neutral atoms contain equal numbers of

Answers

Answer 1

Answer:

protons and electrons

Explanation:


Related Questions

If compound has molecular weight of 114.22g/mole and its empirical formula is C4H9 FIND its molecular formulaa. C12 H27b) C16 H36c) C8 H18d) C4 H9

Answers

Answer

c) CH₁

Explanation

Given that:

A compound has a molecular weight of 114.22 g/mol

The empirical formula for the compound is C₄H₉

What to find:

To determine the molecular formula for the compound.

Step-by-step solution:

(Empirica formula)n = (Molecular weight)

(C₄H₉)n = 114.22

(4 x 12.01 + 9 x 1.01)n = 114.22

(48.04 + 9.09)n = 114.22

57.13n = 114.22

Divide both sides by 57.13

n = 114.22/57.13

n = 2

Therefore, the molecular formula for the compound is (C₄H₉)₂ = CH₁

The correct answer is option c) CH₁

Aluminum bromide can be prepared by reacting small pieces of aluminum foil with liquid bromine at room temperature. The balanced chemical reaction is:2Al(s) + 3Br2(l) → 2AlBr3(s)How many moles of Br2 are needed to produce 5 mol of AlBr3, if sufficient Al is present?

Answers

Based on the mole ratio from the chemical reaction 3 moles of Br2 produces 2 moles of AlBr3. We can set this equation up to determine the unknown:

[tex]\begin{gathered} \frac{2}{3}=\frac{x}{5} \\ 3x=2\times5 \\ x=\frac{10}{3} \\ x=3.3moles \end{gathered}[/tex]

3.3 moles of Br2 is needed to reacts with 5 mol of AlBr3.

How many grams of H3PO4 could be produced from 94 g of H2O and 186 g of PCL5 according to the equation below?

Answers

Answer:

[tex]89.4\text{ g of H}_3PO_4[/tex]

Explanation:

Here, we want to get the mass of H3PO4 produced

We start by getting the balanced equation of reaction:

[tex]PCl_5\text{ + 4H}_2O\text{ }\rightarrow\text{ 5HCl + H}_3PO_4[/tex]

The mass of H3PO4 produced would be based on the limiting reactant

The limiting reactant here is the one that would produce less amount of the product H3PO4

Firstly, let us get the number of moles of H3PO4 produced by each of the reactants

To get this, we start by getting the number of moles of each that reacted

We get this by dividing the masses by the molar masses

For water, we have it that the molar mass is 18 g/mol

Thus, the number of moles would be:

[tex]\frac{94}{18}\text{ = 5.2 moles}[/tex]

From the balanced equation of reaction:

4 moles of water produced 1 mole of H3PO4

5.2 moles of water will produce x moles of H3PO4

Thus:

[tex]\begin{gathered} x\text{ }\times4\text{ = 5.2}\times1 \\ x\text{ = }\frac{5.2}{4}\text{ = 1.3 mole} \end{gathered}[/tex]

For PCl5

The molar mass is 208 g/mol

Thus,we have the number of moles as:

[tex]\frac{186}{208}\text{ = 0.894 mol}[/tex]

From the equation of reaction:

1 mol of PCl5 produced 1 mol of H3PO4

That means 0.894 mol of PCl5 produced 0.894 mol of H3PO4

Since PCl5 produced a lesser amount of moles of water, that means, it is the limiting reactant

To get the mass of H3PO4 produced, we multiply this number of moles by

the molar mass of H3PO4

The molar mass of H3PO4 is 100 g/mol

Thus, we have the mass of H3PO4 produced as:

[tex]0.894\text{ }\times\text{ 100 = 89.4 g}[/tex]

Perform the following operationand express the answer inscientific notation.5.4x103 x 1.2x107[ ? ]x10[?]Coefficient (green) Exponent (yellow)tCoefficient (green)Enter

Answers

Since the operation is a multiplication, the order in which we made the multiplications doesn't matter, so we can reoprder it:

[tex]5.4\times10^3\times1.2\times10^7=5.4\times1.2\times10^3\times10^7[/tex]

Now, we calculate each of them:

[tex]6.48\times10^{3+7}=6.48\times10^{10}[/tex]

CaCO3(s) + 2HCl(aq) ---> CaCl2(s) + CO2(g) + H2O(ℓ)What would be the volume of CO2 (at STP) produced from the complete reaction of 10.0 grams of CaCO3?

Answers

The equation is balanced since the number of atoms of each element is the same on each side of the reaction.

Now, we will calculate the number of moles present in 10 grams of CaCO3. We will use the molar mass of CaCO3 for this

[tex]\begin{gathered} lesofCaCO3=gCaCO_3\times\frac{1molCaCO_3}{MolarMass,\text{gCaCO}_3} \\ MolesofCaCO3=10.0gCaCO_3\times\frac{1molCaCO_3}{100.0869gCaCO_3}=0.1molCaCO_3 \end{gathered}[/tex]

Assuming that the rest of the reactants are in excess, 0.1 mol of CaCO3 will react and form 0.1 mol of CO2, since the ratio is 1 to 1.

Now to calculate the volume, we can apply the ideal gas law which tells us:

[tex]PV=nR_{}T[/tex]

Where,

P is the pressure (STP) =1 atm

V is the volume in Liters

n is the number of moles = 0.1 mol CO2

R is a constant = 0.08206 (atm L)/(mol K)

T is the temperature (STP)= 273.15K

Now, we clear the volume and write the known values:

[tex]\begin{gathered} V=\frac{nR_{}T}{P} \\ V=\frac{0.1\text{mol}\times0.08206\frac{atm.L}{mol.K}\times273.15K}{1atm} \\ V=2.2L \end{gathered}[/tex]

The volume of CO2(at STP) produced would be 2.2L

What is the pressure in a 7.00 L tank with 1.73 grams of hydrogen gas at 375 K?

Answers

Considering the ideal gas law, the pressure in a 7.00 L tank with 1.73 grams of hydrogen gas at 375 K is 26.5987 atm.

Definition of ideal gas law

An ideal gas is called a hypothetical or theoretical gas, which would be composed of particles that move randomly and without interacting with each other.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar gas constant:

P×V = n×R×T

Pressure in this case

In this case, you know:

P= ?V= 7 Lmass of hydrogen= 1.73 gmolar mass of hydrogen= 1 g/molen= mass of hydrogen× molar mass of hydrogen= 1.73 g÷ 1 g/mole= 1.73 molesR= 0.082 atmL/molKT= 375 K

Replacing in the definition of ideal gas law:

P× 2 L = 1.73 moles ×0.082 atmL/molK ×375 K

Solving:

P= (1.73 moles ×0.082 atmL/molK ×375 K)÷ 2 L

P= 26.5987 atm

Finally, the pressure is 26.5987 atm.

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6. What is the percent composition of chlorine in calcium chloride, CaCl₂?a. 32%b. 36%c. 50%d. 64%

Answers

The first step we have to follow is to find the molecular mass of CaCl2.

[tex]\begin{gathered} Ca=40\times1=40 \\ Cl_2=35.45\times2=70.9 \\ CaCl_2=40+70.9=110.9 \end{gathered}[/tex]

Finally divide the mass of Cl2 by the mass of CaCl2 and multiply this product times 100:

[tex]\frac{70.9}{110.9}\cdot100=63.93[/tex]

It means that the correct answer is 64%.

31.The correct name for the compound that has the formula BaCl2 is...Select one:a. Baride chlorine.b. Barium chloride.c. Barium chlorine.d. Barium chlorite.

Answers

ANSWER

option B

EXPLANATION

Given that;

The molecular formula of the compound is given as BaCl2

The compound contain a metal and a non-metal

Ba means Barium

Cl2 is chloride because its a diatomic gas

Then BaCl2 is called Barium chloride

Therefore, the correct answer is option B

I need help on #5-#7

Answers

If 5750 J of energy are added to 455 g of granite at 24 °C. The final temperature of granite is 39.9 °C

Given that :

heat energy = 5750 J

mass of granite = 455 g

initial temperature = 24 °C

specific heat capacity = 0.12 cal / g °C = 0.790 J/ g °C

the expression for the heat capacity is given as :

Q = mcΔT

5750 J = 455 g × 0.790 J/ g °C ( T - 24 °C)

5750 = 359.45 T - 8626.8

T = 39.9 °C

if 5750 J of energy are added to 455 g of granite at 24 °C. The final temperature of granite is 39.9 °C

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Use the equation: 3H2, + N2 —-2NH3, (all are gasses)If you need to make 467L of ammonia gas, how many grams of nitrogen gás do you need to start with?

Answers

1) First, let's rewrite the equation:

3 H2 + N2 ---> 2 NH3

If you need to make 467 L ammonia gas (NH3), let's find out how many moles of it do we need.

For this, we use the molar volume of gases: 22.4L/mol

So:

467 L ------ x mol

22.4 L ----- 1 mol

22.4x = 467

x = 20.8 mol of NH3

2) Now we use the proportion of the chemical equation to find out the quantity in moles of N2 (nitrogen gas):

1 mol of N2 ---- 2 mol of NH3

x mol of N2 ----- 20.8 mol of NH3

2x = 20.8

x = 10.4 mol of N2

3) Now we use the molar mass of N2 to find the quantity in grams that we need to start with:

molar mass N2 = 2x14 = 28 g/mol

Now we use the following equation:

mass = mole × molar mass

mass = 10.4 × 28 = 291.2 grams of Nitrogen Gas

Answer: 291.2 grams of Nitrogen Gas

You have 6.0 g of C2H6 and 20.0 g of O2 for a combustion reaction. If you actuallyproduce 3.80 g of CO2 , What is the percent yield?

Answers

Answer:

The percent yield is 24.2%.

Explanation:

1st) It is necessary to balance the chemical reaction:

[tex]2C_2H_6+7O_2\rightarrow4CO_2+6H_2O[/tex]

2nd) From the balanced reaction, we know that 2 moles of C2H6 react with 7 moles of O2 to produce 4 moles of CO2. With the molar mass of C2H6 (30g/mol), O2 (32g/mol) and CO2 (44g/mol), we can convert the moles to grams:

- C2H6 conversion:

[tex]2moles*\frac{30g}{1mole}=60g[/tex]

- O2 conversion:

[tex]7moles*\frac{32g}{1mole}=224g[/tex]

-CO2 conversion:

[tex]4moles*\frac{44g}{1mole}=176g[/tex]

Now we know that 60g of C2H6 react with 224g of O2 to produce 176g of CO2.

3rd) From the given values of C2H6 (6.0g) and O2 (20.0g), it is necessary to find out which one is the limiting reactant and which one is the excess reactant:

[tex]\begin{gathered} 60gC_2H_6-224gO_2 \\ 6.0gC_2H_6-x=\frac{6.0gC_2H_6*224gO_2}{60gC_2H_6} \\ x=22.4gO_2 \end{gathered}[/tex]

We can see that the 6.0g of C2H6 will need 22.4g of O2 to react, but we only have 20.0g of O2, so O2 is the limiting reactant and C2H6 will be the excess reactant.

4th) Now, using the limiting reactant, we have to calculate the grams of CO2 that should be produced from the stoichiometry of the reaction (this is the Theoretical yield):

[tex]\begin{gathered} 224gO_2-176gCO_2 \\ 20.0gO_2-x=\frac{20.0gO_2*176gCO_2}{224gO_2} \\ x=15.7gCO_2 \end{gathered}[/tex]

5th) Finally, we can calculate the Percent yield of the reaction, by using the Theoretical yield (15.7g) and the Actual yield (3.80g):

[tex]\begin{gathered} PercentYield=\frac{ActualYield}{TheoreticalYield}*100\% \\ PercentY\imaginaryI eld=\frac{3.80g}{15.7g}*100\operatorname{\%} \\ PercentY\mathrm{i}eld=24.2\% \end{gathered}[/tex]

So, the percent yield is 24.2%.

When atoms become bonded with covalent bonds, the result is called a(n):A. ionic bond.B. ion.C. valence.D. molecule.SUBMIT

Answers

Explanation:

A covalent bond occurs when electrons are shared by atoms. Atoms will covalently bond with other atoms to gain stability.

A group of atoms held together by covalent bonds is called a molecule.

Answer: D. molecule

what would be the effect on the melting point of a sample if it were not dried completely after filtering the recrystallized sample?

Answers

It can lower and expand the melting point if the sample is not dried completely.

Impurities may be present in a sample if the drying process is not complete. The melting point is decreased and widened when contaminants are still present in a sample. For instance, if a substance's usual melting point range is 104C to 106C, improper drying could result in the presence of impurities, which would lower and widen the melting point range to something like 85C to 97C.

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during the decomposition of 34 gr ammonia into nitrogen and hydrogen 92 KJ are absorbed. How many grams of ammonia are decomposed when 184 KJ are absorbed? write the decomposition reaction

Answers

Explanation:

Ammonia will decompose into nitrogen gas and hydrogen gas according to the following reaction. In that reaction 92 kJ will be absorbed.

2 NH₃ ----> N₂ + 3 H₂ ΔH = 92 kJ

Since the heat is absorbed, the sign is positive and we can add it to the reactants side.

2 NH₃ + 92 kJ ----> N₂ + 3 H₂

When 92 kJ are absorbed 34 g of ammonia are reacted. We can use that relationship to find the mass of ammonia that reacted when 184 kJ where absorbed.

34 g of NH₃ : 92 kJ

mass of NH₃ = 184 kJ * 34 g of NH₃/(92 kJ)

mass of NH₃ = 68 g

Answer: 68 g of ammonia were decomposed.

2 NH₃ ----> N₂ + 3 H₂ ΔH = 92 kJ

Neon (Z=10) has the minimum electron affinity in the 2nd period in the periodic tableIs it true or false? And why?

Answers

ANSWER

False

EXPLANATION

Electron affinity is defined as the energy released by adding an electron to an isolated gaseous atom

Neon has the electronic configuration of 2, 8, This implies that it belongs to period 2 and group 8

Recall, that Neon is a noble gas. Noble gases do not accept or release electrons.

Hence, neon does not have the tendency to accept or release electrons.

Neon as a noble gas has a large positive value for electron affinity

Therefore, the statement is not TRUE

How do you figure this question out in CHEM 101?What is the mass in grams are in 5.32x10^22 molecules of CO2?

Answers

To answer this question, the first step is to convert the given number of molecules to moles using Avogadro's number:

[tex]5.32\times10^{22}molecules\cdot\frac{1molCO_2}{6.022\times10^{23}molecules}=0.088molCO_2[/tex]

Now, use the molecular weight of CO2 to find the mass of this amount of moles:

[tex]0.088molCO_2\cdot\frac{44g}{molCO_2}=3.872g[/tex]

The mass of 5.32x10^22 molecules of CO2 is 3.872g.

Determine the [H+] of a solution that has a [OH-] of 6.25*10-12. (Enter answer in expanded format not scientific notation)

Answers

answer and explanation

we are given the [OH] concentration as 6.25*10-12

and we know that

[H+][OH-] = 1.0*10^-14

an so using this relationship we can determine the [H+]

[H+][6.25*10-12] = 1.0*10-14

[H+] = 0.0016M

2.Solid iron combines with oxygen gas to form solid iron(III) oxide. Which of the following equations best describes this reaction?Select one:a. Ab. Bc. Cd. D

Answers

ANSWER

option B

EXPLANATION;

The chemical symbol of iron is Fe

The chemical symbol of oxygen is O2

[tex]\text{ 4Fe + 3O}_2\text{ }\rightarrow\text{ 2Fe}_2O_3[/tex]

Therefore, the correct answer is B

9. Calculate the molarity of a 400.0 mL solution that contains 41.5 g of NaCl.

Answers

Answer

1.775 M

Explanation

Given:

Volume of solution, V = 400.0 mL

Mass of NaCl = 45.5 g

What to find:

The molarity of the solution.

Step-by-step solution:

Step 1: Convert the volume from mL to L.

This can be done by dividing the volume in mL by 1000.

V = 400.0 mL = (400.0/1000) = 0.4L

Step 2: Convert the mass of NaCl to moles.

The mass can be converted to moles using the mole formula below:

[tex]\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \end{gathered}[/tex]

From the periodic table, the molar mass is determined to be = 58.44 g/mol

Putting mass = 41.5 g and molar mass = 58.44 g/mol into the formula, we have:

[tex]Moles=\frac{41.5g}{58.44g\text{/}mol}=0.7101\text{ }mol[/tex]

Step 3: Calculate the molarity of the solution using the molarity formula.

Molarity formula is given by:

[tex]Molarity=\frac{Moles}{Volume\text{ }in\text{ }L}[/tex]

Moles= 0.7101 mol and V = 0.4 L

Therefore,

[tex]Molarity=\frac{0.7101mol}{0.4L}=1.775\text{ }M[/tex]

The molarity of a 400.0 mL solution that contains 41.5 g of NaCl = 1.775 M.

why do engineers come up with as many ideas to solve a problem as possible?

Answers

Engineers come up with as many ideas to solve a problem as possible is so as to choose the best which is applicable in helping people.

Who is an Engineer?

This is referred to as an individual or a professional which employs the use of scientific knowledge in the construction and building of different types of machines and tools.

An engineer is someone who has a good analytic and problem solving skills and comes up with many ideas so as to be able to choose the best from the set of alternatives in helping people solve their problems or issues.

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Calculate the molar mass of NaHCO3 and round it to 2 decimal places.

Answers

To calculate the molar mass of NaHCO₃, we need to add the molar mass of each of its atoms.

This compound has 1 atom of Na, 1 of H 1 of C and 3 of O.

The molar mass of these atoms can be consulted on a periodic table, and they are:

[tex]\begin{gathered} M_{Na}=22.9898g/mol \\ M_H=1.0079g/mol \\ M_C=12.0107g/mol \\ M_O=15.9994g/mol \end{gathered}[/tex]

So, the molar mass of NaHCO₃ is:

[tex]\begin{gathered} M_{NaHCO_3}=1\cdot M_{Na}+1\cdot M_H+1\cdot M_C+3\cdot M_O \\ M_{NaHCO_3}=(1\cdot22.9898+1\cdot1.0079+1\cdot12.0107+3\cdot15.9994)g/mol \\ M_{\mleft\{NaHCO_3\mright\}}=\mleft(22.9898+1.0079+12.0107+47.9982\mright)g/mol \\ M_{\mleft\{NaHCO_3\mright\}}=84.0066g/mol\approx84.01g/mol \end{gathered}[/tex]

10.The drink mix and water in a drink solution can be separated by...Select one:a. filtering out the drink mix from the water.b. evaporating the water.c. picking out the drink crystals by hand.d. drawing the drink crystals out with a magnet.

Answers

Answer

b. evaporating the water.

Explanation

The ingredients in a solution cannot be separated by hand because of changes in the ingredients' physical properties. But evaporation can be used to separate some solutions. For example, just in the case of the drink mix and water in a drink solution given.

What physical property can help characterize fragments of glass at a crime scene?

A.
flammability

B.
toxicity

C.
density

D.
volume

Answers

Answer:

I believe it is

C. density

Explanation:

have a nice day!❀

Oxygen gas is made up of diatomic non-polar covalent molecules. This leads to very weak attraction between molecules. Which statement would this best support?

Answers

The oxygen gas is non polar because there is no interaction between the molecules of the gas.

What is a diatomic molecule?

A diatomic molecule is one that has only two atoms in it. These atoms are usually atoms of the same element in the majority of the cases that we encounter. Given the fact that the both atoms belong to the same substance, the electronegativity difference between the atoms is zero.

Given that the electronegativity difference between the atoms is zero, there is little or no interaction between the molecules of the substance. Thus the very weak intermolecular interaction is coming from the fact that there is no kind of interaction between the molecules.

Thus oxygen gas is covalent and the molecules do not interact with each other because the bond is nonpolar.

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Which of the following is a conclusion that the student can draw based on these observations? The two clear liquids-

Answers

In the process that they describe to us, a mixture initially occurs between these two liquids, when they are mixed, a chemical reaction occurs and one of the products obtained is not soluble in the liquids, therefore a precipitate will form. This type of reaction is called a precipitation reaction.

Therefore, the answer will be:

C) Have gone through a chemical reaction in which a new substance called a precipitate was produced

1. A 26.6g sample of mercury is heated to 110.0℃ and then placed in 125g of water in a coffee-cupcalorimeter. The initial temperature of the water is 23.00℃. (c Hg = 0.139 J/g℃). What is the finaltemperature of the water and the mercury? 2. Draw the Lewis bonding structure for PCl3. what would be the hybrid orbitals

Answers

The Lewis structure tells us how atoms are bonded and shows the valence electrons of each element as dots. These valence electrons can be found in the periodic table of the elements, and they coincide with the group number to which the element belongs.

So phosphorus (P) belongs to group 5 and has 5 valence electrons. Chlorine (Cl) is in group 7 and has 7 valence electrons.

The Lewis scheme will be:

The blue dots correspond to the valence electrons of phosphorus, and the purple dots are the electrons of chlorine. The electrons they share can be written with a line.

We have that the geometry of the molecule will be:

Four sp3 type hybrid orbitals are formed, three of which overlap with each of the Cl atoms and the other houses the lone electrons. Sigma type bonds.

Answer: 4 sp3 hybrid orbitals

I’m having trouble figuring out how to do number 13. Iv done some things but still cannot seem to figure it out.

Answers

This is a stoichiometry problem, where we have an initial amount of reactant and we need to find out how much of the product will we end up with, in order to do that we need to:

1. Set up the properly balanced equation, which the question already provided us

2 KClO3 -> 2 KCl + 3 O2

2. Check the molar ratio between the two compounds, which is 2:3, 2 moles of KClO3 will produce 3 moles of O2, but we have 3 moles of KClO3

2 KClO3 = 3 O2

3 KClO3 = x O2

x = 4.5 moles of O2 will be produced from 3 moles of KClO3

3 KClO3

2 KClO3/ 3 O2

4.5 O2

Identify the equation with the elements in BeSO4 in their standard state as the reactants and BeSO4 as the product.

Answers

Answer:

[tex]E[/tex]

Explanation:

Here, we want to identify the elements in BeSO4 in their standard state as the reactants and BeSO4 as the product

From what we have, there are 4 atoms of oxygen, 1 atom of Beryllium, and 1 atom of sulfur

In their standard state, oxygen is a gas, Berrylium and Sulfur are solids

The number of elements atom on the reactant side must be equal to that on the product side

Thus, we have the correct choice of answer as E

Atom A and B both have 10 protons A have 10 B has 11 neutrons, which statement is true A,b have the same element, theyvhave differnet elements, if they have the same mass, only atom b is a isotope

Answers

Atom A and B both have 10 protons A have 10 B has 11 neutrons is A and B are isotopes of same element.

Isotopes are the atoms of same elements , that has same number of proton but different number of neutrons , mass no. is depends on neutrons present in an atom. the given situation is :

                  number of proton      number of neutron

Atom A                10                               10

Atom  B                10                               11

Isotopes are the members of the same family of same elements.

Thus, Atom A and B both have 10 protons A have 10 B has 11 neutrons is A and B are isotopes of same element.

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How many grams are in 4.02 x 10^21 atoms of calcium?

Answers

Answer:

0.268grams

Explanations:

According to the Avogadro's constant

1 mole of an atom = 6.02 * 10^23 molecules

Given the following

atoms of calcium = 4.02 x 10^21 atoms

Determine the moles of calcium

[tex]\begin{gathered} moles\text{ of Ca}=\frac{4.02\times10^{21}}{6.02\times10^{23}} \\ moles\text{ of Ca}=0.668\times10^{21-23} \\ moles\text{ }of\text{ Ca}=0.668\times10^{-2} \\ moles\text{ of Ca}=0.00688moles \end{gathered}[/tex]

Determine the mass of Calcium

[tex]\begin{gathered} Mass=mole\times molar\text{ mass} \\ Mass=0.00688\times40.078 \\ Mass\text{ of Ca}=0.268gram \end{gathered}[/tex]

Hence the required grams in 4.02 x 10^21 atoms of calcium is 0.268grams

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