Standard temperature andpressure (STP) is [?] K and[ ] átm.

In (E)‑3‑methyl‑2‑pentene, methyl group is attached in opposite side of the carbon that why it will be name as (E)‑3‑methyl‑2‑pentene.

The name of the given compound is (E)‑3‑methyl‑2‑pentene.

There are 5 carbon atom present in the compound. Methyl group is attached with C-2 and C-3 carbon atom in opposite direction

The structure of (E)‑3‑methyl‑2‑pentene is given as;

In the structure, it can be seen that methyl group is attached in opposite direction.

Trans molecule is named as E -compound.

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The question requires us to calculate the mass of a block, given its density (7.8 g/cm~3) and dimensions (length = 5.0 cm; width = 6.0 cm and height = 2.0 cm).

Considering that the volume of the block can be calculated following the basic formula for volume (volume = length x width x height), we can obtain the volume of the object from the dimensions given and then use the definition of density to calculate the mass from the density and volume of the block.

First, we'll calculate the volume of the block:

Next, we must consider the definition of density (mass per volume of an object) to calculate the mass of the block:

Therefore, the mass of the block is 468g.

Firstly what you need to know is that metallic bonds form in metallic substances. The elements that form these bonds are found on the left of the periodic table. So the metallic bonds form when the charge when the charge is spread over a wide distance when comparing to the size of the atom. These bonds occur between metals like zinc, and since they are in a form of solids, their atoms are tightly packed together.

The formation of metallic bonds occur because the metals exchange electrons, this electron exchange occur in different spatial directions.

Number 43:

Please look at the next drawing:

Answer: b. upper right

To find the concentration we can do it in terms of molarity. Molarity is a way of expressing the concentration of a solute in a solution, it is expressed with the term M and can be described by the following equation:

So first we must find the moles of NaCl present in 1.00 grams, the moles of NaCl will be:

So, the molarity of the solution will be:

Answer: The concentration of the solution in molarity will be 0.17M

Since water cycle is a multi-process cycle, the best option that describes and summarize all the cycle, will be letter C, in which we have water moving from the surface of the Earth to the sky and back again as rain, and then back to the sky again as water vapor.

Answer:

(C) A process by which water moves from Earth's surface into the sky and back again

Explanation:

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The new volume of the balloon if 0.530 grams of He are added to the balloon is 1.16 L

The number of moles of helium added is determined as follows:

The final volume of the balloon if 0.20 moles of gas are added will be 1.62 L.

Moles = mass / molar mas

molar mass of helium = 4 g/mol

Moles fo helium added = 0.530 / 4

moles of helium added = 0.1325 moles

The final volume is determined using the ideal gas equation as follows:

PV = nRT

Where;

Initial volume, V₁ = 0.50 L

Initial mole of gas, n₁ = 2.50 mol

With pressure and temperature held constant:

Final moles of gas, n₂ = 0.100 + 0.1325

n₂ = 0.2325 mols

Final volume, V₂ = n₂ * V₁ / n₁

V₂ =  0.2325 * 0.5 / 0.1

V₂ = 1.16 L

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Answer:

Explanation:

Sodium oxide is an inorganic compound that has sodium and oxygen as its constituent

Majorly, its applications include in the ceramic industry and also aerounautical applications (for making light weight parts of air crafts)

So what exact properties of this oxide conform these properties?

The property here is that it is insoluble in water and other aqueous solutions

Furthermore, due to its ionic conductivity property, it finds use in applications like in the making of fuel cells.

0.96moles

Given the reaction between Magnessium and silver nitrate expressed as:

Given the following parameter

Moles of Magnessium at the start = 0.480moles

According to stoichiometry, 1mole of magnessium produce 2 moles of silver. Hence the moles of silver that is produced if 0.48moles of Mg reacted is given as:

Hence the moles of silver that will produced is 0.96moles

Answer:

A

Explanation:

There are many definitions, and all of them are organic under some definition. The answer is probably A because it is the only one without hydrogen, and sometimes molecules without hydrogen are counted as being inorganic. A is CCl2F2, which is comprised of two chlorine atoms, two fluorine atoms, and a carbon atom.

0.0000253moles

The decomposition of NI3 is given as shown below;

Given the following parameters

Mass of NI3 = 0.02 grams

Determine the moles of NI3

Acoording to stochiometry, 2 moles of NI3 preoduces 1 mole of nitrogen. The mole of nitrogen produced is;

Hence the moles of nitrogen produced is 0.0000253moles

Answer:

A

Explanation:

The molecule is an amino acid which is used to make proteins, so it is an organic molecule.

It has a double bond between c=o

and single bonds throughout the molecule

Hope this helps!

From the question given, we are to convert -4⁰F to K

The standard value of ⁰F to K is

1⁰F = 255.93K

-4⁰F = x

Let's solve for -4⁰F

From the calculations above, -4⁰F is equal to 253.15K

1) Find the formula mass of Al2O3.

Aluminum mass: 26.982 u.

Oxygen mass: 15.999 u.

Al2O3 mass = 2 * (26.982 u) + 3 * (15.999 u)

Al2O3 mass = 101.961 u.

2) Aluminum percentage.

Aluminum mass: 26.982 u.

Al2O3 mass = 101.961 u.

Moving the decimal point.

52.93%

The percentage of aluminum is 52.93%

3) Oxygen percentage.

Oxygen mass: 15.999 u.

Al2O3 mass = 101.961 u.

Moving the decimal point.

47.07%

The percentage of oxygen is 47.07%.

.

Significant figures correspond to the number of digits that a number contains. Zeros at the beginning and end of the number are not counted, only zeros are counted if they are in an intermediate position.

For this case, the number is written in scientific notation, the corresponding 10 of the scientific notation is not taken into account during the digit count, therefore the significant figures of this number will be:

Answer: In 5.9 x10^4 there are 2 significant figures.

Its volume will be 12-fold.

From the Ideal Gas formula we know that:

- P is the pressure os the gas.

- V is the volume of the gas.

- T is the temperature of the gas.

So, we can replace the hypothetical values to calculate the volume of the gas:

Finally, its volume will be 12-fold.

Answer:

a.) 8 moles of carbon monoxide (CO).

b.) 20 moles of carbon monoxide (CO)

c.) C is the limiting reactant.

d.) The theoretical yield of CO would be 8 moles.

Explanation:

Let's write the chemical equation:

a.) You can see that 5 moles of carbon (C) reacted produces 4 moles of carbon monoxide (CO), so if we want to know how many moles of carbon monoxide can be produced, we can multiply each coefficient in the chemical equation by 2 (because we will have 10 moles of carbon):

The answer is that we will produce 8 moles of carbon monoxide (CO) by 10 moles of carbon (C).

b.) We can apply the same logic to this case. In the chemical equation, we have 2 moles of sulfur dioxide (SO2) reacted that produces 4 moles of carbon monoxide (CO), so if we want to know how many moles of carbon monoxide can be produced, we can multiply each coefficient by 5 so we will have 10 moles of sulfur dioxide:

The answer is that we will produce 20 moles of carbon monoxide (CO) by 10 moles of sulfur dioxide (SO2).

c.) We have already known that 10 moles of C will produce 8 moles of CO, and 10 moles of SO2 will produce 20 moles of CO. If we react 10 moles of C and 10 moles of SO2, you can note that we're going to have an excess of SO2 because we don't have enough amount of C to produce 20 moles of CO as SO2 do. So based on this logic, C is being consumed first and C would be the limiting reactant.

d.) Remember that the theoretical yield indicates the amount of a product obtained in a chemical reaction.

As we saw before, C is the limiting reactant if we react 10 moles of each reactant, so we have already known that 10 moles of C reacted produces 8 moles of CO, so the theoretical yield of CO would be 8 moles.

Hierro

El número de oxidación del hierro en el lado izquierdo de la reacción es +3 mientras que en el lado derecho está como hierro metálico, es decir su número de oxidación es 0

If the question is asking us to find the element based on the quantum numbers of the last electron, we have these informations:

n = 4

l = 1

m = +1

s = -1/2

n represents the shell or level value, this value will generally go from 1 to 7, and since our value is 4, we are talking about an element whose valence shell is 4, so this element is in the 4th period

l represents the value of the orbital, this value can range from 0 to 3,

0 is the s orbital

1 is the p orbital

2 the d orbital

3 = f orbital

In out question we have l = 1, therefore the last electron of this element is in the p orbital and in the 4th period, now we are down to 6 elements, Gallium, Germanium, Arsenic, Selenium, Bromine and Krypton, all 6 elements are in the 4th period and have the p orbital as its last one

m represents the location of the electron within the orbitals, each orbital can hold 2 electrons only, p orbitals can hold 6 electrons in 3 pairs of 2, and the m value represents in which orbital the electron is, for l = 1, m can be -1, 0, +1

and in our question we have m = +1, therefore the electron is located in the last orbital, it can only be the 3rd electron or the 6th electron now, and now we are down to Arsenic and Krypton

s is the spin value of the electron, this value will tell us if the electron is pointing upwards or downwards in the orbital, this value can only be +1/2 (upwards) and -1/2 (downwards), and in our question, we have -1/2, which is the last electron of the orbital

Based on all that information, we conclude that this element is Krypton, with 36 of atomic number and electron configuration of [Ar]3d10 4s2 4p6

Answer: 0.276g of H2 could be obtained from the reaction, considering the mass of reactants given

Explanation:

The question requires us to determine the amount of hydrogen gas (H2) that would be obtained when 10.0g of metallic magnesium (Mg) and 10.0g of chloridric acid (HCl) are reacted.

The following unbalanced chemical equation was provided:

To solve this problem, we'll need:

1) obtain the balanced chemical equation;

2) determine the limiting reactant considering the amount of reactants used and the stoichiometry of the reaction;

3) calculate the mass of hydrogen gas produced, considering the limiting reactant

1) Balancing the chemical equation

From the unbalaced chemical equation, we can see that there is the same amount of Mg on both sides of the equation, but we need to adjust the amount of H and Cl atoms.

There are 2 Cl atoms and 2 H atoms on the right side, and 1 Cl and 1 H atom on the left side, thus we can adjust the coefficient of HCl from 1 to 2 to adjust these elements. The balanced chemical equation can be written as:

2) Determining the limiting reactant

Now that we know the balanced chemical equation, we can say that 2 moles of HCl are necessary to react with 1 mol of Mg. Thus, we can write:

1 mol Mg ----------------------- 2 mol HCl

From this stoichiometric relation, we can calculate the amount of HCl that would be necessary to react with 10.0 g of Mg.

First, let's determine the amount of moles of Mg contained in 10.0g of this metal and the number of moles of HCl in 10.0g of this acid:

(the atomic mass of Mg is 24.31 amu, which is numerically identical to its molar mass, 24.31 g/mol, and the molar mass of HCl is 36.4g g/mol)

Therefore, 0.411 moles of Mg and 0.274 moles of HCl were used in the reaction.

Next, we can determine how many moles of HCl would be necessary to react with 0.411 moles of Mg:

1 mol Mg ----------------------- 2 mol HCl

0.411 mol Mg ----------------- x

Solving for x, we have that 0.822 moles of HCl would be necessary to react with the given amount of Mg. Since the amount actually used of HCl (0.274 mol) is smaller than the necessary amount, we can say that HCl is the limiting reactant.

3) Calculating the mass of H2 obtained

Using the limiting reactant and the stoichiometry of the reaction, we can determine the amount of H2 that could be produced.

From the balanced chemical equation, we know that 2 moles of HCl are necessary to produce 1 mol of H2. Thus, we can write:

2 mol HCl ------------------- 1 mol H2

0.274 mol HCl ------------ y

Solving for y, we have that 0.137 moles of H2 would be obtained.

We can convert the number of moles of H2 to its correspondent mass as it follows (the molar mass of H2 is 2.016 g/mol):

Therefore, 0.276g of H2 could be obtained from the reaction, considering the mass of reactants given.

Step 1

The reaction:

N2(g) + 3H2(g) → 2NH3(g) (balanced and completed)

All gases are assumed to be ideal and to be at STP conditions.

----------------

Step 2

STP conditions:

1 mole of gas = 22.4 L

----------------

Step 3

Information provided:

7 L of NH3 produced (ammonia)

Procedure:

By stoichiometry,

1 mole H2 = 22.4 L

1 mole NH3 = 22.4 L

N2(g) + 3H2(g) → 2NH3(g)

3 x 22.4 L H2 -------- 2 x 22.4 L NH3

X -------- 7 L NH3

X = 7 L NH3 x 3 x 22.4 L H2/2 x 22.4 L NH3 = 10.5 L

Answer: 10.5 L of H2 are consumed.

ANSWER

Weak acid ------ option B

EXPLANATION

Acid is divided in strong and weak acid

Generally, acid can be defined as a substance that will produce hydrogen ions as the only positive ions when dissolved in water.

Strong acid will dissolved completely in water to give hydrogen ions. Example of a strong acid is Hydrogen

Weak acid will dissolved partially in water to give hydrogen ions

Hence, a compound that will give only few of its molecules to produce hydrogen ions when dissolved in water is called a weak acid

Therefore, the correct answer is weak acid

A diol molecule is a compound that contains two Hydroxyl groups (OH), and these hydroxyl groups are attached to a hydrocarbon chain, which makes the main chain of the compound. In this type of molecule, we can find two intermolecular forces

Between the Carbons and Hydrogens in the hydrocarbon chain we have a Van der Waals force, which is a weak force

In the Hydroxyl groups, we will have a Hydrogen bond, which will be connecting Hydrogens and Oxygens

The displacement reaction is given as; [tex]2FeCl_{3} + 3Ba(OH)_{2} ----- > 2Fe(OH)_{2} (s) +3 BaCl2[/tex]. We can see that a precipitate was obtained in the reaction.

We know that a displacement reaction is a reaction that involves the combination of two compounds in which there is a kind of exchange between the reactants. We know in this case that this is a double replacement reaction. The anions that are in the system would exchange partners in the products.

Let us now look at the reaction and try to see how to be able to obtain the reaction. One more time the reaction is going to occur between the aqueous solutions of iron III chloride and barium hydroxide. We must recall that the insoluble product is iron III hydroxide.

We know that the product that is observed is a solid and an aqueous products from the reaction.

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We have a solution that pH = 2

We can use this relation which says:

pH + pOH = 14

If we clear pOH from here:

pOH = 14 - pH = 14 - 2 = 12

So, pOH = 12 and pOH could be calculated as:

pOH = - log [OH-] => we clear [OH-] from this,

10^(-pOH) = [OH-] => 10^(-12) = [OH-] => 1x10^-11 mol/L = [OH-]

(mol/L is generally the unit for [OH-])

Answer: [OH-] = 1x10^-11 mol/L

Question 16:

We are given the following balanced equation: (Remember to always balance the equation)

We are also told that Mg(OH)2 is in excess, meaning HNO3 is the limiting reactant, we will use its moles to find the number of moles of Mg(NO3)2, then we can convert that to mass.

The ratio between HNO3 and Mg(NO3)2 is 2:1

Therefore the number of moles of Mg(NO3)2 = 8.00 mol x (1/2) = 4.00 mol

Now we can convert the number of moles of Mg(NO3)2 to mass: molar mass of Mg(NO3)2 = 148,3 g/mol

So the mol will cancel the mol, then you will be left with g.

Step 1

It is known that the rate law can be written as follows:

Given the reaction: X + Y => Products (completed and balanced), the rate of the reaction would be:

k = rate constant

[X] = concentration of reactant X

[Y] = concentration of reactant Y

a, b = are the order of the reaction with respect to X and Y (they are not necessarily the coefficients of the reaction)

---------

Step 2

Information provided:

k

First order in A

Zero order in B

Second order in C

Therefore, the rate law:

Answer:

The factors that affect electronegativity is Number of electrons and atomic radius. Option A

The term electronegativity has to do with the the bonding situation between two atoms. In this situation, the electrons of the bond would be closer to one of the atoms than the other. In that case, there would be an unequal sharing of the electrons.

There are several facts that affect the electronegativity of an atom and these are the things that determine how electronegative that any particular atom would be.

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The silver produced is 7.77 g.

Given

Mass of Cu (copper) = 1.72 g.

Mass of AgNO3 (silver nitrate) = 12.33 g.

Molar mass of Cu = 63.5 g/mol.

Molar mass of AgNO3 = 170 g/mol.

Molar mass of Ag = 108 g/mol.

Step-by-step solution:

Cu + 2AgNO₃ --> Cu(NO₃)₂ + 2 Ag

First, let's state the chemical equation with copper (Cu) and silver nitrate (AgNO3) reacting:

1.72 g Cu . [tex]\frac{1 mol Cu}{63.5 g Cu}[/tex] = 0.027 moles of Cu

12.33 g AgNO₃ . [tex]\frac{1 mol AgNO_{3} }{170 g AgNO_{3} }[/tex] = 0.072 moles of Ag

Now, let's find the number of moles of each reactant using their molar mass:

0.027 moles Cu . [tex]\frac{2 moles Ag}{1 mol Cu}[/tex]  =  0.054 moles Ag.

Now, let's see how many moles of Ag are being produced based on the number of moles that we found in each reactant. By doing this calculation, we will find the limiting reactant.

You can see in the chemical equation that 1 mol of Cu reacted, produces 2 moles of Ag, so the moles of Ag produced are:

And you can see that moles of AgNO₃ reacts, produces 2 moles of Ag too. This means that the molar ratio between them is 2, more simply sis 1:1. This is telling u that 0.072 moles of AgNO₃ will produce 0.0072 moles of Ag too.

In this case, as you can see the limiting reactant is AgNO₃ because this is being consumed first in the reaction, so the final step is to find the mass using its molar mass. The conversion from 0.0072 moles of Ag to mass in grams is:

0.072 mol Ag . [tex]\frac{108 g Ag}{1 mol Ag}[/tex] = 7.77

The silver that is produced by 0.0072 moles is 7.77 g of Ag (silver).

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The answer is 6.5x10^5

Coefficient = 6.5

Exponent = 5