Answers
It is 0.696% for Part A, and 0.634% for Part B
Male students are more represented in Part A.
Explanation:Given that there are 19100 students.
For Part A, the percentage of male students is part A is:
[tex]\begin{gathered} \frac{\text{Sum of male students in part A}}{\text{Total male students}} \\ \\ =\frac{133}{19100}\times100 \\ \\ =0.696 \end{gathered}[/tex]For Part A, the percentage of male students is part B is:
[tex]\begin{gathered} \frac{121}{19100}\times100 \\ \\ =0.634 \end{gathered}[/tex]
Related Questions
What is an equation of the line that passes through the point (6,-2) and is parallel to the line y=2/3x+4?
Answers
point = (6,-2)
Parallel to y= 2/3x+4
If 2 lines are parallel, both have the same slope
Slope intercept form:
y= mx +b
where:
m= slope
b= y intercept
so, for y= 2/3x+4
slope = 2/3
So far we have
y= 2/3x +b
Replace x,y by the coordinate point given (6,-2) and solve for b:
-2 = 2/3 (6) + b
-2 = 4 + b
-2-4 = b
-6 = b
Final equation:
y= 2/3x - 6
find the new price after the markup given. round to the nearest cent if necessary. $145 marked up 175%
Answers
Answer:
Explanation:
Given that the initial/cost price is;
[tex]\text{ \$145}[/tex]It was then marked up 175%.
The new price can be calculated using the formula;
[tex]\begin{gathered} S=C+r(C) \\ S=(1+r)C \\ \text{where;} \\ S=\text{ new price} \\ C=\text{ cost price} \\ r=\text{markup percent in fraction} \end{gathered}[/tex]Given;
[tex]\begin{gathered} C=\text{ \$145} \\ r=\frac{175\text{\%}}{100\text{\%}} \\ r=1.75 \end{gathered}[/tex]substituting:
[tex]\begin{gathered} S=(1+r)C \\ S=(1+1.75)\times\text{ \$145} \\ S=2.75\times\text{ \$145} \\ S=\text{ \$398.75} \end{gathered}[/tex]Therefore, the new price is;
[tex]undefined[/tex]Part A: A landscape service charges costumers a one-time fee and an hourly rate of $15. For 3 hours of work m, it charges $75 Write the equation in point-slope formHow much does the landscape service charge for 20 hours
Answers
The hourly rate is the slope m, and we're given the point (3,75)
Now, using the point-slope form:
[tex]y-75=15(x-3)[/tex]Now, let's put it in the slope-intercept form (clear y):
[tex]\begin{gathered} y-75=15x-45 \\ \rightarrow y=15x+30 \end{gathered}[/tex]For 20 hours of service,
[tex]\begin{gathered} y=15(20)+30 \\ \rightarrow y=330 \end{gathered}[/tex]The service would charge $330
solve for theta. Enter answer only round to the tenth
Answers
ANSWER:
[tex]\theta=62.73\text{\degree}[/tex]STEP-BY-STEP EXPLANATION:
We can calculate the value of the angle by means of the trigonometric ratio sine which is the following
[tex]\begin{gathered} \sin \theta=\frac{\text{opposite }}{\text{ hypotenuse}} \\ \text{opposite = 24} \\ \text{hypotenuse = 27} \end{gathered}[/tex]Replacing and solving for the angle:
[tex]\begin{gathered} \sin \theta=\frac{24}{27} \\ \theta=\arcsin (\frac{24}{27}) \\ \theta=62.73\text{\degree} \end{gathered}[/tex]Find the area of each circle. Round to the nearest tenth.Only 1 and 2
Answers
Explanation
The area a circle can be expressed in two forms;
[tex]\begin{gathered} \text{Area}=\pi r^2 \\ \text{Area}=\pi(\frac{d}{2})^2 \\ \end{gathered}[/tex]Where r and d are the radius and the diameter of the circle.
Therefore;
For number 1, r =21 yards,
[tex]\text{Area}=\pi\times21^2=1385.4\text{square yards}[/tex]Answer: 1385.4 square yards
For number 2, d= 0.4 km
[tex]\text{Area}=\pi\times(\frac{0.4}{2})^2=\pi\times0.2^2=0.1km^2[/tex]Answer:0.1 square kilometres
order the fallowing numbers from least to greatest -3, -3.12, 1 1/2
Answers
Solution:
Consider the following numbers:
[tex]-3[/tex][tex]-3.12[/tex]and the mixed number:
[tex]1\frac{1}{2}=\frac{(2\text{ x 1)+1}}{2}=\frac{3}{2}\text{ =}1.5[/tex]now, applying the usual order of the real numbers, we have that:
[tex]-3,12<-3<1.5[/tex]then, the order of the given numbers from least to greatest is:
[tex]-3.12[/tex][tex]-3[/tex][tex]1\frac{1}{2}[/tex]B) The value of the function decreased by ____ per year after 1990
Answers
From the question
We are given the function
[tex]y=-0.5x+29[/tex]Comparing the function with the equation
[tex]y=mx+c[/tex]Then the slope of the function is
m = - 0.5
Using the function
[tex]y=-0.5x+29[/tex]When x = 1
[tex]\begin{gathered} y=-0.5(1)+29 \\ y=28.5 \end{gathered}[/tex]When x = 2
[tex]\begin{gathered} y=-0.5(2)+29 \\ y=28 \end{gathered}[/tex]When x = 3
[tex]\begin{gathered} y=-0.5(3)+29 \\ y=27.5 \end{gathered}[/tex]By comparing the values of y, we will notice a decrease of 0.5
Hence,
The value of the function decreased by 0.5 per year after 1990
find the equivalent expression for x^1/2
Answers
We want to find the equivalent expression for
[tex]x^{\frac{1}{2}}[/tex]Read as: x to the power of half
The equivalent expression for this is
[tex]\sqrt[]{x}[/tex][tex]x^{\frac{1}{2}}\text{ and }\sqrt[]{x}\text{ both have the same meaning}[/tex]How can ️WXY be mapped to ️MNQ Translate vertex W to vertex M, then reflect across the line containing A WXB WYC XYD MQ
Answers
The answer is WX, because
If you are rolling two dice (numbered 1-6), what is the probability that the first die shows an odd number and the second die shows a number larger than 4?
Answers
Since we have two dices and we want to know the events where the first one shows an odd number and the second die shows a number larger than 4, we have that the following results are the ones that fit the requirement:
[tex](1,5),(1,6),(3,5),(3,6),(5,5),(5,6)[/tex]Now, we know that the sample space has 6x6=36 possible outcomes, therefore, the desired probability is:
[tex]P(\text{odd,x}>4)=\frac{6}{36}=\frac{1}{6}[/tex]therefore, the probability is 1/6
How can I solve this?x=AD=AB= 5X-4DB=x+1
Answers
AD = AB + DB
AD = (5x - 4) + (x+1)
= 5x - 4 + x + 1
= 5x + x - 4 + 1
AD = 6x - 3
Hi can you please help me with this problem?The shape is shown below What is the area of the triangle below (in square units)?
Answers
ANSWER:
28 square inches
STEP-BY-STEP EXPLANATION:
Given:
Base = 7 inches
Height = 8 inches
We can calculate the area with the help of the triangle area formula, which is as follows:
[tex]A=\frac{1}{2}b\cdot h[/tex]We replacing:
[tex]\begin{gathered} A=\frac{1}{2}\cdot7\cdot8 \\ A=28 \end{gathered}[/tex]The area is 28 square inches.
Classify the following variables as quantitative or qualitative variables. If the variable is quantitative, identify whether it is discrete or continuous.The daily number of customers in a store.
Answers
A quantitative variable is the one who has a numerical significance such as number of items, time spent on playing a video game while a qualitative variable is the one who has not a numerical significance attached to it such as Gender , Eye color
Further in quantitative variable , discrete variable is the one which is a whole number and can not be broken down further , like number of items
while a continuous variable is the one which takes any value within an interval of values like between 1 and 2 , continuous variable can take any value like 1.21, 1.55556, 1.994 etc.
The daily number of customers in a store can take a whole number value.
Thus, the variable is discrete.
In a right triangle, the side opposite angle θ has a length of 80 inches, the side adjacent to angle θ has a length of 84 inches, and the hypotenuse has a length of 116 inches. What is the value of tan(θ)?
Answers
Solution:
The sides of a right triangle are hypotenuse, opposite, and adjacent.
The hypotenuse is the longest sides of the triangle.
The opposite is the side facing the angle.
The adjacent is the third side of the right triangle.
This sides are illustrated as shown below:
Thus, in the above right triangle ABC,
[tex]\begin{gathered} AC\Rightarrow hypotenuse \\ AB\Rightarrow opposite \\ BC\Rightarrow adjacent \end{gathered}[/tex]Given that the opposite side has a length of 80 inches, adjacent has a length of 84 inches, and the hypotenuse has a length of 116 inches, this implies that
[tex]\begin{gathered} AC=116 \\ AB=80 \\ BC=84 \end{gathered}[/tex]To evaluate the value of
[tex]\tan(\theta)[/tex]We use trigonometric ratios.
From trigonometric ratios,
[tex]\tan\theta=\frac{opposite}{adjacent}[/tex][tex]\begin{gathered} where \\ opposite\Rightarrow AB=80 \\ adjacent\Rightarrow BC=84 \\ thus, \\ \tan(\theta)=\frac{AB}{BC}\frac{}{} \\ =\frac{80}{84}=0.9523809524 \end{gathered}[/tex]Hence, the value of tan (θ) is
[tex]0.952[/tex]The first option is the correct answer.
this is 50 points help me out k
Answers
Answer: It is 45
Step-by-step explanation:
you have 5 four and the number is 4
what would the correlation coefficient -0.86 represent in the context of the situation?
Answers
Here, the table and scatter plot show the relationship between the number of missing assignment and the student's grade.
The correlation coefficient shows the relationship between the number of missing assignments and the student's grade.
To find the correlation coefficient, we have:
Make a straight line to connect the points on the graph
The correlation coefficient r, = -0.86
ANSWER:
-0.
assume the unit population density of a state is approximately 104 people per mi2. if this state has 196,352 square miles, what is the population of the state? people
Answers
Given:
The unit population density of a state is 104 people per mi².
Also, the state has 196,352mi².
Therefore, the population of the state will be the multiplication of the unit population density and the square miles of the state.
Hence,
[tex]\frac{104people}{miles^2^{}}\times196352miles^2=20,420,608people[/tex]Therefore, the population of the state is 20,420,608 people.
help with more than 1 question pls and ty if nkt i will report u its not fair
Answers
SOLUTION
9.
[tex]\begin{gathered} (x+10)^2\text{ = ( x + 10 ) ( x + 10 )} \\ =x^2\text{ + 10 x + 10x + 100} \\ =x^2\text{ + 20 x + 100} \end{gathered}[/tex]10.
[tex]\begin{gathered} (x-10)^2\text{ = ( x - 10 ) ( x - 10 )} \\ =x^2\text{ -10 x - 10 x + 100} \\ =x^2\text{ - 20 x + 100} \end{gathered}[/tex]11. ( x + 10 ) ( x - 10 ) ( Difference of two squares)
[tex]\begin{gathered} x^2\text{ - 10 x + 10 x - 100} \\ =x^2\text{ - 100} \end{gathered}[/tex]suppose that GX equals FX +8+4 which statement best compares the graph of GX with the graph of FX
Answers
As given by the question
There are given that the value of g(x) is:
[tex]g(x)=f(x+8)+4[/tex]Now,
According to the rule of transformation,
y = f(x+c) the function f(x) is being shifted c units left
And, for y=f(x)+d, the function f(x) is being shifed d units up
So,
In the given functiong(x)= f(x+8)+4 the value of c is 8 and value of d is 4
So,
The graph of g(x) is the graph of f(x) shifted 8 units to the left and 4 units up.
Hence, the correct option is A
Given the image, if AB is a semicircle and DB = 70 degrees, what is the measure of ACD?
Answers
Continuing from there, since it’s a semi circle, the total angle is 180 degrees. Therefore, ACD = (180 - 70)degrees.
Answer => 110 degrees
Hint - Look at the semi circle as a protractor. It’s exactly like that. If one side is 70, then the other is 110.
Which of the following equations has roots x=3 (multiplicity 3) and x=−i, and passes through the point (1,-16)?
Answers
To verify that a value is a root of a function we use the following setup
F(x) = 0 and replace x by the value in this case 3 and -i.
Let's begin with x=3
[tex]\begin{gathered} f(x)\text{ = }x^3+3x^2+x+3 \\ f(3)\text{ = }3^3+3\cdot3^2+3+3 \\ f(3)\text{ = 60} \end{gathered}[/tex][tex]\begin{gathered} f(x)\text{ = }x^5+9x^4+28x^3+36x^2+27x+27 \\ f(3)\text{ = 3}^5\text{+9}\cdot3^4\text{{}+28}\cdot3^3\text{+36}\cdot\text{3}^2\text{+27}\cdot3\text{+27} \\ f(3)\text{ = 2160} \end{gathered}[/tex][tex]\begin{gathered} f(x)\text{ = }x^5-9x^4+28x^3-36x^2+27x-27 \\ f(3)\text{ = 3}^5-\text{9}\cdot3^4\text{{}+28}\cdot3^3-\text{36}\cdot\text{3}^2\text{+27}\cdot3-\text{27} \\ f(3)\text{ = 0} \end{gathered}[/tex][tex]\begin{gathered} f(x)\text{ = }x^3+3x^2+x+3 \\ f(3)\text{ = }3^3-3\cdot3^2+3-3 \\ f(3)\text{ = 0} \end{gathered}[/tex]Only options C and D pass the first filter.
Let's apply x=-i to those options
[tex]f(-i)\text{ = }(-i\text{\rparen}^5\text{ - 9}\cdot\left(-i\right)^4\text{ + 28}\cdot\text{\lparen-i\rparen}^3\text{ - 36}\cdot(-i)^2+27\cdot(-i)-27[/tex][tex]\begin{gathered} f(-i)\text{ = }-i\text{ - 9 + 28 i - 36}-27i-27 \\ f(-i)\text{ = 0} \end{gathered}[/tex][tex]f(-i)\text{ = \lparen-i\rparen}^3-3\left(-i\right)^2+(-i)-3[/tex][tex]\begin{gathered} f(-i)\text{ = i+ }3-i-3 \\ f(-i)\text{ = 0} \end{gathered}[/tex]both of the accomplish the equality f(x)=0
So to finish we replace the point to check which functions pass
Replacing f(1) = -16
[tex]\begin{gathered} \left(1\right)^5-9\cdot\left(1\right)^4+28\cdot(1)^3-36^{\cdot}(1)^2+27\cdot(1)-27 \\ f(1)\text{ = -16} \end{gathered}[/tex]This is equals to -16
[tex]\begin{gathered} \text{ f\lparen1\rparen= 1- }3+1-3 \\ f(1)=-4 \end{gathered}[/tex]So the answer is option C
Instructions: For the given polynomial, select eachstatement that applies regarding end behavior.
Answers
Solution:
Given:
[tex]f(x)=-x^4-21x^2-2x+3[/tex]To get the end behaviour of the polynomial, we plot the function using a graphing calculator and see how it behaves.
The function is graphed as shown in the image below,
From the image above, the vertex of the curve shows a rise towards the left.
Hence, the end behaviour is that it rises to the left.
Solve the formula for the indicated variable.surface area of cone; S=r^2+rl; solve for l.
Answers
Given:
The formula for the surface area of the cone is given as,
[tex]\begin{gathered} S.A\text{ = }\pi r^2+\pi rl \\ \end{gathered}[/tex]Required:
The modified formula for the surface area of the cone in terms of l.
Explanation:
The formula is given as,
[tex]S=\pi r^2+\pi rl[/tex]Taking common terms separately,
[tex]\begin{gathered} S\text{ = }\pi r(r\text{ + l\rparen}_{\text{ }} \\ \end{gathered}[/tex]Transposing the common terms to LHS,
[tex]r\text{ + l = }\frac{S}{\pi r}[/tex]Rearranging the equation for l,
[tex]\begin{gathered} l\text{ = }\frac{S}{\pi r}\text{ - r} \\ l\text{ = }\frac{S-\pi r^2}{\pi r} \end{gathered}[/tex]Answer:
Thus the required expression in terms of l is,
[tex]l=\frac{\text{S-\pi r}^2\text{{}}}{\text{\pi r}}[/tex]18. What is the value of f(-2) for the function f(x) = 2(3Y"?A12fca=acze33B118С.29D. 18
Answers
Given the function:
[tex]f(x)=2(3)^x[/tex]To find f(-2), substitute x for -2 in the function.
[tex]f(-2)=2(3)^{-2}[/tex]Solving further using law of indicies, we have:
[tex]\begin{gathered} f(-2)\text{ = }\frac{2}{3^2} \\ \\ f(-2)\text{ = }\frac{2}{9} \end{gathered}[/tex]ANSWER:
[tex]\frac{2}{9}[/tex]What is the distance between the points (9.0) and (0,5) on the coordinate plane?
Answers
( x 1 , y 1 ) = ( 9,0 )
( x 2 , y 2 ) = ( 0, 5 )
Distance between the points:
d^2 = ( x2 - x1 ) ^2 + ( y2 - y1 ) ^2
= ( 0 - 9 ) ^2 + ( 5 - 0 )^2
= 81 + 25
= 106
square root both sides, we have:
d = 10 . 296
d = 10. 3 units ( 1 decimal place)
match a graph with the story below.Writte the letter of the graph that corresponds with the story.Explain your answer.1. Opposite Tom’s home is a hill. Tom climbed slowly up the hill, walked across the top, and then ran quickly down the other side.2. Tom skateboarded from his house, gradually building up speed. He slowed down to avoid some rough ground, but then speeded up again.3. Tom walked slowly along the road, stopped to look at his watch, realized he was late, and then started running.4. This graph is just plain wrong. How can Tom be in two places at once?5. After the party, Tom walked slowly all the way home.
Answers
1. D
This graph shows an increase in speed. At first it's slow (Tom climbing up the hill), then it's a little faster (Tom walking across the top) and then it increases more (Tom running down the hill)
2. F
This graph shows a gradual increase of speed, then the speed it's almost zero -which means that in a long interval of time Tom did very little distance- and then the speed goes up again.
3. C
In this story, Tom stopped for a moment and then sped up. In graph C there's a horizontal line at a given distance. This means that Tom stopped walking and, naturally, the time kept going on.
4. H
There's a vertical line in this graph. It means that for a given time Tom was at one distance from home and at another distance from home at the same time. That's why this graph is wrong
5. J
Distance from home = 0 means he's home. He walked all the way home, so the graph has to start at a point that's not 0 and end at distance from home = 0
Need Help Pls Answer
Answers
Answer:
5 yd
Step-by-step explanation:
A square is a quadrilateral with 4 sides of equal length.
The area of a square is found by squaring one side length:
[tex]A=s^2 \quad \textsf{(where $s$ is the side length)}[/tex]
Therefore, to find the side length of a square, simply square root its area:
[tex]\implies A=s^2[/tex]
[tex]\implies \sqrt{A}=\sqrt{s^2}[/tex]
[tex]\implies \sqrt{A}=s[/tex]
[tex]\implies s=\sqrt{A}[/tex]
Therefore, if the area of a square is 25 yd²:
[tex]\implies s=\sqrt{25}[/tex]
[tex]\implies s=5\; \sf yd[/tex]
Answer:
Length (s) = 5 yards
Step-by-step explanation:
Given information is,
→ Area (a) = 25 yd²
→ Length (s) = ?
Now we have to,
→ find the length of side of square.
Formula we use,
→ s² = Area of square
→ s² = a
Then the required length is,
→ s² = a
→ s² = 25
→ s = √(25)
→ [ s = 5 ]
Hence, the length is 5 yards.
What is the area of the circle if CY= 5.4 mm
Answers
Given
The diameter is given XY = 5.4 mm.
Explanation
To determine the area of circle,
Use the area of circle formula.
[tex]A=\pi(r)^2[/tex]Find the radius, using the relation between diameter and radius.
[tex]d=2r[/tex]Substitute the diameter in the relation.
[tex]\begin{gathered} 5.4=2r \\ r=2.7mm \end{gathered}[/tex]Now substitute the radius in the area of circle formula.
[tex]\begin{gathered} A=(2.7)^2\pi \\ A=7.29\pi mm^2 \end{gathered}[/tex]Answer
Hence the area of circle is
[tex]7.29\pi mm^2[/tex]The correct option is C.
3.Which equation does not describe the line? Place the red X on the one that does not belong x y 10 y = 2x + 4 ce 6 4, y + 0 = 2(x + 2) 2 10 -8 -6 -4 2 0 2+ 2 4 6 8 10 y + 4 = 2(x + 0) 4+ 6+ 8+ y - 4 = 2(x + 0) 107
Answers
step 1
Find the equation of the graph
Find the slope
take the points
(-2,0) and (0,4)
m=(4-0)/(0+2)
m-4/2
m=2
step 2
Find the equation of the line in point slope form
point (-2,0) and m=2 ------> y-0=2(x+2)
point (0,4) and m=2 ------> y-4=2(x-0)
Find the equation in slope intercept form
y=mx+b
we have
m=2
b=4 (given)
y=2x+4
therefore
Find the least common multiple of these two expressions. 12x^2w^6v^8 and 8x^5w^3
Answers
Given
[tex]12x^2w^6v^8\text{ }and\text{ }8x^5w^3[/tex]To find:
The Least Common Multiple of the above expressions.
Explanation:
It is given that,
[tex]12x^2w^6v^8\text{ }and\text{ }8x^5w^3[/tex]That implies,
[tex]\begin{gathered} 12x^2w^6v^8=4\cdot3\cdot x^2\cdot w^3\cdot w^3\cdot v^8 \\ 8x^5w^3=4\cdot2\cdot x^2\cdot x^3\cdot w^3 \\ \therefore LCM=4\cdot3\cdot2\cdot x^2\cdot x^3\cdot w^3\cdot w^3\cdot v^8 \\ =24x^5w^6v^8 \end{gathered}[/tex]Hence, the Least Common Multiple of the given expressions is,
[tex]LCM=24x^5w^6v^8[/tex]