We have the following:
Since there are 4 cards and each one has a value of -10 points, we have
[tex]4\cdot-10=-40[/tex]Which means that the score changed by -40 points
Sam bought a stereo that listed for $795. He saved 20% of the originalcost by buying it at a sale and paying cash. How much did he pay for thestereo?a. $159b. $636c. $63.60d. $795
Given:
a.) Sam bought a stereo that was listed for $795.
b.) He saved 20% of the original cost by buying it at a sale and paying cash.
We will be using the following formula:
[tex]\text{ Discounted price = Original Price x (}\frac{100\text{\% - \% Discount}}{100})[/tex]We get,
[tex]\text{ Discounted price = Original Price x (}\frac{100\text{\% - \% Discount}}{100})[/tex][tex]\text{= 795 x (}\frac{100\text{\% - 20\%}}{100})[/tex][tex]\text{ = 795 x (}\frac{80}{100})[/tex][tex]\text{ = 795 x 0.80}[/tex][tex]\text{ Discounted Price = \$}636.00[/tex]Therefore, Sam paid $636 for the stereo.
The answer is letter B.
Use the six steps in the "Blueprint for Problem Solving" to solve the following word problem. You may recognize the solution by just reading the problem. Use n as the variable for the number and write the equation used to describe the problem.When 8 is subtracted from three times a number, the result is 4. Find the number.Equation: ? The number is ? .
Let n be the number we don't know.
Three times this number can be express as:
[tex]3n[/tex]The sentence "When 8 is subtracted from three times a number" can be express (using the expression we found before) as:
[tex]3n-8[/tex]Finally we know that this is equal to 4, then we have the equation:
[tex]3n-8=4[/tex]Solving for n we have:
[tex]\begin{gathered} 3n-8=4 \\ 3n=8+4 \\ 3n=12 \\ n=\frac{12}{3} \\ n=4 \end{gathered}[/tex]Therefore the number we are looking for is 4.
give the following five-number summary, find the interquartile range. 29, 37, 50, 66, 94
we have the data set
29, 37, 50, 66, 94
step 1
Order the data from least to greatest
so
29, 37, 50, 66, 94
step 2
Find the median
29, 37, 50, 66, 94
the median is 50
step 3
Calculate the median of both the lower and upper half of the data
29, 37, 50, 66, 94
the lower half ------> (29+37)/2=33
upper half -------> (66+94)/2=80
step 4
The IQR is the difference between the upper and lower medians
so
80-33=47
the answer is 47m =Y2-71x2-x1Find the slope of the line that passesthrough these two points,(3, 1) (4,9)m = [?]
1) Since, we've got already two points. Let's plug them into the slope formula so that we can find how steep is the line between those two points:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{9-1}{4-3}=\frac{8}{1}=8[/tex]2) Thus, that's the slope.
If 36 identical motors are installed in a drying oven on blowers for that oven and the total current for all 36 motors is 85 amps, what is the approximate current for each motor? Round your answer to two decimal places.
Step 1:
Given data
Number of identical motors = 36
Total current for all 36 motors = 85 amps
Step 2: Calculate current for each motor
If the total current in all 36 motors = 85 amps
To find the current in 1 motor, you will divide the total number of current with the total number of motors.
Step 3: Final answer
[tex]\begin{gathered} \text{Current for each motor = }\frac{Total\text{ current}}{\text{Total number of motors}} \\ =\text{ }\frac{85}{36} \\ =\text{ 2.36 amps/motor} \end{gathered}[/tex]Current for each motor = 2.36 amps/motor
-7 x -10 y equals -83 4x - 10 y equals 16
Answer:
Subtract to eliminate y.
Step by step explanation:
[tex]\begin{gathered} -7x-10y=-83 \\ 4x-10y=16 \end{gathered}[/tex]Since we have the same negative coefficient for y, we can subtract them to eliminate y.
-10-(-10)=0.
Evaluate 2g - 4, if the value of g=5
Put g=5 in 2g-4.
[tex]\begin{gathered} 2g-4=2\times5-4 \\ =10-4 \\ =6 \end{gathered}[/tex]The value is 6.
if planet 1 is 32.7 million miles farther from the sun than planet 2, then planet 3 is 26.5 million miles farther from the sun than planet 1. when the toal of distnaces for these three planets from the sun is 190.0 million miles, how far away from thesun is planet 2?
The distance between planet 2 and sun is of 32.7 million miles.
Let the distance between planet 2 and sun = x
Distance between planet 1 and sun = 32.7 + x
Distance between planet 3 and sun = (32.7 + x) + 26.5
= 59.2 + x
According to question,
Distance between planet 1 and sun + distance between planet 2 and sun + Distance between planet 3 and sun = 190
(32.7 + x) + x + (59.2 + x) = 190
3x + 91.9 = 190
3x = 190 - 91.9
3x = 98.1
x = 98.1 / 3
x = 32.7
Hence, Distance between planet 2 and sun is 32.7 million miles.
Learn more about distance on:
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the function h(x)=x^2+5 maps the domain given by the set {-2,-1,0,1,2} determine the set that represents the range of h (x)
h(x) = x^2 + 5
h(-2) = (-2)^2 + 5 = 4 + 5 = 9
h(-1) = (-1)^2 + 5 = 1 + 5 = 6
h(0) = (0)^2 + 5 = 5
h(1) = (1)^2 + 5 = 1 + 5 = 6
h(2) = (2)^2 + 5 = 4 + 5 = 9
The range is {9, 6, 5, 6, 7]
a hot air balloon decrease its altitude by 3/8 ft each for two seconds what was the total change in altitude
The rate of change is the decrease in altitude per change in two seconds
[tex]\begin{gathered} \frac{3}{8}\text{ divided by 2} \\ \frac{3}{8}\text{ x}\frac{1}{2} \\ \Rightarrow\frac{3}{16}ft\text{ per second} \end{gathered}[/tex]If the initial altitude is y ft
A day of the week is chosen at random. What is the probability that it is a Wednesday or Saturday?A.2/7B.1/7C.2/14D. 2
ANSWER
[tex]A)\frac{2}{7}[/tex]EXPLANATION
There are 7 days in a week.
The probability that a chosen day of the week is Wednesday or Saturday is the sum of the probability that the day is a Wednesday and the probability that the day is a Saturday.
Since there is only one Wednesday in a week, the probability that the day is a Wednesday is:
[tex]P(W)=\frac{1}{7}[/tex]The same rule applies for Saturday:
[tex]P(S)=\frac{1}{7}[/tex]Therefore, the probability that the day is a Wednesday or a Saturday is:
[tex]\begin{gathered} P(W-or-S)=\frac{1}{7}+\frac{1}{7} \\ P(W-or-S)=\frac{2}{7} \end{gathered}[/tex]hello I was trying to do this question on my own for a while and haven't gotten the answer I need but hopefully you can help me and thank you for your time
given diameter (D) of wheel = 24 in rotation of wheel 455 rpm
circunference (C) = π⋅D
[tex]\begin{gathered} C=\pi\times24\text{ in } \\ C=\pi\times\frac{24}{12}=\pi2\text{ ft/r} \end{gathered}[/tex]455 rpm x 60 = 27300 r/h
27300 x 2π = 54600π ft/h
5280 ft = 1 mile
[tex]\frac{54600\pi}{5280}=10.34\pi[/tex]or 10.34 π mph
Hi I need help with this homework so I can get a good grade on the test
The answers are indeed nx and m.
identify all expressions equivalent to the given expressions. 2/3 • 9 ÷ 3 - 1 ANWSER: 6 ÷ 2 - 1 + 2 3 • 2/3 -12/3 • 9 ÷ 1
Simplify each expression and find if the simplified form is the same.
[tex]2/3\cdot9\div3-1[/tex]This can also be writen as:
[tex]=\frac{2}{3}\cdot9\div3-1[/tex]Multiply 2/3 by 9:
[tex]=6\div3-1[/tex]divide 6 by 3:
[tex]=2-1[/tex]Substract 1 from 2:
[tex]=1[/tex]Now, check each option:
6 ÷ 2
Divide both numbers:
[tex]\frac{6}{2}=3[/tex]This is NOT equivalent to the given expression.
- 1 + 2
Add the numbers:
[tex]-1+2=1[/tex]This IS equivalent to the given expression.
3 • 2/3 -1
First, multiply 3 times 2/3:
[tex]3\cdot\frac{2}{3}-1=2-1[/tex]Then, add both numbers:
[tex]2-1=1[/tex]This IS equivalent to the given expression.
2/3 • 9 ÷ 1
Perform the operations from left to right:
[tex]\begin{gathered} \frac{2}{3}\cdot9\div1=6\div1 \\ =6 \end{gathered}[/tex]This is NOT equivalent to the given expression.
Therefore, the expressions that are equivalent to the given one, are:
[tex]\begin{gathered} -1+2 \\ 3\cdot2/3-1 \end{gathered}[/tex]Choose whether the number given in specific notation is representing a large or small number.
Given:
[tex]\begin{gathered} a)1.2\times10^3 \\ b)7.5\times10^^{-4} \end{gathered}[/tex]To find:
The number given in a specific notation is representing a large or small number.
Explanation:
a) It can be written as,
[tex]\begin{gathered} 1.2\times10^3=1.2\times1000 \\ =1200 \end{gathered}[/tex]So, it is a large number.
b) It can be written as,
[tex]\begin{gathered} 7.5\times10^{-4}=7.5\times\frac{1}{10^4} \\ =\frac{7.5}{10000} \\ =0.00075 \end{gathered}[/tex]So, it is a small number.
Final answer:
a) Large
b) Small
Hello can you help with the angles for each letter
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
diagram
Step 02:
angles:
we must analyze the diagram to find the solution.
a = (180 - 115)° = 65°
b = 115°
c = 65°
d = (180 - 135)° = 45°
f = 110°
g = (180 - 110)° = 70°
h = 110°
j = (180 - 65)° = 115°
k = (180 - 45 - 70)° = 65°
m = (180 - 42)° = 138°
n = (180 - 42 - 65)° = 73°
p = (180 - 73)° = 107°
q = (180 - 107)° = 73°
r = (180 - 68)° = 112°
s = (540 - 135 - 115 - 107 - 115)° = 68°
t = (360 - 124 - 73 - 112)° = 51°
u = 135°
v = 45°
w = (180 - 45 - 65)° = 70°
x = (180 - 65)° = 115°
That is the full solution.
18. A line has slope = -9 and goes through the point (-4,-2). What is the equation of this line in point-slope forma A. y + 2 = -91X - 4) B. Y-2= -9(x-4) C. y 2 = -91x + 4) D. y - 2= -9(x +4)
The straight line equation is
[tex]y=mx+b[/tex]where m is the slope and b the y-intercept. In our case m=-9. Hence, our line
equations has the form
[tex]y=-9x+b[/tex]In order to find b, we must use the given point (-4,-2) and substitute it and the last equation.
It yields,
[tex]-2=-9(-4)+b[/tex]hence, we have
[tex]\begin{gathered} -2=36+b \\ -2-36=b \\ b=-38 \end{gathered}[/tex]Finally, the answer is
[tex]y=-9x-38[/tex]Now, we can rewrite this equation as
[tex]\begin{gathered} y=-9(x+4)-2 \\ \text{which is equal to} \\ y+2=-9(x+4) \end{gathered}[/tex]then, the answer is C.
Given h(x) = 5x – 3 and m(x)= -2x^2 what (h o m)(-1)=
Let's begin by listing out the information given to us:
[tex]\begin{gathered} h\mleft(x\mright)=5x-3 \\ m\mleft(x\mright)=-2x^2 \\ \mleft(h^om\mright)\mleft(x\mright)=5(-2x^2)-3 \\ (h^om)(1)=-10x^2-3=-10(-1^3)-3 \\ (h^om)(1)=10-3=7 \\ (h^om)(1)=7 \end{gathered}[/tex]Is Rashida’s work correct? If not, what is the first step where Rashida made a mistake?- Her work is correct - First mistake was in Step 1- First mistake was in Step 2- First mistake was in Step 3*pls help!*
Answer:
First mistake was in Step 1
Explanation:
If f(x) = x² - |x| and we find f(-x), we get:
f(-x) = (-x)² - | - x |
f(-x) = x² - | x |
Therefore, her first mistake was in Step 1 because she changed the sign of |x| and
|x| = |-x|
So, the answer is:
First mistake was in Step 1
I need help it says identity the equivalent expression for the expression above
Given:
Expression is
[tex]=\frac{m^{\frac{1}{3}}}{m^{\frac{1}{5}}}[/tex]Required:
Equivalent expression for the given expression.
Explanation:
We will use
[tex]\frac{x^a}{x^b}=x^{a-b}[/tex]So,
[tex]\begin{gathered} \frac{m^{\frac{1}{3}}}{m^{^{\frac{1}{5}}}}=m^{\frac{1}{3}-\frac{1}{5}} \\ =m^{\frac{2}{15}} \end{gathered}[/tex]Answer:
Hence, 1st option is correct.
Choose the correct table for the inverse of the relation below
GIVEN:
We are given a table of x and y values that defines a function.
Required;
To find the inverse of the relation as shown.
Step-by-step solution;
For a relation defined as an ordered pair in the form,
[tex](x,y)[/tex]then its inverse is a relation of the set of ordered pairs in the form;
[tex](y,x)[/tex]In other words, what we have is;
[tex]\begin{gathered} f(x)=(x,y) \\ \\ f^{-1}(x)=(y,x) \end{gathered}[/tex]The function given has the following ordered pairs;
[tex]\begin{gathered} For\text{ }f(x): \\ \\ (-4,-3),(-1,1),(1,2),(3,6) \end{gathered}[/tex]Therefore, the inverse would be;
[tex]\begin{gathered} For\text{ }f^{-1}(x): \\ \\ (-3,-4),(1,-1),(2,1),(6,3) \end{gathered}[/tex]ANSWER:
Therefore, option A is the correct answer
The function f(T) = a (x - h[ + k is shown in the graph below. 2 0 6 N What is the value of a? What is the value of h? 1 What is the value of k?
As we can see from the graph, the function is shifted from one unit to the right, and two units up, and it is in an inverse way.
Then, we can express this as:
[tex]-1\cdot|x-1|+2[/tex]The value for a = -1.
The value for h = 1.
And the value for k = 2.
A certain company recorded the number of employee absences each week over a period of 10 weeks. The result is the data list 3, 5, 1, 2, 2, 4, 7, 4, 5, 5. Find the mean and standard deviation of the number of absences per week. Round the standard deviation to two decimal places.
The table of the number of absences every week for 10 weeks:
3, 5, 1, 2, 2, 4, 7, 4, 5, 5
The mean can be calculated as:
Where xi is the ith element of the list and n is the number of elements.
Then, the mean is:
Mean = (3+5+1+2+2+4+7+4+5+5)/10
Mean = 3.8
Now, the standard deviation (std) is given by the formula:
Then, using the formula above, we obtain:
std = 1.72
Show work and/or describe how the expression for the completing the square method and the expression associated with the quadratic formula are equivalent.
Given a general quadratic expression:
[tex]ax^2+bx+c=0[/tex]firs, lets divide both sides of the equation by 'a' :
[tex]\begin{gathered} (\frac{1}{a})(ax^2+bx+c=0)^{} \\ \Rightarrow\frac{a}{a}x^2+\frac{b}{a}x+\frac{c}{a}=0 \\ \Rightarrow x^2+\frac{b}{a}x+\frac{c}{a}=0 \end{gathered}[/tex]next, we can move the term c/a to the right side of the equation:
[tex]\begin{gathered} x^2+\frac{b}{a}x+\frac{c}{a}=0 \\ \Rightarrow x^2+\frac{b}{a}x=-\frac{c}{a} \end{gathered}[/tex]now we are ready to complete the square on the left side. What we have to do, is to take the constant that is multiplying x (in this case,b/a), and first, we divide it by 2, and then elevate to the square the result:
[tex]\begin{gathered} \frac{b}{a}\frac{\cdot}{\cdot}2=\frac{b}{2a} \\ \Rightarrow(\frac{b}{2a})^2=\frac{b^2}{4a^2} \end{gathered}[/tex]then, adding this number on both sides of the equation, we get:
[tex]x^2+\frac{b}{a}x+\frac{b^2}{4a}=-\frac{c}{a}+\frac{b^2}{4a^2}[/tex]which we can write like this:
[tex](x+\frac{b}{2a})^2=\frac{-4ac+b^2}{4a^2}_{}[/tex]applying the square root on both sides,we get the following:
[tex]\begin{gathered} \sqrt[]{(x+\frac{b}{2a})^2}=\sqrt[]{\frac{b^2-4ac}{4a^2}}=\pm\frac{\sqrt[]{b^2_{}-4ac}}{2a} \\ \Rightarrow x+\frac{b}{2a}=\pm\frac{\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]finally, we can solve for x:
[tex]\begin{gathered} x+\frac{b}{2a}=\pm\frac{\sqrt[]{b^2-4ac}}{2a} \\ \Rightarrow x=-\frac{b}{2a}\pm\frac{\sqrt[]{b^2-4ac}}{2a}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex]as we can see, if we have a general quadratic equation, we can us the completing the square method to deduce the quadratic formula
whats my test mean by Match the two numbers with their least common multiple (LCM). MatchTermDefinition 8 and 4A) 40 8 and 6B) 24 8 and 10C) 8
LCM of 8 and 10 = 40 ((option C)
LCM of 8 and 4 = 8 (option B)
LCM of 8 and 6 = 24 (option A)
Explanation:We find each of the least common multiple (LCM) of the numbers then we match the result.
We pick the common numbers in both. Then multiplied by other numbers not common to both
8 = 2 × 2 × 2
4 = 2 × 2
LCM of 8 and 4 = 2×2×2
LCM of 8 and 4 = 8 (option B)
8 = 2 × 2 × 2
6 = 2 × 3
LCM of 8 and 6 = 2×2×2×3
LCM of 8 and 6 = 24 (option A)
8 = 2 × 2 × 2
10 = 2 × 5
LCM of 8 and 10 = 2 × 2 × 2 × 5
LCM of 8 and 10 = 40 ((option C)
Can someone help me with these geometry questions sorry it’s a two parter.
In this problem, we are trying to choose between using a permutation and a combination.
The main difference between the two is the order.
In a combination, order doesn't matter, but it does matter in a permutation. Since the coach is choosing people based on how they performed, this will be a permutation.
For the first box on your screen, you should drag and drop the "P" variable for permutation.
Next, we need to apply the permutation formula:
[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]I'm assuming there are a total of 14 players on the team? So we will let
[tex]\begin{gathered} n=14 \\ r=3 \end{gathered}[/tex]Where n represents the total number of players, and r represents the number of people being chosen based on performance. Then we have:
[tex]\frac{14!}{(14-3)!}=\frac{14!}{11!}[/tex]You can drag the 14! to the numerator and the 11! to the denominator.
Finally, we need to simplify to get the final answer. We can always use a calculator, but I'll show the steps for simplifying here:
[tex]\begin{gathered} \text{ Rewrite}14! \\ \frac{14\cdot13\cdot12\cdot11!}{11!} \end{gathered}[/tex][tex]\begin{gathered} \text{ Cancel the }11! \\ \\ \frac{14\cdot13\cdot12\cdot\cancel{11!}}{\cancel{11!}} \end{gathered}[/tex]Multiply the remaining values:
[tex]14\cdot13\cdot12=2184[/tex]The coach has 2184 ways to choose a player.
When the transformation T2,-1 is performed on point A, its image is point A (-3, 4). What are the coordinates ofA?
Answer
A (-5, 5)
Explanation
When the transformation Ta, b is performed on a given coordinate B (x, y), it becomes B' [(x + a). (y + b)]
So, for this question, the transformation is T2, -1, on point A (x, y) to give the image point A' (-3, 4)
A' (-3, 4) = A' [(x + 2), (y - 1)]
x + 2 = -3
x = -3 - 2 = -5
y - 1 = 4
y = 4 + 1 = 5
So, the coordinates of point A is (-5, 5)
Hope this Helps!!!
what is the equation for the line that passes through the given point and is parallel to the graph of y=3x-2; (3,2)
In the early afternoon, a tree casts a shadow that is 2 feet long. A 4.2-foot-tall boy standing nextto the tree casts a shadow that is 0.7 feet long. How tall is the tree?
In this drawing, the traingle on the left, has the height of the tree (T) and the size of the shadow 2 feet
The tringle on the right, has the height of the boy, 4.2 feet and the shadow is 0.7 feet
The angle a is the angle with respect to the sun light
The triangles are congruent, because therefore the proportion of their sides is equal, so we can write:
T/2 = 4.2/0.7
Solving for T:
T = 2(4.2/0.7) = 12
T = 12
Answer:
The tree is 12 feet tall
For each system of equations below, determine whether it has one solution, no solution, or infinite solutions. 4x+9y=1510x+15y=25
Let's solve the system of linear equations
[tex]\begin{gathered} 4x+9y=15 \\ 10x+15y=25 \end{gathered}[/tex]