If x is perpendicular to a and X is perpendicular to b then____X is perpendicular to a A // BA is perpendicular to YX // Y
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Related Questions
An automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars overdomestic. Supposed a sample of 879 new car buyers is drawn. Of those sample 298 preferred foreign over domestic cars. Using the data estimate the proportion of new car buyers who prefer foreign cars. Enter your answer as a fraction or a decimal number rounded to three decimal places
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ANSWER:
0.339
STEP-BY-STEP EXPLANATION:
We can determine the proportion since we know the general sample and the specific sample, just like this:
[tex]\begin{gathered} p=\frac{298}{879} \\ \\ p=0.339 \end{gathered}[/tex]The proportion is 0.339
A projectile is launched from the ground at 128 feet per second and will hit the ground after a certain amount of time. It models the function g(x) = -16x2 + 128x, where x represents the time of the of the flight (in seconds) of the projectile. What is an appropriate domain for this model? 00 0
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time can only take values greater than or equal to zero, so the domain starts on 0
the las point of the domain is when the projectile hit the ground, this means when g=0
now we will replace g=0 o find the last value of the domain
[tex]\begin{gathered} g=0 \\ -16x^2+128x=0 \end{gathered}[/tex]solve x to know the last time
[tex]\begin{gathered} 16x(-x+8)=0 \\ -x+8=\frac{0}{16x} \\ -x+8=0 \\ -x=-8 \\ x=8 \\ \end{gathered}[/tex]the last time in seconds of the model is 8
so the domain is
[tex]\lbrack0,8\rbrack[/tex]Mark to review later..3. Javier purchased a laptop at an electronics store 57 days ago for $385. The store's policy states that items can be returnedwithin 60 days for 90% of the original purchase price. Items can still be returned after 60 days, but there is an additional restockingfee of 2%. If Javier returns the computer today, what is the total amount he will receive as a refund
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Javier has purchased the laptop 57 days ago, and the store's policy for items returned within 60 days is a 90% refund of the original price. Since Javier returned the item today, which is exactly 57 days right after his purchase, the 90% refund will be made. To solve the refunded price, we just multiply the cost of the laptop by the percent refund. We have ($385) x (90%) = $346.5.
Hence, Javier gets $346.5 as a refund on returning the laptop today.
36 inches 23 inches is what fraction of a yard
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If a yard contains 36 inches, then 21 inches is the 7/12 fraction of a yard
A yard contains 36 inches
We know
One yard = 36 inches
Here we have to use the unitary method for the conversion
The unitary method is the method of the value of a single unit.
36 inches = 1 yard
Then one inch = 1 / 36 yard
21 inches = (1 / 36) × 21
Multiply the terms
= 21 / 36
Divide both numerator and denominator by 3
= (21 / 3) / (36 / 3)
Divide the terms
= 7 /12 yard
Hence, if a yard contains 36 inches, then 21 inches is the 7/12 fraction of a yard
The complete question is
A yard contains 36 inches. 21 inches is what fraction of a yard ?
Learn more about unitary method here
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don’t be slow pls i only care about the answers and the steps you did
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Problem N 12
we have that
m by exterior angle
substitute
mm
Problem N 13
we have that
m by exterior angle
substitute given values
45=(1/2){arc JK-55}
90=arcJK-55
arc JK=90+55
arc JK=145 degreesProblem N 14
we have that
m by exterior angle
substitute given values
50=(1/2){110-arc JL}
100=110-arc JL
arc JL=110-100
arc JL=10 degrees⦁ A vine called the mile-a-minute weed is known for growing at a very fast rate. It can grow up to 0.5 ft per day. How fast in inches per hour can the mile-a-minute weed grow up to? Show your work using the correct conversion factors.
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Answer:
"0.5 ft * 12 = 6 inches (because there are 12 inches in 1 foot)1 day = 24 hours0.5 ft per day = 6 inches in 24 hoursInches grown in one hour = 6/24 = 0.25"
Step-by-step explanation:
a and b are supplementary angles. if ma=(2x-24)°and mb=(5x-27)°, find the measure for b
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Supplementary angles add up 180°.
So:
M
(2x-24) + (5x-27) = 180
Solve for x:
2x - 24 + 5x - 27 = 180
Combine like terms:
2x + 5x - 24 -27 = 180
7x -51 = 180
7x = 180 +51
7x = 231
x= 231/7
x= 33
Replace x on m
m< B = 5x-27 = 5 (33) - 27 = 165-27 = 138
m
luann is playing a math game . she chose three cards - first card: -12 - second card: 3- thrid card: -5 what is the sum of the value ?
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we sum the values
[tex]-12+3+(-5)=-12+3-5=-14[/tex]answer: -14
PLEASE HELP IM DESPERATE AND NEED THE ANSWER NOW WILL GIVE BRAINLIEST 50 POINTS
△ABC has a right angle at C, BC=9.2 centimeters, and m∠A=63∘.
What is CA ?
Enter your answer rounded to the nearest tenth in the box.
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Answer:
CA = 4.7 cm
Step-by-step explanation:
There're two ways to solve that
Solve the system algebraically 5 x - y = 0
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Answer:
To solve the system of equations,
[tex]\begin{gathered} 5x-y=0 \\ \frac{y^2}{90}-\frac{x^2}{36}=1 \end{gathered}[/tex]Solving 1st equation we get,
[tex]y=5x[/tex][tex]\frac{y^2}{90}-\frac{x^2}{36}=1[/tex]Substitute y=5x in the above equation, we get
[tex]\frac{(5x)^2}{90}-\frac{x^2}{36}=1[/tex][tex]\frac{25x^2}{90}-\frac{x^2}{36}=1[/tex][tex]\frac{5x^2}{18}-\frac{x^2}{36}=1[/tex][tex]\frac{10x^2-x^2}{36}=1[/tex][tex]\frac{9x^2}{36}=1[/tex][tex]\frac{x^2}{4}=1[/tex][tex]x^2=4[/tex][tex]x=\pm2[/tex]when x=2, we get y=5x=5(2)=10
when x=-2, we get y=5x=5(-2)=-10
There are two solution for the given system.
[tex](2,10),(2,-10)[/tex]Answer is: x=2,y=10 and x=2,y=-10
Find the circumference and area of each. Round for the nearest tenth:
1) a circle has a radius of 2 meters
2) a circle has a diameter of 16 cm
3) a circle has a radius of 8ft
4) a circle has a diameter of 11 cm
Answers
Answers:
1) C = 12.6 m
A = 12.6 m²
2) C= 50.3 cm
A = 201.1 cm²
3) C= 50.3 ft
A = 201.1 ft²
4) C= 34.6 cm
A = 95.0 cm²
Explanation:
The circumference and area of a circle with radius r can be calculated as:
[tex]\begin{gathered} \text{Circumference = 2}\pi r \\ Area\text{ = }\pi r^2 \end{gathered}[/tex]Where π is approximately 3.1416
Then, for each option, we get:
1) Replacing the radius by 2 m, we get:
[tex]\begin{gathered} \text{Circumference}=2(3.1416)(2m)=12.6m \\ \text{Area}=(3.1416)(2m)^2=(3.1416)(4m^2)=12.6m^2 \end{gathered}[/tex]2) If the diameter is 16 cm, the radius is 8 cm because the radius is half the diameter. So, replacing r by 8 cm, we get:
[tex]\begin{gathered} \text{Circumference = 2(3.1416)(8cm) = 50.3cm} \\ \text{Area = (3.1416)(8cm)}^2=(3.1416)(64cm^2)=201.1cm^2 \end{gathered}[/tex]3) Replacing r by 8 ft, we get:
[tex]\begin{gathered} \text{Circumference = 2(3.1416)(8ft) = 50.3ft} \\ \text{Area = (3.1416)(8ft)}^2=(3.1416)(64ft^2)=201.1ft^2 \end{gathered}[/tex]4) If the diameter is 11 cm, the radius is 11/2 = 5.5 cm, so:
[tex]\begin{gathered} \text{Circumference = 2(3.1416)(5.5cm) = 34.6 cm} \\ \text{Area = (3.1416)(5.5cm)}^2=(3.1416)(30.25cm^2)=95.0cm^2 \end{gathered}[/tex]
Rewrite each equation in slope-intercept form, if necessary, then determine whether the lines are parallel , perpendicular, or neither.A.) y=2×+1B.)2x+y=7The slope line A is _The slope of line B is _Lines A and B are _
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You have the following equation of two lines:
A) y = 2x + 1
B) 2x + y = 7
the general form of an equation of a line is given by:
y = mx + b
where m is the slope and b is the y-intercept.
The equation A is already written in the slope-intercep form. By comparing the equation with the general form you can notice that the slope is:
mA = 2
Next, you rewrite the equation B:
2x + y = 7 subtract 2x both sides
y = -2x + 7
by comparing with the general fom you have that the equation B has the following slope:
mB = -2
In order to determine if the lines are parallel,perpendicular, or neither, you calculate the quotien between the slopes of the lines.
mA/mB = 2/(-2) = -1
The quotient between the slopes is -1, this means that the lines are perpendicular
The notation __1____ reads the probability of Event B given that Event A has occurred. If Events A and B are independent, then the probability of Event A occurring ___2___the probability of Event B occurring. Events A and B are independent if_3____1.A. P(AlB)B. P(BlA)C. P (A and B)2. A. Doesn't affectB. Affects3. A. P(BIA) = P(B)B. P(BIA) = P(A)C. P (BIA)= P(A and B).
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P(B|A) (option B)
Doesn't affect (option A)
P(B|A) = P(B) (option A)
Explanation:1) Conditional probabilities could be in the form P(A|B) or P(B|A)
P(B|A) is a notation that reads the probability of event B given that event A has occurred.
P(B|A) (option B)
2) Independent events do not affect the outcome of each other
For event A and B to be independent, the probability of event A occurring doesn't affect the the probability of event B occurring
Doesn't affect (option A)
3) Events A and B are independent if the following are satisfied:
P(A|B) = P(A)
P(B|A) = P(B)
The ones that appeared in the option is P(B|A) = P(B) (option A)
Math answers and how you got the answer to solve
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Hello there. To solve this question, we'll have to remember some properties about functions.
Given the functions:
[tex]\begin{gathered} f(x)=x^3 \\ g(x)=6x^2+11x-2 \end{gathered}[/tex]We have to determine:
[tex]\begin{gathered} (f+g)(x) \\ (f-g)(x) \\ (fg)(x) \\ (ff)(x) \\ \left(\frac{f}{g}\right)(x) \\ \left(\frac{g}{f}\right)(x) \end{gathered}[/tex]And their domain.
Let's do each separately:
(f + g)(x)
In this case, this function is the same as adding f(x) and g(x):
[tex](f+g)(x)=f(x)+g(x)=x^3+6x^2+11x-2[/tex]And as it is a polynomial function, it has no holes or asymptotes, therefore its domain is all the real line. We write:
(f - g)(x)
In the same sense, it is equal to the difference between f and g:
[tex](f-g)(x)=f(x)-g(x)=x^3-(6x^2+11x-2)=x^3-6x^2-11x+2[/tex]Again, as it is a polynomial function, its domain is all the real line, just as before.
(fg)(x)
In this case, it is the same as the product of f and g:
[tex](fg)(x)=f(x)\cdot g(x)=x^3\cdot(6x^2+11x-2)=6x^5+11x^4-2x^3[/tex]Once again, its domain is all the real line.
(ff)(x)
In this case, it is the product of f and itself:
[tex](ff)(x)=f(x)\cdot f(x)=x^3\cdot x^3=x^6[/tex]As before, its domain is entire real line.
(f/g)(x)
In this case, it is the quotient between f and g, respectively:
[tex]\mleft(\frac{f}{g}\mright)(x)=\frac{x^3}{6x^2+11x-2}[/tex]But in this case, its domain is not the entire real line. We have to get rid of the holes and vertical asymptotes of the function.
This function has no holes, since we cannot simplify any terms in the fraction, but it has at least two vertical asymptotes (that we'll find by taking the roots of the denominator).
In fact, the name vertical asymptote stands for the values of x in which the function would not exist (its limit goes to either infinity, -infinity or would not exist).
These roots are given by:
[tex]6x^2+11x-2=0[/tex]Using the quadratic formula, we get:
[tex]\begin{gathered} x=\frac{-11\pm\sqrt[]{11^2-4\cdot6\cdot(-2)}}{2\cdot6}=\frac{-11\pm\sqrt[]{121+48}}{12}=\frac{-11\pm\sqrt[]{169}}{12} \\ \Rightarrow x=\frac{-11\pm13}{12} \\ \Rightarrow x_1=\frac{-11+13}{12}=\frac{2}{12}=\frac{1}{6} \\ x_2=\frac{-11-13}{12}=\frac{-24}{12}=-2 \end{gathered}[/tex]The roots are 1/6 and -2. They are the vertical asymptotes of the function.
The domain of (f/g)(x) is then given by subtracting these values from the real line:
Or also in interval notation:
We do the same to (g/f)(x):
It is equal to the quotient between g and f, respectively, thus
[tex]\left(\frac{g}{f}\right)(x)=\frac{g(x)}{f(x)}=\frac{6x^2+11x-2}{x^3}[/tex]And again in this case, we have no holes, but we do have a vertical asymptote.
Taking the roots of the denominator:
[tex]x^3=0[/tex]The only solution to it is:
[tex]x=0[/tex]And the domain is then given by:
can you please help me
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Given the equation:
[tex]\text{ 2x + 2y = -4}[/tex]a deep dish pizza can be classified as what 3 dimensional object
Answers
Answer:
Cylinder
Explanation:
A deep-dish pizza can be classified as a Cylinder.
Other examples of cylinders are tins of milk, pipes, etc.
∣+8∣−5=2Group of answer choicesv = -1 and v = -15v = -1 and v = -5No Solutionv = -15 and v = 15
Answers
Given:
[tex]|v+8|-5=2[/tex][tex]|v+8|=2+5[/tex][tex]|v+8|=7[/tex]case (1)
[tex]v+8=7[/tex][tex]v=7-8[/tex][tex]v=-1[/tex]Case (2)
[tex]-(v+8)=7[/tex][tex]-v-8=7[/tex][tex]v=-8-7[/tex][tex]v=-15[/tex]Therefore,
[tex]v=-1,-15[/tex]1st option is the correct answer.
Plot the points. Then identify the polygon formed.a) A(4, 1), B(4, 6), C(-1, 6), D(-1, 1)b) A(2, -2), B(5, -2), C(7, -4), D(0, -4)
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a)
The points for polygon a are shown below:
From the graph we notice that this is a square.
b)
The points for polygon b are shown below:
From the graph we conclude that this is a trapezoid.
1. [2/3 Points)DETAILSPREVIOUS ANSWERSSALGTRIG45.4.001.MY NOTESASK YOUR TEACHERFor a function to have an inverse, it must be one-to-oneTo define the Inverse sine function, we restrict the domainDof the sine function to the IntervalXNeed Help? Paad
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In the case of sine function the domain of the function is given by the limits of the range of sine function.
The limits of the range of sine function are [-1,1].
Hence, the domain of the inverse sin function is [-1,1].
4) (-21)³ multiplying complex numbers
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-9257
explanation..........................................................................................................
what is the y-intercept of the function y=-¹/²cos(3/2x)
Answers
Problem
We need to find the y intercept of this function
y=-1/2cos(3/2x)
Solution
The y intercept correspond to the value of x=0 of the function and we can do this:
y= -1/2 cos (3/2 *0)
y= -1/2 cos (0) = -1/2
And then the best solution it would be:
x=0 and y= -1/2
(0,-1/2)
Reflect the figure over the line y = -x - 1.Plot all of the points of the reflected figure.You may click a plotted point to delete it.1098765432-10-9-8-7-6-54345 6789 10-10
Answers
We are going to determine how to reflect over the line
y = - x -1
First, if we are going to undertand how to reflect it over y = -x
What happens when y = - x?If we want to reflect the point (-4, 0) over y = -x, graphically we know that its reflection is (0, 4).
It would be tha same for any point (x, 0), its reflection would be (0, -x).
Similarly, if we want to reflect the point (0, -5) over y = -x. Its reflection would be (5,0).
It would be the same for any point (0, y), its reflection would be (-y, 0)
We can generalize it: if we have a point (x, y) its reflection over y = -x would be (-y, -x)
(x, y) → (-y, -x)
Now that we have undertood when it is reflected over y = -x. We can find how to do it over y = -x -1
Reflection over y = - x -1
Doing the same case as y = -x
If we see the figure we will observe that
(x, y) reflected point would be (- y - 1, - x -1)
(x, y) → (-y - 1, -x - 1)
Reflecting the figure
We can observe that the figure has 5 points
(-4, -1), (-4, -4), (-2, -9), (-7, -2), (-8, -8)
We are going to reflect them using the last formula
(x, y) → (-y - 1, -x - 1)
(-4, -1) → ( -(-1) - 1, - (-4) -1)
= ( 1 -1, 4 - 1) = (0, 3)
(-4, -4) → (- (-4) -1, - (-4) -1)
= (4 -1, 4 - 1) = (3, 3)
(-2, -9) → (- (-9) -1, - (-2) -1)
= (9 - 1, 2 - 1) = (8, 1)
(-7, -2) → (- (-2) -1, - (-7) -1)
= (2 -1, 7 -1) = (1, 6)
(-8, -8) → (- (-8) -1, - (-8) -1)
= (8 - 1, 8 -1) = (7, 7)
Then the new points are:
(0, 3), (3, 3), (8, 1), (1, 6), (7, 7)
Identify all of the features of this graph;A. Amplitude of 4B. Period of 1C. This is a sine curveD. Period of 5pi/2E. Amplitude of 2F. Midline at y= -3G. Period of 2piH. Amplitude of -1I. Midline at y= -2J. This is a cosine curvecan choose more than one
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EXPLANATION
As we can see in the graph:
A. Amplitude is equal to 4 (distance from valley to ridge)
G. Period is equal to 2pi (distance from valley to valley -->5pi/2-pi/2)
F. Midline at y=-3
C. This is a sine curve (Start in pi/2).
For each coefficient choose whether it is positive or negative.Choose the coefficient with the least value.Choose the coefficient closest to zero.
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From the given graph
a)
If the coefficient is positive, then the graph is upward
If the coefficient is negative, then the graph is downward
In the first 2 figures, the graphs are upward, then
A and B are positive
In the last 2 figures, the graphs are downward, then
C and D are negative
b)
The least coefficient is the coefficient of the graph which nearest to the x-axis
Since graph C is the nearest graph to the x-axis, but we have negative values, then
The least coefficient is the coefficient of the downward graph and farthest from the x-axis, then
D is the least coefficient
c)
The closest coefficient to zero is the graph C
3x - 5y = 2 4x + 5y = 33
Answers
the equations are,
3x - 5y = 2
4x + 5y = 33
sum the equations,
7x = 35
x = 35/7
x = 5
put x = 5 in equation 3x - 5y = 2
3(5) - 5y = 2
15 - 2 = 5y
5y = 13
y = 13/5
thus, the answer is x = 5 and y = 13/5
i have solved your problem in the answer tab.
if you have any doubt with this solution then let me know.
Bart has a cylindrical pitcher with a radius of 6 cm and a height of 12 cm and a height of 12 cm he pours 1,300 cubic centimeters of lemonade into the pitcher approximately how much lemonade will a pitcher hold
Answers
SOLUTION
To determine the volume of a cylinder;
Step 1:
[tex]\begin{gathered} Volume\text{ of cylinder=}\pi r^2h \\ \pi=\frac{22}{7} \\ r=6cm \\ h=12cm \end{gathered}[/tex][tex]Volume\text{ of pitcher=}\frac{22}{7}\times6^2\times12=1357.7143\approx1358cm^3[/tex]THE ANSWER IS 1358cm^3
If h(x)-(fog)(x) and h(x) = 4(x+1)*, find one possibility for 5 %) and g(x).f(x) = x +1O A.8(x) = 4x2O B. M(x)=(x+1)8(x)=4x2O c.f(x) = 4x2g(x) = x +1D.f(x) = 4x28(x)= (x+1)
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It is given that h(x)=fog(x) and h(x)=4(x+1)^2.
So it follows:
[tex]\text{fog(x)}=4(x+1)^2[/tex]For option A, f(x)=x+1,g(x)=4x^2
So the value of fog(x) is given by:
[tex]f(g(x))=g(x)+1=4x^2+1[/tex]So A is incorrect.
For option B, f(x)=(x+1)^2,g(x)=4x^2
So the value of fog(x) is given by:
[tex]f(g(x))=g(x)+1=(g(x)+1)^2=(4x^2+1)^2[/tex]So B is incorrect.
For option C, f(x)=4x^2,g(x)=x+1
So the value of fog(x) is given by:
[tex]f(g(x))=4\lbrack g(x)\rbrack^2=4(x+1)^2[/tex]So C is correct.
The equation a +c = b+c demonstrates an examples of which property?O The distributive propertyO The addition property of equality O The commutative propertyO The associative property
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The correct answer is the addition property of equality
Here, we want to select the property demonstrated by the example
The correct answer is the addition property of equality
What this is saying is that if we have two numbers, in this case represented by the variables a= c
If we add an equal number to both sides, then the results on both sides still stay the same regardless since it is the same number that we added on both ends
Bought office equipment of Rs.50,000 on cash and of Rs.70,000 on cReddit from jayaram
Answers
Answer:
dsseeeseeeeeeeeeeeeee33ee3e33ee2eew3wwwwwwwwwwwewqee
One of the largest carnivals has 25 rides and accommodates 120 people on each ride. If every ride was was completely full 4 nights this week, how many people will the carnival accommodate during those 4 nights?
Answers
The carnival has 25 rides
Each ride accomodates 120 people (when full)
Each ride was completelly booked for 4 nights .
Step one, calculate how many people can the carnival accomodate in one night by multiplying the number of people by ride by the number of rides:
120*25= 3000
This means that in one night, the carnival can accomodate 3000 people in all 25 rides.
Step two, multiply the value obtained by the number of nights the carnival will be full:
3000*4=12000
The carnival will expect to accomodate 12000 people for 4 nights with all rides full booked.