The gauge pressure is 562.5 Pa.
Given data:
The density of oil is ρ=0.903 g/ml.
The distance below the surface is h=6.35 cm.
The density in kg/cm³ will be,
[tex]\begin{gathered} \rho=0.903\text{ g/ml }\times\frac{1\text{kg}}{1000\text{ g}}\times\frac{1\text{ml}}{1\text{ }cm^3}\times\frac{10^6\text{ }cm^3}{1m^3} \\ \rho=\frac{903kg}{m^3} \end{gathered}[/tex]The gauge pressure can be calculated as,
[tex]\begin{gathered} p=\rho gh \\ p=(\frac{903kg}{m^3})(\frac{9.81m}{s^2})(6.35cm\times\frac{1\text{ m}}{100cm}) \\ p=\frac{562.5kg}{ms^2}\times\frac{1\text{ Pa}}{\frac{kg}{ms^2}} \\ p=562.5\text{ Pa} \end{gathered}[/tex]Thus, the gauge pressure is 562.5 Pa.
I just need part c please The first one I know it’s 32
We are given that in a falling object the distance "d" is directly proportional to the square of the time and the proportionality constant is 16. This means that the function of distance is given by:
[tex]d(t)=16t^2[/tex]The average rate of change is given by the following formula:
[tex]r=\frac{d(t_f)-d(t_0)}{t_f-t_0}[/tex]Where:
[tex]t_f,t_0=\text{ final and initial time}[/tex]Now, we substitute the values of "d(t)":
[tex]r=\frac{16t_f^2-16t_0^2}{t_f-t_0}[/tex]We can factor the numerator and we get:
[tex]r=16\frac{(t_f-t_0)(t_f+t_0)}{t_f-t_0}[/tex]Simplifying we get:
[tex]r=16(t_f+t_0)[/tex]For the first 2 seconds we have:
[tex]\begin{gathered} t_0=0 \\ t_f=2s \end{gathered}[/tex]Substituting the values we get:
[tex]\begin{gathered} r=16(2s+0s) \\ r=32 \end{gathered}[/tex]Therefore, the average rate of change is 32
For the next 2 seconds we have:
[tex]\begin{gathered} t_0=2s \\ t_f=4s \end{gathered}[/tex]Now, we substitute the values:
[tex]\begin{gathered} r=16(4s+2s) \\ r=96 \end{gathered}[/tex]Therefore, the rate of change in the next two seconds is 96.
For the next 2 seconds we have:
[tex]\begin{gathered} t_0=4s \\ t_f=6s \end{gathered}[/tex]Substituting the values we get:
[tex]\begin{gathered} r=16(6s+4s) \\ r=160 \end{gathered}[/tex]Therefore, the rate of change is 160
Consider an airless, non-rotating planet of mass M and radius R. and electromagnetic launcher standing on the surface of this planet shoots a projectile with initial velocity v0 directed straight up. Unfortunately, due to some error, v0 is less than the planet's escape velocity ve; specifically, v0 = 0.762ve. Unable to escape the planet's gravitational pull, the projectile rises to a maximal height h above the ground, then falls back to the ground. Calculate the ratio h/R of the projectile's maximum height to the planet's radius.
Given data:
The mass of planet is M.
The radius of planet is R.
The initial velocity of projectile is v₀=0.762ve.
The amount of kinetic and potential energy should be equal according to conservation of energy,
[tex]\begin{gathered} KE=PE \\ \frac{1}{2}mv^2_e=\frac{GMm}{R}^{}_{} \\ R=\frac{GM^{}_{}}{v^2_e} \end{gathered}[/tex]The escape velocity is given by,
[tex]v_e=\sqrt[]{\frac{2GR}{M}}[/tex]Here, G is the universal gravitational acceleration.
The time taken to reach the maximum height will be,
[tex]\begin{gathered} v_0=gt \\ t=\frac{v_0}{g} \end{gathered}[/tex]The maximum height reached by the projectile is given by,
[tex]\begin{gathered} h=v_0t+\frac{1}{2}gt^2 \\ h=v_0(\frac{v_0}{g})+\frac{1}{2}g(\frac{v_0}{g})^2 \\ h=\frac{v^2_0}{g}_{}+\frac{1}{2}\frac{v^2_0}{g}_{} \\ h=\frac{3}{2}\frac{v^2_0}{g}_{} \\ h=\frac{3}{2}R \\ \frac{h}{R}=1.5 \end{gathered}[/tex]Answer:
1.39
Explanation:
(1/2)mVe^2=(mMG)/R
Ve^2=2MG/R
(1/2)mVo^2=mMG(1/R-1/(R+h))=mMG(h/(R^2+Rh))
Vo^2=2MG(1/R)(h/(R+h))
Vo^2=Ve^2(h/(R+h))
Vo^2/Ve^2=h/(R+h)
Ve^2/Vo^2=(R+h)/h
1/.762^2=(R+h)/h
1.72h-h=R
.72h=R
h/R=h/.72h
h/R=1.39
You have measured a carts mass and observed that it changed position. What other information do you need to determine the carts momentum during that time? A. The carts electric charge. B. The net force on the cart. C. The displacement of the cart. D. The carts gravitational potential energy
Given that we know the mass and displacement of an object for a given amount of time, to determine the momentum we can use the fact that the change in momentum is equal to the impulse. This can be written as:
[tex]Ft=m\Delta v[/tex]Where:
[tex]\begin{gathered} F=\text{ net force} \\ t=\text{ time} \\ m=\text{ mass} \\ \Delta v=\text{ change in velocity} \end{gathered}[/tex]Therefore, we need to know the net force in order to determine the momentum in that time.
Describe how a convex lens could be used to make a magnifying lens.
Explanation and Answer:
when the object is placed between the optical center and the first focal point of the convex lens. its image is formed on the same side where the object is placed. the image is erect, magnified, and virtual.
we can see the ray diagram to understand it better,
as we can see from the ray diagram, a convex lens is used as a magnifying lens.
The image formed is larger than the original object.
if the object is placed between the first focal and the optical center. the image formed is larger than the object. the formed image is erect, virtual, and magnified. This way convex lens work as a magnifying lens.
A pumpkin pie in a 10.50 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie plate moves through a distance of 258 in. Express the angular distance that the pie plate has moved through in revolutions, radians, and degrees.
The angular distance traveled in degree, radian and revolution are : 49°, 0.273 radian and 0.14 revolution respectively
What is angular velocity?The angular distance traveled around a circular path is the number of radians the path subtends.It can also be defined as the angle made by a body while moving in a circular path.
From the definition, angular distance (theta) = distance moved/radius.
radius = diameter/2
radius= 10.50/2= 5.25inches
angular distance= 258/5.25= 49.14°
in revolution , = 49.14/360=0.14 revolution
in radian ,= 49.14/180= 0.273radian
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A stone is dropped down a well. When it hits the bottom of the well it is travelling at 20 m/s. The mass of the stone is 0.02 kg.
a. Calculate the kinetic energy of the stone as it hits the bottom of the well.
b. What is the gravitational potential energy of the stone at the top of the well?
c. Calculate the height of the well.
Why are quarks important to physics and to the real, modern world?
Because Quarks are the fundamental building blocks of the universe.
Quark is any member of a group of elementary subatomic particles that interact by means of a strong force and are a fundamental constituent of matter.
Mass is the quantity of matter an object has. Is this true or false?
The mass of the object is the amount of matter present in the object.
Thus, the mass of the object does not change with the gravity or any other force unless the matter is removed from the object.
Hence, the given statement is true.
A force F1 of magnitude 5.70 units acts on an object at the origin in a direction = 38.0° above the positive x-axis. (See the figure below.) A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1 + F2.magnitude unitsdirection ° counterclockwise from the +x-axisTwo forces act on an object. Force vector F1 acts up and right on the right side of the object at an angle above the horizontal. Force vector F2 acts vertically upwards on the top side of the object.
ANSWER:
Magnitude: 9.62 units
Direction: 62.1°
STEP-BY-STEP EXPLANATION:
Given:
F1 = 5.7 units
F2 = 5 units
Angle () = 38°
The vertical component of force F1 is:
[tex]\begin{gathered} F_{1y}=F_1\cdot\sin\theta \\ \\ \text{ We replacing:} \\ \\ F_{1y}=5.7\cdot\sin(38)=3.5j\text{ units} \end{gathered}[/tex]The horizontal component of force F1 is:
[tex]\begin{gathered} F_{1x}=F_1\cdot\cos\theta \\ \\ \text{ We replacing:} \\ \\ F_{1x}=5.7\cdot\cos(38)=4.5i\text{ units} \end{gathered}[/tex]Therefore, the total force F1 is:
[tex]\begin{gathered} F_1=F_{1x}+F_{1y} \\ \\ F_1=4.5i+3.5j \end{gathered}[/tex]The vertical component of force F2 is:
[tex]F_{2y}=5j\text{ units}[/tex]The horizontal component of force F2 is:
[tex]F_{2x}=0i[/tex]Therefore, the total force F2 is:
[tex]\begin{gathered} F_2=F_{2x}+F_{2y} \\ \\ F_2=0i+5j \end{gathered}[/tex]The resultant force (F1 + F2) would be:
[tex]\begin{gathered} F=F_1+F_2 \\ \\ F_=4.5i+3.5j+0i+5j \\ \\ F=4.5i+8.5j \end{gathered}[/tex]The magnitude of the resultant force is:
[tex]\begin{gathered} F=\sqrt{(F_x)^2+(F_y)^2} \\ \\ \text{ We replacing:} \\ \\ F=\sqrt{4.5^2+8.5^2} \\ \\ F=\sqrt{20.25+72.25}=\sqrt{92.5} \\ \\ F=9.62\text{ units} \end{gathered}[/tex]The direction is:
[tex]\begin{gathered} \theta =\tan ^{-1}\left(\frac{F_y}{F_x}\right) \\ \\ \text{ We replacing:} \\ \\ \theta =\tan ^{-1}\left(\frac{8.5}{4.5}\right) \\ \\ \theta=62.1\degree \end{gathered}[/tex]Find the x-component of thisvector:47.3m39.40
We know that
• The angle of direction is 39.4.
,• The magnitude of the vector is 47.3 m.
To find the horizontal component, use the following formula.
[tex]v_x=v\cdot\cos \theta[/tex]Use the given information to find the horizontal component.
[tex]v_x=47.3m\cdot\cos 39.4\approx36.6m[/tex]Therefore, the x-component is 36.6(m).A box weighing 100 newtons is pushed up an inclined plane that is 5 meters long. It takes a force of 75 newtons to push it to the top, which has a height of 3 meters. Work Output? Work Input? Efficiency?
The work output can be given as,
[tex]W_O=Fh[/tex]Substitute the known values,
[tex]\begin{gathered} W_O=(75\text{ N)(3 m)(}\frac{1\text{ J}}{1\text{ Nm}}) \\ =225\text{ J} \end{gathered}[/tex]Thus, the work output of the procedure is 225 J.
The work input of the procedure is,
[tex]W_i=wd[/tex]Substitute the known values,
[tex]\begin{gathered} W_i=(100\text{ N)(5 m)(}\frac{1\text{ J}}{1\text{ Nm}}) \\ =500\text{ J} \end{gathered}[/tex]Thus, the work input of the procedure is 225 J.
The efficiency of the work done is given as,
[tex]e=\frac{W_O}{W_i}[/tex]Substitute the known values,
[tex]\begin{gathered} e=\frac{225\text{ J}}{500\text{ J}} \\ =0.45 \end{gathered}[/tex]Thus, the efficiency of procedure is 0.45 or 45%.
A motorboat travels 408 kilometers in 6 hours going upstream and 882 kilometers in 9 hours going downstream. What is the rate of the boat, and what is the rate of the current?
We have the next variables
x = speed of the boat in still water
y = speed of the current
(x-y) = Upstream speed
(x+y) = downstream speed
So we have the next equations for the distance
[tex]\begin{gathered} 6\mleft(x-y\mright)=408 \\ \end{gathered}[/tex][tex]\begin{gathered} 9(x+y)=882 \\ \end{gathered}[/tex]We simplify each equation
[tex]\begin{gathered} x-y=68 \\ x+y=98 \end{gathered}[/tex]we sum both equations
[tex]\begin{gathered} 2x=166 \\ x=\frac{166}{2} \\ x=83 \end{gathered}[/tex]Then we calculate the y
[tex]\begin{gathered} y=98-x \\ y=15 \end{gathered}[/tex]x = speed of the boat in still water=83 km/hr
y = speed of the current 15 km/hr
The horsepower (hp) that a shaft can safely transmit varies jointly with its speed (in revolutions per minute, rpm) and the cube of its diameter. If a shaft of a certain material 2 inches in diameter can transmit 36 hp at 75 rpm, what diameter must the shaft have in order to transmit 134 hp at 35 rph
the shaft must have 4 inches of diameter
Explanation
Step 1
given that The horsepower (hp) that a shaft can safely transmit varies jointly with its speed (in revolutions per minute, rpm) and the cube of its diameter.
[tex]Power\propto diamter^3v[/tex]so
a) If a shaft of a certain material 2 inches in diameter can transmit 36 hp at 75 rpm
[tex]\begin{gathered} 36\text{ hp=\lparen2 in\rparen}^3*75\text{ rpm*k} \\ 36=600\text{ k} \\ k=\frac{36}{600}=0.06 \end{gathered}[/tex]b)what diameter must the shaft have in order to transmit 134 hp at 35 rph
[tex]\begin{gathered} Power\propto diamter^3v \\ Power=d^3*v*k \\ replace \\ 134=d^3*35*0.06 \\ 134=d^3*2.1 \\ divide\text{ both sides by 2.1} \\ \frac{134}{2.1}=\frac{d^3*2.1}{2.1} \\ 63.80=d^3 \\ cubic\text{ root in both sides} \\ \sqrt[3]{63.80}=\sqrt[3]{d^3} \\ 3.996=d \\ rounded \\ d=4\text{ inches} \end{gathered}[/tex]therefore
the shaft must have 4 inches of diameter
I hope this helps you
It took 89.5 degrees to stop the wheel from 47.8 rpm. What is the angular acceleration? (Please give a negative number)
8 rad/s^2 is the angular acceleration when It took 89.5 degrees to stop the wheel from 47.8 rpm.
θ =89.5=1,562 radian
Wf= 5 rad
Wi=0
2αθ=Wf^2-Wi^2
α=(Wf^2-Wi^2)÷2θ
α=8 rad/s^2
The rate at which the angular velocity alters over time in a circular motion is known as the angular acceleration. Rotational acceleration is another name for it. It has both magnitude and direction, making it a vector quantity. The symbol for angular acceleration is alpha.
Variable velocity is the cause of acceleration. If an item is rotating and changing speed, we refer to it as angular acceleration. According to the connection, the angular displacement of an item rotating depends on time t. Any time a body spins, there is angular acceleration. A quantitative vector can be used to indicate the change in angular velocity per unit of time.
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What is the voltage of a circuit that has a resistance of 100 and an internal current of 2 amps 200 volts0 0.02 voltsO 50 volts
Given,
The resistance of the circuit, R=100 Ω
The current in the circuit, I = 2 A
From Ohm's law, we have,
[tex]V=IR[/tex]Where V is the voltage.
On substituting the known values,
[tex]V=2\times100=200\text{ V}[/tex]Thus the voltage of the internal circuit is 200 V.
That is the correct answer is the 1st option.
If I am finding the x component of acceleration and it’s m/s^3, would the answer be m/s^3
No, the aceleration is alwas m/s^2
If you have something in m/s^3, probablly you are missing a multiplication times the time or maybe you have to integrated the function
[tex]y^{\prime}\left(t\right)=\frac{0.018m}{s^2}[/tex]
What happens to Centripedal force on the planet around a star if the radius of an orbit is doubled ? assume that velocity remains the same A) the Centripedal force will be half of its original value B) the Centripedal force will be double its original value C) the Centripedal force will be 1/4 of its original value D) the Centripedal force will not change
We will have the following:
We know that:
[tex]F_c=\frac{mv^2}{r}[/tex]If we double the radius, then:
[tex]F_c=\frac{mv^2}{(2r)}\Rightarrow F_c=\frac{1}{2}\frac{mv^2}{r}[/tex]So, the centripetal force will be half of its original value. [Option A]
A 1,982-kg car starts from rest at the top of a driveway 6.74 m long that is sloped at an angle of 30 degrees with the horizontal. If an average friction force of 2,721 N impedes the motion of the car, find the speed (in m/s) of the car at the bottom of the driveway.Use the approximation that g ≈ 10 m/s2.
In this situation, we cannot apply the law of conservation of energy, as there is friction. For us to solve, let us start by writing the balance equations. We'll have:
[tex]\sum F_x=P*sin(30)-Fat=ma[/tex][tex]\sum F_y=N-P*cos(30)=0[/tex]In order to find out the acceleration, we can use the first equation:
[tex]a=\frac{P*sin(30)-Fat}{m}=\frac{1982*10*sin(30)-2721}{1982}=3.627\frac{m}{s^2}[/tex]The car will then suffer this acceleration on the sloped plane. With this, we can calculate its speed by the end using the equations for a uniformly accelerated movement:
[tex]S(t)=S_0+v_0t+\frac{at^2}{2}\Rightarrow6.74=\frac{3.627*t^2}{2}\Rightarrow t=1.928s[/tex]This is the time the car will take to reach the bottom. By replacing this on the equation for the velocity we get:
[tex]v(t)=v_0+at=0+3.627*1.928=7\frac{m}{s}[/tex]Then, our final answer is 7 m/s
3x5 - 2^2 - can you help me solve this?
Given, 3×5-2²
The multiplication operator precedes a subtraction operator. Thus the multiplication is performed before the subtraction is performed.
Thus,
[tex]\begin{gathered} 3\times5-2^2 \\ =15-4 \\ =11 \end{gathered}[/tex]Thus the answer we get after solving the given equation is 11.
Answer:11
Explanation:2 to the second =4. 3 times 5 equals 15. 15-4=11
Questlon 7 of 10 Which two factors affect the amount of thermal energy an object has? O A. The directions in which the particles of the object are moving [ B. The amount of space between the particles of the object C. The mass of the object O D. The average kinetic energy of the particles of the object SUBM
C. The mass of the object
D. The average kinetic energy of the particles of the object
Thermal energy can be considered as kinetic energy, which involves the motions of the molecules of the object.
If an object has high kinetic energy, then the object has higher thermal energy.
A serving size of Lays Potato Chips is 15 chips. There are 160 calories in one serving and 10 grams of fat. If you eat two servings how many calories and grams of fat are there? Question 5 options: 320 calories, 20 gram of fat 160 calories, 10 grams of fat 340 calories, 15 grams of fat 325 calories, 25 grams of fat
If you eat two servings of Lays Potato Chips, you would have consumed 320 calories and 20 gram of fat.
One serving of Lays Potato Chips = 15 chips
Calories in one serving of Lays Potato Chips = 160 cal
Fat in one serving of Lays Potato Chips = 10 g
Calories in two serving of Lays Potato Chips = 160 * 2 = 320 cal
Fat in two serving of Lays Potato Chips = 10 * 2 = 20 g
Two serving of Lays Potato Chips will have twice the fat and calories of one serving of Lays Potato Chips. So multiply the values of calories and fats by 2 to get the required value.
Therefore, if you eat two servings Lays Potato Chips, you would have consumed 320 calories and 20 gram of fat.
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If you eat two servings of Lays Potato Chips, there are 320 calories and 20 gram of fat so option 1 is correct.
Given:
A serving size of Lays Potato Chips is 15 chips.
There are 160 calories in one serving and 10 grams of fat.
Calories in two serving of Lays Potato Chips = calories in one serving *2
= 160 * 2
= 320 calories.
Fat in two serving of Lays Potato Chips = fat in one serving * 2
= 10 * 2
= 20 grams
Therefore, if you eat two servings Lays Potato Chips, there are 320 calories and 20 gram of fat so option 1 is correct.
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Tory experiments with pulleys in physics class. She applies 60 newtons of force to a single pulley to lift a bowling ball. By adding another pulley, she'd get a mechanical advantage of 2. Whats the minimum input force she'll need to lift the ball if she adds another pulley?
Given,
The force applied by Tory, F=60 N
Mechanical advantage after adding the second pulley, MA=2
As Tory applies 60 N of force when there is only one pulley, the weight of the ball is 60 N.
Thus the output force is 60 N.
The mechanical advantage is given by,
[tex]MA=\frac{\text{output force}}{input\text{ force}}[/tex]On substituting the known values,
[tex]\begin{gathered} 2=\frac{60}{\text{input force}} \\ \Rightarrow input\text{ force}=\frac{60}{2} \\ =30\text{ N} \end{gathered}[/tex]Thus the minimum input force tory need to apply is 30 N
9. In this time interval, what is the vehicle's displacement? (In case it is difficult tosee... at the beginning, t=0s and x=Om at the end t=5s and x=1m)
The term displacement is simply as the distance between the initial position and the final position. It can be measured or calculated in meters
The displacement from the given position is calculated as
[tex]\begin{gathered} d=1-0 \\ =1\text{ m} \end{gathered}[/tex]Hence, the vehicle's displacement is d = 1 m
Question 17 of 30Which of the following is the energy of atoms vibrating inside an object?A. RadiantB. ElectricC. ThermalD. MechanicalSUBMIT
ANSWER:
C. Thermal
STEP-BY-STEP EXPLANATION:
Thermal energy, or heat, is the internal energy of substances; is the vibration and movement of atoms and molecules within a substance.
Therefore, the correct answer is C. Thermal
A motion detector detected that a toy car covered 2 m at a constant speed of 0.25 m/s. Sketchthe graph to represent the motion of an obiect.
Explanation
the function for the distance is given by
[tex]\text{distance}=\text{ sp}eed\cdot time\text{ }[/tex]then, let
speed= 0.25 m/s
time= t
distance= 2m
hence, replace
[tex]\begin{gathered} \text{distance}=\text{ sp}eed\cdot time\text{ } \\ \text{distance}=0.25\frac{m}{s}\cdot t \\ d(t)=0.25t\Rightarrow equation\text{ of the line} \end{gathered}[/tex]Step 2
now, to graph the line we need 2 points
a) when t= 0
[tex]\begin{gathered} d(t)=0.25t\Rightarrow equation\text{ of the line} \\ d(0)=0.25\cdot0 \\ d(0)=0 \\ so \\ \text{coordinate 1(0,0)} \end{gathered}[/tex]P1(0,0)
b) when the car has covered 2m
let d=2
replace and solve for x
[tex]\begin{gathered} d(t)=0.25t\Rightarrow equation\text{ of the line} \\ 2=0.25t \\ \text{divide both sides by 0.25} \\ \frac{2}{0.25}=\frac{0.25t}{0.25} \\ 8=t \\ \text{hence, after 8 seconds, the distance is 2 m, so the coordinate is} \\ (8,2) \end{gathered}[/tex]P2(8,2)
finally, draw a line that passes through the point P1(0,0) and P2(8,2)
I hope this helps you
A _____ stores electrical energy, whereas _____ is the ratio of a stored charge on each plate to the electric potential difference between the plates.capacitor, electrical potentialcapacitor, capacitanceinsulator, energyinsulator, capacitance
A capacitor stores electrical energy, whereas capacitance is the ratio of a stored charge on each plate to the electric potential difference between the plates. Therefore, second option is correct.
Whenever the charge stored in the capacitor increases it increase the capacitance of capacitor but when the potential difference increases it decrease the capacitance of a capacitor.
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Two samples of water are prepared, one with red food coloring and one with blue. When carefully combined, the red-colored water is able to float on top of the bluecolored water. Which statement best explains this result?
A. The blue-colored water is hotter and more dense.
B. The red-colored water is cooler and more dense .
C. The blue-colored water is cooler and less dense.
D. The red- colored water is hotter and less dense.
Answer:
B. The red-colored water is cooler and more dense .
What percentage of the speed of light in vacuum is the speed of light in a diamond? Incorrect: Your answer is incorrect. answer in:_____%
Explanation
Step 1
find the speed of ligth in the diamond:
to do that we can use the formula
[tex]refractive\text{ index\lparen}\mu)=\frac{c(\text{ speed of light in vaccum\rparen}}{s(\text{ speed of light in the material\rparen}}[/tex]we know that :
[tex]\begin{gathered} refractive\text{ index of diamond\lparen}\mu)=2.42 \\ speed\text{ of llight in the vaccum=c=300000 }\frac{km}{s} \end{gathered}[/tex]so, replace and solve for speed of light in the diamond
[tex]\begin{gathered} refractive\text{ index\lparen}\mu)=\frac{c(\text{ speed of light in vaccum\rparen}}{s(\text{ speed of light in the material\rparen}} \\ 2.42=\frac{3*10^5\frac{km}{s}}{s} \\ s=\frac{3\times10^5\frac{km}{s}}{2.42} \\ s=123966.9\text{ }\frac{km}{s} \\ \end{gathered}[/tex]finally, to find the percentage apply this formula
[tex]\begin{gathered} \text{ \% }=\frac{speed\text{ of light in diamond}}{spped\text{ of ligth invaccum}}*100\text{ \%} \\ replace \\ \text{ \%=}\frac{123966.9\frac{km}{s}}{3*10^5\frac{km}{s}}*100\text{ \%} \\ \text{ \%=0.413*100\%} \\ \text{ \%=41.3 \%} \\ rounded\text{ 41\%} \end{gathered}[/tex]so, the answer is
41 %
I hope this helps you
Lola has a two-year lease that requires her to pay $295 rent per month.What is the total amount she will pay for rent during the term of herlease?a. $3,540b. $8,850c. $885d. $7,080
If the price that needs to be paid per month is $295, first let's convert the total amount of time (2 years) to months.
1 year has 12 months, therefore 2 years have 24 months.
Now, to find the total amount, let's multiply the cost per month by the number of months:
[tex]295\cdot24=7080[/tex]Therefore the total amount is $7,080. Correct option: d.
When analyzing a combination circuit, which parts are combined first to determine total resistance? Select one:a.the parallel componentsb.the series components c.it does not matter d.the diagonal components
ANSWER
a. The parallel components
EXPLANATION
When analyzing a combination circuit, we always want to transform it into a series circuit by replacing the parallel sections with an equivalent resistor.
If the circuit is more complex, then we can consider each parallel branch as a subcircuit and solve those first in the same order: first the parallel components and then the series components.