Since every year the value of the house increase by 4%, the new value will be the previous value plus 4% of the previous value. To find 4% of a quantity, we just have have to multiply it by 4 and then divide by 100(or, written as a decimal, multiply the number by 0.04).
If we call the previous value of the house as P and the new value as N, the new value after one year will be
[tex]N=P+0.04P=(1+0.04)P=1.04P[/tex]Every year that passes, to get the new value we multiply again by 1.04. The expression for the predicted value after t years is
[tex]N(t)=P_0(1.04)^t[/tex]Where P0 represents the initial value of the house. Evaluating t = 22 on this expression, we have
[tex]N(22)=205,900(1.04)^{22}=487,966.279171\ldots\approx487,966[/tex]The predicted value of his home in 22 years is $487,966.
Jamie cut a rope into thirds.He used two of the pieces to make a swing
The complete length of the rope would be represented by 1
If he cut the rope into thirds, it means that each length woiuld be 1/3.
Given that he used two of the pieces to make a swing, it means that the length used in making the swing is
1/3 + 1/3 = 2/3
The left over rope is 1/3
Also, he used equal lengths of the left over rope on four picture frames. It means that the length used on each picture frame is
1/3 divided by 4
= 1/3 * 1/4 = 1/12
Thus, the fraction of the original rope that he used for each picture frame is 1/12. Option B is correct
which expression can be used to find the length of the side of the triangle represented by the vertices (5,5) and (7,-3) on the graph?
In order to determine the correct expression for the length of the side, consider that the distance in between two points (x1,y1) and (x2,y2) is given by the following formula:
d = √((x2 - x1)² + (y2 - y1)²)
if (x1,y1) = (5,5) and (x2,y2) = (7,-3) you have for d:
d = √((7 - 5)²+(5 - (-3))²)
How many ways can we award a 1st, 2nd, and 3rd place prize among eight contestants?
We have:
- There are 8 choices for awarding first prize.
- Then there are 7 choices for awarding second prize.
- And there are 6 choices for awarding third prize.
Therefore, there are:
[tex]8\cdot7\cdot6=336\text{ ways}[/tex]Answer: 336 ways
A grocery store surveys its customers and asks them to indicate (a) how many times they go to the grocerystore in a typical month, (b) their age (in years), (c) whether or not they have ever had to wait in line at thegrocery store more than 10 minutes, (d) the product they purchase most often at the grocery store, and (e)how long (in years) they have shopped at this particular grocery store. We would consider the customer'sage in years to be aand whether or not the customer has had to wait in linemore than 10 minutes to be aO numerical variable; categorical variableO categorical variable; categorical variableO numerical variable; numerical variableO explanatory variable; response variableO categorical variable; numerical variable
The age in years is a numerical variable because it can be listed in ascending or descending order. while whether or not the customer has had to wait in line more than 10 minutes is a categorica
Determine the equation of the line that goes through the point (4, 4) with -1/4 slope. Enter your answer in slope-intercept form.Enter EquationPls see picture
The equation of a line in the slope intercept form is expressed as
y = mx + c
where
m represents slope
c represents y intercept
From the information given,
m = - 1/4
the line passes through the point (4, 4). This means that
x = 4, y = 4
We would find c by substituting m = - 1/4, x = 4 and y = 4 into the slope intercept equation. We have
4 = - 1/4 * 4 + c
4 = - 1 + c
Adding 1 to both sides of the equation,
4 + 1 = - 1 + 1 + c
c = 5
By substituting m = - 1/4 and c = 5 into the slope intercept equation, the equation of the line is
y = - x/4 + 5
Name the quadrant in which each of the point lies. (-2,5)
The quadrants have the following division.
Since the points (-2, 5) is located on the negative side of the x-axis, and in the positive side of the y axis, it belongs to the second quadrant.
The answer is quadrant II
use the point slope formula in the given points to choose the correct linear equation in slope intercept formfor ( 4,-3) and (-2,5)
The point-slope formula is
[tex]y-y_1=m(x-x_1)[/tex]where m is the slope of a line passing through the point (x₁, y₁).
Also, the slope m of a line passing through points (x₁, y₁) and (x₂, y₂) is
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]In this problem, the line passes through points (4, -3) and (-2, 5). Thus, we have:
x₁ = 4
y₁ = -3
x₂ = -2
y₂ = 5
Then, the slope is
[tex]m=\frac{5-(-3)}{-2-4}=\frac{5+3}{-6}=\frac{8}{-6}=-\frac{4}{3}[/tex]And the equation in point-slope form is
[tex]y-(-3)=-\frac{4}{3}(x-4)[/tex]Now, we need to rewrite this equation in slope-intercept form. The slope-intercept equation of a line with slope m and y-intercept b is
[tex]y=mx+b[/tex]Thus, we need to isolate y on the left side of the equation to obtain the slope-intercept form, as follows:
[tex]\begin{gathered} y+3=-\frac{4}{3}x-\frac{4}{3}(-4)\text{ using the distributive property of multiplication over addition} \\ \\ y+3=-\frac{4}{3}x+\frac{16}{3} \\ \\ y+3-3=-\frac{4}{3}x+\frac{16}{3}-3 \\ \\ y=-\frac{4}{3}x+\frac{16}{3}-\frac{9}{3} \\ \\ y=-\frac{4}{3}x+\frac{7}{3} \end{gathered}[/tex]Therefore, the slope-intercept form of that linear equation is
[tex]y=-\frac{4}{3}x+\frac{7}{3}[/tex]Write the equation of the line in standard form that passes through point P(-5,7) andPerpendicular to the equation of the line y=-x+2.
The given equation is
[tex]y=-x+2[/tex]We have to find a new line perpendicular to the given line and must pass through P(-5,7).
First, we use the definition of perpendicularity for two lines.
[tex]m_1\cdot m_2=-1[/tex]Where one of the slopes is equal to -1 because the coefficient of x in the given equation is -1. Let's find the other slope.
[tex]\begin{gathered} m\cdot(-1)=-1 \\ m=1 \end{gathered}[/tex]This means the new perpendicular line has a slope of 1.
Now, we use the slope we found, the point P, and the point-slope formula, to find the equation.
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-7=1(x-(-5)) \\ y-7=x+5 \\ y=x+5+7 \\ y=x+12 \end{gathered}[/tex]Therefore, the equation of the new perpendicular line is y = x + 12.hello I'm having some difficulty on this question thank you for viewing it and helping me
The simple interest charged by the lender on Alonzo is $ 126 and the amount paid after 6 years is $ 826.
Principal amount of loan = $ 700
Time period = 6 years
Interest rate = 3 %
The simple interest is charged by the lender:
The interest will be:
SI = p × r × t / 100
Substitute the values, we get that:
SI = 700 × 3 × 6 / 100
SI = 7 × 3 × 6
SI = $ 126
The amount paid by Alonzo after 6 years will be:
Amount = $ 700 + $ 126
A = $ 826
Therefore, the simple interest charged by the lender on Alonzo is $ 126 and the amount paid after 6 years is $ 826.
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Solve the system of equations:3x+y=6 2x+3y=11
Answer:
(1,3)
Explanation:
Given the system of equations:
[tex]f(x)=\begin{cases}3x+y=6 \\ 2x+3y=11\end{cases}[/tex]To solve the system using the elimination method, multiply the first equation by 3.
[tex]\begin{gathered} f(x)=\begin{cases}9x+3y=18 \\ 2x+3y=11\end{cases} \\ \text{Subtract} \\ 7x=7 \\ \text{Divide both sides by 7} \\ \frac{7x}{7}=\frac{7}{7} \\ x=1 \end{gathered}[/tex]Next, substitute x=1 into any of the equations to solve for y.
[tex]\begin{gathered} 3x+y=6 \\ 3(1)+y=6 \\ y=6-3 \\ y=3 \end{gathered}[/tex]The solution to the system of equations is (x,y)=(1, 3).
Filling in Table (decreasing)Dependent QuantityA Helicopter flying at 3509 feet begins its descent. Itdescends at a rate of 41 feet per minuteIndependent Quantity0Complete the missing part of the tables, and make afunction that describes the Helicopter's decent133222Your answer: Not there yet, keep working3140Share with Class
(0,3509)
(1,3468)
(3,3386)
(7,3222)
(9,3140)
h=3509-41x
Explanation
Step 1
as we can see, the independent quantity is the time , and the dependent quantity is the heigth because it depends on the time.
then when time = o, t=o
[tex]0\Rightarrow3509\text{ ft}[/tex]after 1 minute the helicopter has descended 41 ft, then
when time = 1, t=1
[tex]\begin{gathered} heigth_1=3509-(1\cdot41) \\ heigth_1=3509-41 \\ heigth_1=3468 \\ (1,3468) \end{gathered}[/tex]when t=3
[tex]\begin{gathered} heigth_3=3509-(3\cdot41) \\ heigth_3=3509-123 \\ heigth_3=3386 \end{gathered}[/tex]when heigth=3222
[tex]\begin{gathered} \text{heigth}_x=3509-(x\cdot41) \\ 3222=3509-41x \\ \text{subtract 3509 in both sides} \\ 3222-3509=3509-41x-3509 \\ -287=-41x \\ \text{divide both sides by -41} \\ \frac{-287}{-41}=\frac{-41x}{-41} \\ 7=x \\ \text{hence}(7,3222) \end{gathered}[/tex]when heigth=3140
[tex]\begin{gathered} \text{heigth}_x=3509-(x\cdot41) \\ \text{3140}=3509-41x \\ subtract\text{ 3509 in both sides} \\ \text{3140-3509}=3509-41x-3509 \\ -369=-41x \\ \text{divide both sides by -41} \\ \frac{-369}{-41}=\frac{-41x}{-41} \\ 9=x \\ x=9,\text{then} \\ (9,3140) \end{gathered}[/tex]Step 2
now, the equation is
[tex]\begin{gathered} \text{Heigth}=3509-41x \\ h=3509-41x \\ \text{where} \\ h\text{ is the heigth in ft and t is the time in minutes} \end{gathered}[/tex]I hope this helps you
InequalitiesEvaluate. Show your work or explain how you arrived at your answer.-|-34|
The value of -|-34| is -34
-|-34|
Apply absolute rule: |-a|=a, a>0 =-34
The absolute value (or modulus)| x | of a real number x is its non-negative value regardless of its sign. For example, 5 has an absolute value of 5, and 5 has an absolute value of 5. A number's absolute value can be conceived of as its distance from zero along the real number line.
Absolute values for real numbers occur in a wide range of mathematical contexts. Absolute values, for example, are defined for complex numbers, quaternions, ordered rings, fields, and vector spaces. In numerous mathematical and physical contexts, the absolute value is intimately related to the concepts of magnitude, distance, and norm.
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Determine the equation of the straight line that passes through the point (-2, -4)and is perpendicular to the line y +2x=1
If the line is perpendicular to:
[tex]y=-2x+1[/tex]the we know that the slope will be the negative reciproc of the slope so the new slope is:
[tex]m=\frac{1}{2}[/tex]So the equation is:
[tex]y=\frac{1}{2}x+b[/tex]So we can replace the coordinate (-2,-4) and solve for b so:
[tex]\begin{gathered} -4=\frac{1}{2}(-2)+b \\ -4+1=b \\ -3=b \end{gathered}[/tex]So the final equation is:
[tex]y=\frac{1}{2}x-3[/tex]Find the area of 11.4 and 7.4
let,
lenght (l)=11.4 , and width (b)=7.4
so,
[tex]\begin{gathered} \text{area}=l\times b \\ =11.4\times7.4 \\ =84.36 \end{gathered}[/tex]area=84.36
Alex’s paycheck was for $624.65. If Alex worked 32.5 hours, what is his rate of pay?
In order to know the rate of pay, we need to divide the value of the paycheck ($624.65) by the total hours Alex worked (32.5 hours):
$624.65/(32.5 hours) = $624.65/(32.50 hours) = $62465/(3250 hours)
Now, to solve this division, we can do as follows:
Therefore, the rate of pay is
$19.22/hour
A clothing store is donating socks to various charities. The store gave 6 regular packs and 5 value packs to a homeless shelter, which contained a total of 163 pairs of socks. For foster children, the store donated 6 regular packs and 4 value packs, which equaled 146 pairs. How many pairs of socks are in each pack?
Let r and v be the number of socks ina regular pack and value pack, respectively. Since the store gave 6 regular packs and 5 value packs which contained 163 pair of socks, we can write
[tex]6r+5v=163[/tex]Similarly, since the store donated 6 regular packs and 4 value pack which add 146 pair of socks, we can write
[tex]6r+4v=146[/tex]Then, we have the following system of equations:
[tex]\begin{gathered} 6r+5v=163\ldots(a) \\ 6r+4v=146\ldots(b) \end{gathered}[/tex]Solving by elimilation method.
By multiplying equation (b) by -1, we have an equivalent system of equations:
[tex]\begin{gathered} 6r+5v=163 \\ -6r-4v=-146 \end{gathered}[/tex]Then, by adding both equations, we have
[tex]v=17[/tex]Now, in order to obtain the number of socks in a regular pack, we must substitute the last result into equation (a). It yields,
[tex]6r+5(17)=163[/tex]which gives
[tex]6r+85=163[/tex]By subtracting 85 to both sides, we have
[tex]6r=78[/tex]Then, r is given by
[tex]\begin{gathered} r=\frac{78}{6} \\ r=13 \end{gathered}[/tex]Therefore, the answer is: There are 13 pairs of socks in each regular pack and 17 pairs in each value pack.
what value of c would complete the square for the following trinomials?
To find the value of c that will make the given expression a perfect square, we simply;
Step 1: Take the coefficient of x : that is, 6
Step 2: Divide the coefficient obtained in step 1 by 2: That is, 6/2 = 3
Step 3: Square the result in step 2: That is, 3^2 = 9
Hence, c = 9
The value of c in the first expression is 9.
Second Expression:
[tex]x^2-10x+c[/tex]Step 1: 10 ( Do not bother yourself with the negative sign, just pick the number 10)
Step 2: 10/2 = 5
Step 3: 5^2 = 25
so, c = 25
Third expression:
[tex]x^2+32x+c[/tex]Step 1: 32
Step 2: 32/2 = 16
Step 3: 16^2 = 256
So, c = 256
Fourth expression:
[tex]x^2-12x+c[/tex]Step 1: 12
Step 2: 12/2 = 6
Step 3: 6^2 = 36
So, c = 36
Last expression:
[tex]x^2+8x+c[/tex]Step 1: 8
Step 2: 8/2 = 4
Step 3: 4^2 = 16
so, c = 16
1) 42,58, 67,55, 40, 69, 66, 51, 46, 48, 68 Minimum : Q: Q2: Q, Maximum :
EXPLANATION
Minimum
The first Quartile is the value separating the lower quarter and higher three - quarters of the data set.
The first quartile is computed by taking the median of the lower half of a sorted set.
Arranging terms in ascending order
40, 42 , 46, 48, 51, 55, 58, 66, 67, 68, 69
Here, we can see that:
Minimum = 40
Maximum = 69
Q2=55 (median)
Taking the lower half of the ascending set:
Counting the number of terms in the data set:
{40, 42 , 46, 48, 51, 55, 58, 66, 67, 68, 69}
{1, 2 , 3, 4, 5, 6, 7, 8, 9, 10, 11}
The number of terms in the data set is:
11
Since the number of terms is odd, take the elements below the middle one, that is, the lower 5 elements.
40, 42 , 46, 48, 51
Median of 40, 42 , 46, 48, 51:
The number of terms in the data set is 5.
Since the number of terms is odd, the median is the middle element of the sorted set.
Q1: 46
------------------------------------
Q3:
Since the number of terms is odd, take the elements above the middle one, that is, the upper 5 elements.
58, 66, 67, 68, 69
The number of terms in the data set is
5
Since the number of terms is odd, the median is the middle element of the sorted set.
Q3=67
------------------------------------------------------------------------------------
Interquartile Range:
The interquartile range is the difference of the first and third quartiles
We have that:
Q1=46
Q3=67
Computing the difference between 67 and 46:
67-46= 21
Interquartile Range=21
-------------------------------
Answers:
Minimum = 40
Q1=46
Q2=55 (median)
Q3=67
Maximum = 69
Interquartile Range=21
ESFind the distance d(P. P2) between the points P, and P2-omennsP. = (-4.3)P2 = (3.2)ERE!(P, P2) =O(Simplify your answer. Type an exact answer using radicals as needed.)1 Guit2 Gunents
We have two points and we need to calculate the distance between them.
The points are P1(-4,3) and P2(3,2).
We can apply the following formula for the distance between points:
[tex]D=\sqrt{(x_2-x_1)^2}+(y_2-y_1)^2[/tex][tex]\begin{gathered} D=\sqrt{(3-(-4))^2}+(3-2)^2 \\ D=\sqrt{7^2+1^2}=\sqrt{49+1}=\sqrt{50}=\sqrt{(25\cdot2})=5\sqrt{2} \end{gathered}[/tex]The answe is 5 times the square root of 2:
[tex]D=5\sqrt{2}[/tex]12 Stefanie is painting her bedroom. She can paint 12 1/3 square feet in 1/5 of an hour. How many square feet can she paint in one hour?
stephanie can paint 12 1/3 square feet in 1/5 of an hour. So,
[tex]undefined[/tex]can u help solve problem
To multiply the matixes, we'll look at their elements
[tex]A=\begin{bmatrix}{A_1} & {A_2} & {A_3} \\ {} & {} & {} \\ {} & {} & \end{bmatrix},\text{ B=}\begin{bmatrix}{B_1} & {} & {} \\ {B_2} & {} & \\ {B_3} & {} & {}\end{bmatrix}[/tex]In order to get AB, we simply use the following formula
[tex]AB=A_1\cdot B_1+A_2\cdot B_2+A_3\cdot B_3[/tex]In this case
[tex]AB=3\cdot1+4\cdot2+5\cdot3+6\cdot4=3+8+15+24=50[/tex]Since both matrixes have 4 elements. Thus
[tex]AB=50[/tex]using the graph below wich graphs shows the mapping of ABCD to A'B'C'D for a dilation with center (0,0) and a scale factor of 3
The rule for a dilation with center at (0,0) and scale factor k is:
[tex](x,y)\rightarrow(kx,ky)[/tex]Find the transformed vertices A'. B', C' and D' using this rule:
[tex]A(-2,3)\rightarrow A^{\prime}(3\times-2,3\times3)=A^{\prime}(-6,9)[/tex]Similarly, the coordinates of B', C' and D' wil be:
[tex]\begin{gathered} B^{\prime}(6,12) \\ C^{\prime}(6,-3) \\ D^{\prime}(-9,3) \end{gathered}[/tex]Plot A', B', C' and D' along with A, B, C and D:
Determine whether the function is linear. If it is, State the rate of change.Question 8
Question 8.
Given the table:
x -7 -5 -3 -1 0
y 11 14 17 20 23
To determine if the function is linear, let's calculate to see if the rate of change is constant.
The x-values need to have a constant rate of change and the y-values need to have a constant rate of change.
If the function has a constant rate of change, then the functioncan be said to be linear.
To calculate the rate of change, we have:
[tex]\begin{gathered} x2-x1=-5\text{ - (-7) = -5 + 7 = 2} \\ \\ x3-x2=-3-(-5)=-3+5=2 \\ \\ x4-x3=-1-(-3)=-1+3=2 \\ \\ x5-x4=0-(-1)=0+1=1 \\ \\ We\text{ can se}e\text{ the x-values do not have a constant rate of change} \end{gathered}[/tex][tex]\begin{gathered} y2-y1=14-11=3 \\ \\ y3-y2=17-14=3 \\ \\ y4-y3=20-17=3 \\ \\ y5-y4=23-20=3 \\ \\ \text{The y-values have a constant rate of change} \end{gathered}[/tex]Since the x-values do not have a constant rate of change that means the function is not linear.
ANSWER:
The table does not represent a linear function
Simplify.
Radical sign 45x
9
Answer:
20.12461179
Step-by-step explanation
The temperature of a solution in a science experiment is -6.2°C. Jesse wants to raise the temperature so that it is positive. (a) Give an example of a number of degrees Celsius by which Jesse could raise the temperature. (b) Write a equation to represent the solution.
Hello!
First, the temperature is -6.2ºC, and Jesse wants to raise it until be positive.
(a) Give an example of a number of degrees Celsius by which Jesse could raise the temperature.If we add 6.2ºC, we will obtain a temperature equal to 0ºC, right? So, to the temperature be positive you can choose any temperature greater than 6.2º.
For example, I'll choose 15ºC.
(b) Write an equation to represent the solution. We will write the current temperature plus the temperature that we will add, then we obtain the new temperature, look:
-6.2ºC + 15ºC = 8.8ºC
Complete the following equation. Your answers will be algebraic expressions. (a+bi)^2= _____ + 2abiHint: think of i as an ordinary variable and then replace i^2 with -1.
The given expression is:
[tex](a+ib)^2[/tex]Expand to get:
[tex]\begin{gathered} (a+ib)^2=a^2+i^2b^2+2abi \\ =a^2-b^2+2abi \end{gathered}[/tex]The value is as above since it is given that i^2=-1.
So the expansion is:
[tex](a+ib)^2=a^2-b^2+2abi[/tex]The blank should be:
[tex]a^2-b^2[/tex]The ratio of the amount of money Rachel saved to the amount of money Timothy saved was12 : 13. After Timothy spent $27, Rachel had 3 times as much as Timothy,A. How much did Rachel save?b How much did they save altogether at first?
For a)
Before
Rachel : Timothy
12 : 13
After
Rachel : Timothy
3 : 1
In order to have the same amount for Rachel
12: 4
Timothy
13units -4 units =9 units
9units=$27
1 unit=27/9
1unit = $3
For Rachel
Rachel saved $36
b)
Total units at first =12+13=25
If 1units is $3
25 units is 3x25
25 units is $75
They saved together 75
ANSWER
Rachel saved $36
They saved together 75
I need help with this math question I already solved the first question but I don't understand the second.
We can solve this question using cross multiplication,
If the number of students who sleep 6 hours a day increases by, this means we'll have a total of 6 students who sleep 6 hours a day.
We want the ratio to be same: 15%
Then we can write:
[tex]\frac{6}{N}=\frac{15\%}{100\%}[/tex]6 students are the 15%, then N students are the 100%
Now solve for N:
[tex]\begin{gathered} 6·100=15·N \\ \end{gathered}[/tex][tex]N=\frac{600}{15}[/tex][tex]N=40[/tex]The answer is 40 students are expected.
This is a reasonable answer, given that if the number of students who sleep 6 hours doubles, for the rate to remain the same, the total of students must double.
Solve fort.-t = 9(t – 10)t=Stuck? Watch a video or us
We are to solve for t in the equation given
To do this, we have to expand the bracket
Expanding, we have
-t = 9(t-10)
-t = 9t - 90
Collecting the like terms, we have
90 = 9t + t
90 = 10t
Dividing both sides by 10 to get t, we have
[tex]\begin{gathered} t=\frac{90}{10} \\ t=9 \end{gathered}[/tex]Therefore the value of t is 9.
Which tree is growing faster?Tree 2Tree 1 is growing 2 week 2 4 6 8 10inches every week. inches5 10 15 20 25tallHint: First calculate the unit rate for Tree 2.Enter the number that belongs in the numerator.Unit Rate[?]=inches/week
Calculating the unit rate for Tree 2 we have the following
[tex]\text{Unit Rate }=\frac{5\text{ inches}}{2\text{ week}}\text{ }=\frac{10\text{ inches}}{4\text{ week}}\text{ }=\frac{15\text{ inches}}{6\text{ week}}[/tex]When simplified the unit rate is
[tex]\frac{5}{2}\text{ inches/week}[/tex]This is 2.5 inches per week. Compared to Tree 1,