Probability is calculated as follows:
[tex]P=\frac{\text{ number of favorable outcomes}}{\text{ number of total possible outcomes}}[/tex]In this case:
[tex]P=\frac{7}{28}=\frac{1}{4}[/tex]Hi so some of the problems I don't know like I can't but I did do some problem by myself you can tell me whether it's correct
The symmetric property of equality, if AB = YU. then YU = AB
As per the symmetric property of equality,
if AB = YU. then YU = AB
As per the symmetric property of congurence,
∠H ≅ ∠K then ∠K ≅ ∠H
As per the reflexive property of congurence,
∠PQR ≅ ∠PQR
As per the distibutive property, multiplying the sum of two or more term by a number produces the same result as when each term is multiplied individually by the number and the products are added together.
3(x - 1) = 3x - 3
As per the substitution property one value can replace another value in an expression or equation and the value will remain the same.
If LM = 7, EF + LM = NP
Then EF + 7 = NP
Therefore, the above bits are done as per the property mentioned.
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Number 3.Light travels 1.9x10^5 kilometers per second.there are 6.4 x 10^5 seconds in one week .About how many kilometers does light travel.
helloo
from the question given, we have some variables
[tex]\begin{gathered} \text{speed}=1.9\times10^5\operatorname{km}\text{ /s} \\ \text{time}=6.4\times10^5s \\ \text{distance}=x \end{gathered}[/tex]now the formula for speed is given as
[tex]\begin{gathered} \text{speed}=\frac{\text{distance}}{\text{time}} \\ 1.9\times10^5=\frac{x}{6.4\times10^5} \\ x=(1.9\times10^5)\times(6.4\times10^5) \\ x=1.22\times10^{11}\operatorname{km} \end{gathered}[/tex]Find the vbalie If K, and then write an equation to describee the direct variation.
Given:
x = 9 and y = 6
Use the equation:
y = kx
Where y varies directly as x
K is the constant of proportionality.
Let's find the value of k:
[tex]\begin{gathered} y\text{ = kx} \\ \\ 6\text{ = 9k} \\ \\ \text{Divide both sides by 9:} \\ \frac{6}{9}=\frac{9k}{9} \\ \\ \frac{2}{3}=k \end{gathered}[/tex]k = ⅔
An equation to describe the direct variation is:
[tex]y\text{ = }\frac{2}{3}x[/tex]ANSWER:
[tex]undefined[/tex]Suppose 2' is a normally distributed random variable with ft = 10.3 and 0 = 3.8. For the following probability,draw an appropriate diagram, shade the appropriate region and then determine the value:P(9 <2 ≤ 14) = Note: Enter your answer up to 4 decimal places.
GIVEN
The following values are given:
[tex]\begin{gathered} \mu=10.3 \\ \sigma=3.8 \end{gathered}[/tex]SOLUTION
The z-score for the x values 9 and 14 can be calculated using the formula:
[tex]z=\frac{x-\mu}{\sigma}[/tex]For x = 9:
[tex]\begin{gathered} z=\frac{9-10.3}{3.8} \\ z=-0.34 \end{gathered}[/tex]For x = 14:
[tex]\begin{gathered} z=\frac{14-10.3}{3.8} \\ z=0.97 \end{gathered}[/tex]The probability can be calculated as follows:
[tex]P(9\le x\le14)=Pr(-0.34The region that represents the solution is shown below:Therefore, the probability is given to be:
[tex]P(9\le x\le14)=0.4671[/tex]The probability is 0.4671.
The sum of the two numbers is 133. Four times the smaller of the two numbers equals three times the greater number find the numbers using one variable.
The Solution:
Let the two number be x and y133-x (
Such that:
[tex]\begin{gathered} x<133-x \\ x=small\text{ number} \\ 133-x=larger\text{ number} \end{gathered}[/tex]So,
[tex]\begin{gathered} 4x=3(133-x) \\ \end{gathered}[/tex]Solve for x:
[tex]\begin{gathered} 4x=399-3x \\ \text{ Collect the like terms.} \\ 4x+3x=399 \\ 7x=399 \end{gathered}[/tex]Divide both sides by 7.
[tex]x=\frac{399}{7}=57[/tex]Therefore, the correct nswers are:
57 and 76
u= ak - b solve for a
To solve it for "a" is to isolate "a' in one side, by doing some algebraic operations.
U =ak -b
1) Let's rewrite it
-b+ak=u
2) Add b to both sides
-b +b +ak = u +b
ak = u+b
3) Divide both sides by k
[tex]\frac{ak}{k}=\frac{u+b}{k}[/tex]4) Finally, we have it for 'a':
[tex]a\text{ =}\frac{u}{k}\text{ + }\frac{b}{k}[/tex]a teacher performing a demonstration find that a piece of court displaces 23.5 ml of water . the piece of cork had a density of 5.7 grams. what is the density of the cork
We are asked to determine the density of the cork. To do that we will use the following formula:
[tex]D=\frac{m}{V}[/tex]Where:
[tex]\begin{gathered} D=\text{ density} \\ m=\text{ mass} \\ V=\text{ volume} \end{gathered}[/tex]The volume of the cork is the same as the volume that it displaced of water, therefore, we have:
[tex]V=23.5ml[/tex]Now, we substitute the values and we get:
[tex]D=\frac{5.7g}{23.5ml}[/tex]Solving the operations:
[tex]D=0.24\frac{g}{ml}[/tex]Therefore, the density of the cork is 0.24 g/ml.
express 0.004 in scientific notation
We are asked to express 0.004 in scientific notation
The number 0.004 has the decimal point at the start, so we move this decimal point to the right until there is only one non-zero digit is left (4 in this case) and then count the number of times we moved.
[tex]0.0004=4\times10^{-3}[/tex]In this case, we moved 3 times so the exponent (power) is -3
The sign of exponent is negative when we move to the right (like in this case)
The sign of exponent is positive when we move to the left.
If V1 = (2,4) and V2 = (-1,5), then V1*V2is equal to which of the following? A. (-2,20) , B. 18 , C. 22 , D. (8,-5)
B. 18
Explanation
The dot product or scalar product is an algebraic operation that takes two equal-length sequences of numbers (usually coordinate vectors), and returns a single number
it is given by.
[tex]\begin{gathered} u=(u_x,u_y) \\ v=(v_{_x},v_y) \\ u\cdot v=(u_xv_x+u_yv_y) \end{gathered}[/tex]so, we can find the dot product by multiplying the corresponding values in each vector and adding them together
Step 1
get the dot product
let
[tex]\begin{gathered} v_1=(2,4) \\ v_2=(-1,5) \end{gathered}[/tex]then
[tex]\begin{gathered} v_1\cdot v_2=(2\cdot-1)+(4\cdot5) \\ v_1\cdot v_2=-2+20 \\ v_1\cdot v_2=18 \end{gathered}[/tex]therefore, the answer is
B. 18
I hope this helps you
46 = -6t - 8 what is t
t=9,
1) Solving for t we have:
46 = -6t - 8 Add 8 to both sides
46+8 = -6t
54 = -6t Divide both sides by -6
9 = t Flipping it
t=9
2) So the Solution Set is S={9} for this equation.
Two cards are drawn from a deck of 52 cards. The first card is replaced before drawing the second card. Find the probability that the first card is red and the second card is a 7
The probability that the first card is red and the second card is a 7 is 1/26.
What is the probability?Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.
Probability that the first card is a red and the second is a 7 = (number of red cards / total number of cards) x (number of 7 / total number of card)
Probability that the first card is a red and the second is a 7 = (26 / 52) x (4/52) = 1/26
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ANSWER QUESTION 3 PHOTO ATTACHEDFAST REPLY = BETTER RATINGTHANK YOU!
Given
[tex]f(x)=xe^{7x}[/tex]Calculate the second derivative of f(x), as shown below
[tex]\begin{gathered} \Rightarrow f^{\prime}(x)=e^{7x}+7xe^{7x} \\ and \\ \Rightarrow f^{\prime}^{\prime}(x)=7e^{7x}+7(e^{7x}+7xe^{7x}) \\ \Rightarrow f^{\prime}^{\prime}(x)=14e^{7x}+49xe^{7x} \end{gathered}[/tex]Then, find the interval such that f''(x)>0 in order to find where f(x) is concave up,
[tex]\begin{gathered} 14e^{7x}+49xe^{7x}>0 \\ \Rightarrow2e^{7x}+7x*e^{7x}>0 \\ and \\ e{}^{7x}>0,x\in\Re \end{gathered}[/tex]Then,
[tex]\begin{gathered} 2e^{7x}>-7xe^{7x} \\ \Rightarrow2>-7x \\ \Rightarrow x>-\frac{2}{7} \end{gathered}[/tex]Therefore, f(x) is concave up when x in (-2/7, +infinite).
In the case of concavity down,
[tex]\begin{gathered} f^{\prime}^{\prime}(x)<0 \\ \Rightarrow2e^{7x}+7x*e^{7x}<0 \\ \Rightarrow2+7x<0 \\ \Rightarrow-\frac{2}{7}>x \end{gathered}[/tex]Thus, f(x) is concave down when x in (-infinite, -2/7).
The answer is the fifth and last option (top to bottom).
An equilateral triangle is folded in half.IN60° 60°14 cm-4What is x, the height of the equilateral triangle?O 14V301407307
An equilateral triangle is a triangle that has the same length on all its three sides. Therefore, we can say that:
Since the triangle is folded in half, then we can say that:
From this, we can solve "x" using the Pythagorean Theorem.
[tex]c^2=a^{2^{}}+b^2[/tex]where "c" = hypotenuse and "a" and "b" can be either of the remaining sides.
[tex]\begin{gathered} 14^2=7^2+x^2 \\ 196=49+x^2 \\ 196-49=49+x^2-49 \\ 147=x^2 \\ \sqrt[]{147}=\sqrt[]{x^2} \\ 7\sqrt[]{3}=x \end{gathered}[/tex]Therefore, the height of our equilateral triangle is 7√3. This is found in the third option.
Victor took a survey of high school students to see how many had part-time jobs last summer. The results of the survey are shown in the table. Compare theprobability that a student in the sophomore class had a part-time job to the probability that a student in the junior class had a part-time job.
Answer:
A sophomore is less likely than a Junior to have a job.
Explanation:
Given the table in the attached image.
The total number of sophomores is
[tex]35[/tex]The number of sophomores with a job is;
[tex]12[/tex]The probability that a sophomore had a job is;
[tex]P_S=\frac{12}{35}[/tex]The total number of Juniors is
[tex]37[/tex]The number of Juniors with a job is;
[tex]27[/tex]The probability that a Junior had a job is;
[tex]P_J=\frac{27}{37}[/tex]From the derived Probability, we can observe that the probability that a Junior had a job is greater than the probability that a Sophomore had a job.
[tex]P_J>P_S[/tex]Therefore, A sophomore is less likely than a Junior to have a job.
Rational and Irrational Numbers make up the____ system.
We have the following:
Therefore, the answer is real numbers
Find each probability of the events and place them in order
Considering Box A,
Total number of pens = 3 + 5 = 8 pens
Probability of picking a purple (P) and black (B) pen is given below as,
[tex]\begin{gathered} P(P)=\frac{3}{8} \\ P(B)=\frac{5}{8} \end{gathered}[/tex]Considering Box B,
Total number of pens = 15 + 5 = 20 pens
Probability of picking a purple and black pen is given below as,
[tex]\begin{gathered} P(P)=\frac{15}{20} \\ P(B)=\frac{5}{20} \end{gathered}[/tex]For event 1, probability of choosing a red (R) pen from Box B is zero because there is no red pen in the Box.
Event 1 P(R) = 0
For event 2, probability of choosing a purple or black pen from Box A is,
[tex]P(P\text{ or B)=}\frac{3}{8}+\frac{5}{8}=\frac{3+5}{8}=\frac{8}{8}=1[/tex]Event 2 P(P or B) = 1
For event 3, probability of choosing a purple pen from Box A is,
[tex]P(P)=\frac{3}{8}[/tex]Event 3 (P) = 3/8
For event 4, probability of choosing a black pen from Box B is given below as,
[tex]P(B)=\frac{5}{20}=\frac{1}{4}[/tex]Event 4 P(B) = 1/4
Arranging each events from the least likely to the most likely is in the order below
[tex]\text{Event 1, Event 4, Event 3, Event 2}[/tex]Answer deduced above.
Type the correct answer in each box. Use numerals instead of words.The exterior of a solid cone is painted. The height of the cone is 11.4 centimeters, and the diameter of its opening is 5 centimeters.What is the surface area of the solid cone requiring paint to the nearest square centimeter?The surface area of the solid cone requiring paint rounded to the nearest whole number is square centimeters.
The surface area of a cone with diameter d and height h is given by:
[tex]A=\pi(\frac{d}{2})^2+\pi\cdot\frac{d}{2}\cdot\sqrt[]{h^2+(\frac{d}{2})^2}[/tex]For d = 5 cm and h = 11.4 cm, we have:
[tex]\begin{gathered} A=\pi(\frac{5}{2})^2+\pi\frac{5}{2}\sqrt[]{11.4^2+(\frac{5}{2})^2} \\ A=\frac{25}{2}\pi+\pi\frac{25}{2}\sqrt[]{129.96+\frac{25}{2}} \\ A=12.5\pi+12.5\cdot\pi\cdot\sqrt[]{142.46} \\ A\approx12.5\pi+12.5\cdot11.94\cdot\pi \\ A\approx508cm^2 \end{gathered}[/tex]Find the standard deviation for the following wroup of data Hems, Round your answer to the nearest tenth for one decimal place), 7,9,11,14,15,16
The standard deviation of the groups of data is 3.3 .
The standard deviation is calculated using the formula [tex]{\displaystyle \sigma={\sqrt {{\frac {1}{N}}\sum _{i=1}^{N}\left(x_{i}-{\mu }\right)^{2}}}}[/tex]
Where σ is the standard deviation.
x denotes the data of the population.
N is the size of the population.
μ is the mean of the population.
The given population is 7,9,11,14,15,16
Here N= 6
Mean (μ) = (7+9+11+14+15+16)÷6 = 72/6=12
Now we will put the values in the above equation to calculate the sd.
[tex]{\displaystyle \sigma={\sqrt {{\frac {1}{6}}\sum _{i=1}^{6}\left(x_{i}-{12 }\right)^{2}}}}[/tex]
Simplifying we get:
σ = √(64/6)
σ = 3.2659..
σ = 3.3
The standard deviation is a statistic that indicates the degree of volatility or dispersion in a set of numerical values.
A low standard deviation shows that possibly the values tend toward being close to the mean, sometimes referred to as the expected value of the set, whereas a large standard deviation suggests that the values are distributed over a wider range.
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Multiply. Write the result in standard form.(2 + 1)(3^4 + 7 + 2)
To multiply polynomials, we use the distributive law
[tex]\begin{gathered} (2x+1)(3x^4+7x+2)=(2x+1)(3x^4)+(2x+1)(7x)+(2x+1)(2) \\ =2x(3x^4)+1(3x^4)+2x(7x)+1(7x)+2x(2)+1(2)_{} \\ =6x^5+3x^4+14x^2+7x+4x+2 \end{gathered}[/tex]The last part follows by the laws of exponentials, finally we combine like terms
[tex]\begin{gathered} 6x^5+3x^4+14x^2+7x+4x+2=6x^5+3x^4+14x^2+(7+4)x+2 \\ =6x^5+3x^4+14x^2+11x+2 \end{gathered}[/tex]Maggie graphed a scatter plot of the numberof hours she drove, t, and the number of milesshe traveled, d. She then found a trend line ofher data to be d = 45.5t + 8. What is thepredicted distance Maggie will travel # shedrives for 4 hours?A 182 milesB 372 milesC 364 milesD 190 milesWhat’s the answer ?
WE have the following:
[tex]d=45.5t+8[/tex]When t = 4
[tex]undefined[/tex]A cylinder has a height of 10 ft and a volume of 25,456 ft^3.The radius of the cylinder is approximately ___ feet.Round your answer to the nearest whole number.
From the question given, they provided us with the height,h = 10ft, and volume, V=25,456 cubic feet.
Thus, we have:
[tex]\begin{gathered} V=\pi\times r^2\times h \\ 25,456=\pi\times r^2\times10 \\ \frac{25,456}{10\pi}=r^2 \\ \text{Taking the value of }\pi\text{ as 3.142, we have:} \\ r^2=\frac{25,456}{10\times3.142} \\ r^2=810.1846 \\ r=\sqrt[]{810.1846} \\ r=28.46ft \end{gathered}[/tex]Hence, the radius of the cylinder is 28.46ft
Multiply the following polynomials. Once simplified, name the resulting polynomial. (x + 2) (4x^2 - 3x - 2)name:
The resulting polynomial consists of four terms , it is called a quadrinomial.
CAN SOMEONE HELP WITH THIS QUESTION?✨
The given function's f(t) = (t - 4)(t + 1)(t - 7), f-intercept is f(t) = 28 and the t-intercepts are t = - 1, 4, 7.
What are intercepts?A y-intercept, also known as a vertical intercept, is the location where the graph of a function or relation intersects the y-axis of the coordinate system in analytic geometry using the widely used convention that the horizontal axis represents a variable x and the vertical axis represents a variable y. Therefore, x = 0 is satisfied at these sites. The x-intercept and y-intercept are the points where a line crosses each axis.
An intercept is a location where an axis and a graph intersect. The x-intercept is the name given to this particular one.
Put t = 0 in the function f(t) = (t - 4)(t + 1)(t - 7)
f(t)= (0-4)(0+1)(0-7)
f(t) = (-4)(1)(-7)
f(t) = 28
So, the f-intercept is (0,28)
Put f(t) = 0 to find t- intercepts
0 = (t-4)(t+1)(t-7)
So, t - 4 = 0
t = 4
For t + 1 = 0
t = -1
For (t - 7) = 0
t = 7
So, the t intercepts are t = -1, 4, 7.
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Express - 345 asin simplest form, where m and n are integers.Enter the correct answer in the box.-345 =
As -345 is an integer, the simplest fraction form is:
[tex]\frac{-345}{1}[/tex]or -345/1 (m=-345, n=1).
The graph of g consists of two straight lines and a semi circle. Evaluate each
Given:
a)
[tex]\int ^1_0g(x)dx[/tex]Consider the shape included in the region from 0 to 1 of g(x).
The area is,
[tex]\int ^1_0g(x)dx=\frac{1}{2}\times1\times4=2[/tex]b) From x = to x = 6 includes the semi-circle. Its area is calculated as,
[tex]\int ^6_2g(x)dx=-\frac{1}{2}(\pi\times r^2)=-\frac{1}{2}(\pi\times2^2)=-2\pi=-6.28[/tex]Mariah needs to randomly select one of three groups of students to make their presentation first. Which simulation tools could she use in thissituation?O a bag containing 12 chips in three different colors, with four of each coloro a six-sided number cubea full standard deck of cardsa spinner divided evenly into four sections, with each section a different colorO two coins
the correct answer is a bag containing 12 chips in three different colors, with four of each color (option A)
Explanation:
number of groups of student = 3
We need to select one out of the three.
The option that can be used to simulate this choice is having 12 chips in three different colours. Each colour will have 4 each.
The 3 different colours represent the 3 different groups. While each 4 number of a colour represent the number of students in each group.
Hence, the correct answer is a bag containing 12 chips in three different colors, with four of each color (option A)
find the area of the circle with a diameter of 8.6 ft
Given:
Diameter of the circle, d = 8.6 ft
To find the area of a circle, use the formula below:
[tex]undefined[/tex]Diameter of the circle, d
r-9<-25. on a graph bar
r-9<-25 is equal to solution: [tex]$\quad R < -16$[/tex], Interval Notation: [tex]$\quad(-\infty,-16)$[/tex]. The graph is shown in attachement.
R-9<-25
Add 9 to both sides
R-9+9<-25+9
Simplify
R<-16
A graph is simply an orderly representation of data. It aids us in comprehending the info. The numerical information gathered through observation is referred to as data.
Data is derived from the Latin term Datum, which meaning "anything supplied."
Data is collected continuously through observation when a research question is formulated. It is then organized, summarized, categorised, and graphically shown.
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6(__+x)-8(-3+8x) = 30-58xfill in the blank
In this expression, we have the same value on the left side is equal to the same amount on the right side.
So, let's start operating it to simplify it
6(_+x) -8(-3+8x)=30-58x
6(_+x)+24-64x=30-58x
6( ) +6x +24 -64x =30 -58x
6( ) -58x+24=30-58x
6( )-58x +58x=30-24
6( ) =14 DIviding both sides by six
( ) =7/3
Testing:
6(7/3 +x) -8(-3+8x)=30-58x
14+6x +24 -64x =30-58x
38
Select all of the constraints that apply to this situation $1.25x when x <12$12.00 + $0.75(x-12) when X_>12$1.25x when x _>120.75x when x >12$12.00 + $0.75x when x >12
We want to write expressions that describe the cost of the cookies. Let say we sell x cookies. If x is less than 12, then the cost per cookie is 1.25. So the cost of x cookies would be the product of this numbers, so it would be
[tex]1.25x,x<12[/tex]Note that when x=12 the cost should be 12. Also note that for each extra cookie, starting at 12, each cookie costs 0.75. If we buy x cookies , to calculate the extra cookies, with respect to 12, we simply substract 12 from x and we multiply it by 0.75. This would be
[tex]0.75\cdot(x\text{ -12)}[/tex]as this is an additional cost to the 12, we add 12 to this expression. THen we get
[tex]12+0.75\cdot(x\text{ -12)}[/tex]Note that for this expression, when x=12, we get that the expression becomes
[tex]12+0.75\cdot(12\text{ -12)=12}[/tex]THis means that the expression applies from 12 and on, so we have the followin inequality12
[tex]12+0.75\cdot(x\text{ -12), x}\ge12[/tex]