The area of a circle is given by:
[tex]A=\pi r^2[/tex]Since it is a quarter of the circle, the area is:
[tex]\begin{gathered} A=\frac{\pi r^2_{}}{4} \\ where \\ r=7 \\ \pi=3.14 \\ so\colon \\ A=\frac{(3.14)(7^2)}{4} \\ A\approx38.5in^2 \end{gathered}[/tex]what is four fiths minus 6 fiftheens
what is four fiths minus 6 fiftheens
we have
4/5-6/15
Multiply by 3/3 fraction 4/5
4/5(3/3)=12/15
substi
5 times 5 I need help solving that one
5 times 5 = 5 x 5
= 25
Answer : 25
Which of the following is a solution to the quadratic equation below?x²-3x-54-0A. 9B. -57C. 2D. 27
A. 9
Explanationto solve for x we can use the quadratic formula
it says
[tex]\begin{gathered} for \\ ax^2+bc+c=0 \\ the\text{ solution for x is} \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \end{gathered}[/tex]hence
Step 1
a) let
[tex]\begin{gathered} x^2-3x-54=0\Rightarrow ax^2+bx+c=0 \\ so \\ a=1 \\ b=-3 \\ c=-54 \end{gathered}[/tex]b) now, replace in the formula and evaluate
[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ x=\frac{-(-3)\pm\sqrt{(-3)^2-4(1)(-54)}}{2(1)} \\ x=\frac{-(-3)\pm\sqrt{9+216}}{2}=\frac{3\pm\sqrt{225}}{2} \\ x=\frac{3\pm15}{2} \end{gathered}[/tex]so
[tex]\begin{gathered} x_1=\frac{3+15}{2}=9 \\ x_2=\frac{3-15}{2}=-6 \end{gathered}[/tex]therefore, the answer is
A. 9
I hope this helps you
find the slope of the line
Solution
We can use the following points from the graph:
(0,-2) and (2,1)
And we can find the slope on this way:
[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{1+2}{2-0}=\frac{3}{2}[/tex]Then we can find the intercept on this way:
1= 3/2 (2)+b
b= 1-3= -2
Then the equation would be:
y= 3/2 x -2
-2/5 divide (-3) multiply and reduce to lowest terms.
Answer:
2/15
Explanation:
Given the expression:
[tex]-\frac{2}{5}\div(-3)[/tex]First, change the division sign to times by taking the reciprocal of the number after the sign:
[tex]=-\frac{2}{5}\times-\frac{1}{3}[/tex]Next, multiply the numerators and denominators:
[tex]\begin{gathered} =\frac{(-2)\times(-1)}{5\times3} \\ =\frac{2}{15} \end{gathered}[/tex]The fraction is already in its lowest form as required.
GEOMETRY: Express the volume of each cube below as a monomialNeeded fast!
Remember that
The volume of a cube is equal to
[tex]V=b^3[/tex]where b is the long side of the cube
so
Part 19
we have that
[tex]b=7c^6d^2[/tex]substitute in the formula
[tex]V=(7c^6d^2)^3[/tex]Applying property of exponents
[tex]\begin{gathered} V=(7^3)(c^{(6\cdot3)})(d^{(2\cdot3)}) \\ V=342c^{(18)}d^6 \end{gathered}[/tex]Part 20
we have
[tex]b=6r^7s^8[/tex]substitute in the formula
[tex]\begin{gathered} V=(6r^7s^8)^3 \\ V=216r^{(21)}s^{(24)} \end{gathered}[/tex]P(A)=0.35P(B)=0.40P(A and B)=0.13Find P(A or B).Round your answer to two decimal places.
Given:
[tex]\begin{gathered} P\left(A\right)=0.35 \\ P\left(B\right)=0.40 \\ P\left(A\text{ }and\text{ }B\right)=0.13 \end{gathered}[/tex]To find:
[tex]P(A\text{ or }B)[/tex]Explanation:
Using the formula,
[tex]\begin{gathered} P(A\text{ or}B)=P(A)+P(B)-P(A\text{ and }B) \\ =0.35+0.40-0.13 \\ =0.62 \end{gathered}[/tex]Therefore, the value is,
[tex]P(A\text{ or }B)=0.62[/tex]Final answer:
The value is,
[tex]P(A\text{ or }B)=0.62[/tex]I got the first one right but I can’t figure out the rest. College Calculus 1. Please help :)
SOLUTION
Consider the image given
In other to evaluate the value of
[tex]g(f(0))[/tex]We first evaluate
[tex]f(0)[/tex]From the graph,
[tex]f(0)=0[/tex]Then, we obtain the value of g(0) by tracing the value of zero on the blue curve, we have
[tex]g(0)=3[/tex]Therefore
g(f(0) = 3
Flying against the wind, an airplane travels 2010 kilometers in 3 hours. Flying with the wind, the same plane travels 10,530 kilometers in 9 hours. What is the rate of the plane in still air and what is the rate of the wind?
it is given that,
the distance travel against wind = 2010
time = 3 hrs
so, the relative speed is = distance/ time = 2010/3 = 670 km/hr
the distance travel with wind is 10,530
time 9 hrs
so,the relative speed is,= 10 530/9 = 1170 km/hr
let a = speed of plane ,
b = speed of wind
so, when plane travel with wind the the relative speed is ,
a + b = 1170
when travel against wind then the relative speed,
a - b = 670
sum the equation
a + b + a - b = 1170 + 670
2a = 1840
a = 920
put a = 920 in equation a + b = 1170
920 + b = 1170
b = 1170 - 920
b = 250
thus, the rate of plane is 920
rate of wind is 250
What is the value of y in the equation 2(2y − 16) = 0? (5 points)4689
Given the following equation,
[tex]\text{ 2\lparen2y - 16\rparen = 0}[/tex]Let's determine the value of y.
[tex]\text{ 2\lparen2y - 16\rparen = 0}[/tex][tex]\text{ }\frac{2(2y\text{ - 16\rparen}}{2}\text{ = 2}[/tex][tex]\text{ 2y - 16 = 0}[/tex][tex]\text{ 2y = 16}[/tex][tex]\text{ }\frac{2y}{2}\text{ = }\frac{16}{2}[/tex][tex]\text{ y = 8}[/tex]Therefore, y = 8
The answer is 8.
what is five plus two
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
five plus two
Step 02:
addition:
5 + 2 = 7
The answer is:
7
What type of number is 3 - 77iChoose all answers that apply:A. RealB. ImaginaryC. Complex
Blair purchases the T-shirts from Company B. She needs to add a 75markup to her total cost to make a profit when she sells the shirts at thcarnival. How should Blair determine the selling price of each T-shirt athe carnival?Drag a number into each box to make the statements true.She canThe total cost Blair paid for one T-shirt is $calculate the markup by multiplying her total cost byBlair will sell each T-shirt at the carnival for $
Isolating selling price,
[tex]\begin{gathered} \frac{\text{ markup \% }}{100}\text{= }\frac{\text{ selling price - cost}}{\text{ cost}} \\ \frac{\text{ markup \% }}{100}\cdot\cos t=\text{selling price - cost} \\ \frac{\text{ markup \% }}{100}\cdot\cos t+cost=\text{selling price} \\ \cos t(\frac{\text{ markup \% }}{100}+1)=\text{ selling price} \end{gathered}[/tex]The markup is 75 %. Supposing that the cost of a T-shirt is $6.00, then the selling price will be:
[tex]\begin{gathered} \text{selling price = 6.00}\cdot(\frac{75}{100}+1) \\ \text{selling price = 6.00}\cdot(0.75+1) \\ \text{selling price = 6.00}\cdot1.75 \\ \text{selling price = \$}10.5 \end{gathered}[/tex]help my brother the other one I tried was a scam
1. Given the integers a and b, a common multiple is a positive integer that is divisible by both a and b.
2. The Least Common Multiple (LCM ) is the smallest positive integer that is divisible by both a and b.
3. Multiples of 6: 6 (= 6x1), 12 (= 6x2), 18 (= 6x3), 24 (= 6x4), ...
Multiples of 4: 4 (= 4x1), 8 (= 4x2), 12 (= 4x3), 16 (= 4x4), ...
The smallest number of these two lists is 12, then the LCM between 6 and 4 is 12.
Is (2,7) a solution to the system of equations: y= x + 5 y= 4x + 1 Part 1 (circle 1) Yes No Part 2 Shows a proof of your answer
Answer
(2, 7) is not a solution to this system of equations.
The ordered pair doesn't fit into the second equation
Explanation
To check if the given ordered pair is a solution to this, we will insert the values into the two equations and if they fit into rach equation, then, the ordered pair is a solution for this.
y = x + 5
y = 4x + 1
(2, 7) means x = 2, y = 7
y = x + 5
7 = 2 + 5
7 = 7
y = 4x + 1
7 = 4(2) + 1
7 = 8 + 1
7 ≠ 9
The ordered pair doesn't fit into the second equation, hence, (2, 7) is not a solution to this system of equations.
Hope this Helps!!!
Which relation is a function?
Answer:
The left upper one is a function
Step-by-step explanation:
If you draw a straight vertically and the line goes through two point then its not a function. Just look what makes a function or answer again if you are confused.
The relation which is a function is f ( x ) = x³
What is a function rule?The function rule is the relationship between the input or domain and the output or range. A relation is a function if and only if there exists one value in the range for every domain value.
A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.
Given data ,
Let the function be represented as f ( x )
Now , the value of f ( x ) is
y = x³ be equation (1)
Now , relation is a function if and only if there exists one value in the range for every domain value.
So , when x = { 1 , 2 , 3 , 4 }
The values of y are = { 1 , 8 , 27 , 64 }
Hence , the function is y = x³ and the graph is plotted
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The solutions to a quadratic equation are -2 and 6. What is the equation of its axisof symmetry?
General form of a quadratic equation is
[tex]ax^2+bx+c=0[/tex]another form is
[tex](x+h)(x+k_{})=0[/tex]where h and k are the number opposite by the sign of the solutions, then on this case the values of h and k are 2 and -6
[tex](x+2)(x-6)=0[/tex]Our equatio is a parabola then if we find the vertex we are finding the axis of simmetry
to find the vertex we trasnforme ou equation to the general form of a quadratic equation multipliying parenthesis
[tex]\begin{gathered} (x\times x)+(x\times-6)+(2\times x)+(2\times-6)=0 \\ x^2-6x+2x-12=0 \\ x^2-4x-12=0 \end{gathered}[/tex]now take the equation and derivate
[tex]\begin{gathered} 2x-4-0=0 \\ 2x-4=0 \end{gathered}[/tex]if we solve x we find the coordinate x of the vertex and the axis of simmetry
then
[tex]\begin{gathered} 2x-4=0 \\ 2x=4 \\ x=\frac{4}{2} \\ \\ x=2 \end{gathered}[/tex]axis of Symmetry is x=2
What is the value of X?
Check the picture below.
Make sure your calculator is in Degree mode.
The sum of two numbers is30. The sum of4 times the larger and6 times the smaller is128. Find the numbers.
let
the smaller number = x
the larger number = y
x + y = 30
4y + 6x = 128
[tex]\begin{gathered} x+y=30 \\ 4y+6x=128 \\ x=30-y \\ 4y+6(30-y)=128 \\ 4y+180-6y=128 \\ -2y=128-180 \\ -2y=-52 \\ y=\frac{52}{2} \\ y=26 \\ x+y=30 \\ x+26=30 \\ x=30-26 \\ x=4 \end{gathered}[/tex]
The numbers are 4 and 26.
PLEASE HELP 15 POINTS I'M GIVING BRAINLIEST
Answer:
below
Step-by-step explanation:
In a RIGHT triangle such as this, cos = adjacent leg / hypotenuse
cos (beta) = 22/24 = 11/12
If f(x)=x²-20 and g(x) = 4+3x, then f(g(-3)) =
The value of function f(g(-3)= 5.
What is composite function?
A composite function is generally a function that is written inside another function. Composition of a function is done by substituting one function into another function. For example, f [g (x)] is the composite function of f (x) and g (x).
Given, f(x)=x²-20 and g(x) = 4+3x
first we will find
f(g(x)) = f(4+3x)^2-20
=9x^2+16+24x-20
=9x^2+24x-4
Now to find, f(g(-3)), substitute x=-3,
= 9(9)+24(-3)-4
=81-72-4
=5
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f(2)=1/xsolve both go 2)=3x
The functions are:
[tex]\begin{gathered} f(x)=\frac{1}{x} \\ g(x)=3x \end{gathered}[/tex]We need to evaluate f(x) in x=-2 and g(x) in x=2, so:
[tex]\begin{gathered} f(-2)=\frac{1}{(-2)}=-\frac{1}{2}=-0.5 \\ g(2)=3\cdot2=6 \end{gathered}[/tex]In a painting of the Mona Lisa, the length of the painting is 4 - inches, Milo scales the drawing up by 2 What is the length of the scaled copy?
Wee, it he is scalaing the painting by two the new length must be twice the original length.
length = 2 x 4 = 8 in
New length = 8 in
A regular hexagon has perimeter 72m. Find the area
A regular hexagon has six equal sides:
If you notice, a regular hexagon has exactly six equilateral triangles inside of it.
So, to find the area we could find the area of a triangle and then multiply this result by 6. This seems to be a little bit complicated to do, so, there's a formula to find the area of a regular hexagon, which is:
[tex]\begin{gathered} A=\frac{3\sqrt{3}s^2}{2} \\ Where: \\ s:Measure\text{ of a side of the regular hexagon} \end{gathered}[/tex]We know that the measure of any side of our regular hexagon equals 12m, so, we could just replace in the equation:
[tex]A=\frac{3\sqrt{3}(12m)^2}{2}\rightarrow A=\frac{3\sqrt{3}(144m^2)}{2}\rightarrow A=216\sqrt{3}m^2[/tex]Simplified, that's about 374.1 m2.
Three cards are drawn from an ordinary deck and not replaced find the probability of the following P(getting 3 queens)P(getting an ace and king and queen)P(getting club and spade and heart)P(getting 3 diamonds)Answer the following problems using multiplication rule make sure to reduce your fraction
a) P(3 queens) ) = 4/52*3/51*2/50 = 1/5525
b) P(ace,king, queen) = 4/52*4/51*4/50 = 8/16575
c) P( ) = 10/52 * 10/51*10/50 = 5/663
d) P(3 diamonds) = 10/52 * 9/51* 8/50 = 6/1105
Question: What is the solution to this system of linear equations? 8x + 2y = 2 and x + 3y 2 = 14 I NEED The claim, evidence and reasoning. Please I need help
two numbers have a sum of -10 and a difference of -2 what is the product of numbers
let 'x' and 'y' be two numbers that have a sum of -10 and a difference of -2, then, we have the following system of equations:
[tex]\begin{gathered} x+y=-10 \\ x-y=-2 \end{gathered}[/tex]notice that if we add both equations at the same time, we get:
[tex]\begin{gathered} x+y=-10 \\ x-y=-2 \\ --------- \\ 2x=-12 \\ \Rightarrow x=\frac{-12}{2}=-6 \\ x=-6 \end{gathered}[/tex]now that we have that x = -6, we can find the value of y substituting x = -6 on any equation:
[tex]\begin{gathered} -6+y=-10 \\ \Rightarrow y=-10+6=-4 \\ y=-4 \end{gathered}[/tex]therefore, x = -6 and y = -4. Next, we have that the product is (-6)(-4) = 24
How do I know if 6.209 is greater or lesser than 6.29
Since,
[tex]6.29-6.209=0.081[/tex]The difference gives us a positive value.
So, 6.29 is grater than 6.209
Answer: Add a 0 to 6.29 and compare the numbers to see which one is greater
6.29 (or 6.290) is greater than 6.209 since the hundrenth in 6.29 is 9 and the other hundrenth for 6.209 is 0.
I have been stuck on this for a while, your help would be most appreciated!
Answer:I Don't Know What She Said
Step-by-step explanation:
use the equation and type the ordered-pairs.y=3^x[(-1,_),(0,_),(1,_),(2,_),(3,_),(4,_)]
Given the equation :
[tex]y=3^x[/tex]we need to complete the order pairs :
[(-1,_),(0,_),(1,_),(2,_),(3,_),(4,_)]
So, for each value of x, we will find the corresponding value of y
[tex]\begin{gathered} x=-1\rightarrow y=3^{-1}=\frac{1}{3} \\ \\ x=0\rightarrow y=3^0=1 \\ \\ x=1\rightarrow y=3^1=3 \\ \\ x=2\rightarrow y=3^2=9 \\ \\ x=3\rightarrow y=3^3=27 \\ \\ x=4\rightarrow y=3^4=81 \end{gathered}[/tex]So, the answer is : the order pairs will be :
[tex](-1,\frac{1}{3}),(0,1),(1,3),(2,9),(3,27),(4,81)[/tex]