which is the scatter plot for the data set{(1960,3), (1970,3.5), (1990,6)}?

Which Is The Scatter Plot For The Data Set{(1960,3), (1970,3.5), (1990,6)}?

Answers

Answer 1

Given the data set:

(x, y)==> {(1960,3), (1970,3.5), (1980, 5), (1990,6)}

To plot the data above, the x-corrdinates: (1960; 1970; 1980; 1990) which are the first values will be on the horizontal axis, while the y-coordinates (3, 3.5, 5, 6), will be on the vertical axis.

Thus, the correct scatter plot for the data set above will be Scatter Plot A.

The graphical representation is below

ANSWER:

A

Which Is The Scatter Plot For The Data Set{(1960,3), (1970,3.5), (1990,6)}?

Related Questions

Your brother and sister took turns driving on a 635 mile trip that took 11 hours to complete. your brother drove at a constant speed of 60 miles per hour and your sister drove at a constant speed of 55 miles per hour. let x be the number of miles your brother drove and y be the number of miles your sister drove. find the number of miles each of your siblings drove.

Answers

Your brother and sister took turns driving on a 635 mile trip

Total distance travel on trip = 635

Let x be the disatnce travel by your borther and y be the miles travel by the sister

SO, x + y = 635

It took 11 hours to complete the trip

Speed of brother = 60 miles per hour

Speed of sister = 55 miles per hour

The general expression for the speed is :

[tex]\begin{gathered} \text{ Sp}eed=\frac{Dis\tan ce}{Time} \\ \text{Then, }Time=\frac{Dis\tan ce}{Spped} \end{gathered}[/tex]

Then using these expression

Time taken by the brother is :

[tex]\begin{gathered} \text{ Time taken by brother =}\frac{x}{60} \\ \text{Time taken by the sister=}\frac{y}{55} \end{gathered}[/tex]

As total time is 11 hours so:

[tex]\frac{x}{60}+\frac{y}{55}=11[/tex]

So we get the two set of equation :

[tex]\begin{gathered} \frac{x}{60}+\frac{y}{55}=11 \\ x+y=635 \end{gathered}[/tex]

Simplify the set of equation :

Simplify the first equation for x and then put it into another :

[tex]\begin{gathered} \frac{x}{60}+\frac{y}{55}=11 \\ \frac{x}{60}=11-\frac{y}{55} \\ x=660-\frac{12y}{11} \\ \text{Susbtitute the value of x in the second equation:} \\ x+y=635 \\ 660-\frac{12}{11}y+y=635 \\ \frac{-12}{11}y+y=635-660 \\ \frac{-12y+11y}{11}=-25 \\ \frac{-1}{11}y=-25 \\ y=25\times11 \\ y=275 \end{gathered}[/tex]

Substitute y = 275 in the first equation :

x + y = 635

x + 275 = 635

x = 360

As x represent the distance travel by the bother and the rest by sister

Distance travel by brother is 360 miles and the distance travel by the sister is 275 miles

Answer : x = 360 miles, y = 275 miles

in ABC, G is the centroid. If BF=48 find BG

Answers

Recall that the centroid of the triangle is the intersection point of its medians, which are the lines that are formed by joining the midpoint of one side with the remainding vertex of the triangle. This point has the property that for each median it splits it in two smaller segments, one of which has the double of the length of the other.

We are given the following picture

Let us call the lenght of GF x. Since G is the centroid, then the length of BG is 2x. Note that the sum of the length of BG plus the length of GF should be BF. So we have the following equation

[tex]x+2x=48[/tex]

Now, we should solve this equation for x. First we add the x terms on the left. So we get

[tex]3x=48[/tex]

Finally, we divide by 3 on both sides, so we get

[tex]x=\frac{48}{3}=16[/tex]

so the lenght of GF is 16. Now, si BG has the double length of FG, then the length of BG is 16*2 = 32.

The top of a desk would be a representation ofO a pointO a planeO a lineO none of the above

Answers

Given

The top of a desk.

To find:

The top of a desk is a representation of _____.

Explanation:

It is given that,

The top of a desk.

That implies,

Since,

The plane is a flat surface that extends infinitely in all directions.

Then, the top of a desk represents a plane.

Answer:

B-Plane tep-by-step explanation:

10. The graph of y=f(x) is given below.y!24168848 xWhat is the possible degree of f?A. 4IB. -3C. 2D. 3E. -1

Answers

Answer:

The degree of the function is;

[tex]3[/tex]

Explanation:

From the given graph, we can observe that the function has two extremum (one minima and one maxima).

The degree of the function will be the number of extremum plus 1;

[tex]\text{degree}=n+1[/tex]

Since there are two extremum on the graph then;

[tex]\begin{gathered} \text{degree}=2+1 \\ \text{degree}=3 \end{gathered}[/tex]

Therefore, the degree of the function is;

[tex]3[/tex]

Select the correct answer.Consider a regular polygon that has 12 congruent sides. Which angle of rotation will carry it onto itself?

Answers

Answer:

30 degrees

Explanation:

A regular polygon is a polygon in which all the side lengths are equal.

All regular polygons have rotational symmetry, that means it can be rotated so that the pre-image and the image are the same.

The angle by which this rotational symmetry occurs is the exterior angle of the polygon.

Given a regular polygon with 12 sides, the exterior angle is:

[tex]\frac{360}{12}=30\degree[/tex]

Therefore, the angle of rotation that will carry onto itself is 30 degrees.

1. Corinne has a cell phone plan that includes 200 minutes for phone calls and unlimited texting. An additional fee is charged for using more than 200 minutes for phone calls. The figure below is the graph of C = f(m), where C is the monthly cost after m minutes used. Part A What is the minimum monthly cost for Corinne's cell phone plan? Show or explain your work. Part B What is the value of f(150). Explain its meaning in terms of the cell phone plan. Part C For what mis f(m) = 55? Explain its meaning in terms of the cell phone plan. Part D What is the cost per minute after Corinne uses her monthly allowance of 200 minutes? Show or explain your work.

Answers

Answer:

Part A) Minimum cost = $30

Part B) Value of f(150) = $30

Part C) m = 275 minutes

Part D) Cost per minute after 200 minutes = $0.2

Explanations:

From the graph shown:

Monthly rate for 200 minutes for phone calls = $30

An additional fee is charged for more than 200 minutes for phone calls

Part A) The minimum monthly cost of Corinne's cell phone plan.

Note that the minimum monthly cost of Corinne's cell phone plan will be when he does not use more than 200 minutes for phone calls.

Therefore, the minimum monthly cost, C = f(200) = $30

Part B)

The value of f(150)

f(150) means the cost of Corinne's cell phone plan when 150 minutes is spent for phone calls, i.e. m = 150

Since there is a flat rate of $30 for 0 to 200 minutes, f(150) = $30

Part C)

For what m is f(m) = 55

This means that we should find the number of minutes spent when the cost of the plan is $55

From the graph, $55 is charged at 275 minutes

Therefore, when f(m) = 55, m = 275 minutes

Part D)

Cost per minutes after the monthly allowance of 200 minutes

After the monthly allowance of 200 minutes, we would notice that, for every 50 minutes, there is a $10 charge. That means that for every 1 minute, there will be a charge of 10/50 = $0.2

Cost per minute = $0.2

B. Make a line graph for given the data on the table below. No plagiarism

Answers

NOTE ; Kindly ensure the x-axis have equal width

Calculate the value of the expression:1+1x100+2

Answers

In order to calculate the value of this expression, first we need to calculate the multiplication between 1 and 100. Then, w

A function with an input of 1 has an output of 3. Which of the following could not be the function equation?options:y = 3 xy = - x + 4y = x - 2y = 2 x + 1

Answers

Solution:

A function with an input of 1 has an output of 3.

This means that

[tex]when\text{ }x=1,y=3[/tex]

Step 1:

We will try the first option

[tex]\begin{gathered} y=3x \\ y=3(1) \\ y=3 \\ (1,3) \end{gathered}[/tex]

Step 2:

We will try the second option

[tex]\begin{gathered} y=-x+4 \\ y=-1+4 \\ y=3 \\ (1,3) \end{gathered}[/tex]

Step 3:

We will try the third option

[tex]\begin{gathered} y=x-2 \\ y=1-2 \\ y=-1 \\ (1,-1) \end{gathered}[/tex]

Step 4:

We will try the fourth option

[tex]\begin{gathered} y=2x+1 \\ y=2(1)+1 \\ y=2+1 \\ y=3 \\ (1,3) \end{gathered}[/tex]

Hence,

The final answer is

[tex]\Rightarrow y=x-2[/tex]

2^4c^-10 to a fraction

Answers

The given expression is

[tex]2^4c^{-10}[/tex]

We have to solve the power of 2.

[tex](2\cdot2\cdot2\cdot2)c^{-10}=16c^{-10}[/tex]

Then, we use the property for negative exponents.

[tex]a^{-b}=\frac{1}{a^b}[/tex]

This means we have to move the power to the denominator.

[tex]\frac{16^{}}{c^{10}}[/tex]Therefore, the fraction is[tex]\frac{16}{c^{10}}[/tex]

how do I find the value of x so f(x)=7

Answers

We have a function for which we only have the chart.

We need to find the value of x so that f(x)=7.

NOTE: As we are lookin for the value of x that makes the value of f(x) = 7, we are able to see it in the graph directly:

If we start at y=7, we can draw a line until we intersect the line for f(x). When this happens we draw a vertical line towards the x-axis until we intersect it.

The value of x at that point is the one that makes f(x)=7.

If we can not find the solution by graph, we have to find the equation of the line and clear x for f(x)=7.

SOLUTION WITH EQUATION:

With the information from the chart we have to find the equation.

We can identify two points in the function: (2,0) and (5,7).

Using the 2 known points, we calculate the slope of the line as:

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{7-0}{5-2}=\frac{7}{3}[/tex]

Then, we can write the slope-point equation as:

[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y-0=\frac{7}{3}(x-2) \\ y=\frac{7}{3}x-\frac{14}{3} \end{gathered}[/tex]

Then, if we know that y=7, we can replace y with this value and calculate x as:

[tex]\begin{gathered} y=7=\frac{7}{3}x-\frac{14}{3} \\ 7\cdot3=7x-14 \\ 21=7x-14 \\ 7x=21+14 \\ 7x=35 \\ x=\frac{35}{7} \\ x=5 \end{gathered}[/tex]

Answer: the value of x so that f(x)=7 is x=5.

What is the solution to the linear system 4x + 2y = 8 and 2x + 2y = 2?

Answers

Answer:

• x=3

,

• y=-2

Explanation:

Given the linear system of the equations:

[tex]\begin{gathered} 4x+2y=8\cdots\cdots\cdots(1) \\ 2x+2y=2\cdots\cdots\cdots(2) \end{gathered}[/tex]

First, subtract equation(2) from equation(1).

[tex]\begin{gathered} (4x-2x)+(2y-2y)=8-2 \\ 2x=6 \\ \text{Divide both sides by 2} \\ \frac{2x}{2}=\frac{6}{2} \\ x=3 \end{gathered}[/tex]

Next, substitute x=3 into equation (1) to solve for y.

[tex]\begin{gathered} 4x+2y=8\cdots\cdots\cdots(1) \\ 4(3)+2y=8 \\ 12+2y=8 \\ \text{Subtract 12 from both sides.} \\ 12-12+2y=8-12 \\ 2y=-4 \\ \text{Divide both sides by 2} \\ \frac{2y}{2}=\frac{-4}{2} \\ y=-2 \end{gathered}[/tex]

The solution to the linear system is x=3 and y=-2.

simplify 2(w+3)-(w-1)

Answers

we have

2(w+3)-(w-1) ​

apply distributive property first term and remove the parenthesis

2w+6-w+1

combine like terms

w+7

Find the volume of a right circular cone that has a height of 19 e ft and a base with acircumference of 7.6 ft. Round your answer to the nearest tenth of a cubic foot

Answers

In order to solve this problem we will take in account the following picture and formula:

Where:

π ≅ 3.14159

h = height of the cone

r = radius of the base

V = volume

Now, our cone has the following dimensions:

h = 19 ft

c = circunference = 7.6 ft

We see that in order to obtain the volume we must replace the radius in the formula of the picture.

So we obtain first the radius r from the value of the circunference.

The circunference in terms of the radius is:

[tex]c=2\pi r[/tex]

So the radius is:

[tex]r=\frac{c}{2\pi}[/tex]

Now that we have the radius, we replace that in the formula for the volume:

[tex]V=\frac{1}{3}\cdot\pi\cdot h\cdot r^2=\frac{1}{3}\cdot\pi\cdot h\cdot(\frac{c}{2\pi})^2[/tex]

Now we replace the data of our right circular cone:

[tex]\begin{gathered} V\cong\frac{1}{3}\cdot3.14159\cdot19ft\cdot(\frac{7.6ft}{2\cdot3.14159})^2 \\ \cong29.1105ft^3 \\ \cong29.1ft^3 \end{gathered}[/tex]

So the volume of the right circular cone to the nearest tenth is: 29.1 ft³

What are the solutions of 3x^2 - x + 4 = 0

Answers

ANSWER

[tex]x\text{ = 0.167 + }1.142i\text{ and x = 0.167 }-\text{ 1.142i}[/tex]

EXPLANATION

We want to find the solutions of the equation.

The solutions of the equation are the values of x that make that equation equal to zero (0).

The equation given is:

[tex]3x^2\text{ - x + 4}[/tex]

We need to use the quadratic formula.

For a quadratic equation:

[tex]ax^2\text{ + bx + c}[/tex]

the quadratic formula is:

[tex]x\text{ = }\frac{-b\text{ }\pm\text{ }\sqrt[]{b^2\text{ - 4ac}}}{2a}[/tex]

So, we have that:

a = 3, b = -1, c = 4

So::

[tex]\begin{gathered} x\text{ = }\frac{-(-1)\text{ }\pm\sqrt[]{(-1)^2_{}-\text{ 4(3)(4)}}}{2(3)}\text{ = }\frac{1\text{ }\pm\text{ }\sqrt[]{1\text{ - 48}}}{6} \\ x=\text{ }\frac{1\text{ }\pm\text{ }\sqrt[]{-47}}{6}\text{ = }\frac{1\text{ }\pm\text{ }\sqrt[]{47}\cdot\text{ }\sqrt[]{-1}}{6}\text{ = }\frac{1\text{ }\pm\text{ }\sqrt[]{47}\text{ i}}{6} \\ x\text{ = }\frac{1\text{ + 6.86i}}{6}\text{ and x = }\frac{1\text{ - 6.86i}}{6} \\ x\text{ = 0.167 + }1.142i\text{ and x = 0.167 }-\text{ 1.142i} \end{gathered}[/tex]

The equation has complex solutions.

Find the new position of the given point (1,3) after a translation of 3 units down and 3 units to the left.

Answers

Answer:

(-2, 0)

Explanation:

Given the point: (1,3)

• To translate the point ,3 units down,, ,subtract 3 from the y-value,.

,

• To translate the point ,3 units left,, ,subtract 3 from the x-value,.

Therefore, the new position of the point is:

[tex](1-3,3-3)=(-2,0)[/tex]

The new position is (-2, 0).

Re-arrange this vertex equation y = 2 (x + 1)2 - 6 in standard form?

Answers

When we have a quadratic equation, we can have it in vertex and standard form.

The vertex form comes in the form:

[tex]y=a\mleft(x-h\mright)^2+k[/tex]

The standard form comes in the form:

[tex]y=ax^2+bx+c[/tex]

Converting to/from either simply requires some manipulations via expansion of the bracket as will be seen.

[tex]\begin{gathered} y=2(x+1)^2-6 \\ y=2(x^2+2x+1)-6 \\ y=2x^2+4x+2-6 \\ y=2x^2+4x-4 \end{gathered}[/tex]

Hence, we have our standard form.

At 6 AM today, you purchased 1 MW of electricity contract for 12 PM at a price of 100 pounds/MWh. Two hours later, the forecast for solar generation for 12 PM has changed from 4 GW to 4.5 GW. The market is currently bid at 95 pounds/MWh and offered at 105 pounds/MWh. What would you do, and why? Please answer logically, stating all assumptions. Note that no additional research is needed
Expert Answer

Answers

I will sell 1MW electricity contract for 12pm with a bid price of £95/MW.  Lock in losses in the region of £5/MW.

At 6 AM today, you purchased 1 MW of electricity contract for 12 PM at a price of 100 pounds/MWh.

Solar power is more affordable, accessible, and prevalent in the United States than ever before.

From just 0.34 GW in 2008, U.S. solar power capacity has grown to an estimated 97.2 gigawatts (GW) today.

This is enough to power the equivalent of 18 million average American homes.

Today, over 3% of U.S. electricity comes from solar energy in the form of solar photovoltaics (PV) and concentrating solar-thermal power (CSP).

Solar generation implies an increase of 4 GW to 4.5 GW.  Which will provide more power than expected during 12 p.m. This will likely lower the market value.

A bid-offer spread of 10 pounds/MWh is typically wide.  This basically indicates that the market is liquid and volatile.  The price of which might turn against me if I wait.

Some of my guesses are:

I am a risk-averse trader.  Who does not want to take unnecessary

exposure to power market.

I do not have any positions or hedging strategies in the electricity

market that would influence my decisions.

I am not obliged to buy and sell electricity at 12 PM.

Market prices and forecasts are reliable, reflecting actual supply and demand conditions.

Hence the answer is I will sell 1MW electricity contract for 12pm with a bid price of £95/MW.  Lock in losses in the region of £5/MW.

To learn more about market prices click here https://brainly.com/question/26912109

#SPJ1

a) Write the three equations using three ordered pairs.EQ1:EQ2:EQ3:B) Write the linear system:C) Solve the system using substitution and then elimination. Show all work andsteps:

Answers

[tex]\begin{gathered} 5\text{ = a - b + c . . . (1)} \\ -\text{4 = c . . . (2)} \\ \text{0 = 16a + 4b + c . . . (3)} \\ \\ \text{equation of the parabola:} \\ y=2x^2\text{ - 7x - 4} \end{gathered}[/tex]Explanation:

A) To get the three equations, we will substitute each of the 3 points on the parabola into the quadratic formula

Quadratic function formula is given by:

[tex]y\text{ = }ax^2\text{ + bx + c }[/tex]

using point (-1, 5) = (x, y)

[tex]\begin{gathered} 5=a(-1)^2\text{ + b(-1) + c} \\ 5\text{ = a(1) - b + c } \\ 5\text{ = a - b + c }\ldots.(1) \end{gathered}[/tex]

using point (0, -4) = (x, y)

[tex]\begin{gathered} -4=a(0)^2\text{ + }b(0)\text{ + c} \\ -4\text{ = c } \end{gathered}[/tex]

using point (4, 0)

[tex]\begin{gathered} 0=a(4)^2\text{ + b(4) + c} \\ 0\text{ = 16a + 4b + c} \\ \text{16a + 4b + c = 0 . . . (2)} \end{gathered}[/tex][tex]\begin{gathered} \text{The 3 equations using orderd pair:} \\ EQ1\colon\text{ }5=a(-1)^2\text{ + b(-1) + c} \\ EQ2\colon\text{ }-4=a(0)^2\text{ + b(0) + c} \\ EQ3\colon\text{ }0=a(4)^2\text{ + b(4) + c} \end{gathered}[/tex]

B) The linear system:

[tex]\begin{gathered} 5\text{ = a - b + c . . . (1)} \\ -\text{4 = c . . . (2)} \\ \text{0 = 16a + 4b + c . . . (3)} \end{gathered}[/tex]

C) substitute for c in equation 1 and 2:

[tex]\begin{gathered} 5\text{ = a - b + c }\ldots.(1) \\ 5\text{ = a - b -4} \\ 5\text{ + 4 = a - b } \\ 9\text{= a - b }\ldots(4) \\ \\ \text{0 = 16a + 4b + c . . . (3)} \\ \text{0 = 16a + 4b }-4 \\ 0+\text{4 = 16a + 4b } \\ 4\text{ = 16a + 4b . . . (5)} \end{gathered}[/tex]

Using elimnation for equation (4) and (5):

To eliminate a variable, it must have the same coefficient in both equations.

Let's elimnate b. We will multiply equation (4) by 4 so the coefficient will be the same:

4(9) = 4(a) - b(4)

36 = 4a - 4b ...(4)

4 = 16a + 4b ...(5)

Add equation 4 and 5 together:

36 +4 = 4a + 16a - 4b + 4b

40 = 20a

divide both sides by 20:

40/20 = 20a/20

a = 2

substitute for a in equation 5:

4 = 16(2) + 4b

4 = 32 + 4b

4 - 32 = 4b

-28 = 4b

divide both sides by 4:

-28/4 = 4b/4

b = -7

a = 2, b = -7, c = -4

The equation of the parabola becomes:

[tex]y=2x^2\text{ - 7x - 4}[/tex]

What is the area of the trapezoid shown? Te figure is not drawn to scale.thank you ! :)

Answers

Given a trapezoid with different dimensions, we are asked to find the Area.

To solve this we will have to use the area of a trapezoid formula:

Area = 1/2 (a + b)h

Where:

a = 29.2 in

b = 19 in

h = 12.6 in

A = ?

Inputting into the formula:

Area = 1/2 (29.2 + 19) * 12.6

Area = 1/2 (48.2) * 12.6

Area = 1/2 (607.32)

Area = 303.66 in²

Therefore, the Area of the Trapezoid is 303.66 in²

Therefore, the correct option is third option which is 303.66 in².

how do you solve -2×+5=9

Answers

[tex]\begin{gathered} -2x+5=9 \\ -2x=9-5 \\ -2x=4 \\ x=\frac{4}{-2} \\ x=-2 \end{gathered}[/tex]

Use the Distributive Property to find each missing factor.6 x 8 = ( 4 x ____) + ( 2 x 8 )10 x 3 = (___ x 3 ) + ( 2 x 3 )(___ X 7 ) = ( 3 x 7 ) + ( 2 x ___)( 8 X ___) = (___ x 8 ) + ( 4 X 8 )3rd grade subject Distributive property

Answers

The question is given below as

[tex]6\times8=(4\times\ldots)+(2\times8)[/tex]

The distributive property of multiplication states that when a number is multiplied by the sum of two numbers, the first number can be distributed to both of those numbers and multiplied by each of them separately, then adding the two products together for the same result as multiplying the first number by the sum.

[tex]a(b+c)=a\times b+a\times c[/tex]

Let the missing factor in the question be x

[tex]\begin{gathered} 6\times8=(4\times\ldots)+(2\times8) \\ 6\times8=(4\times x)+(2\times8) \end{gathered}[/tex]

By multiplying,

We will have

[tex]\begin{gathered} 6\times8=(4\times x)+(2\times8) \\ 48=4x+16 \end{gathered}[/tex]

Collect like terms,by subtracting 16 from both sides

[tex]\begin{gathered} 48=4x+16 \\ 48-16=4x+16-16 \\ 32=4x \end{gathered}[/tex]

Divide both sides by 4

[tex]\begin{gathered} 4x=32 \\ \frac{4x}{4}=\frac{32}{4} \\ x=8 \end{gathered}[/tex]

Hence,

[tex]\begin{gathered} 6\times8=(4\times8)+(2\times8) \\ 6\times8=8(4+2) \\ 6\times8=6\times8 \end{gathered}[/tex]

Therefore,

The missing factor = 8

26. Find the area of the figure to the nearest tenth,165°7 inA. 13.5 in.B. 7.1 in 2C. 84.8 in 2D. 42.4 in?

Answers

To find the area of the segment of the circle, use the following formula:

[tex]A=\frac{a}{360}\pi r^2[/tex]

Where a is the angle of the segment and r is the radius of it. Replace for the given values and find the area of the segment:

[tex]\begin{gathered} A=\frac{165}{360}\pi\cdot(7)^2 \\ A=70.55 \end{gathered}[/tex]

How many fourteenths are there in 5/7

Answers

38 of them i cant tell you the rest because you never know

PLEASE HELP NOW!!!!!!!!!!!!!!!

Answers

The rate of change of water capacity of the reservoir per year is -1725  acre - feet per year .

In the question ,

a line graph is given which represents the relation between time(t) and the reservoir capacity in acre - feet .

the two points on the line graph means

in the year 1928 the reservoir capacity was 300000 acre - feet .

and in the year 1986 the reservoir capacity was 200000 acre - feet .

the rate of change of water capacity of the reservoir per year can be calculated using the formula ,

rate of change = ( change in water capacity) / ( change in time)

= ( 200000 - 300000)/(1986-1928)

= -100000/58

= -1724.13

≈ -1725

here negative sign means the capacity of the reservoir is decreasing per year .

Therefore , The rate of change of water capacity of the reservoir per year is -1725  acre - feet per year .

Learn more about Rate Of Change here

https://brainly.com/question/27984400

#SPJ1

8. Reece made a deposit into an account that earns 8% simple interest. After 8 years, Reece had earned $400. How much was Reece's initial deposit?

Answers

[tex]\begin{gathered} P\cdot r\cdot t=I \\ r=0.08 \\ t=8 \\ I=400 \\ \text{from the first equation one has} \\ P=\frac{I}{r\cdot t} \\ \text{hence} \\ P=\frac{400}{0.08\cdot8} \\ P=\frac{400}{0.64} \\ P=625 \end{gathered}[/tex]

A and _B are supplementary angles. If m_A = (4x - 16) and m B = (8x + 4), then find the measure of ZA.

Answers

A=48

Explanation

Two Angles are Supplementary when they add up to 180 degrees

Step 1

if A and B are supplementary angles, then

[tex]A+B=180[/tex]

Let

A=4x-16

B=8x+4

Step 2

replace,

[tex]\begin{gathered} A+B=180 \\ 4x-16+8x+4=180 \\ 12x-12=180 \end{gathered}[/tex]

Step 3

solve for x

[tex]\begin{gathered} 12x-12=180 \\ 12x=180+12 \\ 12x=192 \\ x=\frac{192}{12} \\ x=16 \\ \end{gathered}[/tex]

Step 4

finally, replace the value of x= 16 to find A

[tex]\begin{gathered} A=4x-16 \\ A=4(16)-16 \\ A=64-16 \\ A=48 \end{gathered}[/tex]

What is the effect on the graph of f(x) = x2 when it is transformed toh(x) = 3x2 + 12?A. The graph of f(x) is horizontally compressed by a factor of 5 andshifted 12 units up.O B. The graph of f(x) is vertically compressed by a factor of 5 andshifted 12 units to the left.O C. The graph of f(x) is horizontally stretched by a factor of 5 andshifted 12 units to the left.O D. The graph of f(x) is vertically compressed by a factor of 5 andshifted 12 units up.SUBMIT

Answers

the fraction 1/5 horizontally expands the graph and the constant 12 move up the graph because is a sum

so the right option is the last

D. The graph of f(x) is vertically compressed by a factor of 5 and

shifted 12 units up

a regular square pyramid has base whose area is 250 cm^2. a section parallel to the base and 31.8 cm above it has an area of 40 cm^2 . find the ratio of the volume of the frustum to the volume of the pyramid.

Answers

We are given that the area of the base of a pyramid is 250 cm^2. We are asked to determine the ratio of the volumes of the frustum and the volume of the pyramid. To do that, let's remember that the volume of a pyramid is given by:

[tex]V=\frac{1}{3}A_bh[/tex]

Where:

[tex]\begin{gathered} A_b=\text{ area of the base} \\ h=\text{ height} \end{gathered}[/tex]

Now, the volume of the frustum is given by:

[tex]V_f=\frac{1}{3}h_f(A_b+A_f+\sqrt[]{A_bA_f})[/tex]

Where:

[tex]\begin{gathered} h_f=\text{ height of the frustum} \\ A_f=\text{ area of the base of the frustum} \end{gathered}[/tex]

Now, the ratio of between the volume of the frustum and the volume of the pyramid is:

[tex]\frac{V_f}{V_{}}=\frac{\frac{1}{3}h_f(A_b+A_f+\sqrt[]{A_bA_f})}{\frac{1}{3}A_bh_{}}[/tex]

We can cancel out the 1/3 and we get:

[tex]\frac{V_f}{V_{}}=\frac{h_f(A_b+A_f+\sqrt[]{A_bA_f})}{A_bh}[/tex]

Now, we need to determine the heights. To do that we will use the fact that the ratio of the squares of the height of the pyramid and the height to the top of the pyramid is equivalent to the ratio of the areas, therefore, we have:

[tex](\frac{h}{h_t})^2=\frac{A_b}{A_f}[/tex]

Now we substitute the areas:

[tex](\frac{h}{h_t})^2=\frac{250}{40}[/tex]

Taking square root we get:

[tex]\frac{h}{h_t}=\sqrt[]{\frac{250}{40}}[/tex]

Solving the operations:

[tex]\frac{h}{h_f}=2.5[/tex]

Now we multiply by the height of the frustum on both sides:

[tex]h=2.5h_t[/tex]

Now, let's look at the following diagram:

This shows us that the height of the frustum plus the height to the top must be equal to the height of the pyramid, therefore:

[tex]h=h_t+31.8[/tex]

Substituting the relationship we determined for the height to the top we get:

[tex]h=\frac{h}{2.5}+31.8[/tex]

Now we solve form the height "h" first by subtracting h/2.5 from both sides:

[tex]\begin{gathered} h-\frac{h}{2.5}=31.8 \\ \end{gathered}[/tex]

Solving the operations:

[tex]\frac{1.5h}{2.5}=31.8[/tex]

Now we multiply both sides by 2.5:

[tex]\begin{gathered} 1.5h=31.8\times2.5 \\ 1.5h=79.5 \end{gathered}[/tex]

Now we divide by 1.5:

[tex]h=\frac{79.5}{1.5}=53[/tex]

Therefore, the height of the pyramid is 53 cm. Now we substitute in the ratio of the volumes and we get:

[tex]\frac{V_f}{V_{}}=\frac{h_f(A_b+A_f+\sqrt[]{A_bA_f})}{A_bh}[/tex]

Substituting the values:

[tex]\frac{V_f}{V_{}}=\frac{(31.8)(250+40+\sqrt[]{(250)(40)})}{(250)(53)}[/tex]

Solving the operations:

[tex]\frac{V_f}{V}=0.936_{}[/tex]

Therefore, the ratio is 0.936

Trigonometry I’m a little stuck in this problem and I want to know we’re If I messing up and need help to proceed!

Answers

Problem 2.

Using the unit circle as our guide,

Point A would be at 0 degrees

There are 12 points on the circle

Take 360 degrees and divide by 12

360/12 = 30

Each pie shaped wedge is 30 degrees

C is 2 pie pieces so it is 2*30 or 60 degrees from point A

H is 8 pie shapes wedges so it is 8*30 or 240 degrees from point A

Looking at the diagram we can see that A and G are the same distance from the ground

B and F are the same distance from the ground

C and E are the same distance from the ground

H and L are the same distance from the ground

I and K are the same distance from the ground

Other Questions
Hello there I need help with this.Ben and his friend go to buy some water.Still water and sparkling water both cost $p per bottle. Ben and his friend bought 2 bottles of sparkling water and 3 bottles of still water.They spent $6.50 altogether.What is the algebraic equation of the total price T? Enter the equation of the line in slope-intercept formSlope is -4, and (6,1) is on the line.The equation of the line is A plane traveled 1160 kilometers each way to Havana and back. The trip there was with thewind. It took 10 hours, The trip back was into the wind: The trip back took 20 hours. Find thespeed of the plane in still air and the speed of the wind. Ella finished a bike race in 37.6 minutes. Miranda finished the race 9 1/10 minutes sooner than Ella finished it. How many minutes did it take Miranda to finish the race?A. 32.5 minutes B. 46.7 minutes C. 28.59 minutes D. not here Find the simple interest and the total amount after three years.Principal = 7800 rupeesAnnual rate of interest = 9.5%Total interest=rupeesTotal amount =rupees Reaction C3H8(g) +502(g) --> 3CO2(g) + 4HO(g)A scientist completes the reaction above and endsup with 186.68g of carbon dioxide. What mass ofpropane (C3H8) would need to be reacted to endup with that much carbon dioxide? (Round anyatomic masses on the periodic table to onedecimal place.) Complete the two-column proof that the diagonals of a rhombus are perpendicular. Glven: JKLM Is a rhombus Prove:JL I MK J N M K L Part 1 out of 7 Statements Reasons 1.JM JK 1. Definition of rhombus 2. MN AKN 2. (select) Check Next Hello, I need help with this. Please. I would very much appreciate it thank you how would you solve d=9rt for t A tile pattern is represented by the equation "y = 6x + 4".A) what does the six represent in the patternB) what does the four represent in the patternC) how many times will there be in the 75th figure. Is there a tutor that can help me? What is the slope of the line passing through the points (0, - 5) and (4, 2)? Consider the function [tex]y = x ^{3} - 3x[/tex]Find the intervals the function is increasing. Express your answer in interval notation (a,b) Simplify the expression by combining like terms [tex]16 + 8a - 3a + 6b - 9[/tex] An ecosystem is a community of living organisms and their interactions with their abiotic environment. Group of answer choicesTrueFalse angle1=73angle2=34angle3=73Classify the triangle(by the side and by the angles) Find an equation of the line parallel to the graph of y = -3x - 11 that passes through the point of (2,4). Write your equation in slope-intercept form. How do I match these polynomial and what are the correct matches?! Zeros 4 and -3iI already asked for the last question, but Im confused for the i To qualify for a certain need-based scholarship, a student must get a score of at least 75 on a qualification test. In addition, the student's family must make less than $40.000 a year. Define the variables, write a system of inequalities to represent this situation, and name one possible solution.WRITE TWO INEQUALITIES AND ONE POSSIBILITY: