeat in the numerator and denominator, thereforew the fraction in lowest terms is:

[tex]\frac{2}{3}[/tex]

Write the equation in slope-intercept form through the point (3, 1) and is perpendicular to the y-axis and graph

Answers

Write the equation in slope-intercept form through the point (3, 1) and is perpendicular to the y-axis and graph​

step 1

we know that

If the line is perpendicular to the y-axis, that means that the line is parallel to the x-axis

so

Its a forizontal line

the slope is equal to zero

therefore

the equation is

y=1

using a graphing tool

see the attached figure

please wait a minute

Janet, Li Na, and Katie have 68 beads altogether.Janet has 3 times as many beads as Li Na.Katie has 5 more beads than Janet.How many beads does Katie have?

Answers

EXPLANATION:

Given;

We are told that Janet, Li Na and Katie all have a total of 68 beads.

We are also told that;

(i) Janet has 3 times as many beads as Li Na

(ii) Katie has 5 more beads than Janet.

Required;

We are required to find out how many beads Katie has.

Step-by-step solution;

From the conditions given, Janet has 3 times as many beads as Li Na. That means if Li has an y number of beads, Janet's would be times 3.

Therefore, if Li Na is L and Janet is J, then it means;

[tex]\begin{gathered} Li\text{ }Na=l \\ Janet=3l \end{gathered}[/tex]

Also we are told that Katie has 5 more beads than Janet. That means, if Katie is K, then;

[tex]\begin{gathered} Janet=3l \\ Katie=3l+5 \end{gathered}[/tex]

Bear in mind that they all have a total of 68 beads. Hence, we add up their beads as follows;

[tex]\begin{gathered} LiNa+Janet+Katie=68 \\ l+3l+3l+5=68 \end{gathered}[/tex][tex]7l+5=68[/tex]

Subtract 5 from both sides;

[tex]7l+5-5=68-5[/tex][tex]7l=63[/tex]

Divide both sides by 7;

[tex]\frac{7l}{7}=\frac{63}{7}[/tex][tex]l=9[/tex]

This means Li Na has 9 beads. If Katie's bead is given by the expression 3l + 5, then she will have;

[tex]\begin{gathered} Katie=3l+5 \\ Katie=3(9)+5 \\ Katie=18+5 \\ Katie=23 \end{gathered}[/tex]

ANSWER:

Katie has 23 beads.

Given: F(x) = 3x^2+ 1, G(x) = 2x - 3, H(x) = xF(x) + G(x) =

Answers

[tex]f(x)+g(x)=3x^2+2x-2[/tex]

Explanation

to add two functions just add like terms,Like terms" are terms whose variables and their exponents, are the same

so

Step 1

let

[tex]\begin{gathered} f(x)=3x^2+1 \\ g(x)=2x-3 \end{gathered}[/tex]

hence

[tex]f(x)+g(x)=3x^2+1+2x-3[/tex]

we can see the only pair of like terms ar +1 and (-3), so

[tex]\begin{gathered} f(x)+g(x)=3x^2+1+2x-3 \\ \text{add like terms} \\ f(x)+g(x)=3x^2+2x-2 \end{gathered}[/tex]

I hope this helps you

what doesnt belong and why? please someome help me will make brainlist

Answers

The one that doesn't belong is 4² = 4² + 4²

Explanation:

2² = 2 × 2

4² = 4 × 4

4² is not equal to 4² + 4²

this is because 4² + 4² = 16 + 16 = 32

while 4² = 4 × 4 = 16

The one that doesn't belong is 4² = 4² + 4²

What would be the transformation of point A when reflected across the x-axis?(1, -2)(-1, 2)(-1, -2)(1, 2)

Answers

Given:

The coordinates of point A is (-1, 2).

To find:

The reflection of point A across the x-axis.

Solution:

It is known that the reflection of a point (x, y) about the x-axis is (x, -y).

So, the reflection of point A is (-1, -2).

Thus, option C is correct.

a line intercepts the point (-2, 1) and it has a slope of 2 input the correct values into the point slope formula. y- ? = ? ( x- ?)

Answers

Point-slope formula

We know that the point-slope forumal is given by:

[tex]y-y_1=m(x-x_1)[/tex]

where the terms: m, y₁ and x₁ are numbers.

Given that the line passes through a given points we have that:

m is the slope of the line

y₁ is the y value of that given point

x₁ is the x value of that given point

In this case we have that

1. It has a slope of 2, then m = 2

2. The line intercepts the point (-2, 1). Since (-2, 1) = (x₁, y₁) then

x₁ = -2 and y₁ = 1

We have that

m = 2

x₁ = -2

y₁ = 1

Let's replace those values in the first formula:

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \downarrow \\ y-1=2(x-(-2)) \\ y-1=2(x+2) \end{gathered}[/tex]Answer- the point-slope formula of this line is: y - 1 = 2(x + 2)

9) write in standard formthrough: (4,4), parallel to y=-6x + 5

Answers

Data

Point (4, 4)

Equation

y = -6x + 5

Procedure

As the straight line is parallel we use the same slope of the original straight line.

m = -6

Now we will calculate y-intercept

[tex]\begin{gathered} b=y-mx \\ b=4-(-6)\cdot4 \\ b=4+24 \\ b=28 \end{gathered}[/tex]

The equation would be:

[tex]y=-6x+28[/tex][tex]6x+y=28[/tex]

Now in the standard form: 6x+y=28

what digit is in the

Answers

7 more than t

The algebraic expression is:

[tex]t+7[/tex]

Answer: t + 7

Comelius conducts an experiment where he selects a letter tile from the tiles shown, records the letter, then replaces it in the bag The table shows the results after 50 trialsA 1 0E 18T 18U 4What is the relative frequency that a letter was T? Express your answer as a fraction in simplest form

Answers

Relative frequency of T = 9/25

Explanation:

Total number of T's = 18

Total number of A's = 10

Total number of E's = 18

Total number of U's = 4

Total = 18 + 10 + 18 + 4 = 50

Relative frequancy = number of time the letter occurred/total letters

Relative frequency = 18/50

To the simplest form:

Relative frequency of T = 9/25

(x²y³z)^1/5Rewrite the rational exponent expression as a radical expression.

Answers

Given the following rational exponent:

(x²y³z)^1/5

Putting it into a radical expression will be:

[tex]\text{ \lparen x}^2y^3z)^{\frac{1}{5}}\text{ = }\sqrt[5]{x^2y^3z^}[/tex]

A baseball player has a batting average of 0.33. What is the probability that he has exactly 4 hits in his next 7 atbats? Round to 3 decimal places.The probability is

Answers

Given that the player can or cannot hit the ball, then this situation can be modeled with the binomial distribution.

Binomial distribution formula

[tex]P=_nC_xp^x(1-p)^{n-x}^{}[/tex]

where

• P: binomial probability

,

• nCx: number of combinations

,

• p: probability of success in a single trial

,

• x: number of times for a specific outcome within n trials

,

• n: number of trials

Substituting with n = 7, x = 4, and p = 0.33, we get:

[tex]\begin{gathered} P=_7C_4(0.33)^4(1-0.33)^{7-4} \\ P=35(0.33)^4(0.67)^3 \\ P\approx0.125 \end{gathered}[/tex]

The probability is 0.125

Line a is parallel to line b line a passes through the points (1,7) and (2,-4)Line b passes through the point (6,14)The equation of line b is y=__

Answers

Given:

Line a is parallel to line b.

Line a passes through the points (1,7) and (2,-4).

Line b passes through the point (6,14).

The objective is to find the equation of the line b in slope intercept form.

For parallel lines the slope of the two lines will be equal.

Consider the coordinates of the line a as,

[tex]\begin{gathered} (x_1,y_1)=(1,7) \\ (x_2,y_2)=(2,-4) \end{gathered}[/tex]

The slope of line a can be calculated as,

[tex]\begin{gathered} m_a=\frac{y_2-y_1}{x_2-x_1} \\ =\frac{-4-7}{2-1} \\ =-11 \end{gathered}[/tex]

Since both are given as parallel lines, the slop of line b will be,

[tex]m_b=-11[/tex]

If the line b passes throught the point (6,14), the equation can be represented as,

[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-14=-11(x-6) \\ y-14=-11x+66 \\ y=-11x+66+14 \\ y=-11x+80 \end{gathered}[/tex]

Hence, the equation of line b is y = -11x+80.

if D equals 6x - 7 + 8 equals 4x + 9 find the DB

Answers

If DE = 6x - 7 and AE = 4x + 9, find DB.

DE and AE are line segments. We need to equal DE = AE

[tex]DE=AE[/tex][tex]6x-7=4x+9[/tex][tex]6x-4x=9+7[/tex][tex]2x=16[/tex][tex]x=8[/tex]

Now, DB = DE + EB

[tex]DB=6x-7+4x+9[/tex][tex]DB=10x+2[/tex]

x = 8

[tex]DB=10(8)+2\rightarrow DB=82[/tex]

DB is 82

Write the equation of a circle with a radius of 8 and a center at (4, -9).

Answers

The equation of a circle with radius r and center at (h,k) is given by:

(x + h)² + (y + k)² = r²

If r = 8 and (h,k) = (4,-9), we have:

(x-4)² + (y + 9)² = 8²

Determine whether the relation is a function. y=4x-1 with inputs x= -3, x= -2, and x= -1

Answers

Given the equation:

[tex]y=4x-1[/tex]

This is a linear relation, and particularly, it is a function because each x-value has one and only one y-value given by the equation above.

We evaluate this function for x = -3, x = -2, and x = -1:

[tex]\begin{gathered} x=-3\Rightarrow y=4(-3)-1=-13 \\ \\ x=-2\operatorname{\Rightarrow}y=4(-2)-1=-9 \\ \\ x=-1\operatorname{\Rightarrow}y=4(-1)-1=-5 \end{gathered}[/tex]

According to the graph, what is the solution to this system of equations? O (-4,-3) 0 (-3,-4) O (-5, 5) O (5,-5)

Answers

The intersection of the 2 lines is the point of the solution of the graph . Using the graph above , the meeting point of the 2 lines are

[tex](-4,-3)[/tex]

Approximate the median in each of the three graphs. Explain how you determined the answer.

Answers

The median is the centermost data in a set of values.

Since these graphs are for the year 2013, meaning, these graphs contained 365 days of recorded temperature.

For 365 days, the centermost data would be the 183rd day.

Let's take a look at each graph what is the temperature on the 183rd day when data is arranged from lowest to the highest temperature.

As we can see above, the first two bins of the histogram only cover 180 days. Since we are looking for the 183rd day, we moved to the third bin. Hence, the median temperature for City A is between 65 to 75 ℉.

For City B,

The 183rd day in City B is found on the interval 55-75. Hence, the median temperature for City B is between 55-75℉.

Lastly, for City C:

As we can see in the graph above, the 183rd day is approximately closed to the third bin. Hence, for the 183rd day, we can say that the temperature is between 65 to 75℉. The median temperature for City C is between 65 to 75℉.

Problem 12a) solve for x, 3(-2x +5) = 9(x-5), x=b) x = –27, x =

Answers

The given equation is

[tex]3(-2x+5)=9(x-5)[/tex]

Dividing by 3 both sides, we get

[tex]\frac{3\mleft(-2x+5\mright)}{3}=\frac{9\mleft(x-5\mright)}{3}[/tex]

[tex]-2x+5=3(x-5)[/tex]

Multiplying 3 and (x-5) as follows.

[tex]-2x+5=3\times x-3\times5[/tex]

[tex]-2x+5=3x-15[/tex]

Adding 15 on both sides, we get

[tex]-2x+5+15=3x-15+15[/tex]

[tex]-2x+20=3x[/tex]

Adding 2x on both sides, we get

[tex]-2x+20+2x=3x+2x[/tex]

[tex]20=5x[/tex]

Dividing by 5, we get

[tex]\frac{20}{5}=\frac{5x}{5}[/tex][tex]4=x[/tex]

Hence the value of x is 4.

a low-wattage radio station can be heard only within a certain distance from the station. on the graph below, the circular region represents that part of the city where the station can be heard, and the center of the circle represents the location of the station. which equation represents the boundary for the region where the station can be heard,help I need the explanation for it

Answers

In order to find the equation that represents this boundary, let's use the equation of the circumference below:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Where r is the radius and the center of the circumference is the point (h, k).

Looking at the image, we can see that the circumference is centered at (-6, -1), and its radius is equal 4 units.

So we can write the following equation, using h = -6, k = -1 and r = 4:

[tex](x+6)^2+(y+1)^2=16[/tex]

Therefore the correct option is the second one.

What is the difference of the complex numbers below? (6+81)-(1-21 ) O A. 7+10) O O O B. 5+10) O C. 5+67 O 0 7 D. 7 +62

Answers

we have the expression

[tex](6+8i)-(1-2i)[/tex]

Remove parenthesis

[tex]6+8i-1+2i[/tex]

Group similar terms

[tex](6-1)+(8i+2i)[/tex]

Combine like terms

[tex]5+10i[/tex]The answer is option B

I need help with the transition from red to blue

Answers

5 units left and 2 units down

I need a deep explanation we are doing this in school pulled out my notes and still don't understand.

Answers

For an isosceles triangle, two sides are equal and for right triangle o angle should be of 90 degree.

Let the third point coordinate be (x,y).

The distane between given point (-2,-4) and (4,-4) is 6.

The on angle is 90 degree which means one side is perependicular to the given side.

The coordinate of third point must be equal to (4,y) or (-2,y).

As triangle is isosceles so distance between point (4,y) and (4,-4) is equal to 6.

[tex]\begin{gathered} 6=\sqrt[]{(4-4)^2+(y+4)^2} \\ 6=(y+4) \\ y=6-4 \\ =2 \end{gathered}[/tex]

Thus coordinate of third point can be (4,2).

Second case if third point is (-2,y).

Distance between point (-2,y) and (-2,-4) is 6, as triangle is isosceles triangle.

[tex]\begin{gathered} 6=\sqrt[]{(-2+2)^2+(y+4)^2} \\ 6=(y+4) \\ y=2 \end{gathered}[/tex]

Thus third coordinate can be (-2,2).

As from the options only (4,2) is correct.

Demetrius is single but would like to take care of his mother in the event of his death. He would like to replace her income of $25,000 a year with a multiple of 30. How much life insurance should he buy?

Answers

Answer:

750000

Step-by-step explanation:

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