Hello looking for someone to help me out on this question

Hello Looking For Someone To Help Me Out On This Question

Answers

Answer 1

Answer

The value of x = 14

m∠T = 65°

m∠S = 30°

m∠R = 85°

Explanation

From the given ΔRST,

m∠T + m∠S + m∠R = 180° (Sum of angles in a triangle)

m∠T = (4x + 9)°, m∠S = (2x + 2)° and m∠R = (7x - 13)°

⇒(4x + 9)° + (2x + 2)° + (7x - 13)° = 180°

Grouping the terms, we have

4x + 2x + 7x + 9 + 2 - 13 = 180°

13x - 2 = 180°

13x = 180 + 2

13x = 182

Divide both sides by 13

13x/13 = 182/13

x = 14

Therefore,

m∠T = (4x + 9)° = (4(14) + 9)° = (56 + 9)° = 65°

m∠S = (2x + 2)° = (2(14) + 2)° = (28 + 2)° = 30°

m∠R = (7x - 13)° = (7(14) - 13)° = (98 - 13)° = 85°


Related Questions

which choice is equivalent to the quotient below? sqrt 7/8* sqrt7/187/16/121/23/47/12

Answers

We can apply the following properties of radicals:

[tex]\begin{gathered} \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\Rightarrow\text{ Product property} \\ \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}\Rightarrow\text{ Quotient property} \end{gathered}[/tex]

Then, we have:

[tex]\begin{gathered} \text{ Apply the product property} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{7}{8}\cdot\frac{7}{18}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{7\cdot7}{8\cdot18}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{49}{144}} \\ \text{ Apply the quotient property} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\frac{\sqrt[]{49}}{\sqrt[]{144}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\frac{7}{12} \end{gathered}[/tex]

Therefore, the choice that is equivalent to the given product is:

[tex]\frac{7}{12}[/tex]

Write using an exponent: 1×7×7×7×7×7a. 1×7×5b.[tex]1 \times {7}^{5} [/tex]c. [tex]1 \times {5}^{7} [/tex]

Answers

In the expression, the number 7 is multiplied to itself 5 times or five 7's are multiplied with each other. So exponential expression for the equation is,

[tex]1\cdot7\cdot7\cdot7\cdot7\cdot7=1\cdot7^5[/tex]

Option B is correct.

Runner A averages 5 miles per hour, and Runner B averages 6 miles per hour. At these rates, how much longer does it take Runner A than Runner B to run 15
miles?
1 hour
Shour
2.5 hours
1.5 hours
3 hours

Answers

If Runner A averages 5 miles per hour, and Runner B averages 6 miles per hour. At these rates, then it took 3 hours for runner A.

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

Given,

Runner A averages 5 miles per hour, and

Runner B averages 6 miles per hour.

The time required for A to complete 15 miles is

15/5=Time

3 hrs

Hence Runner A needs 3 hours to run 15 miles.

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Yoko, Austin, and Bob have a total of $57 in their wallets. Austin has $7 less than Yoko. Bob has 2 times what Yoko has. How much does each have?

Answers

Yoko has $16 money, Austin has $9 and Bob has $32.

According to the question,

We have the following information:

Yoko, Austin, and Bob have a total of $57 in their wallets. Austin has $7 less than Yoko. Bob has 2 times what Yoko has.

Now, let's take the money Yoko has to be $x.

So, we have the following expressions for the money Austin and Bob have:

Austin = $(x-7)

Bob = $(2x)

Now, we have the following expression by adding them:

x+x-7+2x = 57

4x-7 = 57

4x = 57+7

4x = 64

x = 64/4

x = $16

Now, the money Austin has:

16-7

$9

Money Bob has:

2*16

$32

Hence, Yoko has $16 money, Austin has $9 and Bob has $32.

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Draw the dilation of PQRS using center Q and scale factor 1/2. Label the dilation TUWX. 2. Draw the dilation of PQRS with center R and scale factor 2. Label the dilation ABCD. 3. Show that TUWX and ABCD are similar.

Answers

Based on the given image, you obtain the following figures:

Draw the dilation of PQRS using center Q and scale factor 1/2

Draw the dilation of PQRS with center R and scale factor 2. Label the dilation ABCD

You can notice that both figure TUWX and ABCD are similar because the quotient between sides TU and PQ, XW and RS, UW and BC, TX and AD are the same.

What does the constant 1.6 reveal about the rate of change of the quantity?

Answers

The form of the exponential growth/decay function is

[tex]f(x)=a(1\pm r)^x[/tex]

a is the initial amount

r is the rate of growth/decay per x years

We use + with growth and - with decay

Since the given function is

[tex]f(t)=2700(1.6)^{7t}[/tex]

Where t is time per week

Compare the two functions

[tex]\begin{gathered} a=2700 \\ (1+r)=1.6 \\ x=7t \end{gathered}[/tex]

Since 1.6 is greater than 1, then

The function is growth

Equate 1.6 by (1 + r) to find r

[tex]\begin{gathered} 1+r=1.6 \\ \\ 1-1+r=1.6-1 \\ \\ r=0.6 \end{gathered}[/tex]

Change it to percent by multiplying it by 100%

[tex]\begin{gathered} r=0.6\times100\text{ \%} \\ \\ r=60\text{ \%} \end{gathered}[/tex]

Since x = 7t then the time is every 7 weeks

The answer is

The function is growing exponentially at a rate of 60% every 7 weeks

Part B: select the box or boxes under the coordinate pairs the represent solutions for the system.

Answers

The given system of inequalities is

[tex]\begin{gathered} y>\frac{3}{2}x-2 \\ y\leq-3x-4 \end{gathered}[/tex]

The area of the solution is the area shaded by the 2 colors

Let us check the points

(-2, -5) it lies on the red dashed line

Since the line is dashed, then the points lie on it do not belong to the solution, then

(-2, -5) does not belong to the solution

(-2, -5) is not a solution

(-2, 2) it lies on the blue line

Since the line is solid, then the points that lie on it belong to the solution, then

(-2, 2) is a solution

(0, -4) it is out of the area of both colors, then

(0, -4) is not a solution

(-3, -1) it lies in the area of the common colors, then

(-3, -1) is a solution

(-1, 4) it is out the area of both colors, then

(-1, 4) is not a solution

(-20, 15) is in the area of the common colors, then

(-20, 15) is a solution

(15, 20) it is out the area of both colors, then

(15, 20) is not a solution

Then the solutions of the system are:

(-2, 2), (-3, -1), (-20, 15)

Is (4,-3) a solution to the following system of equations?X - y = 42x + y = 5

Answers

Answer:

No, (4, -3) is not a solution to the system of equations

Explanation:

If (4, -3) is a solution to the given system of equations, then

for x = 4, and y = -3, both of the equations are satisfied.

x - y = 4 - (-3)

= 4 + 3

= 7

This is not 4, so the first equation is not satisfied

2x + y = 2(4) + (-3)

= 8 - 3

= 5

This equation is satisfied

It is sufficient to conclude that (4, -3) is not a solution to the system of equations since it doesn't satisfy the first equation

Jessica borrowed $1,450 for three months at an annual rate of 8.75%under a single-payment plan. How much interest must she pay?a. $0.30b. $31.72c. $4,893.75d. $108.75

Answers

Given:

Principal amount (P)= $1450

Rate (R) = 8.75%

Time (T)= 3 months

The interest is given by the formula,

[tex]\begin{gathered} I=\frac{P\times R\times T}{100\times12} \\ =\frac{1450\times8.75\times3}{100\times12} \\ =31.71875 \end{gathered}[/tex]

it's late but I need help

Answers

Data:

X = weight of the puppy at thefirst visit

Choose the expression that is equal to 28.3A. 3³+27.2-6.8+2⁴-3.1B. 3³+27.2-(6.8+2⁴-3.1)C. [3³+(27.2-6.8)]+2⁴-3.1D. 3³+27.2-(6.8+2⁴)-3.1

Answers

solution

For this case we can solve each case and we have:

A) 27 +27.2 -6.8 +16 -3.1= 60.3

B) 27 +27.2 -(6.8 +16 -3.1)= 54.2- 19.7= 34.5

C) 27 + 20.4 +16 -3.1= 30.1

D) 27 +27.2 - 22-8 -3.1= 28.3

then the correct solution for this case would be:

D)

Are the graphs of the equations parallel, perpendicular, or neither? y= 2x +6 and y= 1/2x +3

Answers

Given the equations:

[tex]\begin{gathered} y=2x+6 \\ y=\frac{1}{2}x+3 \end{gathered}[/tex]

The equation has the form of slope - intercept form which is like:

[tex]y=m\cdot x+b[/tex]

Where m is the slope and b is y- intercept

So,

The slope of the first equation = 2

The slope of the second equation = 1/2

The graphs of the equations are parallel when the slopes are equal

The graphs of the equations are perpendicular when the product of the slopes = -1

so,

the slopes are not equal

The product of the slopes = 2 * 1/2 = 1

So, the graphs of the equations are neither parallel nor perpendicular.

3, -9, 27, -81,..... common difference/ratiod = 3r = 9r = -3 d = 12

Answers

To find the common ratio we divide the terms by the previous one. In this case we have:

[tex]-\frac{9}{3}=-3[/tex][tex]\frac{27}{-9}=-3[/tex][tex]-\frac{81}{27}=-3[/tex]

Therefore, the common ratio is r=-3.

The following data for a random sample of banks in two cities represent the ATM fees for using another bank's ATM. Compute the sample variance for ATM fees for each city.City A1.25 1.00 1.50 1.25 1.50City B2.50 1.25 1.00 0.00 2.00The variance for city Ais $(Round to the nearest cent as needed.)

Answers

City A (n = 5)

1.25 1.00 1.50 1.25 1.50

City B

2.50 1.25 1.00 0.00 2.00

The variance formula is:

So, the mean A is:

(1.25 + 1.00 + 1.50 + 1.25 + 1.50)/5 = 1.30

The variance for city A is:

s²_A = 0.04

For city B:

Mean B = 1.35

The variance for city B is:

s²_B = 0.92

find the mean the median the mode range and standard invitation of each data set that is obtained after adding the given content to each value (number 1)

Answers

Answers:

Mean = 43.7

Median = 44.5

Mode = doesn't exist

Standard deviation = 4.78

Explanation:

First, we need to add the constant to each value, so the new data is:

33 + 11 = 44

38 + 11 = 49

29 + 11 = 40

35 + 11 = 46

27 + 11 = 38

34 + 11 = 45

36 + 11 = 47

28 + 11 = 39

41 + 11 = 52

26 + 11 = 37

Now, we can organize the data from least to greatest as:

37 38 39 40 44 45 46 47 49 52

Then, the mean is the sum of all the numbers divided by 10, because there are 10 values in the data. So, the mean is:

[tex]\begin{gathered} \operatorname{mean}=\frac{37+38+39+40+44+45+46+47+49+52}{10} \\ \operatorname{mean}=43.7 \end{gathered}[/tex]

The median is the value that is located in the middle position of the organized data. Since there are 10 values, the values in the middle are the numbers 44 and 45, so the median can be calculated as:

[tex]\operatorname{median}=\frac{44+45}{2}=44.5[/tex]

The mode is the value that appears more times in the data. Since all the values appear just one time, the mode doesn't exist.

To calculate the standard deviation, we will calculate first the variance.

The variance is the sum of the squared difference between each value and the mean, and then we divided by the number of values. So, the variance is equal to:

[tex]\begin{gathered} (37-43.7)^2+(38-43.7)^2+(39-43.7)^2+(40-43.7)^2+ \\ (44-43.7)^2+(45-43.7)^2+(46-43.7)^2+(47-43.7)^2+ \\ (49-43.7)^2+(52-43.7)^2=228.1 \end{gathered}[/tex][tex]\text{Variance}=\frac{228.1}{10}=22.81[/tex]

Finally, the standard deviation is the square root of the variance, so the standard deviation is:

[tex]\text{standard deviation =}\sqrt[]{22.81}=4.78[/tex]

neeed double chedking on this

Answers

The area will be the area of the blue part minus the area of the white part:

9(8)-5(3)=72-15= 57 square centimeters

Which inequality is represented by the graph

Answers

The inequality 4x - 2y < 12 is represented by the attached graph. which is the answer would be an option (B).

What is inequality?

Inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.

As per option (B),

4x - 2y < 12

We can see that the x-intercept is (0, -6), and the y-intercept is (2.5, 0) in the given graph which is determined by substituting the value of x and y is equal to 0 in the equation 4x - 2y = 12.

The inequality 4x - 2y < 12 is represented by the attached graph.

Hence, the answer would be option (B).

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.Find the side of a square whose diagonal is of the given measure.Given = ft.

Answers

see the figure below to better understand the problem

In the given square ABCD

Apply the Pythagorean Theoren in the right triangle BDC

[tex]\begin{gathered} D^2=a^2+a^2 \\ D^2=2a^2 \\ we\text{ have} \\ D=12\sqrt{10}\text{ ft} \end{gathered}[/tex]

Substitute given value

[tex]\begin{gathered} (12\sqrt{10})^2=2a^2 \\ 144(10)=2a^2 \\ 2a^2=1,440 \\ a^2=720 \\ a=\sqrt{720}\text{ ft} \end{gathered}[/tex]

Simplify

[tex]a=12\sqrt{5}\text{ ft}[/tex]

5. Use the equation E =- my?my where E is kinetic energy, m is the mass of an object, and v is the object'svelocityLet E = 100, 000 J and v = 24 m/s. Find the object's mass.Show your work here:Choose the correct answer:173.6 kg86.8 kg8333.3 kg347.2 kg

Answers

In general, the kinetic energy is given by the formula below

[tex]E=\frac{1}{2}mv^2[/tex]

Where m is the mass and v is the speed of the object.

Therefore, in our case,

[tex]\begin{gathered} E=100000,v=24 \\ \Rightarrow100000=\frac{1}{2}m(24)^2 \end{gathered}[/tex]

Solve for m as shown below

[tex]\Rightarrow m=\frac{200000}{576}=347.2222\ldots[/tex]

Thus, the answer is 347.2 kg, approximately.

Zach puts $1000 into a savings account earning 5% compound interest for 5 years. How much
interest has Zach earned at the end of the the 5 years?
$_______
Do not enter the dollar sign as part of your answer

Answers

The amount of interest Zach earn in 5 years given the principal and interest rate compounded for 5 years is 276.3

What is the amount of interest Zach earned?

A = P(1 + r/n)^nt

Where,

A = principal + interestPrincipal, P = $1000Interest rate, r = 5% = 0.05Time, t = 5 yearsNumber of periods, n = 1

A = P(1 + r/n)^nt

= 1000(1 + 0.05/1) ^(1×5)

= 1000(1 + 0.05) ^5

= 1000(1.05)^5

= 1000(1.2762815625)

= 1,276.2815625

Approximately,

1,276.3

Hence,

A = principal + interest

1, 276.3 = 1000 + interest

1276.3 - 1000 = interest

Interest = 276.3

Therefore, the amount of interest earned in 5 years is 276.3

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From a window 100ft above the ground in building A, the top and bottom of building B are sighted so that the angles are 70 degrees and 30 degrees respectively. Find the height of building B?

Answers

Given:-

From a window 100ft above the ground in building A, the top and bottom of building B are sighted so that the angles are 70 degrees and 30 degrees respectively.

To find:-

The height of building B.

So now, the image of the given data is,

So now we find the value of PS. so we get,

[tex]\begin{gathered} \tan \text{ 30=}\frac{100}{PS} \\ \frac{1}{\sqrt[]{3}}=\frac{100}{PS} \\ PS=100\sqrt[]{3} \end{gathered}[/tex]

So now we find the height of QS,

[tex]\begin{gathered} \tan \text{ 70=}\frac{QS}{PS} \\ 2.7474=\frac{QS}{100\sqrt[]{3}} \\ QS=100\sqrt[]{3}\times2.7474 \\ QS=475.84 \end{gathered}[/tex]

So the total height is,

[tex]100+475.84=575.84[/tex]

So the height of building B is 575.84

Find the value of x and y.

Answers

These 3 angles are equal value

5x + 1 = 6x - 10 = y

Then

5x + -6x = -10 - 1

-x = 11

x= 11

NOW find y value

y = 5x + 1

y= 6x - 10

y = 5•( 11) + 1= 56

y= 6•( 11) -10= 56

Answer is y= 56

Suppose someone wants to accumulate $120,000 for retirement in 30 years. The person has two choices. Plan A is a single deposit into an account with annual compounding and an APR of 6%. Plan B is a single deposit into an account with continuous compounding and an APR of 5.8%. How much does the person need to deposit in each account in order to reach the goal?The person must deposit $______ into the account for Plan A to reach the goal of $.The person must deposit $______ into the account for Plan B to reach the goal of $.(Round to the nearest cent as needed.)

Answers

We want to calculate the amount needed as an initial investment to have 120000 after 30 years.

Recall that the formula of annual compounding is given by the formula

[tex]S\text{ =}P\text{ \lparen1+r\rparen}^t[/tex]

where P is the principal, r is the interest rate and t is the time in years. When compounded continously the formula is

[tex]S=Pe^{rt}[/tex]

where the variables have the same meaning. In both cases we want to find P sucht that

[tex]S=120000[/tex]

when t=30 and r is the interest rate that we are given.

So we have the following equation in the first case

[tex]120000=P\text{ \lparen1+}\frac{6}{100})^{30}[/tex]

so if we divide both sides by (1+6/100)^30 we get

[tex]P=\frac{120000}{(1+\frac{6}{100})^{30}}\approx20893.22[/tex]

so for Plan A 20893.22 is needed to have 120000 after 30 years.

now, we want to do the same with the second plan. We have

[tex]120000=Pe^{\frac{5.8}{100}30}[/tex]

so we divide both sides by exp(5.8*30/100). So we get

[tex]P=\frac{120000}{e^{\frac{5.8}{100}\cdot30}}\approx21062.45[/tex]

so for Plan B 21062.45 is needed to have 120000 after 30 years

Find the coordinates of the midpoint between (8, 1) and (0, - 9). F. (4, -5) G. (4, -4) H. (8, -5) J. (8, -8)

Answers

MidpointAnswer

(4, -4)

Explanation

In order to find the midpoint between two points we have to obtain the midpoint horizontally and vertically.

In this case, we have:

Given the diagram shown, which of the following statements are true.

Answers

I,II

1) Since in this diagram we have two triangles, whose sides AI and LH are parallel to each other we can state the following:

2) And since similar triangles have congruent angles and proportional sides, we can state as true the following:

I.∠JHL ≅ ∠JIK Similar triangles have congruent angles

As they are similar triangles we can write out the following ratios:

[tex]\frac{JI}{JH}=\frac{JK}{JL}[/tex]

These are true

And the third is not correct.

3) Hence, the answer is I,II

Kevin and Randy have a jar containing 67 coins all of which are either quarters or nickels. The total value of the coins in the jar $12.75 ... how many of each type of coin do they have?

Answers

Answer:

47quarters and 20 nickel

Explanation:

Let the number of quarters be x

Let the number of nickels be y

If there are 67 coins in the jar, then;

x + y = 67 ....1

1 quarter = 0.25x

1 nickel = 0.05y

If the total value of the coins in the jar is $12.75, then;

0.25x + 0.05y = 12.75 ....2

Multiply through by 100

25x + 5y = 1275 ....2

Solve 1 and 2 simultaneously

x + y = 67 ....1 * 25

25x + 5y = 1275 ....2 * 1

Using Elimination method

________________________

25x + 25y = 1,675

25x + 5y = 1275

Subtract

25y - 5y = 1675 - 1275

20y = 400

y = 400/20

y = 20

Substitute y = 20 into equation 1;

From 1; x + y = 67

x + 20 = 67

x = 67 - 20

x = 47

This means there are 47quarters and 20 nickel.

Find the value of the test statistic z using z =P-Ppan37) A claim is made that the proportion of children who play sports is less than 0.5, and the sample statistics includen = 1158 subjects with 30% saying that they play a sport.Answer: - 13.6138) The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, andthe sample statistics include n = 647 drowning deaths of children with 30% of them attributable to beaches.Answer: 2.94

Answers

37. The given p-value is 0.5

Also the observed proportion is:

[tex]\hat{p}=30\%=0.3[/tex]

And q is (1-p), so:

[tex]q=1-0.5=0.5[/tex]

And the n-value is given 1158.

By replacing these values into the test statistic formula we obtain:

[tex]z=\frac{\hat{p}-p}{\sqrt[]{\frac{p\cdot q}{n}}}=\frac{0.3-0.5}{\sqrt[]{\frac{0.5\cdot0.5}{1158}}}=\frac{-0.2}{\sqrt[]{0.0002}}=\frac{-0.2}{0.015}=-13.61[/tex]

The answer is -13.61

I need to solve each system by graphing. so pls help! This is Algebra 1

Answers

Given the system of inequalities:

2x + 3y < -6

-2x + 3y < 6

Let's solve the system by graphing.

To graph, rewrite the inequalities in slope-intercept form:

y = mx + b

Inequality 1:'

Subtract 2x from both sides:

2x - 2x + 3y < -2x - 6

3y < -2x - 6

Divide all terms by 3:

[tex]\begin{gathered} \frac{3y}{3}<-\frac{2x}{3}-\frac{6}{3} \\ \\ y<-\frac{2}{3}x-2 \end{gathered}[/tex]

Inequality 2:

Add 2x to both sides:

-2x + 2x + 3y < 2x + 6

3y < 2x + 6

Divde all terms by 3:

[tex]\begin{gathered} \frac{3y}{3}<\frac{2x}{3}+\frac{6}{2} \\ \\ y<\frac{2}{3}x+2 \end{gathered}[/tex]

Now, let's plot 3 points from each inequlality and connect using a straight edge.

Inequality 1:

When x = -3

Substitute -3 for x and solve for y:

[tex]\begin{gathered} y<-\frac{2}{3}(-3)-2 \\ \\ y<2-2 \\ \\ y<0 \end{gathered}[/tex]

When x = 0:

[tex]\begin{gathered} y<-\frac{2}{3}(0)-2 \\ \\ y<-2 \end{gathered}[/tex]

When x = 3:

[tex]\begin{gathered} y<-\frac{2}{3}(3)-2 \\ \\ y<-2-2 \\ \\ y<-4 \end{gathered}[/tex]

From inequality 1, we have the points:

(x, y) ==> (-3, 0), (0, -2), (3, -4)

For inequlity 2:

When x = -3:

[tex]\begin{gathered} y<\frac{2}{3}(-3)+2 \\ \\ y<-2+2 \\ \\ y<0 \end{gathered}[/tex]

When x = 0:

[tex]undefined[/tex]

The sum of two consecutive integers is 17. Which equations could be used to find the twoconsecutive integers? Select all that are correct.A.X+X+1=17B.X+x=17C.2x=17D.2x+2=17E.X+X+2=17F.2x+1=17

Answers

hello

the answer to the question is option A

to solve a problem like this, let x represent the first number

x + (x + 1) = 17

x = first number

x + 1 = successive number

4) P(A) = 0.55 P(B) = 0.25 P(A and B) = ? *a.0.2b.0.21c.0.3d.0.1375

Answers

Since P (A and B) = P(A) · P(B)

Since P(A) = 0.55 and P(B) = 0.25, then

P(A and B) = 0.55 x 0.25

P(A and B) = 0.1375

The answer is d

Other Questions
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