how long must a simple pendulum be if it is to make exactly one swing per five seconds? (that is, one complete oscillation takes exactly 10 ss .)

Answers

Answer 1

A simple pendulum's string needs to be 24.8 metres long in order to oscillate precisely once every 10 seconds.

Use the formula for a simple pendulum:

T = 2π √(L/g)

Where T is the period (time to complete a full oscillation), L is the length, and g is the acceleration due to gravity ≈ 9.81 m/s^2.

Since we need to find the Length of the string we'll solve the equation for L.

√(L/g) = T / (2π)

L = [T / (2π) ] ^2 * g = [ 10.0s / (2π) ]^2 * 9.81 m/s^2 = 24.8 m

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Related Questions

A 512 Hz tuning fork was sounded at the same time as another tuning fork which has been damaged. Over the course of 10 seconds, 30 beats were heard. What are the possible frequencies of the second fork?

Answers

The possible frequency of the second fork is 508.988 Hz or 509Hz approximately.

What is beat frequency ?

When two sounds are played simultaneously, they will conflict with one another. Beats are secondary waves that can be heard when the frequencies of these sounds are sufficiently close to one another. The difference between the two frequencies determines the frequency of these beats:

[tex]f_{beats} = f_{1}-f_{2}[/tex]

Here,

[tex]f_{beats}[/tex] = Beat frequency

[tex]f_{1}[/tex] = Frequency of 1st tuning fork

[tex]f_{2}[/tex] = Frequency of 2nd tuning fork

Now,

1 hertz = 60 Beats per minute.

Given,

Number of beats = 30

time taken = 10 seconds = 0.166 minutes.

Hence, 60 beats per minute = 1 Hz

180.72 beats per minute = 3.012 Hz.

Now,

Beat frequency = 3.012Hz

Frequency of 1st tuning fork = 512Hz

So,

[tex]f_{beats} = f_{1}-f_{2}[/tex]

[tex]f_{2}= f_{1}-f_{beats}[/tex]

  = 512 - 3.012

  = 508.988 Hz

Hence, the possible frequency of the second fork is 508.988 Hz or 509Hz approximately.

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An object has a mass of 100 kg moving at 5 m/s. What is the linear momentum of the object?.

Answers

The linear momentum of the object has a mass of 100 kg moving at 5 m/s = 500 kg m/s.

The linear momentum

Momentum is a quantity that shows the size of the difficulty to stop the motion of an object. If the object is stopped, it requires work equal to the change in mechanical energy.

Linear momentum is related to straight motion and is the product of the mass of the system times its velocity.

The linear momentum equation is:

p = mv

Where,

p is the linear momentum

m is the mass of the object in motion, and

v is the velocity of the object.

We have,

Mass of the object = 100 kg

The velocity of the object = 5 m/s

So, the linear momentum of the object is:

P = (100) (5)

= 500 kgm/s

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Light waves are electromagnetic waves that travel at 3.00 x 10^8 m/s. the eye is most sensitive to light having a wavelength of 5.50 x10^-7 m.(a) Find the frequency of this light wave. (b) Find its period.

Answers

The frequency and the period of light waves with wavelength of  5.50 x10⁻⁷ m is 5.45 x 10¹⁴ Hz and 1.83 x 10⁻¹⁵ second, respectively.

The relation between the speed of an electromagnetic wave, its frequency, and wavelength is given by:

c = λ · f

Where:

c = speed of the electromagnetic wave =  3.00 x 10⁸ m/s

λ = wavelength

f = the frequency of the  electromagnetic wave

In the given problem:

λ = 5.50 x10⁻⁷ m.

Hence,

a) its frequency:

   f = c / λ

     = 3.00 x 10⁸ / 5.50 x10⁻⁷ = 5.45 x 10¹⁴ Hz

b) its period

   T = 1/f = 1.83 x 10⁻¹⁵ second

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light of wavelength 3.19 mm strikes and is absorbed by a molecule. is this process most likely to alter the rotational, vibrational, or atomic energy levels of the molecule?

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light of wavelength 3.19 mm strikes and is absorbed by a molecule this will alter the atomic energy of the molecule.

Rotational strength: kinetic strength related to the rotational movement of molecules. Vibrational strength: the oscillatory movement of atoms or agencies of atoms inside a molecule (capacity strength ↔ kinetic strength exchange).

Electronic strength: strength saved as capacity strength in excited digital configurations .A molecular vibration is worked up whilst the molecule absorbs strength, ΔE, similar to the vibration's frequency, ν, in line with the relation ΔE = hν, wherein h is Planck's constant. A essential vibration is evoked whilst one such quantum of strength is absorbed through the molecule in its floor state.

The first strength degree is likewise referred to as degree 'K'. The 2d degree is referred to as degree L, 1/3 strength degree as M, and so on. Electrons withinside the outermost strength degree also are referred to as Valence electrons. Various residences of atoms are primarily based totally on those valence electrons.

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the waves represented by the data pass by the buoy with a speed of 5 m/s. what is the wavelength of these waves?

Answers

The wavelength of a wave is equal to the speed of the wave divided by its frequency. Since the frequency of the wave is not given, we cannot calculate the wavelength.

The wavelength of a wave is the distance between two successive peaks or troughs of the wave. In order to calculate the wavelength of the waves represented by the data, we need to know the frequency of the waves. Frequency is the number of waves that pass a given point in a given period of time, usually measured in hertz (Hz).

Once we know the frequency of the waves, we can use the following equation to calculate the wavelength:

Wavelength = Speed of Wave / Frequency

For example, if the frequency of the waves is 0.2 Hz, then the wavelength would be:

Wavelength = 5 m/s / 0.2 Hz = 25 m

Therefore, the wavelength of the waves represented by the data will depend on the frequency of the waves.

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a 4.50-v battery is connected across the primary coil of a transformer having 20 turns. if the secondary coil of the transformer has 40 turns, what voltage appears across the secondary?

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A constant flux travels through the secondary coil as a result of the battery's production of a constant current in the first coil. There is no induced voltage across the secondary coil if the flux through the secondary coil remains unchanged.

The value of induced current depends on the change in the flux which is produced due to the change in current in the primary coil, since the voltage is constant the current across the coil is also constant which results in 0 change in flux across the secondary coil which will result in no voltage.

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if there is another objective that can be used, having magnification of -400, what other total magnification is possible?

Answers

The other total magnification possible is 2000.

What is magnification in compound microscope?

The use of many lenses in a microscope is referred to as compounding. Another form of optical microscope is the compound microscope. Simple microscopes are the other kind of optical microscope. Simple and complex microscopes vary in that a simple microscope only requires one lens, but a compound microscope requires many lenses.

An tool used to see magnified pictures of tiny objects, such as cell structures on a glass slide, is a compound microscope or high-power microscope. Enlarging the apparent size is the process of magnification. This expansion is quantified by a mathematical quantity sometimes known as "magnification." Magnification often refers to scaling up graphics to view more detail and raise resolution.

When using a compound light microscope, the power of the objective lens, which can be 4x, 10x, or 40x, must be multiplied by the power of the eyepiece, which is commonly 10x, to determine the overall magnification.Consequently, a 10x eyepiece combined with a 40X objective lens will result in a 400X magnification. Now that the specimen can be seen with the unaided eye at a 400-fold higher magnification, minute features are made visible.

Given,

m = +750

mo = +150

a) total magnification, m  = mo.me

me = m/mo = 750/150 = 5

Thus magnification of eyepiece is 5.

b) Total magnification = mo.me = 400 x 5 = 2000

Thus total magnification of objects having magnification 150 and 400 is 2000.

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The complete question is:

A simple compound microscope with an overall magnification of -750 has an objective that magnifies by -150.

Part (a) What is the magnification of the eyepiece?

Part (b) If there is another objective that can be used, having magnification of -400, what other total magnification is possible?

In what ways is the wireless signal between the cell phones similar to the light that travels from the cell phone to your eyes?.

Answers

Mobile phones transmit and receive signals using electromagnetic waves, that is, wireless signal are electromagnetic waves which can travel through a vacuum, they do not need a medium or matter.

They are generated by electrical and magnetic particles moving at the same time (oscillating).

Characteristics of electromagnetic waves

Network waves are electromagnetic waves.

A mobile phone has coverage when it receives electromagnetic waves from at least one base station.

They do not necessarily require a material medium for their propagation.

Therefore, we can conclude that electromagnetic waves are those that do not need a material medium to propagate and include, among others, radio, television and telephone waves.

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600 joules of heat is absorbed by a system that does 200 j of work on its surroundings. 1) what is the change in the internal energy of the system? (express your answer to one significant figure.)

Answers

the change in the internal energy of the system is 400J

Explanation:

Heat absorbed by the system (q) = 600J

Work done by system (W ) = -200J

First law of thermodynamics

ΔU = q + W

ΔU is change in internal energy

ΔU = 600 - 200

ΔU= 400J

Law of thermodynamics:

The legal guidelines of thermodynamics are a set of scientific legal guidelines which outline a group of physical quantities, along with temperature, electricity, and entropy, that symbolize thermodynamic systems in thermodynamic equilibrium.

The zeroth law of thermodynamics defines thermal equilibrium and forms a basis for the definition of temperature: If two systems are each in thermal equilibrium with a third system, then they are in thermal equilibrium with each other.

the primary law of thermodynamics states that, whilst energy passes into or out of a device (as paintings, warmness, or be counted), the machine's internal strength modifications in accordance with the law of conservation of energy.

the second one law of thermodynamics states that in a natural thermodynamic system, the sum of the entropies of the interacting thermodynamic systems by no means decreases. A commonplace corollary of the statement is that warmth does now not spontaneously bypass from a less warm body to a hotter frame.

The third law of thermodynamics states that the entropy of a system approaches a constant value as the temperature approaches absolute zero. The entropy of a system at absolute zero is usually close to zero, except for amorphous solids (glasses).

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During most of its lifetime, a star maintains an equilibrium size in which the inward force of gravity on each atom is balanced by an outward pressure force due to the heat of the nuclear reactions in the core. but after all the hydrogen fuel is consumed by nuclear fusion, the pressure force drops and the star undergoes a gravitational collapse until it becomes a neutron star. in a neutron star, the electrons and protons of the atoms are squeezed together by gravity until they fuse into neutrons. neutron stars spin very rapidly and emit intense pulses of radio and light waves, one pulse per rotation. these pulsing stars were discovered in the 1960s and are called pulsars.A star with the mass (M=2.0×10^30kg) and size (R=3.5×10^8m) of our sun rotates once every 35.0 days. After undergoing gravitational collapse, the star forms a pulsar that is observed by astronomers to emit radio pulses every 0.200 s. By treating the neutron star as a solid sphere, deduce its radius.

Answers

The radius is 180020 m and the velocity of the star is 5652628 m/s.

Mass of star = m = 2 X 10³⁰ Kg

Radius of star = 3.5 X 10⁸ m

The star rotates around the sun every 35 days.

Time period = t = 35 X 24 X 60 X 60 = 3024000 s

The final time t' = 2 s

Since, angular momentum L is conserved in this process. We can use the formula =

= L = ωI

Here, I = moment of inertia

= I = (2mr²)/5

Thus,

= L = ω X (2mr²)/5

= L = (2mr²)/5 X (2π/t)

= L = (4πmr) / 5t

Now, since L (initial) = L' (final),

= (4πmr) / 5t = (4πmr) / 5t'

Hence,

= (r²/t²) = (r'²/t'²)

Which means,

= r' = r X √(t'/t)

= 7 X 10⁸ X √(0.2/3024000)

= 1.80020 X 10⁵

= 180020 m

And we calculate the velocity of a point on the equator by dividing the final circumference over the final period:

= v = c/t

= v = 2πr'/t'

= v = 2π X 180020/0.2

= v = 5652628 m/s

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The complete question:

During most of its lifetime, s star maintains an equilibrium size in which the inward force of gravity on each atom is balanced by an outward pressure force due to the heat of the nuclear reactions in the core. But after all the hydrogen fuel is consumed by the nuclear fusion, the pressure force drops and the star undergoes a gravitational collapse until it becomes a neutron star. In a neutron star, the electrons and protons of the atoms are squeezed together by gravity until they fuse into neutrons. Neutron stars spin very rapidly and emit intense pulses of radio and light waves, one pulse per rotation. These pulsing stars were discovered in the 1960's and are called pulsars.a) A star with the mass (M=2.0x10^30 Kg) and size (R=7.0x10^8 m) of our sun rotates once every 35 days. After undergoing gravitational collapse, the star forms a pulsar that is observed by astronomers to emit radio pulses every 0.10 s. By treating the neutron star as a solid sphere, deduce its radius.b) What is the speed of a point on the equator of the neutron star? Your answer will be somewhat too large because a star cannot be accurately modeled as a solid sphere. Even so, you will be able to show that a star, whose mass is 10^6 larger than the earth's, can be compressed by gravitational forces to a size smaller than a typical state in the United States!

how fast would a(n) 80 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 380 m/s ?

Answers

14.08 meter per second fast  a(n) 80 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 380 m/s

We have specified that a man weighs 80 kilograms. Additionally, a bullet's mass is equivalent to 8 grams, which is equal to 8 times 10 to the minus 3 kilogram, and its velocity is equal to 380 meters per second. We will now determine the velocity of a man. Now that we have established that the kinetic energy of the guy is equal to the kinetic energy of the bullet, we can conclude that both are equal. In other words, we may write this as 1 divided by 2 capital m multiplied by v square capital m = 1 divided by 2 capital b multiplied by v square capital b.

Generally the equation for the kinetic energy  is mathematically given as

K.E= 1/2*m*[tex]v{2}[/tex]

Therefore

K.E =1/2 *0.008*[tex](420){2}[/tex]

K.E=672.4j

Therefore

[tex]v2[/tex]=673.4*2/85

[tex]v2[/tex]=15.821

v=4.0m/s

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b) given the mass of the rubber in the balloon is 1.80 grams, what is the net vertical force on the balloon if it is let go? consider the buoyant force on the balloon, and the weight of the rubber and the helium inside the balloon. the volume of the rubber itself is negligible

Answers

The net vertical force on the balloon is 0.0058 N.

Given that, mass of rubber in the balloon is 1.8 gm

Acceleration due to gravity is 9.81 m/s²

Let ρ is the density of the gas

v is the volume

Buoyant force is given by Fb = ρ* v* g

Fb = 1.22* 9.81* 2* 10⁻³ = 0.0239364 N = 0.024 N

Net vertical force is given by

Fn = Fb - W he - W r = 0.0239364 - 0.175* 2* 10⁻³ * 9.81 - 1.8 * 10⁻³ *9.81

⇒ 0.0057879 N = 0.0058 N

Thus, the net vertical force on the balloon is 0.0058 N.

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Suppose that the coefficient of kinetic friction between zak's feet and the floor, while wearing socks, is 0. 250. Knowing this, zak decides to get a running start and then slide across the floor.

Answers

The distance travelled by Zak before stopping was 1.84 m.

The force that resists the sliding or rolling of one solid object over another. Frictional forces, such as the traction needed to walk without slipping, may be beneficial, but they also present a great measure of opposition to motion.

Coefficient of Friction = k = 0.250

Zak's speed = v = 3 m/s

Acceleration due to gravity = g = 9.8 m/s²

Work done by frictional force is given by,

= W = ΔKE

= kmgd = (1/2)mv²

= d = v² / 2gk

= d = 3² / 2 X 9.8 X 0.250

= d = 1.84 m

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Why does sleep help injuries?

Answers

Sleep helps in injuries recovery by regulating the proper blood flow on all over the body.

As we fall into the further phases of sleep, our muscles will see an expansion in blood stream, which brings along oxygen and supplements that that help recuperate and fix muscles and recover cells.

Hormones assume a part, as well. At the point when the body enters its profound rest stage known as non-REM rest, the pituitary organ discharges development chemicals that invigorate muscle fix and development. At the point when the body doesn't get sufficient rest, the emission of this development chemical decays, and it can become more diligently for your body to recuperate from wounds.

The hormone prolactin, which manages aggravation, is likewise delivered while resting. On the off chance that you don't get sufficient rest, you're bound to encounter irritation in the body, which can make injury recuperation more troublesome while likewise endangering you of additional injury.

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A galaxy with thin spiral arms and a small spherical central bulge would be a type?a. Sab. SBac. Scd. SBce. S0

Answers

A galaxy with thin spiral arms and a small spherical central bulge would be a type is Sc. Option C.

Spiral galaxies have a central stellar bulge surrounded by a disk containing arms that form a spiral structure. Stars in the bulge of spiral galaxies tend to be older and redder than others. There is also a much darker, roughly spherical halo of stars surrounding the disk.

Central bulge. Surrounding the core is a vast bulge of stars that are roughly spherical in shape and composed mostly of Population II stars but relatively rich in heavy elements. Spiral galaxies typically have rotating disks with spiraling arms that bend from a dense central region. The Milky Way is a spiral galaxy.

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what is the current in milliamperes produced by the solar cells of a pocket calculator through which 4.00 c of charge passes in 4.00 h?

Answers

The current in the milliamperes produced by the solar cells of a pocket is 0.278mA

Magnitude of charge passing through the solar cells, C=4.00C

Time period,  t=4.00h

The current is expressed as the rate at which the electric charge is passing through an electrical appliance. So, the current produced by the solar cells is expressed by the following equation:

I =C/t

Substituting values in the above equation we get

I =0.278mA

The current is defined in physics as the amount of charge that passes through an electrical appliance in a certain amount of time. The magnitude of the current is usually measured in amperes. We can convert the current from amperes to milliamperes by utilizing the appropriate conversion factors.

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if a sound has an intensity 100 times the intensity if a softer sound, how much larger on the decibel scale is the loudness level of the more intense sound?

Answers

A sound level of 10 dB corresponds to a sound that is  or 10 times as loud. A sound level of 20 db is ascribed to a sound that is 10*10 or 100 times stronger . A sound level of 30 db is attributed to a sound that is 10*10*10, or 1000 times more powerful .

What is sound level ?

The term "sound level" relates to different logarithmic measurements of audible vibrations, including: Sound exposure level is a measurement of how loud a sound is in relation to a standard. The rate at which sound energy is emitted, reflected, transmitted, or received per unit of time is measured as the sound power level.

According to the previously mentioned units of 10, a sound that is 10 times louder will be measured as 10 dB, a sound that is 100 times louder than 0 dB will be measured as 20 dB, a sound that is 1,000 times louder than almost silence will be measured as 30 dB, and so on.

Thus,  A sound level of 30 db is attributed to a sound that is 10*10*10, or 1000 times more powerful.

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what mass of 23592u must undergo fission to operate a 1000-mw power plant for one day if the conversion efficiency is 31 %?

Answers

Mass of 23592u must undergo fission to operate a 1000-mw power plant for one day if the conversion efficiency is 31 % is (92)^(235)U`

For 1000MW output, the total power generation is 3000MW, of which 2000W=MW is rejected as "waste" heat. Thus the total energy released in year (3×107s) from fission is about (3×109)(3×107)≈1017 If each fission releases 200MeV of energy, the number of fission required is

(10172×108(1.6×10−19)≈3≈1027fissions The mass of a single uranium atom is about (235u)(1.66×10−27kg/u)≈4.5×10−25kg, so that mass needed is (1017)(2×108)(1.6×10−19) approxeapproxfissionorabouta→n.Since._(92)^(235)U` is only a fraction of normal uranium, and even when the requirement for uranium is of the order of tens of tons.

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3.)slight misalignment between the rotor field and the stator field in a synchronous motor is called the

Answers

Torque Angle is the misalignment of synchronous motor in the stator field and  the rotor field

Torque  Angle: the force used to tighten a bolt or nut. the degree of rotational movement of a bolt or nut. Between the pivot point and the location where the force is applied, measure the distance, r. Calculate the angle between the vector connecting the force's application point and the pivot point and the direction of the applied force. You may calculate the torque by multiplying r by F and sin. Angle refers to the amount of rotation a fastener makes while being tightened and measured for torque.

For example, if a Torque Wrench was to turn and tighten a bolt in one full rotation, this would be 360 degrees. For the d.c. machine, a torque angle of 90° is the normal condition, with field and armature m.m.f.s maintained in quadrature by the angular-position switching action of brushes and commutator.

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you are pulling a child in a wagon. the rope handle is inclined upward at a 60∘ angle. the tension in the handle is 20 n.

Answers

The work done to pull the wagon 100 m at a constant speed is 1000J.

Work is the amount of force that is required to displace any object.

Work is performed when energy is transferred from one energy store to another. It is also performed when we apply a force to an object and it moves.

When work is performed against a frictional force on an object, the temperature of the object rises.

Force is the energy input to change the position of the object.

Given,

Tension T = 20 N

distance, d = 100 m

angle, θ = 60°

Work done = force x distance x Cos θ

Substituting the values in formula, we get

W = 20 x 100 x Cos 60

W = 2000 x 0.5

W = 1000 J

Therefore, the work done to pull the wagon 100 m at a constant speed is 1000J.

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[NOTE: THIS IS AN INCOMPLETE QUESTION. THE COMPLETE  QUESTION IS: You are pulling a child in a wagon. The rope handle is inclined upward at a 60∘ angle. The tension in the handle is 20 N. How much work does the rope do on the wagon if you pull the wagon 100 m at a constant speed?]

an electon in a box absorbs light. the longest wavelength in the absorbtion spectrum is 500 nmnm . how long is the box? for general problem-solving tips and strategies for this topic, you may want to view a video tutor solution of spectrum of dye.

Answers

The length of the box that absorbs the light is;

L =6.74 × 10^(-10) m

Given;

Longest wavelength of spectrum; λ = 500 nm = 500 × 10^(-9) m

The formula for energy of quantization is;

E = h²n²/8mL²

Also, Energy of a photon is;

E = hc/λ

Thus;

hc/λ = h²n²/8mL²

h will cancel out to give;

c/λ = hn²/8mL²

Where;

h is Planck's constant = 6.626 × 10^(-34) m².kg/s

c is speed of light = 3 × 10^(8) m/s

λ is wavelength = 500 × 10^(-9) m

L is length of box

m is mass of electron = 9.11 × 10^(-31) kg

n² is difference in energy levels = (2² - 1²) = 3

Making L the subject gives;

L = √(hn²λ/8mc)

Thus;

L = √((6.626 × 10^(-34) × 3 × 500 × 10^(-9))/(8 × 9.11 × 10^(-31) × 3 × 10^(8))

L = √(4.5458287596 × 10^(-19))

L = 6.74 × 10^(-10) m

The electron is a subatomic  particle with a bad one standard electric charge. Electrons belong to the primary technology of the lepton particle own family, and are typically thought to be fundamental particles because they have no recognized additives or substructure.

For most realistic purposes, an electron is a structureless particle with an intrinsic angular momentum, or spin. simply two numbers — the electron's mass and its electric price — gasoline the equations that describe its behaviour. From this 'sensible electron' version, physicists constructed present day microelectronics.

By using the best values for the wave-length and the scattering by matter of tough X-rays and ?-rays, the radius of the electron is anticipated as approximately 2 × 10^-10 cm.

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The correct answer is, length = 6.74 × 10⁻¹⁰ m

Data given to us;

Longest wavelength of spectrum; λ = 500 nm = 500 × 10⁻⁹ m

The formula for energy of quantization is;

E = h²n²/8mL²

Energy of the proton can be calculated by

E = hc/λ

hc/λ = h²n²/8mL²

c/λ = hn²/8mL²

Where;

h = Planck's constant = 6.626 × 10⁻³⁴ m².kg/s

c = speed of light = 3 × 10⁸ m/s

λ = wavelength = 500 × 10⁻⁹ m

L = length of box

m = mass of electron = 9.11 × 10⁻³¹ kg

n² = difference in energy levels = (2² - 1²) = 3

We can find the length easily by the above formula,

L = √(hn²λ/8mc)

L = √((6.626 × 10⁻³⁴ × 3 × 500 × 10⁻⁹)/(8 × 9.11 × 10⁻³¹× 3 × 10⁸)

L = √(4.5458287596 × 10⁻¹⁹

L = 6.74 × 10⁻¹⁰ m

Therefore, the length of the box is 6.74 × 10⁻¹⁰ m.

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a hockey puck is accelerated using a hockey stick over a smooth level ice surface the puck has a mass of 0.400kg and is moved by the stick for a distance of 0.800m what was the average forcr applied to the puck if the final speed is 25.0m/s

Answers

The average force applied to the puck of mass 0.4 kg is 156.25 N.

What is force?

Force is the product of mass and acceleration.

To calculate the average force applied to the puck, we use the formula below.

Formula:

F = mv²/2s.............................. Equation 1

Where:

F = Average forcem = Mass of the puck = 0.4 kgv = Final speed = 25 m/ss = Distance = 0.8 m

Substitute these values into equation 1

F = (0.4×25²)/(2×0.8)F = 156.25 N

Hence, the average force applied is 156.25 N.

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a 0.10 kg mass is attached to a string 0.75 m long and swings in a horizontal circle, revolving once every 0.80 s.how much tension is in the string?

Answers

The tension in the string is 4.62N

What is tension in a spring system?

When an external force operates at one of the ends of a rope or string, tension, a form of force (pulling force), emerges down the length of the string or rope. The string's tension has an opposing effect to the external force. One type of force is the tension in a rope. Therefore, the units of tension are equivalent to the units of force.As a result, the CGS unit is dyne while the SI unit of tension is Newton (N).Using the three tension force formulas mentioned above, it is simple to determine a rope's tension at mechanical equilibrium.

Given

m = 0.10

l = 0.75

t = 0.80

v = 2πr/t

tension, T = mv^2/t = 4.62 N

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Is more elastic potential energy stored in a spring when the spring is compressed by 1 cm than when it is stretched by the same amount justify your answer?

Answers

The elastic potential energy stored in a spring when the spring is compressed by 1 cm is same as the elastic potential energy stored in a spring when the spring is stretched by 1 cm.

When a spring is compressed or stretched, it will try to restore its equilibrium position by exerting a force equal and opposite to the external force.

So, the external work done by us in compression as well as stretching will store in the spring as potential energy.

It is given by the equation, PE = 1/2* k * x²

where, x is the displacement from its mean position

k is the spring constant

Thus, the potential energy of a spring will depend on the displacement of either compression or stretching. As the displacement in both the cases is same, elastic potential energy is also same.

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Unpolarized light of intensity I0 is incident on three polarizing filters. The axis of the first is vertical, that of the second is 35.0 ∘ from vertical, and that of the third is horizontal.

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Light is added in waves, and mild waves that vibrate in multiple aircraft are called unpolarized mild. Polarized mild waves, on the opposite hand, are mild waves wherein the vibrations arise in a single aircraft.

This mild travels in each vertical and horizontal directionsThe sum of the randomly orientated wave trains outcomes in a wave whose route of polarization modifications unexpectedly and randomly.

Such a wave is stated to be unpolarized. All not unusualplace reassets of mild, such as the Sun, incandescent and fluorescent lights, and flames, produce unpolarized mild.The unpolarized mild of Intensity I 0 is incident on a polarizer then a polarized mild at depth I 0 /2 comes out.Intensity of transmitted beamI t =I 0 /2cos 2 forty five from the system I=I 0 cos 2 θI t = 2I 0 × 21 = 4I 0.

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Need help asap! I’m unsure of how to do this!

Answers

The distance between the two balls of mass 0.872 kg is 0.76 m.

What is distance?

Distance is the total length between two point.

To calculate the distance between the twp balls, we use the formula below.

Formula:

r = √(GMm/F).................. Equation 1

Where:

r = Distance between the two ballsm, M = Mass of the first and second ball respectivelyF = Force of attraction between the two ballsG = Universal constant

From the question,

Given:

M = m = 0.872 kgF = 8.84×10⁻¹¹ NG = 6.673×10⁻¹¹ Nm²/kg²

Substitute these values into equation 1

r = √(0.872×0.872×6.673×10⁻¹¹/8.84×10⁻¹¹)r = √(0.574)r = 0.76 m

Hence, the distance between the two balls is 0.76 m.

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in the activator stage of physical activity you are active but participate inconsistently.

Answers

True, in the activator stage of physical activity you are active but participate inconsistently.

What is physical activity?

Physical activity is described as any voluntary bodily movement produced by skeletal muscles that requires energy expenditure which encompasses all activities, at any intensity, performed during any time of day or night.

The stages of physical activity includes :

Active exerciser- Active on a regular basis. Can overcome obstacles that may discourage others Activator- Active but participates inconsistently Planner- Has taken steps to get ready to be active, such as buying special clothing or equipmentContemplation- Not active but thinking about becoming active Precontemplation- Sedentary living; does no regular activity

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Complete question:

In the activator stage of physical activity you are active but participate inconsistently.

True or False?

How do you solve for dilation?

Answers

Answer: Scale factor = Dimension of the new shape divided Dimension of the original shape.  

Explanation:

I hope this helps

push a cart along a track so twice as much net force acts upon it. if the acceleration remains the same, what is a reasonable explanation?

Answers

It makes sense to assume further that greater net force has improved the cart's ability to transmit energy, thereby permitting it to travel with the alike speed.

This may be the result of less resistance among the cart and even the track or better track construction which enables to achieve a more seamless transmission of energy.

It makes sense to assume that the cart's mass has decreased. This implies further that carts with both the smaller mass could now experience nearly identical resultant force, and this is equivalent towards the object's mass x its speed

An explanation in detail:

1. The net pressure applied on an item is proportional to the object's mass x its speed.

2. Reducing the mass of such a cart will boost the net force pressing upon that cart.

3. When the cart's mass is decreased, relatively similar number of net force could then be applied to the carts including a lower weight.

4. Consequently, despite the cart's lower mass, identical acceleration can somehow be attained.

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An element of atomic number 88 decays radioactively to anelement of atomic number 82.Which of the following emissions achieve this result?a.one alpha particle and one beta particleb. three alpha particlesc. one alpha particled. six beta particles

Answers

Three alpha particles are lost.

The process by which unstable nuclei emit radiation and lose energy  is called radioactive decay. If a material contains an unstable core, it is considered radioactive.

There are three basic types of radioactive decay, Decay of alpha, beta and gamma. Radioactivity can be measured by counting decays per second.

Explanation:

Six protons are lost when atomic number 88 decays to atomic number 82.

The following explains whether the radioactive decay process leads to the loss of six protons.

1. One Alpha and  one beta particles: Alpha particles have two protons and beta particles have one electron. So this is not a loss of 6 protons.

2. Three alpha particles: Alpha particles have two protons. So when 3 alpha particles decay, 6 protons are lost.

3. One Alpha particle: An alpha particle has two protons, so six protons are never lost.

4. Six Beta Particles: A beta particle has 1 electron, therefore 6 protons will be gained during the decay.

Therefore, three alpha particles is correct because when three of them are lost, six protons are lost.

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