How should you solve the equation x + 10 = 80? What is the resulting equivalent equation?Choose the correct answer below.

How Should You Solve The Equation X + 10 = 80? What Is The Resulting Equivalent Equation?Choose The Correct

Answers

Answer 1

Multiply each side by 10, then simplify

Here, we want to know how to proceed with solving the equation

As we can see, we have the division sign between the terms on the left hand side of the equation

To solve the equation, we have to find the value for x by isolating it

What this mean here is that we will have to multiply both sides by 10; so that we can isolate x

Thus, the correct answer here is to multiply each side by 10, then simplify


Related Questions

Part B: select the box or boxes under the coordinate pairs the represent solutions for the system.

Answers

The given system of inequalities is

[tex]\begin{gathered} y>\frac{3}{2}x-2 \\ y\leq-3x-4 \end{gathered}[/tex]

The area of the solution is the area shaded by the 2 colors

Let us check the points

(-2, -5) it lies on the red dashed line

Since the line is dashed, then the points lie on it do not belong to the solution, then

(-2, -5) does not belong to the solution

(-2, -5) is not a solution

(-2, 2) it lies on the blue line

Since the line is solid, then the points that lie on it belong to the solution, then

(-2, 2) is a solution

(0, -4) it is out of the area of both colors, then

(0, -4) is not a solution

(-3, -1) it lies in the area of the common colors, then

(-3, -1) is a solution

(-1, 4) it is out the area of both colors, then

(-1, 4) is not a solution

(-20, 15) is in the area of the common colors, then

(-20, 15) is a solution

(15, 20) it is out the area of both colors, then

(15, 20) is not a solution

Then the solutions of the system are:

(-2, 2), (-3, -1), (-20, 15)

3, -9, 27, -81,..... common difference/ratiod = 3r = 9r = -3 d = 12

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To find the common ratio we divide the terms by the previous one. In this case we have:

[tex]-\frac{9}{3}=-3[/tex][tex]\frac{27}{-9}=-3[/tex][tex]-\frac{81}{27}=-3[/tex]

Therefore, the common ratio is r=-3.

help me with this question please

Answers

So,

From the graph, we can clearly state that:

In 2 mins, there were 0 calls.

In 3 mins, there was 1 call.

In 4 mins, there were 4 calls.

In 5 mins, there were 6 calls.

In 6 mins, there were 4 calls.

Then, the number of calls that were answered to in 6 mins or less were 0+1+4+6+4 = 15

Runner A averages 5 miles per hour, and Runner B averages 6 miles per hour. At these rates, how much longer does it take Runner A than Runner B to run 15
miles?
1 hour
Shour
2.5 hours
1.5 hours
3 hours

Answers

If Runner A averages 5 miles per hour, and Runner B averages 6 miles per hour. At these rates, then it took 3 hours for runner A.

What is Equation?

Two or more expressions with an Equal sign is called as Equation.

Given,

Runner A averages 5 miles per hour, and

Runner B averages 6 miles per hour.

The time required for A to complete 15 miles is

15/5=Time

3 hrs

Hence Runner A needs 3 hours to run 15 miles.

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Harold cut 18 1/2 inches off a rope that was 60 inches long. How is the length of the remaining rope written in decimals?

Answers

Substract 18 1/2 from 60 to determine the length of remaining rope.

[tex]\begin{gathered} 60-18\frac{1}{2}=60-\frac{37}{2} \\ =\frac{120-37}{2} \\ =\frac{83}{2} \\ =41.5 \end{gathered}[/tex]

So length of remaining rope is 41.5 inches.

Which inequality is represented by the graph

Answers

The inequality 4x - 2y < 12 is represented by the attached graph. which is the answer would be an option (B).

What is inequality?

Inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.

As per option (B),

4x - 2y < 12

We can see that the x-intercept is (0, -6), and the y-intercept is (2.5, 0) in the given graph which is determined by substituting the value of x and y is equal to 0 in the equation 4x - 2y = 12.

The inequality 4x - 2y < 12 is represented by the attached graph.

Hence, the answer would be option (B).

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.Find the side of a square whose diagonal is of the given measure.Given = ft.

Answers

see the figure below to better understand the problem

In the given square ABCD

Apply the Pythagorean Theoren in the right triangle BDC

[tex]\begin{gathered} D^2=a^2+a^2 \\ D^2=2a^2 \\ we\text{ have} \\ D=12\sqrt{10}\text{ ft} \end{gathered}[/tex]

Substitute given value

[tex]\begin{gathered} (12\sqrt{10})^2=2a^2 \\ 144(10)=2a^2 \\ 2a^2=1,440 \\ a^2=720 \\ a=\sqrt{720}\text{ ft} \end{gathered}[/tex]

Simplify

[tex]a=12\sqrt{5}\text{ ft}[/tex]

which point is located at (0,8)

Answers

The point (0, 8) simply means the x axis is 0 while the y axis is 8. The answer is C.

Find the coordinates of the midpoint between (8, 1) and (0, - 9). F. (4, -5) G. (4, -4) H. (8, -5) J. (8, -8)

Answers

MidpointAnswer

(4, -4)

Explanation

In order to find the midpoint between two points we have to obtain the midpoint horizontally and vertically.

In this case, we have:

neeed double chedking on this

Answers

The area will be the area of the blue part minus the area of the white part:

9(8)-5(3)=72-15= 57 square centimeters

i need help simplifying 1/3(3n+9)

Answers

Answer:

n+3

Explanation:

Given the expression:

[tex]\frac{1}{3}(3n+9)[/tex]

To simplify, we first open the bracket.

[tex]=\frac{1}{3}(3n)+\frac{1}{3}(9)[/tex]

We can then divide common factors:

[tex]\begin{gathered} =\frac{3n}{3}+\frac{9}{3} \\ =n+3 \end{gathered}[/tex]

The simplified form is: n+3

Choose the expression that is equal to 28.3A. 3³+27.2-6.8+2⁴-3.1B. 3³+27.2-(6.8+2⁴-3.1)C. [3³+(27.2-6.8)]+2⁴-3.1D. 3³+27.2-(6.8+2⁴)-3.1

Answers

solution

For this case we can solve each case and we have:

A) 27 +27.2 -6.8 +16 -3.1= 60.3

B) 27 +27.2 -(6.8 +16 -3.1)= 54.2- 19.7= 34.5

C) 27 + 20.4 +16 -3.1= 30.1

D) 27 +27.2 - 22-8 -3.1= 28.3

then the correct solution for this case would be:

D)

it's late but I need help

Answers

Data:

X = weight of the puppy at thefirst visit

Simplify: (3x-8)+(4x-17)

Answers

Answer:

7x-25

Explanation:

Given the expression:

[tex]\mleft(3x-8\mright)+\mleft(4x-17\mright)[/tex]

First, we open the brackets

[tex]=3x-8+4x-17[/tex]

Next, we rearrange bringing like terms together.

[tex]\begin{gathered} =3x+4x-8-17 \\ =7x-25 \end{gathered}[/tex]

Jessica borrowed $1,450 for three months at an annual rate of 8.75%under a single-payment plan. How much interest must she pay?a. $0.30b. $31.72c. $4,893.75d. $108.75

Answers

Given:

Principal amount (P)= $1450

Rate (R) = 8.75%

Time (T)= 3 months

The interest is given by the formula,

[tex]\begin{gathered} I=\frac{P\times R\times T}{100\times12} \\ =\frac{1450\times8.75\times3}{100\times12} \\ =31.71875 \end{gathered}[/tex]

What does the constant 1.6 reveal about the rate of change of the quantity?

Answers

The form of the exponential growth/decay function is

[tex]f(x)=a(1\pm r)^x[/tex]

a is the initial amount

r is the rate of growth/decay per x years

We use + with growth and - with decay

Since the given function is

[tex]f(t)=2700(1.6)^{7t}[/tex]

Where t is time per week

Compare the two functions

[tex]\begin{gathered} a=2700 \\ (1+r)=1.6 \\ x=7t \end{gathered}[/tex]

Since 1.6 is greater than 1, then

The function is growth

Equate 1.6 by (1 + r) to find r

[tex]\begin{gathered} 1+r=1.6 \\ \\ 1-1+r=1.6-1 \\ \\ r=0.6 \end{gathered}[/tex]

Change it to percent by multiplying it by 100%

[tex]\begin{gathered} r=0.6\times100\text{ \%} \\ \\ r=60\text{ \%} \end{gathered}[/tex]

Since x = 7t then the time is every 7 weeks

The answer is

The function is growing exponentially at a rate of 60% every 7 weeks

which choice is equivalent to the quotient below? sqrt 7/8* sqrt7/187/16/121/23/47/12

Answers

We can apply the following properties of radicals:

[tex]\begin{gathered} \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\Rightarrow\text{ Product property} \\ \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}\Rightarrow\text{ Quotient property} \end{gathered}[/tex]

Then, we have:

[tex]\begin{gathered} \text{ Apply the product property} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{7}{8}\cdot\frac{7}{18}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{7\cdot7}{8\cdot18}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\sqrt[]{\frac{49}{144}} \\ \text{ Apply the quotient property} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\frac{\sqrt[]{49}}{\sqrt[]{144}} \\ \sqrt[]{\frac{7}{8}}\cdot\sqrt[]{\frac{7}{18}}=\frac{7}{12} \end{gathered}[/tex]

Therefore, the choice that is equivalent to the given product is:

[tex]\frac{7}{12}[/tex]

Zach puts $1000 into a savings account earning 5% compound interest for 5 years. How much
interest has Zach earned at the end of the the 5 years?
$_______
Do not enter the dollar sign as part of your answer

Answers

The amount of interest Zach earn in 5 years given the principal and interest rate compounded for 5 years is 276.3

What is the amount of interest Zach earned?

A = P(1 + r/n)^nt

Where,

A = principal + interestPrincipal, P = $1000Interest rate, r = 5% = 0.05Time, t = 5 yearsNumber of periods, n = 1

A = P(1 + r/n)^nt

= 1000(1 + 0.05/1) ^(1×5)

= 1000(1 + 0.05) ^5

= 1000(1.05)^5

= 1000(1.2762815625)

= 1,276.2815625

Approximately,

1,276.3

Hence,

A = principal + interest

1, 276.3 = 1000 + interest

1276.3 - 1000 = interest

Interest = 276.3

Therefore, the amount of interest earned in 5 years is 276.3

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Each table represents a proportional relationship. For each, find theconstant of proportionality, k, and write an equation that represents therelationship. Write k as a simplified proper or improper fraction and use thegiven variables.

Answers

**For the first table:

*We determine the value of k, as follows:

[tex]30=k(18)\Rightarrow k=\frac{5}{3}[/tex]

The equation that represents the table is:

[tex]f=\frac{5}{3}d[/tex]

**For the second table:

*We determine the value of k, as follows:

[tex]18=k(30)\Rightarrow k=\frac{3}{5}[/tex]

The equation that represents the table is:

[tex]d=\frac{3}{5}f[/tex]

[the ending was select all that apply ] can somebody help me with this with an explanation on how to do it?

Answers

Answer: the goal is to isolate the variable so the answer is 12

Step-by-step explanation:

4) P(A) = 0.55 P(B) = 0.25 P(A and B) = ? *a.0.2b.0.21c.0.3d.0.1375

Answers

Since P (A and B) = P(A) · P(B)

Since P(A) = 0.55 and P(B) = 0.25, then

P(A and B) = 0.55 x 0.25

P(A and B) = 0.1375

The answer is d

find the mean the median the mode range and standard invitation of each data set that is obtained after adding the given content to each value (number 1)

Answers

Answers:

Mean = 43.7

Median = 44.5

Mode = doesn't exist

Standard deviation = 4.78

Explanation:

First, we need to add the constant to each value, so the new data is:

33 + 11 = 44

38 + 11 = 49

29 + 11 = 40

35 + 11 = 46

27 + 11 = 38

34 + 11 = 45

36 + 11 = 47

28 + 11 = 39

41 + 11 = 52

26 + 11 = 37

Now, we can organize the data from least to greatest as:

37 38 39 40 44 45 46 47 49 52

Then, the mean is the sum of all the numbers divided by 10, because there are 10 values in the data. So, the mean is:

[tex]\begin{gathered} \operatorname{mean}=\frac{37+38+39+40+44+45+46+47+49+52}{10} \\ \operatorname{mean}=43.7 \end{gathered}[/tex]

The median is the value that is located in the middle position of the organized data. Since there are 10 values, the values in the middle are the numbers 44 and 45, so the median can be calculated as:

[tex]\operatorname{median}=\frac{44+45}{2}=44.5[/tex]

The mode is the value that appears more times in the data. Since all the values appear just one time, the mode doesn't exist.

To calculate the standard deviation, we will calculate first the variance.

The variance is the sum of the squared difference between each value and the mean, and then we divided by the number of values. So, the variance is equal to:

[tex]\begin{gathered} (37-43.7)^2+(38-43.7)^2+(39-43.7)^2+(40-43.7)^2+ \\ (44-43.7)^2+(45-43.7)^2+(46-43.7)^2+(47-43.7)^2+ \\ (49-43.7)^2+(52-43.7)^2=228.1 \end{gathered}[/tex][tex]\text{Variance}=\frac{228.1}{10}=22.81[/tex]

Finally, the standard deviation is the square root of the variance, so the standard deviation is:

[tex]\text{standard deviation =}\sqrt[]{22.81}=4.78[/tex]

The sum of two consecutive integers is 17. Which equations could be used to find the twoconsecutive integers? Select all that are correct.A.X+X+1=17B.X+x=17C.2x=17D.2x+2=17E.X+X+2=17F.2x+1=17

Answers

hello

the answer to the question is option A

to solve a problem like this, let x represent the first number

x + (x + 1) = 17

x = first number

x + 1 = successive number

Are the graphs of the equations parallel, perpendicular, or neither? y= 2x +6 and y= 1/2x +3

Answers

Given the equations:

[tex]\begin{gathered} y=2x+6 \\ y=\frac{1}{2}x+3 \end{gathered}[/tex]

The equation has the form of slope - intercept form which is like:

[tex]y=m\cdot x+b[/tex]

Where m is the slope and b is y- intercept

So,

The slope of the first equation = 2

The slope of the second equation = 1/2

The graphs of the equations are parallel when the slopes are equal

The graphs of the equations are perpendicular when the product of the slopes = -1

so,

the slopes are not equal

The product of the slopes = 2 * 1/2 = 1

So, the graphs of the equations are neither parallel nor perpendicular.

Write using an exponent: 1×7×7×7×7×7a. 1×7×5b.[tex]1 \times {7}^{5} [/tex]c. [tex]1 \times {5}^{7} [/tex]

Answers

In the expression, the number 7 is multiplied to itself 5 times or five 7's are multiplied with each other. So exponential expression for the equation is,

[tex]1\cdot7\cdot7\cdot7\cdot7\cdot7=1\cdot7^5[/tex]

Option B is correct.

From a window 100ft above the ground in building A, the top and bottom of building B are sighted so that the angles are 70 degrees and 30 degrees respectively. Find the height of building B?

Answers

Given:-

From a window 100ft above the ground in building A, the top and bottom of building B are sighted so that the angles are 70 degrees and 30 degrees respectively.

To find:-

The height of building B.

So now, the image of the given data is,

So now we find the value of PS. so we get,

[tex]\begin{gathered} \tan \text{ 30=}\frac{100}{PS} \\ \frac{1}{\sqrt[]{3}}=\frac{100}{PS} \\ PS=100\sqrt[]{3} \end{gathered}[/tex]

So now we find the height of QS,

[tex]\begin{gathered} \tan \text{ 70=}\frac{QS}{PS} \\ 2.7474=\frac{QS}{100\sqrt[]{3}} \\ QS=100\sqrt[]{3}\times2.7474 \\ QS=475.84 \end{gathered}[/tex]

So the total height is,

[tex]100+475.84=575.84[/tex]

So the height of building B is 575.84

Kevin and Randy have a jar containing 67 coins all of which are either quarters or nickels. The total value of the coins in the jar $12.75 ... how many of each type of coin do they have?

Answers

Answer:

47quarters and 20 nickel

Explanation:

Let the number of quarters be x

Let the number of nickels be y

If there are 67 coins in the jar, then;

x + y = 67 ....1

1 quarter = 0.25x

1 nickel = 0.05y

If the total value of the coins in the jar is $12.75, then;

0.25x + 0.05y = 12.75 ....2

Multiply through by 100

25x + 5y = 1275 ....2

Solve 1 and 2 simultaneously

x + y = 67 ....1 * 25

25x + 5y = 1275 ....2 * 1

Using Elimination method

________________________

25x + 25y = 1,675

25x + 5y = 1275

Subtract

25y - 5y = 1675 - 1275

20y = 400

y = 400/20

y = 20

Substitute y = 20 into equation 1;

From 1; x + y = 67

x + 20 = 67

x = 67 - 20

x = 47

This means there are 47quarters and 20 nickel.

Yoko, Austin, and Bob have a total of $57 in their wallets. Austin has $7 less than Yoko. Bob has 2 times what Yoko has. How much does each have?

Answers

Yoko has $16 money, Austin has $9 and Bob has $32.

According to the question,

We have the following information:

Yoko, Austin, and Bob have a total of $57 in their wallets. Austin has $7 less than Yoko. Bob has 2 times what Yoko has.

Now, let's take the money Yoko has to be $x.

So, we have the following expressions for the money Austin and Bob have:

Austin = $(x-7)

Bob = $(2x)

Now, we have the following expression by adding them:

x+x-7+2x = 57

4x-7 = 57

4x = 57+7

4x = 64

x = 64/4

x = $16

Now, the money Austin has:

16-7

$9

Money Bob has:

2*16

$32

Hence, Yoko has $16 money, Austin has $9 and Bob has $32.

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Is (4,-3) a solution to the following system of equations?X - y = 42x + y = 5

Answers

Answer:

No, (4, -3) is not a solution to the system of equations

Explanation:

If (4, -3) is a solution to the given system of equations, then

for x = 4, and y = -3, both of the equations are satisfied.

x - y = 4 - (-3)

= 4 + 3

= 7

This is not 4, so the first equation is not satisfied

2x + y = 2(4) + (-3)

= 8 - 3

= 5

This equation is satisfied

It is sufficient to conclude that (4, -3) is not a solution to the system of equations since it doesn't satisfy the first equation

I need to solve each system by graphing. so pls help! This is Algebra 1

Answers

Given the system of inequalities:

2x + 3y < -6

-2x + 3y < 6

Let's solve the system by graphing.

To graph, rewrite the inequalities in slope-intercept form:

y = mx + b

Inequality 1:'

Subtract 2x from both sides:

2x - 2x + 3y < -2x - 6

3y < -2x - 6

Divide all terms by 3:

[tex]\begin{gathered} \frac{3y}{3}<-\frac{2x}{3}-\frac{6}{3} \\ \\ y<-\frac{2}{3}x-2 \end{gathered}[/tex]

Inequality 2:

Add 2x to both sides:

-2x + 2x + 3y < 2x + 6

3y < 2x + 6

Divde all terms by 3:

[tex]\begin{gathered} \frac{3y}{3}<\frac{2x}{3}+\frac{6}{2} \\ \\ y<\frac{2}{3}x+2 \end{gathered}[/tex]

Now, let's plot 3 points from each inequlality and connect using a straight edge.

Inequality 1:

When x = -3

Substitute -3 for x and solve for y:

[tex]\begin{gathered} y<-\frac{2}{3}(-3)-2 \\ \\ y<2-2 \\ \\ y<0 \end{gathered}[/tex]

When x = 0:

[tex]\begin{gathered} y<-\frac{2}{3}(0)-2 \\ \\ y<-2 \end{gathered}[/tex]

When x = 3:

[tex]\begin{gathered} y<-\frac{2}{3}(3)-2 \\ \\ y<-2-2 \\ \\ y<-4 \end{gathered}[/tex]

From inequality 1, we have the points:

(x, y) ==> (-3, 0), (0, -2), (3, -4)

For inequlity 2:

When x = -3:

[tex]\begin{gathered} y<\frac{2}{3}(-3)+2 \\ \\ y<-2+2 \\ \\ y<0 \end{gathered}[/tex]

When x = 0:

[tex]undefined[/tex]

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