which electromagnetic radiation wavelength is efficiently observed using ground based telescopes?

Because the coulomb force has a wider field of influence and heavier atoms have more neutrons than protons.

Strong nuclear force :

The strong nuclear force is represented by the force that holds protons and neutrons in atoms' nuclei. the things that are heavier than an atom of hydrogen. the center of the fusion of hydrogen and helium in the sun. The strong interaction, commonly referred to as the strong nuclear force, constrains quarks into proton, neutron, and other hadron particles. Neutrons and protons are held together to form atomic nuclei by the nuclear force, often known as the strong interaction. Heavier atoms have more neutrons than protons because the Coulomb force's range is larger. Protons and neutrons are joined together to form atomic nuclei by the nuclear force, also referred to as the strong interaction.

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If a volume of air is warmed, it expands and tends to: cool.

The air expands and takes up more area when heated. The same object gets lighter as it takes up more room. There is warm air As a result, warm air is lighter than cold air. The smoke rises as a result of that.

Air expands as it rises because air pressure decreases as altitude increases. The air cools as a result of this expansion.

The molecules are separating as they heat up and travel more quickly. As a result, air expands when heated and shrinks when it is cooled, like most other things. The air is less dense than the surrounding material because there is more space between the molecules, which causes the heated air to float higher.

Thus, if a volume of air is warmed, it expands and tends to: cool.

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The water that is displaced produces buoyancy, an upward force. As opposed to gravity, which would pull the ship downward, buoyancy acts in the opposite manner.

When the mass of water that the submarine displaces (pushes out of the way) equals the mass of the boat, the submarine (or any boat) can float. The deeper surface is under more pressure. The important thing to keep in mind is that regardless of the depth of the submerged submarine is at, the pressure differential between higher and lower surfaces is always the same since water is incompressible (for all practical purposes here). You mentioned a push, and that contributes to the net buoyancy. To overcome its buoyancy, the submarine must allow water into its ballast chambers. The submarine will need to make modifications while below, adding or "blowing" ballast water to make up for changes in the water's density brought on by temperature or salinity changes, in order to maintain constant depth.

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If the altitude of the North Star is 30º above the horizon, then the highest altitude that the Sun will reach during the Autumnal Equinox: is 60 degrees

The sun shines squarely on the equator at the autumnal equinox, giving both the northern and southern hemispheres an equal quantity of sunlight.

The start of the fall season is signaled by the autumnal equinox, a natural occurrence that takes place in late September every year. The celestial equator coincides with the equator of Earth, such that day and night are of equal length.

It would be 30 degrees north latitude if you could see Polaris at 30 degrees above the horizon. Now, if a star reaches its highest point at a place below the observer's zenith, its latitude is equal to 90 - star altitude.

90 - 30 = 60 degrees

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Binding energy per nucleon of carbon 12 is 7.94 MeV

Carbon 12 contains 6 proton , 6 neutron  and 6 electron hence, calculated atomic mass of carbon 12

= 6Mp+6Mn +6Me

=6 × 1.007 + 6 ×1.008 + 6× 0.00055

=12.102

∴ mass defect = 12.102 -12.000 = 0.102 amu

binding energy = 0.102 ×931 = 95.30 MeV

binding energy per nucleon = 95.30\12 = 7.94 MeV

What is the binding energy for each nucleon?

The least amount of energy necessary to separate or break down an atom’s nucleus into the subatomic particles that make it up is known as nuclear binding energy (which are protons and neutrons)

How is nuclear binding energy determined?

The nuclear binding energy can be determined once the mass defect is known by converting that mass to energy using the formula. E b = ( Δ m ) c 2. ...

Verify that the mass is expressed in kilogram's (kg).

Once the obtained energy is known, it can be scaled into amounts per nucleon and per mole.

What does it signify when a nucleon's binding energy is high?

Binding energy is required to keep nucleons together as a nucleus. One of the most stable elements is iron, which has a mass number of 56. We refer to iron as having a high nucleon-binding energy. Less stable elements are those with a lower and higher mass number per nucleon.

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a) Both spheres have the same speed and both reach at the same time.

b)  Both spheres will have the same speed at the bottom of the incline.

a) consider the energy conservation and calculate the speed of each sphere

0 + mgH = 1/2mv² + 1/2 Iw² + mgy

Here,

m is mass

g is gravity

H is height

v is velocity

I is inertia

w is the angular velocity

Now potential energy will be zero at the base of the incline (y=0) and there are initial height H then take position 1 to be the top and position 2 to be the generic location.

mg(H-y) = 1/2(mv² + 2/5mr² v²/r²)

v= √(10/7 g (H-y))

So according to the solution, it is clear that velocity is not depending upon the mass or radius of the sphere. Hence both have the same speed and both reach at the same time.

b) According to the result obtained in part (a), both have the same speed at each point along the incline so both will have the same speed at the bottom of the incline.

According to the conservation of energy total kinetic energy will be bottom of the incline is equal to the potential energy at the incline. There are initial potential energy is proportional to the mass sphere so massive spheres have greater kinetic energy.

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The force applied to pull on one another is 102.48 N.

Mass of skaters = m = 55 Kg

Length of arms = r = 0.76 m

Time period = 4 s

Force applied to pull one another is = F =

= F = centripetal force

= F = (m X v²) / r

The centripetal force exerts on a body at the time of circular path, which acts towards the centre of a circular path, and It is inverse of radius as more radius has the least centripetal force.

First, the velocity of the skaters is = v =

= v = distance / time

= v = ( 2 X π X r ) / t

= v = ( 2 X π X 0.76 ) / 4

= v = 1.19 m/s

Now,

Force applied to pull one another is = F =

= F = centripetal force

= F = (m X v²) / r

= F = ( 55 X 1.19²) / 0.76

= F = 102.48 N

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Answer:

C. -6.1 m/s2

Explanation:

a = (vf - vi) / t = (15 m/s - 29 m/s) / 2.3 s = -6.1 m/s2

You are decelerating (slowing down);  value is negative

Simply said, radio is a wavelength of electromagnetic radiation that is well suited for ground-based telescope observation.

The distance between any two identical locations on adjacent waves may always be used to calculate the wavelength. When dealing with a longitudinal wave, the distance between one compression and the next or between one rarefaction and the next is used to calculate the wavelength.

The distance between two identical points (adjacent crests) in consecutive cycles of a waveform signal's journey through space or over a wire is known as the wavelength. Wireless systems frequently use meters (m), centimeters (cm), or millimeters (mm) to represent this length (mm).

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The energy was transformed into internal energy by means of air friction is equal to 1.2789 × 10⁹J.

According to the law of conservation of energy, energy can be transformed from one to another but it is not possible to create or destroy it. Energy happens in nature in various forms such as heat, chemical energy, electricity, nuclear energy, and so on.

The sum of the potential energy and kinetic energy before and after are equal.

PE₁ + KE₁ = PE₂ + KE₂ + Qₙ

where Qₙ is the heat energy.

The kinetic energy at the initial stage is zero.

PE₁ = PE₂ + KE₂ + Qₙ

[tex]\displaystyle -(\fracGMm}{R+h} ) =-(\frac{GMm}{R} ) +\frac{1}{2}mv^2 +Q_f[/tex]

[tex]\displaystyle Q_f = (\frac{GMm}{R} ) - (\frac{GMm}{R+h} ) -\frac{1}{2}mv^2[/tex]

[tex]\displaystyle Q_f = {6.67\times 10^{-11}\times 5.98\times 10^{24}\times 550}[(\frac{1}{6.371 \times 10^6} ) - (\frac{1}{6.371 \times 10^6 +400\times 10^3} )] -\frac{1}{2}(550)(2200)^2[/tex]

Heat energy = 1.2789 × 10⁹J

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The energy from the light is captured and stored by the surface without being reflected or transmitted then it has been absorbed.

Bouncing back of light into the same medium is known as reflection of light

As per law of reflection we know that light incident on the surface at a given angle with respect to the normal then the angle of reflected light with the normal will be same

= angle of incidence of light = angle of reflection of light

Also we know that incident light, reflected light and normal always lie in the same plane. However in this case, the light is trapped which gives it a room to get absorbed.

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Since the closest approach distance is 39.5 fermi, the initial speed is in a head-on collisions between an alpha particle and a gold nucleus (Z=79) is 10.5 MeV.

Alpha particles are alternatively known as Alpha radiation or Alpha rays.

In physics, alpha is a variable that is used for numbers that could be different from one another.

Rf - beta - Rf = alpha (Rm-Rf)

R is a symbol for portfolio return.

The risk-free return rate is denoted by Rf.

The systematic risk of the a portfolio is represented by beta.

According to a benchmark, Rm stands for the market return.

Therefore the alpha particle must have an initial speed of 10.6 MeV  to just touch the surface of a gold nucleus before being turned back.

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The mass of the asteroid is 4×10^13 kg.

The amount of time it takes an astronomical object to complete one orbit around another object is known as the orbital period.

Given that orbital period: T = 3.02 hour

= 3.02*3600 second

= 10872 second.

Radius of orbit = 2.0 km = 2.0*1000 m.

Let the mass be M.

Again we know that: the relation among time period and radius of orbit is given by:

T² = 4π²R³/GM

M =  4π²R³/GT²

= { 4π²(2.0*1000)³/(6.67× 10^-11 × 10872²)}

= 4×10^13 kg.

Hence, the mass of  is  4×10^13 kg.

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The wavelength of the monochromatic ligh beam in this case was found to be  497nm

what is monochromatic light ?

Monochromatic lights are single-wavelength lights, with mono denoting single and chroma denoting colour. Monochromatic lights are visible light with a small band of wavelengths. It has a wavelength in the short wavelength region. These lights are characterised by their intensity or brightness, colour, propagation direction, and polarisation condition.

Monochromatic Light's Source and Applications

The LASER is a well-known source of monochromatic light. The acronym LASER stands for Light Amplification By Stimulated Emission Of Radiation. A laser light is produced by a single atomic transition with a single wavelength, resulting in a monochromatic light beam.

work function = 2.50 eV 

V0 = 1.00 eV (the stopping potential.)

Electron charge, e = 1.6 x 10^-19 C

Light speed, c = 3 x 10^8 m/s

h = 6.63 10^-34 Js = 4.14 10^-15 eVs (Planck's constant.

The photoelectric equation of Einstein is provided by:

= E - ϕ ——- (1) represents the greatest kinetic energy.

E is the absorbed photons' energy: E = hf

is the surface's work function: ϕ = hf₀

The potential difference necessary to return all expelled electrons is known as the Stopping Potential (V0).

——-

(2) is substituted for (1)

  eV₀ = E - ϕ

1.6 x 10⁻¹⁹ x 1 = E - 2.50

E = 1.6 x 10⁻¹⁹ + 2.50

E = 2.50 eV

E = hf = hc/λ

 λ = (4.14 × 10⁻¹⁵ × 3 x 10⁸) / 2.50

λ = 1240 × 10⁻⁹ / 2.50

λ = 496.8 × 10⁻⁹ m

λ = 497 × 10⁻⁹ m  

 λ = 497 nm

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The rate of change of the distance between the car and the person at that instant is 12m/sec.

We have given that a person is standing 10 meters east from junction or intersection point. Now, we have given that rate of change of car from north direction as 13m/sec.

So, let assume distance of intersection point from the final point is y meters and distance of a person from final point as x meters,

Therefore, using pythagoras theorem,we get

=>y² = x² +(10)²

=>y=√(x²+100)

Now we are given rate of change of x in form of dx/dt,so on differentiating we get

=>dy/ dt = [(1/2) × (1/√(x²+100))] × (2 × x × dx/dt)

=>dy / dt =( x /√(x²+100)) × dx/ dt

Now, we are given value of dx/dt= -13m/sec. Since, distance is decreasing with time therefore dx/dt = -13m/sec.

Now, putting value of dx/dt and x=24meters,we get

=>dy /dt = (24 / √[(24)²+100]) × (-13)

=>dy /dt = (24 / √(576+100)) × (-13)

=>dy /dt = (24/26)×(-13)

=>dy/dt = -24/2

=>dy/dt = -12m/sec

Hence, rate of change of the distance is 12m/sec.

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Using the Second Law of Newton concept, the force F done by the person is 27N and it takes 1.125m for the mover before stopping.

From the case, we know that:

Fnet = 51N

m = 24kg

f = 24N

v = 1.5m/s --> after F is removed

From the system, we know that F net is the net external force working on the system, where:

Fnet = F - f

51 = F - 24N

F = 27N

When the force F is removed, the mower is still moving with speed of 1.5m/s. It will come to stop because of the friction force working on the system. Hence, based on the Second Law of Newton, we know that:

∑F = m.a

- f = m.a

-24 = 24.a

a = -1m/s²

Next we will use velocity and acceleration formula to find the distance needed for the mower to stop.

v² = u² + 2as

where:

v = initial velocity

u = final velocity

a = acceleration

s = distance

We will use the provided information above:

(1.5)² = (0)² + 2(-1)s

2.25 = 0 - 2s

s = 1.125m

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Complete Question:

In Figure 4.7, the net external force on the 24-kg mower is stated to be 51N. If the force of friction opposing the motion is 24N, what force F (in newton) is the person exerting on the mower? Suppose the mower is moving at 1.5m/s when the force F is removed. How far will the mower go before stopping?

Picture attached bellow

a) I₀ = 90.71 μA

b) Prad = 0.25mW

a) To find the current that must be fed to the antenna,

λ = c/f

λ = 3 X 10 ⁸/ 100 X 10 ⁶

λ = 3 m

Emax = ηπI₀S/ r λ²

I₀ = Emax r λ²/ ηπS

I₀ = 50 X 10 ⁻³X 3 X3²/ 120 η (0.2) ² X 100

I₀ = 90.71μA

b) The average power radiated by antenna,

Rrad = 320π⁴S/ λ⁴

         = 60.77 KΩ

Prad = 1/2 I₀Rrad

Prad = 0.25mW

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The rest mass of the electron is 8.199 x 10⁻¹⁴ Joules or 0.511 MeV.

The relativistic kinetic energy equation demonstrates how an object's energy increases as its velocity approaches the speed of light. In order to accelerate an object across this boundary is therefore impossible. The mass-energy equivalence formula is Erest=E0=mc2, which is derived from calculations of kinetic energy.

Relativistic kinetic Energy:

The relativistic energy of a particle with mass m, can be found using the following equation

Krel= (γ-1) mc²

It is given that the mass of the electrons is 9.11 x 10⁻³¹kg, thus we have

m =  9.11 x 10⁻³¹kg

it is required to find the rest mass of the electron,

mc² = ?

Knowing the mass of the electron, we can find the rest mass of the electron,

as follows

mc² = 9.11 × 10⁻³¹ × (3 × 10⁸) ²

mc² = 8.199 x 10⁻¹⁴Joules

And, to convert from energy units of joule to eV, we divide by the electron charge, thus we have = 8.199 x 10⁻⁴/1.6 x 10⁻¹⁹= 511741.376 eV

511741.376 eV ≈ 0.511 MeV

Thus, the rest mass of the electron is 8.199 x 10⁻¹⁴ Joules or 0.511 MeV.

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The value of m, which is a mass at the end of a spring that oscillates with a frequency of 0.83Hz, that been added with 680g to the mass with frequency 0.60Hz is 0.74 kg.

It is a repetitive or periodic variation, typically in time, of some measure about a central value or between two or more different states. As an example, swinging pendulum and alternating current are represents oscillation.

let's use the relation between frequency and mass.

f = 1 / 2π * √k/m

where f = frequency

m = mass

k = spring constant

(2πf)^2 = (√k/m)^2

(4 * π^2 * f^2) * m = (k/m) * m

divided both side with 4 * π^2

m * f^2 = k / 4 * π^2

because k / 4 * π^2 is constant, we will leave that out from the equation

Now, let's try to answer the value of m

m * f1 ^2 = m * f2^2

m * 0.83^2 = (m + 0.68) * 0.6^2

0.6889m = 0.36m + 0.2448

0.3289m = 0.2448

m = 0.74kg

Therefore, the mass m at the end of a spring that oscillates with a frequency of 0.83Hz is 0.74kg.

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The energy system utilized during high intensity sprint is glycogen stored in muscles.

Sprinting burns a ton of calories, improves cardiovascular fitness, develops muscle, and increases speed and power. To step up your training, incorporate them into your program.

Additionally, sprint exercises save a lot of time. Even though up to 60 minutes of moderate exercise should be performed three times each week, most people don't get that much exercise for a variety of reasons, including a lack of time.

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The angular acceleration when the pencil is 10° from the vertical is 17 rad/s². The time for the pencil to hit the ground is 0.43 s.

Look at the attachment for the complete question. The weight of the pencil is in the middle of it. When the pencil has an angle of 10.0° from the vertical

When the pencil hit the ground

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The induced current on the ring will be counter-clockwise (left-hand-rule).

Fleming's left-hand rule for electric motors is one among a pair of visual mnemonics, the opposite being Fleming's proper-hand rule (for generators). They had been originated with the aid of John Ambrose Fleming, within the overdue nineteenth century, as a simple way of working out the direction of motion in an electric powered motor, or the route of electric modern in an electric generator.

While modern-day flows through a conducting twine, and an outside magnetic discipline is carried out across that float, the accomplishing twine experiences a pressure perpendicular each to that area and to the path of the current drift (i.e they're jointly perpendicular). A left hand can be held, as proven in the illustration, so one can represent 3 jointly orthogonal axes at the thumb, fore finger and center finger. each finger is then assigned to a quantity (mechanical force, magnetic field and electric powered present day). The right and left hand are used for turbines and automobiles respectively.

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Trigonal, 120 degree, the ideal bond angles are 120° when there are three electron domains encircling an atom.

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More current will flow through the battery when the same three resistors are connected in parallel.

Equivalent resistance when the three equal resistors are connected in parallel is R eq = R/3

We know that, according to ohm's law, V = i * R eq

where, V is the voltage

i is the current

R eq is the equivalent resistance

We know that, voltage is same across the circuit of three resistors connected in parallel.

Now, substituting R eq in the above equation, we have

i = V/ R eq = V/ (R/3) = 3* V/R

Thus, more current flows through the same three resistors which are connected in parallel.

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The apparent weight of the person as the cart passes over the top of the fill for question A is 470N.
The maximum speed that the cart may travel at the top of the hill without losing contact with the surface from question B is 19.8 m/s.

Based from the question above, we will approach using centripetal force to answer question A, and centripetal acceleration to answer question B.

It is a force that makes a body follow a curved path. Its direction is always orthogonal to the motion of the body and towards the fixed point of the instantaneous center of curvature of the path.

Now, let's calculate question A about the apparent weight of the person as the cart passes over the top of the hill.

Given from the question

mass of the person = 70kg

weight of the person will be = mass * earth gravity

= 70 * 9.8

= 686N

Radius of the circle of which the arc is a part = r = 40m

speed of the cart = 12 m/s

The centripetal force on the person =

Fc = mass * ((cart speed (v))^2 / radius of the circle (r))

= 75 * (12^2/50)

= 216N

from here, apparent weight can be calculate below :

R (apparent weight) = weight - centripetal force (Fc)

= 686 - 216

= 470N

Therefore, the answer of question A, the apparent weight of the person as the cart passes over the top of the hill is 470N

Now, moving on to question B. The person can have a maximum speed when the centripetal acceleration is equal to the acceleration due to gravity.

Vmax = √r (radius) * g (gravity)

= √40 * 9.8

= √392

= 19.8 m/s (rounded)

Therefore, the maximum speed of the cart at the top of the hill without losing contact with the surface is 19.8m/s. This answer also depends on the radius of the circular path and velocity of the cart.

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When we are aware of all the forces operating on an object and its mass, we can use those two pieces of knowledge to calculate the object's acceleration.

Newton's first law of motion and the second law of motion are closely related. The causal relationship between force and modifications in motion is expressed mathematically.

More quantitative, and frequently used to determine what happens when a force is applied, is Newton's second law of motion. We need to clarify a few concepts before we can write out Newton's second law as a straightforward equation expressing the precise relationship between force, mass, and acceleration.

a = Fnet / m

That is

Fnet = m • a

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A series circuit is a closed circuit in which the current follows one path. Current path is a path by which the electrical current flows. Magnitude load is P is for a force acting on a position, along a line, or across an area. M is for bending moments acting on a position or along a line.

The fact that the same current flows through every component in a series circuit is what distinguishes it from other types of circuits. The current can only move in one direction.

Every component in a series receives the same amount of current. The sum of all resistances constitutes the total resistance. The total applied voltage is equal to the sum of all voltage drops.

A series circuit's overall current equals the current flowing through any resistance in the circuit. Through every circuit resistor, the overall circuit current would stay constant.

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The frequency of a sound wave is  17000Hertz if its speed is 340m/sec and wavelength is 20cm

For sound wave ,we know an expression

c=ν × λ

where c is the defined as the speed of wave  in any medium,

ν is  defined as the frequency of the wave and

λ is defined as the  wavelength of the wave.

Frequency is the quantity of events of a rehashing occasion for every unit of time. It is likewise sometimes alluded to as worldly recurrence for lucidity, and is unmistakable from rakish recurrence. Frequency is estimated in Hertz (Hz) which is equivalent to one occasion each second. The period is the time frame between occasions, so the period is the corresponding of the frequency.

Now,340m/sec=v×20cm

=>340m/sec=v×0.20m

=>v=340/0.20

=>v=34000/20

=>v=17000/sec

or v=17000Hertz

Hence, frequency is 17000Hertz.

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No, if the angular velocity is constant, the combined acceleration of the mass and rod cannot be zero. Because two masses are connected by a massless rod that revolves around its Centre on a fixed axis.

In one-dimensional motion, constant speed is related with zero acceleration, however in two- and three-dimensional kinematics, things are a little different since, for example, a system particle rotating at constant speed does experience acceleration (not angular acceleration though). Due to the constant magnitude velocity vector that is always tangential and perpendicular to the position vector in the direction of the centripetal force, the total acceleration of the mass/rod cannot be zero if the angular velocity is constant.

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a) Acceleration is zero  

b) Speed ​​is zero

a) The equation of the simple harmonic motion is

x = A cos (wt +φ)

where

A = amplitude of the movement,

w= angular velocity and

φ = phase

Body acceleration is

a = d²x / dt²

dx / dt = - A w sin (wt + φ)

a = d²x / dt² = - A w² cos (wt + φ)

when it is not stretched x = 0

The spring is released at maximum elongation, φ = 0

0 = A cos wt

Cos wt = 0        

wt = π / 2

a = -A w² cos π/2 = 0

Acceleration is zero

c) When the spring is compressed x = A

Speed ​(v) = dx / dt

v = - A w sin wt

A = A cos wt

cos wt = 1        

wt = 0, π

v = -A w sin 0 = 0

Speed ​​is zero

Complete question:

A mass is connected to a spring and is allowed to move horizontally. The mass is at a position L when the spring is unstretched. The mass is then moved, stretching the spring, and released from rest. It then moves with simple harmonic motion. (a) At the instant that the mass passes through the position where the spring is unstretched, what can be said about its instantaneous acceleration? Grade Summary It is maximum. OIt is zero It is non-zero but not maximum Potential per attempt) Hint I give up 1% -ム33%Part (b) At the instant that the spring is compressed the most, what can be said about the magnitude of its instantaneous velocity?

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