expand the given number to decimal for by expanding in powers and by using the calculator short cut. 82104nine in powers, write the calculator shortcut extension for 82104nine, convert 82104nine to decimal form.

Expand The Given Number To Decimal For By Expanding In Powers And By Using The Calculator Short Cut.

Answers

Answer 1

We have a number expressed in a base of 9, instead of the most common decimal base.

Then, is we have the number 82104 in 9-base, it means that we can expand it as:

[tex]82104_{\text{nine}}=8\cdot9^4+2\cdot9^3+1\cdot9^2+0\cdot9^1+4\cdot9^0[/tex]

We then can expand this as:

[tex]82104_{\text{nine}}=8\cdot6561+2\cdot729+1\cdot81+0\cdot9^{}+4\cdot1[/tex]

We can finally calculate what this number is in decimal form by finishing simplyfing the expression above:

[tex]\begin{gathered} 82104_{\text{nine}}=8\cdot6561+2\cdot729+1\cdot81+0\cdot9^{}+4\cdot1 \\ 82104_{\text{nine}}=52488+1458+81+4 \\ 82104_{\text{nine}}=54031 \end{gathered}[/tex]

Answer:

If we decompose this number given the base 9, we get the following terms:

[tex]82104_{\text{nine}}=8\cdot9^4+2\cdot9^3+1\cdot9^2+0\cdot9^1+4\cdot9^0[/tex]

The decimal form of 82104(nine) is 54031.


Related Questions

Find the area of the shaded region.3112Note: Use either the pi button on your calculator or 3.14 for pi. Round to the nearest tenth.

Answers

The area of a sector of a circle can be calculated by using the formula:

[tex]A=\frac{\theta}{360}\cdot\pi\cdot r^2\text{ where }\theta\text{ is the angle in degrees and r is the radius}[/tex]

The total area of a circle can be calculated as:

[tex]A_{total}=\pi\cdot r^2\text{ where r is the radius}[/tex]

To find the area of the shaded region, you need to calculate the total area of the circle and then subtract the area of the non-shaded region, as follows:

[tex]\begin{gathered} A_{total}=\pi\cdot r^2\text{ The given value for r is 3} \\ A_{total}=\pi\cdot3^2\text{ } \\ A_{total}=\pi\cdot9 \\ A_{total}=3.14\cdot9 \\ A_{total}=28.3 \end{gathered}[/tex]

Now let's calculate the area of the non-shaded region:

[tex]\begin{gathered} A=\frac{\theta}{360}\cdot\pi\cdot r^2\text{ the given values for }\theta=112\text{ and r=3} \\ A=\frac{112}{360}\cdot\pi\cdot3^2\text{ } \\ A=0.31\cdot3.14\cdot9 \\ A=8.8 \end{gathered}[/tex]

The area of the shaded region will be:

[tex]\begin{gathered} A_{SR}=A_{total}-A \\ A_{SR}=28.3_{}-8.8 \\ A_{SR}=19.5 \end{gathered}[/tex]

IF AN AUTO DRIVING AT 40MPH DRIVES 4 HOURS, ANDSTOPS, AND THEN DRIVE '2 HOURSMORE AT 10 Metly thoutte(MILES) DID IT GO?

Answers

• We assume here that the auto drives at 40 mph for 4 hours.

,

• Then, it stops and then drives for 2 hours at 10 mph.

,

• We need to find the total miles the auto drove.

,

• To answer this question, we need to know that we have a constant rate at each part of the driving of the auto: in the first part, it drove at a constant speed of 40 mph. In the second part, it drove at a constant speed of 10 mph.

,

• We can say that the total distance for the first part is:

,

• d1 = 40 miles/hour * 4 hours ---> ,d1 = 160 miles.

,

• In the second part:

,

• d2 = 10 miles/hour * 2 hours ---> ,d2 = 20 miles.

,

• Then, the total miles it went was:

,

• ,d1 + d2 = 160 miles + 20 miles = 180 miles.

,

• The auto drove for 180 miles.

,

,

A student was measuring water in a graduated cylinder. The student read the amount of water at 20 ml. The actual amount of water in the graduated cylinder was 17 ml, What is the approximate percent error?

Answers

Recall that percent error is given by the formula:

[tex]|\frac{real\text{ value-measured value}}{\text{real value}}|\cdot100[/tex]

Therefore in our case this becomes:

[tex]|\frac{17-20}{17}|\cdot100=|\frac{3}{17}|\cdot100\approx17.65[/tex]

Therefore the rounded (to two decimals) answer is : 17.65 %

Sam read 6 books in the time it took his little sister, faith, to read 1/2 of a book
Sam's sister read how many times as many books as sam read?

Answers

Answer:

3

Step-by-step explanation:

6 x 1/2 = 3

Two occupations predicted to greatly increase in number of jobs are pharmacy technicians and network systems and data communication analysts. The number of pharmacy technician jobs predicted for 2005 through 2014 can be approximated by 7.1x-y=-254. The number of network and data analyst jobs for the same years can be approximated by 12.2x-y=-231. For both equations, x is the number of years since 2005 and y is the number of jobs in thousands.Solution to the ordered pairs:(5, 286)Use your result from part (a) to estimate the year in which the number of both jobs is equal.

Answers

Given the system of equations:

7.1x - y = -254

12.2x - y = -231

Where x is the number of years since 2005

y is the number of Jobs in thousands.

After solving the system, we have the solution:

(x, y) ==> (5, 286)

Let's determine the year in which the number of both jobs is equal.

The graph of both lines will meet at the solution point.

Given that x represents the number of years since 2005, the year which the number of both jobs is equal will be 5 years after 2005.

Hence, we have:

Year in which number of both jobs are equal = 2005 + 5 = 2010

Therefore, in 2010, the number of both jobs will be equal.

ANSWER:

2010

Which additional piece of information would you need to prove these two triangles are congruent using the side-side-side or SSS triangle congruence postulate?

Answers

By using congruency of triangles, the result obtained is

The additional information needed to make [tex]\Delta STU \cong \Delta SHU[/tex] by SSS axiom is

TU = SH

Side SH is congruent to side TU

Third option is correct

What is Congruency of triangles?

Two triangles are said to be congruent if the corrosponding sides and corrosponding angles are same.

The different axioms of congruency are SSS axiom, SAS axiom, ASA axiom, AAS axiom, RHS axiom

In [tex]\Delta STU[/tex] and [tex]\Delta SHU[/tex]

ST = HU [Given]

SU is common

The additional information needed to make [tex]\Delta STU \cong \Delta SHU[/tex] by SSS axiom is

TU = SH

Side SH is congruent to side TU

To learn more about congruency, refer to the link-

https://brainly.com/question/2938476

#SPJ1

Complete Question

The diagram has been attached here

Mars is about 142 million miles from the sun. The earth is about 93,000,000 miles from the sun. How much farther from the sun is Mars than the earth? Express the answer in scientific notation State the letter of the correct answer. A.) 235x10 B.) 2.35x107 C) 4.9x10 D.) 49x107

Answers

D)

1) Let's visualize it to better understand this

2) Let's pick the distance between Mars and the Sun, and subtract it by the distance (Earth-Sun):

[tex]142,000,000-93,000,000=49,000,000=49\cdot10^6\text{ or 4.9 }\cdot10^7[/tex]

3) So Mars is 4.9 x 10^7 miles farther from the sun than the Earth.

Jen Butler has been pricing Speed-Pass train fares for a group trip to New York Three adults and tour children must pay $124. Two adults and three children must pay $88. Find the serice of the addit's ticket and the price of a child's ticketThe price of a child's ticket is $The price of an adult's ticket is $

Answers

It is given that two adults and three children pay $88.

Represent it as equation

2x+3y=88

Then three adults and four children pay $124.

It is written is equation form as follows.

3x+4y=124

Here x is adults' price and y is children's price.

Solve the system of equation as follows.

[tex]\begin{gathered} 3x+4y=124 \\ 2x+3y=88 \\ 6x+8y=248 \\ 6x+9y=264 \end{gathered}[/tex]

Now subtract each of the last two equations to get -y=-16

Hence y = 16

Substitute in equation 1, we get

[tex]\begin{gathered} 2x+48=88 \\ 2x=40 \\ x=20 \end{gathered}[/tex]

Therefore, adult price is $20 and children price is $16

Solve for Time Principle $2,000Interest $480Rate 8%

Answers

ANSWER:

t = 3

STEP-BY-STEP EXPLANATION:

Given:

Principle (P) = 2000

Interest (I) = 480

Rate (r) = 8% = 0.08

The simple interest formula is the following:

[tex]I=P\cdot r\cdot t[/tex]

We substitute each value and solve for t, like this:

[tex]\begin{gathered} 480=2000\cdot 0.08\cdot \:t \\ \\ t=\frac{480}{2000\cdot0.08}=\frac{480}{160} \\ \\ t=3 \end{gathered}[/tex]

Therefore, the time would be 3 periods (it depends on the interest rate if it is annual, monthly, etc.)

What is the domain and range of y=-1/2x+3

Answers

For the function

[tex]y=-\frac{1}{2}x+3,[/tex]

the range is all the values y can have and the domain is all the possible values that x can take.

In our function there seems to be no restriction on what values x and y can take—our function is defined for all real values of x and y — therefore, the domain and the range of our function is all real numbers.

A school track team member ran for a total of 149.5 miles in practice over 57.5 days. About how many miles did he average per day?

Answers

Data

• Total: 149.5 miles

,

• Days: 57.5

,

Which interval notation represents a function with a domain of all real numbers greater than -3 and less than 6?A.) -2

Answers

The domain is the values of x, and if we want x to fit the inequalities they gave us, we have that

[tex]-3\leq x<6[/tex]

An unusual die has the numbers 2,2,3,3, 7 and 7 on its six faces. Two of these dice are rolled, and the numbers on the top faces are added. How many different sums are possible?

Answers

To find the total numbers of sum, we just have to elevate the number of faces by the second power.

[tex]6^2=36[/tex]

There are 36 total numbers of sums.

However, there are just 6 different sums.

[tex]\begin{gathered} 2+2=4 \\ 2+3=5 \\ 2+7=9 \\ 3+3=6 \\ 3+7=10 \\ 7+7=14 \end{gathered}[/tex]Therefore, there are 6 different sums.

The point P. = (x,1/3) lies on the unit circle shown below. What is the value of x insimplest form?

Answers

When a point (x,y) lies on a unit circle, the following equation holds true:

[tex]x^2+y^2=1[/tex]

We are given

[tex]y=\frac{1}{3}[/tex]

and need to find x.

Let's put it into the equation and figure out x. Shown below:

[tex]\begin{gathered} x^2+y^2=1 \\ x^2+(\frac{1}{3})^2=1 \\ x^2+\frac{1}{9}=1 \\ x^2=1-\frac{1}{9} \\ x^2=\frac{8}{9} \\ x=\sqrt[]{\frac{8}{9}} \\ x=\frac{\sqrt[]{8}}{\sqrt[]{9}} \\ x=\frac{\sqrt[]{8}}{3} \end{gathered}[/tex]

We can simplify the square root of 8 by using the radical property:

[tex]\sqrt[]{a\cdot b}=\sqrt[]{a}\sqrt[]{b}[/tex]

Thus, square root of 8 becomes:

[tex]\sqrt[]{8}=\sqrt[]{4\cdot2}=\sqrt[]{4}\sqrt[]{2}=2\sqrt[]{2}[/tex]

Thus, the simplest form of x is:

[tex]x=\frac{2\sqrt[]{2}}{3}[/tex]

Find the area of the given geometric figure. If the figure is a circle, give an exact area and then use 22/7 as an approximation for pie to approximate the area. r=2in

Answers

[tex]\begin{gathered} \text{geometric figure:circle} \\ \text{radius: 2 inches} \\ \pi=\frac{22}{7} \\ \end{gathered}[/tex]

the area of a circle is given by:

[tex]\text{Area}=\pi\cdot radius^2[/tex]

Step 1

replace

[tex]\begin{gathered} \text{Area}=\frac{22}{7}\cdot(2inches)^2 \\ \text{Area}=\frac{22}{7}\cdot4in^2 \\ \text{Area}=\frac{22\cdot4}{7} \\ \text{Area}=12.57 \end{gathered}[/tex]

so, the answer is 12.57 square inches

Lola has 8 bear figurines. These bear figurines make up 40% of her collection of animal figurines. Find the total number

Answers

[tex]\begin{gathered} \text{Let the total number of the bear figurines be N} \\ \text{Thus,} \\ 40\text{ percent of N=8} \\ \frac{40}{100}\times N=8 \\ \frac{40N}{100}=8 \\ 40N=100\times8 \\ 40N=800 \\ N=\frac{800}{40} \\ N=20 \end{gathered}[/tex]

Hence, the total number of bear figurines are 20

Question 7 of 10Estimate the sum of the decimals below by rounding to the nearest wholenumber. Enter your answer in the space provided.8.9995.496+ 1.199

Answers

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given decimals

[tex]8.999+5.496+1.199[/tex]

STEP 2: Round the given decimals

[tex]\begin{gathered} 8.999\approx9 \\ 5.496\approx5 \\ 1.199\approx1 \end{gathered}[/tex]

STEP 3: Find the sum

[tex]9+5+1=15[/tex]

Hence, the sum is estimatedly 15

Use the Leading Coefficient Test to determine the end behavior of the polynomial function. f((x) = (x + 1)(x + 4)(x + 5)^5

Answers

Answer:

The graph falls to the left and rises to the right.

Explanation:

Given f(x) defined below:

[tex]f\mleft(x)=(x+1)(x+4)(x+5)^5\mright?[/tex]

We are to determine the end behavior of the polynomial using the Leading Coefficient Test.

When using the Leading coefficient test, the following rule applies:

• When the ,degree is odd, and the ,leading coefficient is positive,, the graph falls to the left and rises to the right.

,

• When the ,degree is odd, and the ,leading coefficient is negative,, the graph rises to the left and falls to the right.

,

• When the ,degree is even, and the ,leading coefficient is positive,, the graph rises to the left and right.

,

• When the ,degree is even, and the ,leading coefficient is negative,, the graph falls to the left and right.

Back to our function, f(x):

[tex]\begin{gathered} f(x)=(x+1)(x+4)(x+5)^5 \\ \text{Degree}=7\text{ (Odd)} \\ \text{Leading Coefficient = 1 (Positive)} \end{gathered}[/tex]

From the first rule above, we can conclude that the graph falls to the left and rises to the right.

A graph of f(x) is attached which confirms this end behavior.

6. Use common denominators for these fractions. Arrange them from smallest to largest.

Answers

Given the fractions:

[tex]\frac{9}{16},\frac{3}{8},\frac{1}{4},\frac{5}{8}[/tex]

We will arrange them from the smallest to the greatest using the common denominators

So, the common denominator for the fractions will be = 16

[tex]\begin{gathered} \frac{9}{16}=\frac{9}{16} \\ \\ \frac{3}{8}=\frac{2\cdot3}{2\cdot8}=\frac{6}{16} \\ \\ \frac{1}{4}=\frac{4\cdot1}{4\cdot4}=\frac{4}{16} \\ \\ \frac{5}{8}=\frac{2\cdot5}{2\cdot8}=\frac{10}{16} \end{gathered}[/tex]

So, the answer will be the arrange will be:

[tex]\begin{gathered} \frac{4}{16},\frac{6}{16},\frac{9}{16},\frac{10}{16} \\ \\ \frac{1}{4},\frac{3}{8},\frac{9}{16},\frac{5}{8} \end{gathered}[/tex]

-4(0.25b-2) - (7 - b) + 3/2 (4b - 2/3)simply please

Answers

-4(0.25b-2) - (7 - b) + 3/2 (4b - 2/3)

We must open the parenthesis first by multiplying the elements in it be the elements outside

Bearing in mind that

- * - = +

- * + = -

-4(0.25b-2) - (7 - b) + 3/2 (4b - 2/3)

= -b - 8 -7 + b + 6b - 1

Now we rearrange so all like terms are together noting the signs before each term

= -b + b + 6b - 8 - 7 - 1

= 6b - 16

You may leave the answer in this form or go further to factorize

= 2 (3b - 8)

Select all that apply. What value(s) for x make(s) the equation true?-8y - 2 = -8y - 2

Answers

According to the given data we have the following equation:

-8y - 2 = -8y - 2

In order to calculate the value(s) for x make(s) the equation true we would have to calculate variable y as follows:

We would substitute the y with the values 0, -15, 37, 343

So, if we substitute for 0

-8(0)-2=-8(0)-2

0-2=0-2

-2=-2

value for x=0 applies.

if we substitute for -15

-8(-15)-2=-8(-15)-2

120-2=120-2

118=118

if we substitute for 37

-8(37)-2 +8(37)+2=0

-296-2 +296+2=0

if we substitute for 343

-8(343) -2 +8(343)-2=0

solve for y in the equation below
2 4y = 9

Answers

Answer:9/24

Step-by-step explanation

Use to reflect over the x-axis. Identify the transformed vector.

Answers

To reflect the given matrix over the x-axis, you have to multiply both matrices:

[tex]\begin{bmatrix}{1} & {0} \\ {0} & {-1}\end{bmatrix}\cdot\begin{bmatrix}{7} \\ {-12}\end{bmatrix}[/tex]

Multiply each term of the first row of the first matrix with the corresponding terms of the column of the second matrix and add the results:

Repeat the process for the second row of the first matrix

The resulting matrix is:

[tex]\begin{bmatrix}{1} & {0} \\ {0} & {-1}\end{bmatrix}\cdot\begin{bmatrix}{7} \\ {-12}\end{bmatrix}=\begin{bmatrix}{(1\cdot7)+(0\cdot-12)} \\ {\square}(0\cdot7)+(-1\cdot-12)\end{bmatrix}=\begin{bmatrix}{7} \\ {12}\end{bmatrix}[/tex]

The correct option is option D.

A piece of wire 32 cm long is cut into two pieces, each to be bent to make a square. The length of a side of one square is to be 4 cm longer than the length of a side of the other How should the wire be cut?The length of the shorter piece of wire is :

Answers

Let P1 represent the perimeter of the larger square and let P2 represent the perimeter of the smaller square. Since the piece of wire is 32 cm long and both squares are made of this wire, we have the following:

[tex]P_1+P_2=32[/tex]

Now let x be the length of the side of the smaller square. Since the larger square has sides 4cm longer than the length of the side of the other square, we have the following:

[tex]\begin{gathered} P_1=4(x+4) \\ P_2=4x \end{gathered}[/tex]

using these expressions on the first equation and solving for x, we get:

[tex]\begin{gathered} 4(x+4)+4x=32 \\ \Rightarrow4x+16+4x=32 \\ \Rightarrow8x=32-16=16 \\ \Rightarrow x=\frac{16}{8}=2 \\ x=2 \end{gathered}[/tex]

we have that x = 2. Then, the length of the shorter piece of wire will be the perimeter of the smaller square, therefore, the length of the shorter piece of wire is P2 = 4(2) = 8 cm

What is the value of x?

Answers

Answer:

The two angles are congruent, so: 2x+2=3x-52

2x-3x=-2-52

-x=-54

x=54

X=54 because that’s what I got

Calculate Jayden's simple interest on a 5-year car loan for $33,486 at 2.38%.

Answers

Answer:

$3984.83.

Explanation:

[tex]Simple\: Interest=\frac{Principal\times Rate\times Time}{100}[/tex]

In this particular case:

• The principal/loan amount = $33,486.

,

• Rate = 2.38%.

,

• Time = 5 years.

Substituting these into the formula above:

[tex]\begin{gathered} Simple\: Interest=\frac{33,486\times2.38\times5}{100} \\ =\$3984.83 \end{gathered}[/tex]

Jayden's simple interest is $3984.83.

What 4x 5 + 2?????? ????

Answers

Given:

[tex]4\times5+2[/tex]

To find the value:

Using the BODMAS rule,

[tex]\begin{gathered} 4\times5+2=(4\times5)+2 \\ =20+2 \\ =22 \end{gathered}[/tex]

Hence, the answer is 22.

What are the first and third quartiles of rainfall of this data? Q1 = 5. Q3 = 8 Q1 = 6, Q3 = 8 Q1 = 4, Q3 = 7 Q1 = 5, Q3 = 7.5

Answers

Answer:

Q1 = 5, Q3 = 8

Explanation:

There are a total of 19 dots on the chart.

[tex]\begin{gathered} Item\; in\; Q_1=\frac{1}{4}\times19 \\ =4.75th\text{ item} \end{gathered}[/tex]

The 5th item on the chart =5, therefore:

• Q1 = 5

Similarly:

[tex]\begin{gathered} Item\; in\; Q_3=\frac{3}{4}\times19 \\ =14.25th\text{ item} \end{gathered}[/tex]

The 14th and 15th item on the chart =8, therefore:

• Q3 = 8

Find the missing length indicated. Leave your answer in the simplest radical form.92112-1620649

Answers

Apply teh altitude theorem:

9/12 = 12/x

Solve for x:

9x = 12 (12)

9x = 144

x = 144/9

x = 16

Two real numbers have coordinates w and t as shown on the number line below. Copy the number line into your Student Answer Booklet W + 2 3 -5 -4 3 2 1 0 1 4 5 a. What are the two real numbers represented by w and t on the number line? b. The coordinate of Point A on the number line is w + t. Plot and label Point A on the number line and explain how you decided upon its location. c. The coordinate of Point B on the number line is w — t. Plot and label Point B on the number line and explain how you decided upon its location, . d. The coordinate of Point C on the number line is wet. Plot and label Point C on the number line and explain how you decided upon its location.

Answers

1.

The location of w and t on the number line arenot exact so you will need to approximate .

In the first point w, it is between -4 and - 3 but closer than -4 compared to -3.Additionally, the point w is located at a position greater than -3.5 .It will be okay to approximate point w at -3.6.

w= -3.6

In the second point t, it is located between 0 and 1 but closer to 0 than 1. Additionally, t is less than 0.5 because it is located at a position less than 0.5, hence it is approximately at : t = 0.4

w= -3.6 and t = 0.4 -------approximated actual values

The two real numbers for w and t will be :

w= - 4 and t = 0 ---------approximated real numbers.

NB;

w= -3.7 and t= 0.3 is also a correct approximate because the difference of +/- 0.1 can be allowed for this case.

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