a homogeneous cylinder of radius r and height h floats at the interface of two fluids with densities. if p2

Answers

Answer 1

The pressure differential between the cylinder's top and bottom is expressed as

Δp=gH/2(Pa+Pb)

define homogeneous ?

A homogeneous population is one that is made up of components or pieces that are all of the same sort; it is not heterogeneous.

Mathematics.

possessing a common quality throughout: a homogenous solid figure.

A homogeneous equation has all terms of the same degree.

when each variable is multiplied by that constant, the function of numerous variables gets multiplied by some power of that constant: x2y3 is a degree 5 homogeneous expression related to a differential equation in which a linear combination of derivatives is set to zero.

As we know, the weight of the cylinder balances the force due to pressure.

As a result, we will have

F=mg

so we have

Δpπr^2=mg

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Related Questions

A train is moving at a speed of 65.0 mi/h. The ticket collector is walking 2.00 mi/h toward the front of the train. How fast is the ticket collector moving from the point of view of a person on the train?

Answers

Answer:

the ticket collector is moving at 2.00 mi/h in the same direction, the relative speed of the ticket collector to the person on the train is 65.0 mi/h - 2.0 mi/h = 63.0 mi/h.

Explanation:

From the point of view of a person on the train, the ticket collector is moving at a speed of 63.0 mi/h. To determine this, we need to subtract the speed of the train from the speed of the ticket collector in the same direction. Since the train is moving at 65.0 mi/h

In a hydraulic press the large piston has cross-sectional area 230 cm2 and the small piston has cross-sectional area 5 cm2. If a force of 250 N is applied to the small piston, what is the force (in kN) on the large piston? Give the answer with one decimal an no unit.

Answers

The force on the larger piston of cross-sectional area 230 cm² is 11500 N.

What is force?

Force can be defined as the product of mass and acceleration.

To calculate the force on the larger piston, we use the formula below.

Formula:

F = fA/a............... Equation 1

Where:

F = Force on the larger pistonf = Force applied to the smaller pistonA = Cross-sectional  Area of the larger pistona = Cross-sectional Area of the smaller piston

From the question,

Given:

A = 230 cm²a = 5 cm²f = 250 N

Susbtitute these values into equation 1

F = (250×230)/5F = 11500 N

Hence, the force on the larger piston is 11500 N.

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a few objects with the same mass and radius are rotating around axes through their centers. which of these objects would be the easiest to stop from rotating?

Answers

The hollow sphere would be the easiest to stop from rotating. The body's moment of inertia and angular velocity combine to form the angular momentum: L=I ω

I = (2/5)MR2 (solid) and I = (2/3)MR2 (hollow) are the moments of inertia for spheres of any diameter that are solid and hollow, respectively (hollow)

A HOLLOW sphere has a higher angular momentum than a solid sphere with the same mass and rotational velocity because (2/3)>(2/5).

If they were the same size and made of the same material, the solid sphere would, intuitively, have a higher angular momentum (and therefore different mass). To illustrate this, consider a hollow sphere with a wall thickness of R. Its volume is thus Vol=4R2R.

Since M=V and is the density, I(hollow)=(8/3)R4R is the moment of inertia.

I(solid) = ρ(8π/15)R^5

hence, I (solid)/I (hollow)

=(1/5)R/∆R

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about the atmospheric winds at different heights on the giant planets, which one of the following statements is not correct?

Answers

"Saturn has the strongest magnetic field among all planets in our solar system," statement is incorrect.

What is a magnetic field?

A magnetic field, a vector field that describes the magnetic influence on moving electric charges, electric currents, and magnetic materials. When a charge moves through a magnetic field, a force that is perpendicular to both its own velocity and the magnetic field operates on it.

The magnetosphere, a massive magnetic bubble formed by forces deep inside Saturn, has a significant impact on the space environment close to the planet. Deep within the planet's fluid innards, material cycles produce Saturn's magnetic field.

The solar wind, or flow of electrically charged solar particles (electrons and ions), travels across the solar system at a million miles per hour beyond Saturn's magnetosphere. The magnetosphere of Saturn develops when the solar wind collides with its own magnetic field. The magnetic forces of the sun are strongest outside the planet's magnetosphere, while Saturn's magnetic fields are strongest inside the planet's protective envelope.

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In the laboratory, you connect a resistor and a capacitor with unknown values in series with a battery of emf ε = 12 V. You include a switch in the circuit. When the switch is closed at time t = 0, the circuit is completed, and you measure the current through the resistor as a function of time as plotted below. A data-fitting program finds that the current decays according to the equation Using common symbols for the battery, the resistor, the capacitor, and the switch, draw the circuit that you constructed (on paper). Show the circuit before the switch is closed and include whatever other devices you need to measure the current through the resistor to obtain the above plot. Label each component in your diagram.

Answers

The voltage across the capacitor is VC=qC since the formula for capacitance is C=q/V. Ohm's law states that the current is defined as I=dq/dt and the potential drop across the resistor is VR=IR.

What happens when a capacitor and a resistor are connected in series?

A series connection between a resistor and a capacitor creates an RC circuit, which charges the capacitor progressively through the resistor until the voltage across it equals the supply voltage. The time needed to fully charge the capacitor is about equal to 5 time constants, or 5T.

How can a capacitor with a resistor issue be fixed?

Simply use V=IR, where V is the battery voltage and R is the resistor resistance, to determine the current flowing through the circuit, and then solve for I. When the capacitor is finished charging, the current has progressively decreased and is getting close to zero.

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Energy stored as a result of deformation of an elastic object

A.Thermal Energy
B.Chemical Potential Energy
C.Elastic Potential Energy
D.Energy Transfer

Answers

Elastic potential energy is the  energy stored as a resulting of the applying a force to deform an elasticity object.

What is elastic potential energy?

Elastic potential energy is the  energy stored as of a result of applying a force to the  deform an elasticity object. The energy is the  stored until the force is to the  removed and the object by  springs back to it's own shape, doing work in the process.

Elastic potential energy is the  energy stored as a result of the applying by a force to the  deform an elasticity of object. The energy is stored by it's until the force is the  removed and the object of the  springs back to its own original shape, doing their work in the processing. There are deformations could involve compressions, stretching or the twisting of the object.

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you hold a spherical salad bowl 50 cm in front of your face with the bottom of the bowl facing you. the salad bowl is made of polished metal with a 36 cm radius of curvature.(a) Where is the image of your 5.0-cm-tall nose located?(b) What are the image’s size, orientation, and nature (real or virtual)?

Answers

a) q = 28.57 cm ,  b)   h ’=  -0.114 cm  the image is inverted and REAL

How does physics create an image?

Because light can come from an item in many different directions, a picture can be created. According to the rule of reflection, some of the light (which we depict as rays) hits the screen and reflected off of it.

Briefing:

For this exercise we will use the equation of the constructor

         1 / f = 1 / p + 1 / q

where f is the focal length of the salad bowl, p and q are the distance to the object and the image

The metal salad bowl behaves like a mirror, so its focal length is

          f = R / 2

          f =36/2

          f = 18 cm

a) Suppose that the distance to the object is p = 50 cm, let's find the distance to the image

          1 / q = 1 / f  - 1 / p

          1 / q = 1/18 - 1/50

          1 / q = 0.035

           q =28.57 cm

b) to calculate the size of the image we use the equation of magnification

          m = h’/ h = - q / p

           h ’= - q / p h

           h ’= - 28.57 / 50×5

           h ’= -0.114 cm

The negative sign means that the image is inverted

As the rays of light pass through the image this is REAL.

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Find the depth in a lake at which the pressure is 173.693 lb/in2.

Answers

The depth in the lake of pressure 173.693 lb/in² is 122.45 m.

What is depth?

Depth is the distance down either from the top of something to the bottom, or to a distance below the top surface of something.

To calculate the depth in the lake, we use the formula below.

Formula:

h = P/gD........................ Equation 1

Where:

h = Depth in the lakeP = Pressure D = Density of waterg = Acceleration due to gravity

From the question,

Given:

P = 173.693 lb/in² = 1.2×10⁶ N/m²g = 9.8 m/s²D = 1000 kg/m³

Substitute these values in to equation 1

h = (1.2×10⁶)/(9.8×1000)h = 122.45 m

Hence, the depth in the lake is 122.45 m.

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Which of the following quantities is conserved for plant orbiting a star in a circular orbit? Only the planet itself is to be taken as the system the star is not included a. Momentum and energy b. Energy and angular momentum c. Momentum, angular momentum and energy d. None of the above.

Answers

Energy and angluar momentum quantity is conserved for plant orbiting a star in a circular orbit.

What is energy?

Energy is ability to do the work.scientist defines energy as the ability to do work.

Energy and angular momentum, arter all other factors- change.

In the Earth-Satellite system, a gravitational force acts to the  join the two bodies. Thus, there is no torque due by  to gravitational force. Hence, the angular velocity is conserved.

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You would like a pendulum that swings back and forth once every 2 seconds, but the one you have swings once every 1.9 seconds. Which of the following should you do to adjust it so that it has the desired period?a) Add more mass to the pendulum.b) Make the pendulum slightly longer.c) No answer text providedd) Remove some mass from the pendulum.e) No answer text provided.f) Make the pendulum slightly shorter.

Answers

You need to make your pendulum slightly longer

What is a pendulum?

A pendulum is a body suspended from a fixed point so that it can swing back and forth under the influence of gravity. The time interval of a pendulum's complete back-and-forth movement is constant.

Your pendulum does a complete swing in 1.9 seconds.  You want to SLOW IT DOWN so it takes 2.0 seconds.

Longer pendulums swing slower.

You need to make your pendulum slightly longer

If your pendulum is hanging by a thread or a thin string, then its speed doesn't depend at all on the weight at the bottom. You can add weight or cut some off, and it won't change the speed a bit.  

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Problem 4 Consider two superconducting wires, tin (Sn, Type I) and Nb3Sn (Type II), each 1 mm in thickness. The magnetic field on the surface of a current-carrying conductor is given by BMol 2nr a) Assuming that Sn wire loses its superconductivity when the field at the surface reaches the critical field (0.2 T), calculate the maximum current and hence the critical current density that can be passed through the Sn wire near absolute zero of temperature. b) Calculate the maximum current and critical current density for Nb3Sn wire using the same assumption as in part (a) but taking the critical field to be the upper critical field Bc2, which is 24.5 T at 0 K. How does your calculation of Je compare with the critical current density of about 10" A/m² for Nb3Sn at OK?

Answers

This value is close to the experimental value of approx. 1011 A/m2

Super conductivity, or current flow with zero electric resistance, is the ability to conduct electricity without suffering energy losses.

The superconductivity is quenched when current through the wire causes the critical magnetic field at the wire surface.

Given that,

B = 0.2T

R = 0.001m (R = r/2)

a. Maximum current, critical current density

Ic = B*2πr / μo

Ic = {0.2 * 2 * (22/7) * (0.001/2)} / 4 * (22/7) * 10-7

Ic = 500A

Thus, maximum current Jc=Ic/A = 6.363 * 108 A/m2

It turns out that the critical current density for TYPE I superconductors is indeed in the range of this magnitude. The superconductivity is destroyed by a current that produces a field on the conductor surface that is equivalent to B.

b. Type II superconductor, Nb3Sn

Critical field is the upper critical field, B2

Ic = B*2πr / μo

Given that, B = 24.5T,   Thickness = 0.001m

 Ic = {24.5 * 2 * π * (0.001/2)} / 4 * π *10-7

 Ic = 61250A

Thus, Maximum Current Jc= Ic/A = 7.795 * 1010 A/m2

This value is close to the experimental value of approx. 1011 A/m2

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Bumper car A (296 kg) moving +3.74 m/s makes an
elastic collision with bumper car B (222 kg) moving
+1.85 m/s. What is the velocity of car A after the
collision?
Use the formula to find the final velocity of car A.
Bumper Car A
m₁ = 296 kg
V₁i = 3.74 m/s
m₁ - m²)√₁i+
m1
m2
V₁f = (m
Bumper Car B
m₂ = 222 kg
V2i = 1.85 m/s
(m²
2m²)V₂i = [?] m/s
m₁ + m2
m₁ + m2
Remember: right is +, left is -.

Answers

The speed of car A after the collision is 0.52 m/s.

What is speed?

In everyday use and kinematics, the speed of object is the amount of change in position over time, or the amount of change in position per unit time. So it's a scalar quantity.

For a bumper car A

Mass (m₁) = 296 kg

Velocity (V₁) = 3.74 m/s,

For a bumper car B

Mass (m₂) = 222 kg

Velocity (V₂) = 1.85 m/s,

To calculate velocity of car A after the collision mathematically:

Vₙ =(m₁-m₂/m₁+m₂)V₁

Vₙ = Final velocity of car A

Vₙ = (296 - 222/296 + 222) × 3.74

Vₙ = 0.52 m/s

Hence, the velocity of car A after the collision

Vₙ = 0.52 m/s

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An egg is attached to a parachute. It is dropped (starting from rest) from a height of 16 m. The parachutes slows it's acceleration downward to 0.4 m/s^2. It can hit the ground at a velocity of 0.8 m/s without cracking. Does the egg crack when it hits the ground?

A) Yes
B) No

PLEASE HELPPPPPP ME

Answers

An egg is attached to a parachute and dropped from a height of 16 meters, after hitting the ground the egg will crack. Hence, option A is correct.

What is Acceleration?

A moving object's speed and orientation vary over time at a certain rate, which is known as acceleration. An object or location is considered to be accelerated when it moves more quickly or more slowly in a straight path.

A circle's motion increases despite its constant speed because its direction is always changing. For all other motions, by and also to acceleration is used.

Because of its magnitude and direction, it is a vector quantity.

As per the given information in the question,

The egg is attached to a parachute.

The dropping height of the egg is 16 m.

The given velocity is 0.8 m/s.

When the egg will strike the ground with minimal velocity doesn't matter it will break anyway because the out shell of the egg is very smooth or soft and every soft strike will lead to the breaking of the egg.

Then the egg will crack after hitting the ground.

Hence, option A is correct.

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A catcher catches a baseball (m = 145 g) traveling at a speed of 42.5 m/s. How much work was done on the baseball to bring it to rest?

Answers

The net work done on the baseball to bring it to rest is -130.953 J or approximately 131 J. The negative sign indicates that the force has been applied opposite to the direction of motion of the baseball.

What is the work-kinetic energy theorem ?

The work-kinetic energy theorem states that an object's change in kinetic energy is equivalent to the work that has been done on it.

[tex]W_{net} = KE_{f} -KE_{i}[/tex]

Here,

[tex]W_{net}[/tex] = Net work done

[tex]KE_{f}[/tex] = Final Kinetic Energy

[tex]KE_{i}[/tex] = Initial Kinetic Energy

We know,

[tex]KE = \frac{1}{2} mv^{2}[/tex]

Here, m = Mass of the object

v = velocity of the object

Now,

[tex]W_{net} = KE_{f} -KE_{i}\\W_{net}= \frac{1}{2} mv^{2}_{f} - \frac{1}{2} mv^{2}_{i}[/tex]

Given,

Mass of baseball (m) = 145g = 0.145 kg

Initial velocity ([tex]v_{i}[/tex]) = 42.5 m/s

Final velocity ([tex]v_{f}[/tex]) = 0 m/s  (since, the baseball comes to rest.)

Inserting these values in the above equation we get,

[tex]W_{net}= \frac{1}{2} mv^{2}_{f} - \frac{1}{2} mv^{2}_{i}\\ = 0- \frac{1}{2} *0.145*42.5*42.5 \\= -130.953[/tex]

Hence, the net work done on the baseball to bring it to rest is -130.953 J or approximately 131 J.

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The pendulum was released from point A with (MECHANICAL ENERGY) ME = 10J. No Friction is present. What will be the approximate value of velocity at point M if the mass of the pendulum is 0.1 kg

Answers

The approximate value of velocity at point M will be 15 m/s if the mass of the pendulum is 0.1 kg.

What is mechanical energy?

The energy that an object possesses as a result of its motion or position is known as mechanical energy. Kinetic energy, or the energy of motion, and potential energy are two types of mechanical energy (stored energy of position).

According to the question, total mechanical energy of the pendulum at point A = 10 J.

Let the velocity of the pendulum at point M be v.

Then

kinetic energy at point M = total mechanical energy at point A

⇒ 1/2 × 0.1 × v² = 10

⇒ v² = 200

⇒ v = 10√2 = 15 (approx.)

Hence,  the approximate value of velocity at point M  will be 15 m/s.

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A 2.4 × 10-6 C charge experiences a 1.7 × 10-2 N force from a -4.1 × 10-6 C charge. What is the distance separating these two charges?
A.
5.7 × 10-10 m
B.
2.3 m
C.
5.2 m
D.
2.4 × 10-5 m

Answers

The distance separating these two charges is 2.3 m. Hence, option (B) is correct.

What is electric force?

Electric force is the attracting or repulsive interaction between any two charged particles.

Given that: the two charges are 2.4 × 10^-6 C and -4.1 × 10^-6 C.

Force experienced by it =  1.7 × 10^-2 N.

Let the distance between them = r, then

F = kQq/r²

1.7 × 10^-2  = {9×10^9×2.4 × 10^-6×4.1 × 10^-6 }/r^2

r =√[ {9×10^9×2.4 × 10^-6×4.1 × 10^-6 }/ 1.7 × 10^-2  ]

=2.3 m.

Hence, the distance between two charges is 2.3 m.

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b. Calculate the force acting on a falling 2 kg mass.

Answers

Answer: 9.81(2)=19.62N

Explanation:



9. Which Lewis structure represents a molecule with a bent geometry?

Answers

Answer:

The third structure is a bent geometry of a molecule as it consists of one atom of B(boron)and 3 atoms of Cl(chlorine) linked to the atom of and the bond angle is 120°

Answer:

The first one.

Explanation:

Water + HeatObservations Before Interaction

Answers


Proof of a Chemical Reaction Example: Sugar + Heat The sugar is in tiny white particles in a pile. Heat is not seen but is implied by the heat source. The pile of sugar in the pot weighs 100 grams. There is a solid, light brown mass at the bottom of the pot. It weighs 100 grams. Yes, both the reactants and the products weigh the same. There was not a chemical reaction. Sugar did not change composition. It only melted. Melting point is a physical property, and this is a physical change. Steel Wool + Oxygen (Fire) Egg + Heat Water + Heat Zinc+ Hydrogen Chloride Sodium Hydroxide + Copper Sulfate

Consider two carts, of masses m and 2m, at rest on an air track. If you push first one cart for 3 s and then the other for the same length of time, exerting equal force on each, the momentum of the light cart is ________ the momentum of the heavy cart.a) four timesb) twicec) equal tod) one-halfe) one-quarter

Answers

The value of the momentum on the second cart is p₂ = v₂m₂ = 2vm.

What is momentum?

Momentum is defined in Newtonian mechanics as the product of an object's mass and velocity. It is a vector quantity with magnitude and direction. If an object's mass is m and its velocity is v,

Given that consider two carts, of masses m and 2m, at rest on an air track. if you first push one cart for 3 s and then the other for the same length of time, exerting equal force on each.

The momentum on the second cart will be calculated as,

F = m₁ a₁ = m₂ a₂

if m₁ = m and m₂ = 2m :

F = ma₁ = 2m  a₂ ⇒ a₁ = 2 a₂

Since v = at + v₀  with t = 3, v₀ = 0 ⇒ v = 3a:

v₁ = 2 v₂

Since p = vm with v₁ = 2v and v₂ = v :

p₂ = v₂m₂ = 2vm

Therefore, the value of the momentum on the second cart is p₂ = v₂m₂ = 2vm.

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why fan videos be streamed from the cloud to a computer with no lost quality

Answers

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

How do digital signals work?

An established or one that represents data as a step made up of discrete values is known as a digital signal. There is no noise produced by digital signals. Electronic signals sent as pulses are used to transmit digital signals to computers. These signals can be found in things like digital phones and computers.

Because digital signals are used to transport data to and from the cloud, it should be noted that videos are said to stream from the cloud to a computer without quality degradation.

Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.

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about two thirds of the nearby spiral galaxies (which we can study in more detail) don't have a round central bulge, but instead show

Answers

About two-thirds of the nearest spiral galaxies display a central bulge with a bar of stars in the middle rather than a circular central bulge.

What is Spiral Galaxies?

The twisted clusters of stars and gas known as spiral galaxies, which are frequently formed of hot, young stars, have striking shapes. As opposed to the other two major groups of galaxy forms, elliptical and irregular, spiral galaxies make up the majority of the galaxies that astronomers have so far discovered.

A spiral galaxy is one that contains Earth and our solar system, such as the Milky Way.

The majority of spiral galaxies have a flat, spinning disc of stars around a central bulge. Older, fainter stars make up the bulge in the centre, which is thought to house a supermassive black hole. A bar structure runs through the core of almost two-thirds of spiral galaxies, including the Milky Way.

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What is the formula for conservation of energy if there is no resistance and no friction?

Answers

Answer:

If there is no friction then energy is conserved. There are two parts in this case, potential energy and kinetic energy. The object starts out with no kinetic energy and potential energy of PE = mgh where m is the mass, g is acceleration due to gravity and h is its initial height above the ground.

Explanation:

A 1.60 kg, horizontal, uniform tray is attached to a vertical ideal spring of force constant 195 N/m and a 280 g metal ball is in the tray. The spring is below the tray, so it can oscillate up-and-down. The tray is then pushed down 15.0 cm below its equilibrium point (call this point A) and released from rest. a) How high above point A will the tray be when the metal ball leaves the tray? (Hint: This does not occur when the ball and tray reach their maximum speeds.) b) How much time elapses between releasing the system at point A and the ball leaving the tray? c) How fast is the ball moving just as it leaves the tray?

Answers

(a) The height above point A will be the tray when the metal ball leaves the tray is 29.24 cm.

(b) The total time elapses between releasing the system at point A and the ball leaving the tray is 0.09 seconds.

(c) The speed of the ball moving just as it leaves the tray is 1.16 m/s.

A) F= gx

ma=gx

(2.295)(9.8)=190x

X= 11.84 cm

B) h= 11.84+17.4 = 29.24 cm

Y=Acos√kt/m-0

T= 0.09s

C) ½ mv² + ½ ky² = ½ kA²

v² = 1.16m/s

What is speed?

In everyday use and in kinematics, the velocity (commonly referred to as v) of an object is the amount of change in its position over time, or the amount of change in its position per unit time; it is therefore a scalar quantity.

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Suppose your bicycle tire is fully inflated, with an absolute pressure 4.00 x 10^5 Pa at a temperature of 15.0 °C. What is the pressure after its temperature has risen to 40.0 °C? Assume that there are no appreciable leaks or changes in volume.

Answers

The pressure after the temperature has risen to 40.0 °C, assuming that there are no appreciable leaks or changes in volume is 4.35×10⁵ Pa

How do I determine the pressure at 40.0 °C?

From the question given above, the following data were obtained:

Initial pressure (P₁) = 4.00×10⁵ Pa Initial temperature (T₁) = 15 °C = 15 + 273 = 288 K New temperature (T₂) = 40 °C = 40 + 273 = 313 KVolume = ConstantNew pressure (P₂) = ?

The pressure the temperature has risen to 40 °C can be obtained as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

Volume = contant

P₁ / T₁ = P₂ / T₂

4.00×10⁵ / 288 = P₂ / 313

Cross multiply

P₂ × 288 = 4.00×10⁵ × 313

Divide both sides by 288

P₂ = (4.00×10⁵ × 313) / 288

P₂ = 4.35×10⁵ Pa

Thus, the pressure at 40 °C is 4.35×10⁵ Pa

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Which of the following statement describes the coriolis effect? Coriolis effect causes the air moving into a low pressure system to bend to the left in the northern hemisphere Coriolis effect causes the air moving out of a high pressure system to bend to the left in the northern hemisphere. Coriolis effect causes the air moving into a low pressure system to bend to the right in the southern hemisphere. Coriolis effect causes the air moving out of a high pressure system to bend to the left in the southern hemisphere. All of the above

Answers

C is the finest statement to describe the Coriolis effect. The apparent route of ocean currents curves due to the rotation of the Earth.

What is the effect of Coriolis?

This is an evident force, relative to the earth's surface, that causes moving things to the right within the Northern Hemisphere and to the left within the Southern Hemisphere as a result of the earth's rotation.

The Coriolis effect is an apparent force, relative to the earth's surface, that causes moving objects to deflect to the right within the Northern Hemisphere and to the left within the Southern Hemisphere as a result of the earth's rotation.

C is the finest statement to describe the Coriolis effect. The apparent route of ocean currents curves due to the rotation of the Earth.

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Observations suggest that Pluto is covered with icy frost and has a moderately high albedo (0.5). What is
Pluto’s brightness (at the average opposition) relative to the sun if Pluto’s radius is 1120 km?

Answers

Pluto’s brightness relative to the sun is 4.46×10^-7 if Pluto’s radius is 1120 km.

What is albedo?

Albedo, which ranges from 0 (a black body that absorbs all incident radiation) to 1, (a body that reflects all incident radiation), is a measurement of the diffuse reflection of solar radiation out of the total solar radiation.

Given that  albedo of Pluto = 0.5.

Pluto’s radius: R =  1120 km.

Hence, Pluto’s brightness relative to the sun = albedo /(radius)²

= 0.5/(1120×10^3)

= 4.46×10^-7.

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an all so annoying fish fly bug encounters moving vehicle and splatters against the winshield. compared to the force of the car on the bug, the force of the bug on the car is.

Answers

The force exerted by the insect and the automobile is equal and opposite, according to Newton's law.

What exactly is acceleration?

In physics, acceleration is defined as the rate of change in velocity. As a result, the unit is m/s2. According to Newton's second equation of motion, the force acting on a moving body is the product of its mass and acceleration.

As a result, F= ma an implies that the acceleration is inversely proportional to the mass. As a result, a body with more mass will have less acceleration but more force.

An action has an equal and opposite response, according to the third law of motion. Thus, the force exerted by the bug on the car and the force exerted by the car on the bug are equal and opposite, with the bug accelerating faster due to its lower mass.

The force exerted by the insect and the automobile is equal and opposite, according to Newton's law. As a result, their acceleration reduces as their mass grows. As a result, the bug's acceleration will be greater than that of the automobile.

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based on what you know about the moons of saturn, select all of the correct statements from the following list.

Answers

Saturn's atmosphere is substantially less active than Jupiter's because it is twice as far away from the sun.

how many moons are there for saturn ?

Saturn's moons are many and diverse, ranging from small moonlets barely tens of metres wide to Titan, which is bigger than Mercury. Saturn has 83 verified moons with proven orbits that are not contained in its rings, with just 13 having diameters more than 50 kilometres, as well as thick rings with millions of embedded moonlets and uncountable smaller ring particles. Only one or two of Saturn's moons, Titan and maybe Rhea, are massive enough to have collapsed into a relaxed, ellipsoidal form. Titan, the second-largest moon in the Solar System (after Jupiter's Ganymede), has a nitrogen-rich Earth-like atmosphere and a terrain that includes dry river networks.

Smaller moons "shepherd" or retain particles in their rings in the ring system.

Saturn's atmosphere is substantially less active than Jupiter's because it is twice as far away from the sun.

Saturn's rings are largely comprised of ice particles.

Saturn is not the only planet with a ring system, despite being the most extensive.

Some ring particles are miniature moons separated by tidal forces.

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if the mass of an object were doubled, its weight would be

Answers

Weight of a body is defined as the force with which it is attached to the earth.

mass is the total quantity of matter present.

the weight of something is given as mass * acceleration

weight of an object is directly proportional to the mass of the object.  so, if mass doubles, weight will also double.

hope this helps :)

- jeron

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