65091/4562Long division This this is to solve how many brownies Joshua has. Help please and thank you.
Answers
Given:
[tex]\frac{65091}{4562}[/tex]Number of Brownies= 14.27
Number of Brownies=14 (approximately)
Related Questions
Which equation has (1,1),(2,4),(3,7) and (4,10) as solutions?A)y=2x - 1.B)y= 2x+3.C)y=3x-2.D)y=3x+1.
Answers
Answer:
y=3x-2
Explanation:
The equation that has the given solutions is the equation that satisfies all the given (x, y) pairs.
From the given options:
[tex]\begin{gathered} \text{When x=1} \\ y=3x-2 \\ y=3(1)-2=1 \\ \implies(1,1) \end{gathered}[/tex]Likewise:
[tex]\begin{gathered} \text{When x=}2 \\ y=3x-2 \\ y=3(2)-2=4 \\ \implies(2,4) \end{gathered}[/tex]Also when x=3:
[tex]\begin{gathered} y=3\mleft(3\mright)-2=7 \\ \implies(3,7) \end{gathered}[/tex]Finally, when x=4
[tex]\begin{gathered} y=3\mleft(4\mright)-2=10 \\ \implies(4,10) \end{gathered}[/tex]Thus, since y=3x-2 satisfies all four points, it is the right equation.
This parabola opens to the left. P. O A. True O B. False
Answers
Answer:
True.
Explanation:
We take the analogy from the graph of y = ax^2
When y = x^2, the parabola opens upward (towards the positive y-axis). However, when the parabola is y = -x^2, it opens downward (towards the negative y-axis).
In a similar way, when we have x = ay^2, the parabola opens towards the positive x-axis ( towards the right). However, if we have x = -ay^2, then the parabola opens towards the negative x-axis ( towards the left).
Therefore, by comparison, x = - 1/8 y^2, opens to the left, and the correct option to choose is 'True'.
The drink booth at the school fair had these 5 types of drinks: ice tea, root beer, apple cider, lemonade, and orange juice. The 12 students from Mr. Yu's class were asked which drink they ordered. Here are the results: apple cider, orange juice, lemonade, root beer, orange juice, orange juice, lemonade, orange juice, ice tea, root beer, orange juice, orange juice Draw the bar graph for these data. Frequency 24 Explanation root beer Check apple cider lemonade orange juice Type of drink X ? 2022 McGraw H LLC. All Rights Reserved. Terms of
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The first step is to find the frequency of each type of drink. It is shown below
apple cider = 1
Orange juice = 6
Lemonade = 2
root beer = 2
ice tea = 1
The bar graph is shown below
Find the zeros by using the quadratic formula and tell whether the solutions are real or imaginary. F(x)=3x^2+4x+2
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The quadratic formula states that the solutions x1 and x2 of a quadratic function in the form y = ax^2 + bx + c is equal to:
[tex]\begin{gathered} x_1=\frac{-b+\sqrt[]{b^2-4ac}}{2a} \\ x_2=\frac{-b-\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]So, using this formula with the values a = 3, b = 4 and c = 2, we have that:
[tex]\begin{gathered} x_1=\frac{-4+\sqrt[]{4^2-4\cdot3\cdot2}}{2\cdot3}=\frac{-4+\sqrt[]{16-24}}{6}=\frac{-4+\sqrt[]{-8}}{6} \\ x_1=\frac{-4+\sqrt[]{2^2\cdot(-2)}}{6}=\frac{-4+2\cdot\sqrt[]{-2}}{6}=\frac{-2+\sqrt[]{-2}}{3}=-\frac{2}{3}+i\cdot\frac{\sqrt[]{2}}{3} \\ x_2=\frac{-4-\sqrt[]{-8}}{6}=\frac{-2-\sqrt[]{-2}}{3}=-\frac{2}{3}-i\cdot\frac{\sqrt[]{2}}{3} \end{gathered}[/tex]Since the zeros have a complex part, the solutions are imaginary.
Both customers spent same amount of money. customer one bought 8 chicken wings and left a tip of four dollars. second customer bought 10 chicken wings and left a tip of $2.50. how much is each chicken wing?
Answers
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the representation of the chicken wings
Let the chicken wing be represented by x
[tex]\begin{gathered} For\text{ Customer 1, he spent;} \\ 8x+4 \\ From\text{ second customer, he spent} \\ 10x+2.50 \end{gathered}[/tex]STEP 2: Equate the two amounts
Since they both spent same amount of money, this means that;
[tex]8x+4=10x+2.50[/tex]STEP 3: Solve for x
[tex]\begin{gathered} Collecting\text{ like terms:} \\ 8x-10x=2.50-4 \\ -2x=-1.5 \\ Divide\text{ both sides by -2} \\ \frac{-2x}{-2}=\frac{-1.5}{-2} \\ x=0.75 \end{gathered}[/tex]Hence, each chicken wing costs $0.75
Is 49 prime or composite?
Can Mario organize his marbles into equal piles ?
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Sasha has $850 todeposit into twoaccounts.Sasha will deposit $450at First Oak Bank.She will deposit the restinto River Point Bank.Sasha will not make additionaldeposits or withdrawals.How much more money will bein her account at First Oak thanat River Point after 2 years?
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Given
Sasha has $850 to deposit into two accounts.
Sasha will deposit $450 at First Oak Bank.
She will deposit the rest into River Point Bank.
Sasha will not make additional deposits or withdrawals.
To find how much more money will be in her account at First Oak than at River Point after 2 years.
Now,
It is given that,
In the first Oak bank the rate of interest is 6%.
Then, the amount in her account after 2 years is,
[tex]\begin{gathered} A=P+\frac{Pnr}{100} \\ A=450+\frac{450\times2\times6}{100} \\ A=450+54 \\ A=454 \end{gathered}[/tex]Hence, the amount in the First Oak bank is $454.
In the River point bank the rate of interest is 2% compounded annually.
Then, the amount in her account after 2 years is,
[tex]\begin{gathered} A=P(1+\frac{r}{100})^t \\ A=P(1+\frac{2}{100})^2 \end{gathered}[/tex]Since Sasha will deposit $450 at First Oak Bank and she will deposit the rest into River Point Bank.
Then, the amount deosited in the River point bank is,
[tex]\begin{gathered} P=850-450 \\ =400 \end{gathered}[/tex]Therefore,
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1. Gustava Valadez opened a new checking account by depositing her paycheck for$347.95. The check register shows her transactions since opening her account.What should her new balance be?
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When he deposite the paycheck for $347.95. An amount of $347.95 will be creted to in his account.
Therfore, the new balance is $347.95
In a circle of radius 10 cm, there are two parallel chords (in different sides of a circle) of lengths 16 cm and 12 cm. Calculate the distance between the chords.
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The distance between the chords is 14 cm
Given that AB=16 cm and CD=12 cm
So, AL=8 cm and CM=6 cm (⊥ from the centre to the chord bisect the chord)
In right triangles OLA and OMC,
By Pythagoras theorem,
OA² = OL²+AL²
and OC² = OM²+CM²
⇒ 10² = OL²+8²
and 10² = OM²+6²
⇒ OL²=100-64
and OM² = 100 - 36
⇒ OL² = 36 and OM² = 64
⇒ OL = 6 cm
and OM = 8 cm
In the second case distance between AB and CD is:
LM=OM+OL
= 8+6
= 14 cm
Hence distance between the chords is 14 cm,
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There are 30 boys in a sporting club, 20 of them play hockey and 15 play volleyball. Each play at least one 9f the two games. Illustrate this using:
A. The Venn diagram.
B. Only volleyball
C. Both games
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The students who play both hockey and volleyball 5 and the Venn diagram is shown below.
What are Venn diagrams?A Venn diagram uses overlapping circles or other shapes to illustrate the logical relationships between two or more sets of items. Often, they serve to graphically organize things, highlighting how the items are similar and different.A Venn diagram is an illustration that uses circles to show the relationships among things or finite groups of things. Circles that overlap have a commonality while circles that do not overlap do not share those traits. Venn diagrams help to visually represent the similarities and differences between two concepts.So, the Venn digram will be:
The total number of boys are 30.Boys playing hockey are 20.The boys playing volleyball are 15.A Number of students who play both:
(20+15) - 3035 - 305So, the Venn diagram will be:
(Refer to the Venn diagram attached below)Therefore, the students who play both hockey and volleyball 5 and the Venn diagram is shown below.
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3SpointsWhich is the image of vertex C after the triangle is rotated 180 degrees about the origin?
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T' (3,0) A' (5,-1) and C' (2,-4)
1) Considering that the Pre-image coordinates are :T(-3,0), A (-5,1) C(-2,4)
and there was a rotation 180º about the origin, then
2) In the Rotation, the rules for 180º rotation Counterclockwise and clockwise is
Pre-image Image
(x,y) ---- (-x, -y)
3)
Thus,
T' (3,0) A' (5,-1) and C' (2,-4)
what is 3 1/6 + 5 2/3
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The given expression is
[tex]3\frac{1}{6}+5\frac{2}{3}[/tex]First, we transform each mixed number into a fraction
[tex]\begin{gathered} 3\frac{1}{6}=\frac{3\cdot6+1}{6}=\frac{18+1}{6}=\frac{19}{6} \\ 5\frac{2}{3}=\frac{5\cdot3+2}{3}=\frac{15+2}{3}=\frac{17}{3} \end{gathered}[/tex]We use these fractions to make the sum
[tex]\frac{19}{6}+\frac{17}{3}[/tex]Now, we use the following property
[tex]\frac{a}{b}+\frac{c}{d}=\frac{a\cdot d+b\cdot c}{b\cdot d}[/tex][tex]\frac{19\cdot3+17\cdot6}{6\cdot3}=\frac{57+102}{16}=\frac{159}{16}[/tex]Hence, the result is 159/16.an object is thrown upward from the top of a 160 foots building with an initial velocity of 48 feet per second .solve the equation -16^2 + 48t + 160=0 find the time(t) in seconds at which the object hits the ground.
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The given equation represents the distance travelled by the object at time t.
The given equation is expressed as
-16t^2 + 48t + 160
At the point where it hits the ground, the distance woule be 0. Thus, we would so;ve the equation,
-16t^2 + 48t + 160=0
We would divide through by - 16. We have
t^2 - 3t - 10 = 0
We would find two terms such that their sum or difference is - 3t and their product is - 10t^2. They are 2t and - 5t. We have
t^2 + 2t - 5t - 10 = 0
By factorising, we have
t(t + 2) - 5(t + 2) = 0
(t + 2)(t - 5) = 0
t + 2 = 0 or t - 5 = 0
t = - 2 or t = 5
Since the time cannot be negative, the correct answer is
time = 5 seconds
In a lottery, the top cash prize was $629 million, going to three lucky winners. Players pick four different numbers from 1 to 56 and one number from 1 to 41.A player wins a minimum award of$525 by correctly matching three numbers drawn from the white balls (1 through 56) and matching the number on the gold ball (1 through 41).What is the probability of winning the minimum award?
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Step 1
Given;
[tex]\begin{gathered} Top\text{ cash prize is \$629} \\ Players\text{ pick four different numbers from 1 to 56 and 1 to 41} \end{gathered}[/tex]Step 2
Probability is given as;
[tex]undefined[/tex]Translate to an equation and solve: 4 is the product of 8 and b. Simplify all fractions.Provide your answer below:b=
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If 4 is the product of 8 and b, 4 is the result of the multiplication of 8 and b. Then,
4 = 8b
Which is the same as:
8b = 4
To find b, let's divide both sides by 8:
[tex]\begin{gathered} \frac{8b}{8}=\frac{4}{8} \\ b=\frac{4}{8} \end{gathered}[/tex]
Dividing the numerator and the denominator by 4:
[tex]\begin{gathered} b=\frac{\frac{4}{4}}{\frac{8}{4}} \\ b=\frac{1}{2} \end{gathered}[/tex]Answer:
[tex]b=\frac{1}{2}[/tex]1. Predict what will happen when a tape diagram has a large number of squares, some squares are removed, and thenthe same amount of squares are added back on.Build a tana diagram mit 10
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When some squares are removed, the number of squares in the tape diagram are reduced but when the same number of squares are added back, then we will find out that the number of squares in the tape diagram remain the same.
the probability that describe the related frequency of actual observation of an event is an experiment is which of the following
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The relative frequency is an empirical probability. So, the answer is the first option
Any answer?? I'm struggling to find the answer to this equation
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The last option is the correct answer ( no solution)
what are 4 numbers that are divisible by both 4 and 6
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We need 4 numbers that are divisible by 4 and 6 at the same time, so the first number will be the multiplication of them:
[tex]4\cdot6=24[/tex]Now wecan multiply this new number for 4 or for 6 to get other two numbers:
[tex]\begin{gathered} 24\cdot4=96 \\ 24\cdot6=144 \end{gathered}[/tex]and finally we can multiply 96 for 4 to get the last number:
[tex]96\cdot4=384[/tex]these four numbers works
Solve by substitution method. a) x + y = 8 and x - y = 4
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Answer:
x = 6
y = 2
Step-by-step explanation:
x + y = 8 ---> (1)
x - y = 4 ---> (2)
First, let us find the value of x.
For that, add both equations.
(1) + (2)
x + y + ( x - y ) = 8 + 4
Solve the brackets.
x + y + x - y = 8 + 4
2x = 12
Divide both sides by 2.
x = 6
Now let us find the value of y.
For that, let us use equation 1 and replace x with 6.
x + y = 8
6 + y = 8
Subtract 6 from both sides.
y = 8 - 6
y = 2
A manufacturer knows that their items have a normally distributed lifespan, with a mean of 3.5 years, and standarddeviation of 0.6 years.The 10% of items with the shortest lifespan will last less than how many years?[1])])1)Give your answer to one decimal place.
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1) In this question, we need to make use of a standard normal table to check which is the value (in terms of Z-score) for that 10%.
2) Checking that out, we can see that the Z-score is -1.282. So now, let's plug that into the Z-score formula so that we get the corresponding raw value:
[tex]\begin{gathered} Z=\frac{X-\mu}{\sigma} \\ -1.282=\frac{X-3.5}{0.6} \\ X=2.73\approx2.7 \end{gathered}[/tex]Thus, this is the answer: 2.7 years
Which additional piece of information would you need to prove these two triangles are congruent using the side-side-side or SSS triangle congruence postulate?
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By using congruency of triangles, the result obtained is
The additional information needed to make [tex]\Delta STU \cong \Delta SHU[/tex] by SSS axiom is
TU = SH
Side SH is congruent to side TU
Third option is correct
What is Congruency of triangles?
Two triangles are said to be congruent if the corrosponding sides and corrosponding angles are same.
The different axioms of congruency are SSS axiom, SAS axiom, ASA axiom, AAS axiom, RHS axiom
In [tex]\Delta STU[/tex] and [tex]\Delta SHU[/tex]
ST = HU [Given]
SU is common.
The additional information needed to make [tex]\Delta STU \cong \Delta SHU[/tex] by SSS axiom is
TU = SH
Side SH is congruent to side TU
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15x+3x^2+55x^2+3x+155+3x+15x^2which is written in standard form.
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ANSWER
[tex]5x^{2}+3x+15[/tex]EXPLANATION
A standard quadratic equation must be of the form;
[tex]ax^2+bx+c=0[/tex]Hence, the standard equation is;
[tex]5x^2+3x+15[/tex]3x-8=2x+18Solve for x
Answers
x=26
Explanation
[tex]3x-8=2x+18[/tex]Step 1
subtract 2x in both sides
[tex]\begin{gathered} 3x-8=2x+18 \\ 3x-8-2x=2x+18-2x \\ x-8=18 \end{gathered}[/tex]Step 2
add 8 in both sides
[tex]\begin{gathered} x-8=18 \\ x-8+8=18+8 \\ x=26 \end{gathered}[/tex]I hope this helps you
Which one of the following equations could describe the above graph?OA. Y=1.5^(x+2)-3OB. Y=2^x+6Oc. = y=(1/2)^x+6D. Y= 3^(x-1)
Answers
Given:
The points lie on the graph are (1,1) and (2,3).
Required:
We need to find the equation of the given graph.
Explanation:
Consider the individual equation.
A.
[tex]y=1.5^{(x+2)}-3[/tex]Substitute x =1 and y =1 in the equation.
[tex]1=1.5^{(1+2)}-3[/tex][tex]1=0.375[/tex]This is not true,
This is not a required equation.
B.
[tex]y=2^x+6[/tex]Substitute x =1 and y =1 in the equation.
[tex]1=2^1+6[/tex][tex]1=8[/tex]This is not true,
This is not a required equation.
C.
[tex]y=(\frac{1}{2})^x+6[/tex]Substitute x =1 and y =1 in the equation.
[tex]1=(\frac{1}{2})^1+6[/tex][tex]1=6.5[/tex]This is not true,
This is not a required equation.
D.
[tex]y=3^{(x-1)}[/tex]Substitute x =1 and y =1 in the equation.
[tex]1=3^{(1-1)}[/tex][tex]1=1[/tex]This is true.
Substitute x =2 and y =3 in the equation.
[tex]3=3^{(2-1)}[/tex][tex]3=3[/tex]This is true.
This is a required equation.
Final answer:
[tex]y=3^{(x-1)}[/tex]I think I got the two that I did but I’m not sure and really need help
Answers
b) You have the following expression:
[tex]x^3=\frac{27}{64}[/tex]Take into account that 27/64 can be written as follow:
[tex]\frac{27}{64}=\frac{3}{4}\cdot\frac{3}{4}\cdot\frac{3}{4}[/tex]Then, x = 3/4
c) For the following expression:
[tex]x^3=\frac{1}{8}[/tex]you can write it as follow:
[tex]\frac{1}{8}=\frac{1}{2}\cdot\frac{1}{2}\cdot\frac{1}{2}[/tex]Then, x = 1/2
. Find an ordered pair that represents a solution to the equation x + 2y = 20
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we have
x + 2y = 20
The linear equation represent the equation of a line
If a ordered pair is a solution of the equation, that means that the ordered pair lies on the line
so
Find a ordered pair that represents a solution
Assume the value of x
so
For x=1
substitute in the equation
(1)+2y=20
solve for y
2y=20-1
2y=19
y=19/2
y=9.5
therefore
The ordered pair (1,9.5) represents a solutionIn a game, 2 players each flip a coin. If both land on heads, player A gets 2points and player B loses 1 points. If both land on tails, player B gets 2 points andplayer A loses 1 point. Find the expected value of the game for each player.
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The expected value for player A is:
[tex]\begin{gathered} (\frac{1}{2}\times\frac{1}{2}\times2)-(1\times\frac{1}{2}\times\frac{1}{2}) \\ =(\frac{1}{4}\times2)-(1\times\frac{1}{4}) \\ =(\frac{1}{2})-(\frac{1}{4}) \\ =\frac{1}{4} \end{gathered}[/tex]The expected value of player B is:
[tex]\begin{gathered} (\frac{1}{2}\times\frac{1}{2}\times2)-(1\times\frac{1}{2}\times\frac{1}{2}) \\ =(\frac{1}{4}\times2)-(1\times\frac{1}{4}) \\ =(\frac{1}{2})-(\frac{1}{4}) \\ =\frac{1}{4} \end{gathered}[/tex]the minimum point on the graph of the equation y = f(x) is (-1,-3). what is the minimum point on the graph of the equation y=f(x)+5?
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the minimum point on the graph of the equation y = f(x) is (-1,-3). what is the minimum point on the graph of the equation y=f(x)+5?
we have that
the rule of this transformation is equal to
(x,y) ------> (x, y+5)
so
(-1,3) -----> (-1,3+5)
(-1,8) is the minimum pointWhat was the median price of new home in 1981
Answers
1) In this question, let's spot in the graph the median price given by the blue curve on the graph.
2) Examining it we can see that the y-axis point that corresponds to the Median Price in 1981 is:
[tex]\$70,000[/tex]