Directions: Drag each tile to the correct box.Put the recursive formulas below in order from least to greatest according to the value of their 10th terms.For all of the formulas, let n be equal to the whole numbers greater than or equal to one.
Answers
Solving for the 10th term for each of the recursive sequence
First sequence
[tex]\begin{gathered} a_1=32 \\ a_{n+1}=-5+a_n \\ \\ \text{This can be converted to} \\ a_n=a_1+(n-1)(-5) \\ \\ \text{Substitute }n=10 \\ a_{10}=32+(10-1)(-5) \\ a_{10}=32+(9)(-5) \\ a_{10}=32-45 \\ a_{10}=-13 \end{gathered}[/tex]Second sequence
[tex]\begin{gathered} a_1=2048 \\ a_{n+1}=-\frac{1}{2}a_n \\ \\ \text{This can be converted to} \\ a_n=a_1\cdot\Big(-\frac{1}{2}\Big)^{n-1} \\ \\ \text{Substitute }n=10 \\ a_{10}=2048\cdot\Big(-\frac{1}{2}\Big)^{10-1} \\ a_{10}=2048\cdot\Big(-\frac{1}{2}\Big)^9 \\ a_{10}=-4 \end{gathered}[/tex]Third sequence
[tex]\begin{gathered} a_1=0.125 \\ a_{n+1}=2a_n \\ \\ \text{This can be converted to} \\ a_n=a_1\cdot2^{n-1} \\ \\ \text{Substitute }n=10 \\ a_{10}=0.125\cdot2^{10-1} \\ a_{10}=0.125\cdot2^9 \\ a_{10}=64 \end{gathered}[/tex]Fourth sequence
[tex]\begin{gathered} a_1=-7\frac{2}{3} \\ a_{n+1}=a_n+1\frac{2}{3} \\ \\ \text{This can be converted to} \\ a_n=a_1+(n-1)\Big(1\frac{2}{3}\Big) \\ \\ \text{Substitute }n=10 \\ a_{10}=-7\frac{2}{3}+(10-1)\Big(1\frac{2}{3}\Big) \\ a_{10}=\frac{-23}{3}+(9)\Big(\frac{5}{3}\Big) \\ a_{10}=-\frac{23}{3}+\frac{45}{3} \\ a_{10}=\frac{22}{3} \\ a_{10}=7\frac{1}{3} \end{gathered}[/tex]Arranging the formulas from least to greatest according to their 10th terms, we have the following:
First Sequence → Second Sequence → Fourth Sequence → Third Sequence
Related Questions
Solve for r and s. 2r + 6s =6 and 6r +2s =2 what kid of line are they
Answers
r = 0, s = 1
The lines are neither parallel nor perpendicular
Explanation:The given equations are:
2r + 6s = 6........(1)
6r + 2s = 2........(2)
Multiply equation (1) by 3
6r + 18s = 18........(3)
Subtract equation (2) from equation (3)
16s = 16
s = 16/16
s = 1
Substitute s = 1 into equation (2)
6r + 2(1) = 2
6r + 2 = 2
6r = 2 - 2
6r = 0
r = 0/6
r = 0
Make r the subject of the formula in equation (1)
2r = -6s + 6
r = -3s + 6
The slope of the line represented by equation (1) = -3
Make r the subject of the formula in equation (2)
6r = -2s + 2
r = (-2/6)s + (2/6)
r = (-1/3)s + 1/3
The slope of the line represented by equation (2) = -1/3
As seen above, the slope are not equal and are not negative inverses of each other. therefore, the lines are neither parallel nor perpendicular
1 pointQuestion 5: Which one is NOT a correct description of these angles? *119BThey create a right angle.They are adjacent angles.UΟ Ο Ο ΟO They are complementary angles.O They are supplementary angles.
Answers
SOLUTION:
The one that is not a correct description of these anles is tption D. (They are supplementary angles)
EXPLANATION:
Two angles are said to be supplementary if they add up to be 180 and considering the sum of these angles which is 90 (right angle)
Find the center and the radius of the circle whose equation is x^2+y^2+8x-10y-23=0
Answers
Finding the equation of the standard form:
[tex]\begin{gathered} x^2+y^2+8x-10y-23=0 \\ x^2+y^2+8x-10y=23 \\ x^2+8x+16+y^2-10y+25=23+16+25 \\ \\ \\ (x+4)^2+(y-5)^2=64 \end{gathered}[/tex]
Based on the image, h = -4, k = 5 and r = 8, then...
Answer:
Center: ( -4, 5)
Radius: 8
Answer:the center would be (-4 -5)
Hope this helps
Compare the ratios in Table 1 and Table 2. Table 1 5 6 10 9 15 12 20 Table 2 7 10 20 21 30 28 40 Which statements about the ratios are true? Check all that apply. The ratio 3:5 is less than the ratio 7:10. Save and Exit Nexd Mark this and return
Answers
Table 1
3:5 , 6 : 10 , 9 :15 , 12 : 20
Table 2
7 : 10 , 14 : 20 , 21 : 30 , 28 : 40
Notice that all ratios in each table are equal. Additionally, since:
[tex]\frac{3}{5}=\frac{6}{10}[/tex]And 6<7, then the ratio 3:5 is less than the ratio 7:10.
Therefore, all ratios in table 1 are less than all ratios in table 2.
Some specific comparisons between ratios may apply as well. For example:
The ratio 14:20 (table 2) is greater than the ratio 9:15 (table 1).
write the number 9,700,000 in scientific notation
Answers
Explanation
[tex]9700000[/tex]All numbers in scientific notation or standard form are written in the form
[tex]a\cdot10^b^{}[/tex]where a is a number between 1 and 10, and b is a integer positive or negative
Step 1
Move the decimal 6 times to left in the number so that the resulting number, a= 9.7, is greater than or equal to 1 but less than 10
so
Cindy read a total of 8 books over 2 months. If Cindy has read 20 books so far, how many
months has she been with her book club? Solve using unit rates.
months
Submit
3
Answers
The points U, V, W and X all lie on the same line segment, in that order, such that the ratio of UV : VW:W X is equal to 1:3 : 4. If U X = 8, find VX.
Answers
The points U, V, W and X all lie on the same line segment, in that order, such that the ratio of UV : VW:W X is equal to 1:3 : 4. If U X = 8, find VX.
In this problem we have that
UV+VW+WX=UX -----> by addition segment postulate
we have
UX=8 units
so
UV+VW+WX=8 -------> equation A
UV/VW=1/3 ------> equation B
UV/WX=1/4 -----> equation C
Solve the system of equations
In equation B isolate the variable VW
so
3UV=VW
VW=3UV -------> equation D
In equation C isolate the variable WX
4UV=WX
WX=4UV ------> equation E
Substitute equation D and equation E in equation A
UV+(3UV)+(4UV)=8
solve for UV
8UV=8
UV=1
Find VW
VW=3UV
VW=3(1)=3 units
FInd WX
WX=4UV
WX=4(1)=4 units
Find out the value of VX
we have that
VX=VW+WX
substitute
VX=3+4=7 units
therefore
VX=7
Yurly and his brother Anduray are each mailing a birthday gift to a friend. Yuriy's package weighs one lesspound than three times the weight of Anduray's package. The combined weight of both packages is 7pounds.Part 3: Yuriy and Anduray each graph the system that represents this situation. Who is correct? Explain why.
Answers
Yuriy
Explanations:[tex]\begin{gathered} \text{Let the weight of Yuriy's package be w}_y \\ \text{Let the weight of Anduray's package be w}_a \end{gathered}[/tex]Yuriy's package weighs one less pound than three times the weight of Anduray's package.
[tex]w_y=3w_a-1[/tex]The combined weight of both packages is 7 pounds
[tex]w_y+\text{ }w_a=\text{ 7}[/tex]The graph representing the two equations is:
how to solve 7.-4y=48
Answers
solve for y
[tex]\begin{gathered} 7-4y-7=48-7 \\ -4y=41 \\ -\frac{4y}{-4}=\frac{41}{-4} \\ y=-\frac{41}{4} \end{gathered}[/tex]Answer:
y = -41/4 or 10.25
Step-by-step explanation:
7 - 4y = 48
Move 7 across the equals sign to make y stand alone
-4y = 48 - 7
= 41
Divide both sides by the coefficient of y, which is -4
-4y/4 = 41/4
y = -41/4 or 10.25
A line has a slope of 2/3 and contains point A(-6,-4) and point B (a, 2) what is the value of a?
Answers
From the point-slope formula, we have:
[tex]y-y_0=m(x-x_0)[/tex]where m is the slope, (x_0,y_0) are known points.
In this case, we have the slope and two points, we can substitute in the formula to get:
[tex]\begin{gathered} \text{if:} \\ (x,y)=(-6,-4) \\ \text{and} \\ (x_0,y_0)=(a,2) \\ \Rightarrow-4-2=\frac{2}{3}(-6-a) \\ \Rightarrow-6=-\frac{2\cdot6}{3}-\frac{2}{3}a \\ \Rightarrow-6=-4-\frac{2}{3}a \\ \Rightarrow-6+4=-\frac{2}{3}a \\ \Rightarrow-2=-\frac{2}{3}a\Rightarrow a=-\frac{2}{-\frac{2}{3}}=\frac{3\cdot2}{2}=\frac{6}{2}=3 \\ a=3 \end{gathered}[/tex]therefore, a=3
Note: you can also find a if you use the slope formula.
3a) Find length between A(-3,8) and B(5,-4) in simplest radical form:
Answers
Find length between A(-3,8) and B(5,-4) in simplest radical form:
we know that
The distance between two points is equal to
[tex]d=\sqrt[]{(y2-y1)^2\text{ +(x2-x1)\textasciicircum{}2}}[/tex]we have
(x1,y1)=A(-3,8)
(x2,y2)=B(5,-4)
substitute in the formula
Suzy was reading Aniya's math notebook. Aniya wrote forty-six thousand three hundredfifteen > 46, 350. Suzy replied, "I think there is an errorExplain why Suzy said this using numbers, words, or another method to representyour thinking
Answers
it is an error because the number is
[tex]46,315[/tex]b. expanded form
[tex]\begin{gathered} 40,000+ \\ 6,000 \\ 300 \\ 50 \\ 0 \\ ------ \\ 46,350 \end{gathered}[/tex]c. 46,350 to the nearest thousand
[tex]46,350\longrightarrow46,000[/tex]Weights of 2-year-old girls are normally distributed with a mean of 253 lbs, and a standarddeviation of 1.12 lbs. According to this information, what weight would be the 33rd percentile? You must
Answers
We have here a case of a normally distributed variable. We can solve this kind of problem using the standard normal distribution, and the cumulative standard normal table (available in any Statistic Book, or on the internet).
We have that we can find z-scores to normalized the situation, and then, using the cumulative standard normal table, we can find the percentile. Then, we have:
[tex]z=\frac{x-\mu}{\sigma}[/tex]In this case, we need to find the raw value, x. We need to find a z-score that represents that before it there are 33% of the cases for this distribution: in this case, the value for z is approximately equal to z = -0.44.
Now, we have the mean (253 lbs), and the standard deviation (1.12 lbs):
[tex]-0.44=\frac{x-253}{1.12}[/tex]And now, we can determine the value, x, which is, approximately, the 33% percentile of this normal distribution:
1. Multiply by 1.12 to both sides of the equation:
[tex]1.12\cdot(-0.44)=\frac{1.12}{1.12}\cdot(x-253)\Rightarrow-0.4928=x-253[/tex]2. Add 253 to both sides of the equation:
[tex]-0.4928+253=x-253+253\Rightarrow252.5072=x\Rightarrow x=252.5072[/tex]Therefore, the weight that would be the 33rd percentile, is, approximately, x= 252.5072 or 252.51lbs (rounding to the nearest hundredth).
Simple Interest Practice P5(A)-2135-7-MATH / Simple Interest 2. What was the original amount deposited on an account with a total amount of $80 in the account after 8 years with a 2% interest rate?
Answers
The formula to use for solving simple interest rate problems is:
[tex]i=\text{Prt}[/tex]Where
i is interest accumulated
P is the initial, or principal, amount
r is the rate of interest [in decimal]
t is the time
Given,
Total amount in account is 80 [principal plus interest]
rate is 2%
time is 8 years
Let's write:
[tex]\begin{gathered} 80=P+\text{Prt} \\ 80=P(1+rt) \\ 80=P(1+(0.02)(8)) \\ 80=P(1+0.16) \\ 80=P(1.16) \\ P=\frac{80}{1.16} \\ P=68.9655 \end{gathered}[/tex]The amount in the account was around $68.97
2(x+4)=150+ (-2) can u solve
Answers
Given equation:
[tex]2(x+4)\text{ = 150 + (-2) }[/tex]Open the bracket:
[tex]\begin{gathered} 2x\text{ + 8 = 150 - 2} \\ 2x\text{ + 8 = 148} \end{gathered}[/tex]Collect like terms:
[tex]\begin{gathered} 2x\text{ = 148 - 8} \\ 2x\text{ = 140} \end{gathered}[/tex]Divide both sides by 2:
[tex]\begin{gathered} \frac{2x}{2}\text{ = }\frac{140}{2} \\ x\text{ = 70} \end{gathered}[/tex]Answer:
x = 70
A worker is getting a 3% raise. His current salary is $35,868. How much will his raise be?
Answers
Hello there. To solve this question, we'll simply have to multiply the percent and the salary to find how much will the raise of the worker.
Given his salary: $35,868 and knowing he'll get a 3% raise, we make:
3/100 * 35,868
107,604/100 = 1,07604
Rounding up the answer to the nearest tenth, we have that his raise will be $1,1.
In the coordinate plane the vertices of angle RST are R(6,-1) S(1,-4) and T(-5,6). Prove that angle RST is a right triangle. State the coordinates of point P such that quadrilateral RSTP is a rectangle. Prove that your quadrilateral RSTP is a rectangle.
Answers
We are given coordinates of three points RST and are asked to prove that it forms a Right Triangle.
We kn
Can you please help me out with a question
Answers
We have the following diagram
We are told that the arc NOL has an angle measure of 300°. Recall that the angle measure of the whole circle is 360°. Since the whole circle is the sum of the measures of arcs LMN and NOL we have that the measure of the arc LMN is
[tex]\text{LMN+NOL=360}[/tex][tex]\text{LMN}+300=360[/tex]By subtracting 300 on both sides, we get
[tex]\text{LMN=360-300=60}[/tex]so arc LMN has a measure of 60°. However, note that measure of the arc LMN is the sum of the measures of arcs LM and MN. So
[tex]LM+MN=\text{LMN}=60[/tex]Now, note since lines MX and LM are perpendicular, we can do the following drawing
We can take a look at triangles LDX and NDX. Since the angles NDX and XDL are perpendicular, we can think of line MX as an axis of symmetry. That is, the left side of the circle with respect line MX is an exact copy of what is on the right. This means that the measure of the arc LM is the same as the measure of the arc MN. So we have that
[tex]LM\text{ + MN = MN+MN=2MN=60}[/tex]So, dividing both sides by 2, we get
[tex]MN\text{ =}\frac{60}{2}=30[/tex]So the measure of the arc MN is 30°.
A coordinate map of the local grocery store is shown below. ice cream is located at the point (-8,0) sprinkles. are located at the point (-8,6)
Answers
The points (-8,0) & (-8,6)
To find the distance between then
Apply the distance formulae for coordinates:
[tex]\text{ Distance=}\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]Substitute the coordinates:
[tex]\begin{gathered} \text{ Distance=}\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ \text{ Distance=}\sqrt[]{(6-0)^2+(-8-(-8))^2} \\ \text{ Distance=}\sqrt[]{6^2+0} \\ \text{Distance =6 units} \end{gathered}[/tex]So, Icecream is 6 units away from the sprinkles
Answer : 6 unit
Which one of the following simplifications is incorrect?
Group of answer choices
sqrt(48x^4)*root(4)(16x^10)=8x^4root(4)(3x^2)
sqrt(4x)*sqrt(12x^8)=4x^4sqrt(3x)
sqrt(x^3)*sqrt(xy^4)= x^2y^2
root(3)(64)*sqrt(18)=12sqrt(2)
Answers
After simplification, the option 2, [tex]\sqrt{4x}\times \sqrt{12x^8}=4x^4\sqrt{3x}[/tex] is correct option.
In the given question,
We have to find which simplifications is incorrect.
Option 1: [tex]\sqrt{48x^4}\times\sqrt[4]{16x^{10}}=8x^4\sqrt[4]{3x^2}[/tex]
To check whether the given expression is true or not simplifying the left hand side expression.
We simplifying the left hand side by writing it as
[tex]\sqrt{48x^4}*\sqrt[4]{16x^{10}}=\sqrt{16\times3\times (x^2)^2}\times\sqrt[4]{(2)^4\times x^{8}\times x^2}[/tex]
[tex]\sqrt{48x^4}*\sqrt[4]{16x^{10}}=\sqrt{(4)^2\times3\times (x^2)^2}\times\sqrt[4]{(2)^4\times (x^{2})^4\times x^2}[/tex]
Now simplifying the roots
[tex]\sqrt{48x^4}*\sqrt[4]{16x^{10}}=4\times x^2\times\sqrt{3}\times2\times x^2\times\sqrt[4]{ x^2}[/tex]
Now writing it in a simplified form
[tex]\sqrt{48x^4}*\sqrt[4]{16x^{10}}=8\times x^{2+2}\times\sqrt{3}\sqrt[4]{ x^2}[/tex]
[tex]\sqrt{48x^4}*\sqrt[4]{16x^{10}}=8x^{4}\sqrt{3}\sqrt[4]{ x^2}[/tex]
Hence, the simplified form of [tex]\sqrt{48x^4}*\sqrt[4]{16x^{10}}[/tex] is [tex]8x^{4}\sqrt{3}\sqrt[4]{ x^2}[/tex].
So the given statement is wrong.
Option 2. [tex]\sqrt{4x}\times \sqrt{12x^8}=4x^4\sqrt{3x}[/tex]
To check whether the given expression is true or not simplifying the left hand side expression.
We simplifying the left hand side by writing it as
[tex]\sqrt{4x}\times \sqrt{12x^8}=\sqrt{(2)^2\times x}\times \sqrt{3\times4\times (x^4)^2}[/tex]
[tex]\sqrt{4x}\times \sqrt{12x^8}=\sqrt{(2)^2\times x}\times \sqrt{3\times(2)^2\times ({x^4})^2}[/tex]
Now simplifying the roots
[tex]\sqrt{4x}\times \sqrt{12x^8}=2\sqrt{x}\times 2\times x^4\times\sqrt{3}[/tex]
[tex]\sqrt{4x}\times \sqrt{12x^8}=4x^4\sqrt{3x}[/tex]
Hence, the simplified form of [tex]\sqrt{4x}\times \sqrt{12x^8}[/tex] is [tex]4x^4\sqrt{3x}[/tex].
Hence, the option 2 is correct.
Since we get the write answer so we haven't solve the next option.
The next 2 options also can be solved in the way that we use in previous option to solve.
So the option 2 [tex]\sqrt{4x}\times \sqrt{12x^8}=4x^4\sqrt{3x}[/tex] is correct option.
To learn more about the simplification of expression link is here
https://brainly.com/question/14575743
#SPJ1
Jamie is cutting for a craft project.she has a ribbon that is 2 1/4 inches long. How many pieces of ribbon can she cut that are 3/8inches long
Answers
Total Lenght = 2 1/4
Lenght of each piece = 3/8
Divide the total lenght by the lenght of each piece:
Total lenght = 2 1/4 = (2*4+1)/4 = 9/4
Total lenght / lenght of each piece = (9/4 ) / (3/8)
To divide 2 fractions we can multiply by the inverse of the second fraction:
[tex]\frac{9}{4}\times\frac{8}{3}=\frac{72}{12}[/tex]Simplify by 12:
6
Answer: 6 pieces
Student Beyonce You decide to buy a Super Size Hamburger Combo at the Burger Princess for 5.95. much change would you receive from 10.00. division Subtraction multiplication addition
Answers
Answer: 4.05
Just subtract 10.00 by 5.95 to get 4.05
hope this helps :)
how to solve this problem
Answers
Let
x -----> number of students that preferred vanilla cupcakes
y ----> number of students that preferred chocolate
we know that
x+y=750 -----> equation A
and
2/5=x/y
x=(2/5)y ------> equation B
substitute equation B in equation A
(2/5)y+y=750
solve for y
(7/5)y=750
y=750*5/7
y=536
find the value of x
x=(2/5)(736)
x=214
therefore
the answer is 214 students preferred vanilla cupcakes801/4 is 5% of what number
Answers
5% could be express as 0.05
a number coul be express as x
then
[tex]x*0.05=\frac{801}{4}[/tex]solving for a number (x)
[tex]x=\frac{801}{4*0.05}=4005[/tex]4005
Galina runs a bakery, where she sells packages of 4 dozen cookies for $24.96 per package. The amount of money she makes by selling x packages is represented by the function f(x)=24.96x, and her cost for making each package is g(x)=0.04x2+4x+71.If profit is equal to sales minus cost, which function represents her profit, p?
Answers
Answer:
p(x) = f(x) - g(x) = -0.04x² + 20.96x - 71
Explanation:
The sales are given by f(x) = 24.96x and the cost are represented by g(x) = 0.04x² + 4x + 71.
Then, the profit is equal to
p(x) = f(x) - g(x)
p(x) = 24.96x - (0.04x² + 4x + 71)
p(x) = 24.96x - 0.04x² - 4x - 71
p(x) = -0.04x² + 20.96x - 71
Therefore, the answer is
p(x) = f(x) - g(x) = -0.04x² + 20.96x - 71
-2v + 9 = 25 what is it?
Answers
-2v + 9 = 25
-2v=25-9
-2v=16
v=16/-2
v=-8
Help me question 20 please find the domain and range
Answers
Suppose 225 trout are seeded into a lake. Absent constraint, their population will grow by 25% a year. If the lake can sustain a maximum of 3500 trout, use a logistic growth model to estimate the number of trout after 5 years. trout
Answers
It is known that the population growth model is given by:
[tex]P=P_0e^{kt}[/tex]Initial population is 225 so P0=225 so it follows:
[tex]P=225e^{kt}[/tex]Each year the population will increase by 25% so it follows:
[tex]\begin{gathered} P_0+0.25P_0=225e^k \\ e^k=\frac{5}{4} \\ k\ln e=\ln (\frac{5}{4}) \\ k\approx0.2231 \end{gathered}[/tex]So the population function is:
[tex]P=225e^{0.2231t}[/tex]The population in 5 years is given by:
[tex]P=225e^{0.2231\times5}\approx686.4960025[/tex]Hence the population of trout will be 686.4960025 after 5 years which can be rounded to 687.
A random sample of n= 100 observations is selected from a population with u = 30 and 6 = 21. Approximate the probabilities shown below.a. P(x228) b. P(22.1sxs 26.8)c. P(xs 28.2) d. P(x 2 27.0)Click the icon to view the table of normal curve areas.a. P(x228)(Round to three decimal places as needed.)
Answers
Problem Statement
We have been given random sample of 100 observations and we have been asked to find the probabilities of getting certain observed values given the population mean of 30 and a standard deviation of 21.
Method
To solve this question, we need to:
1. Find the z-score of the observations. The formula for calculating the z-score is:
[tex]\begin{gathered} z=\frac{X-\mu}{\sigma} \\ \text{where,} \\ X=\text{ The observed value} \\ \mu=\text{population mean} \\ \sigma=\text{ standard deviation} \end{gathered}[/tex]2. Convert the z-score to probability using the z-score table.
Implementation
Question A
1. Find the z-score of the observations.:
[tex]\begin{gathered} X\ge28 \\ \mu=30,\sigma=21 \\ z\ge\frac{28-30}{21} \\ z\ge-\frac{2}{21} \\ \\ \therefore z\ge-0.0952 \end{gathered}[/tex]2. Convert the z-score to probability using the z-score table.:
Using a z-score calculator, we have the probability to be:
[tex]P(z\ge-0.0952)=0.037938[/tex]This probability is depicted in the drawing below:
If the mean is represented by 0 and the right-hand side of 0 has a probability of 0.5, then the probability of getting greater than or equal to 28, is the addition of the probability 0.037938 gotten above with the 0.5 on the right-hand side of zero.
Thus, the answer to Question A is:
[tex]\begin{gathered} P(X\ge28)=0.037938+0.5=0.537938 \\ \\ \therefore P(X\ge28)\approx0.538\text{ (To 3 decimal places)} \end{gathered}[/tex]
Question B:
[tex]undefined[/tex]Interior angle sum of a polygon: Find all the variables
Answers
We can see that angle d is the supplement of 97°. So d = 180°-97°= 83°
We can see that angle c and 97° are corresponding. So c=97°
If we see the triangle we can deduce that it is isosceles. So, the angles of the triangle would be (26°, 77°, 77°)( Since the sum of all angles must be equal to 180° and two angles must be equal)
The angle a is the supplement of angle 77°, so a= 180°- 77° = 103°.
The angle b is the supplement of angle 77°, so b= 180°- 77° = 103°.
Finally, we can find the angle e formulating the following equation:
540° - a - b - c- d = e (Since the sum of the angles of a pentagon must be equal to 540°)
540° - 103° - 103° - 97° - 83° = e (Replacing)
154° = e (Subtracting)