how would I solve this problem?

Answer:

Describe how a sample of copper chloride crystals could be made from copper carbonate and dilute hydrochloric acid. Add excess copper carbonate to hydrochloric acid in a beaker, stirring until there is no further reaction. Filter the mixture to remove the remaining copper carbonate, then heat the remaining solution to the point of crystallisation.

Explanation: Hope this is right.

Answer:

0.319 M

Explanation:

M1V1 = M2V2

M1 = 0.55M

V1=145 mL = 0.145 L

V2 = 250mL = 0.250L

M2 = M1V1/V2=0.55x0.145/0.250 = 0.319 M

Answer:

6.2

Explanation:

Complete Question:

Give one word for the following.

a. An undesirable constituent of air

b. The constituent of air that helps in burning

c. The thick layer of air surrounding the earth

d. Carbon dioxide does not support this process​

Answer:

a. Pollutant.

b. Oxygen.

c. Atmosphere.

d. Combustion.

Explanation:

a. Pollutant: an undesirable constituent of air. Pollution can be defined as the physical degradation or contamination of the environment through an emission of harmful, poisonous and toxic chemical substances known as pollutants. Some examples of pollutant are carbon monoxide, nitrogen dioxide, ozone, etc.

b. Oxygen: the constituent of air that helps in burning. Oxygen is an element that aids in the combustion (burning) process because it is an oxidizing agent.

c. Atmosphere: the thick layer of air surrounding the earth. It comprises of nitrogen, oxygen, carbon dioxide, argon and other gases in very small proportion.

d. Combustion (burning): Carbon dioxide does not support this process but it is an end product of the process.

Combustion can be defined as an exothermic chemical reaction between physical substances, usually in the presence of oxygen and hydrocarbons to produce heat, light and carbon.

Answer:thanks for the points

Explanation:

Answer: 2

Explanation:

it’s reflected

Answer:

Transmitted

Explanation:

Because this is when its granted safe passage through the medum

Absorbed: energy goes through and disappears

Reflected: is when light bounces off a surface (mirrors)

In science, literature, and everything, equilibrium has the same meaning. The meaning simply put, is balance. If you wanted a sentence example, it could be something like:

'He sat down to try and recover his equilibrium.'

Or

'They can't maintain enough equilibrium to ride a bike.'

I hope you understand the meaning now?

Answer:

2a) 15 g/dm3

2b) 0.512 g/dm3

Explanation:

Use the concentration = mass/volume equation.

Balanced Eqn

2

C

2

H

6

+

7

O

2

=

4

C

O

2

+

6

H

2

O

By the Balanced eqn

60g ethane requires 7x32= 224g oxygen

here ethane is in excess.oxygen will be fully consumed

hence

300g oxygen will consume  

60

⋅

300

224

=

80.36

g

ethane

leaving (270-80.36)= 189.64 g ethane.

By the Balanced eqn

60g ethane produces 4x44 g CO2

hence amount of CO2 produced =

4

⋅

44

⋅

80.36

60

=

235.72

g

and its no. of moles will be  

235.72

44

=5.36 where 44 is the molar mass of Carbon dioxide

hope this helps

We can use the equation for dilutions that relates concentration and volume:

[tex]M_1V_1=M_2V_2[/tex]

where M is the molarity, V is the volume, and 1 and 2 refer to the initial and final states of the solution, respectively. Here, we are given the molarity of the initial solution and the volumes of the initial and final (diluted) solutions. To find the final concentration (i.e., the molarity of the diluted solution), we would be solving for M₂:

[tex]M_2=\frac{M_1V_1}{V_2} = \frac{(0.55 \text{ M})(145 \text{ mL})}{250 \text{ mL}} \\ M_2 = 0.319 \approx 0.32 \text{ M}.[/tex]

The molarity is given to two significant figures as both our M₁ and V₂ are given to two significant figures.

Note: Although our volumes are in mL instead of L, we do not need to convert them to L for the purposes of our calculation since we would be multiplying our V₁ and V₂ by a common factor that would cancel out in division. All that matters is the ratio between the two volumes, which is the same whether the volumes are in mL or in L.

---

We follow the exact same procedure in the second question as we did in the first problem: solve for M₂ given M₁ = 9.02 M, V₁ = 35.0 mL, and V₂ = 45.0 mL:

[tex]M_2=\frac{M_1V_1}{V_2} = \frac{(9.02 \text{ M})(35.0 \text{ mL})}{45.0 \text{ mL}} \\ M_2 = 7.02 \text{ M}.[/tex]

Answer:

122g/63.5

1.92 mol

Answer:

None

Explanation:

There are two S=O. bonds and two S-O bonds in sulfate ion lewis structure. Sulfur atom is the center atom and four oxygen atoms are located around sulfur atom. There are no lone pairs in the last shell of sulfur atom.

Answer:

4.03 g

Explanation:

The mass in grams of the hydrogen gas is 4.0 g

From the question,

We are to determine the mass in grams of the hydrogen gas.

First, we will determine the number of moles of hydrogen gas present.

Using the formula,

[tex]Number\ of\ moles =\frac{Number\ of \ molecules}{Avogadro's\ constant}[/tex]

From the given information,

Number of hydrogen molecules = 1.204 × 10²⁴ molecules

Thus,

Number of moles of hydrogen gas present = [tex]\frac{1.204 \times 10^{24} }{6.02 \times 10^{23} }[/tex]

Number of moles of hydrogen gas present = 2 moles

Now, for the mass of the hydrogen gas

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of hydrogen gas = 2.016 g/mol

Then,

Mass of the hydrogen gas = 2 × 2.016

Mass of the hydrogen gas = 4.032 g

Mass of the hydrogen gas ≅ 4.0 g

Hence, the mass in grams of the hydrogen gas is 4.0 g

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Answer:

It's either C or D

Explanation:

I'm learning this too! :)

56.8g of aluminum chloride will be produced if the reaction begins with 135.0 g Al and 75.0 g chlorine gas.

A body's mass is an inherent quality. Prior to the discovery of a atom or particle physics, it was widely considered to be tied to the amount of matter inside a physical body. It was discovered that, despite having the very same quantity of matter in theory, different atoms and elementary particles have varied masses.

There are various conceptions of mass in contemporary physics that are theoretically different but physically equivalent. The resistance of the body to acceleration in the presence of a net force can be measured experimentally as mass. The gravitational pull an object has on other bodies is also influenced by its mass.

2 Al + 3 Cl[tex]_2[/tex] → 2 Al C l[tex]_3[/tex]

mole of Al =  135.0/ 26=5.19mol

mole of Cl[tex]_2[/tex] = 75.0/ 35 =2.14 mol

mass of aluminum chloride =  56.8g

Limiting reagent = Al

excess reactant =  Cl[tex]_2[/tex]

Therefore, 56.8g of aluminum chloride will be produced if the reaction begins with 135.0 g Al and 75.0 g chlorine gas.

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Answer:

A solid metal bead of the same size is dropped into the same cup and sinks to the bottom of the cup. How do the pebble and the metal bead compare? They both have the same mass. They are both denser than water.

Explanation:

nun

Answer:

Both the pebble and metal bead of the same mass will be equally accelerated  if they are at the same place, in this case, they are in the same place meaning they will be accelerated at the same speed towards the earth. Thus even if they are in the water they will sink at the same speed and finally will reach the bottom of the cup.

Answer:

A. 650 g

Explanation:

The equation of the reaction is given as;

2 HgO(s) --> 2Hg(s)  + O2(l)

From the reaction;

2 mol of HgO produces 1 mol of O2

x mol of HgO would produce 1.50 mol of O2

2 = 1

x = 1.5

Solving for x;

x = 1.5 * 2 / 1 = 3 mol

Converting to mass;

Mass = Number of moles * Molar mass

Mass = 3 mol  * 216.59 g/mol

Mass = 649.77 g ≈ 650. g

Correct option is ;

A. 650 g

Answer:

pH = 3.69

Explanation:

HCl is a strong acid. It will disscociates completely into dissoluted ions such that,

[tex][H^+]=2\times 10^{-4}\ M[/tex]

The formula for pH is given by :

[tex]pH=-log[H^+]\\\\pH=-log(2\times 10^{-4})\\\\pH=3.69[/tex]

So, the pH of the solution is 3.69.

The answer to your question is 4.

Answer:

86

Explanation:

According to the concept of percent yield, the percent yield of carbon dioxide is 72.51%.

Percent yield is defined as the ratio of actual yield to the theoretical yield multiplied by 100. If the actual and theoretical yield are same then the percent yield is 100%.If actual yield is less than the theoretical yield then the percent yield is less than 100%.Reason of this condition arising is the incompletion of reaction or loss of sample during recovery process.

In cases where percent yield is over 100% it indicates that more sample is recovered than the predicted amount.This condition arises when there are other simultaneous reactions taking place leading to the formation of product. It can also arise if there is incomplete removal of impurities from the sample .

In the given example, theoretical yield of carbon dioxide is as 32 g oxygen produces 44 g carbon dioxide,thus 32.5 g which is obtained by 2.5 moles of oxygen will require 32.5×44/32=44.68 g

Thus , on substitution in formula of percent yield, 32.4/44.68×100=72.51%.

Hence, the percent yield of carbon dioxide is 72.51%.

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Answer:

C. do not touch the victim keep the victim quiet and call dor medical assistance

Answer:

D.

Explanation:

MSDS if available should have tx instructions once a call for emergency medical assistance has been made

The given question is incomplete. The complete question is:

Determine how many carbon dioxide molecules are produced if molecules of water are produced

[tex]C_2H_6(g)+O_2 (g)\rightarrow CO2(g)+H_2O(g)[/tex]

Answer: [tex]5.60\times 10^{23}[/tex] molecules of carbon dioxide are produced

Explanation:

The balanced chemical equation is:

[tex]2C_2H_6(g)+7O_2 (g)\rightarrow 4CO2(g)+6H_2O(g)[/tex]

[tex]\text{Moles of water}=\frac{\text{given molecules}}{\text{Avogadros number}}=\frac{8.45\times 10^{23}}{6.023\\times 10^{23}}=1.40moles[/tex]

Accoding to stoichiometry:

6 moles of water are produced along with = 4 moles of carbon dioxide

Thus 1.40 moles of water are produced along with = [tex]\frac{4}{6}\times 1.40=0.93[/tex] moles of carbon dioxide

Molecules of carbon dioxide = [tex]moles\times {\text {Avogadros number}}=0.93\times 6.023\times 10^{23}=5.60\times 10^{23}[/tex]

Explanation:

It to be fossilized, the remains usually to be covered by sediment soon after death. sediment can include the sandy seafloor,lava,and even sticky tar. Over time, minerals in the sediment seep in to remains. The remains become fossilized.

Answer: combustion and girl

Explanation: C3H6O + 4 O2 → 3 CO2 + 3 H2O COMBUSTION

Answer:

Explanation:

close to freezing cause once i go to bed my pillow will always stay cold and i can finally have all my blankets on and not over heat and not to mention when i play sports free air conditioning

Answer:

okay but give me brainliest

Explanation:

A volcano is formed when hot molten rock, ash and gases escape from an opening in the Earth's surface. The molten rock and ash solidify as they cool, forming the distinctive volcano shape shown here. As a volcano erupts, it spills lava that flows downslope. Volcanic flows are called lahars.

Ionic compound K₂O is potassium superoxide. CaCl₂ is calcium chloride. The compound Mg₃N₂ is magnesium nitride and NaClO is sodium hypochlorite and KNO₃ is potassium nitrate.

Ionic compounds are formed between metals and non-metals. They are bonded by lose of electrons from the metal to the non-metals. An ionic compound is named starting with the cation and then the anionic part is named second with the suffix "ide" , "ate" , "ite" etc.

The compounds with the general formula M₂O are called super oxides. K₂O is called potassium superoxide or dipotassium oxide.

The compound, CaCl₂ is named as calcium chloride. The subscripts in formula  are the number of each atoms in the compounds.

Similarly Mg₃N₂ is named as magnesium nitride and KNO₃ is called potassium nitrate. The compound NaClO is named as sodium hypochlorite.

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3.300

bc im right fgdfgdffffffffg

Answer:

C

Explanation:

The pairing of the cell produced during meiosis and correct example is haploid cell: egg cell (Option C).

In conclusion, the pairing of the cell produced during meiosis and correct example is haploid cell: egg cell (Option C).

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