SOLUTION
The duration for watering the whole flower is
[tex]\begin{gathered} \text{ finishing time- starting time } \\ 13\colon25-11\colon36 \\ \end{gathered}[/tex]Which is
[tex]1\text{hours 49minutes or 109 minutes }[/tex]This means it takes 109minutes for watering the whole flowers.
The time taken for 4/7 of the flowers is
[tex]\begin{gathered} \frac{4}{7}0f\text{ 109} \\ \\ \frac{4}{7}\times109=\frac{436}{7}=62.29 \\ \\ \end{gathered}[/tex]Then it takes 62minutes 29seconds to wet 4/7 of the flowers
[tex]\begin{gathered} 62\text{minutes 29 seconds will be } \\ 1\text{hours 0.5minutes } \end{gathered}[/tex]The time they will finish watering 4/7 of the flowers will be
[tex]\begin{gathered} \text{starting time +Duration for 4/7 of the flowers } \\ 11\colon36+1;05 \\ 12\colon41 \end{gathered}[/tex]1455 is 150% of blank
We have to calculate of which value x we have that 1455 is the 150%.
We have to express mathematically "150% of x is 1455". This can be written as:
[tex]\begin{gathered} \frac{150}{100}\cdot x=1455 \\ 1.5x=1455 \\ x=\frac{1455}{1.5} \\ x=970 \end{gathered}[/tex]Answer: 1455 is 150% of 970.
use the given actual and magnified lengths to determine which of the following insects were looked at using the same magnifying glass (with the same scale factor)
Grasshoper
Actual: 2 in
Magnified: 15 in
The scale factor is given by:
[tex]k=\frac{15}{2}=7.5[/tex]Black beetle
Actual: 0.6 in
Magnified: 4.2 in
The scale factor is:
[tex]k=\frac{4.2}{0.6}=7[/tex]Honybee
Actual: 5/8 in
Magnified: 75/16 in
The scale factor is:
[tex]k=\frac{\frac{75}{16}}{\frac{5}{8}}=\frac{75\cdot8}{16\cdot5}=\frac{600}{80}=\frac{15}{2}=7.5[/tex]Monarch butterfly
Actual: 3.9 in
Magnified: 29.25 in
The scale factor is:
[tex]k=\frac{29.25}{3.9}=\frac{15}{2}=7.5[/tex]Answer:
Grasshoper, Honybee and Monarch butterfly have the same factor scale = 7.5
Black beetle has a factor scale = 7
Two systems of equations are given below.For each system, choose the best description of its solution.If applicable, give the solution.System AThe system has no solution.The system has a unique solution:3x + 5y = 112x + 5y=4(x, y) = (1,5The system has infinitely many solutions.System BThe system has no solution.The system has a unique solution:y = 3x + 7y = 3x + 4(x, y) = (2, 2)The system has infinitely many solutions.
We are given the following system of equations:
[tex]\begin{gathered} 3x+5y=11,(1) \\ 2x+5y=4,(2) \end{gathered}[/tex]We can solve this system of equations using the method of elimination. To do that we will multiply equation (2) by -1:
[tex]-2x-5y=-4,(3)[/tex]Now we add equations (1) and (3):
[tex]3x+5y-2x-5y=11-4[/tex]Adding like terms:
[tex]x=7[/tex]Now we replace the value of "x" is equation (1):
[tex]\begin{gathered} 3(7)+5y=11 \\ 21+5y=11 \end{gathered}[/tex]Now we subtract 21 to both sides:
[tex]\begin{gathered} 5y=11-21 \\ 5y=-10 \end{gathered}[/tex]Dividing both sides by 5:
[tex]\begin{gathered} y=-\frac{10}{5} \\ y=-2 \end{gathered}[/tex]Therefore, the solution of the system is:
[tex](x,y)=(7,-2)[/tex]For the second system of equations:
[tex]\begin{gathered} y=3x+7,(1) \\ y=3x+4,(2) \end{gathered}[/tex]These equations represent two lines with the same slope, and therefore, parallel lines. Since they are parallel lines this means that the system has no solutions.
I need to know the answer to this question please
Answer:
Explanation:
Given:
[tex]3)\text{ }(32\div16)\div4\text{ = 32 }\div\text{ \lparen16}\div4)[/tex]To find:
the property demonstrated in the equation
Associative property is in the form:
(a + b) + c = a + (b + c)
The left side = right side
[tex]\begin{gathered} (32\div16)\div4\text{ = 32 }\div\text{ \lparen16}\div4) \\ Associative\text{ property was applied but the left side is not equal to the right side} \end{gathered}[/tex]That is why associative priperty is used for addition and multiplication
Write a equation of a line in slope intercept form that is perpendicular to the line y= [tex] \frac{1}{4} x[/tex]and crosses through the point (-3, -2)
Here, we want to write the equation of a line that passes through the given point and is perpendicular to the given line
When two lines are perpendicular to each other, what this mean is that the product of their slopes are equal to -1
Generally, the equation of a straight line can be written in the form;
[tex]y\text{ = mx + b}[/tex]where m is the slope of the line and b is the y-intercept of the given line
Now from the given equation, we can see that the coefficient of x is 1/4. What this mean is that the slope of the line is 1/4 (the line's y-intercept is zero)
We can then proceed from here to get the slope of the second line
Mathematically, since the two lines are perpendicular;
[tex]m_{1\text{ }\times\text{ }}m_2\text{ = -1}[/tex]Thus;
[tex]\begin{gathered} \frac{1}{4}\text{ }\times m_2\text{ = -1 } \\ \\ m_2\text{ = -1 }\times\text{ 4 = -4} \end{gathered}[/tex]This shows that the slope of the second line is -4
We can write the equation of the second line as;
[tex]y\text{ = -4x + c}[/tex]To completely write the equation of the second line, we need to get the value of c
To do this, we substitute the coordinates of the point that lies on the line
The point we are given is (-3,-2)
So in this case, we substitute the value x = -3 and y = -2
Thus, we have;
-2 = -4(-3) + c
-2 = 12 + c
c = -2 -12
c = -14
I have a triangle and diamond on an equation which is =1.05so I am asking am I suppose to divide by 2 to get the answer?
Let,
T = Triangle
S = Semi Circle
R = Star
D = Diamond
Given:
a.) 4 Triangles = 2 Semi Circle + 2 Star → 4T = 2S + 2R
b.) 1 Triangle + 1 Diamond = 1.05 → 1T + 1D = 1.05
c.) 1 Star + 1 Semi Circle = 0.525 → 1R + 1S = 0.525
d.) Diamond = ?
For us to be able to determine the value of the diamond, we must be able to determine the value of the Triangle.
For us to get it, we will be using first the equation at a and c.
4T = 2S + 2R
1R + 1S = 0.525
We get,
2S + 2R = 2(1S + 1R)
2S + 2R = 2(0.525)
2S + 2R = 1.05
Let's now get the value of the triangle,
4T = 2S + 2R
4T = 1.05
T = 1.05/4
T = 0.2625 (Value per triangle)
Let's now determine the value of the DIAMOND.
1 Triangle + 1 Diamond = 1.05 → 1T + 1D = 1.05
1T + 1D = 1.05
1(0.2625) + 1D = 1.05
0.2625 + 1D = 1.05
1D = 1.05 - 0.2625
1D = D = 0.7875
ANSWER: The value of the diamond is 0.7875
The distance from Becca’s house to Liz’s house is 13 kilometers. Approximately how many miles does Becca live from Liz? Use the conversion factor shown below.
Data:
13 km
Convert to miles
(1 km is equal to 0.6214 miles)
[tex]13\operatorname{km}\cdot\frac{0.6214mi}{1\operatorname{km}}=8.078mi[/tex](1 mile is equal to 1.6093km)
[tex]13\operatorname{km}\cdot\frac{1mi}{1.6093\operatorname{km}}=8.078mi[/tex]Then, Becca lives 8.078 miles (aprroximately 8.1 miles) from LizEnter an equation for the function. Give your answer in the form a(6"). In theevent that a = 1, give your answer in the form b".A laser beam with an output of 4 milliwatts is directed into a series of mirrorsThe laser beam loses 6% of its power every time it reflects off of a mirror. Thepower p(n) is a function of the number n of reflections.The equation is p(n) = 0
From the data provided, we have the following;
Initial power output = 4 milliwatts
Power lost per reflection = 6% (OR 0.06)
We need to find a function that shows the power each time the laser beam is reflected off a mirror.
Note that the general equation for an exponential decay/loss is given as;
[tex]\begin{gathered} y=a(1-r)^x \\ OR \\ f(x)=a(1-r)^x \end{gathered}[/tex]Note also that (1 - r) is often replaced by b. Therefore, the equation can be written as;
[tex]\begin{gathered} f(x)=a(1-r)^x^{} \\ f(x)=ab^x \end{gathered}[/tex]Where the number of reflections is given by n and p(n) is a function of the number of reflections, we now have;
[tex]p(n)=ab^n[/tex]Where the variables are;
[tex]\begin{gathered} a=4\text{ milliwatts (initial value)} \\ r=0.06 \end{gathered}[/tex]We now have the function as;
[tex]\begin{gathered} p(n)=a(1-0.06)^n \\ p(n)=a(0.94)^n \end{gathered}[/tex]ANSWER:
[tex]p(n)=a(0.94)^n[/tex]Please help will mark brain list
answer:
y = -2/3x -4/3
step-by-step explanation:
you start with 6x-9y = 12. you need to get y alone and on its own side of the equal sign.
starting easy, all coefficients (6, -9, and 12) have a GCF of 3. so, let's divide all sides by 3.
you are left with 2x-3y=4. now, we need to get -3y on its own side of the equal sign before we can get rid of its coefficient (-3). also, when identifying the coefficient of x, y, or any variable, include the + or - sign. you just don't need to write +, but you have to write -.
2x-3y=4 means we subtract 2x from both signs because it is positive. we now have
-3y = 2x + 4. let's divide by -3 to get y on it's own
y = -2/3x -4/3
Write inequalities to represent the situation below.Latoya exercises no less than 50 minutes per day.Use t to represent Latoya's amount of exercise (in minutes per day).(Thank you for the help!)
To answer this question, we have that:
1. Latoya exercises no less than 50 minutes per day.
In this case, we can say that Latoya exercises more than 50 minutes per day.
Therefore, if we have that t represents Latoya's amount of exercise - in minutes per day, we can express this using inequality as follows:
[tex]t>50[/tex]In summary, we can represent the situation as:
[tex]t>50[/tex]In ABC, AB = 10 and BC = 5. Which expression is always true?
Using the Triangle inequality:
In every triangle the sum of the lengths of any two sides is always greater than the length of the remaining side, so:
[tex]\begin{gathered} AB+BC>AC \\ so\colon \\ 5What type of number is 4π?whole numberintegerrational numberirrational number
Answer:
(D)Irrational number
Explanation:
The number π is Irrational because the digits after the decimal point go on indefinitely.
Therefore, a product of a number and π is also an Irrational Number.
Which of the following expressions can be used to rationalize the fractions below?
SOLUTION:
Case: Rationalizing fractions
Method:
[tex]\begin{gathered} \frac{16}{\sqrt{2}} \\ \Rightarrow \\ \frac{16}{\sqrt{2}}\times\frac{\sqrt{2}}{\sqrt{2}} \\ =\frac{16\sqrt{2}}{\sqrt{4}} \\ =\frac{16\sqrt{2}}{2} \\ =8\sqrt{2} \end{gathered}[/tex]Final answer: Option (A)
[tex]\frac{\sqrt{2}}{\sqrt{2}}[/tex]Order the angles of the triangle from smallest to biggest T R 12 addre S
It's important to know that each side is related to its angle in front. In other words, the greatest side has the greatest angle in front, and so on.
Having said that, the order of the angles from least to greatest is
[tex]\begin{gathered} 6<11<12 \\ \angle S<\angle R<\angle T \end{gathered}[/tex]Therefore, the order is S, R, and T.Tell which choice, 100, 500, or 1,000, is the best estimate of the solution.39.4x = 37,627a. 1,000b.500c.100Please select the best answer from the choices providedΑВС
39.4 x = 37627
Divide both sides by 39.4
[tex]\begin{gathered} \frac{39.4x}{39.4}=\frac{37627}{39.4} \\ x=955 \end{gathered}[/tex]955 is nearest to 1000 than 500 or 100
Then the best estimate is 1000
The answer is A
17. A publisher marks up a textbook by 60%, and a bookstore further marks up the textbook by 25%. What percentage of the original cost do you pay?%
A publisher marks up a textbook by 60%, and a bookstore further marks up the textbook by 25%. What percentage of the original cost do you pay?
Let
x ------> original cost
so
1) publisher marks up a textbook by 60%
cost=1.60x
2) bookstore further marks up the textbook by 25%
cost=1.60x(1.25)=2x
therefore
200%Please explain step by step on how to solve As I am brand new to this What is the median of 19,3,7,1,11,19,2,3,17,4,14,12
Answer:
The median is 9
Explanation:
The median of a data set is the value that lies in the middle of the ordered data set.
In this case, we have:
19,3,7,1,11,19,2,3,17,4,14,12
We need to order the list in ascending order:
1, 2, 3, 3, 4, 7, 11, 12, 14, 17, 19, 19
There are 12 values, since is an even number, the median is the average of the pair in the middle.
In this case, the pair in the middle is 7 and 11. The average is:
[tex]\frac{7+11}{2}=\frac{18}{2}=9[/tex]Thus, the median is 9
Part 2 out of 2If you plan to cancel your internet service after 11 months, which is the cheaper option
m = number of months
Option 1 cost = 35 + 20m
Option 2 cost = 25m
Part 1: If the cost is equal for both otpions, then we can write: 35 + 20m = 25m, solving for m:
5m = 35 ==> m = 35/5 = 7
m = 7
In month 7, the cost is 35 + 20(7) = 35 + 140 = 175
Part 2:
Option1 cost when m = 11: 35 + 20(11) = 35 + 220 = 255
Option2 cost when m = 11: 25(11) = 275
Option 2 costs more than option 1, so Option 1 is cheaper
what is the value of f(0)=
SOLUTION:
Case:
Given:
Required:
Method:
Step 1:
Step 2:
Step 3:
Final answer:
A. Substitute the x-values shown to the right into y = xand y = |x| to find several points on their graphs. Usethe probe to check your work.
For the function y=x we just have to replace the values in the table for the x so:
[tex]\begin{gathered} -3\to x=-3 \\ -2\to x=-2 \\ -1\to x=-1 \\ 0\to x=0 \\ 1\to x=1 \\ 2\to x=2 \\ 3\to x=3 \end{gathered}[/tex]and for y = |x| we have to change all the negative values for positive:
[tex]\begin{gathered} -3\to\mleft|x\mright|=3 \\ -2\to|x|=2 \\ -1\to|x|=1 \\ 0\to|x|=0 \\ 1\to|x|=1 \\ 2\to|x|=2 \\ 3\to|x|=3 \end{gathered}[/tex]Anjali's Bikes rents bikes for $15 plus $7per hour. Aliyah paid $57 to rent a bike.For how many hours did she rent the bike?
From the question;
Anjali's Bikes rents bikes for $15 plus $7 per hour.
Let h represent the number of hours she rent the bike;
the total amount she will pay for h hours is;
[tex]T=15+7h[/tex]Given that; Aliyah paid $57 to rent a bike.
T = $57
The equation becomes;
[tex]T=15+7h[/tex]Express the following ratio in simplest form 39:10
ok
If we have
[tex]\text{ }\frac{39}{10}[/tex]It was not possible to simplify it anymore so the answer will be the same.
It is not possible to implify it because the are no common fators between 39 and |0.
You poured 1/4 of the juice from a 2-liter bottle while serving guests at a party. How much juice, in liters, is still left in the bottle?
How much juice was used?
How much is left?
Answer:
1.5 litters is left and 0.5 litters was used
Step-by-step explanation:
2 litters divided by 4 = 0.5 litters and you can do the rest of the math if needed
The count in a bacteria culture was 800 after 15 minutes and 1000 after 30 minutes. Assuming the count grows exponentiallyA)What was the initial size of the culture? B)Find the doubling period. C)Find the population after 60 minutes. D)When will the population reach 13000.
Answer:
A) The initial size o the culture is 640
B) The doubling period is 47 minutes
C) The population after 60 minutes is 1563
D) The population will reach 13000 after 3 hours 22 minutes
Explanation:
The form of an exponential grow model is:
[tex]S=Pb^t[/tex]Where:
S is the population after t hours
P is the initial population
b is the base of the exponent
t is the time, in hours
We know that after 15 minutes, the population was 800. 15 minutes is a quarter of an hour. Thus, t = 1/4, S = 800:
[tex]800=Pb^{\frac{1}{4}}[/tex]Also, we know that after 30 minutes, the population was 1000. Thus, t = 1/2, S = 1000
[tex]1000=Pb^{\frac{1}{2}}[/tex]Then, we have a system of equations:
[tex]\begin{cases}800=Pb^{\frac{1}{4}}{} \\ 1000=Pb^{\frac{1}{2}}{}\end{cases}[/tex]We can solve the first equation for P:
[tex]\begin{gathered} 800=Pb^{\frac{1}{4}} \\ P=\frac{800}{b^{\frac{1}{4}}} \end{gathered}[/tex]And substitute in the other equation:
[tex]1000=\frac{800}{b^{\frac{1}{4}}}b^{\frac{1}{2}}[/tex]And solve:
[tex]\frac{1000}{800}=\frac{b^{\frac{1}{2}}}{b^{\frac{1}{4}}}[/tex][tex]\begin{gathered} \frac{5}{4}=b^{\frac{1}{2}-\frac{1}{4}} \\ . \\ \frac{5}{4}=b^{\frac{1}{4}} \end{gathered}[/tex][tex]\begin{gathered} b=(\frac{5}{4})^4 \\ . \\ b=\frac{625}{256} \end{gathered}[/tex]Now, we can find the initial population P:
[tex]P=\frac{800}{(\frac{625}{256})^4}=\frac{800}{\frac{5}{4}}=\frac{800\cdot4}{5}=640[/tex]The initial population is 640
To find the doubling period, we want that the population equal to twice the initial population:
[tex]S=2P[/tex]Then, since we know the equation, we can write:
[tex]2P=P(\frac{625}{256})^t[/tex]Then:
[tex]\begin{gathered} \frac{2P}{P}=(\frac{625}{256})^t \\ . \\ 2=(\frac{625}{256})^t \\ \ln(2)=t\ln(\frac{625}{256}) \\ . \\ \frac{\ln(2)}{\ln(\frac{625}{256})}=t \\ . \\ t\approx0.7765 \end{gathered}[/tex]If an hour is 60 minutes:
[tex]60\cdot0.7765=46.59\approx47\text{ }minutes[/tex]To find the population after 60 minutes, we use t = 1 hour and we want to find S:
[tex]\begin{gathered} S=640(\frac{625}{256})^1 \\ . \\ S=640\cdot\frac{625}{256}=1562.5 \end{gathered}[/tex]To find when the population is 13000, then we use S = 13000 and solve for t:
[tex]\begin{gathered} 13000=640(\frac{625}{256})^t \\ . \\ \frac{13000}{640}=(\frac{625}{256})^t \\ . \\ \frac{325}{16}=(\frac{625}{256})^t \\ . \\ \ln(\frac{325}{16})=t\ln(\frac{625}{256})^ \\ . \\ t=\frac{\ln(\frac{325}{16})}{\ln(\frac{625}{256})}\approx3.373 \\ \\ \end{gathered}[/tex]We have 3 full hours and 0.373. Since one hour is 60 minutes:
[tex]60\cdot0.373\approx22[/tex]The population reach 13000 after 3 hours 22 minutes
an unusually shaped section of a park is to be paved. this section is drawn to scale below. the length of a single grid segment is 1 m.
Since the length of a single grid square is 1m, then its area is:
[tex]A=1m\times1m=1m^2\text{.}[/tex]Now, to compute the area of the given section we will use the following diagram.
To compute the area of each triangle we will use the following formula for the area of a triangle:
[tex]\begin{gathered} A=\frac{bh}{2}, \\ \text{where b is the base of the triangle and h is its height.} \end{gathered}[/tex]And to compute the area of the rectangle we will use the following formula:
[tex]\begin{gathered} A=bh, \\ \text{where b is the base of the rectangle and h is its height.} \end{gathered}[/tex]Therefore the area of triangle A is:
[tex]A_A=\frac{6m\cdot2m}{2}=6m^2\text{.}[/tex]The area of triangle B is:
[tex]A_B=\frac{4m\cdot2m}{2}=4m^2\text{.}[/tex]The area of triangle C is:
[tex]A_C=\frac{3m\cdot1m}{2}=1.5m^2\text{.}[/tex]The area of triangle D is:
[tex]A_D=\frac{5m\cdot1m}{2}=2.5m^2\text{.}[/tex]The area of rectangle E is:
[tex]A_E=12m^2\text{.}[/tex]Finally, the area of the given section is:
[tex]\begin{gathered} A=A_A+A_B+A_C+A_D+A_E \\ =6m^2+4m^2+1.5m^2+2.5m^2+12m^2=26m^2\text{.} \end{gathered}[/tex]Answer:
The area of a single grid square is:
[tex]1m^2\text{.}[/tex]The approximate area of the section that will be paved is:
[tex]26m^2\text{.}[/tex]
Campbells wants to try and sell their soup in boxes rather than cans. The originalcans have a height of 6 inches and a diameter of 4 inches. If the boxes can only be 2inches deep, 4 inches wide and the keep the volume the same, what is the height ofthe new rectangplar box?
Given
Original cans
Height of 6 inches
Diameter of 4 inches
New boxes
2 inches deep
4 inches wide
Same volume
Procedure
Now let's calculate the volume of the soup cans.
[tex]\begin{gathered} V=\pi r^2h \\ V=\pi(2)^2(6) \\ V=75.36\text{ cubic inches} \end{gathered}[/tex]Now let's calculate the volume of the boxes
[tex]\begin{gathered} V=2\cdot4\cdot h \\ V=8h \end{gathered}[/tex]Now we must equal the volume of the cans and then calculate the height.
[tex]\begin{gathered} 75.36=8h \\ h=\frac{75.36}{8} \\ h=9.42\text{ inches} \end{gathered}[/tex]The height of the boxes must be equal to 9.42 inches.
Which expression is equivalent to75a7b"40213,9 ? Assume a=1 and C=0.
we have the expression
[tex]\sqrt[3]{\frac{75a^7b^4}{40a^{(13)}c^9}}[/tex]Remember that
[tex]\frac{75}{40}=\frac{15}{8}=\frac{15}{2^3}[/tex][tex]\frac{a^7}{a^{(13)}}=\frac{1}{a^6}[/tex]substitute
[tex]\sqrt[3]{\frac{75a^7b^4}{40a^{(13)}c^9}}=\sqrt[3]{\frac{15b^4}{2^3a^6c^9}}[/tex]we have that
[tex]2^3a^6c^9=(2a^2c^3)^3[/tex]substitute
[tex]\sqrt[3]{\frac{15b^4}{2^3a^6c^9}}=\frac{\sqrt[3]{15b^4}}{(2a^2c^3)}=b\frac{\sqrt[3]{15b^{}}}{(2a^2c^3)}[/tex]answer is the second option108A) 54B) 60C) 68D) 72BCNote: Figure not drawn to scale.In the figure above, lines and m are paralleland BD bisects ZABC. What is the value of x?
Given the shown figure:
lines l and m are parallel
So, m∠A = m∠ABC
Because the alternative angles are congruent
So, m∠ABC = 108°
And BD bisects the m∠ABC
So, m∠CBD = 1/2 * m∠ABC = 1/2 * 108 = 54°
As the lines l and m are parallel
So, m∠CBD = m∠D = x
So, the answer will be x = 54
The answer will be A) 54
The ratio of the quantities of sugar and flour needed to bake a cake is 2:5. What is the quantity of sugar needed for a cake, if 750 grams of flour are used to bake it?
The quantity of sugar needed for a cake, if 750 grams of flour are used to bake it is 300 grams.
What is ratio?Ratio demonstrates how many times one number can fit into another number. Ratios contrast two numbers by ordinarily dividing them.
In this case, the ratio of the quantities of sugar and flour needed to bake a cake is 2:5.
The quantity of sugar needed is illustrated by x.
This will be:
2/5 = x/750
Cross multiply
5x = 2 × 750
5x = 1500
Divide
x = 1500/5
x = 300
The sugar needed is 300 grams.
Learn more about ratio on:
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About 1% of the population has a particular genetic mutation. 100 people are randomly selected.Find the standard deviation for the number of people with the genetic mutation in such groups of 100. (Remeber that standard deviation should be rounded to one more decimal place than the raw data, in this case 1 decimal place is necessary.)
ANSWER:
1.0
STEP-BY-STEP EXPLANATION:
Given:
p = 1% = 0.01
q = 1 - p = 1 - 0.01 = 0.99
n = 100
The standard deviation is calculated using the following formula:
[tex]\begin{gathered} \sigma=\sqrt{n\cdot p\cdot q} \\ \\ \text{ We replace each value and obtain the standard deviation:} \\ \\ \sigma=\sqrt{100\cdot0.01\cdot0.99} \\ \\ \sigma=\sqrt{0.99} \\ \\ \sigma=0.99498 \\ \\ \sigma=0.995\rightarrow1\text{ decimal place}\rightarrow1.0 \end{gathered}[/tex]Therefore, the standard deviation is equal to 1.0