mechanical energy is____one because the roller coaster____one energy due to friction and air resistance as it travels down the track.

Answer:

~ 5300 W  ( rounded)

Explanation:

The POTENTIAL energy of 90 kg of water before it falls 60 m

 is   mgh =  90 * 9.81 * 60 = 52974 J

POWER = energy / time = 5297.4 W    ( assuming no losses)

Since space is so vast, many astronomers choose to use a unit of measurement known as a parsec instead of measuring distances in miles or kilometers. the nearest star, Alpha Centauri, in your mind

Why then would Solo use a parsec, which measures distance rather than time, to describe how fast his ship could move? Here, two distinct narratives are in play.

The Kessel RuEmpire then was among the busiest smuggling routes in the Galactic Empirethe Galactic Empire, the Kessel Run was one of the busiest smuggling routes. The Kessel Run, according to Han Solo, was completed by his Millennium Falcon in fewer than twelve parsecs. Unlike time, a parsec measures distance. When he said this, Solo wasn't specifically referring to his ship's speed speed of his ship.

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The moment of inertia (Icm) of the uniform flat disk without the point mass = Icm = MR².

The moment of inertia with respect to point P on the disk without the point mass =  Ip = 3MR².

The total moment of inertia (of the disk with the point mass with respect to point P) = I total = 5MR².

We know from the case, that:

Mass = 2M

Radius = R

Mass at the edge = M₂ = 1/2M

Distance between the centre of mass to point P = p = R

Distance of the point mass to point P = d = 2R

We know that the moment of inertia for an uniform flat disk = 1/2mr².

(a) Then the moment of inertia for the uniform flat disk is:

= Icm = 1/2mr²

= Icm = 1/2(2M)(R²)

= Icm = MR²

(b) Next, we will find the moment of inertia of the disk with respect to point P. We know that point P is positioned at the arc of the disk. Hence,

= Ip = Icm + mp²

= Ip = MR² + (2M)R²

= Ip = 3MR²

(c) Then, the total moment of inertia of the disk with the point mass is:

= I total = Ip + I mass

= I total = 3MR² + (1/2M)(2R)²

= I total = 3MR² + 2MR²

= I total = 5MR²

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The complete question:

A uniform flat disk of radius R and mass 2M is pivoted at point P A point mass of 1/2 M is attached to the edge of the disk 2M 2 M Part (a) Calculate the moment of inertia ICM of the disk (without the point mass) with respect t0 the central axis of the disk in terms of M and R. Part (b) Calculate the moment of inertia [p of the disk (without the point mass) with respect to point P in terms of M and R. Part (c) Calculate the total moment of inertia [of the disk with the point mass with respect to point P in terms of M and R.

The cart's increased speed is the same as when it first took off.

Rate is the speed from which an object travels along a path over time, whereas velocity is the speed and orientation of an item's motion.

At first, the cart is at rest.

So, u = 0 m/s.

A brief period of time is spent with a constant force applied.

The final speed that the force gives the cart is what we'll call v.

Newton's first equation of motion yields the following results:

v = u + at

Where;

The ultimate speed =v.

The starting speed =u.

Acceleration = a.

Time = t

u = 0 m/s, therefore we now have;

v = 0 + at

v = at

Let's now use Newton's second rule of motion to construct a formula to introduce force;

F = ma

Where;

Force = f.

Mass = m.

Acceleration = a.

So,

= a = F/m.

Substituting in v = at,

= v = (F/m)t

The final speed, v, is evidently exactly related to the force. So, if the force is constant, the end speed will also stay constant.

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The complete question is -

A constant force is exerted for a short time interval on a cart that is initially at rest on an air track. This force gives the cart a certain final speed. Suppose we repeat the experiment but, instead of starting from rest, the cart is already moving with constant speed in the direction of the force at the moment we begin to apply the force.

After we exert the same constant force for the same short time interval, the increase in the cart's speed:

A. is equal to two times its initial speed.

B. is equal to the square of its initial speed.

C. is equal to four times its initial speed.

D. is the same as when it started from rest.

E. cannot be determined from the information provided.

The image given, is explained in terms of Newton's 1st law of motion.

Based on Newton's First Law of Motion (Inertia).  An object at rest remains at rest, and an object in motion continues in motion at a steady speed and in a straight path until operated on by an unbalanced force.

Newton's first rule of motion states that if a pan of water were being moved along a track, the water would tend to keep moving ahead. However, the water will appear to splash to the right while it goes to the left. Space is nearly a perfect vacuum, devoid of both gravity and matter. Think about a satellite travelling 17,500 mph around the Earth. If a rock were to be launched from the satellite, it would orbit the earth adjacent to the satellite at a speed of 17,500 mph.

Here, in the given image, it is shown that the sofa is remain in the place unless a person forcefully move it from one place to another.

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The velocity of the wave is 1.5 m/s.

Since, the crest occurs every 2 seconds,

Time period = t = 2 s

Distance between two crests = Wavelength of the wave = λ = 3 m

Frequency of the wave = f

The velocity of the wave is = v =

The velocity of a wave is equal to the product of its wavelength and frequency (number of vibrations per second) and is independent of its intensity.

= v = λ X f

and, f = 1/t

= v = λ / t

= v = 3/2

= v = 1.5 m/s

Thus, the velocity of the wave is 1.5 m/s.

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Dark energy is the energy associated with the motion of particles of dark matter. FALSE

Dark Energy is a hypothetical form of energy that exerts a negative, repulsive pressure, behaving like the opposite of gravity.

Another definition of dark energy is as follows; it is a hypothetical form of energy that produces a force that opposes gravity and is thought to be the cause of the accelerating expansion of the universe.

The force of gravity which force from dark energy opposes is given as;

F = Gm₁m₂/R²

where;

Thus, the force of gravity which is being opposed by the force produced by the dark energy is directly proportional to the mass of two objects in the universe and inversely proportional to the square of the distance between the two objects.

So the given statement is FALSE.

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The magnitude of the normal force on a 15.0kg block, the block is resting on a surface titled up at a 30.0 angle with respect the horizontal is 127.3 N.

We are told the block is resting on a surface tilted up at a 30° angle with respect to the horizontal.

∴Thus, resolving the force in the horizontal direction will give us the normal force,

∴ θ = 30⁰

∴ m = 15 kg

∴ N = mg cosθ°

we know that g = 9.8 m/s

∴ N = 15 × 9.8 × (cos 30° )

∴ N = 15 × 9.8 × 0.866

∴ N = 127.3 N

Hence, the magnitude of force is 127.3N

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The time constant of the circuit is 0.9163τ

The charge of RC circuit is

q = 0.6q0

The expression for a charging capacitor is given by,

q = q0 ( 1-  e⁻⁽⁻t/T⁾)

Here, t

is the time, q0 is the equilibrium charge of circuit and τ is the time constant.

Substitute all the known values in the above formula.

t≈0.9163τ

The term time constant in an RC circuit can be evaluated with the help of the equilibrium charge of the circuit, charge at a specific time and time. The relation for a charging capacitor is an exponential expression.

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The acceleration due to gravity on jupiter is 23 m/s². And the correct option is D. 23 m/s².

Acceleration due to gravity is the acceleration gained by an object due to gravitational force. Its SI unit is m/s².

To calculate the acceleration due to gravity on jupiter, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solve for g'

Hence, the acceleration due to gravity on jupiter is 23 m/s².

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Metamorphic rock was under the most pressure and the highest temperature.

Rocks found under extremely high pressures and average to high temperatures are called eclogite and are often rich in cardinal and pyroxene. 8. The hornfels contains a series of rocks that result from contact metamorphism under low pressures and a wide range of temperatures.

Metamorphic rocks form when live rocks are exposed to heat and pressure deep within the Earth's surface. The new rock is completely different from the other.

So we can conclude that A rock with this feeling is called gneiss. Since gneisses form at the highest temperatures and pressures, some partial melting may occur.

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It will take 1.1824 min for the reactant concentration to decrease from 0. 13 m to 0. 088 m.

K = 0.33/min

for first-order reaction

K×t = ln([A0]/[A])

[A0] = 0.13 M

[A] = 0.088 M

t = ln (0.13/0.088)/0.33 = 1.1824 min

A first-order reaction depends on the awareness of the most effective reactant (a unimolecular response). other reactants may be present, however, their attention has no impact on the fee. The fee regulation for a primary order response is --d[A]/dt = okay[A],

Although not affecting the above math, the general public of first-order reactions continues through intermolecular collisions. Such collisions, which contribute the electricity to the reactant, are always 2nd order. The fee of those collisions is, but, masked via the reality that the price determining step stays the unimolecular breakdown of the energized reactant. The half of-existence is impartial of the beginning awareness and is given with the aid of t1/2 = In(2)/k

In organic chemistry, the class of SN1 (nucleophilic substitution unimolecular) reactions includes first-order reactions. for instance, in the reaction of aryldiazonium ions with nucleophiles in an aqueous solution, [ArN2+] + X− → ArX + N2, the fee equation is v0 = ok[ArN2+], wherein Ar shows an aryl group.

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The minimum coefficient of friction required is 0.885  for a 925kg car rounds an unbanked curve at a speed of 25m/sec.

We know that if a body wants to travel from one place to another place, we need friction to move along the surface.

Now,we know that centripetal force is required to move along a curve.Also,due to friction same amount of force acts on the car to move along the surface.

It means centripetal force=mv²/r where v is the velocity of the body and r is the radius of the body is equal to force applied by the friction which is equal to =μmg  

So,mv²/r=μmg  

=>v²/r =μg

=>μ= v²/rg

On putting the values of speed, radius and acceleration due to gravity

=>μ=(25)²/(72×9.8)

=>μ=625/705.6

=>μ=0.885

Hence, required value of coefficient of friction is 0.885.

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The reaction force at Q is 4N.

A support reaction is a force on a support or a resulting restraining end moment, which results due to a prevented possibility to move. In the case of structural systems, support reactions are in equilibrium with the external forces acting on the structure.

The uniformly distributed load can be replaced by a concentrated load acting at the centre of gravity of the UDL. The total load on beam is the UDL multiplied by the length of the beam,

So  support reaction is,

R = Load × Length

In this question,

The equation of equilibrium of moments is

[tex]R_{Q[/tex] × 40 - Mg×20-  4N× 10 = 0

So, [tex]R_{Q[/tex] = 10 N× 20 + 4N× 10 ÷ 40 = 4 N

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This ranges from 10 to 200 degrees Fahrenheit (ca. 93 °C) in the majority of cooling systems. The heat flux ranges from 5,000 to 15,000 Btu/ft2/hr and is typically low.

Use the equation Q = MC T to determine the amount of heat released during a chemical reaction. Q represents the heat energy transferred (in joules), m represents the mass of the liquid being heated (in kilograms).

C represents the liquid's specific heat capacity (joule per kilogram degrees Celsius), and T represents the change in temperature.

Therefore, The heat flux can reach 3,000,000 Btu/ft2/hr in extreme circumstances, including the indirect cooling of molten metal.

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The range will become the 4 times of intial velocity

if the initial velocity is doubled then the horizontal range will be 4 times.

R = u² sin²θ / g

R directly proportional U²

if initial velocity becomes 2 times, then horizontal range becomes 4 times.

This will be when angel of projection is same, the horizontal velocity is directly proportional to initial velocity.

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Answer:

The penguins are gliding foward without stopping because there is no external force changing their state.

Explanation:

Newtons first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

In a particle system of smoke, color over Lifetime is used to change the dense black, to semi-transparent gray and finally white.

The Color over Lifetime module permits you to change the Color and Alpha qualities over time.

The Force over Lifetime module permits you to add wind-impacted articulations to Particles.

For instance, on the off chance that you set it as displayed in the picture, it will appear as though the breeze is blowing to one side.

The Limit Velocity over Lifetime module permits you to dial back the development of a molecule.

This permits you to execute articulations like air opposition.

In the Speed field of the Limit Velocity over Lifetime module, you can enter the speed that outcomes from the deceleration because of air opposition.

Dampen is the magnitude of the air resistance.

Set Start Speed to 20, Speed in the Limit Velocity over Lifetime module to 0, and Dampen to 0.1.

Assuming Hose is set to 0.1, the speed of 20 will continuously move toward 0 lastly stop.

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The plane's landing speed was 250 m/s.

The force required to slow the plane down is equal to the spring constant multiplied by the amount it stretched. Thus, we can use the equation:

where F is the force required, k is the spring constant, and x is the amount stretched.

In this case:

We can use the equation for momentum to solve for the plane's speed:

where p is the momentum, m is the mass, and v is the velocity.

In this case:

Rearranging for v, we get:

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AnswerAnswerAnswer:.

Explanation:

.

She boosts her angular velocity when she pulls her arms in toward her body since doing so causes her rate of spin to increase dramatically, which lowers her moment of inertia. She pulls her arms in with effort, increasing rotational kinetic energy.

The angular momentum of the system of particles is conserved if there is no net external torque at a given position in a fixed inertial reference frame:

You can see that the whole angular momentum is conserved. Any one of the individual angular momenta can change as long as the aggregate remains unchanged. This equation represents the conservation of linear momentum when there is no outside force acting on the system.

As a result, since the conservation of angular momentum can be demonstrated by an ice skater doing a spin. Her net torque is virtually zero because there isn't much friction between her skates and the ice. Furthermore, the friction is applied rather close to the pivot.

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The voltage supplied determines how strong the electrostatic force is inside a capacitor, and the length among the plates determines how weak it is.

The energy held in the capacitor stays unchanged as plates spacing increases, while capacitance falls. As a result, there is only a potential rise inside the differential here between plates.

By virtue of energy conservation, kinetic energy (KE) must be proportional to the change in potential energy (qV), either conversely. In terms of numbers, the voltage among the plates and the electron's energy in electron-volts are identical. For instance, a 5000-V voltage differential results in 5000-eV electrons. Energy in potential is position-dependent. To put it another way, it varies based here on weight and height of the object. The mass and initial velocity affect the kinetic energy of that object. When we consider a waterfall, we can see that the motionless liquid now at peak of something like the drop possesses potential energy.

The virial theory argued that kinetic energy is equivalent to half of potential energy's negative figure. The double of negative kinetic energy is called potential energy. The kinetic energy's opposite, amount of energy, is the same.

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The acceleration of an 8kg box at net force of 50N would be d.) 6.25m/s²

The acceleration due to gravity value of 9.8 m/s2 means that the velocity of a body falling freely changes by 9.8 m/s per second.

The acceleration of an object is equal to the net force exerted on it divided by its mass, or a = F m, in accordance with Newton's second rule of motion. When the mass of an item and the net force acting on it are known, the acceleration of that object can be determined using this equation for acceleration.

Throughout time, the velocity is shifting. In actuality, the velocity is changing by a fixed rate of 10 m/s every second.

Let the direction of the 50 N be positive.

Fnet = (50 -10) N = +40 N

Fnet = m•a

a = Fnet/m = 40/75 m/s²

a = +0.53333 m/s² but round to 1 or 2 sig figs: +0.53 m/s² in the direction of the 50 N.

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The option that is not a direct cost for a scooter manufacturer is office rent. (Option A)

Direct costs are expenses that can be directly attributed to the production of a specific product. Office rent is not a direct cost for a scooter manufacturer.

In the case of a scooter manufacturer, direct costs would include items like wheels, handlebars, brakes, and grip tape, as these are all components directly involved in the manufacturing process of the scooters.

On the other hand, office rent is an indirect cost, also known as an overhead cost. Indirect costs are expenses that are not directly traceable to a specific product or production process.

So option A is the correct answer.

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The minimum uncertainty in the electron's position is equal to the velocity uncertainty divided by the speed of light, which is 131 m/s / 299,792,458 m/s ≈ 4.37 × 10^−9 m.

The minimum uncertainty in the electron's position is determined by the Heisenberg Uncertainty Principle, which states that the product of the uncertainties in position and momentum have to be greater than or equal to a constant, which is equal to Planck's constant (h) divided by 4π.

Therefore, the minimum uncertainty in the electron's position (Δx) can be calculated using the equation below:

Δx * Δp ≥ h/4π

Where Δp is the uncertainty in the electron's momentum, which is equal to the electron's velocity uncertainty (Δv) multiplied by the electron's mass (m):

Δp = Δv * m

Inserting this into the equation for the minimum uncertainty in position, we get:

Δx * Δv*m ≥ h/4π

Simplifying and rearranging this equation, we get:

Δx ≥ h/4π * (1/m*Δv)

For a single electron with a mass of 9.11 x 10-31 kg and velocity uncertainty of 131 m/s, the minimum uncertainty in its position is 1.11 x 10.

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25 Newtons force would be needed to make mass M accelerate at rate 4A

An object with mass M is subjected to a force of 100 newtons and accelerates at rate A.

25 Newtons force would be needed to make mass M accelerate at rate 4A

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False, a personal foul does not necessarily involve illegal entry or excessive timeouts, though they can be part of a personal foul.

A personal foul is a penalty in certain sports, such as basketball and American football, that involves an illegal action by a player. A personal foul occurs when a player has unsportsmanlike conduct, illegal entry, or excessive timeouts. Unsportsmanlike conduct is defined as any action that is not considered to be ethical or respectful within a sporting event. This includes taunting, arguing with a referee, or showing disrespect towards another player or team.

Illegal entry is when a player enters a restricted area without permission or authorization. This can be a violation of the playing rules or a foul against another player. Excessive timeouts are when a team uses all of its allotted timeouts in a game or a player takes an excessive amount of time to make a decision, such as when taking a free throw.

All of these actions, when committed by a player, can be considered a personal foul. A personal foul is a violation of the rules that can result in a variety of consequences, from a warning to a technical foul, to a disqualification from the game. The severity of the consequences depends on the severity of the foul and the specific sport in which it is committed.

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If a net force of 270 N applied on a 35-kg mass, the acceleration is 7.7 m/s²

The problem can be solved by applying the Newton's 2nd law of motion, which states: the acceleration on an object is directly proportional to the net force applied to it and inversely proportional to its mass.

F = ma

Where:

F = net force acted on the object

m = mass

a = acceleration

Parameters given in the problem:

m = 35 kg

F = 270 N

Plug these parameters into the formula:

270 = 35 x a

a = 270/35 = 7.7 m/s²

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Answer:

equal magnitude and opposite direction