Given the distance traveled by rocket is
[tex]D=5600[/tex]The time taken by the rocket is 3 hours.
[tex]T=3\text{ hours}[/tex]Calculate the speed of the rocket.
[tex]\begin{gathered} \text{Speed = }\frac{5600km}{3\text{ hours}} \\ \text{Speed = 1866.66 }\frac{km}{hr} \end{gathered}[/tex]Thus, the time taken by the rocket is 1866.66 km/hr.
A racecar travels around a circular track of radius 400 meters at constant speed. If the car's acceleration is 4 m/s2, what is its speed?
We are given that a car travels in a circular motion with an acceleration of 4m/s^2. We are asked to determine the speed of the motion. To do that we will use the following formula:
[tex]a=\frac{v^2}{r}[/tex]Where:
[tex]\begin{gathered} a=\text{ acceleration} \\ v=\text{ velocity} \\ r=\text{ radius} \end{gathered}[/tex]We will solve for the velocity first by multiplying both sides by "r":
[tex]ar=v^2[/tex]Now we take the square root to both sides:
[tex]\sqrt[]{ar}=v[/tex]Now we plug in the values:
[tex]\sqrt[]{(4\frac{m}{s^2})(400m)}=v[/tex]Now we solve the operations:
[tex]40\frac{m}{s}=v[/tex]Therefore, the velocity of the car is 40 meters per second.
On Earth, the gravitational force of a robotic helicopter is 1.8 kilograms. What is the helicopter's gravitational
force on Mars?
On Earth, g = 9.8m/s²
On Mars, g = 3.71 m/s².
(1 point)
O 6.68 N
O 0.49 N
O 17.64 N
O2.64 N
The gravitational force of the robotic helicopter of mass 1.8 kg on Mars is 6.68 N.
What is gravitational force?Gravitational force is the force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface.
To calculate the helicopter's gravitational force, we use the formula below.
Formula:
F = mg'............ Equation 1Where:
F = Gravitational force of the helicopterm = Mass of the helicopterg' = Acceleration due to gravity of MarsFrom the question,
Given:
m = 1.8 kgg' = 3.71 m/s²Substitute these values into equation 1
F = 1.8×3.71F = 6.678F ≈ 6.68 NHence, the helicopter's gravitational force on Mars is 6.68 N.
Learn more about gravitational force here: https://brainly.com/question/19050897
#SPJ1
A wheel of radius 30.0 cm is rotating at a rate of 2.30 revolutions every 0.0810 s.Through what angle does the wheel rotate in 1.00 s?What is the linear speed of a point on the wheel’s rim?What is the wheel’s frequency of rotation?
Given data
*The given radius of the wheel is r = 30.0 cm = 0.30 m
*Rate of rotation is 2.30 revolutions every 0.0810 s
The angle of the wheel rotates in one second is calculated as
[tex]\begin{gathered} \theta=(2.30\times2\pi)\times\frac{1}{0.0810} \\ =178.32\text{ radian} \end{gathered}[/tex]Hence, the angle of the wheel rotating in one second is 178.32 radian
The formula for the linear speed of a point on the wheel's rim is given as
[tex]v=r\omega[/tex]Substitute the known values in the above expression as
[tex]undefined[/tex]Define electricity in detail.
Electricity is the phenomenon of the flow of electric charges due to the potential difference.
The flow of electric charges across the conductor is known as electric current.
Unit of electric current is Ampere.
Potential difference is the difference of potential between two charges.
There are two charges namely positive and negative.
Uneven distribution of charges causes the potential difference.
Suppose A and B are two points on a conductor where A has a 5 C charge and B has a 3 C charge.
Thus, the current will flow from higher potential to lower potential which is from A to B.
Resistance is the opposing property of the conductor which opposes the flow of current.
The unit of resistance is ohm.
The belief that for every particle there is a force particle is referred to in modern physics as which of the following?Select one:a.unification theoryb.string theoryc.supersymmetryd.quantum tunneling
We will have that the one would be supersymmetry.
A block of mass of 1kg is hit by a force of magnitude 5 N which causes the block to have an acceleration of magnitude a. If the same block is hit by a force of magnitude 40 N, then which of these is the new magnitude of acceleration of the block?A) 2.8284aB) one eighth of aC) one/ 64 of aD) 8aE) 64a
The acceleration is related to the force and mass by Newton's second law which states:
[tex]a=\frac{F}{m}[/tex]for the first mass we have:
[tex]a_1=\frac{5}{1}=5[/tex]If the same block is hit by a force of 40 N then the new acceleration is:
[tex]a=\frac{40}{1}=40[/tex]Which is eight times the original acceleration; therefore, the answer is D.
Charge q1 = 2.00 x 10-9 C is located +0.020 m from the origin along the x-axis. Charge q2 =-3.00 x 10-9 C is located +0.040 m from the origin along the x-axis. What is the electric force exerted by these two charges on a third charge, q3 = 5.00 x 10-9 C, located at the origin?
Given,
Charge q1 = 2.00 x 10-9 C is located +0.020 m from the origin along the x-axis. Charge q2 =-3.00 x 10-9 C is located +0.040 m from the origin along the x-axis.
There is a third charge q3 = 5.00 x 10-9 C, located at the origin.
Now the force acting on the third charge due to other two charge is:
[tex]\begin{gathered} F=k\frac{2\times10^{-9}\times5\times10^{-9}}{0.02^2}+k\frac{3\times10^{-9}\times5\times10^{-9}}{0.04^2} \\ \Rightarrow F=0.0002225+0.0000834=0.000305C \end{gathered}[/tex]
Hello, i just need to check this problem, thanks in advance!
Given:
The mass of the bucket is m = 0.25 kg
The length of the string from the center is L = 0.4 m
The speed of the bucket is v = 5 m/s
To find The tension in the string at the bottom of the circle.
Explanation:
Forces acting on the bottom of the circle are tension due to the string and force due to gravity.
The tension in the string at the bottom of the circle can be calculated by the formula
[tex]T=\frac{mv^2}{L}+mg[/tex]Here, g = 9.8 m/s^2 is the acceleration due to gravity.
Substituting the values, the tension in the string at the bottom of the circle is
[tex]\begin{gathered} T\text{ = }\frac{0.25\times(5)^2}{0.4}+0.25\times9.8 \\ =18.075\text{ N} \end{gathered}[/tex]
Final Answer: Thus the tension in the string at the bottom of the circle is 18.075 N
Identify the Action and Reaction Forces
A pair of forces that will always move in conflict with one another is referred to as an action-reaction force.
What is newton's third law?The third law of Newton asserts because when bodies interact, they exert forces that are equal in size and directed in the reverse way. Another name for the newton's third is the law of action and reaction. This equation is crucial for understanding issues with static balance, in which all forces are all in balance, but it also holds true for bodies moving at a steady or accelerated speed.
Hammer hitting a nail : In this, the hitting by the hammer is the action and the nail is going into the surface is the reaction force.
Book placed on the table : In this book is applying gravitational force that is action force and the reaction force is applied by the table.
Hitting a tennis ball : In this, hitting the ball is the action and the ball is going in the direction of hitting is the reaction force.
To know more about Newton's third law:
https://brainly.com/question/974124
#SPJ2
b. How many square meters does an 80. ft2 rug occupy? (1 ft = 12 in.)
b.
First squared the following conversion factor: 1 ft = 12 in, as follow:
[tex]\begin{gathered} 1ft=12in \\ (1ft)^2=(12in)^2 \\ 1ft=144in^2 \end{gathered}[/tex]Then, use the previous result as a conversion factor to convert 80.0ft^2, as follow:
[tex]80.0ft^2\cdot\frac{144in^2}{1ft^2}=11520in^2[/tex]Now, consider that 1 m = 39.3701 in, then, if you squared you obtain:
[tex]\begin{gathered} 1m=39.3701in \\ (1m)^2=(39.37in)^2 \\ 1m^2=1550.004774in^2 \end{gathered}[/tex]use the previous result as a conversion factor:
[tex]11520in^2\cdot\frac{1m^2}{1550.004774in^2}\approx7.43m^2[/tex]Hence, 80.0ft^2 is approximately 7.43 m^2
A company is constructing a building for a recordings tudio. Which of the following would be the LEAST HELPFUL in reducing road noise in the studio?
The lest helpful solution is reduncing the number of trees on the property. Therefore, the answer is A.
This comes from the fact that all the other option will better absorb sound waves on the building itself.
A battery does 1.922 J of work to transfer 0.089 C of charge from the negative to the positive terminal. What is the emf of this battery?
We can find the EMF as follows:
[tex]\begin{gathered} EMF=\frac{W}{q} \\ where: \\ W=1.922J \\ q=0.089C \\ so: \\ EMF=\frac{1.922}{0.089} \\ EMF=21.5955V \end{gathered}[/tex]Answer:
21.5955V
wut is phisics\and what do the do in physica
Physics is the branch of science that deals with the energy and matter and how they are relate to each other. Physics is simply as a natural science that depends on the approximation, measurements and mathematical analysis.
A satellite is in orbit around Earth. How does the force exerted by Earth on the satellite compare to the force exerted by the satellite on Earth? Note: >> means much greater than; << means much less than.
The formula for the gravitational force between two bodies is given as
[tex]F=\frac{GmM}{r^2}[/tex]*Here m is the mass of the first object
*Here M is the mass of the second object
*Here r is the distance between the two objects
*Here G is the gravitational force
The force exerted by the earth on the satellite is equal to the force exerted by the satellite on the earth. Hence, the correct option is (b)
A pitcher throws a 0.14-kg baseball with a speed of 28.8 m/s. The batter strikes it with an average force of 5000 N, which results in the ball traveling with an initial speed of 37.0 m/s toward the pitcher. For how long we’re the bat and ball in contact?
Given data:
* The velocity of the ball before hitting is,
[tex]u=28.8\text{ m/s}[/tex]* The velocity of the ball after hitting the bat is,
[tex]v=-37\text{ m/s}[/tex]Here, the negative sign is indicating the direction of motion of ball is in opposite direction to the direction of motion before hitting by the bat.
* The mass of the ball is,
[tex]m=0.14\text{ kg}[/tex]* The average force on the ball by the bat is,
[tex]F=5000\text{ N}[/tex]Solution:
The change in the momentum of the ball after hitting is,
[tex]\Delta p=p_2-p_1[/tex]where p2 is the momentum of the ball after hitting from the bat and p1 is the momentum of the ball before hitting from the bat,
The change in momentum in terms of mass is,
[tex]\begin{gathered} \Delta p=mv-m\text{u} \\ =m\mleft(v-u\mright) \end{gathered}[/tex]Substituting the known values,
[tex]\begin{gathered} \Delta p=0.14(-37-28.8) \\ \Delta p=-0.14\times65.8 \\ \Delta p=-9.212\text{ kgm/s} \end{gathered}[/tex]Thus, the time at which the bat and ball were in contact is,
[tex]\begin{gathered} F=\frac{|\Delta p|}{\Delta t} \\ \Delta t=\frac{|\Delta p|}{F} \end{gathered}[/tex]Substituting the known values,
[tex]\begin{gathered} \Delta t=\frac{9.212}{5000} \\ \Delta t=0.0018\text{ s} \\ \Delta t=1.8\times10^{-3}\text{ s} \end{gathered}[/tex]Thus, the ball and bat were in contact for 0.0018 seconds.
If a bullet leaves the muzzle of a rifle with a speed of 600 m/s, and the barrel of the rifle is 0.800 m long, at what rate is the bullet accelerated while in the barrel?That is the question I am having trouble with
Given that the final velocity of the bullet is
[tex]V_f=600\text{ m/s}[/tex]The initial velocity of the bullet is
[tex]V_i=0\text{ m/s}[/tex]The distance traveled by the bullet is x = 0.8 m
We have to find the acceleration.
Let the acceleration be denoted by a.
The equation which can be used to calculate acceleration is
[tex](V_f)^2-(V_i)^2=2ax[/tex]Substituting the values, acceleration will be
[tex]\begin{gathered} (600)^2-0^2=2\times a\times0.8 \\ a=\frac{360000}{1.6} \\ =225000m/s^2 \end{gathered}[/tex]Thus the acceleration will be 225000 m/s^2.
Question 5 of 10Which phrase is the best definition of matter?A. A substance that cannot be divided into smaller piecesB. The smallest piece of a chemical compound that retains theproperties of the compoundC. Something that occupies a volume of space and also has massD. A substance that can change in both volume and shape
Something that occupies a volume of space and also has mass is the best definition of matter.
everything that occupies space and has mass. Matter, in the form of atoms, which are made up of protons, neutrons, and electrons, makes up all physical objects. Greek philosophers Democritus (470–380 BC) and Leucippus are credited with originating the notion that matter was composed of constituent parts or particles (490 BC).
Atoms form the basis of matter. One proton makes up the most fundamental atom, the protium isotope of hydrogen. Atoms are composed of protons, neutrons, and electrons, however these particles are based on fermions. Despite fitting certain definitions of matter, quarks and leptons aren't commonly regarded as types of matter. It's easiest to just declare that matter is made up of atoms at the majority of levels.
To know more about matter visit : https://brainly.com/question/3764450
#SPJ9
A jet is goes from 180km/ to 139km/s in. 22 seconds what is its acceleration Vi-Vf-T-A-
Given
Initial velocity,
[tex]v_i=180\text{ km/s}[/tex]Final velocity,
[tex]v_f=139\text{ km/s}[/tex][tex]Time\text{ taken , t=22 s}[/tex]To find
The acceleration
Explanation
Acceleration is the ratio of change in velocity to that of the time taken
Thus,
[tex]\begin{gathered} a=\frac{v_f-v_i}{t} \\ \Rightarrow a=\frac{180-139}{22} \\ \Rightarrow a=1.86\text{ km/s}^2 \end{gathered}[/tex]Conclusion
The acceleration is
[tex]1.86\text{ km./s}^2[/tex]The correct unit for the frequency of oscillation is asecond/wavewave/secondHertzsecond
To find the unit of frequency.
Explanation:
The SI unit of frequency is Hertz (Hz). It is named after Heinrich Hertz.
It is equivalent to
[tex]\begin{gathered} frequency\text{ =}\frac{1}{time\text{ period}} \\ 1\text{ Hz}=\frac{1}{s} \\ =s^{-1} \end{gathered}[/tex]
Which statement given BEST describes what happens to light as it passes from air into a piece of glass?a) The speed increases, its wavelength becomes longer, and its frequency decreases.b)The speed increases, its wavelength becomes longer, and its frequency remains the same.c) The speed decreases, its wavelength becomes shorter, and its frequency remains the same.d) The speed decreases, its wavelength becomes shorter, and its frequency increases.
Given that the light passes from air to glass, that means it enters to denser medium from rarer medium.
Here, air is the rarer medium and glass is the denser medium.
Speed decreases when light enters from rarer to densr medium , while the frequency remains the same and its wavelength becomes shorter.
Thus, option C is correct.
A comet is known to be traveling at 236 km per second. It is observed to give light with a frequency of 641 x 1014 Hz. What frequency of light would the come be emitting if it were motionless? Express your answer to the nearest hundred trillion Hz.
ANSWER
6.4 x 10¹⁶ Hz
EXPLANATION
Given:
• The speed of the source, vs = 236 km/s
,• The speed of light, c = 300,000 km/s
,• The observed frequency of the light, fo = 641 x 10¹⁴ Hz
Find:
• The frequency of the source, fs
To solve this problem, we have to apply the Doppler Effect formula for light,
[tex]f_o=f_s\sqrt{\frac{1-v_s/c}{1+v_s/c}}[/tex]Solving for fs,
[tex]f_s=f_o\sqrt{\frac{1+v_s/c}{1-v_s/c}}[/tex]Replace the known values and solve,
[tex]f_s=641\cdot10^{14}Hz\cdot\sqrt{\frac{1+(236km/s)/(300,000km/s)}{1-(236km/s)/(300,000km/s)}}\approx6.4\cdot10^{16}Hz[/tex]Hence, the emitted frequency of the comet's light is 6.4 x 10¹⁶ Hz.
If an alarm clock is ringing what is the medium for the sound waves
Sound energy travels through air in waves. When an alamr clock rings, nearby air molecules vibrate.
Can you please answer the questions and explain how you got it?
Given data:
The mass of the block on table is M=500 g.
The hanging mass is m=300 g.
The kinetic friction is μ=0.25.
Part (a)
The free body diagram of the block on table is shown below,
The free body diagram of hanging mass is shown below,
Part (b)
The equation according Newton's second law for 500 g mass will be,
[tex]\begin{gathered} F_{net}=Ma \\ T-f=Ma \\ T-\mu N=Ma \\ T-\mu Mg=Ma \\ T=M(a+\mu g)\ldots\ldots(1) \end{gathered}[/tex]Here, f is the friction force, N is the normal force, and T is the tension in the string.
Part (c)
The equation according Newton's second law for 300 g mass will be,
[tex]\begin{gathered} F_{net}=ma \\ mg-T=ma \\ T=mg-ma \\ T=m(g-a)\ldots\ldots(2) \end{gathered}[/tex]Part (d)
Equating equation (1) and (2) to solve for acceleration,
[tex]\begin{gathered} M(a+\mu g)=m(g-a) \\ 500(a+0.25(9.81))=300(9.81-a) \\ a+2.45=0.6(9.81-a) \\ a+2.45=5.886-0.6a \\ a+0.6a=5.886-2.45 \\ 1.6a=3.436 \\ a=2.14m/s^2 \end{gathered}[/tex]Thus, the acceleration of the blocks are 2.14 m/s².
Part (e)
Substitute the value of acceleration in equation (1) to calculate the tension,
[tex]\begin{gathered} T=M(a+\mu g) \\ T=500(2.14+(0.25)(9.81)) \\ T=2296gm/s^2\times\frac{1\text{ N}}{1000gm/s^2} \\ T=2.296\text{ N} \end{gathered}[/tex]Thus, the tension in the sting is 2.296 N.
- (True/False) If there is no friction, the efficiency of a machine can be greater than 100%.
ANSWER:
False
STEP-BY-STEP EXPLANATION:
Even without friction, the efficiency cannot be greater than 100%, because the output cannot be greater than the input, therefore, the statement is false.
What are some simple machines that decrease mechanical advantage used to do?
Omultiply distance to increase speed
Odivide distance to decrease speed
O decrease work
O increase work
Some simple machines decrease mechanical advantage and are used to A) multiply distance to increase speed.
Define Mechanical Advantage.
When analyzing the forces in straightforward machines like levers and pulleys, mechanical advantage—a measure of the ratio of output force to input force in a system—is utilized. The conservation of energy still holds true and the output energy is equal to the input energy even when the forces being applied change.
The mechanical advantage is typically described in terms of perfect systems, also known as 100% efficient systems, where there are no energy losses between the input and output times.Through energy efficiency:Fi×di=Fo×do
The input energy (or work put into a machine) is on the left, and the output energy (or work that comes out of a machine, for no-loss energy) is on the right.
By extending the distance across which the effort force is applied, the equations demonstrate how a basic machine can produce the same amount of work while using less effort force.
Hence, Option A) is correct.
To learn more about mechanical advantage from the given link
https://brainly.com/question/18345299
#SPJ1
Assume that the ammeter in the figure below is removed and the current that flows through the 4.0Ω path, I3, is unknown. Determine all the currents in the circuit.
The circuit is in parallel connection
Equivalent resistance = 1/Req = 1/R1 + 1/R2 + 1/R3
From the information given,
R1 = 5
R2 = 2
R3 = 4
1/Req = 1/5 + 1/2 + 1/4 = (4 + 10 + 5)/20 = 19/20
Req = 20/19 = 1.053 ohms
I = V/R
Given that V = 12,
Current flow through circuit = 12/1.053 = 11.4 A
I1 + I2 + I3 = 11.4
I1 = 12/5 = 2.4 A
I2 = 12/2 = 6 A
I3 = 12/4 = 3A
3. The mass of an electron is 9.1x10^-31 kg. The mass of a proton is 1.7x10^-27 kg.The gravitational force between them in the hydrogen atom is 1.0x10^-47 N.What is the separation distance between them?
Given:
The mass of the electron is,
[tex]m_e=9.1\times10^{-31}\text{ kg}[/tex]The mass of the proton is,
[tex]m_p=1.7\times10^{-27}\text{ kg}[/tex]The gravitational force between the electron and the proton in the hydrogen atom is,
[tex]1.0\times10^{-47}\text{ N}[/tex]To find:
the separation between them
Explanation:
The gravitational force between two masses is,
[tex]F=\frac{Gm_1m_2}{r^2}[/tex]Here, the universal gravitational constant is,
[tex]G=6.67\times10^{-11}\text{ Nm}^2kg^{-2}[/tex]Substituting the values we get,
[tex]\begin{gathered} 1.0\times10^{-47}=\frac{6.67\times10^{-11}\times9.1\times10^{-31}\times1.7\times10^{-27}}{r^2} \\ r^2=\frac{6.67\times10^{-11}\times9.1\times10^{-31}\times1.7\times10^{-27}}{1.0\times10^{-47}} \\ r^2=1.03\times10^{-20} \\ r=\sqrt{1.01\times10^{-20}} \\ r=1.01\times10^{-5}\text{ m} \end{gathered}[/tex]Three liquids are at temperatures of 10 ◦C, 22◦C, and 29◦C, respectively. Equal masses of the first two liquids are mixed, and the equi- librium temperature is 12◦C. Equal masses of the second and third are then mixed, and theequilibrium temperature is 25.9◦C.Find the equilibrium temperature when equal masses of the first and third are mixed.Answer in units of ◦C.
A uniform disk of radius 0.473 m and unknown mass is constrained to rotate about a perpendicular axis through its center. A ring with the same mass as the disk is attached around the disk's rim. A tangential force of 0.203 N applied at the rim causes an angular acceleration of 0.125 rad/s2. Find the mass of the disk.
From the calculations, the mass of the object is 3.43 Kg.
What is the mass of the rod?We know that the term circular motion has to do with motion along a circular path. The force that acts on the body in this case is tangential to the circle. This tangential force can be obtained from;
F = mrα
F = tangential force
m = mass of the object
r = radius of the object
α = angular acceleration
When we make m the subject of the formula;
m = F/rα
m = 0.203 N/0.473 m * 0.125 rad/s2
m = 3.43 Kg
Learn more about tangential force:https://brainly.com/question/13885495
#SPJ1
y=a on x Represents_____________
Answer:
a
Explanation:
to be linear equation, x needs to be multiplied by a constant but xy = a doesn't satisfy that