To answer this question, we need to solve this inequality for y as follows:
[tex]2x-3y\ge12[/tex]Then, we have:
[tex]-3y\ge12-2x\Rightarrow\frac{-3y}{-3}\leq\frac{12}{-3}-\frac{2x}{-3}\Rightarrow y\leq-4+\frac{2x}{3}[/tex]As we can see the direction of the inequality changed because we multiplied it by a negative number.
Then, if we can see the inequality, we find that the values that make this inequality true
are infinite values (the values of y are in function of the values of x).
Then, since we have the values given in the options, we need to check which of these values make the inequality true or we can graph a line for this inequality.
We have that the line is given by:
y = 2x/3 - 4
The x-intercept for this line is:
[tex]undefined[/tex]which of the following expressions is equal to 5^6/5^2?
Simplify the expression 5^6/5^2.
[tex]\begin{gathered} \frac{5^6}{5^2}=5^6\cdot5^{-2} \\ =5^{6-2} \\ =5^4 \\ =5\cdot5\cdot5\cdot5 \\ =625 \end{gathered}[/tex]Thr sum of 2 numbers is 97.The greater number is three less then four times the lesser number.Find the numbers
need answer soon PLEASE!!!!
Answer:
Greater number: 77 Lesser number: 20
Step-by-step explanation:
Sooo
20 × 4 is 80
80 - 3 = 77
77 + 20 = 97
Answer:
77 & 20
Step-by-step explanation:
x+y=97
x=4y-3
4y-3+y=97
5y=97+3
5y=100
5 5
y=20
x=4y-3
x=4(20)-3
x=80-3
x=77
don't forget to follow , rate & like
For the following situation, (a) write an equation in the form y=mx+b, (b) find and interpret the ordered pair associated with the equation for x=5, and (c) answer the question.A health club membership costs $80, plus $48 per month. Let x represent the number of months and y represent the cost in dollars. How much does the first year’s membership cost?
Based on the question, a health club membership costs $80, plus $48 per month. This can be written as $80 + $48 per month = health membership cost.
If x = month and y = cost, then we can rewrite the equation as:
[tex]\begin{gathered} 80+48x=y \\ or \\ y=48x+80 \end{gathered}[/tex]a. This is our equation in the form of y = mx + b. (y = 48x + 80).
b. If the number of months is 5 or x = 5, we can solve for the total cost of membership by replacing "x" with "5" in the equation.
[tex]\begin{gathered} y=48x+80 \\ y=48(5)+80 \\ y=240+80 \\ y=320 \end{gathered}[/tex]The ordered pair is (5, 320).
This ordered pair indicates that the cost for 5-month membership is $320.
c. Since there are 12 months in 1 year, replace "x" in the equation with 12 and then, solve.
[tex]\begin{gathered} y=48x+80 \\ y=48(12)+80 \\ y=576+80 \\ y=656 \end{gathered}[/tex]Therefore, the first year's membership cost is $656.
Solve for k in 2 - (k+4) = 3a.) What is the variable?b.) What is happing to the variable? (list the operations from the first thing to the last thing)c.) What is the inverse (opposite) of the last thing that happened to the variable. (Make a list of the steps to solve)
We have the equation 2-(k+4)=3.
The variable is k, because is the only unknown number. Solving for k:
[tex]\begin{gathered} 2-(k+4)=3 \\ 2=3+(k+4)=3+4+k=7+k \\ 2-7=k \\ -5=k \end{gathered}[/tex]The variable has the following operations:
• Add 4
,• Multiply by (-1)
,• Add 2
The inverse of the last thing is Subtract 2, subtract is the opposite of add.
state the equation of the axis of symmetry of the function f(x) = 3x^2 + 6x - 2
The given function is:
[tex]f(x)=3x^2+6x-2[/tex]Complete the square and factor as follows:
[tex]\begin{gathered} f(x)=3(x^2+2x+1)-2-3 \\ f(x)=3(x+1)^2-5_{} \end{gathered}[/tex]Compare with:
[tex]f(x)=a(x-h)^2+k[/tex]To get:
[tex](h,k)=(-1,-5)[/tex]Since the parabola is vertical the axis of symmtery is vertical which is x=-1.
Write a piecewise function describing your weekly pay P, in terms of the number of hours worked, h.
SOLUTION
the wage for less that 40 hours of work is
[tex]12h[/tex]The wage for more than 40 hours is:
[tex]1.5\times12=18h[/tex]Therefore the piecewise function is
[tex]\begin{cases}12h{,0\lt h\le40} \\ 18h{,h\gt40}\end{cases}[/tex]
amir drove from Jerusalém to the lowest on place on Earth , the dead Sea His altitude relative to sea level as a function of time is graphed what was amir's altitude at the begining of the drive?
Explanation
Step 1
define
Type the correct answer in each box. Use numerals instead of words In the figure, lines BD and QS are parallel
..Given: Two parallel lines BD and QS and a transversal AT
To Determine: The measure of CRQ and CRS
Solution
From the image given, angle DCR and CRQ are alternate angles
Also angle DCR and angle CRS are each pair of the same interior angles
Please note that alternates angles are equal and each pair of same-side interior angles are supplementary
Apply the theorem above
[tex]\begin{gathered} \angle CRQ=\angle DCR(alternate-angles) \\ \angle CRQ=77^0 \end{gathered}[/tex]Also
[tex]\begin{gathered} \angle DCR+\angle CRS=180^0(same-ineterior-angles) \\ 77^0+\angle CRS=180^0 \\ \angle CRS=180^0-77^0 \\ \angle CRS=103^0 \end{gathered}[/tex]Hence:
∠CRQ = 77⁰
∠CRS = 103⁰
WCompare Function ValuesGiven the functions f(2) = 2:24 and g(x) = 11 - 2", which of the followingstatements is true?O f(3) > g(3)O f(3) < 9(3)Submit AnswerO f(3) = g(3)
Notice that
[tex]\begin{gathered} f(3)=2\cdot(3)^4=162 \\ g(3)=11\cdot2^3=88 \end{gathered}[/tex]Notice that
[tex]\begin{gathered} f(6)=6^2=36 \\ g(6)=2^6=64 \\ \end{gathered}[/tex]Then, f(6) < g(6)
PLS HELP DUE TODAY!Find the mean, median, mode, and range of each set of data round answers to the nearest hundredth 0,3,2,1,7,4,3,2,1,1,1,0,2,3,0,2,6,2Second question:Find the mean, median, mode, and range of each set of data round answers to the nearest hundredth 3,2,2,1,0,0,5,3,1,0,1,0,2,6,3,2,3
To answer this question, we (first) need to order the data from the least to the greatest element of this set:
[tex]l=\mleft\lbrace0,3,2,1,7,4,3,2,1,1,1,0,2,3,0,2,6,2\mright\rbrace[/tex]If we order in that mentioned way, we have (this is done, mostly to find the median):
[tex]l=\mleft\lbrace0,0,0,1,1,1,1,2,2,2,2,2,3,3,3,4,6,7\mright\rbrace[/tex]MedianTo find the median of this data, we need to find the value for which 50% of the data are below this value, and above this value - it is a central value. We have 18 elements:
0,0,0,1,1,1,1,2,2,2,2,2,3,3,3,4,6,7
Since we have an even number of elements, we need to find the "average" of both central numbers:
[tex]Median=\frac{2+2}{2}\Rightarrow Median=2[/tex]Therefore, the median is equal to 2.
ModeThe mode is the element that is more founded into the set of numbers. In this case, if we look carefully at the data, we have that this value is 2 because we have 5 cases in which 2 appears in that set of data.
MeanTo find the mean, we need to sum each of the elements in the set of data, and then divide that result by the number of data - in this case, we have 18 elements. Then, we have:
[tex]Mean=\frac{(0+0+_{}0+1+1+1+1+2+2+2+2+2+3+3+3+4+6+7)}{18}[/tex][tex]\text{Mean}=\frac{40}{18}\Rightarrow Mean=2.22222222222\ldots[/tex]If we round the mean to the nearest hundredth, we have that the mean = 2.22.
RangeThe range is the difference between the maximum value and minimum value of the set of data, and we have:
Minimum = 0
Maximum = 7
Therefore, the range is equal to R = (7 - 0) ---> Range = 7.
In summary, for this set of data, we have that:
• Mean = 2.22 (rounded to the nearest hundredth)
,• Median = 2 (2.00 rounded to the nearest hundredth)
,• Mode = 2 (2.00 rounded to the nearest hundredth)
,• Range = 7 (7.00 rounded to the nearest hundredth)
hi I'm having trouble on solving systems and graphing them
The system of equations is
0 = 2y + 6 - x (1)
0 = 4y + 3x - 8 (2)
To solve it graphically we must find 2 points on each line
So let us choose values of x and find their corresponding values of y
Let x = 2
Substitute it in equation (1)
0 = 2y + 6 - (2)
Add the like terms on the right side
0 = 2y + (6 - 2)
0 = 2y + 4
Subtract 4 from both sides
0 - 4 = 2y + 4 - 4
-4 = 2y
Divide both sides by 2
-2 = y
The 1st point is (2, -2)
Let x = 4
Substitute it in the equation to find y
0 = 2y + 6 - (4)
0 = 2y + (6 - 4)
0 = 2y + 2
Subtract both sides by 2
0 - 2 = 2y + 2 - 2
-2 = 2y
Divide both sides by 2 to find y
-1 = y
The 2nd point is (4, -1)
Now you can plot these to points and join them to draw the 1st line
We will do the same with equation (2)
Let x = 4
Substitute it in the equation (2)
0 = 4y + 3(4) - 8
0 = 4y + 12 - 8
Add the like terms in the right side
0 = 4y + (12 - 8)
0 = 4y + 4
Subtract 4 from both sides
0 - 4 = 4y + 4 - 4
-4 = 4y
Divide both sides by 4
-1 = y
The 1st point on the second line is (4, -1)
Let x = -4
0 = 4y + 3(-4) - 8
0 = 4y -12 - 8
0 = 4y + (-12 - 8)
0 = 4y - 20
Add 20 to both sides
0 + 20 = 4y - 20 + 20
20 = 4y
Divide both sides by 4
5 = y
The 2nd point on the second line is (-4, 5)
Plot the two points and join them to form the second line
As you see the two lines have point (4, -1),
then the two lines will intersect at this point
The solution of the system is (4, -1)
You stand 40 feet from a tree. The anlge of elevation from the ground tothe top of the tree is 47 degrees. How tall is the tree? (round to the nearesttenth)0 42.9 feet0 27.3 feet29.3 feetO 40 feet
The first step is to draw the picture.
We want to find the opposite side.
We know the adjacent side
The trig function with opposite and adjacent is tangent
tan 47 = opp / adjacent
tan 47 = opp/40
40 * tan 47 = opp side
42.8947484 = opp side
Rounding to the nearest tenth
42.9 ft
Can you help me with this assignment
The question provides one endpoint and then the midpoint. The midpoint on the coordinate grid is (0, -7) and one endpoint is (-2,-6).
The formula for calculting the midpoint is given as follows;
[tex]\begin{gathered} M=\frac{x1+x2}{2},\frac{y1+y2}{2} \\ Take\text{ the x coordinates and y coordinates one after the other,} \\ 0,7=\frac{-2+x2}{2},\frac{-6+y2}{2} \\ \text{The x coordinates and the midpoint coordinate are} \\ 0=\frac{-2+x2}{2} \\ \text{Cross multiply and you have;} \\ 0=-2+x2 \\ 2=x2 \\ \text{The y coordinates and the midpoint coordinates are;} \\ 7=\frac{-6+y2}{2} \\ \text{Cross multiply and you have;} \\ 14=-6+y2 \\ 14+6=y2 \\ 20=y2 \\ \text{Therefore, the coordinates for the other midpoint is derived as;} \\ (2,20) \end{gathered}[/tex]Therefore, the coordinates of B is calculated as (2, 20)
Given f(x)= 1/x+6, find the average rate of change of f(x) on the interval [8,8+h]. Your answer will be an expression involving h
Function:
[tex]f(x)=\frac{1}{x+6}[/tex]Interval: [ 8, 8+h ]
Average rate of change:
[tex]A(x)=\frac{f(b)-f(a)}{b-a}[/tex]where a = 8 and b = 8 + h...
[tex]\begin{gathered} f(b)=\frac{1}{b+6} \\ f(8+h)=\frac{1}{8+h+6}=\frac{1}{h+14} \\ f(8+h)=\frac{1}{h+14} \end{gathered}[/tex][tex]\begin{gathered} f(a)=\frac{1}{a+6} \\ f(8)=\frac{1}{8+6}=\frac{1}{14} \end{gathered}[/tex]Then:
[tex]\begin{gathered} A(x)=\frac{\frac{1}{h+14}-\frac{1}{14}}{8+h-8}=\frac{\frac{1}{h+14}-\frac{1}{14}}{h}=-\frac{1}{14\cdot(h+14)} \\ A(x)=-\frac{1}{14h+196} \end{gathered}[/tex]can you please help me
The formula for the area of a circle is:
[tex]A=\pi\cdot r^2[/tex]also the diameter can be written in function of the radius
[tex]D=2\cdot r[/tex]from this equation we can find the radius
[tex]r=\frac{D}{2}[/tex]this transforms the formula for the area into
[tex]\begin{gathered} A=\pi\cdot(\frac{D}{2})^2 \\ A=\frac{\pi}{4}\cdot D^2 \end{gathered}[/tex]since the diameter is equal to 26cm, then the area will be
[tex]\begin{gathered} A=\frac{\pi}{4}\cdot676cm^2 \\ A=169\pi(cm^2)\approx530.93cm^2 \end{gathered}[/tex]The owners of a recreation area are filling a small pond with water. Let W be the total amount of water in the pond (in liters). Let T be the total number of minutes that water has been added. Suppose that w= 35T +300 gives W as a function of T during the next 70 minutes.Identify the correct description of the values in both the domain and range of the function. Then, for each, choose the most appropriate set of values.
Given:
[tex]W=35T+300[/tex]To find:
The domain and the range when t = 70 minutes.
Explanation:
When t = 70, we get
[tex]\begin{gathered} W=35(70)+300 \\ W=2750l \end{gathered}[/tex]The ordered pair of the solution is,
[tex](70,2750)[/tex]As the domain is the set of all input values, so the domain will be,
[tex][0,70][/tex]As the range is the set of all output values, so the range will be,
[tex][300,2750][/tex]Final answer:
The domain is,
[tex][0,70][/tex]The range is,
[tex][300,2750][/tex]find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -12 and 768 respectively
ANSWER:
[tex]a_n=3\cdot(-4)^{n-1}[/tex]STEP-BY-STEP EXPLANATION:
We have the following formula for nth terms
[tex]a_n=a_1\cdot r^{n-1}^{}[/tex]we replace for each point and we are left
[tex]\begin{gathered} a_2=-12 \\ -12=a_1\cdot r^{2-1}\rightarrow-12=a_1\cdot r^{}\text{ (1)} \\ a_5=768 \\ 768=a_1\cdot r^{5-1}\rightarrow768=a_1\cdot r^4\text{ (2)} \end{gathered}[/tex]We solve the system of equations that remains like this:
[tex]\begin{gathered} a_1=\frac{-12}{r}\text{ (3)} \\ a_1=\frac{768}{r^3}\text{ (4)} \\ \text{we equalize (3) and (4)} \\ -\frac{12}{r}=\frac{768}{r^4} \\ r^3=\frac{768}{-12} \\ r=\sqrt[3]{-64} \\ r=-4 \end{gathered}[/tex]Now, for a1
[tex]\begin{gathered} a_1=\frac{-12}{-4} \\ a_1=3 \end{gathered}[/tex]real exponential equation the base B must be positive. graph the equation using basis that are less than one or greater than one to determine any differences. what differences are there if any?
Let's graph the following functions.
[tex]\begin{gathered} f(x)=2^x \\ g(x)=(\frac{1}{2})^x \end{gathered}[/tex]The image below shows the graph.
According to the graph, the difference between the function is that f(x) is increasing and g(x) is decreasing, this behavior is caused by the base of the powers, the base 1/2 (between 0 and 1) gives a decreasing exponential function, and the base 2 (greater than 1) gives an increasing exponential function.
Hence, C is the right answer.Help Please! Will give brainliest and 45 points!
What is 12/10 as a fraction? What is 132/100 as a fraction? What is 546/100 as a fraction? What is 123/10 as a fraction? What is 872/100 as a fraction?
What is 12/10?
6/5 or 1 1/5 or 1.2
________________
What is 132/100?
33/25 or 1 8/25 or 1.32
________________
What is 546/100?
273/50 or 5 23/50 or 5.46
________________
What is 123/10?
123/10 or 12 3/10 or 12.3
________________
What is 872/100?
218/25 or 8 18/25 or 8.72
Answer:
12/10 = 1.2132/100 = 1.32 546/100 = 5.46123/10 = 12.3 872/100 = 8.72Step-by-step explanation:
1) 12/10 as a decimal is?
→ 12/10
→ 6/5 = 1.2
2) 132/100 as a decimal is?
→ 132/100
→ 1.32
3) 546/100 as a decimal is?
→ 546/100
→ 5.46
4) 123/10 as a decimal is?
→ 123/10
→ 12.3
5) 872/100 as a decimal is?
→ 872/100
→ 8.72
Hence, these are the answers.
the hikers received more fruit then they brought on the hike?
When the fruit in question was shared. They each got 14/4 = 3 and half ( 3.5 )
Those who brought less than 3 and half are those who we need to find
Baxter brought 3, Hendrick = 2, Mary = 4, Kendra = 5.
So those who brought less than they got ( 3 and half ) are Baxter and Hendrick
Abha is hosting a party at a place that can hold up to 125 people. Seventy eight people have said they are coming. How many more people can Abha invite?Inequality: ?Solution: ?
Since 78 people said they are coming already, and the place can hold a maximum of 125 people. Abha can invite a certain number of people (say x) such that the total number of attendees, ie x + 78 does not exceed 125.
In inequality form;
[tex]x+78\leq125[/tex]We can go for the solution;
[tex]\begin{gathered} x+78\leq125 \\ x\leq125-78 \\ x\leq47 \end{gathered}[/tex]Thus the inequality is
[tex]\begin{gathered} x+78\leq125 \\ \text{and the solution is} \\ x\leq47 \end{gathered}[/tex]What’s the answer to which expression is larger 5^3 or 4^4
5^3 = 5 x 5 x 5 = 125
4^4 = 4 x 4 x 4 x 4 = 256
256 > 125
4^4 is larger than 5^3
A storage container is 3 feet long, 5 feet wide, and 6 feet tall. if the diameter of a baseball is about 1.43 inches, approximately how many basketballs fit in the container? ( volume of a sphere is V = 4/3pi^3)
First, let's find the volume of the storage container:
Vs = 3*5*6 = 90 ft³
Now, let's do a conversion:
1.43 in * 1ft/12in = 0.119 ft
The radius is the diameter divide by 2:
r = 0.119/2 = 0.059583 ft
Let's find the volume of the baseball:
V = 4/3 π r³ = 4/3 π (0.059583)³ = 0.000886 ft³
Now divide the volume of the storage container by the volume of the baseball:
90/0.000886 ≈ 101573
Approximately 101573 balls fit in the container
State the null and alternative hypotheses for the claimThe average score of high school basketball games is less than 88.
For the equation −2 + 3 = 6 a. Find y when x is 3b. Find x when y is 4
Given equation,
[tex]-2x+3y=6[/tex](a) Find y when x is 3.
[tex]\begin{gathered} -2\times(3)+3y=6 \\ -6+3y=6 \\ 3y=12 \\ y=4 \end{gathered}[/tex](b) Find x when y is 4.
[tex]\begin{gathered} -2x+3y=6 \\ -2x+3\times4=6 \\ -2x+12=6 \\ -2x=-6 \end{gathered}[/tex]Thus, the value of x is
[tex]\begin{gathered} 2x=6 \\ x=3 \end{gathered}[/tex]a bowling alley charges its customers an hourly rate to bowl plus shoe rental. The hourly rates are per Lane. a linear model of this situation contains the values (2,39) and (3, 56.25), where x represents the number of hours bowled on one lane, and why represents the total cost for bowling.
Answer:
[tex]\$17.25[/tex]Explanation: We have to find the hourly rate to bowl, provided the following information:
[tex]\begin{gathered} (x_1,y_1)=(2,39) \\ (x_2,y_2)=(3,56.25) \end{gathered}[/tex]Where x is the number of hours and y is the total cost.
[tex]\begin{gathered} y(x)=mx \\ m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{56.25-39}{3-2} \\ m=\frac{56.25-39}{3-2}=\frac{\$17.25}{1hr} \\ m=\frac{\operatorname{\$}\times17.25}{1hr} \\ \therefore\rightarrow \\ y(x)=17.25x \end{gathered}[/tex]Therefore it costs $17.25 for an hour to bowl.
question provided in photo only need help with system b
Consistent dependent
Infinitely many solutions
Explanation:The given system of equations is:
[tex]\begin{gathered} y=-\frac{3}{2}x\ldots\ldots\ldots....\ldots\ldots\ldots\text{.}(1) \\ 3x+2y=0\ldots\ldots\ldots\ldots.......\ldots(2) \end{gathered}[/tex]A system of equations is consistent if it has at least one solution.
A system of equations is dependent if it has infinite number of solutions.
Considering the graph of the lines drawn in the question, the two lines are perfectly drawn on each other, which means that there are infinite numbers of solutions.
Therefore, the system of equations is consistent dependent.
This means that the system has infinitely many solutions. mber
Select all prime numbers 2,4,6,7,9,5
The Solution:
Given the set of numbers below:
[tex]2,4,6,7,9,5[/tex]We are asked to select all the prime numbers in the set.
A prime number is a number that can only be divided by 1 and itself. That is, it is a number that has only two factors.
So, the prime numbers in the set are:
[tex]2,7,5[/tex]Since these numbers only have two factors each.
Therefore, the correct answer is {2,7,5}
Answer:
The prime numbers would be 2, 5, and 7.
Step-by-step explanation:
Prime numbers are numbers that can only be multiplied by 1 and itself.
Here is a list of the common factors of each number:
2: 1, 2
4: 1, 2, 4
6: 1, 2, 3, 6
7: 1, 7
9: 1, 3, 9
5: 1, 5
So, our prime numbers are 2, 5, and 7.
May I have Brainliest please? My next rank will be the highest one: A GENIUS! Please help me on this journey to become top of the ranks! I would really appreciate it, and it would make my day! Thank you so much, and have a wonderful rest of your day!
Which of thhr following liner equations have a negitive y-intercept?circle all that apply
any letters or words in your answer! Ciera works at a day care center. Her job is to make sure there are always enough adult workers. Last month, there were 7 adults for 56 children, which is the minimum ratio allowed under state law. This month, 74 children are expected to enroll. How many adults will there need to be at the center? Your answer
10 adults
Explanation
Step 1
find the unit rate
[tex]\text{unit rate=}\frac{Number\text{ of Children}}{\text{Number of adults}}[/tex]Let
number of children=56
number of adults=7
replace,
[tex]\begin{gathered} \text{unit rate=}\frac{Number\text{ of Children}}{\text{Number of adults}}= \\ \text{unit rate=}\frac{56\text{ Children}}{7\text{ adults}} \\ \text{unit rate= 8 Children per adult} \end{gathered}[/tex]Step 2
Let x represents the adults needed for 74 children
find the unit rate:
[tex]\begin{gathered} \text{unit rate=}\frac{Number\text{ of Children}}{\text{Number of adults}} \\ \text{unit rate=}\frac{74}{x} \end{gathered}[/tex]as the unit rate must be the same
[tex]\begin{gathered} 8\frac{Children}{\text{adult}}=\frac{74}{x} \\ 8=\frac{74}{x} \\ cross\text{ multiply} \\ 8x=74\cdot1 \\ 8x=74 \\ \text{divide both sides by 8} \\ \frac{8x}{8}=\frac{74}{8} \\ x=9.25 \\ \text{hence, we n}eed\text{ 10 adults at the center} \end{gathered}[/tex]