The number of protons, neutrons, and electrons in isolated ions having the following nuclear symbols:
a) ¹⁹F⁻ has 9 protons , 9 neutrons , 10 electrons
b) ²⁴Mg²⁺ 12 protons , 12 neutrons , 10 electrons
c) ⁵⁶Fe³⁺ 26 protons , 26 electrons , 23 electrons
The atomic number of element represent the number of protons present. the no. of electrons is equals to no. of protons for neutral. the difference between mass no. and the atomic no. is equals to the no. of neutrons.
a) The atomic number of Fluorine is 9. for neutral fluorine the no. of proton is 9 , no. of neutron is 9 , no. of electron is 9. negative sign represent one extra electron.
¹⁹F⁻ has 9 protons , 9 neutrons , 10 electrons
b) The atomic number of Mg is 12. + 2 represents that 2 electrons are removed from the neutral Mg.
²⁴Mg²⁺ 12 protons , 12 neutrons , 10 electrons
c) The atomic number of Fe is 26.
⁵⁶Fe³⁺ 26 protons , 26 electrons , 23 electrons
Thus, The number of protons, neutrons, and electrons in isolated ions having the following nuclear symbols:
a) ¹⁹F⁻ has 9 protons , 9 neutrons , 10 electrons
b) ²⁴Mg²⁺ 12 protons , 12 neutrons , 10 electrons
c) ⁵⁶Fe³⁺ 26 protons , 26 electrons , 23 electrons
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Which of these characteristics would most help a city make long-term road
and infrastructure plans?
O A. Age structure
OB. Birthrate
C. Growth rate
OD. Death rate
The characteristics that would help a city to be able to make long term infrastructural plans is the growth rate. Option C
What is infrastructure?The term infrastructure has to do with the facilities that are put up in a city to aide life in a city. It is the process of development in a city that helps a city to be able to aide the inhabitants to live a comfortable life.
It is very important to see that there is a laid down plan for the development of a city or a place and this is very essential to the development of the place and the better life of the people that live in the city.
Now, the infrastructural plans that are made in a city has to factor in the growth rate of the city and this have to be based on the projected growth rate.
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A mixture of krypton and neon gas is compressed from a volume of 79.0L to a volume of 71.0L, while the pressure is held constant at 17.0atm. Calculate the work done on the gas mixture. Round your answer to 2 significant digits, and be sure it has the correct sign (positive or negative).
Using the fact that:
[tex]W=P\Delta V[/tex]We could replace our values as follows:
[tex]\begin{gathered} W=17atm\cdot(71L-79L) \\ W=17atm\cdot(-8L) \\ W=-136J \end{gathered}[/tex]As you can see, the work done is negative since the gas is being compressed. Therefore,
The work done is -136J.
In kJ, the answer is -0.136kJ. Rounded to 2 significant digits, this is -0.14kJ
Calculate the [H+] given a pH of 2.80
Answer:
The [H+] is 1.6x10^-3 M.
Explanation:
1st) We can calculate the concentration of H+, using the pH formula:
[tex]\begin{gathered} pH=-log\lbrack H^+\rbrack \\ 2.80=-log\lbrack H^+\rbrack \\ 10^{(-2.80)}=\lbrack H^+\rbrack \\ 1.6*10^{-3}M=\lbrack H^+\rbrack \end{gathered}[/tex]So, the [H+] is 1.6x10^-3 M.
Which of the following statements is FALSE:O Density is a measure of how closely packed the atoms of a substance are.O The Density of a substance can change if its location changes.O The Density of steel is greater than the Density of cotton.O To calculate the Density of an object we must know its mass
Answer
The Density of a substance can change if its location changes.
Explanation
All the statements are TRUE except
The Density of a substance can change if its location changes.
This is because density is an intensive property, that is regardless of the object's shape, size, or quantity, the density of that substance will always be the same. Even if you cut the object into a million pieces, they would still each have the same density.
Therefore, the statement that is FALSE is
The Density of a substance can change if its location changes.
The options for this question are vaporizing, condensing, freezing, and melting but I’m not sure where to put them. If anyone could help it would be greatly appreciated
Physical states are different in compounds if we have a change of temperature or pressure, and in certain temperatures we can see a compound undergo a physical change, going from solid to liquid or gas, and the reverse is also possible, as we will see now:
If liquid is turning into solid, then we have a freezing situation
Liquid to solid will be known as melting
Gas to liquid will be known as condensing
Liquid to gas will be known as vaporizing
Nitrogen dioxide reacts with water to produce nitric acid and nitrogen monoxide. How many grams of nitric acid can be prepared from 95.52 grams of nitrogen dioxide?
87.22grams
Explanations:The chemical reaction between Nitrogen dioxide and water to produce nitric acid and nitrogen monoxide is expressed as:
[tex]3NO_2+H_2O\rightarrow2HNO_3+NO[/tex]Determine the moles of nitrogen dioxide(NO2)
[tex]\begin{gathered} mole=\frac{mass}{molar\text{ mass}} \\ mole=\frac{95.52}{46.0055} \\ mole\text{ of NO}_2=2.076moles \end{gathered}[/tex]According to stoichiometric ratio, 3 moles of nitrogen dioxide produces 2moles of nitric acid, the moles of nitric acid required is expressed as;
[tex]\begin{gathered} moles\text{ of }HNO_3=\frac{2}{3}\times2.076 \\ moles\text{ of }HNO_3=1.384moles \end{gathered}[/tex]Determine the mass of nitric acid
[tex]\begin{gathered} mass\text{ of HNO}_3=mole\times molar\text{ mass} \\ mass\text{ of HNO}_3=1.384\times63.01 \\ mass\text{ of HNO}_3=87.22grams \\ \end{gathered}[/tex]Hence the mass of nitric acid required is 87.22grams
An equilibrium mixture, at 529°C in a 1208-mL container, involving the chemical system
N2(g) + 3H2(g) == 2NH3(g)
is found to contain 3.62 g of N2, 0.773 g of H2, and 0.498 g of NH3. Calculate the equilibrium constant (Keq expressed in terms of the molar concentrations) at the given temperature.
The equilibrium constant at the given temperature is equal to 0.1677.
What is the equilibrium of a chemical reaction?The chemical equilibrium can be described as the state of a chemical reaction where the concentration of the reactants and products does not change with respect to time.
The balanced chemical equation of the formation of ammonia:
[tex]N_2+3H_2\leftrightarrows 2NH_3[/tex]
The mass of the nitrogen gas = 3.62 grams
The moles of nitrogen gas = 3.62/28 = 0.1293 mol
The concentration of the nitrogen gas = (0.1293/1208)× 1000 = 0.107 M
The mass of the hydrogen gas = 0.773 grams
The moles of hydrogen gas = 3.62/2 = 0.386 mol
The concentration of the hydrogen gas = (0.386/1208)× 1000 = 0.32 M
The mass of the ammonia = 0.498 grams
The moles of ammonia = 0.498/17 = 0.029 mol
The concentration of the ammonia = (0.029/1208)× 1000 = 0.024 M
The equilibrium constant: [tex]K_{eq} = \frac{[NH_3]^2}{[H_2]^3[N_2]}[/tex]
[tex]K_{eq} = \frac{[0.024]^2}{[0.107][0.32]^3}[/tex]
[tex]K_{eq} =0.1677[/tex]
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4. Calculate the pH of 0.90M HPO4?Ka HPO4^2- = 4.5 x 10-13(a) 7(b) 14(c) 12.3(d) 8.20(e) 6.20
Answer
Explanation
Given:
[H⁺] = 0.90 M
Ka HPO₄²⁻ = 4.5 x 10⁻¹³
what is functional group?write the functional group ofalcoholesteracid hydridealdehyde and mention an example of each compound containing these functional group
EXPLANATION:
A functional group is a collection of atoms within molecules that bind together to react in predictable ways.
The functional group tell us how a compound react and, also, the chemical properties of such compound
Below are the functional group of some compound
Alcohol
The functional group of alcohol is ---- OH
Example: Ethanol
Ester
The functional group of Ester is --O--
Example: Ethyl ethanoate
Aldehyde
The functional group of aldehyde is
Example: Vanillin
What type of model that is a smaller or larger copy of an
object and one that shows key features or interactions?
A. mathematical model
B. physical model
C. conceptual model
D. statistical model
A physical model is a replica that has been built that is intended to represent the original object. A physical model may be the same size as the real object it represents, smaller, or larger. A scale model is one that is either bigger or smaller than the real thing.
A physical model is a streamlined tangible depiction of an object or phenomenon that has to be studied, typically on a smaller scale.
The model can replicate the relevant physical factors (temperature, waves, speed, etc.) and forecast the unique limits of the circumstance. Before starting the last stages of a project, these constraints can be considered, tested, and solutions implemented.
Urban planning, naval construction, aeronautics, and other fields involving geometry, thermodynamics, and fluid mechanics frequently use physical models.
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What is the %v/v when 17.8mL is Acetic Acid is dissolved in 40.8mL of water?
Answer:
30.4 %.
Explanation:
Let's see the volume percentage (% v/v) formula:
[tex]Percent\text{ volume=}\frac{volume\text{ of solute}}{volume\text{ of solution}}\cdot100\text{ \%,}[/tex]in this case, the solute is acetic acid and the solution is the solute and solvent (which is water). Based on this logic, the volume of solute is 17.8 mL, whereas the volume of solution is the sum of the volumes of solute and solvent ( 17.8 mL + 40.8 mL = 58.6 mL), so we just have to replace the values that we have in the formula:
[tex]\begin{gathered} Percent\text{ volume=}\frac{17.8\text{ mL}}{58.6\text{ mL}}\cdot100\%, \\ \\ Percent\text{ volume=30.4\%.} \end{gathered}[/tex]The answer would be 30.4 %.
what type of bonding results from the force of attraction between positively and negatively charged ions?
ANSWER
Ionic bonding
EXPLANATION
Ionic bonding is also known as electrovalent bond, this is a type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound
The charge are always negative and positive charge.
Therefore, the type of bonding is called ionic bonding
I need to see how to do 2 and 3
Answer:
Explanation:
a) Here, we want to get the limiting reactant
The limiting reactant forms less of the product
From the equation of reaction:
4 moles of aluminum gave 2 moles of product
0.32 mol will give x moles of product:
4 * x = 0.32 * 2
x = 0.16 moles
3 moles of oxygen gave 2 moles of product
0.26 mol will give x moles of product
3 * x = 0.26 * 2
x = 0.173 moles
That means that aluminum is the limiting reagent
b) From the question:
6.38 * 10^-3 mol oxygen gives x mol of product
3 moles of oxygen gives 2 moles of product
To get x:
[tex]x\text{ = }\frac{6.38\times10^{-3}\times2}{3}\text{ = }0.00213\text{ mole}[/tex]For aluminium, we do same process:
[tex]x\text{ = }\frac{9.15\times10^{-3}\times2}{4}\text{ = 0.004575 mole}[/tex]c) From the mass available, we need to get the number of moles that could be produced from each
To get the number of moles, we have to divide the mass by the atomic mass of the element
For Aluminium, the atomic mass is 27 amu
That means the number of moles is:
[tex]\frac{3.17}{27}\text{ = 0.1174 mole}[/tex]Now, from the equation of reaction:
4 moles aluminum gave 2 moles oxygen
0.1174 mole aluminum will give:
[tex]\frac{0.1174\times2}{4}\text{ = 0.0587 mole}[/tex]For oxygen, the atomic mass is 16 amu
For molecular oxygen, we have the molar mass as 32g/mol
The number of moles that will react is thus:
[tex]\frac{2.55}{32}\text{ = 0.0796875 mole}[/tex]From the equation of reaction:
3 moles of oxygen gave 2 moles of product,
0.159375 mole will give:
[tex]\frac{0.0796875\times2}{3}\text{ = 0.053125 mole}[/tex]Since the number of moles from oxygen is lesser, it translates to a lesser amount of product and that makes oxygen the limiting reactant in this case
Answer question number 13. The question is in the image.
Answer: One carbon atom can make a maximum of 4 covalent bonds. The best option to answer the question is number 4.
Explanation:
The question requires us to choose, among the options given, which one corresponds to the maximum number of carbon bonds that can be formed by one carbon atom.
To answer this question, we can consider the electronic configuration of a carbon atom. Carbon (C) presents atomic number 6, therefore it contains 6 electrons and its electronic configuration can be written as:
[tex]1s^22s^22p^2[/tex]Note that there are 4 electrons in carbon's valence shell (2s2 and 2p2), thus a carbon atom needs additional 4 electrons to achieve stability.
If the atom needs 4 electrons to achieve stability, it means it can make 4 covalent bonds to "acquire" these electrons.
Therefore, the best option to answer the question is number 4.
Which element is most likely to behave as a metalloid?NaArZnAs
A metalloid is an elements that has some characteristics of metal and other of non-metals. In a periodic table, it is somewhere in between the metals and non-metals.
Looking to a periodic table, we have Na to the far left, so it must has metal characteristics.
Ar is to the far right, it is a noble gas, so not metalloid.
Zn is quite close to the right side, however it is in the groups of transition metals, so it is still a metal and must have metal characteristics.
As is even more to the right, exactly where the metal characteristics of elements start to change to non-metals, so As is probably the one with metalloid characteristics.
C*(UPQuestion 6 of 26šiWhich of the following sets of quantum numbers is not allowed?A) n = 1, l = 0, ml = 0B) n = 4, f = 0, ml = -1C) n = 3, l = 1, ml = 0D) n = 2,1 = 0, ml = 0E) n = 3, l = 2, ml = -2
Let's analyze option B:
Given that n=4, l=0 and ml=-1, we could draw:
If we have n=4, l=0, that means that the electron configuration ends at 4s. As you can notice, "s" orbital can only adquire one pair of electrons and ml can only be 0. In the answer option this is -1, so this option is not correct.
The answer is B.
Properties:large brittle crystalhigh MPthigh BPtnon-conductorThe properties above would best describe a solid held together by.....ionic bondscovalent bondsintermolecular forces
In general, ionic compounds have the following characteristics:
• They are solid at room temperature;
,• Its atoms arrange themselves in such a way as to produce a crystalline lattice (a crystal).
,• They are soluble in water;
,• They are capable of performing the phenomenon of dissociation (ion release) when they undergo fusion, that is, when they change from the solid state to the liquid state, or when they are dissolved in water;
,• They have high melting and boiling points;
,• They have shine;
,• They conduct current when dissolved in water or after undergoing the melting process.
,• Non-conductor at solid state.
Covalent compounds have the following characteristics:
• Physical State at Room Temperature: Under ambient conditions, molecular and covalent compounds are found in three physical states (solid, liquid, and gas).
,• Melting and Boiling Point: In general, the melting and boiling points of these substances are lower than those of ionic substances.
,• Electric current: In their pure forms, both liquids and solids do not conduct electric current.
,• Solubility: Polar dissolves into polar and non-polar dissolves into non-polar.
,• Tenacity: The resistance of covalent substances to impact or mechanical shock is low.
,• In general, they are brittle solids, as shown in the case of glass, which is formed by sodium and calcium silicates.Hardness: In general, they have high hardness.
With this in mind...
Answer: ionic bonds
What type(a) of interparticle forces exist between molecules in a pure sample of CH2F2? A) induced dipole attractionsB) dipole-dipole forcesC) H-bonding
This molecule will have dipole-dipole forces.
Answer: B
Ammonia, NH3 , reacts with oxygen to form nitrogen gas and water.
4NH3(aq)+3O2(g)⟶2N2(g)+6H2O(l)
What is the percent yield of the reaction?
The percent yield of the reaction when 3.85g of Ammonia reacts with 5.78g of O2 to give out 0.750L of nitrogen is 27.43%
It is given that the mass of Ammonia is 3.85g and the mass of Oxygen is 5.78g. The yield of Nitrogen is 0.750L. To find the percent yield, we need to know the number of moles of ammonia and Oxygen.
No of moles of Oxygen = 5.78/31.99
No moles of Oxygen= 0.181 mol of O2.
No. of moles of Ammonia = 3.85/17.03
= 0.226 mol of NH₃
It can be seen that 0.226 mol of NH₃ reacts with 3/4th of 0.226 mol of O₂ which is 0.1695 mol of O₂.
But the given moles of O₂ are more than that of the required value. Therefore, NH₃ is the limiting reactant and O₂ is the excess.
Therefore,
0.226 mol of NH3 x 2 mol of N₂/ 4 mol of NH3
= 0.113 mol of N₂
Experimentally it would be calculated as
n = PV/RT
n = (1 x 0.750)/(0.0821x295)
n = 0.031 mol of N₂
Percent yield = Experimental yield/theoretical yield x 100
Percent yield= (0.031/0.113)x100
Percent yield= 27.43%
Therefore, the percent yield of N₂ is 27.43%
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Laboratory balances that measure to the hundredths (0.01g) are calleda) centigram balanceb) milligram balancec) analytical balance
Answer:
[tex]A[/tex]Explanation:
Here, we want to select the balance used to measure mass to a hundredth accuracy
The kind of balance used in this case is the centigram balance. The measure the mass of a substance to an accuracy of a hundredth which is 0.01g
if 2.00 moles of aluminum nitrate are dissolved to form 2.00l of solution , the concentration of the NO3 ion will be ?
First, we write the reaction to solve this:
Al(NO₃)₃(aq) => Al³⁺(aq) + 3NO₃⁻(aq)
We need to calculate the concentration of the salt:
Molarity = moles of Al(NO₃)₃ / Volume of solution (L)
Molarity = 2.00 moles / 2.00 L = 1.00 mol/L
The salt is completely disociated, so the concentration of NO3- ion is:
Concentration NO3- = 3 x Concentration of the salt = 3 x 1.00 mol/L = 3.00 mol/L
Answer: 3.00 mol/L
11. Balance the following acid/base reaction: __Ca(OH)2 + __H2CO3 --> __CaCO3 + __H2O
Given the unbalanced acid/base reaction expressed as:
[tex]aC_{}a\mleft(OH\mright)_2+bH_2CO_3\longrightarrow cCaCO_3+dH_2O[/tex]The equation is balanced if the number of moles of element at the reactant is equal to that of the product.
Next is to determine the values of the constants a,b, c, and d by equating the number of moles of the element on both sides.
For the Calcium element:
a = c .................................. 1
For the Oxygen element
2a + 3b = 3c + d ......................... 2
For the Hydrogen element
2a + 2b = 2d
a + b = d .......................... 3
For the carbon element
b = c ....................... 4
Substitute equation 1 and 4 into 3 to have:
c + c = d
2c = d
d = 2c ...................... 5
Substitute equations 1, 4, and 5 into the unbalanced equation to have:
[tex]cC_{}a(OH)_2+cH_2CO_3\longrightarrow cCaCO_3+2cH_2O[/tex]Cancel out the constant "c" from both sides of the equation to have:
[tex]\begin{gathered} \cancel{c}C_{}a(OH)_2+\cancel{c}H_2CO_3\longrightarrow\cancel{c}CaCO_3+2\cancel{c}H_2O \\ C_{}a(OH)_2+H_2CO_3\longrightarrow CaCO_3+2H_2O \end{gathered}[/tex]This gives the balanced chemical equation
How is electroplating done?
A. The anode is replaced by the object to be electroplated.
B. A precipitation reaction is used to plate the cathode with an ion.
OC. The metals in the anode and cathode electrodes trade positions.
OD. Ions of one metal are reduced onto a cathode made of a different
metal.
The process of electroplating is done as follows:
Ions of one metal are reduced onto a cathode made of a different
metal; option D is correct.What is electroplating?Electroplating is the process by which one metal is used to coat the surface of another metal.
Electroplating is done in order to improve the appearance of one metal and is also done in order to protect against corrosion.
The process of electroplating involves electrolysis.
The metal to be coated over the is used as the anode while the metal to be coated is used as the cathode.
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A cube with 34.16 inch sides of an unknown material weighs 6.85 kg. What is this material'sdensity in g/mL? (Hint: 1 in = 2.54 cm)
From the calculations above, the density of the material is 0.01g/mL
To solve this problem, we have to calculate the volume of the cube, but first of all, we should convert the unit from in to cm.
Conversion from Inches to CentimeterLet us convert the unit of the side length from inches to centimeter.
[tex]\begin{gathered} 1in=2.54\operatorname{cm} \\ 34.16in=\text{xcm} \\ x=34.16\times2.54 \\ x=86.7664\operatorname{cm} \end{gathered}[/tex]Volume of a CubeThe volume of a cube is given as
[tex]\begin{gathered} v=l^3 \\ l=\text{side length} \end{gathered}[/tex]let's substitute the values and solve for the volume.
[tex]\begin{gathered} v=l^3 \\ v=(84.7664)^3 \\ v=653212.87\operatorname{cm}^3 \end{gathered}[/tex]Note;
[tex]\begin{gathered} 1\operatorname{cm}^3=1mL \\ 653212.87\operatorname{cm}^3=653212.87mL \end{gathered}[/tex]Now that we have the volume of the material, let us calculate it's density
Density of a materialThe density of a material can be calculated as
[tex]\rho=\frac{\text{mass}}{\text{volume}}[/tex]But the given mass is in kg and we are asked to find the density in g/mL
Conversion of mass from kg to g[tex]\begin{gathered} 1\operatorname{kg}=1000g \\ 6.85\operatorname{kg}=6850g \end{gathered}[/tex]We can substitute this information and calculate for the density.
[tex]\begin{gathered} \rho=\frac{\text{mass}}{\text{volume}} \\ \rho=\frac{6850}{653212.87} \\ \rho=0.010\text{ g/mL} \end{gathered}[/tex]From the calculations above, the density of the material is 0.01g/mL
Which of the following minerals is the most resistant to being scratched?
Hematite
Calcite
Orthoclase
Garnet
How would you prepare 250 mL of 0.125 M HCl from concentrated HCl (aq) that is 38.0% by mass with a density of 1.19 g/mLnote: find moles in 250 mL of 0.125 HCl
Answer
250 mL of 0.125 M HCl can be prepared from concentrated HCl (aq) that is 38.0% by mass with a density of 1.19 g/mL by adding 2.49 mL of HCL(38%) into a small quantity of water, mix to disperse; then dilute with solvent water up to but not to exceed the total needed volume of solution (in this case 250 mL).
Explanation
The problem can be solve in four steps:
Step 1: Calculate the number of moles in 38.0% by mass of HCl.
[tex]\begin{gathered} \text{HCl (38.0}\%)\text{ }=(\frac{38g\text{ HCl}}{100\text{ g solution}})=(\frac{x\text{ moles HCl}}{1.0\text{ Liter Solution}}) \\ \\ \Rightarrow Moles\text{ of HCl in 38 grams }=\frac{38g\text{ HCl}}{36\text{ g/mol}}=1.06\text{ mole HCl} \end{gathered}[/tex]Step 2: The volume of the 38.0% by mass HCl solution.
Volume of solution in Liters containing 1.06 mole of HCl =
[tex]\frac{Mass}{D\text{ensity}}=\frac{100g}{1.19gmL^{-1}^{}}=84.03\text{ mL HCl(38.0}\%)\text{ }=0.084\text{ L HCl(38.0}\%)[/tex]Step 3: Calculate the molarity of HCl (38.0%)
[tex]\text{Molarity of HCl (38.0}\%)=\frac{Number\text{ of mole}}{Volume\text{ in liters}}=\frac{1.06\text{ mole HCl}}{0.084\text{ L HCl}}=12.62\text{ M}[/tex]Step 4: To calculate the volume of HCl (38.0%) required to prepare 250 mL of 0.125 M HCl.
Note: Formula weight of HCl = 36 g/mol
[tex]\begin{gathered} \text{Volume of HCl(38.0}\%)\text{ required }=\frac{(Molarity)(Volume)(Formula\text{ Weight)}}{(\text{Purity)(Specific Gravity)}} \\ \\ \text{Volume of HCl(38.0}\%)\text{ required }=\frac{(0.125\text{ M)})(250\text{ }mL)(36\text{ g/mol)}}{(0.38\text{)}(1.19\text{ g/mL)}} \\ \\ \text{Volume of HCl(38.0}\%)\text{ required }=\frac{(0.125\text{ M)})(0.250\text{ }L)(36\text{ g/mol)}}{(0.38\text{)}1.19\text{ g/mL)}} \\ \\ \text{Volume of HCl(38.0}\%)\text{ required }=\frac{1.125}{0.4522}=2.49\text{ mL} \end{gathered}[/tex]Therefore, 250 mL of 0.125 M HCl can be prepared from concentrated HCl (aq) that is 38.0% by mass with a density of 1.19 g/mL by adding 2.49 mL of HCL(38%) into a small quantity of water, mix to disperse; then dilute with solvent water up to but not to exceed the total needed volume of solution (in this case 250 mL).
What is the density of NH3 at 800 torr and 25 degree celsius?
To solve this question, we need to use the following formula:
[tex]\rho\text{ = }\frac{(MM_{NH_3})(P)}{(R)(T)}[/tex]where:
d = density
MMNH3 = molar mass of NH3 = 17 g/mol
P = pressure = 800 Torr = 1.05263 atm (just divide by 760)
T = 25 °C = 273.15 + 25 = 298.15 K
R = 0.082 atm
So:
d = 17 * 1.05263/0.082 * 298.15
d = 17.8947/24.4483
d = 0.7319 g/L
Answer: density = 0.7319 g/L
37.In the compound MgO, what is the oxidation number of oxygen?Select one:a. +4b. +2c. +1d. -2
When we have to determine the oxidation number of compounds, we need to look at their specific and most common charges in their non neutral form, and Oxygen is an element that will usually present a -2 oxidation number and charge, the same way Hydrogen will almost always present a charge of +1, these fixed values for some elements is helpful for us to determine the oxidation number of other elements. For oxygen is -2, therefore letter D
3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4H₂O
In the above equation how many moles of NO can be made when 75 moles of HNO3 are
consumed?
As per the given statement 0.297mol NO can be made when 75 moles of HNO3 are consumed
What is HNO3?The inorganic substance with the formula HNO3 is nitric acid. It is a mineral acid that is quite corrosive. The substance is colourless, but older samples have a tendency to have a yellow cast because of breakdown into nitrogen oxides..
'3 Cu + 8HNO3 3 Cu(NO3)2 + 2 NO + 4H₂O
Element Molar Mass
Hydrogen 1
Nitrogen 14
Copper 63.5
Oxygen 16
Referring the above table we get no of moles in HNO3
1(1.0) + 1(14) + 3(16) = 1 + 14 + 48 = 63 g/mol
75g HNO3 x 1 mol HNO3/63 g HNO3 = 1.190 mol HNO3
The coefficient of HNO3 is 8, and NO is 2
1.190 mol HNO3 x 2 mol NO/8 mol HNO3 = 0.297mol NO
Hence, 0.297mol NO can be made when 75 moles of HNO3 are consumed.
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A balloon is filled with a 0, gas and has a volume of 179mL at 2.00 atm pressure. What will its volume be if thepressure is changed to 5.50 atm?A) 29.2 mLB) 65.1 mLC) 17.9 mLD) 83.0 ml
In this case, we can use the Boyle's law to solve this problem:
[tex]P1\cdot v1=P2\cdot v2[/tex]We already know the values of P1, v1 and P2 and we have to find v2. Replace for the given values and solve for v2:
[tex]\begin{gathered} 179ml\cdot2.00atm=5.50atm\cdot v2 \\ v2=\frac{179ml\cdot2.00atm}{5.50atm} \\ v2=65.1ml \end{gathered}[/tex]The correct answer is B) 65.1ml.