Since the mass is not present, the tension in the rope T = 0 N.
What is tension in physics?Tension, in physics, is be defined to be the pulling force transmitted axially by the means of a string, a rope, chain, or similar object. The opposite of tension could be compression.
At the atomic level, when atoms/molecules are pulled apart from each other and gain potential energy with a restoring force still existing, the restoring force might create tension.
Tension is a pulling force since it is exerted when a mass being pulled by a rope or a similar object. If the mass is not present, then there is no tension (pulling force) exerted by the rope, hence T = 0 N.
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Help with explaining please!
As the elevator moves upward, the cables are under 1,960 N of tension.
The given parameters are,
The mass of the elevator (m) = 200 kg
According to Newton's Second Law of Motion, an object's force is directly inversely proportional to its mass times its acceleration.
The tension in the cables as the elevator travel upwards is calculated by applying the 2nd law of Newton,
T = ma +mg
where a is the acceleration of the elevator and g is the acceleration due to gravity,
At constant velocity, acceleration is zero. (a =0)
T = m(0) +mg
T = mg
T = 200*9.8
T = 1,960 N
Thus, As the elevator moves upward, the cables are under 1,960 N of tension.
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State two assumptions of the Kinetic Theory.
Answer:
Explanation: 1: The gas particles move in a straight line before colliding with something, usually the wall of their containers.
2: The is no attraction or repulsion between the gas particles.
A ray diagram without the produced image is shown.Which describes the image produced by the lens?smaller than the object and uprightsmaller than the object and invertedreal and uprightreal and inverted
smaller than the object and upright.
We have a negative lens, the image is between the object and the lens.
The top of the virtual image must be below and touching the ray that connects the top of the car with the lens (green)
So, the image will be smaller than the car and it won't be inverted.
What is the total displacement during the interval from t=0 until t=11 s?
Brainlist if answered correctly.
Answer:
830 cm
Explanation:
From 0 - 4
acceleration = slope = 90 /4 = 22.5
distance = 1/2 at^2 = 1/2 (22.5)(4^2) = 180 cm
from 4-7 velocity is constant 90 cm/s = 270 cm
from 7-11 acceleration = slope = 10 /4 = 2.5 m/s^2
distance =vo t + 1/2 a t^2 = 90(4) + 1/2 (2.5)(4^2) = 380 cm
Summed = 180 + 270 + 380 = 830 cm
Answer:
Explanation:
Given:
t₀ = 0 s
V₀ = 0 cm/s = 0 m/s
t = 11 s
V = 100 cm/s = 1 m/s
________________
| S | - ?
Movement module:
| S | = V·t = 1·11 = 11 m
(The displacement is numerically equal to the area of the triangle AOB):
A crane used 600,000 Joules of work to move a beam to the top of a building in 30 seconds. How much power did the crane use?
The power crane used is2× 10⁵ W.
What is power, exactly?The amount of work finished in a specific length of time is a definition of power. The SI unit of power is the watt (W), which is derived from joules per second (J/s). Horsepower (hp) is a unit of measurement sometimes used to express the power of motor vehicles and other equipment. It is roughly comparable to 745.7 watts.
How to Calculate?Given parameters:
Work done = 600,000J
Time taken = 30s
Unknown:
Power of the crane = ?
Mathematically,
Power = Work done /time taken
= 600,000J/30
Power= 200000 W
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A bowling ball is dropped from the top of a building that has a height of h = 159 m.a) Assuming air resistance is negligible, what is the ball's speed, vf in m/s, when it strikes the ground? b) If drag produces an opposing force of 10 N while the ball's falling, what is the ball's speed, vf in m/s, when it strikes the ground? Assume the ball has a mass of 5 kg.c) A different ball was dropped and the final speed was measured to be vf = 6.5 m/s while the drag force was measured to be 50 Newtons. What is the mass of this ball in kg?
ANSWER:
a) 55.82 m/s
b) 49.8 m/s
c) 5.17 kg
STEP-BY-STEP EXPLANATION:
Given:
Height (h) = 159 m
Initial speed (vi) = 0 m/s
a)
We calculate the final speed using the following formula:
[tex]\begin{gathered} (v_f)^2=(v_i)^2+2gh \\ \\ \text{ we replacing:} \\ \\ (v_f)^2=(0)^2+2(9.8)(159) \\ \\ v_f=\sqrt{3116.4} \\ \\ v_f=55.82\text{ m/s} \end{gathered}[/tex][tex]\begin{gathered} (v_f)^2=(v_i)^2+2gh \\ \\ \text{ we replacing:} \\ \\ (v_f)^2=(0)^2+2(9.8)(159) \\ \\ v_f=\sqrt{3116.4} \\ \\ v_f=55.82\text{ m/s} \end{gathered}[/tex]b)
To determine the final velocity with the opposing force, we have to determine the net force and then calculate the acceleration that would be used to calculate the velocity, like this:
[tex]\begin{gathered} F_n=mg-10 \\ \\ \text{ we replacing} \\ \\ F_n=5\cdot9.8-10 \\ \\ F_n=49-10=39\text{ N} \\ \\ F=m\cdot a \\ \\ a=\frac{F}{m}=\frac{39}{5} \\ \\ a=7.8\text{ m/s^^b2} \\ \\ \text{ Therefore:} \\ \\ (v_f)^2=(v_i)^2+2ah \\ \\ \text{ we replacing:} \\ \\ (v_f)^2=(0)^2+2(7.8)(159) \\ \\ v_f=\sqrt{2480.4} \\ \\ v_f=49.8\text{ m/s} \end{gathered}[/tex]c)
We can calculate the mass in the following way, first, we must calculate the acceleration to be able to determine the mass:
[tex]\begin{gathered} (v_{f})^{2}=(v_{i})^{2}+2ah \\ \\ \text{ we replacing:} \\ \\ 6.5^2=0^2+2\cdot a\cdot(159) \\ \\ 318a=42.25 \\ \\ a=\frac{42.25}{318} \\ \\ a=0.133\text{ m/s^^b2} \\ \\ \text{ Now we can calculate the mass using the force balance:} \\ \\ ma=mg-50 \\ \\ a=g-\frac{50}{m} \\ \\ \text{ we replacing:} \\ \\ 0.133=9.8-\frac{50}{m} \\ \\ 1.333-9.8=-\frac{50}{m} \\ \\ -9.667m=-50 \\ \\ m=\frac{-50}{-9.667} \\ \\ m=5.17\text{ kg} \end{gathered}[/tex]Given a horizontal uncharged insulating rod. A negatively charged rod touches the middle of the horizontal rod. Which of these best describes what happens? A)the rod becomes positively charged on its left end and negatively charged on its right end B)the middle of the rod becomes negatively charged C)the rod becomes positively charged all over its surface D)the rod becomes negatively charged all over its surfaceE) the rod remains uncharted
Answer:
E) The rod remains uncharted.
Explanation:
The negatively charges rod has an excess of electrons. These electrons repel each other, so when this rod touches the horizontal uncharged insulating rod, they will try to go to the uncharge rod. However, this is an insulating rod, so there will be no transfer of electrons. It means that the rod remains uncharted.
On Saturday, Ashley rode her bicycle to visit Maria. Maria’s house is directly east of Ashley‘s. The graph shows how far Ashley was from her house after each minute of her trip.
1. Ashley Road at a constant speed for the first four minutes of her trip. What was her constant speed?
2. what was Ashley‘s average speed for the entire trip?
3. what was her average velocity for the entire trip?
4. Ashley stop to talk with another friend during her trip. How far is she from her house when she stopped?
5. what is the slope of the line after Ashley stopped to talk with her friend?
6. how is the slope of the line related to her speed?
1. The constant speed of Ashley for first four minute of her trip is calculated here
For first four minutes Ashley travelled 800 m distance (d) , substituting this value in the formula of speed
Speed(s) = distance (d)/ time (t)
Speed(s) = 800/4
Speed(s)= 200m/s
2. Ashley's average speed for the entire trip is
The total distance (d) traveled by Ashley is 1600 m and time (t) taken for that is 10 minutes.
Speed (s)= distance(d)/time(t)
Speed (s)= 1600/10
Speed(s) = 160m/s
3. The average velocity of Ashley is 160 m/s in east direction. As velocity is nothing but speed with direction.
4. In graph there is linear slop when Ashley was 800 m away from her house where net displacement is zero means she stopped there to talk with friend.
5. Slope of line after Ashley stopped to talk to her friend is
Slope = [tex]X_{2}[/tex] - [tex]X_{1}[/tex]/ [tex]Y_{2}[/tex]-[tex]Y_{1}[/tex]
Slope= 8-0/800-800
Slope= 0 as it is a linear line and slope of it is zero.
6. The slope of a line is related to her speed as speed increases the slope increases.
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A ball is fired at 5 m/s to the right and bounces off a second ball, initially at rest, and comes back to the left at 1m/s. What is the velocity of the second ball? Assume both balls have a mass of 3.86kg and make to the right positive.
ANSWER:
6 m/s
STEP-BY-STEP EXPLANATION:
Given:
Mass of balls (m) = 3.86 kg
Initial speed of ball 1 (u1) = 5 m/s
Final speed of ball 1 (v1) = - 1 m/s
Initial speed of ball 2 (u2) = 0 m/s
We make the balance for the moment and we are left with the following:
[tex]\begin{gathered} m_1\cdot u_1+m_2\cdot u_2=m_1\cdot v_1+m_2\cdot v_2 \\ \\ \text{ We repalcing:} \\ \\ 3.86\cdot5+3.86\cdot0=3.86\cdot-1+3.86\cdot v_2 \\ \\ 19.3=-3.86+3.86v_2 \\ \\ 3.86v_2=19.3+3.86 \\ \\ v_2=\frac{23.16}{3.86} \\ \\ v_2=6\text{ m/s} \end{gathered}[/tex]Therefore, the speed of the second ball is equal to 6 m/s
A 29-g rifle bullet traveling 220 m/s embeds itself in a 3.9-kg pendulum hanging on a 3.0-m-long string, which makes the pendulum swing upward in an arc.
The vertical component (height) of the pendulum's maximum displacement is 0.146 meters.
What is maximum displacement?In physics, the maximum displacement or range traveled by a point on a vibrating body or wave calculated from its equilibrium position is known as amplitude. It is one-half of the length of the vibration path.
We have a collision when the bullet hits the pendulum, and momentum is preserved in any collision. Let the pendulum's beginning momentum and the bullet's initial momentum be, p₁ and p₂, respectively.
Following the impact, the pendulum and the bullet travel as one object with the same velocity, v. Let p₃ be the momentum of the pendulum and as well as the bullet following the impact.
Hence,
First momentum = Last Momentum
p₁ + p₂ = p₃
[3.4kg x 0m/s] +([2.90 x 10⁻²] x 200m/s) = 3.48kg x v
Simplified, we have
5.8kg · m/s = 3.49kg · v
Making v the subject of the formula, we have
v = 1.69m/s
As a result, the combined velocity of the pendulum and bullet after the contact is v = 1.69 m/s.
We are now using the conservation of energy equation. The potential energy at the maximum height will be equal to the kinetic energy of the pendulum plus the bullet.
mgh = 1/2mv²
Where
m is the mass in kilograms
g is the acceleration due to gravity
h is height in meters; and
v is velocity
If we divide both sides with m and make h the subject of the formula, we have:
h = v²/2g
= (1.69m/s)²/2 (9.81)m/s²
= 0.14557084607m
Hence,
The vertical component of the pendulum's maximum displacement (h) [tex]\approx[/tex] 0.146m
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Full Question:
A 29-g rifle bullet traveling 220 m/s embeds itself in a 3.9-kg pendulum hanging on a 3.0-m-long string, which makes the pendulum swing upward in an arc.
Determine the vertical component of the pendulum's maximum displacement. Express your answer in two significant figures and include the appropriate units.
A spring is pulled down by a weight by 1.24 meters. The spring constant (k) is 330 N/m. What is the mass of the weight?
Given,
The extension of the spring due to the attached mass, x=1.24 m
The spring constant, k=330 N/m
The weight of a mass m is given by,
[tex]F=mg[/tex]Where g is the acceleration due to gravity,
The magnitude of the restoring force of a spring is given by,
[tex]\begin{gathered} F=kx \\ \Rightarrow mg=kx \end{gathered}[/tex]Therefore,
[tex]m=\frac{kx}{g}[/tex]On substituting the known values,
[tex]\begin{gathered} m=\frac{330\times1.24}{9.8} \\ =41.76\text{ kg} \end{gathered}[/tex]Thus the mass of the weight is 41.76 kg
Consider a system of a cliff diver and the earth. The gravitational potential energy of the system decreases by 26,500 J as the diver drops to the water from a height of 33.0 m. Determine her weight in newtons.
Given data:
* The change in gravitational potential energy is 26500 J.
* The change in height of the diver is 33.0 m.
Solution:
The change in gravitational potential energy in terms of change in height of the diver is,
[tex]dU=mg\times dh[/tex]where m is the mass of diver, g is the acceleration due to gravity, dh is the change in height, and dU is the change in gravitational potential energy,
Substituting the known values,
[tex]\begin{gathered} 26500=mg\times33 \\ mg=\frac{26500}{33} \\ mg=803.03\text{ N} \end{gathered}[/tex]The weight of the diver is,
[tex]\begin{gathered} W=mg \\ W=803.03\text{ N} \end{gathered}[/tex]Thus, weight of the diver is 803.03 N.
6. Suppose that two chrome steel balls attract each other with a gravitational
force of 16 units. If the mass of both objects was doubled, and if the distance
between the objects was doubled, then what would be the new force of attraction
between the two objects?
4 units
8 units
16 units
32 units
64 units
Answer:
Explanation:
Given:
m₁
m₂
R₁
F₁ = 16 units
m₁' = 2·m₁
m₂' = 2·m₂
R₂ = 2·R₁
_________
F₂ - ?
The force of gravity:
F₁ = G·m₁·m₂ / (R₁)²
F₂ = G·m₁'·m₂' / (R₂)² = G·(2·m₁)·(2·m₂) / (2·R₁)² =
= 4·m₁·m₂ / (4·R₁²) = m₁·m₂ / (R₁)² = F₁
F₂ = F₁ = 16 units
a hoopof moment of inertia released from the top of an inclined plane 20m high and length 32m rolls drawn without slipping determine the speed and acceleration when it reaches the foot of the inclined plane
The speed and acceleration when it reaches the foot of the inclined plane is 14√2 m/s
Torricelli's theorem states that the speed of a liquid flowing through an orifice is equal to the speed it would attain if falling freely a distance equal to the height of the liquid's free surface above the orifice.
Given that
A hoop of the moment of inertia released from the top of an inclined plane 20m high and length 32m rolls drawn without slipping
W have to determine the speed and acceleration when it reaches the foot of the inclined plane
By using Torricelli's theorem
V= √2gh
Here g= 9.8 and h = 20m
V= √2x9.8x20
V= √4x9.8
V= 14√2 m/s
Therefore the speed and acceleration when it reaches the foot of the inclined plane is 14√2 m/s
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light ray passing through the focus is undeviated true or false
Answer:true
Explanation:
dentify the objective of this lab. select all that apply: group of answer choices to submurged different objects in the fluid. to determine density of unknown materials using archimedes' principle to discover the relationship between aarchimedes' principal and hydrostatic pressure in object submerged in a fluid. to test archimedes' principle for objects of different densities
The objective of the experiment of submerging different objects in fluid is to determine the density of the unknown material using Archimedes' principle.
Archimedes' principle- The amount of the upward force felt by the object when submerged in fluid is equal tot he weight of the mass of the fluid displaced.
So, in this experiment,
The objects of unknown densities are submerged in liquid, they displaces some amount of liquid. The amount of liquid is related to the buoyancy of the unknown object as,
Vₐpg = Vσg
where,
p is the density of the unknown object,
σ is the density of the fluid and Vₐ is the volume of the body submerged in fluid and V is the volume of the water displaced.
So, by this relation, we can find the density of the unknown material.
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A car travelling with an initial velocity of
15.0 m/s, accelerates at 2.40 m/s² over a
distance of 180 m. What is the final
velocity of the car (m/s)?
?] m/s
The final velocity of the car 120.93 m/sec.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Uniform motion an object is said to have uniform motion when object cover equal distance in equal interval of time within exact fixed direction. For a body in uniform motion, the magnitude of its velocity remains constant over time.
Given in the question, a car travelling with an initial velocity of 15.0 m/s, accelerates at 2.40 m/s² over a distance of 180 m
Using equation of motion,
v² = u² + 2as
v² = 15² + 2*40*180
v = 120.93 m/sec
The final velocity of the car 120.93 m/sec.
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Describe where infrared is found on the ems compared to the other six forms of radiation.
Between visible light and microwave is where infrared falls. Infrared has a higher energy than radio but a lower energy than gamma rays.
Where, in relation to the other six types of radiation, is infrared found on the EMS?The term "infrared" refers to electromagnetic waves that exist within the electromagnetic spectrum at frequencies slightly below those of red visible light and just above those of microwaves. According to the California Institute of Technology, the wavelengths of infrared radiation are longer than those of visible light (Caltech).
Where can I find radio waves on the EMS?The majority of the radio portion of the electromagnetic spectrum (EM spectrum) is found between 1 cm and 1 km, or 30 GHz and 300 kHz in frequency. The EM spectrum's radio region is relatively vast. Astronomers usually employ wavelength in the infrared and optical spectrum.
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This question is typical on some driver’s license exams: A car moving at 46 km/h skids
15 m with locked brakes.
How far will the car skid with locked brakes
at 115 km/h? Assume that energy loss is due
only to sliding friction.
Answer in units of m.
A car moving at 46 km/h skids 15 m with locked brakes. The distance travelled by the car when it skids is 94.74 m.
What is the acceleration of the car?The acceleration of the car is calculated by applying the following kinematic equation.
v² = u² - 2as
where,
v is the final velocity of the car
u is the initial velocity of the car
a is the acceleration of the car
s is the distance travelled by the car
when the car stops, the final velocity, v = 0
0 = u² - 2as
2as = u²
a = u²/2s
where,
u = 46 km/h = 12.7 m/s
a = (12.7²) / (2 x 15)
a = 5.37 m/s²
When the speed of the car changes from 42 km/h to 126 km/h, the distance travelled by the car at the same acceleration is calculated as follows;
s = u²/2a
where,
u = 115 km/h = 31.9 m/s
s = (31.9²) / ( 2 x 5.37)
s = 94.74 m
The distance travelled by the car when it skids is 94.74 m.
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A balloon bursts when more air is filled in it.
give reason?
Spiral galaxy rotation curves are generally fairly flat out to large distances. Suppose that spiral galaxies did not contain dark matter. How would their rotation curves be different?.
Spiral galaxy rotation curves are generally fairly flat out to large distances. Suppose that spiral galaxies did not contain dark matter. Their rotational curves be different as the orbital speeds would fall off sharply with increasing distance from the galactic center.
Plotting the orbital speeds vs radius graph gives us the rotational curves. According to the theoretical calculations, the curve increases as the radial distance decrease and then decreases as the radial distance increases. The theoretical graph does not take the dark matter into account.
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The pressure of a gas goes from 1 atm to 0.5 atm. based on the relationship between pressure and volume, what will happen to the volume of the gas?
Based on the relationship between pressure and volume, the volume of the gas will increase if the pressure of a gas goes from 1 atm to 0.5 atm.
According to ideal gas equation,
PV = nRT
P = Pressure
V = Volume
n = Number of moles
R = Gas constant
T = Temperature
At constant Temperature,
P ∝ 1 / V → ( 1 )
From ( 1 ), it can be clearly seen that pressure is inversely proportional to volume. So as pressure increases the volume will decrease and if the pressure decreases, the volume will increase. In the given situation, the pressure is decreased. So the volume will increase.
Therefore, the volume of the gas will increase if the pressure of a gas goes from 1 atm to 0.5 atm.
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A ball rolls down a hill that leads to a cliff.
How does the ball move when it reaches the edge of the cliff?
C. The ball keeps moving forward and falls downward at the same time.
B. The ball's forward motion ends at the edge of the cliff, where it falls straight down.
A. The ball falls downward in a spiral-shaped path.
The ball's forward motion continues briefly beyond the edge of the cliff, and then it falls straight down.
Answer:
Option C is correct. The ball keeps moving forward and falls downward at the same time.
Explanation:
When the ball reaches the edge of the cliff, its forward motion will indeed continue due to its inertia. Inertia is the property of an object to maintain its state of motion. However, gravity will also be acting on the ball, causing it to accelerate downward.
As a result, the ball will move forward and descend downward at the same time. The trajectory of the ball will be a curved path that combines the horizontal motion (forward movement) and the vertical motion (downward fall) simultaneously. This curved path is known as a parabolic trajectory.
The exact shape of the trajectory will depend on factors such as the initial velocity, angle of the cliff, and air resistance. If there is no air resistance and the cliff is not too steep, the ball's trajectory may resemble a smooth parabolic curve. However, if there is air resistance or the cliff is steep, the trajectory might deviate from a perfect parabola.
Eventually, due to the downward acceleration caused by gravity, the ball's vertical motion will dominate, and it will fall straight down. But immediately after reaching the edge of the cliff, the ball will experience a combination of forward motion and downward descent.
Which object is made up of a magnetic material?
A. A copper wire
B. A plastic spoon
C. An iron nail
D. An ice cube
Answer: C
Explanation: because it is made out of metal.
Answer:
C- iron nail.
Explanation:
iron nails are attracted to magnets and that's made of magnetic material.
How much heat is necessary to change 295 g of ice at -5°C to water at 20°C? Answer must be in kcal
Given:
• Mass of ice = 295 g ==> 0.295 kg
,• Initial temperature, T1 = -5°C
,• Final temperature, T2 = 20°C
Let's find the amount of heat necessary to change the ice to water.
To find the amount of heat, let's apply the Specific Heat Capacity formula:
[tex]\begin{gathered} Q=mc\Delta T \\ \\ Q=mc(T_2-T_1) \end{gathered}[/tex]Where:
m is the mass in kg = 0.295 kg
T1 is the initial temperature
T2 is the final temperature.
c is the specific heat capacity
Let's first find the amount of heat required to change ice from -5°C to 0°C.
[tex]\begin{gathered} Q_1=0.295*0.50*(0-(-5)) \\ \\ Q_1=0.295*0.50*5 \\ \\ Q_1=0.74\text{ kcal} \end{gathered}[/tex]Now, let's find the heat required to change from 0°C(ice) to 0°C(water).
We have:
[tex]\begin{gathered} Q_2=m*L \\ \end{gathered}[/tex]
Where L is the latent fusion of water:
[tex]\begin{gathered} Q_2=0.295*79.7 \\ \\ Q_2=23.51\text{ kcal} \end{gathered}[/tex]Now, let's find the heat required to change 0°C (water) to 20°C(water).
We have:
[tex]\begin{gathered} Q_3=mc_{water}(T_2-T_1) \\ \\ Q_3=0.295*1.0*(20-0) \\ \\ Q_3=0.295*1.0*20 \\ \\ Q_3=5.9\text{ kcal} \end{gathered}[/tex]Therefore, the total heat required is:
Q = Q1 + Q2 + Q3
Thus, we have:
[tex]\begin{gathered} Q=0.74+23.51+5.9 \\ \\ Q=30.15\text{ kcal} \end{gathered}[/tex]Therefore, the amount of heat neccesary is
A 250 kg object is lifted to a height of 4 m. What is the work done? How much
potential energy does the object have? What is the maximum kinetic energy on impact
if the object is released?
Answer:
9800J
Explanation:
It appears that potential energy is given to the object, so to calculate total energy in the system, we can use the potential energy formula
Potential energy = 250 kg • 9.8 m/s/s • 4 m
Potential energy = 9800J
You'll notice that the equation for the potential energy and work in this scenario is the same due to the fact that force would be equal to mass multiplied by gravity anyway.
Assuming the system has 100% efficiency, the total kinetic energy will be equivalent to the potential in the system currently
A dvd is rotating with an ever-increasing speed. how do the centripetal acceleration arad and tangential acceleration atan compare at points p and q?.
The centripetal acceleration arad and tangential acceleration atan compare at points P and Q by Q having a greater arad and atan than point P.
arad = v² / r
v = 2 π r / T
arad = 4 π² r / T²
Since time period will be constant at any point in the radius line,
arad ∝ r
So larger the radius, larger will be the centripetal acceleration. The radius at point P is smaller than the radius at point Q.
arad at Q > arad at P
atan = r α
α = 2 π / T²
atan = 2 r π / T²
Since time period will be constant at any point in the radius line,
atan ∝ r
So larger the radius, larger will be the tangential acceleration. The radius at point P is smaller than the radius at point Q.
atan at Q > atan at P
Therefore, Q has a greater arad and atan than point P.
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You throw a ball vertically upward from the roof of a tall building.
The ball leaves your hand at a point even with the roof railing with
an upward speed of 15.0 m/s; the ball is then in free fall. On its
way back down, it just misses the railing. Find the ball's posi-
tion and velocity 1.00 s and 4.00 s after leaving your hand
11.1 m and -18.4 m is the ball's position, 5.2 m/s and -24.2 m/s is the ball's velocity after leaving your hand
s = ut + 1/2at²
s = 15(t) + 1/2(-9.8)(t)²
s = 15t - 4.5(t)²
t = 1 second,
s = 15(1) - 4.9(1)²
s = 15 - 4.5
s = 11.1 m [at t = 1 second]
t = 4 seconds,
s = 15(4) - 4.9(4)²
s = 60 - 4.9(16)
s = 60 - 78.4
s = -18.4 m [t = 4 seconds]
v = u + at
v = 15 + (-9.8)t
time = 1 second,
v = 15 - 9.8
v = 5.2 m/s [ t = 1 second]
time = 4 seconds,
v = 15 - (9.8)(4)
v = 15 - 39.2
v = -24.2 m/s [for t = 4 seconds]
velocity's a vector quantity have magnitude and direction.
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2.
The magnetic field of magnet A extends further than the
magnetic field of magnet B.
State what can be concluded about the strengths of these
two magnets.
The magnetic field of magnet A extends further than the magnetic field of magnet B concludes that magnet A is larger in size and have stronger magnetic field than magnet B.
What is a magnetic field?A magnetic field is a vector field that represents the effect of magnetic effect on moving charges, currents, and magnetic bodies. A charge moving in a magnetic field experiences a force perpendicular to its velocity and magnetic field.
Does size affect the strength of a magnet ? The answer is yes, but it's because the size of a magnet is proportional to its ability to align and produce a stronger magnetic field than smaller pieces of the same material. Because it means there are more domains.
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The driver of a car going 16.0 m/s suddenly sees the lights of a barrier 84.0 m ahead. It takes the driver 0.75 s to apply the brakes, and the average acceleration during braking is -10.0 m/s2.
(a) what is the total displacement of the car.
The driver of a car going 16.0 m/s suddenly sees the lights of a barrier 84.0 m ahead. It takes the driver 0.75 s to apply the brakes, and the average acceleration during braking is -10.0 m/s2. The total displacement of the car 9.19 m
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.
s = u*t + 1/2 a [tex]t^{2}[/tex]
s = displacement
u = initial speed
t = time
a = acceleration
s = 16 * 0.75 + 1/2 * ( -10 ) * [tex](0.75)^{2}[/tex] = 9.19 m
The total displacement of the car will be 9.19 m
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