Answer: a lot of 5
Step-by-step explanation:
yes
Answer:
Rewrite in vertex form and use this form to find the vertex (h,k)(h,k).(12,−254)
Step-by-step explanation:
Hope this helps ;)
Which of the following functions have the ordered pair (2, 5) as a solution?4 + x = yy = 2 x7 - x = yx + 3 = y
Given
The ordered pair (2,5).
To find which of the functions have the ordered pair as a solution.
Explanation:
It is given that,
The ordered pair (2,5).
Then, put x=2, and y=5 in the function x+3=y.
That implies,
[tex]\begin{gathered} 2+3=5 \\ 5=5 \end{gathered}[/tex]Hence, the ordered pair (2,5) is a solution of the function x+3=y.
Also, substitute x=2, y=5 in the function 7-x=y.
That implies,
[tex]\begin{gathered} 7-2=5 \\ 5=5 \end{gathered}[/tex]Hence, the ordered pair (2,5) is a solution of the function 7-x=y.
what is 3(x+5) 12 please help I’ve been stuck on it
Given data:
The given inequality is 3(x+5) >12.
The given inequality can be written as,
[tex]\begin{gathered} 3\mleft(x+5\mright)>12 \\ 3x+15>12 \\ 3x>-3 \\ x>-1 \\ x\in(-1,\text{ }\infty) \end{gathered}[/tex]The graph of the above solution is,
Thus, the solution of the given inequality is (-1, ∞).
What is the horizontal and vertical shift for the absolute value function below?f(x) =|x-5|+1The graph shifts right 5 and up 1.The graph shifts left 5 and up 1.The graph shifts left 5 and down 1.The graph shifts right 5 and down 1.
The correct answer is option A;
The graph shifts right 5 and up 1
14. What is the volume of a box with these dimensions? 4 cm 5 cm 10 cm.
The volume of a rectangular prism is given by the product of its three dimensions.
Since the box dimensions are 4 cm, 5 cm and 10 cm, its volume is:
[tex]\begin{gathered} V=4\cdot5\cdot10 \\ V=200\text{ cm}^3 \end{gathered}[/tex]So the volume of the box is equal to 200 cm³.
factoring quadratics h^2+12h+11
Multiply.
7.
-2 7
-5 -6
Español
Write your answer in simplest form solve this
The simplest form of 7 × (-2/-5) × (7/-6) is - 49/15.
Multiplication of fractions:A whole number or another fraction is produced when one fraction is multiplied by another fraction. We all know that a fraction has two components: a numerator and a denominator. In order to multiply any two fractions, we must multiply the numerators and denominators, respectively.
Here we have
=> [tex]7. \frac{-2}{-5} .\frac{7}{-6}[/tex]
Can be multiplied as given below
=> [tex]7 \times\frac{-2}{-5} \times\frac{7}{-6}[/tex]
=> [tex]7 \times\frac{1}{5} \times\frac{7}{-3}[/tex]
=> [tex]-\frac{49}{15}[/tex]
Therefore,
The simplest form of 7 × (-2/-5) × (7/-6) = -49/15
Learn more about Fractions at
https://brainly.com/question/1050042
#SPJ1
The standard form of the equation of a parabola isy=x²-4x+21. What is the vertex form of the equation?O A. y = ¹/(x-4)² +13OB. y=(x-4)² +21C. y = 1/(x+4)² +1+13O D. y = 1/(x+4)² +21
Answer:
[tex]y=\frac{1}{2}(x-4)^2+13\text{ }\operatorname{\Rightarrow}(A)[/tex]Explanation: We have to find the vertex form of the parabola equation from the given standard form of it:
[tex]y=\frac{1}{2}x^2-4x+21\rightarrow(1)[/tex]The general form of the vertex parabola equation is as follows:
[tex]\begin{gathered} y=A(x-h)^2+k\rightarrow(2) \\ \\ \text{ Where:} \\ \\ (h,k)\rightarrow(x,y)\Rightarrow\text{ The Vertex} \end{gathered}[/tex]Comparing the equation (2) with the original equation (1) by looking at the graph of (1) gives the following:
[tex](h,k)=(x,y)=(-4,13)[/tex]
Therefore the vertex form of the equation is as follows:
[tex]y=\frac{1}{2}(x-4)^2+13\Rightarrow(A)[/tex]Therefore the answer is Option(A).
80 students scores recorded 68 84 75 82 68 90 62 88 76 93 73 88 73 58 93 71 59 58 5161 65 75 87 74 62 95 78 63 72 66 96 79 65 74 77 95 85 78 8671 78 78 62 80 67 69 83 76 62 71 75 82 89 67 58 73 74 73 6581 76 72 75 92 97 57 63 83 81 82 53 85 94 52 78 88 77 71mean exam score
Solution
We have the following values:
68,84,75,82,68,90,62,88,76,93,73,79,88,73,58,93,71,59,
58,51,61,65,75,87,74,62,95,78,63,72,66,96,79,65,74,77,95,
85,78,86,71,78,78,62,80,67,69,83,76,62,71,75,82,89,67,58,
73,74,73,65,81,76,72,75,92,97,57,63,68,83,81,82,53,85,94,
52,78,88,77,71
Part a
Range = Max- Min= 97-51= 46
Part b
The mean is given by:
[tex]\text{Mean}=\frac{\sum ^n_{i\mathop=1}x_i}{n}=75[/tex]Part c
The median is given by:
Position 40 ordered= 75 and Position 41 ordered= 75
Then the median is:
[tex]\text{Median}=\frac{75+75}{2}=75[/tex]Part d
The most is the most frequent value and for this case is:
Repeated 5 times
Mode = 78
Part e
The data within the interval 50-54 is:
51 52 53
The variance is given by:
[tex]s^2=\frac{\sum ^n_{i\mathop=1}(x_i-Mean)^2}{n-1}=1[/tex]And the deviation si:
[tex]s=\sqrt[]{1}=1[/tex]
what is an equation of the line that passes through the point (-2,-3) and is parallel to the line x+3y=24
Solve first for the slope intercept form for the equation x + 3y = 24.
[tex]\begin{gathered} \text{The slope intercept form is }y=mx+b \\ \text{Convert }x+3y=24\text{ to slope intercept form} \\ x+3y=24 \\ 3y=-x+24 \\ \frac{3y}{3}=\frac{-x}{3}+\frac{24}{3} \\ y=-\frac{1}{3}x+8 \\ \\ \text{In the slope intercept form }y=mx+b,\text{ m is the slope. Therefore, the slope of} \\ y=-\frac{1}{3}x+8,\text{ is }-\frac{1}{3}\text{ or } \\ m=-\frac{1}{3} \end{gathered}[/tex]Since they are parallel, then they should have the same slope m. We now solve for b using the point (-2,-3)
[tex]\begin{gathered} (-2,-3)\rightarrow(x,y) \\ \text{Therefore} \\ x=-2 \\ y=-3 \\ \text{and as solved earlier, }m=-\frac{1}{3} \\ \\ \text{Substitute the values to the slope intercept form} \\ y=mx+b \\ -3=(-\frac{1}{3})(-2)+b \\ -3=\frac{2}{3}+b \\ -3-\frac{2}{3}=b \\ \frac{-9-2}{3}=b \\ b=-\frac{11}{3} \end{gathered}[/tex]After solving for b, complete the equation.
[tex]y=-\frac{1}{3}x-\frac{11}{3}\text{ (final answer)}[/tex]2x + 2/3y= -2 x, y intercept
We need to find the points at which the expression below intercept the axis of the coordinate plane:
[tex]2x+\frac{2}{3}y=-2[/tex]To find the "x" intercept we need to find the value of "x" that results in a value of "y" equal to 0. We have:
[tex]\begin{gathered} 2x+\frac{2}{3}\cdot0=-2 \\ 2x+0=-2 \\ 2x=-2 \\ x=\frac{-2}{2}=-1 \end{gathered}[/tex]To find the "y" intercept we need to find which value of "y" the function outputs when we make x equal to 0.
[tex]\begin{gathered} 2\cdot0+\frac{2}{3}y=-2 \\ \frac{2}{3}y=-2 \\ 2y=-6 \\ y=\frac{-6}{2}=-3 \end{gathered}[/tex]The x intercept is -1 and the y intercept is -3.
Net force = ?Net force = ?16 NThe net force for example A isNAThe net force for example B is NA
Part A
The net force is 4 N up
Part B
The net force is 3 N to the left
Nimol talks on the phone [tex]3 \frac{1}{2} [/tex] more than his brother. His parents scolded him and asked him to cut down on phone calls.He reduced[tex] \frac{2}{5} [/tex] of the time he used to. How long did his brother spend talking on the Phone.
His brother spent talking on the phone
Step - by - Step Explanation
What to find?
Time Nimol's brother spent talking on phone.
Let x be the time Nimol spent in talking on phone.
Let y be the time Nimol's brother spent talking on phone.
x = y + 3 1/2
x =2/5 ( y + 3 1/2)
A team digs 12 holes every 20 hours, what is the unit rate?
The unit rate = 0.6 holes per hour
Explanation:Number of holes dug by the team = 12
Total time taken = 20 hours
The unit rate = (Number of holes) / (Time)
The unit rate = 12/20
The unit rate = 0.6 holes per hour
If y=kx, where k is a constant, and y=24 when x=6, what is the value of y when x=5?A. 6B. 15C. 20D. 23
First, we will find the value of k
We can do this by sybstituting y=24, x=6 in;
y=kx and then solve for k
24= k(6)
divide both-side of the equation by 6
24/6 = k
4 = k
k=4
Then when x = 5, we will substitute x=5 and k=4 in; y=kx and then solve for y
y= (4)(5)
y = 20
verizon charges $200 to start up a cell phone plan. then there is a $50 charge each month. what is the total cost (start up fee and monthly charge) to use the cel phone plan for 1 month?
write the total costs a linear function in the form
[tex]y=mx+b[/tex]in which:
y= total cost
x= number of months
m= charge per month
b= fixed start up fee
replace all data in the equation
[tex]\begin{gathered} y=50\cdot x+200 \\ y=50x+200 \end{gathered}[/tex]Since the question is the cost for 1 month, x=1
[tex]\begin{gathered} y=50(1)+200 \\ y=250 \end{gathered}[/tex]The cost for the use of the cellphone is $250
Find cosθ, cotθ, and secθ, where θ is the angle shown in the figure. Give exact values, not decimal approximations.cosθ=cotθ=secθ=
First let's find the missing value of the hypotenuse:
[tex]\begin{gathered} c^2=a^2+b^2 \\ a=4 \\ b=5 \\ \Rightarrow c^2=(4)^2+(5)^2=16+25=41 \\ \Rightarrow c=\sqrt[]{41} \\ \end{gathered}[/tex]we have that the hypotenuse equals sqrt(41). Now we can find the values of the trigonometric functions:
[tex]\begin{gathered} \cos (\theta)=\frac{adjacent\text{ side}}{hypotenuse} \\ \Rightarrow\cos (\theta)=\frac{4}{\sqrt[]{41}} \\ \sec (\theta)=\frac{1}{\cos (\theta)} \\ \Rightarrow\sec (\theta)=\frac{1}{\frac{4}{\sqrt[]{41}}}=\frac{\sqrt[]{41}}{4} \\ \tan (\theta)=\frac{opposite\text{ side}}{adjacent\text{ side}} \\ \Rightarrow\tan (\theta)=\frac{5}{4} \\ \cot (\theta)=\frac{1}{\tan (\theta)} \\ \Rightarrow\cot (\theta)=\frac{1}{\frac{5}{4}}=\frac{4}{5} \end{gathered}[/tex]The circle below has center S. Suppose that m QR = 84°. Find the following.
Given:
[tex]\text{m}\hat{\text{QR}}=84^{\circ}[/tex]b) To find:
[tex]\angle QSR[/tex]We know that,
[tex]\hat{QR}=\angle QSR=84^{\circ}[/tex]Thus, the answer is,
[tex]\angle QSR=84^{\circ}[/tex]a) To find:
[tex]\angle QPR[/tex]We know that,
[tex]\begin{gathered} \angle QPR=\frac{1}{2}\angle QSR \\ \angle QPR=\frac{1}{2}(84^{\circ}) \\ \angle QPR=42^{\circ} \end{gathered}[/tex]Thus, the answer is,
[tex]\angle QPR=42^{\circ}[/tex]I am having a tough time solving this problem from my prep guide, can you explain it to me step by step?
The range in the average rate of change in temperature of the substance is from a low temperature of -[tex]22^{0}[/tex]F to a high of [tex]16^{0}[/tex]F
The domain of the function f(x) = sin x includes all real numbers, but its range is −1 ≤ sin x ≤ 1. The sine function has different values depending on whether the angle is measured in degrees or radians. The function has a periodicity of 360 degrees or 2π radians.
Given f(x) = -19sin(7/3x + 1/6) – 3
We have to the range in the average rate of change in temperature of the substance is from a low temperature of ___F to a high of ___F
We know that the range of sin x is [-1, 1]
f(x) = -19 sin(7/3x + 1/6) – 3
We know
-1 ≤ sin(7/3x + 1/6) ≤ 1
Now multiply with -19 on both sides
19 ≥ -19sin(7/3x + 1/6) ≤ -19
-19 ≤ -19sin(7/3x + 1/6) ≤ 19
Now subtract 3 from both sides
-19 - 3 ≤ -19sin(7/3x + 1/6) - 3 ≤ 19 - 3
-22 ≤ -19sin(7/3x + 1/6) ≤ 16
-22 ≤ f(x) ≤ 16
Therefore the range in the average rate of change in temperature of the substance is from a low temperature of -220F to a high of 160F
To learn more about the range of sinx functions visit
https://brainly.com/question/18452384
#SPJ9
Anthony has already taken 1 quiz during past quarters, and he expects to have 5 quizzes during each week of this quarter. How many weeks of school will Anthony have to attend this quarter before he w have taken a total of 31 quizzes?
The first step to solve the problem is to create a function that relates the number of quizzes he attends by the number of weeks that elapses. Since he alread took one quizz, then the function must start from that and must grow at a rate of 5 quizzes per week. We have:
[tex]\text{quizzes(w)}=5\cdot w+1[/tex]We want to know how many weeks until he takes 31 quizzes, then we need to make the expression equal to 31 and solve for the value of w. We have:
[tex]\begin{gathered} 5\cdot w+1=31 \\ \end{gathered}[/tex]Then we subtract both sides by 1.
[tex]\begin{gathered} 5\cdot w+1-1=31-1 \\ 5\cdot w=30 \end{gathered}[/tex]Then we divide both sides by 5.
[tex]\begin{gathered} \frac{5\cdot w}{5}=\frac{30}{5} \\ w=6 \end{gathered}[/tex]It'll take 6 weekes before he have taken a total of 31 quizzes.
Graph the linear function using the slope and the y-intercept.y = 2x + 3CORTUse the graphing tool to graph the linear equatium. Use the slope and y-intercept when drawing the line.Click toenlargegraph
Answer:
Explanation:
If we have a linear equation of the form
[tex]y=mx+b[/tex]then m = slope and b = y-intercept.
Now in our case, we have
[tex]y=2x+3[/tex]which means that slope = 2 and y-intercept = 3
Therefore, we graph a line that has a slope of 2 and a y-intercept of 3.
A slope of 2 means that for every step you take to the right on a graph, you move 2 steps up to get to a point on the line.
The y-intercept of 3 means that the line passes through the point (0, 3).
Using these two facts about the line, we draw the following line.
From the above plot, we can clearly see that the line has a slope of 2 and a y-intercept of 3 - the same line described by y = 2x + 3.
The sum of three numbers is 106. The second number is 2 times the third. The first number is 6 more than the third. What are the numbers?First numberSecond number Third number
Let's call the numbers a, b and c.
The first statement tells us that the sum of the three numbers is 106, so:
[tex]a+b+c=106.[/tex]The second statement tells us that the second number is two times the third so:
[tex]b=2c\text{.}[/tex]The final statement tells us that the first number is 6 more than the third, so:
[tex]a=c+6.[/tex]This gives us a system of three equations with three variables. Let's take the value of a given by the third equation, use it in the first one and isolate another variable:
[tex](c+6)+b+c=106,[/tex][tex]2c+b+6=106,[/tex][tex]2c+b=100,[/tex][tex]b=100-2c\text{.}[/tex]Let's take this value of b and use it in the second equation:
[tex]100-2c=2c,[/tex][tex]100=4c,[/tex][tex]c=25.[/tex]Now we know the exact value of c, so let's go back to the third equation:
[tex]a=25+6=31,[/tex]and now we also know the exact value of a, so let's go back to the second equation:
[tex]b=2(25)=50.[/tex]So, the first number (a) is 31, the second (b) is 50 and the third (c) is 25.
31+50+25=106.
Identify any congruent figures in the coordinate plane. Explain. This is a fill in the blank question based off of the options that are listed down below!
Solution
For this case we can conclude the following:
triangle HJK ≅ triangle QRS because one is rotation of 90º about the origin of the other
Rectangle DEFG ≅ rectangle MNLP because one is a translation of the other
triangle ABC ≅ no given figure because one is not related by rigid motions of the other
A surveyor wants to find the height of a tower used to transmit cellular phone calls. He stands 125 feet away from the tower and meandered the angle of elevation to be 40 degrees. How tall is the tower?
Given
Answer
[tex]\begin{gathered} \tan 40=\frac{h}{125} \\ 0,84\times125=h \\ h=105\text{ ft} \end{gathered}[/tex]height of tower is 105 ft
Can someone please help me solve #6 on this packet?
The distance between the two camper stations are 60.44 km and 62.95 km. as calculated using the law of sines.
Let us consider the the first ranger station is A and the second ranger station is C and the camper is at the position B.
It is given that AC = 10 km
∠BAC = 100°
∠BCA = 71°
∴∠ABC = 180 - (100 + 71) = 9
Now we will use this to find the distance between each ranger station and the camper by using the law of sines.
From the law of sines we know that :
[tex]{\displaystyle {\frac {a}{\sin {\alpha }}}\,=\,{\frac {b}{\sin {\beta }}}\,=\,{\frac {c}{\sin {\gamma }}}\,}[/tex]
Now we will use this ratio to calculate the other sides of the triangle.
10 / sin 9 = BC / sin 100
or, BC = 10 × sin 100 / sin 9
or, BC = 62.95 km
Again:
10 / sin 9 = AB / sin 71
or. AB = 60.44 km
Therefore the distance between the two camper stations are 60.44 km and 62.95 km.
To learn more about law of sines visit:
https://brainly.com/question/17289163
#SPJ9
If twice the age of a stamp is added to the age of a coin, the result is 45. The difference between three times the age of a stamp and the age of a coin is 5. What is the age of the stamp?
10 years
1) Considering that we can call the age of a stamp by "s" and the age of a coin by "c" we can write out the following system of Linear Equations:
[tex]\begin{gathered} 2s+c=45 \\ 3s-c=5 \end{gathered}[/tex]Note that we can solve it using the Elimination Method.
2) So let's add simultaneously both equations:
[tex]\begin{gathered} 2s+c=45 \\ 3s-c=5 \\ -------- \\ 5s=50 \\ \frac{5s}{5}=\frac{50}{5} \\ s=10 \end{gathered}[/tex]We can plug into that s=10 and find the age of a coin as well:
[tex]\begin{gathered} 2(10)+c=45 \\ c=45-20 \\ c=20 \end{gathered}[/tex]Note that we subtracted 20 from both sides.
3) Hence, the age of a stamp is 10 years
The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is nine times the measure of the first angle. The third angle is 26 more than the second let x,y, and z represent the measures of the first second and third angles, find the measures of the three angles
Answer:
x = 18, y = 68, z = 94.---------------------------------
Set equations as per given details.The sum of the measures of the angles of a triangle is 180:
x + y + z = 180 (1)The sum of the measures of the second and third angles is nine times the measure of the first angle:
y + z = 9x (2)The third angle is 26 more than the second:
z = y + 26 (3)SolutionSubstitute the second equation into first:
x + y + z = 180,y + z = 9x.Solve for x:
x + 9x = 180,10x = 180,x = 18.Substitute the value of x into second and solve for y:
y + z = 9x,y + z = 9*18,y + z = 162,y = 162 - z.Solve the third equation for y:
z = y + 26,y = z - 26.Compare the last two equations and find the value of z:
162 - z = z - 26,z + z = 162 + 26,2z = 188,z = 94.Find the value of y:
y = 94 - 26,y = 68.Answer:
x = 18°
y = 68°
z = 94°
Step-by-step explanation:
Define the variables:
Let x represent the first angle.Let y represent the second angle.Let z represent the third angle.Given information:
The sum of the measures of the angles of a triangle is 180°. The sum of the measures of the second and third angles is nine times the measure of the first angle. The third angle is 26 more than the second.Create three equations from the given information:
[tex]\begin{cases}x+y+z=180\\\;\;\;\;\;\:\: y+z=9x\\\;\;\;\;\;\;\;\;\;\;\;\;\: z=26+y\end{cases}[/tex]
Substitute the third equation into the second equation and solve for x:
[tex]\implies y+(26+y)=9x[/tex]
[tex]\implies 2y+26=9x[/tex]
[tex]\implies x=\dfrac{2y+26}{9}[/tex]
Substitute the expression for x and the third equation into the first equation and solve for y:
[tex]\implies \dfrac{2y+26}{9}+y+26+y=180[/tex]
[tex]\implies \dfrac{2y+26}{9}+2y=154[/tex]
[tex]\implies \dfrac{2y+26}{9}+\dfrac{18y}{9}=154[/tex]
[tex]\implies \dfrac{2y+26+18y}{9}=154[/tex]
[tex]\implies \dfrac{20y+26}{9}=154[/tex]
[tex]\implies 20y+26=1386[/tex]
[tex]\implies 20y=1360[/tex]
[tex]\implies y=68[/tex]
Substitute the found value of y into the third equation and solve for z:
[tex]\implies z=26+68[/tex]
[tex]\implies z=94[/tex]
Substitute the found values of y and z into the first equation and solve for x:
[tex]\implies x+68+94=180[/tex]
[tex]\implies x=18[/tex]
Solve the following system of equations using the elimination method. Note that the method of elimination may be referred to as the addition method. (If there is no solution, enter NO SOLUTION. If there are infinitely many solutions, enter INFINITELY MANY.)20x − 5y = 208x − 2y = 8(x, y) =
Given
The system of equations,
20x − 5y = 20
8x − 2y = 8
To find: The solution.
Explanation:
It is given that,
20x − 5y = 20 _____(1)
8x − 2y = 8 _____(2)
That implies,
Divide (1) by 5 and (2) by 2.
Then, (1) and (2) becomes,
4x - y = 4.
Hence, there is infinitely many solution.
PerioAlgebra 2NameUsing Linear Equations to Solve Problems Date1) The chess club is selling popcorn balls for $1.00 and jumbo candy bars for$1.50 each. This week they have made a total of $229 and have sold 79popcorn balls. How many candy bars have they also sold?
The popcorn balls cost $1.00 each
Jumbo candy bars cost $1.50 each
This week they have made a total of $229 and have sold 79
popcorn balls.
First, let's make a function with includes this information.
Let's say that popcorn balls are x and Jumbo candy bars are y.
So the function would be
1.00x+ 1.50y = 229
We already have the x value which represents the total of popcorn balls sold this week, so replace this value in the function:
1.00x+ 1.50y = 229
1.00(79)+ 1.50y = 229
79.00 + 1.50y = 229
Solve the equation for y to find the total of candy bars sold.
79 + 1.50y = 229
1.50y = 229 - 79
1.50y = 150
y = 150/1.50
y = 100
So the have sold 100 candy bars this week
What are the coordinates of point B on AC such that the ratio of AB to BC is 5 : 6
We have a segment AC, with the point B lying between A and C.
The ratio AB to BC is 5:6.
The coordinates for A and C are:
A=(2,-6)
C=(-4,2)
We can calculate the coordinates of B for each axis, using the ratio of 5:6.
[tex]\begin{gathered} \frac{x_a-x_b}{x_b-x_c}=\frac{2-x_b}{x_b+4}=\frac{5}{6}_{} \\ 6\cdot(2-x_b)=5\cdot(x_b+4) \\ 12-6x_b=5x_b+20 \\ -6x_b-5x_b=20-12_{} \\ -11x_b=8 \\ x_b=-\frac{8}{11}\approx-0.72\ldots \end{gathered}[/tex]We can do the same for the y-coordinates:
[tex]\begin{gathered} \frac{y_a-y_b}{y_b-y_c}=\frac{-6-y_b}{y_b-2}=\frac{5}{6} \\ 6(-6-y_b)=5(y_b-2) \\ -36-6y_b=5y_b-10 \\ -6y_b-5y_b=-10+36 \\ -11y_b=26 \\ y_b=-\frac{26}{11}\approx-2.36\ldots \end{gathered}[/tex]The coordinates of B are (-8/11, -26/11).
i really need help writting the slope intercept form
Equation in slope intercept form is written as
y = mx + b
If slope m = 1/3 and y-intecept b = 3
Equation form using the information above is
[tex]y\text{ =}\frac{1}{3}x\text{ + 3}[/tex]Point slope form using the point (3, 4)
simply use the formula
y - y₁ = m( x- x₁ )
[tex]y\text{ -4=}\frac{1}{3}(x-3)[/tex]