if f(x) = 1/x and g(x) = x+1/x find(fog)(x).a) x +1/ x squared b) x / x + 1 c) x squared (x + 1)d) x + 1 / x cubed

If F(x) = 1/x And G(x) = X+1/x Find(fog)(x).a) X +1/ X Squared B) X / X + 1 C) X Squared (x + 1)d) X

Answers

Answer 1

We have the following:

[tex]\begin{gathered} f(x)=\frac{1}{x} \\ g(x)=\frac{x+1}{x} \end{gathered}[/tex]

now, (f(x) o g(x))

[tex]\mleft(f\: (x)\circ\: g(x)\mright)=\frac{1}{\frac{x+1}{x}}=\frac{x}{x+1}[/tex]

The answer is the second option

[tex]\frac{x}{x+1}[/tex]


Related Questions

The equation and graph of a polynomial are shown below. The graph reachesits minimum when the value of xis 4. What is the y-value of this minimum?--y= 2x2-16x + 30ys

Answers

We can find the y-value of the minimum using the graph or using the equation. Let's use the equation and evaluate it when x = 4.

[tex]\begin{gathered} y=2x^2-16x+30=2(4)^2-16(4)+30 \\ y=2\cdot16-64+30=32-64+30=-2 \end{gathered}[/tex]Hence, the y-value of the minimum is -2.

Use a unit multiplier to convert 90 meters per minute to meters per second.

Answers

Hello there. To solve this question, we'll have to remember some properties about unit conversions.

We want to convert 90 meters per minute to meters per second.

Remember 1 minute is equal to 60 seconds, therefore we can write

90 meters per 60 seconds

Simplify it by a factor of 30

3 meters per 2 seconds

Which is the same as

1.5 meters per second

The unit multiplier was divide the number by 60, in order to get minutes to seconds and, therefore, find the value in m/s.

- 10x + 100y = 30-3x + 30y = 9

Answers

The given system is

[tex]\mleft\{\begin{aligned}-10x+100y=30 \\ -3x+30y=9\end{aligned}\mright.[/tex]

First, we multiply the first equation by -3/10.

[tex]\mleft\{\begin{aligned}3x-30y=-9 \\ -3x+30y=9\end{aligned}\mright.[/tex]

Then, we sum the equations

[tex]\begin{gathered} 3x-3x+30y-30y=9-9 \\ 0x+0y=0 \\ 0=0 \end{gathered}[/tex]According to this result, we can deduct that the system doesn't have any solutions because the lines represented by the equations are parallel.

Write a system of equations to describe the situation below, solve using an augmented matrix.The glee club needs to raise money for the spring trip to Europe, so the members are assembling holiday wreaths to sell. Before lunch, they assembled 20 regular wreaths and 16 deluxe wreaths, which used a total of 140 pinecones. After lunch, they assembled 20 regular wreaths and 18 deluxe wreaths, using a total of 150 pinecones. How many pinecones are they putting on each wreath?The regular wreaths each have ? pinecones on them and the large ones each have ? pinecones.

Answers

Given

First : They assembled 20 regular wreaths and 16 deluxe wreaths, which used a total of 140 pinecones

Let's represent regular wreaths with r

and

Let's represent deluxe wreaths with d

[tex]20r+16d=140[/tex]

Second: They assembled 20 regular wreaths and 18 deluxe wreaths, using a total of 150 pinecones

[tex]20r+18d=150[/tex]

We now have

[tex]\begin{gathered} 20r+16d=140\text{ ...Equation 1} \\ 20r+18d=150\text{ ...Equation 2} \end{gathered}[/tex]

we can now solve simultaneously, by subtracting the equation 1 and 2

[tex]\begin{gathered} 20r-20r+16d-18d=140-150 \\ -2d=-10 \\ Divide\text{ both sides by -2} \\ -\frac{2d}{-2}=-\frac{10}{-2} \\ \\ d=5 \end{gathered}[/tex]

We can subsitute d=5 in equation 1 or 2

[tex]\begin{gathered} 20r+16d=140\text{ ... Equation 1} \\ 20r+16(5)=140 \\ 20r+80=140 \\ 20r=140-80 \\ 20r=60 \\ divide\text{ both sides by 20} \\ \frac{20r}{20}=\frac{60}{20} \\ \\ r=3 \end{gathered}[/tex]

The final answer

5 pinecones on the deluxe wreath and 3 pinecones on the regular wreath

determine whether or not each equation is a linear equation in two variables. if so, identify a b and c a. 2x =5 + yb. y = 5x + 3

Answers

Given:

Linear equation in x and y:

An equation of the form y = mx + c or ax + by +c =0 is a linear equation as the degree of both variables x and y is one.

(a) 2x = 5 + y:

The equation can be written as:

[tex]y=2x-5\text{ or 2x-y-5=0}[/tex]

This is of the form of ax+by+c=0 so it is linear.

Here, a=2, b= 1, c= - 5

(b) y = 5x + 3:

[tex]y=5x+3\text{ or 5x-y+3=0}[/tex]

This is already in the form of ax + by+ c=0 so it also linear.

Here, a= 5 , b = - 1, c= 3

identify the maximum from the tabletype your answer as an ordered pair (x,y)

Answers

We want to know the maximum value for f(x). In this case, we have that when f(x) = 10, x =6. Then, the ordered pair (6,10) represents the maximum from the table

The value of China's exports of automobiles and parts (in billions of dollars) is approximately f ( x ) = 1.8208 e .3387 x , where x = 0 corresponds to 1998. In what year did/will the exports reach $7.4 billion?

Answers

We have the following equation:

[tex]f(x)=108208e^{0.3387x}[/tex]

where x denotes the number of years after 1998.

By substituting the given information, we have that

[tex]7.4=1.8208e^{0.3387x}[/tex]

and we need to find x. Then, by dividing both sides by 1.8208, we get

[tex]e^{0.3387x=}4.0641475[/tex]

then by taking natural logarithm to both sides, we obtain

[tex]0.3387x=ln(4.0641476)[/tex]

which gives

[tex]0.3387x=1.4022040[/tex]

then, the number of years after 1998 is:

[tex]\begin{gathered} x=\frac{1.4022040}{0.3387} \\ x=4.13996 \end{gathered}[/tex]

which means 4 years after 1998. Then, by rounding to the nearest year, the answer is 2002.

2. Does the data describe a positive or negative correlation? (1/2 point)3. Find the equation of your line of fit. (1 point)+4. What predicted vehicle weight would indicate a vehicle whose gas mileage is 30 miles per gallon?(1 point)5. Suppose you have a vehicle that weighs 1500 pounds. Use the model to determine the expected city MPGof the vehicle. (1 point)

Answers

Given the values shown in the table, let be "x" the Vehicle weight (in hundreds of lbs.) and "y" the City MPG (Miles per gallon).

1. Given the points:

[tex](27,25),(35,19),(39,16),(32,21),(40,15),(23,29),(18,31),(37,15),(17,46),(23,26),(37,17),(30,26),(23,29),(32,19),(20,33),(30,21)[/tex]

You can plot them on a Coordinate Plane:

2. Notice the following line:

Notice that the points are closed to the red line that has a negative slope. Therefore, you can identify that when one of the variables increases, the other variable decreases. Hence, you can conclude that the data describes a negative correlation.

3. You need to follow these steps to find the equation of the line of best fit:

- You need to find the average of the x-values by adding them and dividing the Sum by the number of x-values:

[tex]\bar{X}=\frac{27+35+39+32+40+23+18+37+17+23+37+30+23+32+20+30}{16}[/tex][tex]\bar{X}=28.9375[/tex]

- Find the average of the y-values:

[tex]\bar{Y}=\frac{25+19+16+21+15+29+31+15+46+26+17+26+29+19+33+21}{16}[/tex][tex]\bar{Y}=24.25[/tex]

- Find:

[tex]\sum_{i=1}^n(x_i-\bar{X})[/tex]

Where this represents each x-values in the data set:

[tex]x_i[/tex]

You get:

[tex]\sum_{i=1}^n(x_i-\bar{X})=(27-28.9375)+(35-28.9375)+(39-28.9375)+(32-28.9375)+(40-28.9375)+(23-28.9375)+(18-28.9375)+(37-28.9375)+(17-28.9375)+(23-28.9375)+(37-28.9375)+(30-28.9375)+(23-28.9375)+(32-28.9375)+(20-28.9375)+(30-29.9375)[/tex][tex]\sum_{i=1}^n(x_i-\bar{X})=1.0625[/tex]

- Find:

[tex]\sum_{i=1}^n(x_i-\bar{Y})[/tex]

You get:

[tex]\sum_{i=1}^n(x_i-\bar{Y})=(25-24.25)+(19-24.25)+(16-24.25)+(21-24.25)+(15-24.25)+(29-24.25)+(31-24.25)+(15-24.25)+(46-24.25)+(26-24.25)+(17-24.25)+(26-24.25)+(29-24.25)+(19-24.25)+(33-24.25)+(21-24.25)[/tex][tex]\sum_{i=1}^n(x_i-\bar{Y})=-3.25[/tex]

- Find:

[tex]\sum_{i=1}^n(x_i-\bar{X})(y_i-\bar{Y})[/tex]

You get:

[tex]=-857.75[/tex]

- Find:

[tex]\sum_{i=1}^n(x_i-\bar{X})^2[/tex]

You can find it by squaring each Difference of the x-values and the Mean. you get:

[tex]=862.9375[/tex]

- Find the slope of the line

[tex]m=\frac{-857.75}{862.9375}\approx-0.994[/tex]

- Find the y-intercept with this formula:

[tex]b=\bar{Y}-m\bar{X}[/tex][tex]b=24.25-(-0.994)(1.0625)[/tex][tex]b=53.0135[/tex]

Therefore, the line in Slope-Intercept Form:

[tex]y=mx+b[/tex]

is the following:

[tex]y=-0.9940x+53.0135[/tex]

4. If:

[tex]y=30[/tex]

You can predict the vehicle weight by substituting that value into the equation found in Part 3, and solving for "x":

[tex]30=-0.9940x+53.0135[/tex][tex]\frac{30-53.0135}{-0.9949}=x[/tex][tex]x\approx23.1524[/tex]

5. If a vehicle weighs 1500 pounds, then:

[tex]x=1500[/tex]

Then you can determine the expected city MPG of the vehicle by substituting this value into the equation and evaluating:

[tex]y=-0.9940(1500)+53.0135[/tex][tex]y\approx-1437.9865[/tex]

Hence, the answers are:

1.

2. It describes a negative correlation.

3.

[tex]y=-0.9940x+53.0135[/tex]

4.

[tex]x\approx23.1524\text{ \lparen in hundreds of pounds\rparen}[/tex]

5.

[tex]y\approx-1437.9865\text{ \lparen In miles per gallon\rparen}[/tex]

I need help with the calculus portion of my ACT prep guide

Answers

The first thing we have to do is find the pascal coefficients of the triangle for this we use the following image

From our exercise we know that

[tex]\begin{gathered} (2x^3-3y)^3\to(a+b)^3 \\ a=2x^3 \\ b=-3y \end{gathered}[/tex]

Then our coefficients of Pascal's triangle are 1 - 3 - 3 - 1

Using the right triangle we get:

[tex]1a^3+3a^2b+3ab^2+1b^3[/tex]

We substitute the values of a and b in our new expression to find our solution

[tex]1(2x^3)^3+3(2x^3)^2(-3y)+3(2x^3)(-3y)^2+1(-3y)^3[/tex][tex]\begin{gathered} 8x^9+3(4x^6)^{}(-3y)+3(2x^3)(9y^2)^{}-27y^3 \\ 8x^9-36x^6y+54x^3y^2-27y^3 \end{gathered}[/tex]

So the solution is:

[tex]8x^9-36x^6y+54x^3y^2-27y^3[/tex]

what are the bounds of integration for the first integral ?

Answers

We are going to use the properties of definite integrals. Note that if c belongs to the interval [a,b] and is integrable in [a,c] and [c,b], then f is integrable in [a,b]. Moreover,

[tex]\int_a^cf(x)dx+\int_c^bf(x)dx=\int_a^bf(x)dx[/tex]

Applying this property to the presented case, we obtain that

[tex]\begin{gathered} \int_a^bf(x)dx=\int_{-5}^9f(x)dx+\int_9^{13}f(x)dx-\int_{-5}^2f(x)dx \\ \int_a^bf(x)dx=\int_{-5}^{13}f(x)dx-\int_{-5}^2f(x)dx \\ \int_a^bf(x)dx=\int_2^{13}f(x)dx \end{gathered}[/tex]

Note: Another way to interpret the exercise is to interpret the integral as the area under the curve.

Thus, the answer to the exercise is a= 2 and b = 13.

A) This graph represents Function or non function?B) is it discrete or Continuous?Because of you count dots or measure lines?The domain is:The range is:

Answers

A) It's a function because each point of x has a point on y.

B. It's a discrete functions because you can't see a continuous line.

C. Domain (-3,6)

D. Range (0,3)

* C and D if each square is equivalent to 1 unit.

Find the equation of a line perpendicular to y + 1 =-1/2xthat passesthrough the point (-8, 7).

Answers

step 1

Find out the slope of the given line

we have

y+1=-(1/2)x

The slope is m=-1/2

Remember that

If two lines are perpendicular

then

their slopes are negative reciprocal

so

The slope of the perpendicular line is

m=2

step 2

Find out the equation of the line in slope-intercept form

y=mx+b

we have

m=2

point (-8,7)

substitute and solve for b

7=2(-8)+b

7=-16+b

b=23

therefore

the equation of the line is

y=2x+23

Given v=7i - 5j and w=-i+j,a. Find project wv .b. Decompose v into two vectors V, and v2, where vy is parallel to w and v2 is orthogonal to w.

Answers

For the given vector  v=7i - 5j and w=-i+j,

        projwv =  6i - 6j

                   v1 = 6i -6j

                     v2 = i +j

Vector:

              A quantity that has both magnitude and direction are called vector. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude.

           

a) projwv is the projection of v onto w. Use the following equation:

projwv = [(v•w)/((magnitude(w))2)] w

v•w = (7*-1) + (-5*1) = -12

(magnitude w)^2 = ([tex]\sqrt{1^{2} + 1^{2}}[/tex])^2 = 2

projwv = ((-12)/2)(-i + j)

            =  6i - 6j

b) The two components of the decomposed v will add to create the original vector v. v1 that is parallel to w will be the same as the projection of v onto w.

v = v1 + v2

v2 = v - v1 = (7i - 5j) - (6i -6j) = i +j

You can check that v2 is orthogonal by taking the dot product (v2•w). This equals 0.

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PLEASE HELP!!!

As part of a major renovation at the beginning of the year, Atiase Pharmaceuticals, Incorporated, sold shelving units (recorded as Equipment) that were 10 years old for $800 cash. The shelves originally cost $6,400 and had been depreciated on a straight-line basis over an estimated useful life of 10 years with an estimated residual value of $400.


2. Prepare the journal entry to record the sale of the shelving units. (If no entry is required for a transaction/event, select "No Journal Entry Required" in the first account field. Do not round intermediate calculations.)


(4 accounts)

Answers

Therefore, the total asset account balance is $400 and total liabilities and stockholders’ equity balance is $400.

Given,

The selling cost of shelving units that are 10 years old = $800

Original cost of shelving units = $6400

Estimated residual value for 10 years = $400

Assets = Liabilities +Stockholders equity

Calculate the accumulated depreciation for 10 years;-

Accumulated depreciation for 10 years=[(Original cost of the equipment-Residual value) / Useful life] ×10 years

=[($6400-$400)/10 years]×10 years

=$600×10 years

=$6000

Calculate book value of equipment.

Book value equipment=Original cost of the equipment-Accumulated depreciation for 10 years

=$6400-$6000

=$400

Calculate gain on sale of equipment.

Gain on equipment sale equals selling price minus book value of equipment

=$800-$400

=$400

Therefore, the total asset account balance is $400 and total liabilities and stockholders’ equity balance is $400.

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use a unit rate to find the unknown value.2/4=?/16the unknown value is?

Answers

Let x be the unknown value.

Therefore we have

[tex]\frac{2}{4}=\frac{x}{16}[/tex]

So we can inform from the first term that the denominator is double the numerator, since this term is equal to second term with the unknown x, same applies there also.

So,

[tex]\begin{gathered} 2x=16 \\ x=\frac{16}{2}=8 \end{gathered}[/tex]

This can be further confirmed by applying cross multiplication,

[tex]\begin{gathered} \frac{2}{4}=\frac{x}{16} \\ 16\times2=4x \\ x=\frac{16\times2}{4}=8 \end{gathered}[/tex]

The function c(x) = 50x represents the number of words c(x) you can type in x minutes. How many words can you type in 6.5 minutes? PLEASE HELP!

Answers

Given the function c(x) = 50x where c (x) is the number of words. In 6.5 minutes, the number of words that can be typed is

= 50 * 6.5

= 325 words

what degree are vertical angles?

Answers

Vertical angles are opposite angles that also are congruent angles.

Then, due to the given figure, you can conclude that the vertical angles are:

angle FGD and angle of 15° are vertical, then

Using the figure, determine the length, in units, of LM

Answers

Given the coordinates of L and M

To get the length between the two coordinates, we will follow the steps below

Step 1: List out the coordinates of L and M

[tex]L(-4,-3)[/tex]

[tex]M(-4,4)[/tex]

step 2: calculate the distance

Since they both have the same x coordinates, we can simply subtract the y-coordinate of L from M

[tex]M-L=4-(-3)=4+3=7[/tex]

Therefore, the distance LM is 7 units

what would be the most appropriate domain for this function? Number 7

Answers

Explanation:

This function is C(n) which means it's a function of n. It is said that n is the number of observed vehicles in a specified time interval. It cannot be negative and it has to be an integer. Therefore the domain is all integers greater or equal than zero.

Answer:

4) {0, 1, 2, 3...}

What is the x-value of the solution to the system of equations shown below? 2x + y = 20 6x - 5y = 12

Answers

Given the equation system:

[tex]\begin{gathered} 1)2x+y=20 \\ 2)6x-5y=12 \end{gathered}[/tex]

To solve the system and determine the value of x, first step is to write one of the equations in terms of y:

[tex]\begin{gathered} 2x+y=20 \\ y=20-2x \end{gathered}[/tex]

Then replace this expression in the second equation

[tex]\begin{gathered} 6x-5y=12 \\ 6x-5(20-2x)=12 \end{gathered}[/tex]

Now that you have an expression with only one unknown, x, you can calculate its value.

Solve the parenthesis using the distributive property of multiplication

[tex]\begin{gathered} 6x-5\cdot20-5\cdot(-2x)=12 \\ 6x-100+10x=12 \\ 6x+10x-100=12 \\ 16x=12+100 \\ 16x=112 \\ \frac{16x}{16}=\frac{112}{16} \\ x=7 \end{gathered}[/tex]

State the equations and use the graph to determine where the 2 points intersect

Answers

EXPLANATION:

We are given an exponential function as shown below;

[tex]f(x)=2^x[/tex]

When shifted one unit right we have the following;

[tex]m(x)=2^{x-1}[/tex]

We also are given the quadratic function;

[tex]g(x)=x^2[/tex]

When shifted one unit right and one unit up, we would have;

[tex]n(x)=(x-1)^2+1[/tex]

The equations for both functions after the transformations would be;

[tex]\begin{gathered} m(x)=2^{x-1} \\ n(x)=(x-1)^2+1 \end{gathered}[/tex]

The graphs of both equations is now shown below;

The two points where m(x) and n(x) intersect are;

[tex](1,1)\text{ and }(2,2)[/tex]

ANSWER:

[tex]\begin{gathered} (a)\text{ }m(x)=2^{x-1} \\ n(x)=(x-1)^2+1 \\ (b)\text{ }(1,1),(2,2) \end{gathered}[/tex]

The locations of student desks are mapped using a coordinate plane where the origin represents the center of the classroom. Maria's desk is located at (2, −1), and Monique's desk is located at (−2, 5). If each unit represents 1 foot, what is the distance from Maria's desk to Monique's desk?

square root of 10 feet
square root of 20 feet
square root of 52 feet
square root of 104 feet

Answers

Answer:

√52 feet

Step-by-step explanation:

5 - -1 = 6

-2 - 2 = -4

6 = change in y

-4 = change in x

a² + b² = c² (pythagoras theorem)

6² = 36

-4² = 16

36 + 16 = 52

c² = 52

c = √52

Answer: square root of 52 feet

(r^2/s)^3 Simplify this exponential expression

Answers

Answer:  (r^6)/(s^3)

Reason:

When we cube the (r^2) in the numerator, we're multiplying it by itself 3 times

(r^2)^3 = (r^2)*(r^2)*(r^2) = r^(2+2+2) = r^6

or a shortcut is to say

(r^2)^3 = r^(2*3) = r^6

That explains how we get r^6 in the numerator of the final answer.

The s^3 in the denominator is simply the result of cubing the 's' in the original expression.

Answer:

r2x3 / s1x3

Step-by-step explanation:

Raise both the numerator and denominator to the third power. Multiply by the exponents in the numerator (2x3). Multiply the exponents in the denominator (1x3). PF.

5. Given the degree and zeros of a polynomial function, find the standard form of the polynomial.

Degree: 5; zero: 1, i, 1+i

The expanded polynomial is:

x5 +
x4+
x3 +
x2 +
x +

Answers

The equation of the polynomial equation in standard form is P(x) = x⁵ -3x⁴ + 5x³ -5x² + 4x - 2

How to determine the polynomial expression in standard form?

The given parameters are

Degree = 5

Zero = 1, i, 1 + i

There are complex numbers in the above zeros

This means that, the other zeros are

Zeros = 1 - i and -i

The equation of the polynomial is then calculated as

P(x) = Leading coefficient * (x - zero)^multiplicity

So, we have

P(x) = (x - 1) * (x - (1 + i)) * (x - (1 - i) * (x - (-i)) * (x - i)

This gives

P(x) = (x - 1) * (x - 1 - i) * (x - 1 + i) * (x² + 1)

Solving further, we have

P(x) = (x - 1) * (x² - x + ix - x + 1 - i - ix + i + 1) * (x² + 1)

P(x) = (x - 1) * (x² - 2x + 2) * (x² + 1)

Evaluate the products)

P(x) = (x³  - x² + x - 1) * (x² - 2x + 2)

This gives

P(x) = x⁵ - 2x⁴ + 2x³ - x⁴ + 2x³ - 2x² + x³ - 2x² + 2x - x² + 2x - 2

Express in standard form

P(x) = x⁵ - 2x⁴ - x⁴ + 2x³  + 2x³ + x³ - 2x²  - 2x²  - x² + 2x + 2x - 2

Evaluate the like terms

P(x) = x⁵ -3x⁴ + 5x³ -5x² + 4x - 2

Hence, the equation is P(x) = x⁵ -3x⁴ + 5x³ -5x² + 4x - 2

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A recipe has a ratio of 6 cups of flour to 2 cups ofwater. There is cups of water for each cup offlour.

Answers

Given:

A recipe has a ratio of 6 cups of flour to 2 cups of water.

We need to find the number of cups of water for each cups of flour

So, let the number of cups of water = x

We have the following ratio:

[tex]\begin{gathered} \frac{x\text{ cups of water}}{1\text{ cup of flour}}=\frac{2\text{ cups of water}}{6\text{ cups of flour}} \\ \end{gathered}[/tex]

Solve for x:

[tex]x=\frac{2}{6}=\frac{1}{3}[/tex]

so, the answer will be:

There are 1/3 cups of water for each cup of flour.

A sequence is generated by An= -2n - 4, find the 5 terms of the sequence

Answers

William, this is the solution:

An= -2n - 4

A1 = -2 * 1 - 4

A1 = -6

A2 = -2 * 2 - 4

A2 = -4 - 4

A2 = -8

A3 = -2 * 3 - 4

A3 = -6 - 4

A3 = -10

A4 = -2 * 4 - 4

A4 = -8 - 4

A4 = - 12

A5 = -2 * 5 - 4

A5 = -10 - 4

A5 = - 14

Use properties to rewrite the given equation. Which equations have the same solution as 2.3p-10.1=6.5p-4-0.01p? Select two options

Answers

Given:

Given the equation

[tex]2.3p-10.1=6.5p-4-0.01p[/tex]

Required: Rewrite the given equation.

Explanation:

Take the common coefficients of p and add the constants.

[tex]\begin{gathered} 2.3p-10.1-6.5p+4+0.01p=0 \\ (2.3-6.5+0.01)p+(4-10.1)=0 \\ -4.19p-6.1=0 \\ 4.19p+6.1=0 \end{gathered}[/tex]

Final Answer: The given equation can be rewritten as 4.19p+6.1 = 0

4. What is 10% of 25? Type your answer using numbers only. Your answer

Answers

10% = 10/100 = 0.10

therefore:

[tex]25\times0.10=2.5[/tex]

answer: 2.5

5x + 3y = 9
can you put it the following equation in slope-intercept form?

Answers

[tex]\framebox{Slope intercept: -$\dfrac{5}{3}$x+3}[/tex]

The slope intercept form of  [tex]5x+3y=9[/tex] would be written as:

[tex]-\frac{5}{3} x+3[/tex]

I need help with this please thank you very much

Answers

So,

We can notice that the graph of g, is translated 2 units to the left and 4 units up. We can express these changes with the following equation:

[tex]g(x)=(x+2)^2+4[/tex]

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