The options are A,B,C,D can we make this quick please I am in a rush to turn this in!! thank you so much.

The Options Are A,B,C,D Can We Make This Quick Please I Am In A Rush To Turn This In!! Thank You So Much.

Answers

Answer 1

The function we have is:

[tex]y=-x+4[/tex]

First, we need to find the rate of change of this function and then we can compare it with the rate of change of each option.

To find the rate of change, we compare the given equation with the general slope-intercept equation:

[tex]y=mx+b[/tex]

Where m is the slope, also called the rate of change and b is the y-intercept.

By comparing the two equations, we find that the rate of change is:

[tex]m=-1[/tex]

So now we will analyze the given options to see in which of them we find a rate of change of -1.

Option A:

In this option (and in option B) we have a table of values for x and y.

We calculate the rate of change by taking two (x,y) points from the table,

Here, we will take the first two (x,y) values and label them as follows:

[tex]\begin{gathered} x_1=-4 \\ y_1=1 \\ x_2=-2 \\ y_2=2 \end{gathered}[/tex]

And we calculate the rate of change "m" using the slope formula:

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \end{gathered}[/tex]

Substituting the values we get:

[tex]m=\frac{2-1}{-2-(-4)}[/tex]

Solving the operations:

[tex]\begin{gathered} m=\frac{1}{-2+4} \\ m=-\frac{1}{2} \end{gathered}[/tex]

The rate of change if NOT -1, this option is not correct.

Option B. We do the same as in the first option.

Label the first two (x,y) values as follows:

[tex]\begin{gathered} x_1=4 \\ y_1=5 \\ x_2=8 \\ y_2=8 \end{gathered}[/tex]

And use the slope formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Substituting the values:

[tex]\begin{gathered} m=\frac{8-5}{8-4} \\ m=\frac{3}{4} \end{gathered}[/tex]

Again, the slope or rate of change is NOT -1, this is also not the option we are looking for,

Option C. In options, C and D we have a graph. To find the rate of change from the graph of a line, we take two points where the line passes, and find the rate of change as follows:

[tex]m=\frac{\text{change in y}}{change\text{ in x}}[/tex]

For the graph in C, we will take the following red points

Drawing a triangle between the points we can find the change in y and the change in x:

[tex]\begin{gathered} \text{change in y=-1} \\ \text{change in x=1} \end{gathered}[/tex]

Thus, the rate of change is:

[tex]\begin{gathered} m=-\frac{1}{1} \\ m=-1 \end{gathered}[/tex]

C is the correct option.

The Options Are A,B,C,D Can We Make This Quick Please I Am In A Rush To Turn This In!! Thank You So Much.
The Options Are A,B,C,D Can We Make This Quick Please I Am In A Rush To Turn This In!! Thank You So Much.

Related Questions

Which lists all of the x-intercepts of the graphed function? A. (0,6)B. (1,0) and (2,0)C. (1,0), (2, 0), and (-3,0)D. (1,0), (2,0), (-3, 0), and (0, 6)

Answers

From the graph, the points at which the curve touch the x-axis is the intercepts on x

looking at the graph, the curve cut through the x axis at points -3, 1 and 2

hence the points will be

(-3, 0), (1, 0) and (2, 0)

Thus, the correct option is C;

(1, 0), (2, 0) and (-3, 0)

Not sure how to figure this out.Options:A. 49 square feet B. 7 square feet. C. 28 square feet. D.14 square feet

Answers

According to the information given in the exercise, the pen for his rabbit is square and each side is 7 feet long.

You know that the formula for calculating the area of a square is:

[tex]A=s^2[/tex]

Where "s" is the length of each side of the square.

In this case:

[tex]s=7ft[/tex]

Then, you need to substitute this length into the formula and then evaluate, in order to find the area. You get:

[tex]\begin{gathered} A=(7ft)^2 \\ A=49ft^2 \end{gathered}[/tex]

Hence, the answer is: Option A.

Is the ordered pair (3,-4) a solution to : 5x-2y=17

Answers

Given

[tex]5x-2y=17[/tex]

Set x=3 and solve for y, as shown below

[tex]\begin{gathered} x=3 \\ \Rightarrow5*3-2y=17 \\ \Rightarrow15-2y=17 \\ \Rightarrow-2y=2 \\ \Rightarrow y=-1 \end{gathered}[/tex]

Therefore, a solution to the equation is the ordered pair (3,-1).

(3,-4) cannot be a solution to the equation.

Hi, I need help with this problem please. No explanations/steps required. Just need the final answer

Answers

To simplify the expression we fist need to express each trigonometric function in terms of sines and cosines; to do this we need to remember that:

[tex]\begin{gathered} \sec x=\frac{1}{\cos x} \\ \csc x=\frac{1}{\sin x} \end{gathered}[/tex]

With this in mind we have:

[tex]\begin{gathered} \frac{\csc x}{\sec x}=\frac{\frac{1}{\sin x}}{\frac{1}{\cos x}} \\ =\frac{\cos x}{\sin x} \end{gathered}[/tex]

Finally we need to remember that:

[tex]\cot x=\frac{\cos x}{\sin x}[/tex]

Therefore, we have that:

[tex]\frac{\csc x}{\sec x}=\cot x[/tex]

Solve the quadratic equation by completing the square.4a²- 48a +52 = 0a= _,_

Answers

Given

[tex]4a^2-48a+52=0[/tex]

Solution

[tex]\begin{gathered} 4a^2-48a+52=0 \\ So\text{ divide both sides by 4} \\ \frac{4a^2}{4}-\frac{48a}{4}+\frac{52}{4}=0 \\ which\text{ gives } \\ a^2-12a+13=0 \\ Keep\text{ a on LHS} \\ a^2-12a=-13 \\ Take\text{ the half of coefficient of a and square it} \\ (-\frac{12}{2})^2=36 \\ \\ rewrite\text{ as perfect square} \\ \\ (a-6)^2=-13+36 \\ (a-6)^2=23 \\ \end{gathered}[/tex]

[tex]\begin{gathered} a-6=\pm\sqrt{23} \\ a=6\pm\sqrt{23} \end{gathered}[/tex]

[tex]\begin{gathered} a=10.79583\text{ ,}a=1.20416 \\ or \\ a=6+\sqrt{23},\:a=6-\sqrt{23}\quad \\ \\ \end{gathered}[/tex]

help please and thankyou Graph the line y = 2x + 3

Answers

the line will be:

we can find the method of finding the intercepts and then link them with a unique line:

the x-intercept is when y=0 then 2x+3=0 then x=-3/2=-1.5

the y-intercept is when x=0 then y=3

then we can link the points (-1.5,0) and (0,3) and we have the graph of the given line.

Triangle JKL is rotated 270° counterclockwise about the origin to form triangle J'K'L'. What is the y-coordinate of point J'? y 6 5 4 K 3 2. 1 -6 -5 -4 -3 -2 1 2 3 4 0 -1 6 Jo -2 3 4 -5 L -6 Type the answer in the box.

Answers

Rotation of 270° ,counterclockwise

Find center point of triangle

JK = √ 9^2 +5^2

. = √ 106

JL = √9^2 + 3^2

. = √90

KL = 8

Then now find point J'

Distance from J to origin = JO = √4^2+2^2 =√20

Angle is arctan (2/4) = 26.56°

Then new coordinates J' are

Angle 270+26.56 = 296.56°

From origin trace a line perpendicular to JO

then

y = √20• Cos 26°

y = 4

Answer:

-4

Step-by-step explanation:

good luck kiddos :)

A local road rises 33 feet for every 423 feet of pavement. What is the slope of the road? Simplify your answer.

Answers

If a local road rises 33 feet for every 423 feet of pavement, the slope of the road will be rate of change of pavement with respect to the road. This is expressed as;

slope of the road = 423/33

Slope of the road = 12.82

Hence the slope of the road is 12.82

Mixture of 40 liters of paint is 25% red tint, 30% yellow tint and 45% water. Five liters of red tint and five liters of yellow tint are added to the original mixture. What is the percent of water in this new mixture?

Answers

Step 1

25% of 40 litres is;

[tex]\frac{25}{100}\times40=10\text{ litres of red tint}[/tex]

Step 2

30% of 40 litres;

[tex]\frac{30}{100}\times40=\text{ 12 litres of yellow tint}[/tex]

Step 3

45% of 40 litres;

[tex]\frac{45}{100}\times40=18\text{ litres}[/tex]

Step 4

5 liters of red tint are added and 5 liters of yellow tint are added to the original mixtures

[tex]\begin{gathered} 10\text{ +5=15 litres of red tint} \\ 12+5=17\text{ liters of yellow tint} \\ 18\text{ liters of water} \end{gathered}[/tex]

Answer; What is the percent of water in this new mixture?

[tex]\begin{gathered} Total=15+17+18=50\text{ liters} \\ \frac{18}{50}\times100=36\text{\%} \end{gathered}[/tex]

John is a salesman for a company. he earns a straight commission at a rate of 4 and 1/2% . last month his total says were $82,969. what is his gross monthly income for last month?

Answers

hello

his gross income was = $82,969

commission = 4 1/2% or 4.5%

since we have the gross income, we can use that data to find his actual salary for the month.

all we need to do is find 4.5% of 82969 and subtract the value from it

[tex]\begin{gathered} 4.5\text{ \% of 82969} \\ \frac{4.5}{100}=\frac{x}{82969} \\ \text{cross multiply both sides and solve for x} \\ 100\times x=4.5\times82969 \\ 100x=373360.5 \\ \text{divide both sides by 100} \\ \frac{100x}{100}=\frac{373360.5}{100} \\ x=3733.605 \end{gathered}[/tex]

the commission pay was $3733.605

to find his actual salary, subtract 3733.605 from 82969

[tex]\text{ income}=82969-3733.605=79235.395[/tex]

from the calculations above, his income for last month was $79235.395

One month Susan rented 5 movies and 6 video games for a total of $57. The next month she rented 3 movies and 2 video games for a total of $25. Find the rental cost for each movie and each video game?

Answers

The rental cost of each movie is $4.50

The rental cost of each video game is $5.75

Explanation:

let the cost of one movie = m

let the cost of one video games = v

1st month:

Number of movies = 5

number of video games = 6

Total cost of both = $57

Total cost = cost of one movie(Number of movies ) + cost of one video (Number of video games)

57 = m(5) + v(6)

57 = 5m + 6v ...equation 1

2nd month:

Number of movies = 3

number of video games = 2

Total cost of both = $25

Total cost = cost of one movie(Number of movies ) + cost of one video (Number of video games)

25 = m(3) + v(2)

25 = 3m + 2v ...equation 2

57 = 5m + 6v ...equation 1

25 = 3m + 2v ...equation 2

Using elimination method:

To eliminate v, we would multiply equation 2 by 3:

3(25) = 3(3m) + 3(2v) ...equation 2

75 = 9m + 6v ...equation 2

57 = 5m + 6v ...equation 1

subtract equation 1 from 2:

75 - 57 = 9m - 5m + 6v - 6v

18 = 4m + 0

18 = 4m

m = 18/4

m = 4.5

Substitute for m in any of the equation:

Using eqauation1: 57 = 5m + 6v

57 = 5(4.5) + 6v

57 = 22.5 + 6v

57 - 22.5 = 6v

34.5 = 6v

v = 34.5/6

v = 5.75

The rental cost of each movie is $4.50

The rental cost of each video game is $5.75

Matt drew the two rectangles shown in thediagram below.ABD16 in.ABD12 inсMatt dilated Rectangle ABCD to createRectangle A'B'CD'.What scale factor did Matt use todilate Rectangle ABCD?

Answers

[tex]\begin{gathered} \\ \text{scale}=\frac{12}{16}=0.75 \\ \\ \text{The scale is 0.75 } \end{gathered}[/tex]

Write an inequality to match the statement.The difference of a number x and 7 is less than or equal to the sum of the same number x and 5

Answers

The difference of a number x and 7 is less than or equal to the sum of the same number x and 5​

The difference means subtraction.

A number is x

Less than or equal is represented with the symbol ≤

So:

The difference of a number x and 7

x-7

is less than or equal to the sum of the same number x and 5​

≤ x+5

Altogether:

x-7≤ x+5

1Convert without rounding:8into a decimal (no need to show work)Τ Τ Τ ΤParagraphVArialV3 (12pt)V

Answers

Given: the fraction 1/8.

Objective is to convert this fraction in to decimal.

[tex]\frac{1}{8}=0.125[/tex]

Answer: 0.125

The graph of a function f is given. Use the graph to estimate the following. (Enter your answers using interval notation) PLEASE HELP!! confused on whole problem

Answers

From the graph

Domain = [ -1 , 4]

Range = [ -1 , 3 ]

b) When you look at the graph, the function f

Increasing = [ -1, 1 ] , [ 2, 4 ]

Decreasing = [ 1 , 2 ]

Which expression is a factor of 9r2 – 4r + 1? F3r-1 Gr 1 H 9741 3 There are no real factors.

Answers

There are no real factors

Here, we want to factorize the given expression

To check if there are real factors, we will need to get the determinant

mathematically, we have this as;

[tex]D=b^2-4ac[/tex]

where a is 9, b is -4 and c is 1

Substituting these values;

[tex]D=(-4)^2-4(9)(1)\text{ = 16-36 = -20}[/tex]

As we can see, the value of the determinant is negative

Whenever the determinant value is negative, there are no real roots

Complete the explanation of whether the graph represents a proportional oa neno relationship 5 5 5 relationship The graph represents a (select) (select) proportional nonproportional

Answers

We are given the graph of a line, and we are asked to determine if it is a proportional or non-proportional relationship. Let's remember the general form of the equation of a line, that is:

[tex]y=mx+b[/tex]

where "m" is the slope and "b" the y-intercept. The y-intercept is the value where the line touches the y-axis. According to the graph, the value of "b" is b = 1, therefore, the equation of the line would be:

[tex]y=mx+1[/tex]

A proportional relationship is of the form:

[tex]y=kx[/tex]

since the value of "b" is different from zero the relationship is non-proporsional.

The relationship is non-proportional

Evaluate the input/output table for the expression x - 9.Хy-101

Answers

x - 9

when x = -1

out put is -1 -9 = -10

when x = 0

Output is 0-9 = -9

when x = 1

output = 1-9 = -8

x y

-1 -10

0 -9

1 -8

Fill in the following values for a 45-45-90 triangle Leg Leg Hypotenuse 5 А B C С D 32 Fill in the following values for a 30-60-90 triangle Short Leg Long Leg Hypotenuse 6 E H 20 G

Answers

First Part 45-45-90 Triangle

first triangle

where the two angles different to 90° are same, the measure of the legsof the triangle are the same

then

[tex]A=5[/tex]

and to calculate B or the hypotenuse we use pythagoras

[tex]a^2+b^2=h^2[/tex]

where a and b are legs and h the hypotenuse

replacing

[tex]\begin{gathered} 5^2+5^2=h^2 \\ 25+25=h^2 \\ 50=h^2 \\ h=\sqrt[]{50} \\ h=5\sqrt[]{2} \end{gathered}[/tex]

the hypotenuse or B is

[tex]B=5\sqrt[]{2}[/tex]

Second triangle

legs of the triangle have the same value then if we apply pythagoras

[tex]a^2+b^2=h^2[/tex]

and replace the legs with the same value(a)

[tex]\begin{gathered} a^2+a^2=h^2 \\ 2a^2=h^2 \end{gathered}[/tex]

we can replace the hypotenuse and solve a

[tex]\begin{gathered} 2a^2=(3\sqrt[]{2})^2 \\ 2a^2=18 \\ a^2=\frac{18}{2} \\ \\ a=\sqrt[]{9} \\ a=3 \end{gathered}[/tex]

value of each leg is 3 units, then

[tex]C=D=3[/tex]

Second part 30-60-90 triangle

First triangle

we use trigonometric ratios to solve, for example I can use tangent for the angle 60 to find E

[tex]\tan (\alpha)=\frac{O}{A}[/tex]

where alpha is the angle, O the oppiste side of the angle and A the adjacet side of the angle

using angle 60°

[tex]\begin{gathered} \tan (60)=\frac{E}{6} \\ \\ E=6\tan (60) \\ \\ E=6\sqrt[]{3} \end{gathered}[/tex]

now using sine we calculate F or the hypotenuse

[tex]\sin (\alpha)=\frac{O}{H}[/tex]

where alpha is the angle, O the opposite side from the angle and H the hypotenuse

using angle 60°

[tex]\begin{gathered} \sin (60)=\frac{E}{F} \\ \\ F=\frac{E}{\sin (60)} \\ \\ F=\frac{6\sqrt[]{3}}{\sin (60)} \\ \\ F=12 \end{gathered}[/tex]

Second triangle

we use sine with 60° to find H

[tex]\begin{gathered} \sin (\alpha)=\frac{O}{h} \\ \\ \sin (60)=\frac{H}{20} \\ \\ H=20\sin (60) \\ H=10\sqrt[]{3} \end{gathered}[/tex]

use cosine with 60° to find G

[tex]\begin{gathered} \cos (\alpha)=\frac{A}{h} \\ \\ \cos (60)=\frac{G}{20} \\ \\ G=20\cos (60) \\ \\ G=10 \end{gathered}[/tex]

Final Values

[tex]\begin{gathered} A=5 \\ B=5\sqrt[]{2} \\ C=3 \\ D=3 \\ E=6\sqrt[]{3} \\ F=12 \\ G=10 \\ H=10\sqrt[]{3} \end{gathered}[/tex]

What is the output value for the following function, f(x) = 5x - 2 if the input value is 3?options:1751131

Answers

Solution:

Given the function below

[tex]f(x)=5x-2[/tex]

Where

[tex]\begin{gathered} x\text{ is the input value} \\ f(x)\text{ is the output value} \end{gathered}[/tex]

If the input value is 3, i.e. x = 3, the output value will be

[tex]\begin{gathered} f(x)=5x-2 \\ f(3)=5(3)-2=15-2=13 \\ f(3)=13 \end{gathered}[/tex]

Hence, the output value is 13

If a population isa sample of the population could be

Answers

REQUIRED;

To identify which of the statements given properly depicts the population and the sample.

Explanation:

In statistics and research processes, a population ideally refers to the entire group that we want to study and reach conclusions about. It can best be described as all-inclusive.

On the other hand, a sample is a portion taken out of an entire population for the purpose of studies or research and the appropriate data is collected from these.

We shall now examine the options given one after the other.

(A) Registered state voters randomly collected for a poll; all citizens of the state. This represents SAMPLE and POPULATION

(B) All professional football players; all professional athletes. This represents POPULATION and POPULATION

(C) All customers at a shopping mall; people who purchased shoes. This represents POPULATION and SAMPLE.

(D) Passengers with window seats; all passengers on an airplane. This represents SAMPLE and POPULATION.

ANSWER:

Therefore, the correct answer is OPTION C.

"If a population is all customers at a shopping mall, a sample of the population could be peole who purchased shoes.

Find the mean, median, and mode for the data set. If there is no mode, write none. If there is more than one mode,write your solutions from least to greatest, separated by a comma.50,30,40,10,20,80,60,90,10,30,110, 70mean:median:mode:

Answers

Answer:

• Mean: 50

,

• Median: 45

,

• Mode: 10,30

Explanation:

Given the data set:

[tex]50,30,40,10,20,80,60,90,10,30,110,70[/tex]

Before we begin, arrange the numbers from the least to the greatest.

[tex]10,10,20,30,30,40,50,60,70,80,90,110[/tex]

(a)Mean

To find the mean, add up the numbers and divide by the number of items (12 in this case).

[tex]\begin{gathered} Mean=\frac{10+10+20+30+30+40+50+60+70+80+90+110}{12} \\ =\frac{600}{12} \\ Mean=50 \end{gathered}[/tex]

The mean of the dataset is 50.

(b)Median

The median is the number in the middle of the dataset when arranged in ascending order.

• There are two numbers in the middle: 40 and 50

,

• Take the average to find the median.

[tex]Median=\frac{40+50}{2}=\frac{90}{2}=45[/tex]

The median of the dataset is 45.

(c)Mode

The mode is/are the number(s) that appear the most number of times..

[tex]10,10,20,30,30,40,50,60,70,80,90,110[/tex]

In the dataset:

• 10 appears twice

,

• 30 appears twice

The modes of the dataset are 10 and 30.

find the volume for the spear shown to The Right. Use 3.14 for pi sphere is 5.8

Answers

Semicircle perimeter is 5.8 m

THEN

2π • R + 2R = 5.8

R = 5.8/(2π + 2) = 0.7 meters

Now find Volume

Volume V = (4/3)•π•R^3

V= (4/3)•π•(0.7^3) = 1.438 cubic meters

V=. 1.438 m^3


Rita earns scores of 83, 87, 85, 88, and 90 on her five chapter tests for a certain class and a grade of 82 on the class project.
The overall average for the course is computed as follows: the average of the five chapter tests makes up 30% of the course
grade; the project accounts for 30% of the grade; and the final exam accounts for 40%. What scores can Rita earn on the final
exam to earn a "B" in the course if the cut-off for a "B" is an overall score greater than or equal to 80, but less than 90? Assume>that 100 is the highest score that can be earned on the final exam and that only whole-number scores are given.>To obtain a "B", Rita needs to score between>and>inclusive

Answers

Given:

Rita earns scores of 83, 87, 85, 88, and 90 on her five-chapter tests for a certain class.

And a grade of 82 on the class project.

First, we will find the average of the scores of the five tests

[tex]5-tests\text{ }average=\frac{83+87+85+88+90}{5}=\frac{433}{5}=86.6[/tex]

The overall average for the course is computed as follows:

30% of the course grade ⇒ Rita get 86.6

30% of project grade ⇒ Rita get 82

40% of the final exam ⇒ let Rita get x

We will find the value of x provided that Rita will earn a "B" score

a "B" is an overall score greater than or equal to 80, but less than 90

So, we will find (x) as follows:

[tex]\frac{30*86.6+30*82+40*x}{100}\ge80[/tex]

Solve the inequality to find (x):

[tex]\begin{gathered} 5058+40x\ge8000 \\ 40x\ge8000-5058 \\ 40x\ge2942 \\ x\ge\frac{2942}{40} \\ \\ x\ge73.55 \end{gathered}[/tex]

And the upper limit will be as follows:

[tex]\frac{30\times86.6+30\times82+40x}{100}<90[/tex]

Solve to find (x):

[tex]\begin{gathered} 5058+40x<9000 \\ 40x<9000-5058 \\ 40x<3942 \\ x<\frac{3942}{40} \\ \\ x<98.55 \end{gathered}[/tex]

So, the answer will be:

To obtain a "B", Rita needs to score between 73.55 and 98.55

determine whether the triangle with the given side lengths is a right triangle4 ,7, 11

Answers

For the a triangle to be a right angle triangle, the length of the three sides must form a pythagorean triple. This means that if we apply pythagoras theorem, the square of the length of the longest side must equal the sum of the squares of the length of the other sides. This means that

11^2 must be equal to 4^2 + 7^2

11^ = 121

4^2 + 7^2 = 16 + 49 = 65

Since they are not equal, then the triangle with the given sides, 4, 7, 11 cannot form a right angle triangle.

Convert the Cartesian equation x^2 + y^2 + 3y = 0 to a polar equation.r^2 = -3 sin θr = √3 sin θr = -3 sin θ

Answers

SOLUTION

From the question

[tex]x^2+y^2+3y=0[/tex]

This becomes

[tex](x^2+y^2)+3y=0[/tex]

In polar,

[tex]\begin{gathered} x^2+y^2=r^2 \\ \\ \text{and } \\ \\ y=r\sin \theta \end{gathered}[/tex]

So, this becomes

[tex]\begin{gathered} r^2+3r\sin \theta=0 \\ \\ \frac{r^2}{r}=\frac{-3r\sin \theta}{r} \\ \\ r=-3\sin \theta \end{gathered}[/tex]

I know the answer to fill i is -24 but how do I simplify ??

Answers

[tex]a^{-24\text{ }}=\frac{1}{a^{24}}[/tex]

The first expression es the simplified expression using the property of negative exponents.

Keico is selling rattle tickets to raise money for the sancol band. The odds againet winning a prize in the raffleare 121. What is the probability of winning a prize? Express your anewer as a decimal. if necessary, round youranower to the nearest thousandth.0 130 0.923O 0.083O 0.0777

Answers

Given:

The odds against winning a prize in the raffle are 12:1

[tex]\begin{gathered} \text{Probability of winning a prize=}\frac{1}{13} \\ \text{Probability of winning a prize=}0.077 \end{gathered}[/tex]

0.077 is the probability of winning a prize.

Use the given information to create the equation for the rational function. The function is written in factored form to help you see how the given information shapes our equation. If the leading coefficient is not an integer enter the value as a fraction.Vertical asymptote at x=-1, double zero at x=2, y-intercept at (0,2).The numerator is: Answer (x-Answer )(x-Answer )The denominator is: (x+Answer )

Answers

Given:

• Vertical asymptote at : x = -1

,

• Double zero at: x = 2

,

• y-intercept at: (0, 2)

Let's create the equation for the rational function using the given properties.

Since the vertical asymptote is at x = -1, to find the deominator of the equation, equate the vertical asymptote to zero.

Add 1 to both sides:

[tex]\begin{gathered} x+1=-1+1 \\ x+1=0 \end{gathered}[/tex]

Therefore, the denominator of the function is ==> x + 1

Since it has a double zero at x = 2, we have the factors:

[tex]\Longrightarrow(x-2)(x-2)[/tex]

We now have the equation:

[tex]y=\frac{a(x-2)(x-2)}{x+1}[/tex]

Also, the y-intercept is at: (0, 2)

To find the value o a, substitute 2 for y and 0 for x then evaluate:

[tex]\begin{gathered} 2=\frac{a(0-2)(0-2)}{0+1} \\ \\ 2=\frac{a(-2)(-2)}{1} \\ \\ 4a=2 \\ \\ a=\frac{2}{4} \\ \\ a=\frac{1}{2} \end{gathered}[/tex]

Therefore, the rational function is:

[tex]y=\frac{\frac{1}{2}(x-2)(x-2)}{x+1}[/tex]

ANSWER:

[tex]y=\frac{\frac{1}{2}(x-2)(x-2)}{x+1}[/tex][tex]\begin{gathered} \text{Numerator: }\frac{1}{2}(x-2)(x-2) \\ \\ \\ \text{Denominator: (x + 1)} \end{gathered}[/tex]

simplify 2a x a x 3a + b x 4b

Answers

[tex]6a^3+4b^2[/tex]

Explanation:

[tex]\begin{gathered} 2a\text{ *a *a * 3a = 2 * 3 * a *a * a } \\ 6\text{ * a}^3\text{ = 6a}^3 \end{gathered}[/tex][tex]\begin{gathered} \text{b * 4b = 4 *b * b } \\ \text{4 * b}^2\text{ = 4b}^2 \end{gathered}[/tex]

Put them together

[tex]2a*a*a*3a\text{ + b * 4b = 6a}^3+4b^2[/tex]

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