Answers
Equations showing direct variations are 2x = y and y = 1.8c
Direct Variation exists between two variables when one variable is directly dependent to another variable means change in one variable will create change in other one also and vice versa.
Two variable increase or decrease by the same factor.
Suppose x and y is that are in direct variation then you can write
y ∝ x
where, "∝" denotes proportionality
removing proportionality sign by constant then you can write
y = k x , where k is constant and can hold any real value
From the following equation ,
2x = y with 2 as constant and
y = 1.8x with 1.8 as constant shows direct variations
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Related Questions
In O O, mCD = 30° and CA BD. Also, the center of the circle,point o, is the intersection of CB and AD.DWhat is mAB?АBMAB = Just answers
Answers
Answer:
mAB = 30°
Explanation:
mCD is the measure of angle 1 and mAB is the measure of angle 2. These angles are vertically opposite because they are formed by intersecting lines and they are on opposite sides.
Vertically opposite angles have the same measure, so:
mAB = mCD
mAB = 30°
Therefore, the measure of AB is 30°
Relationship A has a greater rate than Relationship B. This table represents Relationship B.Hours worked2458Amount paid30.4060.8076121.60Which equation could represent Relationship A?Hours worked is represented by x and Amount paid is represented by y.Select each correct answer.y = 15.4xy = 15.2xy = 16.4xy = 14.9x
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ANSWER:
[tex]\begin{gathered} y=15.4x \\ y=16.4x \end{gathered}[/tex]STEP-BY-STEP EXPLANATION:
We can calculate the equation that represents relationship B, calculating the slope using the data from the table, like this:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \text{replacing} \\ m=\frac{121.60-30.40}{8-2} \\ m=\frac{91.2}{6} \\ m=15.2 \end{gathered}[/tex]Therefore, the equation of relationship B is:
[tex]y=15.2x[/tex]Therefore, the relationship A, having a greater rate, could be the following:
[tex]\begin{gathered} y=15.4x \\ y=16.4x \end{gathered}[/tex]A certain loan program offers an interest rate of 4%, compounded continuously. Assuming no payments are made, how much would be owed after six yearson a loan of I300Do not round any intermediate computations, and round your answer to the nearest cent
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In order to calculate how much will be owed, we can use the formula below for interest compounded continuously:
[tex]A=P\cdot e^{rt}[/tex]Where A is the final amount after t years, P is the initial amount and r is the interest rate.
So, using P = 1300, r = 0.04 and t = 6, we have:
[tex]\begin{gathered} A=1300\cdot e^{0.04\cdot6}\\ \\ A=1300\cdot e^{0.24}\\ \\ A=1652.62 \end{gathered}[/tex]Therefore the amount owed after 6 years is $1652.62.
Find a quadratic function of the form y=ax^2 that passes through the point (-2,-8)
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Solution
[tex]\begin{gathered} \text{ since }y=ax^2 \\ \\ \text{ at }(-2,-8) \\ \\ \Rightarrow-8=a(-2)^2 \\ \\ \Rightarrow-8=a(4) \\ \\ \Rightarrow a=-\frac{8}{4}=-2 \\ \\ \Rightarrow y=-2x^2 \end{gathered}[/tex]The quadratic equation is
[tex]y=-2x^2[/tex]Construct triangle ABC if AB = 5cm, BC=5cm and AC=3cm. What type if triangle does this create
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The type of triangle is isosceles.
Picture
Graph the system of inequalities {y > 3x+2 and y<-2x+1. Which two quadrants does the solution lie in?
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Quadrants 2 and 3
Explanation
[tex]\begin{cases}y>3x+2 \\ y\leq-2x+1\end{cases}[/tex]
Step 1
graph inequality 1
[tex]y>3x+2[/tex]a)Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)
so
[tex]\begin{gathered} y=3x+2 \\ i)\text{ for x= 0} \\ y=3(0)+2=0+2=2 \\ so \\ A(0,2) \\ i)\text{ for x= -1} \\ y=3(-1)+2=-3+2=-1 \\ B(-1,-1) \end{gathered}[/tex]draw a line that passes trough P1 ( 0,2) and P2( -1,-1) and
b)shade below the line for a "less than" (y< or y≤).
so
[tex]y>3x+2[/tex]Step 2
graph inequality 2
[tex]\begin{gathered} y\leq-2x+1 \\ \end{gathered}[/tex]a)Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)
so
[tex]\begin{gathered} y=-2x+1 \\ i)\text{ for x= 0} \\ y=-2\cdot(0)+1=0+1=1 \\ so \\ C(0,1) \\ i)\text{ for x= -1} \\ y=-2(-1)+1=2+1=3 \\ D(-1,3) \end{gathered}[/tex]draw a line that passes trough C ( 0,1) and D( -1,3) and
b)shade below the line for a "less than" (y< or y≤).
so
[tex]\begin{gathered} y\leq-2x+1 \\ \end{gathered}[/tex]Step 3
finally, the solution is the intersection of the shaded areas,hence
therefores, the solution lies in
Quadrants 2 and 3
I hope this helps you
Using the figure below as a starting point, identify the figure in which lines to l are drawn through points A, B, C, and D.
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SOLUTION
We want to find the figure in which lines perpendicular to l are drawn through points A, B, C, and D
The correct figure will be the one in which a vertical line is drawn across each of points A, B, C and D.
Looking at this, we can see that the correct answer is the first option
Answer:
a
Step-by-step explanation:
It takes Mike’s 40 minutes to type and spell check six pages find how many pages he can type and spell check in one. Five hours round answer to the nearest 10th
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Ok, so it takes Mike 40 minutes to work on 6 pages. Let's calculate how many he types in 1.5 hours.
In order to calculate that, we'll use a cross product. But first, let's see how many minutes 1.5 hours are correspondent to:
1 hours - 60 minutes
1.5 hours - x
x= 60*1.5 = 90 minutes.
So:
40 min - 6 pages
90 min - x
40x = 6*90
40x = 540
x= 13.5 pages
He will type and spell check 13.5 pages.
An accountant used to charge $72 perhour, but recently decided to charge 25%less. Now how much does she charge perhour?
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ANSWER :
EXPLANATION :
The sum of two numbers is 12 ar their difference is 4.
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This problem is sysyem of equations
Equation 1 x + y = 12
WILL GIVE BRAINLEST! I NEED HELP ASAPPP! The highest score on an Algebra test was 40 points more than the lowest. When added together, the lowest and highest score was 152. Write an equation to find the highest score, then solve.
A= x + x + 40 = 152; 56
B= x + x = 152; 76
C= x + x - 40 = 152; 96
D= x + x + 40 = 152; 96
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Answer:
D is correct.
Step-by-step explanation:
Let x be the lowest score. Then x + 40 is the highest score.
[tex]x + x + 40 = 152[/tex]
[tex]2x + 40 = 152[/tex]
[tex]2x = 112[/tex]
[tex]x = 56[/tex]
[tex]x + 40 = 96[/tex]
Lowest score is 56, highest score is 96.
I need help with this problem if anyone want to help me please do thanks
Answers
Solve e from the equation by substraction 96 to both sides of the equal sign:
[tex]undefined[/tex]Drag each label to the correct location on the flowchart.Given: Line l and line m intersectProve: Complete the proof. is supplementaryto is supplementaryto Line l and line mintersect
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Solution:
The question asked to prove that
[tex]\angle1\cong\angle3[/tex]The given statement is
Line l and line m intersect
Linear pair theorem:
In math, the linear pair postulate or linear pair theorem, says the same in mathematical terms. If two angles form a linear pair, then the measures of the angles add up to 180
Also,
Two angles are called supplementary when their measures add up to 180 degrees.
That is,
[tex]\begin{gathered} \angle2\text{ is supplementary to }\angle3 \\ \angle2+\angle3=180^0 \\ \angle3\text{ is supplementary to }\angle4 \\ \angle3+\angle4=180^0 \\ \angle1\text{ is supplementary to }\angle4 \\ \angle1+\angle4=180^0 \\ \angle2\text{ is supplementary to }\angle3 \\ \angle2+\angle3=180^0 \\ \angle1\text{ is supplementary to }\angle2 \\ \angle1+\angle2=180^0 \end{gathered}[/tex]Hence,
Linear pair theorem :
∠1 is supplementary to ∠2
∠2 is supplementary to ∠3
Congruent Supplements Theorem:
If two angles are supplements of the same angle (or congruent angles), then the two angles are congruent.
Since angles 1 and 3 are supplements of the same angle 2
Therefore,
With the statement above we can conclude that
∠1 ≅ ∠3 (congruent supplements theorem)
Solve the right triangle with a=60.6 and C= 90 degrees. Round off the results according to the table below
Answers
SOLUTION
Given the question in the image, the following are the soluton steps to answer the question.
STEP 1: Draw the given triangle
STEP 2: Write the given parameters
[tex]\theta=90^{\circ},a=60.6[/tex]Since we do not know the measure of any of the two remaining angles, we cannot solve for the required sides and angles.
Hence, There is no enough information to solve the triangle
10. The perimeter of the rectangle to the right is 28 ft. What is the value of x?
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ANSWER
x = 9
EXPLANATION
We have the rectangle with width 3 ft and length (2 + x) ft.
The perimeter of the triangle is 28 ft.
The perimeter of a rectangle is given as:
P = 2(L + W)
where L = length
W = width
Therefore, we have that:
28 = 2[(2 + x) + 3]
28 = 2(2 + x + 3) = 2(x + 5)
28 = 2x + 10
=> 2x = 28 - 10 = 18
Divide through by 2:
2x/2 = 18/2
x = 9
That is the value of x.
Triangle RJM has an area of 6 and a perimeter of12. If the triangle is dilated by a scale factor of 3centered at the origin, what are the area andperimeter of its image, triangle R'I'M"?1) area of 9 and perimeter of 152) area of 18 and perimeter of 363) area of 54 and perimeter of 364) area of 54 and perimeter of 108
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The perimeter of a triangle is given by:
[tex]P=s_1+s_2+s_3=12[/tex]Now, if the triangle is dilated by a factor of 3 this means that we multiply each side by 3, then we have:
[tex]P^{\prime}=3s_1+3s_2+3s_3=3(s_1+s_2+s_3)=3(12)=36_{}_{}[/tex]Therefore the new triangle will have a perimeter of 36.
Now, the original area is given by:
[tex]A=\frac{1}{2}bh=6[/tex]if we dilate the triangle by a factor of three we get:
[tex]A=\frac{1}{2}(3b)(3h)=9(\frac{1}{2}bh)=9(6)=54[/tex]Therefore the new area is 54.
Wiith this we conclude that the answer is 3.
Line DA bisects angle EAC, line AB is congruent to line BC, measure of angle B is 74 and measure of angle EAD =44 degrees. Find measure of angle EAB.
Answers
From the given information, since AB is congruent to BC then triangle ABC is issoceles,
therefore, the base angles measure the same and they are denoted by x. Since interior angles of any triangle add up to 180, we have
[tex]74+x+x=180[/tex]which gives
[tex]\begin{gathered} 74+2x=180 \\ 2x=180-74 \\ 2x=106 \\ x=\frac{106}{2} \\ x=53 \end{gathered}[/tex]Then, each base angle measure 53 degrees.
On the other hand, since DA bisects angleEAC then angle DAC measure the same as angle EAD, that is,
Therefore, angleEAB is equal to
[tex]m\angle EAB=x+44+44[/tex]By substituting our last result, we have
[tex]\begin{gathered} m\angle EAB=53+44+44 \\ m\angle EAB=53+88 \\ m\angle EAB=141 \end{gathered}[/tex]then, the answer is 141 degrees
(a) Name the vertex (b) Which direction does the graph open? (c) Find the Axis of Symmetry (d) Graph (e) Maximum or Minimum (f) Name the domain and range. (9) Write the equation in standard form
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The vertex of the parabolic equation y = (x+2) (x-2) is at (0,4) .
The given equation is of the form y = (x+2) (x-2).
This can be simplified using the properties of algebra:
y = x² - 4
the graph of the parabolic function y = x² - 4 is attached below.
a) The vertex of this graph is at (0,4) .
b) The graph opens upwards
c)The axis of symmetry of the graph is the y-axis or the line x = 0
e)For finding the maximum and minimum values we find the derivative of x.
y = x² - 4
dy/dx = 2x
at dy/dx = 0 , x = 0
at x=0 , y= - 4
hence the function has a minimum value at -4 and the maximum value of y is infinity.
f) Domain of the function (-∝ < x < ∝)
range of the function ( y ≥ 4 )
g) The equation in the standard form is given by y = x² - 4 .
Disclaimer: The missing equation is y = (x+2)(x-2).
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write a function to describe the following scenario.a garden watering bucket has 3,000 mm of water in it but there is a hole that is leaking 18 mm every minute how much water remains in the container after certain number of minutes? y= ? - __x
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The bucket has 3000 milliliters of water.
It leaks 18ml per minute.
Let "y" represent the remaining water after a certain number of minutes and "x" represent the number of minutes passed.
"3000ml" represents the y-intercept of the function (the amount of water in the bucket at x=0 minutes)
and "-18ml" represents the amount of water that has leaked after a certain amount of time, and is the slope of the function. The value is negative because the volume of the bucket is decreasing as time passes.
Then the function will be
[tex]y=3000-18x[/tex]What specific measure of a geometric figure is shown in the image?90100 110 12080 70 6013014049 15030 40 50 60 70 80140 130 120 110 10070 20 1010 170160 170 1800 i10294 5 632-N5LLLLLLLLگی۔LEO A. A 140 mm side lengthO B. A 40° angleO C. A 140° angleOO D. A 180 mm side length
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ANSWER :
The answer is C. a 140-degree angle
EXPLANATION :
A protractor is used to measure the angle.
From the figure, the angle is 140 degrees.
6. Which of the following statements must be true when 0 < a < 1 ?. sqrt a a >1II. 2a < 1III. a ^ 2 - a ^ 3 < 0A. I onlyB. III onlyC.I and III onlyD.II and III only
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Given:
The following inequalities:
[tex]\frac{\sqrt[]{a}}{a}>1\rightrightarrows\frac{1}{\sqrt[]{a}}[/tex]When 0 < a < 1
So, the denominator will be always < 1
so, all the fraction will be greater than 1
So, the first inequality True
[tex]\begin{gathered} 2a<1 \\ a<\frac{1}{2} \end{gathered}[/tex]when 0 < a < 1
The inequality will be true as a < 1/2
The inequality will be wrong when a >1/2
So, the second inequality is wrong
[tex]\begin{gathered} a^2-a^3<0 \\ a^2(1-a)<0 \end{gathered}[/tex]The inequality true when a >1
so, for 0 < a < 1, the inequality is wrong
So, the answer will be option A. I only
Using the slope formula, find the slope of the line through the points (0, 0) and (5, 20).
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The slope formula for 2 points is
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]where
[tex]\begin{gathered} (x_1,y_1)=(0,0) \\ (x_2,y_2)=(5,20) \end{gathered}[/tex]By substituting these values into the slope formula, we get
[tex]\begin{gathered} m=\frac{20-0}{5-0} \\ m=\frac{20}{5} \\ m=4 \end{gathered}[/tex]therefore, the slope is 4.
As part of an art installation, Larry wants to tie a piece of rope from the end of a 10m branch that is sticking out of the ground at 23.58 degrees angle to the end of a 1 m tall stake that is 4 m west of the end of the branch. The plans for the installation are shown below. Answer the questions below:1. How many meters above the ground is the end of the branch?2. What is the shortest possible rope length (in meters) that Larry can use to attach the end of the branch to the top of the stake?
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Given data:
The length of branch is BC=10 m.
The given angle is β=23.58 degrees.
1)
The expression for the height of the branch above the ground is,
[tex]h=BC(\sin \beta)[/tex]Substitute the given values in the above expression.
[tex]\begin{gathered} h=(10m)(sin(23.58^{\circ})) \\ =4m\text{ } \end{gathered}[/tex]Thus, the height of the branch above the ground is 4 m.
a right triangle is shownwhich angle measure is closet to x
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We know that
[tex]\cos (x)=\frac{20}{24}[/tex]Solving for x,
[tex]\begin{gathered} x=\cos ^{-1}(\frac{20}{24}) \\ \Rightarrow x=33.56 \end{gathered}[/tex]x is aproximately 33.56
Is the expression 4sr2(2rs + 3s) completely factored? Complete the sentence with the correct explanation.
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The expression 4sr²(2rs + 3s) is not completely factored.
How to factor an expression?An algebraic expression consists of unknown variables, numbers and arithmetic operators.
In other words, an expression or algebraic expression is any mathematical statement which consists of numbers, variables and an arithmetic operation between them.
An expression is completely factored when no further factoring is possible.
Therefore, let's check if the expression is completely factored.
4sr²(2rs + 3s)
The expression still have a common factor which is s. This means its not completely factored.
The complete factorisation is as follows;
4sr²(2rs + 3s) = 4s²r²(2r + 3)
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In the diagram below AB⊥CD and bisects ∠MOP.(a) If m∠MOP=130° find m∠POD.(b) If m∠COM=38°, find m∠MOP and m∠POD.
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A
Since AB in perpendicular to CD and bisects mThis can be written as
[tex]m<\text{MOP}+m<\text{COM}+m<\text{DOP}=180\text{ (1)}[/tex]but
[tex]m<\text{COM}=m<\text{DOP}[/tex]then
[tex]m<\text{MOP}+2m<\text{DOP}=180[/tex]pluggin the value of the angle m[tex]\begin{gathered} 130+2m<\text{DOP}=180 \\ 2m<\text{DOP}=180-130 \\ m<\text{DOP}=\frac{50}{2} \\ m<\text{DOP}=25 \end{gathered}[/tex]Therefore the angle m
B
As we mentioned above the angle mthen m
Using equation (1) of part to find the angle m[tex]\begin{gathered} m<\text{MOP}+38+38=180 \\ m<\text{MOP}=180-76 \\ m<\text{MOP}=104 \end{gathered}[/tex]therefore the angle m
x+4/-2=-1how to solve this problem
Answers
Solve;
[tex]\begin{gathered} \frac{x+4}{-2}=-1 \\ \text{Cross multiply and you have;} \\ x+4=-2\times-1 \\ x+4=2 \\ \text{Subtract 4 from both sides of the equation} \\ x+4-4=2-4 \\ x=-2 \end{gathered}[/tex]what the lowest terms for 15/75
Answers
the given expression is
15/ 75
that is
1/5
thus, the lowest term is 1/5
Assume the given function is one-to-one. Find the indicated value:If f(3)=2 then f^{-1}(2)=AnswerIf f^{-1}(-2)=-1 then f(-1)=?Answer
Answers
The question asks us to perform the inverse of two functions.
To solve this question, we need to understand how the inverse of a function works.
The inverse of a function is defined thus:
[tex]\begin{gathered} \text{if }f(x)=y \\ x=f^{-1}(y) \end{gathered}[/tex]With this definition, we can solve the questions.
Question 1:
[tex]\begin{gathered} f(3)=2 \\ \therefore f^{-1}(2)=3_{} \end{gathered}[/tex]Question 2:
[tex]\begin{gathered} f^{-1}(-2)=-1_{} \\ \\ \therefore f(-1)=-2 \end{gathered}[/tex]Thus, the answers are
[tex]\begin{gathered} \text{Question 1:} \\ f^{-1}(2)=3 \\ \\ \text{Question 2:} \\ f(-1)=-2 \end{gathered}[/tex]
find the upper and lower sums for the region bounded by the graph of the function and the x-axis on the given interval. Leave your answer in terms of n, the number of subintervals.
Answers
Explanation
The area under a curve between two points can be found by doing a definite integral between the two points
Step 1
a) set the intergral
[tex]\begin{gathered} limits:\text{ 1 and 2} \\ function:\text{ f\lparen x\rparen=6-2x} \end{gathered}[/tex]hence
[tex]Area=\int_1^26-2x[/tex]Step 2
evaluate
let ; numbers of intervals
[tex]\begin{gathered} \begin{equation*} \int_1^26-2x \end{equation*} \\ \int_1^26-2x=\lbrack6x-x^2\rbrack=(12-4)-(6-1)=8-5=3 \end{gathered}[/tex]therefore, the area is
[tex]area=3\text{ units }^2[/tex]
I hope this helps you