Answer:
9 m /s
Step-by-step explanation:
To find the speed, take the distance and divide by the time
45 m/ 5 s
9 m /s
Answer:
[tex] \sf9ms ^{ - 1} [/tex]
Step-by-step explanation:
[tex] \sf \: Average \: speed = \frac{ Total \: distance }{Total \: Time}[/tex]
Let us find the average speed now.
[tex] \sf \: Average \: speed = \frac{ Total \: distance }{Total \: Time} \\ \sf \: Average \: speed = \frac{ 45m }{5s} \\ \sf \: Average \: speed = 9ms ^{ - 1} [/tex]
1. Mr. Z's class has 18 boys and 22 girls. What is the ratio of girls to boys?
2. What is the ratio of boys to total students?
3. What is the ratio of girls to total students?
Solve. −45 = −2b + 3 + 8b
Answer:
b= -8
Step-by-step explanation:
just trust me dude. I know what I'm doing
Annie's mother asked Annie to go buy oranges, dog food, and bug spray. Each square's side length is 1 block. How many blocks will Annie have to walk in all if she visits the fruit stand, the pet store, and the supermarket, in that order, before returning home?
Here using the length of square, it is obtained that
Annie walked 14 blocks in total.
What is a square?
Square is a two dimensional four sided figure.
Here,
Length of each side of one square = 1 block
From Annie's home to the supermarket, Annie will have to walk 1 block
From Supermarket to pet store, Annie will have to walk 1 block straight and then 2 blocks to the left
From pet store to the fruit vendor, Annie will have to walk 1 block straight and then 2 blocks to the left
Total number of blocks walked by Annie from home = 1 + 1 + 2+ 1 + 2
= 7 blocks
Total number of blocks walked by Annie while returning home
= 1 + 1 + 2+ 1 + 2
= 7 blocks
Total number of blocks walked by Annie = 7 + 7 = 14 blocks
To learn more about square, refer to the link-
https://brainly.com/question/25092270
#SPJ1
Complete Question
The figure has been attached
6. Chester paid a $30 membership fee to a toddler gym and $8 for each of 6 tumbling
classes for his son. The expression 30 + 8 x 6 can be used to evaluate the total cost
of the program. Is the cost $228 or $78? Explain.
Answer:
$78
Step-by-step explanation:
pemdas says we multiply then add
8x6+30
48+30
78
It is $78 and not $228 because we do not add first when doing order of operations and when we multiply first we get 78 also it’s each tumbling is 8 dollars and there were 6 of them so we just multiply the cost by each tumbling and add the membership fee after.
Hopes this helps please mark brainliest
i need help with a couple more im really confused. i'll post all of them.
The all three given problem are equivalent to each other.
64(2⁻ˣ)64/2ˣ64(1/2)ˣWhat is referred as the index/ indices?An index can be assigned to a number or a variable. A variable's index (or constant) is a value raised to a power of a variable. Indexes are also referred to as powers and exponents. It indicates how many times a provided number must be multiplied.If a constant or parameter has an index of '0,' the outcome will be one, regardless of the base value.If the index is negative, it can be represented by the reciprocal of a positive score raised to the identical variable.For the given three problems;
Problem 1: 64(2⁻ˣ)
Taking reciprocal of the (2⁻ˣ),
64/(2ˣ) ....1
Problem 2: 64/2ˣ ....2
Problem 3: 64(1/2)ˣ
Taking (1)ˣ = 1.
64/(2)ˣ ....3
Thus, three equation 1, 2 and 3 are in the same form so are equivalent.
To know more about the index/ indices, here
https://brainly.com/question/10339517
#SPJ1
find 3 consecutive odd integers when the sum of the first and third integer is 26
Let's call the first odd number x.
The next odd number will be x + 2, and the last one will be x + 4.
If the sum of the first number and the last one is 26, we have that:
[tex]\begin{gathered} x+x+4=26 \\ 2x+4=26 \\ 2x=22 \\ x=\frac{22}{2}=11 \end{gathered}[/tex]So the numbers are:
[tex]\begin{gathered} x\to11 \\ x+2\to13 \\ x+4\to15 \end{gathered}[/tex]11, 13 and 15.
Solve for z in -3 < z-1 < 3.Give the result in the interval notation and graph on a number line
Answer:
(-2,4)
Explanation:
Given the inequality:
[tex]-3First, we add 1 to all parts of the inequality.[tex]\begin{gathered} -3+1We can represent this in interval notation as:[tex](-2,4)[/tex]The solution set is graphed on the number line below:
help meeeeeeeeeeeeeee pleaseeeeeee
Answer: 19.6 feet
Step-by-step explanation:
Using the Pythagorean theorem,
[tex]x^2 +(x+6)^2 =48^2\\\\x^2 +x^2 +12x+36=2304\\\\2x^2 +12x-2268=0\\\\x^2 +6x-1134=0\\\\x=\frac{-6 \pm \sqrt{6^2 -4(1)(-1134)}}{2(1)}\\\\x \approx 30.8 \text{ } (x > 0)\\\\\implies x+(x+6) \approx 67.6\\\\\therefore (x+(x+6))-48 \approx 19.6[/tex]
Complete the similarity statement relating the three triangles in the diagram. Show work.
Answer:
[tex]\Delta JKM\approx\Delta MKL\approx\Delta JML[/tex]Explanation:
There are three right angled triangles are in the diagram of three different sizes.
Identify the right angles.
In the first triangle, the right angle is angle M. In the second one, the right angle is angle K and in the third triangle, it is angle K.
Now, identify the shortest sides of each.
The shortest side in the first triangle is MJ, in the second triangle, it is JK and in the third triangle, it is MK.
In the given triangle JKM, notice that JK is the shortest side and angle K is the right angle. Write the other two tringles also in the similar form with the first two letters gives the short side and middle letter represents the right angle.
So, the similarity statement is
[tex]\Delta JKM\approx\Delta MKL\approx\Delta JML[/tex]Help
In 1846 the depth of the river was 5 feet deep.
In 1847 it dropped to 3.8 feet.
This year, 1848, it rose to 6.4 feet.
Find the percent change in river depth & complete the table.
The percent change in river depth is 52%
How to calculate the percentage?From the information, the depth of the river was 5 feet deep, it dropped to 3.8 feet and in 1848, it rose to 6.4 feet. The new feet will be:
= -5 - 3.8 + 6.4
= 2.4
Therefore, the percentage change will be:
= New feet / Initial feet × 100
= (5 - 2.4) / 5 × 100
= 2.6 / 5 × 100
= 52%
Note that there was no table given.
Learn more about percentages on:
brainly.com/question/24304697
#SPJ1
The area of circular pound is 21.5 m2. Work out the diameter of the circle. Give your answer correct to the nearest centimetre.
The diameter of the circle is 5.2m.
The area of circular pond is 21.5 m2
area of a circle is given by the formula
area = πr²
21.5 = 3.14 r²
r² = 6.84
r = ±2.6
r is a length and it cannot be negative
So, r = 2.6
Diameter is twice of radius
d = 2r
d = 2(2.6)
d = 5.2
Therefore, the diameter of the circle is 5.2m.
To learn more about circle refer here
https://brainly.com/question/24375372
#SPJ1
Solve the equations.a) 4t^2 - 5t = 0d) (y + 6)(y - 6) = - (y + 6)^2h) h) (u - 4)(u + 4) = (u + 2)(u - 2).
The equations are given
a) 4t^2 - 5t = 0
d) (y + 6)(y - 6) = - (y + 6)^2
h) (u - 4)(u + 4) = (u + 2)(u - 2).
Explanationa. 4t^2 - 5t = 0
[tex]\begin{gathered} t(4t-5)=0 \\ t=0,4t-5=0 \\ t=0,t=\frac{5}{4}=1.25 \end{gathered}[/tex]d. (y + 6)(y - 6) = - (y + 6)^2
[tex]\begin{gathered} y^2-6y+6y-36=-(y^2+36+12y) \\ y^2-36=-y^2-36-12y \\ y^2+y^2+36-36+12y=0 \\ 2y^2+12y=0 \\ 2y(y+6)=0 \\ y=0,y=-6 \end{gathered}[/tex]h. (u - 4)(u + 4) = (u + 2)(u - 2).
[tex]\begin{gathered} u^2+4u-4u-16=u^2-2u+2u-4 \\ u^2-16=u^2-4 \\ u^2-16-u^2+4=0 \\ -12\ne0 \end{gathered}[/tex]Answer
Hence the solution to the equations are
[tex]\begin{gathered} a.t=0,1.25 \\ d.\text{ y=0,-6} \\ h.\text{ no solution} \end{gathered}[/tex]Which expression is a factored form of −32m+96 −8(4m+12) 32(−m−3) 16(−2m+6) 32(−m+3)
Answer:
32(−m+3)
Step-by-step explanation:
1. Find the greatest common factor.
32 is the GCF
2. Factor.
32(-m + 3) -- you can check with distrubutive property.
ſ x - 5y = -9( 4x + 4y = - 12Step 1 of 2: Determine if the point (-4,1) lies on both of the lines in the system of equations by substituting theordered pair into both equations.
Given:
[tex]\begin{gathered} x-5y=-9\ldots\ldots(1) \\ 4x+4y=-12\ldots\text{.}\mathrm{}(2) \end{gathered}[/tex]The given point is (-4,1)
Let's check the ordered pair (-4,1) in the first equation
[tex]\begin{gathered} x-5y=-9 \\ (-4)-5(1)=-9 \\ -4-5=-9 \\ -9=-9 \end{gathered}[/tex]Hence, (-4,1) is a solution of the first equation x-5y=-9.
Now, let's check (-4,1) in the second equation.
[tex]\begin{gathered} 4x+4y=-12 \\ 4(-4)+4(1)=-12 \\ -16+4=-12 \\ -12=-12 \end{gathered}[/tex]So, (-4,1) is a solution of the second equation 4x+4y=-12.
Hence, (-4,1) is a solution of both equation in the system, then it is a solution to the overall system.
What number is in the hundreds place after
simplifying?
(21 × 10¹)+(3×
X
10²) + (9 × 10²)
a) 4
b) 1
c) 3
d) 7
The digit in the hundreds place is 4
From the question, we have
(21 × 10¹)+(3×10²) + (9 × 10²)
=210+300+900
=1410
The digit in the hundreds place is 4 and the value is 400.
Multiplication:
Mathematicians use multiplication to calculate the product of two or more numbers. It is a fundamental operation in mathematics that is frequently utilized in everyday life. When we need to combine groups of similar sizes, we utilize multiplication. The fundamental concept of repeatedly adding the same number is represented by the process of multiplication. The results of multiplying two or more numbers are known as the product of those numbers, and the factors that are multiplied are referred to as the factors. Repeated addition of the same number is made easier by multiplying the numbers.
To learn more about multiplication visit: https://brainly.com/question/5992872
#SPJ1
6. Find the are of the Rectangle
776
in
13
in
Answer:
about 3.09
Step-by-step explanation:
A = l x w
A = 13/7 x 7/6
A = 1.857 x 1.666
A = 3.09
Hope it helps!
point(10) On Myra's family vacation, her mom drove on the highway at aconstant speed of 60 miles per hour. Based on this rate, which of thefollowing times and miles driven are correct? Select all that apply. GRP.30190 miles driven in 3 hours150 miles driven in 2.5 hours30 miles driven in 30 minutes
Hello, I need help solving is and finding the checkpoints
161 feet lower
166 feet
Explanationsa) Given the following parameters
Distance of checkpoint 3 above the sea = -197 feet
Distance of checkpoint 5 above the sea = -36 feet
Determine the distance between the checkpoints
Distance = checkpoint 5 - (checkpoint 3)
Distance = -36 - (-197)
Distance = -36 + 197
Distance = 161feet
Hence checkpoint 3 is 161 feet lower than checkpoint 5
b) If the top of the hill is 363feet above check point 3, the altitude of the top of the hill is given as:
Altitude = -197 + 363
Altitude = 166feet
Hence the altitude of the top of the hills is 166feet
If ABCD is dilated by a factor of 2, thecoordinate of B' would be:543С2B1-8 -7-6-5-4-3-2-1 012.34567891011-1A-2D-3B' = ([?], [ ]=4Cotor
We have a figure ABCD that is dilated by a factor of 2.
We have to find the coordinate of the image point B'.
If the center of dilation is the origin (0,0) and the factor is k = 2, we can write the rule:
[tex](x,y)\longrightarrow(2x,2y)[/tex]Then, for B(-1,1), we will get:
[tex]B=(-1,1)\longrightarrow B^{\prime}=(2\cdot(-1),2\cdot1)=(-2,2)[/tex]Answer: B' = (-2,2)
Suppose that h(x) varies inversely with x and h(x)=50 when x = 0. 25. What is h(x) when x = 2?.
If h(x) varies inversely with x , then the value of h(x) is 6.25 , when x = 2 .
In the question ,
it is given that ,
the function h(x) varies inversely with x ,
that means h(x) ∝ 1/x ,
to remove the proportionality sign , we write the constant of proportionality "k",
h(x) = k*(1/x)
given , that h(x)=50 when x = 0. 25
Substituting the values we get
50 = k*(1/0.25)
50 = k/0.25
k = 50×0.25
k = 12.5
So , the equation becomes
h(x) = 12.5/x
to find the value of h(x) when x = 2, we put x = 2 , in the equation ,
h(2) = 12.5/2
= 6.25
Therefore , If h(x) varies inversely with x , then the value of h(x) is 6.25 , when x = 2 .
Learn more about Equations here
https://brainly.com/question/6995691
#SPJ4
the product of 5 - 2i and i is
Answer:
5i + 2
Step-by-step explanation:
(5-2i)(i)
5i - 2i^2
i^2= -1
5i -2(-1)
= 5i + 2
solveeeeeeeeeeeee for x
Answer:
7.5/3
Step-by-step explanation:
set AC and BD equal to eachother because they are equal and solve
$57Mr. Harris attaches a full tank of propane to his grill. Then he turns on the grill and cooks food for a barbecue.Which graph shows the relationship between the amount of propane in the tank and time?OAOB.РРtTime (min.)PropanePropane
As he cooks on the barbecue, the weight of the tank goes down because some of the propane is getting used up.
Given that is happening, the graph showing that has to start with a lot in it and slowly decrease.
That being said, the graph representing the decrease in propane as time passes is C.
Answer: C.
help me out with this question..this is a k11..remember this is a practice question not a graded one
Each flight has a probability of 60% or 0.6 of being on time. This means that its complement, or the probability that the flight isn't on time is:
[tex]\text{\textasciitilde{}P(on time)}=1-0.6=0.4[/tex]It is 40% or 0.4. "~P(on time)" stands for the probability of the flight not being on time.
1. The probability that at least 2 flights are on time is:
To find the probability that 2 or more flights are on time we can fight the probability that "0" or "1" are not on time.
[tex]P(0\text{ on time)}=0.4^9=0.000262144[/tex][tex]\begin{gathered} P(1\text{ on time})=\frac{9!}{1!\cdot(9-1)!}\cdot0.6\cdot(0.4)^8 \\ P(1\text{ on time)}=9\cdot0.6\cdot(0.4)^8=0.003538944 \end{gathered}[/tex][tex]\begin{gathered} P(1\text{ or less on time)}=P(0\text{ on time)}+P(1\text{ on time)} \\ P(1\text{ or less on time)}=0.000262144+0.003538944=0.003801088 \end{gathered}[/tex]The probability of 2 or more flights are on time is:
[tex]P(2\text{ or more on time)}\cdot=1-0.003801088=0.996198912[/tex]The probability of 2 flights or more are on time is 0.996198912
2.
We need to calculate the probabilities of 7,8 and 9 flights are on time and then subtract by 1.
[tex]\begin{gathered} P(7)=\frac{9!}{7!\cdot(9-7)!}\cdot0.6^7\cdot0.4^2 \\ P(7)=36\cdot0.6^7\cdot0.4^2=0.161243136 \end{gathered}[/tex][tex]\begin{gathered} P(8)=\frac{9!}{8!\cdot(9-8)!}\cdot0.6^8\cdot0.4 \\ P(8)=9\cdot0.6^8\cdot0.4=0.060466176 \end{gathered}[/tex][tex]P(9)=0.6^9=0.010077696[/tex]The probability of at most 6 flights are on time is:
[tex]\begin{gathered} P(6\text{ or less on time) = 1 - (}P(7)+P(8)+P(9)) \\ P(6\text{ or less on time) = 1-(0.161243136+0.060466176+0.010077696)=}0.768212992 \end{gathered}[/tex]The probability of 6 or less are on time is 0.768212992.
3.
The probability of exactly 5 flights are on time is:
[tex]\begin{gathered} P(5)=\frac{9!}{5!(9-5)!}0.6^5\cdot0.4^4 \\ P(5)=126\cdot0.6^5\cdot0.4^4=0.250822656 \end{gathered}[/tex]The probability of exactly 5 flights are on time is 0.250822656.
Which of the following equation has one solution?
Responses
4x + 2x = 6x - 4
3 (2x + 4) = 2 (2x - 4)
5(x - 3) = 5x - 3
2x = 2x + 4
a) 4x + 2x = 6x - 4
= 6x = 6x - 4
cannot be solved further.
b) 3(2x + 4) = 2(2x - 4)
= 6x + 12 = 4x - 4
(bring the numbers and variables on one side)
= 6x + 4x = 12 - 4
10x = 8
x = 8/10 = 4/5
can be solved.
c) 5(x - 3) = 5x - 3
= 5x - 15 = 5x - 3
= (bring the variables and numbers on one side)
5x + 5x = -15 - 3
= 10x = -18
x = -18/10 = 9/5
can be solved
d) 2x = 2x + 4
= 2x + 2x = 4
= 4x = 4
x = 4/4 OR 1.
THUS, (B, (C AND (D CAN BE SOLVED WITH ONE SOLUTION.……………………………………………………..
?
Please type what you are trying to solve or any questions that you would like answers for.
an arithmetic sequence has these properties: a1=2an = an-1 + 5 what are the first four terms of the sequence?
we have that the arithmetic sequence have:
[tex]\begin{gathered} a_1=2 \\ a_n=a_{n-1}+5 \end{gathered}[/tex]so we can replace for n=2,3,and 4 to find the first four terms so:
for n=2
[tex]\begin{gathered} a_2=a_{2-1}+5 \\ a_2=a_1+5 \\ a_2=2+5 \\ a_2=7 \end{gathered}[/tex]for n=3
[tex]\begin{gathered} a_3=a_{3-1}+5 \\ a_3=a_2+5 \\ a_3=7+5 \\ a_3=12 \end{gathered}[/tex]and for n=4
[tex]\begin{gathered} a_4=a_{4-1}+5 \\ a_4=a_3+5 \\ a_4=12+5 \\ a_4=17 \end{gathered}[/tex]So the first four numbers are
[tex]2,7,12,17[/tex]Use the elimination method to solve the system of equations.3x + 4y = 8x - y = 12
Answer:
We have to use to elimination method to solve the provided system of equations, this method essentially involves eliminating one of the variables in the first equation by adding or subtracting a multiple of the second equation:
[tex]\begin{gathered} 3x+4y=8\rightarrow(1) \\ \\ x-y=12\rightarrow(2) \end{gathered}[/tex]The elimination of the variable y in equation (1) is achieved by adding the 4 times the equation 2 into the equation (1), the steps of the process are as follows:
[tex]\begin{gathered} 3x+4y=8 \\ \\ + \\ \\ 4\times(x-y)=4\times12 \\ \\ ------------------------------- \\ \\ 3x+4x=8+48 \\ \\ \\ 7x=56 \\ \\ \\ x=8 \end{gathered}[/tex]We have found the x value, the last step is to plug in the variable x value in any of the (1) or (2) equations, and solve for the y variable, the steps are as follows:
[tex]\begin{gathered} x-y=12 \\ \\ x=8 \\ \\ \therefore\Rightarrow \\ \\ 8-y=12\rightarrow y=8-12=-4 \\ \\ y=-4 \end{gathered}[/tex]The final answer is as follows:
[tex](8,-4)\Rightarrow\text{ Option \lparen B\rparen}[/tex]Therefore the answer is Option(B).
while shopping for clothes, Daniel spent $26 less than 2 times what curtis spent. Daniel spent $10. write and solve an equation to find how much curtis spent. let x represent how much curtis spent
while shopping for clothes, Daniel spent $26 less than 2 times what curtis spent. Daniel spent $10. write and solve an equation to find how much curtis spent. let x represent how much curtis spent
Let
x ------> amount that Curtis spent
we have that
10=2x-26 ------> equation that represent this situation
solve for x
2x=10+26
2x=36
x=$18
therefore
Curtis spent $18laws exponents multiplication band power to a power simplifymake it small steps please the smallest you can like the minimum steps
Answer:
-64x^12
Explanation:
Given the expression
m = -4x^4
You are to look for m^3 as shown;
[tex]\begin{gathered} m=-4x^4 \\ m^3\text{ = (-4x}^4\text{)}^3 \\ m^3=(-4)^3\times(x^4)^3 \end{gathered}[/tex]Open the bracket:
[tex]\begin{gathered} (-4)^3\text{ }\times(x^4)^3\text{ = (-4}\times-4\times-4\text{)}\times x^{^{12}} \\ (-4)^3\text{ }\times(x^4)^3\text{ = (16}\times-4\text{)}\times x^{^{12}} \\ (-4)^3\text{ }\times(x^4)^3=-64x^{12} \end{gathered}[/tex]THe correct answer is -64x^12