Mathematics College

[the ending was select all that apply ] can somebody help me with this with an explanation on how to do it?

Answers

Answer 1

Answer: the goal is to isolate the variable so the answer is 12

Step-by-step explanation:

Related Questions

write a polynomial function of least degree with integral coefficients that had the given zeros. -3,3,-2

Answers

x³ + 2x² - 9x - 18 is the polynomial function of least degree with integral coefficients that had the zeros -3 , 3 , -2.

Given, the zeros of a polynomial be,

-3 , 3 and -2

As, the polynomial has 3 zeros then the degree of the polynomial is also be , 3.

Let the polynomial be,

p(x) = (x - (-3))(x - 3)(x - (-2))

p(x) = (x + 3)(x - 3)(x + 2)

On multiplying the factors, we get

p(x) = (x² - 3²)(x + 2)

p(x) = (x² - 9)(x + 2)

p(x) = (x³ - 9x + 2x² - 18)

p(x) = x³ + 2x² - 9x - 18

So, x³ + 2x² - 9x - 18 is the polynomial function of least degree with integral coefficients that had the zeros -3 , 3 , -2.

Hence, x³ + 2x² - 9x - 18 is the polynomial function of least degree with integral coefficients that had the zeros -3 , 3 , -2.

Learn more about Polynomials here https://brainly.com/question/23974386

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Simplify 5(3p - 2) + 2(p +4)

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[tex]5\mleft(3p-2\mright)+2\mleft(p+4\mright)\text{ = 17p-2}[/tex]

Here, we want to simplify the expression

To do this, we shall use the term outside the bracket to multiply the terms inside the brackets before we proceed to add them together

We have this as follows;

[tex]\begin{gathered} (5\times3p)-(5\times2)\text{ + (2}\times p_{})\text{ + (2}\times4) \\ =\text{ 15p - 10 + 2p + 8} \\ =\text{ 15p}+2p-10+8 \\ =\text{ 17p -2} \end{gathered}[/tex]

Simplify 5(3p-2) +2(p+4)
15p - 10 +2p+8
17p-2

Given:• VU is tangent to Circle Q• UV = 20• UT = 8U2000TSFind the length of the radius of the circle.6O 1202142

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To solve this question and find the radius of the circle, we will use the s

11) Tell whether (3, 20) is a solution of y = 4x +8 A) Yes B) No

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y = 4x + 8

To tell if (3, 20) is a solution, we will substitute the value of x = 3 and y= 20

into the equation to see if the left-hand side equals the right-hand side of the equation

So, upon substituting

20 = 4 x 3 + 8

20 = 12 + 8

20 = 20

Since the left-hand side of the equa

can you break it down and help me out please?

Answers

Given

[tex]x^2+x-2\ge0[/tex]

To find the solution.

Now,

It is given that,

[tex]x^2+x-2\ge0[/tex]

Using factorization method,

[tex]\begin{gathered} x^2+x-2=0 \\ x^2-x+2x-2=0 \\ x(x-1)+2(x-1)=0 \\ (x+2)(x-1)=0 \end{gathered}[/tex]

That implies,

[tex]\begin{gathered} x+2\ge0,x-1\ge0 \\ x\ge-2,x\ge1 \end{gathered}[/tex]

Hence, the solution set is,

[tex]undefined[/tex]

find 264 + 638 using drawings of place value blocks. please show the work

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

264 + 638

Step 02:

place value blocks

264

+ 638

_______

902

That is the full solution.

what is the surface area for a m rectangular prism. with the measurements as: height = 9 length = 3width = 7

Answers

Answer:

Surface area = 222 square cm

Explanation:

Given the following data

Length = 3 cm

Height = 9 cm

Width = 7 cm

Surface area = 2(wl + hl + hw)

Surface area = 2(7 * 3 + 9 * 3 + 9 * 7)

Surface area = 2( 21 + 27 + 63)

Surface area = 2( 111)

Surface area = 222 square cm

Therefore, the surface area is 222 square cm

I need help with math

Answers

We have the following problem:

Using the kinematic equation, we know that for movements with constant acceleration the position is

[tex]h(t)=h_0+v_0t-\frac{gt^2}{2}[/tex]

I already wrote the variables convenient for our problem, where

t = time (s)

h₀= initial height (m)

v₀ = initial velocity (m/s)

g = gravity acceleration (m/s²)

h = height after t seconds

We also know that

t = independent variable

h₀= 10m

v₀ = 56 m/s

g ≅ 10 m/s²

h = dependent variable

Therefore our quadratic will be

[tex]\begin{gathered} h(t)=10+56t-\frac{10t^2}{2} \\ \\ h(t)=10+56t-5t^2 \end{gathered}[/tex]

Now we can answer the question in fact.

The rocket will hit the ground when the height is equal to zero, hence, h(t) = 0. In fact, we are looking for the zeros of the quadratic

[tex]\begin{gathered} 10+56t-5t^2=0 \\ \\ t=\frac{-56\pm\sqrt{56^2-4\cdot(-5)\cdot(10)}}{2\cdot(-5)} \\ \\ t=\frac{-56\pm\sqrt{3136+200}}{-10} \\ \\ t=\frac{56\pm\sqrt{3336}}{10} \\ \\ t=11.38\text{ s or }-0.18\text{ s} \end{gathered}[/tex]

See that we have one negative zero, but we will ignore that because it's physically impossible, therefore the rocker will reach the ground after 11.38 seconds

To find the maximum height we must find the max value of the quadratic, we know that the vertex of a quadratic is its max/min, also, we can write it as

[tex]\begin{gathered} y_V=-\frac{\Delta}{4a} \\ \\ x_V=-\frac{b}{2a} \end{gathered}[/tex]

Where

[tex](x_V,y_V)[/tex]

Is the vertex. Here, we want to find the y coordinate, because y here is the height, therefore

[tex]\begin{gathered} \max h=-\frac{\Delta}{4a} \\ \\ \operatorname{\max}h=-\frac{3336}{4\cdot(-5)} \\ \\ \operatorname{\max}h=\frac{3336}{20} \\ \\ \operatorname{\max}h=166.8\text{ m} \end{gathered}[/tex]

The max height of the rocket is 166.8m

Now we have a similar problem, it's also the vertex but now the coordinate x, that here, represents the time, then

[tex]\begin{gathered} t_{\max}=\frac{-b}{2a} \\ \\ t_{\operatorname{\max}}=\frac{-56}{2\cdot(-5)} \\ \\ t_{\operatorname{\max}}=\frac{56}{10} \\ \\ t_{\operatorname{\max}}=5.6\text{ s} \end{gathered}[/tex]

The rocket will reach the maximum height after 5.6 seconds.

The circumference of a big circle is 36 pi. The area of a smaller circle located inside the bigger circle is 16 pi. If you randomly pick a point inside the big circle, what is the probability the point lands in the smaller one?

Answers

Given:

a.) The circumference of a big circle is 36 pi.

b.) The area of a smaller circle located inside the bigger circle is 16 pi.

The probability that the point lands in the smaller one is,

[tex]\text{ Probability = }\frac{Area_{Small\text{ Circle}}}{Area_{Big\text{ Circle}}}[/tex]

However, only the circumference of the big circle is given. To be able to get the probability, we must first determine the area of the circle.

a.) Area of the big circle.

[tex]\begin{gathered} \text{ Circumference = }2\pi r \\ 36\pi\text{ = 2}\pi r \\ \frac{36\pi}{2\pi}\text{ = r} \\ 18\text{ = r} \end{gathered}[/tex][tex]\begin{gathered} \text{ Area = }\pi r^2 \\ \end{gathered}[/tex][tex]\begin{gathered} \text{ = }\pi(18)^2 \\ \text{ = }\pi(324) \\ \text{ Area = 324}\pi \end{gathered}[/tex]

b.) Let's now determine the probability.

[tex]\text{ Probability = }\frac{Area_{Small\text{ Circle}}}{Area_{Big\text{ Circle}}}[/tex][tex]\text{ = }\frac{16\pi}{324\pi}[/tex][tex]\text{ = }\frac{16}{324}\text{ = }\frac{\frac{16}{4}}{\frac{324}{4}}\text{ = }\frac{4}{81}[/tex][tex]\text{ Probability = }\frac{4}{81}[/tex]

Therefore, the probability that the point lands in the smaller one is 4/81.

PLEASE HELP. FUNCTIONS AND RELATIONS. The height of a model rocket, h(t), is a function of the time since it was launched, t. What is the domain of h(t)?

Answers

Recall that the domain is all the values of the graph from left to right.

From the given graph we get that its domain consists of all values greater than or equal to 0 and less than or equal to 42.

Then the domain of the given function in algebraic notation is:

[tex]0\leq t\leq42.[/tex]

Answer: Option D.

Cuánto es 71/4 menos un entero 3/4

Answers

7 1/4 - 1 3/4

[tex]7\frac{1}{4}-1\frac{3}{4}=\frac{28+1}{4}-\frac{4+3}{4}=\frac{29}{4}-\frac{7}{4}=\frac{22}{4}=5\frac{2}{4}=5\frac{1}{2}[/tex]

Respuesta:

5 1/2

[tex]5\frac{1}{2}[/tex]

Please help me on the question I don’t get it c) For architects, by what percent did the median earnings increase for those who held a graduate degree compared to those who were recent college graduates? (round to the nearest integer)d) For nurses, by what percent did the median earnings increase for those who held a graduate degree compared to those who were recent college graduates? (round to the nearest integer)

Answers

(a) From the graph, the average recent college graduate engineer makes $65000, and the average recent college graduate accountant makes $40000. Therefore, an engineer makes $65000 - $40000 = $25000 more than the accountant.

(b) In marketing, the average graduate degree holder makes approximately $80000 (rounded down to the nearest thousand), and the average recent college graduate makes approximately $35000 (rounded down to the nearest thousand). Therefore, the average graduate degree holder makes $80000 - $35000 = $45000 more than the average recent college graduate

(c) graduate degree holder architect average earning: $75000 (rounded down to the nearest thousand)

average recent college graduate architect average earning: $35000 (rounded down to the nearest thousand)

The percent increase is computed as follows:

[tex]\begin{gathered} \text{percent increase = }\frac{\text{ degr}ee\text{ holder - college graduate}}{\text{college graduate}}\cdot100 \\ \text{percent increase = }\frac{75000-35000}{35000}\cdot100 \\ \text{percent increase }\approx114\text{ \%} \end{gathered}[/tex]

(d) graduate degree holder nurse average earning: $ 80000 (rounded down to the nearest thousand)

average recent college graduate nurse average earning: $45000 (rounded down to the nearest thousand)

The percent increase is computed as follows:

[tex]\begin{gathered} \text{percent increase = }\frac{\text{ degr}ee\text{ holder - college graduate}}{\text{college graduate}}\cdot100 \\ \text{percent increase = }\frac{80000-45000}{45000}\cdot100 \\ \text{percent increase = 78 \%} \end{gathered}[/tex]

(e) Comparison between average earning of a degree holder and of a college graduate for each area:

Engineers