M O GEOMETRY Identifying parallelograms, rectangles, and squares Answer the questions about the figures below. 3 m Figure A Explanation 3 m 3 m (a) Which figures are squares? Mark all that apply. Figure A (b) Which figures are parallelograms? Mark all that apply. O Figure A O Figure B (c) Which figures are rectangles? Mark all that apply. O Figure A 3 m O Figure B O Figure C Figure B Check O Figure C O Figure C Figure B 2 m 5 m 4 m O None of the figures O None of the figures O None of the figures 3 m L X Figure C 5 m 5 m ☐ L ? 3 m 0/5 O2022 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center Nikid Ac
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Given the dimensions of each figure:
• Figure A:
Length of each side = 3m
All sides have equal lengths.
• Figure B:
Length of top base = 2 m
Length of bottom base = 5m
Length of each leg = 4m
• Figure C.
Length = 5 m
Width = 3m
Since the length of all sides in figure A are equal and they meet at right angles, we can say figure A is a square.
Also, figure A has 2 pairs of parallel sides.
Since it has 2 pairs of parallel sides, we can say it is also a parallelogram.
Figure B has two parallel bases, while the opposite legs are equal.
Figure B has just one pair of parallel side.
Thus, we can figure B is a trapezoid.
Figure C has two pairs of parallel sides and the opposite sides have equal lengths.
Thus, we can say Figure B is rectangle and also a parallelogram.
Hence, we have the following:
• Squares ==> Figure A
,• Parallelogram ==> Figure A and Figure C
,• Rectangle ==> Figure C.
• ANSWER:
(a).
(c).
Related Questions
The water level of a tank every minute since it began filling is indicated by segments A,B,and C on the graph
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SOLUTION
From the graph
The slope of line A is
[tex]m=\frac{60-20}{2-0}=20[/tex]The slope of line B is
[tex]n=\frac{80-60}{6-2}=5[/tex]The slope of line C is
[tex]p=\frac{110-80}{9-6}=10[/tex]The least segment is the segment with the least slope.
The required arrangement is
[tex]B,C,A[/tex]what is the slope of the equation y = - 7x + 9
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EXPLANATION
The slope of a line is given by the following expression:
[tex]\text{Slope = }\frac{rise}{run}=\frac{(y_2-y_1)}{(x_2-x_1)}[/tex]In this case, we have that the slope is represented by the generic form:
y = mx + b
Where m is the slope and b is the y-intercept.
So, the slope is -7.
Answer: m=-7
Use the appropriate form of the percentage formula.30% of what number is 21?
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If 30% of a number x is equal to 21, then x is to 100% as 21 is to 30%:
[tex]\frac{x}{100}=\frac{21}{30}[/tex]Solve for x:
[tex]x=\frac{21}{30}\times100=70[/tex]Then, 30% of 70 is 21.
Therefore, the answer is 70.
Use the Venn diagram to complete the sentences. Write All or Some or No in each blank
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If we look at the image, we must see that the parallelogram's circle is greater than the trapezoid's circle, in other words, the trapezoids are contained in the parallelograms. In addition, no information about the quadrilaterals is provided in the Venn diagram. The correct word in each sentence are
1. No trapezoids are quadrilaterals.
2. No quadrilaterals are trapezoids.
3. Some parallelograms are trapezoids.
4. All trapezoid are parallelograms.
Hello! I need some help with this homework question, please? I just need help with C or D Q2
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C) Considering that f(x)=x² we can write the composite function f(f(x)) y plugging into the x-variable the function f(x) itself:
[tex]\begin{gathered} f(f(x)) \\ f\mleft(x\mright)=x^2 \\ f(f(x))=(x^2)^2 \\ f(f(x))=x^4 \end{gathered}[/tex]Now, let's find the Domain. Considering that this is a polynomial function that has no restraints nor discontinuity we can write out the following:
[tex]\begin{gathered} The\: domain\: of\: f\circ f\: is\: all\: Real\: numbers \\ D=\: \mleft(-\infty\: ,\: \infty\: \mright) \end{gathered}[/tex]PLEASE HELP!!!!! I WILL GIVE BRAINLIEST!!!!
Evaluate the expression . Write your answer as a simplified mixed number, or as a decimal. Show your work
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Answer:
[tex]-3\frac{15}{16}[/tex]
Step-by-step explanation:
Given:
[tex](-\frac{1}{4}+2.875)\div(-\frac{2}{3})[/tex]
First, convert 2.875 to an improper fraction:
[tex]2.875=2\frac{875}{1000}=2\frac{7}{8}=\frac{23}{8}[/tex]
The expression becomes:
[tex](-\frac{1}{4}+\frac{23}{8})\div(-\frac{2}{3})[/tex]
Then, add the terms in the parentheses:
[tex]-\frac{1}{4}+\frac{23}{8}=-\frac{2}{8}+\frac{23}{8}=\frac{21}{8}[/tex]
The new expression is:
[tex]\frac{21}{8}\div-\frac{2}{3}[/tex]
Dividing two fractions is the same as multiplying the first fraction by the reciprocal of the second fraction. Therefore:
[tex]\frac{21}{8}\times-\frac{3}{2}[/tex]
Next, multiply the numerators and denominators:
[tex]-\frac{63}{16}[/tex]
Finally, simplify to a mixed fraction:
[tex]-3\frac{15}{16}[/tex]
Simplify. In the form of a paragraph, explain in complete sentences the steps necessary to simplify the expression andinclude the final answer in your explanation. Complete your work in the space provided or upload a file that can displaymath symbols if your work requires it.
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1. When dividing with exponents, the exponent of a variable in the denominator is subtracted from the exponent in the numerator for the same variable. Then, first step to simplify is subtract the exponents of x and y in the fraction in parentheses:
[tex]\begin{gathered} =(x^{3-1}y^{1-2})^{-2} \\ =(x^2y^{-1})^{-2} \end{gathered}[/tex]2. To remove the parentheses you multiply each exponent in the parentheses by the exponent out of the parentheses:
[tex]\begin{gathered} =x^{2\cdot(-2)}y^{(-1)\cdot(-2)} \\ \\ =x^{-4}y^2 \end{gathered}[/tex]3. When you have a negative exponent (as the x powered to -4) you divide 1 in to the term with negative exponent (after you divide the exponent turns into a positive exponent):
[tex]=\frac{1}{x^4}\cdot y^2[/tex]4. Then, the given expression simplified is:
[tex](\frac{x^3y}{xy^2})^{-2}=\frac{y^2}{x^4}[/tex]assume that y varies inversely with x. If y = -4 when x = 1/2 , find x when y=2
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it is given that x and y have inverse relation
so K = xy
put y = -4 and x = 1/2
[tex]\begin{gathered} k=\frac{1}{2}\times-4 \\ k=-2 \end{gathered}[/tex]now
y = 2
then'
[tex]\begin{gathered} -2=x\times2 \\ x=\frac{-2}{2} \\ x=-1 \end{gathered}[/tex]so the value of x = -1
[tex]\begin{gathered} x\infty\frac{1}{y} \\ x=\frac{K}{y} \\ K=xy \end{gathered}[/tex]5) A ball is dropped from a height of 400 feet. Each time it hits the ground, it rebounds 75% of the distance it has fallen. How far will the ball travel before coming to rest?
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Initial height: 400 m
Each time it hits the ground, it rebounds 75% the distance it has fallen. Let us say this distance is d, then the new height is:
[tex]\begin{gathered} h=75\text{\% of }d=\frac{75}{100}\cdot d \\ \Rightarrow h=\frac{3}{4}d \end{gathered}[/tex]If the initial height is 400 m, then the subsequent heights are given by the recurrence equation:
[tex]\begin{gathered} h_0=400 \\ h_n=(\frac{3}{4})^n\cdot h_0 \\ \Rightarrow h_n=400\cdot(\frac{3}{4})^n \end{gathered}[/tex]And the total distance traveled D is:
[tex]\begin{gathered} D=h_0+2\cdot\sum ^{\infty}_{n\mathop=1}\lbrack(\frac{3}{4})^n\cdot h_0\rbrack \\ \Rightarrow D=400+800\cdot\sum ^{\infty}_{n\mathop{=}1}(\frac{3}{4})^n \end{gathered}[/tex]Now, let us analyze the sum term:
[tex]\sum ^{\infty}_{n\mathop{=}1}(\frac{3}{4})^n=\frac{3}{4}+(\frac{3}{4}_{})^2+(\frac{3}{4})^3+\cdots_{}[/tex]From the infinite geometric sequence:
[tex]\begin{gathered} \sum ^{\infty}_{n\mathop=0}r^n=\frac{1}{1-r} \\ \Rightarrow\sum ^{\infty}_{n\mathop{=}1}r^n=\frac{1}{1-r}-1 \end{gathered}[/tex]Where r < 1. From our problem, r = 3/4 < 1, then:
[tex]\begin{gathered} \sum ^{\infty}_{n\mathop{=}1}(\frac{3}{4})^n=\frac{1}{1-\frac{3}{4}}-1=\frac{1}{\frac{1}{4}}-1=4-1 \\ \Rightarrow\sum ^{\infty}_{n\mathop{=}1}(\frac{3}{4})^n=3 \end{gathered}[/tex]Finally, using this result:
[tex]D=400+800\cdot3=400+2400=2800[/tex]Solve $9.75 x $40 to get $390.00, using long multiplication
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I will be using a rough sketcher to show the long multiplication:
The process is shown below:
Note:
the last zero is taken down last, after the multiplication is done [shown by green arrow]
Lastly, we put the decimal point "2 places to the left" since the multiplication problem has "2 decimal places"
Hello there! can you help me on questions 3, 4, and 5 please? Thank you!
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(3) A rate that is increasing means as the y variable increases, so does the x variable. This graph has its line rising up from left to right
(4) A graph with a rate that is decreasing would have the line sloping downwards from left to right (like the one provided in your question)
(5) A graph with a rate of zero means that, the y variable does not change, whereas the x variable keeps changing. This graph is a horizontal line (its parallel to the x-axis)
The rate is increasing
The rate is decreasing
The rate of change is zero
12. To prepare an aquarium for use, you can clean it with a saltwater solution. The amount of salt varies directly with the volume of the water. The solution has 2 teaspoons of aquarium salt for every gallon of water. a. How many teaspoons of aquarium salt are needed for 5 gallons of water? b. Write an equation that relates x gallons of water to y teaspoons of salt. c. Use the equation to find the number of gallons of water to use for 12 teaspoons of salt.
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Given:
The solution has 2 teaspoons of aquarium salt for every gallon of water.
a.) How many teaspoons of aquarium salt are needed for 5 gallons of water?
- To be able to determine how many teaspoons of aquarium salt are needed, we will be using ratios and proportions.
[tex]\text{ 2 teaspoon of salt : 1 gallon of water = x : 5 gallons of water}[/tex]Where,
x = teaspoons of aquarium salt
We get,
[tex]\text{ 2 teaspoon of salt : 1 gallon of water = x : 5 gallons of water}[/tex][tex]\frac{2}{1}\text{ = }\frac{x}{5}[/tex][tex]\text{ (2)(5) = (x)(1)}[/tex][tex]\text{ 10 = x}[/tex]Therefore, you will be needing 10 teaspoons of aquarium salt for 5 gallons of water.
b.) Write an equation that relates x gallons of water to y teaspoons of salt.
Let,
x = gallons of water
y = teaspoons of salt
[tex]\text{ }\frac{2\text{ teaspoons of salt}}{1\text{ gallon}}\text{ = }\frac{y}{x}\text{ }\rightarrow\text{ }\frac{2}{1}\text{ = }\frac{y}{x}\text{ }\rightarrow\text{ 2 = }\frac{y}{x}[/tex][tex]\text{ 2x = y}[/tex]Therefore, the equation of the mixture will be 2x = y.
c.) Use the equation to find the number of gallons of water to use for 12 teaspoons of salt. Substitute, y = 12.
[tex]\text{ 2x = y}[/tex][tex]\text{ 2x = 12}[/tex][tex]\text{ }\frac{2x}{2}\text{ = }\frac{12}{2}[/tex][tex]\text{ x = 6}[/tex]Therefore, you will be needing 6 gallons of water for 12 teaspoons of salt.
In quadrilateral BADC, AB = AD andBC = DC. The line AC is a line ofsymmetry for this quadrilateral
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Given the quadilateral: BADC
AB = AD
BD = DC
The line AC is a diagonal of the quadilateral.
The given quadilateral is a kite.
Let's answer the following questions using the given information.
Part a:
Diagonal AC and diagonal BD are perpendicular.
The diagonals of a kite are perpendicular, this is because the point of intersection of both diagonals form a right angle (90 degrees).
Therefore, based on the line of symmetry, we can say diagonals AC and BD are perependicular because the quadilateral is symmetric along the diagonals AC and BD of the figure.
• Part b:
Based on the line of symmetry, angle ABC and angle ADC have the same measure because the qudilateral has
At the grocery store, 3 apples cost $0.65. What is the cost of 8 apples? 7th honors it is due today help
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Answer:
$1.76 for 8 apples
Step-by-step explanation:
0.65 / 3 = 0.22
0.22 * 8 = 1.76
what is the volume of the cone? use Pi and round to the nearest tenth
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Let's begin by listing out the information given to us:
Radius (r) = 7ft
Height (h) = 25ft
The volume of a cone is calculated as shown below:
V = ⅓πr²h
V = ⅓ * 3.14 * 7² * 25 = 1282 1/6
V = 1282 1/6 or 1282.667 = 1282.7 = 1283 ft³
V = 1283 ft³
. A town committee has a budget of $75 to spend on snacks for the volunteers participating in aclean-up day. The committeechairperson decides to purchase granola bars and at least 50 bottlesof water. Granola bars cost $.50 each, and bottles of water cost $.75 each. Write and graph asystem of linear inequalities for the number of bottles of water and the number of granola bars thatcan be purchased
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Assume that the number of granola bars is x and the number of bottles is y
Since they decided to purchase at least 50 bottles
At least means greater than or equal, so
[tex]x\ge50[/tex]Since the cost of 1 bar = $0.50, then
The cost of all bars = 0.50x
Since the cost of 1 bottle = $0.75, then
The cost of all bottles = 0.75y
Since their budget is $75
They can not exceed that, then
[tex]0.50x+0.75y\le75[/tex]The solution will be in the common part of the two colors
The red represents the second inequality
The blue represents the first inequality
the first three terms of a sequence are given around the nearest thousandth if needed 16,4,1,... Find the 6th term
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16, 4, 1....
2^4, 2^2, 2^0
[tex]2^4,2^2,2^0,2^{-2},2^{-4},2^{-6},2^{-8}\ldots[/tex]6th term would be 2^-6:
[tex]2^{-6}[/tex]Series
The remains of an ancient ball court include a rectangular playing alley with a perimeter of about 18m. The length of the alley is two times the width. Find the length and the width of the playing alley.The width is ? m and the length is ? m.
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Given:
Perimeter = 18 m
The formula for the perimeter of a rectangle is:
[tex]P=2l+2w[/tex]Where:
l = lenght
w = width
In this case, we have that:
l = 2w
Therefore, we substitute the values in the formula:
[tex]\begin{gathered} P=2l+2w \\ 18=2(2w)+2w \end{gathered}[/tex]And solve for w:
[tex]\begin{gathered} 18=4w+2w \\ 18=6w \\ \frac{18}{6}=\frac{6w}{6} \\ w=3 \end{gathered}[/tex]For the length:
[tex]l=2w=2(3)=6[/tex]Answer:
The width is 3 m
The length is 6 m
Write an addition fact that corresponds to the following sentence, and then answer the questionOn three consecutive passes, a football team gains 10 yards, loses 19 yards, and gains 21 yards. What number represents the total net yardage?The addition fact that corresponds to the sentence is_____The total net yardage is yards______
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Given:
On three consecutive passes, a football team gains 10 yards, loses 19 yards, and gains 21 yards.
To find:
An addition fact that corresponds to the given sentence and the number represents the total net yardage.
Solution:
It is given that first football gains 10 yards then loses 19 yards and then again gains 21 yards.
The gaining is shown by a positive sign and the loss is shown by a negative sign.
So, the addition fact is given below:
[tex]+10-19+21[/tex]Now, the resultant of the above expression is the total net yardage.
[tex]\begin{gathered} +10-19+21=+31-19 \\ =+12 \end{gathered}[/tex]Thus, the total net yardage is 12 yards.
How do I write five hundred and eight hundredths as a decimal number.
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start by writing the whole part, sine there us only hundreds we can write it as
[tex]500[/tex]then write the decimal part, we can see that there are no tenths in this expression so we start with a 0, then for the hundredths, we can put the number 8
[tex].08[/tex]The complete number should be
[tex]500.08[/tex]Which of the following has a graph that is an ellipse centered at (−2, 3)
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Solution:
The vertex equation of an ellipse is;
[tex]\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1[/tex]Thus, given the center;
[tex](h,k)=(-2,3)[/tex]Then, the equation whose graph is an ellipse centered at (-2,3) is;
[tex]\frac{(x+2)^2}{12}+\frac{(y-3)^2}{18}=1[/tex]
Z (7x+3)° m n (6x+11)
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In this problem, the two angles are equal because of the properties, so:
[tex](7x+3)=(6x+11)[/tex]and we can solve for x
[tex]\begin{gathered} 7x-6x=11-3 \\ x=8 \end{gathered}[/tex]So the angles are:
[tex]\begin{gathered} 7(8)+3=59 \\ 6(8)+11=59 \end{gathered}[/tex]Find the angle between the vectors u = 5i – 2j and v = 2i + 3j.
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STEP - BY - STEP EXPLANATION
What to find?
The angle between the given vectors.
Given:
u = 5i – 2j and v = 2i + 3j.
To solve the given problem, we will follow the steps below:
Step 1
Write the formula that can be use to solve the above.
[tex]cos\theta=\frac{\vec{a}\vec{.b}}{\vec{|a}\vec{||b}|}[/tex]Step 2
Determine;
→ →
a. b
[tex]\begin{gathered} \vec{a}\vec{.b}=(5)(2)+(-2)(3) \\ \\ =10-6 \\ \\ =4 \end{gathered}[/tex]Step 3
Determine;
→ →
|a| and | b|
[tex]\begin{gathered} \vec{|a|}=\sqrt{5^2+(-2)^2} \\ \\ =\sqrt{25+4} \end{gathered}[/tex][tex]=\sqrt{29}[/tex][tex]\begin{gathered} \vec{|b|}=\sqrt{2^2+3^2} \\ \\ =\sqrt{4+9} \\ \\ =\sqrt{13} \end{gathered}[/tex]Step 4
Substitute the values into the formula.
[tex]\begin{gathered} cos\theta=\frac{4}{\sqrt{29}\times\sqrt{13}} \\ \\ =\frac{4}{\sqrt{377}} \end{gathered}[/tex]Step 5
Take the arc cos of both-side.
[tex]\theta=cos^{-1}(0.20601)[/tex][tex]\theta=78.1\degree[/tex]ANSWER
θ = 78. 1°
What is the x-value of the solution to this system of equations? x = 2y - 4 7x + 5y = -66 F-2 G 19 7 H -8 62 19
Answers
Answer:
x = -8
Explanation:
Given the below system of equations;
[tex]\begin{gathered} x=2y-4\ldots\ldots\ldots\ldots\ldots\text{.Equation 1} \\ 7x+5y=-66\ldots\ldots\ldots\ldots\text{Equation 2} \end{gathered}[/tex]The solve the above, let's go ahead and put equation 1 into equation 2 and solve for y;
[tex]\begin{gathered} 7(2y-4)+5y=-66 \\ 14y-28+5y=-66 \\ 19y=-66+28 \\ 19y=-38 \\ y=-\frac{38}{19} \\ y=-2 \end{gathered}[/tex]To find x, we have to substitute the value of y into equation 1 and solve for x;
[tex]\begin{gathered} x=2(-2)-4=-4-4=-8 \\ x=-8 \end{gathered}[/tex]-4(-7x-6) help me please
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multiply each term by -4 and sum
[tex]\begin{gathered} (-4\times-7x)+(-4\times-6) \\ =28x+24 \\ \end{gathered}[/tex]Use the change of base formula to compute log/174.Round your answer to the nearest thousandth.
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Answer:
The Expression is given below as
[tex]\log_{\frac{1}{7}}4[/tex]Represent the expression above to be
[tex]=x[/tex]That is, we will have that
[tex]\log_{\frac{1}{7}}4=x[/tex]Applying the change of base rule below, we will have that
[tex]\begin{gathered} \log_ab=y \\ b=a^y \\ lnb=lna^y \\ lnb=ylna \\ y=\frac{lnb}{lna} \end{gathered}[/tex][tex]\begin{gathered} \log_{\frac{1}{7}}4=x \\ (\frac{1}{7})^x=4 \\ (7^{-1})^x=4 \\ 7^{-x}=4 \\ take\text{ ln of both sides} \\ ln7^{-x}=ln4 \\ -xln7=ln4 \\ dividie\text{ both sides by -ln7} \\ \frac{-xln7}{-ln7}=\frac{ln4}{-ln7} \\ x=-0.712 \end{gathered}[/tex]Hence,
The final answer is
[tex]\rightarrow-0.712[/tex]choose the image that corresponds to Figure 1 after a reflection over the x-axis and a translation of one unit left
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Solution
For this case the solution would be given by:
I need help with this problem. Please show work and simplify the answer!
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i only need the final answers, i do not need an explanation i am just double checking my final answer
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Convert the following mixed number to an improper fraction: 28 1 / 8 What is the numerator of this improper fraction? State the answer without reducingAll negatives must be included in your final answer:ie. if the question asks for the whole number portion, numerator, or denominator of the answer and it has a negative, you must include that negative.Be sure to reduce all fractions fully and convert improper fractions to mixed numbers before stating your final answer
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Given the mixed number:
[tex]28\frac{1}{8}[/tex]Let's convert the mixed number to an improper fraction.
To convert a mixed number to improper fraction, multiply the denominator by the whole number, then add the result to the numerator.
Thus, we have:
[tex]\begin{gathered} 28\times8=224 \\ \Longrightarrow224+1=225 \end{gathered}[/tex]Therefore, the improer fraction is:
[tex]\frac{225}{8}[/tex]The numerator is the number at the top of the fraction.
Therefore, the numerator of this improper fraction is = 225
ANSWER:
[tex]\frac{225}{8}[/tex]Numerator = 225
Answer: To convert a mixed number to improper fraction multiply the whole number and the denominator and then add the numerator. This gives the numerator of the improper fraction. The denominator is the same as the denominator of the given mixed number.
Step-by-step explanation:
[tex]28\frac{1}{8}[/tex] = [28x8+1] / 8 = [tex]\frac{224+1}{8}[/tex] = [tex]\frac{225}{8}[/tex]
The numerator of [tex]\frac{225}{8}[/tex] is 225
To learn more about conversion of mixed number to improper fraction:
https://brainly.in/question/28231026