Find a best-fit linear model for the following data:xy−3196−2139−1820251−322−893−146y = −57xy = 57xy = 57x + 25y = −57x + 25
Answers
Explanation
We are given a set of x and y values in the table
To compute the best-fit model for the data, we will use the graphing calculator
From the graph above, we have the function to be
[tex]y=-57x+25[/tex]Thus, the answer is y= -57x +25
Related Questions
the chance of you having the same DNA as another person (other than an identical twin) is approximately 1 in 10 trillion (one trillion is a 1 by 12 zeros). Given the fraction,express this very small number using a negative power of 101/10,000,000,000,000
Answers
We are asked to write the quotient : 1/10,000,000,000,000 in a notation with powers of ten. This is called "scientific notation".
when we perform the division of 1 by that enormous number, we get:
0.0000000000001
This can be represented by a 10 to a negative exponent. Notice that we have 13 zeros in the denominator (which implies that we have to divide 13 times by ten)
so we can write the answer as: 1 * 10^(-13)
which with the appropriate equation editor becomes:
[tex]1\cdot10^{-13}[/tex]the base 10 with exponent -13 (negative 13)
Use the Trapezoidal Rule to approximate ∫43ln(x2+9) dx using n=3. Round your answer to the nearest hundredth.
Answers
The Trapezoidal rule formula is given to be:
[tex]\begin{gathered} \int_a^bf(x)dx\approx\frac{\triangle x}{2}(f(x_o)+2f(x_1)+2f(x_2)+2f(x_3)+...+2f(x_{n-1})+f(x_n) \\ where \\ \triangle x=\frac{b-a}{n} \end{gathered}[/tex]The question gives:
[tex]\begin{gathered} f(x)=\ln(x^2+9) \\ a=3 \\ b=4 \\ n=3 \\ \therefore \\ \triangle x=\frac{1}{3} \end{gathered}[/tex]Therefore, divide the interval into n = 3 subintervals of length 1/3 with the following endpoints:
[tex]a=3,\frac{10}{3},\frac{11}{3},4[/tex]Evaluate the function at the endpoints:
[tex]\begin{gathered} f(x_0)=f(3)=2.89 \\ 2f(x_1)=2f(\frac{10}{3})=6.00 \\ 2f(x_2)=2f(\frac{11}{3})=6.22 \\ f(x_3)=f(4)=3.22 \end{gathered}[/tex]Sum up the calculated values and multiply by Δx/2:
[tex]\Rightarrow\frac{1}{3\times2}(2.89+6.00+6.22+3.22)=3.06[/tex]Therefore, the answer will be:
[tex]\int_3^4\ln(x^2+9)dx\approx3.06[/tex]Calculate the area of the region enclosed by the x-axis and the curve y(x)=−x^2−3x+4.(show a figure and detailed answer please)
Answers
Given that the region is enclosed by the x-axis and this curve:
[tex]y=-x^2-3x+4[/tex]You can graph the function using a Graphic Tool:
Noice that the area region you must calculate is:
Notice that it goes from:
[tex]x=-4[/tex]To:
[tex]x=1[/tex]Therefore, you can set up that:
[tex]Area=\int_{-4}^1(x^2-3x+4)-(0)dx[/tex]In order to solve the Definite Integral, you need to:
- Apply these Integration Rules:
[tex]\int x^ndx=\frac{x^{n+1}}{n+1}+C[/tex][tex]\int kf(x)dx=k\int f(x)dx[/tex]Then, you get:
[tex]=(\frac{x^3}{3}-\frac{3x^2}{2}+4)|^1_{-4}[/tex]- Evaluate:
[tex]=(\frac{1^3}{3}-\frac{3(1)^2}{2}+4)-(\frac{(-4)^3}{3}-\frac{3(-4)^2}{2}+4)[/tex][tex]Area\approx64.17[/tex]Hence, the answer is:
[tex]Area\approx64.17[/tex]Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each series with the equivalent series written in sima notation.
Answers
Step 1
Given;
Step 2
[tex]3(5)^0+3(5)^1+3(5)^2+3(5)^3+3(5)^4[/tex][tex]3+15+75+375+1875[/tex][tex]\begin{gathered} 4(8)^0+4(8)^1+4(8)^2+4(8)^3+4(8)^4 \\ 4+32+256+2048+16348 \end{gathered}[/tex][tex]\begin{gathered} 2(3)^0+2(3)^1+2(3)^2+2(3)^3+2(3)^4 \\ 2+6+18+54+162 \end{gathered}[/tex][tex]\begin{gathered} 3(4)^0+3(4)^1+3(4)^2+3(4)^3+3(4)^4 \\ 3+12+48+192+768 \end{gathered}[/tex]Answer:
a backyard sandbox shaped like a right rectangular prisms is 0.45 meters high 2 m 2.6 m long if the sand is the box is 0.25 m deep what volume of sand is the box?
Answers
In order to determine the volume of the sand inside the box, take into account that the shape of the volume of the sand inside the box is the same that the rectangular prism. Then, you can use the folowing formula for the volume of the sand:
V = w·h·l
where w is the width, h the height and l the length. In this case, the height of the sand is 0.25m and the width and the length are the same of the box.
w = 2 m
l = 2.6 m
h = 0.25 m
replace the previous values of the parameters into the formula for V:
V = (2 m)(2.6 m)(0.25 m)
V = 1.3 m³
Hence, the volume of the sand inside the box is 1.3 m³
Find the 38th term 359,352,345
Answers
Let's begin by listing out the information given to us:
1st term = 359, 2nd term = 352, 3rd term = 345
[tex]\begin{gathered} 359,352,345\ldots x_n \\ x_1=359,x_2=352,x_3=345 \\ x_1-x_2=x_2-x_3\Rightarrow359-352=352-345\Rightarrow7=7 \\ 7=7 \end{gathered}[/tex]This is an Arithmetic Progression (A.P.)
[tex]\begin{gathered} x_1=359 \\ x_2=359-7(2-1)\Rightarrow359-7(1)=359-7=352 \\ x_3=359-7(3-1)\Rightarrow359-7(2)=359-14=345 \\ x_n=x_1-7(n-1) \\ n_{38}=x_1-7(38-1)=359-7(37)=359-259=100 \\ n_{38}=100 \end{gathered}[/tex]Need help solving question 34 via expanding and simplifying thanks
Answers
34. The equation is given as
[tex](x+y)^2-x(2-y)[/tex]Solving the equation by expanding and simplifying.
Use the identity,
[tex](a+b)^2=a^2+b^2+2ab[/tex][tex]x^2+y^2+2xy-2x+xy[/tex][tex]x^2+y^2-2x+3xy[/tex]Hence the answer is
[tex]x^2+y^2-2x+3xy[/tex]2? + kI - 20limI-5I - 5Solve for k to make it exist?
Answers
Answer:
k = -1
Step-by-step explanation:
The limit will exist if:
One of the roots of the equation in the numerator is 5. This happens because if this happens, we can simplify with the denominator. So
Solving a quadratic equation:
In the following format:
ax² + bx + c = 0
The solution is given by:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]In this question:
x² + kx - 20 = 0
The solution is:
[tex]x=\frac{-k\pm\sqrt[]{k^2-4\ast1\ast(-20)}}{2}=\frac{-k\pm\sqrt[]{k^2-80}}{2}[/tex]Since we want x = 5.
[tex]\frac{-k+\sqrt[]{k^2+80}}{2}=5[/tex][tex]-k+\sqrt[]{k^2-80}=10[/tex][tex]\sqrt[]{k^2+80}=10+k[/tex][tex](\sqrt[]{k^2+80})^2=(10+k)^2[/tex][tex]k^2+80=100+20k+k^2[/tex][tex]k^2+80-100-20k-k^2=0[/tex][tex]-20-20k=0[/tex][tex]20k=-20[/tex][tex]k=\frac{-20}{20}=-1[/tex]k = -1
Assume that random guesses are made for six multiple-choice questions on a test with five choices for each question so that there are n equals six trials each with the probability of success (correct) given by P equals 0.20. Find the probability of no correct answers.
Answers
Given in the question:
a.) Random guesses are made for six multiple-choice questions.
b.) There are five choices for each question.
c.) There are n equals six trials each with the probability of success (correct) given by P equals 0.20.
We will be using the Binomial Probability Formula:
[tex]P(X=k)=(_nC_k)(p^k)(1-p)^{n-k}[/tex]Where,
n = Number of trials = 6
P = Probability of success = 0.20
X = Correct answers
Let's evaluate the definition of binomial probability at k = 0 since we are tasked to find the probability of no correct answers.
[tex]P(X=0)=(_6C_0)(0.20^0)(1-0.20)^{6-0}[/tex][tex]P(X=0)\text{ = (}\frac{6!}{0!(6-0)!})(0.20^0)(0.80^6)^{}^{}[/tex][tex]P(X=0)\text{ = }0.262144\text{ }\approx\text{ 0.26}2[/tex]Therefore, the probability of no correct answers is 0.262 or 26.20%.
what is 6 5/6 as a decimal
Answers
the answer for 6 5/6
6.83
due today, i will mark as brainliest!
Answers
Step-by-step explanation:
y=2x-20 is the right answer mark brainliest
Answer:
[tex]\sf Y=2X-20[/tex]
Step-by-step explanation:
Given linear equation:
[tex]\sf X=\dfrac{1}{2}(20+Y)[/tex]
To express Y in terms of X, rearrange the equation to isolate Y.
Apply the distributive property of multiplication over addition:
[tex]\implies \sf X=\dfrac{1}{2} \cdot 20+\dfrac{1}{2} \cdot Y[/tex]
[tex]\implies \sf X=\dfrac{20}{2}+\dfrac{Y}{2}[/tex]
[tex]\implies \sf X=10+\dfrac{Y}{2}[/tex]
Subtract 10 from both sides of the equation:
[tex]\implies \sf X-10=10+\dfrac{Y}{2}-10[/tex]
[tex]\implies \sf X-10=\dfrac{Y}{2}[/tex]
Multiply both sides of the equation by 2:
[tex]\implies \sf 2(X-10)=2 \cdot \dfrac{Y}{2}[/tex]
[tex]\implies \sf 2(X-10)=Y[/tex]
[tex]\implies \sf Y=2(X-10)[/tex]
Apply the distributive property of multiplication over subtraction:
[tex]\implies \sf Y=2\cdot X- 2\cdot 10[/tex]
[tex]\implies \sf Y=2X- 20[/tex]
I would appreciate some help here, i’m bad at math
Answers
The equation of a line in the slope intercept form is expressed as
y = mx + c
where
m = slope
c = y intercept
Considering the given line,
m = - 3 and c = - 1
By substituting these values into the slope intercept equation, the equation of the line is
y = - 3x - 1
We would substitute values of x into the equation and solve for corresponding values of y. It is shown below
For x = - 2, y = - 3 * - 2 - 1 = 6 - 1 = 5
For x = - 1, y = - 3 * - 1 - 1 = 3 - 1 = 2
For x = 0, y = - 3 * 0 - 1 = 0 - 1 = - 1
For x = 1, y = - 3 * 1 - 1 = - 3 - 1 = - 4
For x = 2, y = - 3 * 2 - 1 = - 6 - 1 = - 7
We would plot the corresponding x and y values on the horizontal and vertical axes of the graph respectively. The graph is shown below
Evaluate the expression when y= -4.y²-7y+2
Answers
Put y = -4 into the expression below:
[tex]y^2-7y+2[/tex]Hence,
[tex]\begin{gathered} y^2-7y+2=(-4)^2-7(-4)+2 \\ =16+28+2 \\ =46 \end{gathered}[/tex]Therefore, the value of the expression when y = -4 is 46
Suppose f(x) = x. Find the graph of f(x + 2).graph 1, 2, 3, or 4
Answers
Do you go to the movies at least twice a week?Yes No TotalMale 35 45 80Female 67 28 95Total 102 73 175Jasmine wants to find out how manystudents at her school go to themovies at least twice a week. Sheinterviews 175 students and recordstheir gender and a yes if they go atleast twice a week and no if they goless than twice a week. She displaysthe results in the table.What is the probability that a personwho does not go to the movies atleast twice a week is male (round tothe thousandth)?
Answers
We have to determine the probability that a person who does not go to the movies at least twice a week is male.
From the table , it is given that there are total 73 students who does not go to school atleast twice a week.
Also, the number of male students whod does not go to school atleast twice a week is, 45.
Therefore, the probability that a person who does not go to the movies at least twice a week is male is determined as.
[tex]P=\frac{45}{73}[/tex][tex]P=0.61643[/tex]ANSI’s bought 3 1/2 yards of ribbon she had 2 feet 10 inches of ribbon left after trimming some curtains how many inches did she used to trim the curtains
Answers
With the help of conversion units, we know that 56 inches of ribbon was used in the curtains.
What is a conversion unit?If you want to change the units of a measured quantity without changing the value, you can do so by using a conversion factor, which is an expression representing the relationship between the units. A conversion ratio (or unit factor), if the numerator and denominator have the same value represented in various units, always equals one (1).So, inches of ribbon Ansi used in curtains:
1 yard = 36 inches
Now,
3½6+1/25/22.5Now, 2.5 yards in inches:
2.5 × 36 = 90 inchesNow, 1 foot = 12 inches.
Then, 2 feet and 10 inches:2 × 12 + 1024 + 1034 inchesInches of ribbon used:
90 - 34 = 56 inchesTherefore, with the help of conversion units, we know that 56 inches of ribbon was used in the curtains.
Know more about conversion units here:
https://brainly.com/question/97386
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Fidn the x intercept(s) and the coordinates of the vertex for the parabola y=x^2-8x+12 if there is more then one x intercept esperate them with commas!
Answers
To calculate the x-intercepts we replace y=0 and solve for x
[tex]x^2-8x+12=0[/tex]where a is 1, b is -8 and c 12
so factor the expression using
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]replacing
[tex]\begin{gathered} x=\frac{-(-8)\pm\sqrt[]{(-8)^2-4(1)(12)^{}}}{2(1)} \\ \\ x=\frac{8\pm\sqrt[]{64-48}}{2} \\ \\ x=\frac{8\pm\sqrt[]{16}}{2} \\ \\ x=\frac{8\pm4}{2} \\ \\ x=4\pm2 \end{gathered}[/tex]so x have two solutions because there are two x-intercepts
[tex]\begin{gathered} x_1=4+2=6 \\ x_2=4-2=2 \end{gathered}[/tex]then the x-intercepts are 6 and 2, the corrdinates are
[tex]\begin{gathered} (6,0) \\ (2,0) \end{gathered}[/tex]Vertex
the vertex is a point (x,y) to calculate x we use
[tex]x=\frac{-b}{2a}[/tex]and replace
[tex]\begin{gathered} x=\frac{-(-8)}{2(1)} \\ \\ x=\frac{8}{2}=4 \end{gathered}[/tex]now replace x=4 on the equation of the parable to find y
[tex]\begin{gathered} y=x^2-8x+12 \\ y=(4)^2-8(4)+12 \\ y=16-32+12 \\ y=-4 \end{gathered}[/tex]the coordinate of the vertex is
[tex](4,-4)[/tex]slove for y(13x-27)(9y + 19)(10x+6)
Answers
To obtain the value of y, we need to obtain the value of x first
Step 1: Finding x
(13x - 27) and (10x + 6) are equal (Alternate exterior angles)
so we can equate both angles
13x - 27 = 10x + 6
13x - 10x = 27 + 6
3x = 33
Divide both sides by 3
x = 33/ 3
x = 11
Step 2: Finding y
(9y + 19) and (10x + 6) are supplementary, hence they add up to 180
9y + 19 + 10x + 6 = 180
9y + 10x + 19 + 6 = 180
9y + 10x + 25 = 180
9y + 10x = 180 - 25
9y + 10x = 155
9y = 155 - 10x
substitute the value of x = 11 from step 1 into the equation
9y = 155 - 10 x 11
9y = 155 - 110
9y = 45
divide both sides by 9
y = 45/9
y = 5
I don’t know if it’s maximum value or minimum value and the answer too
Answers
Answer:
The minimum value is 0
Step-by-step explanation:
If there is a negative sign in front of the x^2 it is always a maximum (-x^2 goes downwards)
If the x^2 is positive it always a minimum.
You have the correct ordered pair, the minimum value is equal to the y value.
The box plots represent the length of 100 randomly sampled commercial breaks for two different television stations Length of Commercial Breaks Channel 1 Channel 2 20 40 60 140 160 80 100 120 Time (seconds) Which statement about the difference in the medians of the two data sets is true?
Answers
Given data:
The length of the first commercial break is,
[tex]\begin{gathered} C_1=(120-90) \\ =30 \end{gathered}[/tex]The length of the second commercial break is,
[tex]\begin{gathered} C_2=(90-50) \\ =40 \end{gathered}[/tex]The expression for the diffrence compared to the first channel is,
1 1 2. Consider 2 divided by 2 (a) Write a real-world problem for the division. (b) Create a model or write an equation for the division. (C) Find the quotient for the real-world problem in part (a). Show your work or explain your reasoning. Answer:
Answers
We will have the following:
a) His parents spent:
[tex]2.49\cdot6=14.94[/tex]So they spent $19.94.
b) They will spent the following in rental:
[tex]\frac{150}{8}=18.75[/tex]So, the hourly rate $18.75.
c) We will determine the amount spent:
[tex]182.53-150-14.49=18.04[/tex]So, it would be $18.04.
J is the midpoint of HK . What are HJ, JK, and HK?
Answers
HJ=25
JK=25
HK=50
Explanation
Step 1
J is the midpoint, it means
[tex]HJ=JK[/tex]Step 2
replace andsolve for x
[tex]\begin{gathered} HJ=JK \\ 9x-2=4x+13 \\ \text{subtract 4x in both sides} \\ 9x-2-4x=4x+13-4x \\ 5x-2=13 \\ add\text{ 2 in both sides} \\ 5x-2+2=13+2 \\ 5x=15 \\ divide\text{ both sides by 5} \\ \frac{5x}{5}=\frac{15}{5} \\ x=3 \\ \end{gathered}[/tex]Step 3
finally replace the valure of X to find HJ and JK
[tex]\begin{gathered} HJ=JK=9x-2=9\cdot3-2=27-2=25 \\ HJ=25 \\ JK=25 \\ then \\ HK=HJ+JK=25+25 \\ \\ HK=50 \end{gathered}[/tex]I hope this helps you
my question:solve the equation or inequality.5t - 3 (7t + 1) < 93would the answer be 7 > -6?
Answers
Answer:
Explanation:
To solve the inequality for t, we first expand the left-hand side to get:
[tex]5t-21t-3<93[/tex]adding the like terms gives
[tex]-16t-3<93[/tex]adding 3 to both sides gives
[tex]-16t<96[/tex]At this point, we have to remember that dividing or multiplying an inequality by a negative number reverses its sign. So when we divide our inequality by -16, the inequality reverses sign and we get:
[tex]t>-\frac{96}{16}[/tex][tex]\boxed{\therefore t>-6.}[/tex]which is our answer!
which statement best describes the changes to the graph when the coefficient of x^2 is multiplied by 1/2?A. the parabola will get narrower.B. the parabola will get wider.C. the parabola will shift to the right by 1/2 unit.D. the parabola will shift to the left by 1/2 unit.
Answers
B. The parabola will get wider
Explanatiion:The graph for the function x² is shown in the question
The graph x² is multiplied by 1/2. The new function becomes 1/2 x²
Let us plot the graph of 1/2 x² to compare with the graph of x² that has already been given
The graph of 1/2 x² is plotted above
As shown, it is obvious from the graphs of 1/2 x² and x² that the graph of 1/2 x² is wider than the graph of x²
Your sock drawer has 4 pairs of pink socks, 2 pairs of white socks, and 7 pairs of black socks. What is the probability that if you choose at random withough replacement you will not choose black socks 2 days in a row? a 1/12b 2/13c 3/8d 5/26
Answers
SOLUTION:
Case: Probability
Method:
To select socks that are not black without replacement,
Since there are a total of 6 pairs that are not black (NB)
[tex]\begin{gathered} Pr(NB) \\ =\frac{6}{13}\times\frac{5}{12} \\ =\frac{5}{26} \end{gathered}[/tex]Final answer:
5/26
Students in a science class recorded lengths of a stretched spring as shown in the table. Find the rate of change and explain what it means for this situation.
Answers
To find the rate of change;
Rate of change = change in y / change in x
= 10-0/ 2-0
=10/2
=5/1
=5
This means that the increase in w
Marc se come un sándwich de huevo para el desayuno y una hamburguesa grande para el almuerzo todos los días.
El sándwich de huevo tiene 250 calorías. Si Marc come 5,250 calorías en el desayuno y almuerzo en toda la
semana en total, ¿cuántas calorías tiene una hamburguesa grande?
lón de juegos la primera vez ella ganó 60 boletos. La segunda vez,
Answers
Answer:Hay 500 calorías en una Big Burger.
Step-by-step explanation:
En una semana (7 días), Mark come 7 sándwiches de huevo, que son 1750 calorías. Reste la cantidad total de calorías que consumió por la cantidad de calorías consumidas a través de sándwiches de huevo; 5250-1750=3500. 3500 es el número total de calorías que Mark consumió al comer una Big Burger todos los días durante 7 días. Divide 3500 entre 7 = 500. Hay 500 calorías en una Big Burger.
16. – 2y+5=-1IIs 3 the solution?
Answers
We plug the value given to see tif the equation holds:
[tex]\begin{gathered} -2(3)+5=-1 \\ -6+5=-1 \\ -1=-1 \end{gathered}[/tex]Since the equation holds then, 3 IS the solution.
USH financial is a small bank that is examining it’s customers use of its website. The numbers of online transactions made per day during the past 8 days are as follows.
Answers
Given:
The number of online transaction made per day during tha past 8 days are given as follows
51, 57, 71, 57, 55, 62, 51, 65
Find:
we have to find Mean, Median and mode of the given data.
Explanation:
(a)Mean
Mean of the given data is
[tex]\begin{gathered} Mean=\frac{51+57+71+57+55+62+51+65}{8} \\ Mean=58.6 \end{gathered}[/tex]Therefore, Mean is 58.6
(b) Median
Write the given data values in ascending order as following
51
51
55
57 Now n = 8
57 n/2 = 4
62 Median = Average of 4th and 5th items
65 Median = (57 + 57)/2 = 57
71
Therefore, Median is 57
(c)Mode
We know, the Mode is the value or values that occur most frequently.
Since 51 occurs 2 times and 57 also occurs 2 times.
Therefore, there are two modes, which are 51 and 57
Which is the better deal? Cheerios12 oz. for $ 1.9936 oz. for $2.5948 oz. for $3.9960 oz. $4.59
Answers
To calculate which is the best deal we must standardize all prices and compare them.
To do this we will divide the value by the number of ounces they have and thus choose the best one.
1.
[tex]\frac{1.99}{12}=0.165[/tex]2.
[tex]\frac{2.59}{36}=0.071[/tex]3.
[tex]\frac{3.99}{48}=0.083[/tex]4.
[tex]\frac{4.59}{60}=0.076[/tex]The price list by ounces would be as follows.
0.165
0.071
0.083
0.076
Best deal is number 2 0.071