Fred's car van travel 368 miles on one tank of gas. His has tank holds 16 gallons what is the unit rate for mules per gallon

Answers

Answer 1

16 gallons is needed for 368miles

Therefore

1 gallon is needed for 368/16 = 23miles

Hence the rate for miles per gallon is


Related Questions

Find the value of x in the triangle shown below.=2°31770

Answers

The sum of all the angles in a triangle is always 180°.

We can write the equation and solve for the missing angle:

[tex]31^o+77^o+x=180^o[/tex]

Solving for x:

[tex]\begin{gathered} x=180^o-31^o-77^o \\ \\ x=72^o \end{gathered}[/tex]

The measure of the unknown angle is 72 degrees.

Solve F=mv^2/R for V

Answers

SOLUTION

We want to solve for v in

[tex]F=\frac{mv^2}{R}[/tex]

This means we should make v the subject, that is make it stand alone. This becomes

[tex]\begin{gathered} F=\frac{mv^2}{R} \\ m\text{ultiply both sides by }R,\text{ we have } \\ F\times R=\frac{mv^2}{R}\times R \\ R\text{ cancels R in the right hand side of the equation we have } \\ FR=mv^2 \end{gathered}[/tex]

Next, we divide both sides by m, we have

[tex]\begin{gathered} FR=mv^2 \\ \frac{FR}{m}=\frac{mv^2}{m} \\ m\text{ cancels m, we have } \\ \frac{FR}{m}=v^2 \\ v^2=\frac{FR}{m} \end{gathered}[/tex]

Lastly, we square root both sides we have

[tex]\begin{gathered} v^2=\frac{FR}{m} \\ \sqrt[]{v^2}=\sqrt[]{\frac{FR}{m}} \\ \text{square cancels square root, we have } \\ v=\sqrt[]{\frac{FR}{m}} \end{gathered}[/tex]

Hence the answer is

[tex]v=\sqrt[]{\frac{FR}{m}}[/tex]

select the graph represented by the exponential function y = 4(1/2)×

Answers

SOLUTION

We want to tell the graph that represents the function

[tex]y=4(\frac{1}{2})^x[/tex]

The graph of this function is shown below

Comparing this to what we have in the options,

we can see that the correct answer is option D

Last week, Shelly rode her bike a total of 30 miles over a three-day period. On the second day, she rode LaTeX: \frac{4}{5}45 the distance she rode on the first day. On the third day, she rode LaTeX: \frac{3}{2}32 the distance she rode on the second day

Answers

We make expressions for each afirmation

Where X is the first day, Y second day and Z the third

1. the sum of the 3 days gives us 30

[tex]X+Y+Z=30[/tex]

2. Second day is 4/5 of the first day

[tex]Y=\frac{4}{5}X[/tex]

3.Third day is 3/2 of the second day

[tex]Z=\frac{3}{2}Y[/tex]

Whit the expressions I try to represent everything as a function of X

I must represent Z in function of X, for this I can replace Y of the second expression in the third expression

[tex]\begin{gathered} Z=\frac{3}{2}(\frac{4}{5}X) \\ Z=\frac{12}{10}X \\ Z=\frac{6}{5}X \end{gathered}[/tex]

So I have:

[tex]\begin{gathered} Y=\frac{4}{5}X \\ Z=\frac{6}{5}X \\ \end{gathered}[/tex]

And I can replace on the first expression

[tex]\begin{gathered} X+Y+Z=30 \\ X+(\frac{4}{5}X)+(\frac{6}{5}X)=30 \end{gathered}[/tex]

I must find X

[tex]\begin{gathered} (1+\frac{4}{5}+\frac{6}{5})X=30 \\ 3X=30 \\ X=\frac{30}{3} \\ X=10 \end{gathered}[/tex]

So, if I have X I can replace on this expressions to find de value:

[tex]\begin{gathered} Y=\frac{4}{5}X \\ Z=\frac{6}{5}X \end{gathered}[/tex]

Where X is 10

[tex]\begin{gathered} Y=\frac{4}{5}\times10 \\ Y=\frac{40}{5}=8 \\ \\ Z=\frac{6}{5}\times10 \\ Z=\frac{60}{5}=12 \end{gathered}[/tex]

To check:

[tex]\begin{gathered} X+Y+Z=30 \\ (10)+(8)+(12)=30 \\ 30=30 \\ \end{gathered}[/tex]

The result is correct, therefore:

[tex]\begin{gathered} X=10 \\ Y=8 \\ Z=12 \end{gathered}[/tex]

If: x+y+z=2-x+3y+2z=84x+y=4Find the value of x, y and z

Answers

We have

[tex]\begin{gathered} x+y+z=2 \\ -x+3y+2z=8 \\ 4x+y=4 \end{gathered}[/tex]

We have with the third equation

[tex]y=4-4x[/tex]

We substitute in the first and second equation

[tex]\begin{gathered} x+4-4x+z=2 \\ -3x+z=-2 \end{gathered}[/tex][tex]\begin{gathered} -x+3(4-4x)+2z=8 \\ -x+12-12x+2z=8 \\ -13x+2z=8-12 \\ -13x+2z=-4 \end{gathered}[/tex]

Then we have

[tex]z=-2+3x[/tex]

We substitute

[tex]\begin{gathered} -13x+2(-2+3x)=-4 \\ -13x-4-6x=-4 \\ -19x=0 \\ x=0 \end{gathered}[/tex]

if x=0

[tex]z=-2[/tex]

and if x=0

[tex]y=4[/tex]

ANSWER

x=0

y=4

z=-2

Find the augmented matrix for the systemIt gives us 3 numbers already

Answers

It is required that we find an augmented matrix for the system.

Recall that a matrix that contains the coefficients and constant terms of a system of equations, each written in the standard form with the constant terms to the right of the equals is called an augmented matrix.

The given system of equations is:

[tex]\begin{cases}x+5y+8z=-9 \\ 3x+z=-4 \\ 7x+5y+7z=3\end{cases}[/tex]

The first, second, and third equations can be rewritten to get:

[tex]\begin{cases}1x+5y+8z=-9 \\ 3x+0y+1z=-4 \\ 7x+5y+7z=3\end{cases}[/tex]

Hence, the augmented matrix using the system is:

[tex]\begin{bmatrix}{1} & 5 & 8{|} & {-9} \\ {3} & {0} & {1|} & {-4} \\ {7} & {5} & {7|} & {3} \\ & {} & {} & {}\end{bmatrix}[/tex]

PLEASE HELP!!!!! I really really really really really need help with this math problem can someome help me please its has to be done in 20 mins!!!!!!!! PLEASE HELP!!!

Answers

A) To do that we will draw a line inside the triangle that is perpendicular to the base as I have don above.

B) We will also do the same for B

Drag each label to the correct location on the table. Each label can be used more than once, but not all labels will be used. Simplify the given polynomials. Then, classify each polynomial by its degree and number of terms.polynormial 1:[tex](x - \frac{1}{2})(6x + 2)[/tex]polynormial 2:[tex](7 {x}^{2} + 3x) - \frac{1}{3} (21 { x}^{2} - 12)[/tex]polynormial 3:[tex]4(5 {x}^{2} - 9x + 7) + 2( - 10 {x}^{2} + 18x - 03) [/tex]

Answers

Given the polynomials, let's simplify the polynomials and label them.

Polynomial 1:

[tex]\begin{gathered} (x-\frac{1}{2})(6x+2) \\ \text{Simplify:} \\ 6x(x)+2x+6x(-\frac{1}{2})+2(-\frac{1}{2}) \\ \\ =6x^2+2x-3x-1 \\ \\ =6x^2-x-1 \end{gathered}[/tex]

After simplifying, we have the simplified form:

[tex]6x^2-x-1[/tex]

Since the highest degree is 2, this is a quadratic polynomial.

It has 3 terms, therefore by number of terms it is a trinomial.

Polynomial 2:

[tex]\begin{gathered} (7x^2+3x)-\frac{1}{3}(21x^2-12) \\ \\ \text{Simplify:} \\ (7x^2+3x)-7x^2+4 \\ \\ =7x^2+3x-7x^2+4 \\ \\ \text{Combine like terms:} \\ 7x^2-7x^2+3x+4 \\ \\ 3x+4 \end{gathered}[/tex]

Simplified form:

[tex]3x+4[/tex]

The highest degree is 1, therefore it is linear

It has 2 terms, therefore by number of terms it is a binomial

Polynomial 3:

[tex]\begin{gathered} 4(5x^2-9x+7)+2(-10x^2+18x-13) \\ \\ \text{Simplify:} \\ 20x^2-36x+28-20x^2+36x-26 \\ \\ \text{Combine like terms:} \\ 20x^2-20x^2-36x+36x+28-26 \\ \\ =2 \end{gathered}[/tex]

Simplified form:

[tex]2[/tex]

The highest degree is 0 since it has no variable, therefore it is a constant.

It has 1 term, by number of terms it is a monomial.

ANSWER:

Polynomial Simplified form Name by degree Name by nos. of ter

1 6x²-x-1 quadratic Trinomial

2 3x + 4 Linear Binomial

3 2 Constant Monomial

Create a "rollercoaster using the graphs of polynomials with real and rational coefficients.
The coaster ride must have at least 3 relative maxima and/or minima.
The coaster ride starts at 250 feet (let this be your y-intercept).
The ride dives below the ground into a tunnel (under the x-axis) at least once.
The graph must have at least one even multiplicity, two real solutions, and two imaginary solutions.

Answers

The polynomial that represents the rollercoaster, using the Factor Theorem, is given as follows:

y = 400(x - 1)²(x + 1)(x² + 0.1)(x + 5).

What is stated by the Factor Theorem?

The Factor Theorem states that a polynomial function with zeros [tex]x_1, x_2, \codts, x_n[/tex], also represented by factors [tex]x - x_1, x - x_2, \cdots x - x_n[/tex] is given by the rule presented as follows:

[tex]f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)[/tex]

In which a is the leading coefficient of the polynomial function with the given roots.

For this problem, the requirements are as follows:

At least 3 relative maxima and/or minima -> derivative of 3rd order -> 4 unique rootsy-intercept of 250 feet -> controlled by the leading coefficient.

The roots will be given as follows:

Root at x = 1 with even multiplicity -> (x - 1)².Real solution at x = -1 -> (x + 1).Two imaginary solutions -> (x² + 0.1).Unique root at x = -5 -> (x + 5).

Hence the function is:

y = a(x - 1)²(x + 1)(x² + 0.1)(x + 5).

At x = 0, the function assumes a value of 250, hence the leading coefficient is obtained as follows:

0.5a = 200.

a = 400.

Thus the function is:

y = 400(x - 1)²(x + 1)(x² + 0.1)(x + 5).

Which has the desired features, as shown by the image at the end of the answer.

More can be learned about the Factor Theorem at https://brainly.com/question/11813480

#SPJ1

Which ratio of cups of banana to cups of apple juice is also equivalent to ¼:⅓?• 4/4 : 3/3• 3/3 : 3/4• 3/4 : 4/3• 3/4 : 3/3

Answers

ANSWER

3/4 : 3/3

EXPLANATION

We have the ratio of cups of banana to cups of apple juice to be 1/4 : 1/3

Equivalent ratios can be gotten by multiplying the ratio with a common integer.

This means we can multiply bot sides of the ratio with the same integer e.g. 2, 4, 7...

Since from the diagram, the next equivalent ratio is given (2/4 : 2/3), we can obtain the next equivalent ratio by multiplying the ratio by 3. That is:

3/4 : 3/3

Therefore, the correct option is 3/4 : 3/3

Help me with number 4 please Identify the 17th term of a geometric sequence where a1 = 16 and a5 = 150.06 Round the common ratio and 17th term to the nearest hundredth.

Answers

Answer:

Common ratio = 1.75

17th term = 123,802.31

Explanations:

Given the following parameters:

[tex]\begin{gathered} a_1=16 \\ a_5=150.06 \end{gathered}[/tex]

Since the sequence is geometric, the nth term of the sequence is given as;

[tex]a_n_{}=a_{}r^{n-1}[/tex]

a is the first term

r is the common ratio

n is the number of terms

If the first term a1 = 16, then;

[tex]\begin{gathered} a_1=ar^{1-1}_{} \\ 16=ar^0 \\ a=16 \end{gathered}[/tex]

Similarly, if the fifth term a5 = 150.06, then;

[tex]\begin{gathered} a_5=ar^{5-1} \\ a_5=ar^4 \\ 150.06=16r^4 \\ r^4=\frac{150.06}{16} \\ r^4=9.37875 \\ r=1.74999271132 \\ r\approx1.75 \end{gathered}[/tex]

Hence the common ratio to the nearest hundredth is 1.75

Next is to get the 17th term as shown;

[tex]\begin{gathered} a_{17}=ar^{16} \\ a_{17}=16(1.75)^{16} \\ a_{17}=16(7,737.6446) \\ a_{17}\approx123,802.31 \end{gathered}[/tex]

Hence the 17th term of the sequence to the nearest hundredth is 123,802.31

Find the slope of each line and then determine if the lines are parallel, perpendicular or neither. If a value is not an integer type it as a decimal rounded to the nearest hundredth.Line 1: passes through (-8,-55) and (10,89) the slope of this line is Answer.Line 2: passes through (9,-44) and (4,-14) the slope of this line is Answer.The lines are Answer

Answers

For line 1 =

The coordinates given are (-8,-55) , (10,89)

The slope of the line is

[tex]m=\frac{89+55}{10+8}=\frac{144}{18}=8[/tex]

For line 2 =

The coordinates given are (9,-44) , (4,-14)

The slope of the line is

[tex]m=\frac{-14+44}{4-9}=\frac{30}{-5}=-6[/tex]

The lines are not perpendicular or parallel because the slope of the lines does not satisfy the condition of perpendicular or parallel slopes.

Hence the answer is neither.

You TryWrite an equation for each of the following,then solve for the variable.20 is the same as the sum of 4 and g.

Answers

Given statement:

20 is the same as the sum of 4 and g

Let us break down the statement into parts and then write the equation

the sum of 4 and g:

[tex]\text{= 4 + g}[/tex]

This sum is equal to 20:

[tex]4\text{ + g = 20}[/tex]

Hence, the equation is:

[tex]4\text{ + g = 20}[/tex]

Solving for the variable:

[tex]\begin{gathered} \text{Collect like terms} \\ g\text{ = 20 -4} \\ g\text{ = 16} \end{gathered}[/tex]

Answer Summary

[tex]\begin{gathered} \text{equation: 4 + g = 20} \\ g\text{ = 16} \end{gathered}[/tex]

8 ( 11 - 2b ) = -4 ( 4b - 22 )

Answers

Problem

8 ( 11 - 2b ) = -4 ( 4b - 22 )

Solution

We can distribute the terms in the equation and we got:

88 -16b = -16b +88

If we add 16b in boh sides we got:

88 =88

Then for this case we can conclude that this equation has infinite solutions

Show that if the diagonals of a quadrilateral bisect each other at right angles then it is a rhombus.

Answers

To Show that if the diagonals of a quadrilateral bisect each other at right angles then it is a rhombus.

Proof:

Let ABCD be a quadrilateral such that the diagonals bisect each other,

Therefore,

[tex]\begin{gathered} OA=OC\ldots(1) \\ OB=OD\ldots(2) \end{gathered}[/tex]

the diagonal bisect at right angle.

Hence,

[tex]\begin{gathered} \angle AOB=90^{\circ} \\ \angle BOC=90^{\circ} \\ \angle COD=90^{\circ} \\ \angle AOD=90^{\circ}\ldots(3) \end{gathered}[/tex]

to prove: ABCD is rombus,

Rombus: its is a parallelogram, with all the sides equal.

so, to prove ABCD a parallelogram.

consider the triangle,

[tex]\begin{gathered} triangleAOD\text{ and triangle }COB, \\ OA=OC \\ \angle AOD=\angle COB \\ OD=OB \\ \end{gathered}[/tex]

thus, traingle

[tex]\text{AOD}\cong COB[/tex]

consider the sides, AD and BC

with the transversal ac,

The angles,

[tex]\angle OAD\text{ AND }\angle OCB[/tex]

are alterntaive angles. they are equal.

this implies, AD is parallel BC.

similarly, AB is parallel to DC.

Hence, AD II BC and AB II DC.

In ABCD the opposite sides are parallel,

This implies, ABCD is parallelogram.

Now, to prove that ABCD is a rombus.

for that all the sides of ABCD should be equal.

now, consider the triangle AOD and COD.

[tex]\begin{gathered} OA=OC \\ \angle AOD=\angle COD \\ OD=OD\text{ common side} \end{gathered}[/tex]

By SAS congruent rule,

Traingles,

[tex]AOD\cong COD[/tex]

Thus, by CPCT Corresponding parts of congruent triangles ,

AD= CD

we know that,

AD=CB and CD=AB

Thus, AD=CD=CB=AB.

hence, all the sides are eqaul and ABCD is parallelogram.

So, ABCD is a rhombus.

40% of the students on the field trip love the museum. If there are 20 students on the field trip, how many love the museum?

Answers

well, what's 40% of 20?

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{40\% of 20}}{\left( \cfrac{40}{100} \right)20}\implies 8[/tex]

if there are 7 teams and every teams plays everyone once how many games total played

Answers

This is a problem about combinations where the order doesn't matter. The solution is usually written as 7C2 (seven choose two) and has the value

[tex]\frac{7!}{(7-2)!2!}=21[/tex]

Comment: 7C2 is the answer to the question "How many pairs (in our case, these pairs are seen as games played) can we form from a group of 7 things?".

What is the domain of the function shown in the graph below? y 10 9 8 7 6 5. 4 3 2 -10 -9 -8 -7 -6 in -4 3 -2 1 6 2 8 9 10 -2 -3 -4 -5 -6 -8 9 10 W Type here to search Et TH-WL-57336

Answers

1) As the Domain is the set of inputs (x) for that function, as we can see in the graph.

There's one point in the graph x =8, where should be an asymptote i.e. a vertical or horizontal line that prevents both graphs do not trespass.

So we can write the Domain as

D =(-∞, 8) U (8, ∞)

Because in this function, the point x=8 is not included, and from point 8 on the function continues.

Write an equation and solve.The supplement of an angle is 63º more than twicethe measure of its complement. Find the measure ofthe angle.

Answers

Answer:

The measure of the angle is 63 degrees

Explanation:

Let the angle in question be x degrees.

The supplement is (180 - x) degrees, and the complement is (90 - x) degrees.

Given that the supplement is 63 degrees more than twice the measure of its complement, we have the equation:

180 - x = 2(90 - x) + 63

Solving for x in the above:

180 - x = 180 - 2x + 63

2x - x = 180 - 180 + 63

x = 63

use the invert-and-multiply rule to divide. Reduce your answer to lowest terms.4 divide (- 2/5)

Answers

ANSWER:

- 10

STEP-BY-STEP EXPLANATION:

We have the following expression

[tex]4\div\mleft(-\frac{2}{5}\mright)[/tex]

We know that when dividing from, the nvert-and-multiply rule must be applied, as follows

[tex]\begin{gathered} 4\div\mleft(-\frac{2}{5}\mright)\rightarrow4\times\mleft(-\frac{5}{2}\mright)=\frac{4\cdot-5}{2}=\frac{-20}{2}=-10 \\ \end{gathered}[/tex]

Therefore the result of the operation is -10

What is the mean before the rent ? What is the mean after the change ?

Answers

Given:

The data set of the monthly rent paid by 7 tenants

990, 879, 940, 1010, 950, 920, 1430

We will find the mean of the data:

Mean = Sum/n

n = 7

Sum = 990+879+940+1010+950+920+1430 = 7119

Mean = 7119/7 = $1017

One of the tenants change from 1430 to 1115

The mean after the change will be as follows:

Sum = 990+879+940+1010+950+920+1115 = 6804

n = 7

Mean = 6804/7 = 972

So, the answer will be:

Mean before the change = 1017

Mean after the change = 972

Sketch and calculate the area enclosed by y² = 8-x and (y + 1)² = −3+x.

Answers

The area enclosed by y² = 8 - x and (y + 1)² = −3 + x is 243.

We are given y² = 8 - x and (y + 1)² = −3 + x.

To sketch and calculate the area enclosed, find the intersection points:

y² = 8 - x ⇒ x = 8 - y²

Substitute x = 8 - y² in (y + 1)² = −3 + x:

(y + 1)² = −3 + 8 - y²

y² + 2y + 1 = −3 + 8 - y²

2y² + 2y - 4 = 0

y² + y - 2 = 0

(y - 1) (y + 2) = 0

y = 1, -2

Substitute y = 1, -2 in x = 8 - y²:

When y = 1, x = 8 - (1) ⇒ x = 7

When y = -2,  x = 8 - (-2)² ⇒ x = 4

Thus, the point of intersection is (4, -2) and (7, 1).

Graph of the region enclosed by y² = 8 - x and (y + 1)² = −3 + x:

The area of the enclosed region is given by:

A = [tex]\int \, \int \,dA[/tex]

[tex]=\int\limits^7_{-2} \, \int\limits^{3+ (y+1)^{2} } _{8 - y^{2} } \, dxdy[/tex]

[tex]=\int\limits^7_{-2} \, (x)^{3+ (y+1)^{2} } _{8 - y^{2} } \, dy[/tex]

[tex]=\int\limits^7_{-2} \, [{(3+ (y+1)^{2} )} -({8 - y^{2} })] \, dy[/tex]

[tex]=\int\limits^7_{-2} \, {(2 y^{2} + 2y -4) } \, dy[/tex]

[tex]=(\frac{2y^3}{3} + \frac{2y^2}{2} -4y)^7_{-2}[/tex]

[tex]=\frac{686}{3} + 49 - 28 + \frac{16}{3} - 4 - 8[/tex]

= 343

Hence, the area enclosed by y² = 8 - x and (y + 1)² = −3 + x is 243.

To learn more about the area of the enclosed region visit:

https://brainly.com/question/28158496

#SPJ9

The equation 8x+8y=16 in slope-intercept form

Answers

The slope-intercept form is y=mx+b y = m x + b , where m m is the slope and b b is the y-intercept. Add 8x 8 x to both sides of the equation. Divide each term in 8y=16+8x 8 y = 16 + 8 x by 8 8 and simplify. Divide each term in 8y=16+8x 8 y = 16 + 8 x by 8 8 .

Simplify using the distributive property.8(y + 12)8 y + 9620 + y8 y + 1220 y

Answers

Solution:

Concept:

The distributive property of multiplication states that when a number is multiplied by the sum of two numbers, the first number can be distributed to both of those numbers and multiplied by each of them separately, then adding the two products together for the same result as multiplying the first number by the sum.

The expression is given below as

[tex]\begin{gathered} 8(y+12) \\ =8\times y+8\times12 \\ =8y+96 \end{gathered}[/tex]

Hence,

The final answer is

[tex]\Rightarrow8y+96[/tex]

For the polyhedron, use eular's foemula to find the missing number

Answers

Given:

Edges of the polyhedron, E = 10

Vertices, V = 5

A polyhedron is a three-dimensional figure.

Let's find the number of faces using Euler's formula.

To find the number of faces of the polyhedron, we have the Euler's formula:

V + F - E = 2

Substitute values into the formula:

5 + F - 10 = 2

Combine like terms:

F + 5 - 10 = 2

F - 5 = 2

Add 5 to both sides:

F - 5 + 5 = 2 + 5

F = 7

Therefore, the number of faces of the polyhedron is 7

ANSWER:

7 faces

a) How many hand-held color televisions can be sold at $ 400 per television?b) How many televisions will be sold when supply and demand are equal?c) Find the price at which supply and demand are equal.

Answers

a) Since we are interested in the number of TVs that can be sold at $400, we need to use the Demand model equation and set p=400; thus,

[tex]\begin{gathered} p=400 \\ \Rightarrow N=-7\cdot400+2820=20 \\ \Rightarrow N=20 \end{gathered}[/tex]

The answer to part a) is 20 TVs per week.

b) Set N=N, then

[tex]\begin{gathered} N=N \\ \Rightarrow-7p+2820=2.4p \\ \Rightarrow9.4p=2820 \\ \Rightarrow p=\frac{2820}{9.4}=300 \\ \Rightarrow p=300 \end{gathered}[/tex]

Therefore, using p=300 and solving for N,

[tex]\begin{gathered} \Rightarrow N=2.4\cdot300=720 \\ \Rightarrow N=720 \end{gathered}[/tex]

The answer to part b) is 720 TVs per week.

c) In part b), we found that when supply and demand are equal, p=300. Thus, the answer to part c) is $300

Simplify (a + 15) •2

Answers

(a + 15) •2

Multiply each term in the parentheses by 2

a*2 + 15*2

2a + 30

With the points (8. 4) (-6, -6) (-10, 12) (2,-4). What are the new points if thescale factor of dilation is X?

Answers

With the points (8. 4) (-6, -6) (-10, 12) (2,-4). What are the new points if the

scale factor of dilation is X?

we know that

The rule of the dilation of a point is equal to

(x,y) -------> (ax, ay)

with a scale factor a

so

In this problem

the scale factor is x

therefore

(8. 4) --------> (8x. 4x)

Question 2b: NAME THE Y-INTERCEPTy = -2(x - 3)^2

Answers

The given equation corresponds to a parabola:

[tex]y=-2(x-3)^2[/tex]

The y-intercept of the parabola is the point when it crosses the y-axis, at this point x=0, to determine this value you have to replace the formula with x=0 and calculate the value of y:

[tex]\begin{gathered} y=-2(0-3)^2 \\ y=-2(-3)^2 \end{gathered}[/tex]

Solve the exponent first, then the multiplication

[tex]\begin{gathered} y=-2(-3)^2 \\ y=-2\cdot9 \\ y=-18 \end{gathered}[/tex]

The y-intercept for the given function is (0,-18)

How much would $200 interest compounded monthly be worth after 30 years

Answers

Given:

Principal (P)=$200

Rate of interest (r) =4%

time (t)=30 years

Number of times compounded per year(n) = 12

Required- the amount.

Explanation:

First, we change the rate of interest in decimal by removing the "%" sign and dividing by 100 as:

[tex]\begin{gathered} r=4\% \\ \\ =\frac{4}{100} \\ \\ =0.04 \end{gathered}[/tex]

Now, the formula for finding the amount is:

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Put the given values in the formula, we get:

[tex]A=200(1+\frac{0.04}{12})^{12\times30}[/tex]

Solving further, we get:

[tex]undefined[/tex]

Other Questions
You are given two overlaying squares with side length a. One of the squares is fixed at thebottom right corner and rotated by an angle of (see drawing). Find an expression for theenclosed area A() between the two squares with respect to the rotation angle . For this problem identify P, FV, I, r, n, and t. 1. Write a function V(x) that models the volume of the box where the length of the sides of the squares is x cm. (The formula for the volume of a box is: V = l w ).2. Graph V(x). (You may use Desmos or draw in the provided grid.) Which fraction and decimal forms match the long division problem? 15) 4.000 301 1 00 90 100 90 A. and 0.26 15 . 15 and 0.26 C. and 0.26 15 15 and 0.266 need help asappppppp What is the correct classification of the system of equations below?14x + 2y = 10y + 7x = -5A. parallelB. coincidentC. intersecting If f -1(x) = (6/5)x - 9, find f (x). -2(y+5)+21 In quadrilateral ABCD, MZA = 72, mZB = 94, and m2C = 113. What is m2D? 3andLet's compare38=First, write the fractions with the same denominator.?138-138Then, use to compare the fractions.m 100 the points (v,-3) and (8,5) fall on a line with a slope of -8. what is the value of v? What is the solution to this equation?15(x+134)=212Responsesx=2114x equals 21 and 1 over 4x=1414x equals 14 and 1 over 4x=1034x equals 10 and 3 over 4x=334 help in mathematics pls i am troubled if you shift the function F(x) = log10 x up four units, what is the new function, G(x)?*PHOTO* IIIDECIMALSRounding decimalsRound 0.434 to the nearest hundredth.0x Find the future value$4013 invested for 9 years at 4.1% compounded quarterly. Find an equation for the line thats passes through the following points shown in the picture. ( Please fins answer in timely answer very brief explaination :) ) Determine whether or not the following table represents an exponential function. If it does, state the common ratio and if it represents exponential growth or decay. If it does not, state why. what's the solution to this system The repetition of beginning sounds in words is