Answer:
Explanation:
Given:
m₁ = 3 000 kg
m₂ = 2 500 kg
F = 0.004 N
___________
r - ?
F = G·m₁·m₂ / r²
r = √ (G·m₁·m₂ / F)
r = √ (6.67·10⁻¹¹·3000*2500 / 0.004) ≈ 0.35 m
art a a long, straight, vertical wire carries a current upward. due east of this wire, in what direction does the magnetic field point?
The direction does magnetic field point will be in the direction of east
According to Fleming’s left-hand rule, if the thumb, middle finger, and index finger represent the direction of magnetic force, the direction of the current, and the direction of the magnetuc field, so if a conductor placed in between a magnetic field will experience a Magnetic force on it.So since the direction of the current is given in the direction upward which is the north direction, according to the rule the direction of the magnetic will point to the east direction.
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8) The weight of a pony standing still on Earth is 1025N.
What is the pony's mass?
A)
m=
g
g
1025 N
9.8 m/s²
JP
C) Where will the pony weigh the least (Moon, Jupiter, impossible)?
pick one of these three
D) Where will the pony have less mass (Moon, Jupiter, impossible)?
pick one of these three
Explanation:
mass = newton ÷ g
m = 1025 ÷ 10
mass= 102.5kg
The formula shown below is used to calculate the energy released when a specific quantity of fuel is burned. What is the missing factor?
Q = m c Δt is the formula used to determine the energy released when a certain amount of fuel is burned.
To calculate the amount of energy required to raise the temperature of a known mass of a substance, we can use the specific heat formula:
Q = m × c × ΔT
In the formula for specific heat, the letters Q, m, c, and ΔT stand for the quantities that represent the energy transferred in joules, the mass of the substances in kilograms, the specific heat capacity in J/kg degrees C, and the change in temperature in degrees Celsius respectively.
Distinct materials have different relationships between heat energy and temperature, and the term "specific heat" summarizes how these relationships play out. When heat energy is delivered to a substance, its temperature will vary by a certain amount.
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Describe where microwaves are found on the ems compared to the other six forms of radiation.
On the EMS microwaves fall between radio waves and infrared radiations.
Electromagnetic radiation, which travels through space and conveys electromagnetic radiant energy, makes up electromagnetic radiation.
EMS consists of
radio waves, microwaves, infrared radiations, visible light, ultraviolet radiations, X-rays, gamma rays.These waves are all components of the electromagnetic spectrum. Electromagnetic waves are synchronized oscillations of the electric and magnetic fields that make up electromagnetic radiation in a classic way. Due to the periodic alteration of the electric or magnetic field, electromagnetic radiation or waves are produced. Different wavelengths of the electromagnetic spectrum are created depending on the manner in which this periodic change takes place and the power generated. Electromagnetic waves move at the speed of light, in a vacuum.
An image is attached for further clarification.
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Please help me complete. The second picture is the options you have to choose from from each
This drawing helps us understand the contribution of each the magnetic field of each wire. Wire 1 will contribute with positive field for everything on its left, and with negative field for everything on its right. The opposite is true for wire 2, so, if we analyse regions I, II and III:
Region I: Wire 1 contributes with positive and Wire 2 contributes with negative. As any point on region I will be closer to Wire 1, its contribution will be more significant, and the field will be positive
Region II: Wire 1 and 2 contribute with negative field. Thus, the resulting field will be negative
Region III: Wire 1 contributes with negative field and Wire 2 contributes with positive field. As any point on region III will be closer to Wire 2, its contribution will be more significant, and the field will be positive.
Now all we have to do is calculate the value of the fields. The field on point P1 will have positive contribution from Wire 2 and negative contribution from Wire 1, which will be:
[tex]P1=\frac{\mu_0*I}{2\pi d}-\frac{\mu_0*I}{2\pi(2d)}=\frac{4\pi *10^{-7}}{2\pi *11.4*10^{-2}}-\frac{4\pi *10^{-7}}{4\pi *11.4*10^{-2}}=0.8772\mu T[/tex]The field on the midpoint (distance d/2 from each wire) will be negative, as the contribution from both wires will be negative, thus:
[tex]P_{med}=-2*\frac{4\pi *10^{-7}*5.4}{2\pi *(\frac{11.4}{2})*10^{-2}}=-37.8947\mu T[/tex]The field on point P2 will be positive, which can be written as:
[tex]P2=\frac{\mu_0I}{2\pi *2d}-\frac{\mu_0I}{2\pi *(3d)}=\frac{4\pi *10^{-7}*5.4}{2\pi *(2*11.4*10^{-2})}-\frac{4\pi *10^{-7}*5.4}{2\pi *(3*11.4*10^{-2})}[/tex][tex]P2=1.5789\mu T[/tex]Summary:
a) Pmed = -37.8947uT into the screen
b) P1 = 0.8772uT out of the screen
c) P2 = 1.5789uT out of the screen
Frosted glass is made of glass with a scratched surface. Decide whether frosted glass is opaque, translucent,or transparent and explain your reasoning.
Frosted glass is made of glass with a scratched surface and it is translucent because of its partial transparency.
Why is translucent glass frosted glass?Technically speaking, frosted glass is a transparent sheet of glass that has been etched or sandblasted to become opaque. The glass appears translucent as a result of light scattering during transmission, obstructing visibility even while light is transmitted through it.
Therefore, Translucent materials include certain polymers and frosted glass. Only a portion of the light that strikes transparent materials goes through. The materials prevent the light from passing through them directly.
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1. If a cart with a mass of 5 kg is accelerated at a rate of 12 m/s/s, then what is theNUMERICAL value for the force?
*The mass of the cart is
m=5 kg
*The acceleration is
[tex]undefined[/tex]Advanced Wireless Services (AWS) is a wireless telecommunications spectrum band used for mobile voice and data services, video, and messaging. The AWS band uses frequencies in several segments: from 1695 to 2200 MHz. a) Determine the corresponding range of wavelengths used by the AWS mobile devices. b) To what region/band of electromagnetic spectrum does the range belong
Given data
*The given frequency is
[tex]f_1_{}=1695\text{ MHz}=1695\times10^6\text{ Hz}[/tex]*The another given frequency is
[tex]f_2=2200\text{ MHz=}2200\times10^6\text{ Hz}[/tex]*The given speed of light is c = 3.0 × 10^8 m/s
(a)
The formula for the wavelength is given as
[tex]\lambda_1=\frac{c}{f_1}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} \lambda_1=\frac{(3\times10^8)}{(1695\times10^6)^{}} \\ =0.176\text{ m} \end{gathered}[/tex]The another wavelength for the another frequency is calculated as
[tex]\begin{gathered} \lambda_2=\frac{c}{f_2} \\ =\frac{(3.0\times10^8)}{(2200\times10^6)} \\ =0.136\text{ m} \end{gathered}[/tex](b)
Radio spectrum is an electromagnetic spectrum where the frequency range belongs of wireless telecommunication.
explain how the current would change if the amount of voltage increased, but resistance stayed the same. using ohms law
When the voltage in a circuit is increased, the current flowing in the circuit will also increase
How would I know what will happen to the current?Ohm's law states that the current flowing through a metallic conductor is directly proportional to the voltage provided all physical properties like resistance remains constant This is represented mathemathically as:
Voltage (V) = Current (I) × resistance (R)
V = IR
If R is constant, then
V₁ / I₁ = V₂ / I₂
Where
V₁ and V₂ are the initial and new voltageI₁ and I₂ are the initial and new currentNow, let us see what will happen to the current when we increase the initial voltage, say by a factor of 2. This is illustrated below:
Initial voltage (V₁) = V Initial current (I₁) = INew voltage (V₂) = 2VNew current (I₂) = ?V₁ / I₁ = V₂ / I₂
V / I = 2V / I₂
Cross multiply
V × I₂ = I × 2V
Divide both sides by V
I₂ = (I × 2V) / V
I₂ = I × 2
I₂ = 2I
Thus, we can see that the new current also increase by a factor of 2
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According to Loftus, why is the study of eyewitness memory important? Be sure to include a specific quotation from the excerpt above to support your explanation.
Do the Loftus studies support the use of eyewitness testimony as evidence? Be sure to include specific details from the studies to support your position.
Loftus thought that, to a certain extent, eye witness recollection was significant during a court case or prosecution. Eye witness memory, according to Loftus, is crucial since it provides a different perspective and gauges how reliable a witness's testimony is.
What is eyewitness memory?A person's memory of a particular occurrence, sometimes a crime or accident of some sort, that he or she directly witnessed or experienced. Given the occurrence of phenomena like the weapon-focus effect and the disinformation effect, the credibility of eyewitness evidence is a significant problem in forensic psychology.The law certainly cares about knowing something about the precision, completeness, and malleability of such memories, he said. So he doesn't entirely back the use of eye witness memory. This is so that, because an eyewitness's memory is "malleable," the prosecutor's tone of voice could persuade the witness to alter his or her statement.According to Loftus, eye witness recall is crucial since it provides a different viewpoint and gauges how reliable a witness's testimony is. It also gauges the degree to which it can be trusted. It is evident that the law is interested in learning more about the precision, completeness, and malleability of such memories." His assertion amply supports the significance of eye witness recall.To know more about eyewitness memory, visit:
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one example of these kinds of economic activities is ____
One very good example of kinds of economic activities simply is buying and selling goods.
How buying and selling of goods an an economic activitiesEconomics simply refers to the study of social science which human relationship in relationships with ends and and scarce means which have alternative uses.
However, economics from the description above also involves the buying and selling of goods or products. These selling of these goods is also a function of the quantity demanded.
In conclusion, we can now confirm and deduce from the explanation given above that we the quantity of goods demanded will determine its sales.
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a communication satellite orbits laurus in a circular trajectory at an altitude of 226 km. find the velocity of this satellite in km/s.
The velocity of the satellite is 2.44 x 10 ^16 km /s
Since we are given the attitude which is 226 km, we know the radius of the earth is =6,400 km, and the mass of the earth, M =6×1024 kg. The formula we refer to for calculating the velocity of the satellite is :
V = √.GM/(R+h), where G is the gravitational constant which is 6.67×1011N−m2G=6.67×1011N-m2/kg2kg2. , R is the radius and m is the mass and h is the height at which the satellite is situated.Therefore , substituitng the values we get,
= √ 6.67×1011 *6×1024/( 6,400+ 226 )
= √ 4.00 X10^36 /6626
=√6.00x 10^32
= 2.44 x 10 ^16 km /s
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A ball rolls off a cliff and falls for 4.5 s. What is the final vertical velocity of the ball? (Answer must be negative!!!)
Answer:
-199 m/s
Explanation:
Ignoring the horizontal velocity, the vertical velocity =
a *t a = -9.81 m/s^2
-9.81 ( 4.5^2) = - 199 m/s
A small child weighs 18 kg. If his mom left him sitting on top of the stairs, which are 10m high, how much energy does the child have?
Explanation:
Find an energy is E=mgh, so E=18*10*10=1800J
In the diagram, q1 = +8.60 x 10-6 C,92 +5.10 x 10-6 C, and q3 = -3.30 x 10-6 C.Find the magnitude of the net force on 92.0.350 m9192magnitude (N)0.155 m93(Make sure you know the direction of each force!Opposites attract, similar repel.)
Given:
• q1 = +8.60 x 10⁻⁶ C
,• q2 = +5.10 x 10⁻⁶ C.
,• q3 = -3.30 x 10⁻⁶ C.
,• d12 = 0.350 m
,• d23 = 0.155m
Let's find the magnitude of the net force on q2.
First find the force on the charge 1 and 2:
[tex]\begin{gathered} F_{12}=-\frac{kq_1q_2}{(d_{12})^2} \\ \\ F_{12}=-\frac{9\times10^9*8.60\times10^{-6}*5.10\times10^{-6}}{0.350^2} \\ \\ F_{12}=-3.22\text{ N} \end{gathered}[/tex]Also for the force on charge 2 and 3, we have:
[tex]\begin{gathered} F_{23}=\frac{kq_2q_3}{(d_{23})^2} \\ \\ F_{23}=\frac{9\times10^9*5.10\times10^{-6}*(3.30\times10^{-6})}{0.155^2} \\ \\ F_{23}=6.305\text{ N} \end{gathered}[/tex]Now, the magnitude of net force on q2 will be:
[tex]\begin{gathered} F_{net}=\sqrt{(F_{12})^2+(F_{23})^2} \\ \\ F_{net}=\sqrt{(-3.22)^2+6.305^2} \\ \\ F_{net}=\sqrt{10.38+39.75} \\ \\ F_{net}=\sqrt{50.13} \\ \\ F_{net}=7.08\text{ N} \end{gathered}[/tex]Therefore, the magnitude of the net force on q2 is 7.08 N.
• ANSWER:
7.08 N
A ball is kicked with a speed of 20 m/s at an angle of 15 degrees to the horizontal. With what vertical velocity was it kicked with?
Answer:
Explanation:
Given:
V₀ = 20 m/s
α = 15°
___________
Vy - ?
Vy = V₀·sin α = 20·sin 15° = 20·0.2588 ≈ 5.2 m/s
A 3.0kg cat and a 14kg dog exert a force of gravity on each other equal to 1.12 x 10^-10 N. how far apart are they
The expression for the gravitational force between two bodies is given by:
[tex]F=G\frac{m_1m_2}{r^2}[/tex]where,
G: Cavendish's constant = 6.67*10-11Nm^2/kg^2
m1 = 3.0kg
m2 = 14kg
Solve the equation above for r:
[tex]\begin{gathered} r=\sqrt{\frac{Gm_1m_2}{F}} \\ r=\sqrt[]{\frac{(6.67\cdot10^{-11}\frac{Nm^2}{\operatorname{kg}^2})(3.0kg)(14kg)}{10\cdot10^{-10}N}} \\ r\approx1.67m \end{gathered}[/tex]Hence, the distance between the dog and the car is approximately 1.67m
what is a frame of reference.....
Answer: A frame of reference is a set of criteria or stated values in relation to which measurements or judgements can be made. A reference point is an object that happens to be at rest. Given an example Car A and Car B are moving but without a reference you would not be able to know the car that is moving but with a signboard you can be able to tell which Car moved forward or backward.
Explanation:
Hope this was helpful
A 60.0 kg astronaut is on a spacewalk when the tether line to the shuttle breaks. The astronaut is able to throw a spare 10.0 kg oxygen tank in a direction away from the shuttle with a speed of 12.0 m/s, propelling the astronaut back to the shuttle. Assuming that the astronaut starts from rest with respect to the shuttle, find the astronaut’s final speed toward the shuttle after the tank is thrown.
Given,
m1 = Mass of Astronaut
m2= Mass of tank
v1 = Velocity of Astronaut
v2 = Velocity of tank
Concept used,
Explain what conservation of momentum is.According to the rule of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. based on the preservation of linear momentum.
m1.v1= m2.v2
v1= m2.v2/m1
= 10×12/60
= 2m/s
Distance = Speed × Time
= 2×60= 120m
So, the maximum distance she can travel is 120 m.
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How much energy is required to freeze 20 ml of water already at 0.0 0C?
Given
Amount of water,
[tex]m=20\text{ ml}[/tex]Temperature is,
[tex]T=0.00C[/tex]To find:
Energy required to freeze the water.
Explanation:
The latent heat of fusion is
[tex]L=33.5\times10^4\text{ J/}kg[/tex]Converting the amount of water to kg,
[tex]m=0.020kg[/tex]Thus the energy required is:
[tex]\begin{gathered} H=mL \\ \Rightarrow H=0.020\times33.5\times10^4=0.67\times10^4J \end{gathered}[/tex]Conclusion:
The amount of energy required is
[tex]0.67\times10^4J[/tex]The magnetic field of an electromagnetic wave moving in the z-direction is given by in si units. What is the maximum electric field strength?.
The maximum electric field strength is f=1.98×10⁵
The magnetic field of a plane-polarized electromagnetic wave moving in the z-direction is given by :
B=1.2×10⁶ sin[2π(Z/240-10⁷t/8)].....(1)
The general equation of the magnetic field wave is given by :
B=B°sin(kz-wt) ....(2)
Equation (1) is in form of equation (2), if we compare equations (1) and (2) we find that,
w=10⁷/8
We need to find the frequency of the wave. It is given by :
f=w/2π
f=10⁷/8×2π
f=1.98×10⁵ Hz
So, the frequency of the wave is f=1.98×10⁵ Hz.
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There are 16 ounces in a pound. Calculate the equivalent of a one ounce force in newtons.
The equivalent of a one ounce force in Newtons = 0.278N
What is an ounce in physics?Ounce is a unit of mass used in the imperial and US measurement systems. Shorthand: oz. A slice of bread weighs about the same as one ounce. The actual weight is 28.349523125 grammes. In some systems of measurement, such as English engineering units and British gravitational units, an ounce-force is a unit of force.
The ounce-force is equivalent to the force produced by a mass of one ounce in a typical gravitational field. Meanwhile, the SI-derived unit of force is the newton (N). It is equal to the force necessary to accelerate a mass of one kilograms at a rate of one meter per second squared, according to Newton's second law of motion. Consequently, 1 N = 1 kg/m/s2.
Given:
16 ounces in a pound
So, 1 ounce-force = 1/16 lbf ≈ 0.27801 N.
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full answer = brainliest
Answer:
F = 2N
Explanation:
Moment of 3.0N = 3 × (90 - 50)
3×40
= 120Ncm
Moment of 2.0N = 2.0 × 30
= 60Ncm
Value of F = F × 30
= 30F
60 + 30F = 120
30F = 120 - 60
30F/30 = 60/30
F = 2N
If you start with 500g of water in your pot, and after it boils away, the steam takes up 2 m3 of space, what is the density of the steam in g/m3?
Density of the steam will be 250 g/m³
What is density?Density (volumetric mass density or specific mass) is the mass of matter per unit volume. The most common symbol for density is ρ (lowercase Greek letter rho), but the Latin letter D can also be used. Mathematically, density is defined as:
Density = [tex]\frac{Mass}{Volume}[/tex]
Or ρ = [tex]\frac{m}{V}[/tex]
Where ρ = density, m = mass, and V = volume.
The density of matter changes with temperature and pressure. This variation is typically small for solids and liquids and much larger for gases. Increasing the pressure on an object decreases the volume of the object, thus increasing its density. Increasing the temperature of a substance (with some exceptions) increases its volume and decreases its density. In most materials, heating the bottom of the liquid causes convection of heat from the bottom to the top as the density of the heated liquid decreases, increasing the density compared to a denser, unheated material.
Given,
Mass of water evaporated = 500g
Volume of steam = 2m³
Density = [tex]\frac{500}{2}[/tex]
Density = 250 g/m³
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name three ways in which forces are created(Cpo Science book, 8th grade)
Answer:
he reason would be straightforward in case you have complete the test already. The bottles have a undeniable volume of air interior them.. you have often happening that gases do strengthen in case of heating.So, the air interior the bottle in sunlight expands.. often, in case you don't have an go out course for the air, it would desire to develop the stress interior the bottle or if is extra suitable than a undeniable decrease.It may blow up the bottle too. As u would desire to have considered some bicycle tires explode while saved below warm sunlight.Here, even with the undeniable fact that, we are offering an get away course for the air interior the bottle via keeping a balloon above.So the elevated air escapes into the balloon thereby swelling it.While the balloon saved below would not have a lot variations to observe. Its truly an straightforward test to do..
Explanation:
A student in track and field is running a hurdles race. The hurdles are 91.4 cm tall. The student is running with a horizontal velocity of 4.00 m/s and leaps with a vertical velocity of 9.00 m/s. If the student makes this leap 0.400 m before the hurdle, will they clear the hurdle?
No, they will not be able to clear the hurdle from the given distance of their leap.
What are the projectile motion?Projectile motion includes vertical and horizontal velocity components. It's important to understand that the two are independent of each other. But what is a projectile and what is a good example. Well, a projectile is an object that is thrown by applying a force that falls under gravity and is subject to the resistance of the medium in which it travels. It can be thrown into the air and fall under the influence of gravity.
First of all the time required to reach the hurdle is:
by using horizontal velocity we have time = [tex]\frac{distance}{speed}[/tex]
t = [tex]\frac{0.400}{4}[/tex]
t = 0.100s
Now for the vertical distance covered by student:
S = ut + [tex]\frac{1}{2}[/tex] gt²
S = 9 × 0.100 + [tex]\frac{1}{2}[/tex] 9.8 × 0.100²
S = 0.851m or 85.1cm
Since the distance calculated is less than the height of hurdles which is 91.4 cm so the student may not be able to clear the hurdle.
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A voltage of 12 V is applied across a circuit with one 3 0hm resistor in series and three 3 Ohm resistors in parallel. What is the total voltage drop in the first 3 Ohm resistor in the circuit? Select one:a. 3 Volts b. 9 Volts c. 36 Volts d. 6 VoltsThe total current is 3 A.
In order to calculate the voltage drop in a resistor, we can use the formula below:
[tex]V=I\cdot R[/tex]If the current passing through the resistor is 3 A and its resistance is 3 ohms, so the voltage drop is:
[tex]\begin{gathered} V=3\cdot3\\ \\ V=9\text{ Volts} \end{gathered}[/tex]Therefore the correct option is b.
The formula shown below is used to calculate the energy released when a specific quantity of fuel is burned. Calculate the energy released by a burning sample of fuel if the temperature of 100g of water was raised by 20°C. (Specific heat capacity of water = 4,200J/kg °C
The energy released by a burning sample of fuel is 8400 J.
The formula referenced in the question is:
Q = m.c.ΔT
where m is the mass of the water sample
c is the specific heat capacity of water
ΔT is the variation in temperature
Q is the thermal energy
According to the question,
c = 4,200 J/kg °C
ΔT = 20 °C
m = 100 g = 0.1 kg
On Solving, we put these values in the formula to evaluate the thermal energy,
Q = 0.1 * 4,200*20 = 8400 J
Thus, the energy released by a burning sample of fuel is 8400 J.
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4. Can you curl your tongue up on the sides? tongue-curling in humans is a dominant genetic trait. Suppose a man who is tt for tongue-curling marries a woman who is also tt for this trait. What are the possible genotypes and phenotypes of their children and the percent chance for each?.
The possible genotypes and phenotypes of their children and the percent chance for each is 0%.
The capacity to roll one's tongue outweighs the lack of capacity.The two people have the homozygous recessive character if the dominant allele is R and the recessive allele is r.This indicates that the organism's genotype will be "rr."If such people cross each other:
Parents X Parents
gamma r r
Children rr
That results in :
The genotype of the offspring will be homozygous recessive (rr) based on the genetic cross.Because they lack the dominant allele, the child will therefore be unable to roll their tongue.The possible genotypes and phenotypes of their children and the percent chance for each is 0%.
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When the mass of the cylinder increased from 3.0 kg to 6.0 kg, what happened to the amount of heat generated in the system? it decreased by a factor of 3. it decreased by a factor of 2. it increased by a factor of 2. it increased by a factor of 3.
Option c. It is increased by 2.
Heat generation that is thermal capacity of an object is dependent on mass. So if the mass of an object increases, the heat generation also increases.
How thermal capacity is related to mass?
Thermal capacity= mass × specific heat
As we can see by the formula, that the thermal capacity is directly proportional to mass. So if the mass of the object increases, so does the thermal capacity.
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The answer is C:
It increased by a factor of 2.