LEO AND OLIVER HAVE TLO CLEAN THIER BEDROOMS. OLIVER CLEANS HIS ROOM IN 3/4 OF AN HOUR.LEO TAKES TWICE AS LONG AS OLIVER. HOW DID IT TAKE LEO TO CLEAN HIS ROOM?

LEO AND OLIVER HAVE TLO CLEAN THIER BEDROOMS. OLIVER CLEANS HIS ROOM IN 3/4 OF AN HOUR.LEO TAKES TWICE

Answers

Answer 1

It took 1.5 hour for Leo to clean the room .

In the question ,

it is given that

Leo and Oliver clean their their room

time taken by Oliver to clean the room is = 3/4 of an hour = 0.75 hours .

and also given that Leo takes twice as long as Oliver

which means

time taken by Leo to clean the room = 2*(time taken by Oliver to clean the room )

On substituting the values

we get ,

time taken by Leo to clean the room = 2*(0.75 hours)

= 1.5 hours

Therefore , Leo takes 1.5 hours to clean the room .

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Related Questions

Fill in the blanks using these answer choices: always, never, sometimes, once.

Answers

The complete text would be as following:

Parallel lines cross never

Perpendicular lines cross once

Lines that are neither parallel or perpendicular cross once

Lines that are the same cross always

Perpendicular lines cross at a 90 degree angle

For each scenario, use the tape diagram to help answer the question. Think of different labels to use for the diagram depending on the situation. Mai has picked 1 cup of strawberries for a cake, which is enough for 3/4 of the cake. How many cups does she need for the whole cake?Priya has picked 1 1/2 cups of raspberries. which is enough for 3/4 of a cake. How many cups does she need for the whole cake?

Answers

Answer:

The number of cups of strawberries needed to make a whole cake is;

[tex]\begin{gathered} \frac{4}{3}\text{ cups} \\ or \\ 1\frac{1}{3}\text{ cups} \end{gathered}[/tex]

Explanation:

Given that;

[tex]1\text{ cup of strawberries can make }\frac{3}{4}of\text{ a cake}[/tex]

To get the number of cups of strawberries needed for a whole cake.

Let us multiply both sides by 4/3;

[tex]\begin{gathered} 1\times\frac{4}{3}\text{ cup of strawberries can make }\frac{3}{4}\times\frac{4}{3}of\text{ a cake} \\ \frac{4}{3}\text{ cup of strawberries can make 1-whole }of\text{ a cake} \end{gathered}[/tex]

Therefore, the number of cups of strawberries needed to make a whole cake is;

[tex]\begin{gathered} \frac{4}{3}\text{ cups} \\ or \\ 1\frac{1}{3}\text{ cups} \end{gathered}[/tex]

what percent of 28 is 35? the answer is (blank)%

Answers

[tex]\begin{gathered} \Rightarrow\frac{35}{28}\times100 \\ \Rightarrow125\text{ \%} \end{gathered}[/tex]

write the given equation in slope intercept form. 5x-3y = -9

Answers

Thae equation is given as :

5x - 3y = -9

The equation can be written in slope intercept form as;

y= mx + c where m is the gradient and c is the y-intercept

So this will be;

5x = 3y -9

5x + 9 = 3y

5/3 x + 9/3 = 3y/3

5/3 x + 3 = y

y= 5/3 x + 3

Answer

y = 5/3 x + 3

A sector with a central angle measure of \purpleD{\dfrac{\pi}{6}} 6π start color #7854ab, start fraction, pi, divided by, 6, end fraction, end color #7854ab (in radians) has a radius of \maroonD{12\,\text{cm}}12cmstart color #ca337c, 12, start text, c, m, end text, end color #ca337c.

Answers

EXPLANATION:

Given;

We are given a sector of a circle with the following dimensions;

[tex]\begin{gathered} radius=12 \\ central\text{ }angle=\frac{\pi}{6} \end{gathered}[/tex]

Required;

We are required to calculate the area of the sector with the details given.

Step-by-step solution;

To calculate the area of a sector with the central angle given in radians, we will use the following formula;

[tex]Area\text{ }of\text{ }a\text{ }sector=\frac{\theta}{2\pi}\times\pi r^2[/tex]

We can now substitute and solve;

[tex]Area=\frac{\frac{\pi}{6}}{2\pi}\times\pi r^2[/tex][tex]Area=(\frac{\pi}{6}\div\frac{2\pi}{1})\times\pi r^2[/tex][tex]Area=(\frac{\pi}{6}\times\frac{1}{2\pi})\times\pi\times12^2[/tex][tex]Area=\frac{1}{12}\times144\times\pi[/tex][tex]Area=12\pi[/tex]

ANSWER:

In terms of pi the area of the sector is

[tex]undefined[/tex]

what is the perimeter of 6.05m and 3.5m

Answers

Recall that the perimeter P of a rectangle is given as

P = 2(L + B)

where L is the length and B is the width of the rectangle

Given that the length is 6.05m and the width is 3.5m

Then the perimeter

= 2(6.05 + 3.5)

= 2 (9.55)

= 19.10m

Show how Aaliyah can finish her work using complexnumbers. As a reminder, her last step before requiringassistance is:(x- 3)2=1Be sure to show ALL steps that lead to your finalsolution set!

Answers

aAs given by the question

There are given that the equation

[tex]x^2-6x+10=0[/tex]

Now,

The solution of the Aaliyah is:

[tex](x-3)^2=-1[/tex]

Then,

The next step of the given solution is:

[tex]\begin{gathered} (x-3)^2=-1 \\ x-3=\sqrt[]{-1} \end{gathered}[/tex]

According to the concept of complex number

[tex]i=\sqrt[]{-1}[/tex]

So,

[tex]\begin{gathered} x-3=\sqrt[]{-1} \\ x-3=i \\ x=i+3 \end{gathered}[/tex]

Use f(x)=-x-8 and g(x) = x² + 8x − 15 to answer the following: a) f(1) + g(–3) b) g(−9) − f(–7)

Answers

ANSWER:

a) -37

b) 9

Given:

f(x)=-x-8 and g(x) = x² + 8x − 15

a) f(1) + g(–3)

f(1) = 1 - 8 = -7

g(-3) = -3² + 8(-3) - 15 = 9 - 24 - 15 = -30

f(1) + g(–3) = -7 + (-30)

= -7 - 30

-37

b) g(−9) − f(–7):

g(-9) = -9² + 8(-9) - 15 = 81 - 72 - 15 = -6

f(-7) = -7 - 8 = -15

Thus,

g(−9) − f(–7) = -6 - (-15)

= -6 + 15

= 9

Aaron received credit of$48 on a purchase of $960. What percent of$960 is 48%?

Answers

we have

[tex]\begin{gathered} \frac{48}{960}=\frac{x}{100} \\ 100\times\frac{48}{960}=100\times\frac{x}{100} \\ x=5 \end{gathered}[/tex]

answer: 5%

the answer is 5% percent

Peter, a cyclist, rides 5.673 kilometers, takes a break, and then rides an additional 4321 meters.a. How many hectometers total did he ride?How many decimeters did he ride?

Answers

Explanation:

a) First Distance = 5.673 kilometers

2nd distance = 4321 meters

Total distance = 1st distance + 2nd distance

Total distance = 5.673 kilometers + 4321 meters

Conversion from kilometers to meters:

1 kilometer = 1000meters

5.673 kilometers = 5673 meters

Total distance in meters = 5673 meters + 4321 meters

Total distance in meters = 9994 meters

Conversion of meters to hectometers:

100 meters = 1 hectometers

9994 meters = x

cross multiply:

100(x) = 9994(1)

100x = 1994

x = 1994/100

x = 19.94 hectometers

Hence, he rode 19.94 in hectometers

b) converting to decimeters:

It is easier to convert from meters to decimeters

0.1 meters = 1 decimeter

9994 meters = y

y(0.1) = 1(9994)

0.1y = 9994

y = 9994/

84 is 75% of what number

Answers

Answer:

112

Explanation:

We need to find a number that represents 100% when 84 represents 75%, so we will use the following

[tex]100\text{ \% }\times\frac{84}{75\text{ \%}}=\frac{100\times84}{75}=\frac{8400}{75}=112[/tex]

Therefore, 84 is 75% of 112.

Answer:112

Step-by-step explanation: - 84 is 75% of 112. 100% of 112 is 112, hope this helps

The answer and how to do it

Answers

Answer:

v ≈ 4 cm

Step-by-step explanation:

using the Sine rule in Δ VWX

[tex]\frac{v}{sinV}[/tex] = [tex]\frac{w}{sinW}[/tex]

where v = WX and w = VX

∠ W = 180° - (126 + 21)° = 180° - 147° = 33° , then

[tex]\frac{v}{sin21}[/tex] = [tex]\frac{6}{sin33}[/tex] ( cross- multiply )

v × sin33° = 6 × sin21° ( divide both sides by sin33° )

v = [tex]\frac{6sin21}{sin33}[/tex] ≈ 4 cm ( to the nearest cm )

x^3-6x^2+12x-8=27
thnk kiu

Answers

x^3−6x^2+12x−8=0

⇔x^3−3x^2.2+3.x.2^2−2^3=0

⇔(x−2)^3=0

⇔(x−2)=0

⇔x=2

Suppose a jar contains 20 red marbles and 31 blue marbles. If you reach in the jar and pull out 2 marbles at random at the same time, find the probability that both are red.

Answers

The probability that they are both are red is 0.15.

What is probability?

Probability is the occurence of likely events. It is the area of mathematics that deals with numerical estimates of the likelihood that an event will occur or that a statement is true.

The jar contains 20 red marbles and 31 blue marbles. The total marble is 51.

Therefore, the probability will be:

= P(red) × P(red)

= 20/51 × 19/50

= 380 / 2550

= 0.15

The probability is 0.15.

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Graph the line x=3 .

Answers

According to the given equation, x=3, the line that represents it is a vertical line that passes throught the x axis at x=3.

This is a constant line, which means that for all the values of y, x will always be 3.

The graph of this line is the following:

levon scored 38 points in the first half of the basketball game, and he scored p points in the second half of the game. write an expression to determine the number of points he scored in all. then, find the number of points he scored in all if he scored 20 points in the second half of the game.

Answers

By the given information you can raise the following equation, and since levon scored 38 points in the first half of the basketball game, then

[tex]\begin{gathered} TP=38+n \\ \text{Where} \\ TP\colon\text{ the number of points that he scored in total.} \\ n\colon\text{ the number of points that he scored in the second half of the game} \end{gathered}[/tex]

So, if n=20

[tex]\begin{gathered} TP=38+n \\ TP=38+20 \\ TP=58 \end{gathered}[/tex]

Therefore, if Levon scored 20 points in the second half of the game, in all he scored 58 points.

7 in. 6in. 9 in. it's the formula of a triangle

Answers

Area of a Triangle

Given a triangle of base length B and height length H, the area can be calculated by the formula:

[tex]A=\frac{B\cdot H}{2}[/tex]

The base and the height must be perpendicular.

The height of the given triangle is H=7 in. We need to calculate the length of the base.

We are providing a new image where a variable x is introduced to help us calculate the base length:

The triangle formed by the sides 9-7-x is right, so we can calculate the value of x by applying the Pythagora's Theorem:

[tex]7^2+x^2=9^2[/tex][tex]49+x^2=81[/tex]

Solving for x:

[tex]\begin{gathered} x^2=81-49=32 \\ x=\sqrt[]{32} \end{gathered}[/tex]

The length of the base is:

[tex]B=9+\sqrt[]{32}[/tex]

Thus, the area of the triangle is:

[tex]A=\frac{7\cdot(9+\sqrt[]{32})}{2}[/tex]

Calculating:

A = 51.3 square inches

What is 2 8/10 in decimal form?

Answers

Okay, here we have this:

We are going to convert the following mixed number to decimal: 2 8/10, so we obtain the following:

[tex]\begin{gathered} 2\frac{8}{10} \\ =\frac{2\cdot10+8}{10} \\ =\frac{28}{10} \end{gathered}[/tex]

Finally we obtain that 2 8/10 expressed as a fraction is equal to 28/10.

question 1 estimated number of dogs = 6.99 × 107=6.99 • 10,000,000=69,900,000estimated number of cats = 3.61 × 107=3.61 • 10,000,000= 36,100,000estimated number of birds = 8.3 × 106= 8.3 • 1,000,000= 8,300,000-------------------------------------------Question 2The estimated number of dogs is 6.99 x 10⁷The estimated number of cats is 3.61 x 10⁷The estimated number of birds is 8.3 x 10⁶The power of 10 in 8.3 x 10⁶ is 6 which is less than the power of 10 in the other two numbers. To make the calculation simpler, convert this number so the exponents are all the sameMultiply and divide 8.3 x 10⁶ by 10 to increase its exponent by 18.3x 10⁶= 10/10 • 8.3x 10⁶=8.3/10 •10⁶ •10= 0.83 x 10⁷

Answers

SOLUTION

For question 1, we have

[tex]\begin{gathered} 6.99\times10^7=69,900,000 \\ 3.61\times10^7=36,100,000 \\ 8.3\times10^6=8,300,000 \end{gathered}[/tex]

Take the sum of the number above, we have

[tex]\begin{gathered} 69,900,000+36,100,000+8,300,000 \\ =114,300,000 \end{gathered}[/tex]

For Question 2, we have

We need to add the number without converting to the ordinary form i.e will add the number in thier exponential form.

[tex]6.99\times10^7+3.61\times10^7+0.83\times10^7[/tex]

The exponent is the common factor, hence we add the other numbers

[tex]\begin{gathered} (6.99+3.61+0.83)\times10^7 \\ =11.43\times10^7 \end{gathered}[/tex]

Changin the result in question 2 to ordinary form, we have

[tex]11.43\times10^7=11.43\times10,000,000=114,300,000[/tex]

Hence

Yes the answer in question 1 and question 2 are the same.

We can tell this because the nunbers have the same values(they are the same) but are in different forms(ordinary form and the exponential form). Hence the numbers can be use interchangeably.

Hannah bought a total of 5.12 pounds of fruit at the market. she bought 2.5 pounds of pears and she also bought some bananas. how many pounds of bananas did she buy please show work and answer

Answers

Hannah bought pears and bananas only, so let's write the following equation:

[tex]\text{total}=\text{pears}+\text{bananas}[/tex]

If the total weight bought is 5.12 and 2.5 pounds are pears, we can calculate the weight of bananas bought:

[tex]\begin{gathered} 5.12=2.5+\text{bananas} \\ \text{bananas}=5.12-2.5 \\ \text{bananas}=2.62 \end{gathered}[/tex]

So Hannah bought 2.62 pounds of banana.

Write the sequence of transformations that changes figure ABCD to figure A’B’C’D. Explain your answer and write the coordinates of the figure obtained after each transformation. Are the two figures congruent? Explain your answer.

Answers

SOLUTION:

We can compare a point to get the translation.

We can use the point;

[tex]A(-4,4)[/tex]

which transforms to;

[tex]A^{\prime}^^{\prime}(3,-4)[/tex]

The first transformation is a reflection over the x-axis to map point A to;

[tex]A^{\prime}(-4,-4)[/tex]

The next transformation is a translation 7 units to the right.

Therefore, the sequence of transformations are;

Part B: The two figures are congruent because the transformations used are non-rigid.

Emmanuel added two integers Which condition will always give Emmanuel a negative solution when he adds two integers? Both integers have negative values Both integers have positive values O. One integer has a positive value, and one integer has a negative value O The values of the two integers are opposites

Answers

Both integers have negative values

Explanation

Let

x and y represents the number

so, the options are

[tex]\begin{gathered} +\text{ + +} \\ +\text{ + -} \\ -\text{ + +} \\ -\text{ +-} \end{gathered}[/tex]

a) Both integers have negative values Both integers

[tex]-x-y=-(x+y)\rightarrow you\text{ will always get a negative number}[/tex]

b) Both integers have positive values

[tex]x+y=+\text{ + += you will always get a positive number}[/tex]

c)One integer has a positive value, and one integer has a negative value

[tex]\begin{gathered} -x+y\text{ or x-y} \\ the\text{ sign of the result depends on the greates absolute value, it means the answer will have the same of the bigger number( absolute value)} \end{gathered}[/tex]

d)The values of the two integers are opposites​

as the point C , the sign depends on the bigger number

for example

[tex]\begin{gathered} 8-5=3\text{ positive because 8 is the bigger} \\ 5-8=-3\text{ negative because (-8) is has the bigger absolute value} \end{gathered}[/tex]

so, the answer is Both integers have negative values

I hope this helps you

how to find the length of side x. really having a hard time on this

Answers

Since the figure is a square the diagonal divide it in two congruent right triangles. One of them is shown below:

Since we have right trisang

the diagram show a side (a) find the height of the top of the side(b) find the length of the side

Answers

Part a

Find out the height of the triangle of the figure

we have that

sin(70)=h/2 -----> by opposite side divided by the hypotenuse

solve for h

h=2*sin(70)

h=1.88 m

Part b

Find the base of complete triangle

so

Let

x-----> the base of complete triangle

we have that

x=2*cos(70)+h/tan(40)

substitute the value of h

x=2*cos(70)+1.88/tan(40)

x=2.92 m

A line cuts the y-axis at (0, -6) and passes through the point (9, -3). Find the equation of the line.

Answers

point 1 (0,-6) and point 2 (9,-3)

the equation is

[tex]y-y1=m(x-x1)[/tex]

where m =

[tex]m=\frac{y2-y1}{x2-x1}=\frac{-3-(-6)}{9-0}=\frac{-3+6}{9}=\frac{3}{9}=\frac{1}{3}[/tex]

answer: the equation of the line is

[tex]\begin{gathered} y-(-6)=\frac{1}{3}(x-0) \\ y+6=\frac{1}{3}x \\ y+6-6=\frac{1}{3}x-6 \\ y=\frac{1}{3}x-6 \end{gathered}[/tex]

A population of beetles are growing accordingto a linear growth model. The initial population (week 0) isPo = 5, and the population after 7 weeks is P = 82.Find an explicit formula for the beetle population after n weeks..Pn-After how many weeks will the beetle population reach 258?weeks

Answers

Answer:

P(n) = 5 + 11n

n = 23 weeks

Explanation:

The equation for the population as a linear growth model has the form

P = P0 + an

Where P0 is the initial population, n is the number of weeks and a is the rate of increase per week. We know that P0 = 5, so

P = 5 + an

Additionally, when n = 7 the value of P = 82, so we can use this to find the value of a as follows

82 = 5 + a(7)

82 = 5 + 7a

82 - 5 = 5 + 7a - 5

77 = 7a

77/7 = 7a/7

11 = a

Therefore, the equation for the population after n weeks is

P(n) = 5 + 11n

Finally, to know the number of weeks to reach a population of 258, we need to replace P by 258 and solve for n, so

258 = 5 + 11n

258 - 5 = 5 + 11n - 5

253 = 11n

253/11 = 11n/11

23 = n

So, after 23 weeks the population will be 258.

Select the correct answer.What is the range of Piecewise and Absolute Value Functions

Answers

Given the function :

g(x) = -1/2 |x-6| + 1

• Th,e, 1 ,, highlighted in yellowabove, indicates the maximum y- intercept that the graph will ever reach .

,

• The equation follows y = Mx + b structure , meaning range is from -infinity.

,

• So the range of this equation will be (-∞ ; 1]

,

• Option A is the correct choice .

Absolute value:

asymptote : none

extreme point (6;1)

critical point : x = 6

Provide reasons for the proofGiven line m is parallel to line nprove angle 1 is supplementary to angle 3

Answers

The first reason is Given.

The second is corresponding angles theorem.

The third one is definition of congruent angles.

The fourth is definition of linear pair.

The fifth is linear pair theorem.

The sixth is definition of supplementary angles.

The seventh is addition property of equality.

The eighth is definition of supplementary angles.

I need help with these two problems.Use the given functions solve:f(x)=6x+7. g(x)= -2x-4. h(x)= -3x/41. g(-6)2. h(-12)I also need help with this.I attached the graph that goes along with the questions.1. If Unit Produced is a function of Labor Hours,f(5)=?A. 3B. 4C. 8D. 102. What can be determined, when f(x)=8?A. Units produced are 5B. Labor hours are 5C. Units produced are 10D. Cannot be determined

Answers

We are given the following functions

[tex]f\mleft(x\mright)=6x+7\qquad g(x)=-2x-4\qquad h(x)=-\frac{3x}{4}[/tex]

We are asked to find out g(-6) and h(-12)

1. g(-6)

it simply means that we have to plug x = -6 into the function of g(x)

[tex]\begin{gathered} g(x)=-2x-4 \\ g(-6)=-2(-6)-4 \\ g(-6)=12-4 \\ g(-6)=8 \end{gathered}[/tex]

Therefore, g(-6) = 8

2. h(-12)

Once again we have to plug x = -12 into the function of h(x)

[tex]\begin{gathered} h(x)=-\frac{3x}{4} \\ h(-12)=-\frac{3(-12)}{4} \\ h(-12)=\frac{36}{4} \\ h(-12)=9 \end{gathered}[/tex]

Therefore, h(-12) = 9

y=3sin(1/2 x+pi/6)please find amplitude period and phase shift

Answers

The given function is

[tex]y=3\sin (\frac{1}{2}x+\frac{\pi}{6})[/tex]

We have to use the following form

[tex]a\sin (bx-c)+d[/tex]

Where the amplitude is a, the period is 2pi/b, and the phase shift is c/b. In the given function a = 3, b = 1/2, and c = pi/6.

[tex]\begin{gathered} a=3 \\ T=\frac{2\pi}{b}=\frac{2\pi}{\frac{1}{2}}=4\pi \\ \theta=\frac{c}{b}=\frac{\frac{\pi}{6}}{\frac{1}{2}}=\frac{2\pi}{6}=\frac{\pi}{3} \end{gathered}[/tex]Therefore, the amplitude is 3, the period is 4pi, and the phase shift is pi/3.
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