A ladder, 510 cm long, leans against a building. If the angle between the ground and the ladder is 57 degrees, how far from the wall is the bottom of the ladder? Round to the nearest tenth
Answers
Let's use cosine function to find the distance between the wall and the bottom of the ladder:
[tex]\begin{gathered} \cos (\theta)=\frac{adjacent}{hypotenuse} \\ \cos (57)=\frac{x}{510} \\ solve_{\text{ }}for_{\text{ }}x\colon \\ x=510\cdot\cos (57) \\ x=277.8\operatorname{cm} \end{gathered}[/tex]
Related Questions
Find the Midpoint of the two given endpoints of (-5, 6) and (9,7)
Answers
1) Given those endpoints, we can
Find the slope, if it exists, of the line containg the pairs of pointsplease answer them all :(1. ( -4, -1 ) and ( 4, 4 )2. ( 0, 3 ) and ( 4, 0 )3. ( 0, 1 ) and ( 3, 0 )4. ( 7, 8 ) and ( -7, 8 )5. ( 1, 5 ) and ( -8, 5 )
Answers
The formula for determine the slope is given by
m = ( y2-y1)/(x2-x1) where ( x1,y1) and (x2,y2) are points on the line
m = ( 4 - -1)/(4 - -4)
Rewriting
m = ( 4+1)/( 4+4)
= 5/8
The slope is 5/8
A teacher wants to track the number of books students have read each week,encouraging them to increase their reading throughout the school year. Which ofthe following graphs might be most effective to inspire the student?
Answers
We have to find which of the graph options is best to track the number of books that the students read each week and encourage them to increase them.
Option 1 (scatter plot): in this case, it is not useful in the sense that we can not compare the evolution in time of each student. We can only see the number of books per student for specific weeks.
Option 2 (time series): in this case, the attendance is not a variable of interest, so it is not suitable.
Option 3: A pie chart is only useful to compare proportions and percentages, and not track an evolution of a variable in time.
Option 4: This aggregation of the data in a Pareto only allows to compare the total number of books per week, but the evolution is not clear, as we sort the columns by the number of books instead of time.
Option 5: A time series with weeks in the x-axis and number of books in the y-axis let the teacher clearly see the evolution of books read in time. So this option is the most suitable.
Answer: Option 5 (time series)
list the following information about the function: y = 2 (x-3)^2-1 (parent graph y = x^2)
Answers
Given
The function is defined as:
[tex]y\text{ = 2\lparen x -3\rparen}^2\text{ - 1}[/tex]x-intercepts
The x-intercepts of the function y are the values of x when y = 0
Substituting 0 for y and solving for x
[tex]\begin{gathered} 2(x-3)^2\text{ -1 = 0} \\ 2(x-3)^2\text{ = 1} \\ Divide\text{ both sides by 2} \\ (x-3)^2\text{ = }\frac{1}{2} \\ Square\text{ root both sides} \\ x-3\text{ = }\pm\sqrt{\frac{1}{2}} \\ x\text{ = 3 }\pm\text{ }\sqrt{\frac{1}{2}} \end{gathered}[/tex]Hence, the x-intercepts are:
[tex](\sqrt{\frac{1}{2}}\text{ + 3, 0\rparen, \lparen-}\sqrt{\frac{1}{2}}\text{ + 3,0\rparen}[/tex]y-intercepts
The y-intercepts are the values of y when x = 0
[tex]\begin{gathered} y\text{ = 2\lparen0-3\rparen}^2-\text{ 1} \\ =\text{ 2}\times9-1 \\ =\text{ 17} \end{gathered}[/tex]Hence, the y-intercept is (0, 17)
Maximum or minimum of the function
The given equation is in vertex form.
[tex]\begin{gathered} y\text{ = a\lparen x-h\rparen}^2\text{ + k} \\ Where\text{ \lparen h,k\rparen is the vertex} \end{gathered}[/tex]Hence, the minimum value of the function is (3,-1)
There is 1 teacher for every 18 students on a school trip. How many teachers are there if 72 students go ve values to create a proportion that can be used to solve the problem.
Answers
Proportion 1 : 18
x : 72
Ratio
1 teacher / 18 students = number of teacher / 72 students
1/18 = x/ 72
x= 72/ 18
x = 4
_____________
Answer
if 72 students go, 4 teaches are required.
_______________
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When the price of petrol increases by 20%,
a motorist decreases his volume of petrol
consumption by 10%. Find the percentage
increase in his petrol bill.
Answers
Answer:
The percentage increase in his petrol bill is 16 2/3%
The percentage increase in his petrol bill would be equal to 16 2/3%
What is the percentage?A percentage is a minimum number or ratio that is measured by a fraction of 100.
Given that When the price of petrol increases by 20%, a motorist decreases his volume of petrol consumption by 10%.
Let the inital price be 100 and consumption be 100t.
Now increased price
= 120 % of 100
= 120
New consumption
= 100 x 100 / 120
= 83.33
Hence, percentage reduction in the consumption will be;
(100 - 83.33)/ 100 x 100
16 and 2/3 %
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Logarithmic help is needed. Be sure to note the differences between logarithmic and exponential forms in each equation.
Answers
The pattern in converting logarithmic form to exponential form and vice versa is this:
[tex]y=b^x\leftrightarrow\log _by=x[/tex]For the first exponential equation that is 16 = 8^4/3, our y = 16, b = 8, and x = 4/3. Let's plug this in the logarithmic pattern.
[tex]\begin{gathered} \log _by=x \\ \log _816=\frac{4}{3} \end{gathered}[/tex]The logarithmic form of the first equation is log₈ 16 = 4/3.
Now, let's move to the second one.
[tex]\log _5(15,625)=6[/tex]b = 5, y = 15, 625, and x = 6. Let's plug these in to the exponential pattern.
[tex]\begin{gathered} y=b^x \\ 15,625=5^6 \end{gathered}[/tex]Hence, the exponential form of the second equation is 15, 625 = 5⁶.
(n-1)9. Expand11-11 + 2 + 3 + 4 + 5 + 60 + 1 + 2 + 3 + 4 + 5 + 60 + 1 + 2 + 3 +4 + 5AB(-1) + (-2) + (-3) + (-4) + (-5) + (-6)
Answers
To expand the given summation, we proceed as follows:
[tex]\begin{gathered} \text{Given:} \\ \sum ^6_{n\mathop=1}(n-1) \\ \Rightarrow\text{ }\sum ^6_{n\mathop{=}1}(n)-\text{ }\sum ^6_{n\mathop{=}1}(1) \\ \text{Now:} \\ \sum ^6_{n\mathop{=}1}(n)\text{ is the sum of the first six natural numbers (1,2,3,4,5,6)} \\ \text{And:} \\ \sum ^6_{n\mathop{=}1}(1)\text{ is simply (6}\times1)--That\text{ is, the number 1 added to itself six times } \\ \text{Therefore, we have:} \\ \Rightarrow\text{ }\sum ^6_{n\mathop{=}1}(n)-\text{ }\sum ^6_{n\mathop{=}1}(1) \\ \Rightarrow(1+2+3+4+5+6)-(1+1+1+1+1+1) \\ \Rightarrow(1+2+3+4+5+6)-(6) \\ \Rightarrow(1+2+3+4+5) \\ \end{gathered}[/tex]Therefore:
[tex]\sum ^6_{n\mathop{=}1}(n-1)\text{ = 1+2+3+4+5}[/tex]So, the correct option is option C
This is because the sum: 0+1+2+3+4+5 gives the same value as the sum: 1+2+3+4+5
2. Damian is buying movie tickets to a movie. The tickets cost $4.35 per ticket. Damian has $40.00. What is the greatest amount of tickets he can buy?
Answers
Given:
Cost of one ticket is, c = $4.35.
Total amount with Damian is, T = $40.00.
The objective is to find the number of tickets Damian can buy with this total amount.
Consider the number of tickets as x.
The equation for this situation can be represented as,
[tex]\begin{gathered} \text{Total amount=cost per ticket}\times\text{number of tickets } \\ T=c\times x \end{gathered}[/tex]Now, substitute the given values in the above equation.
[tex]\begin{gathered} 40=4.35x \\ x=\frac{40}{4.35} \\ x=9.19 \\ x\approx9 \end{gathered}[/tex]Hence, Damian can buy maximum 9 tickets with total cost of $40.00.
The equation that models Earth's elliptical orbit around the sun is (x+2.5)^2/22,350.25+y^2/22,344=1 in millions of kilometers. If the sun is located at one focus and it’s coordinates are (0,0), find Earth's farthest distance from the sun in millions of kilometers.
Answers
Given the equation of the elliptical orbit is (x+2.5)^2/22,350.25+y^2/22,344=1.
This equation can be written as
[tex]\begin{gathered} \frac{(x+2.5)^2}{22350.25}+\frac{y^2}{22344}=1 \\ \frac{(x+2.5)}{(149.5)^2}+\frac{y^2}{(149.479)^2}=1 \end{gathered}[/tex]Now, if we shift this path by 2.5 units to left then we get
[tex]\frac{x^2}{(149.5)^2}+\frac{y^2}{(149.479)^2}=1[/tex]The farthest distance of the earth from the sun will be 149.5 - 2.5 = 147 million of kilometers
Thus, option C is correct.
What about takes four hours to travel 128 km going upstream and return it takes two hours going down stream what is the rate of the boat in Stillwater and what is the rate of a Current
Answers
Since the rate = distance/time
Since the distance is 128 km
Since the time of upstream is 4 hours
Then the rate of the boat in the still water is
[tex]\begin{gathered} R_s=\frac{128}{4} \\ R_s=32km\text{ per hour} \end{gathered}[/tex]Since the boat took 2 hours downstream, then
The rate of the current is
[tex]\begin{gathered} R_c=\frac{128}{2} \\ R_c=64km\text{ per hour} \end{gathered}[/tex]the graph shows the relationship between the length of time Ted spends knitting and the number of scars he Knits. what does 16 meak in this situation ( ima send a picture of the graph )
Answers
we have the point (1,16)
that means
1 scar
16 hours
is the option C
Which of the following words best completes this sentence? "The real roots of a quadratic equation correspond to the of the graph of the related function."
Answers
This is an example of a quadratic function
The real roots are where it crosses the x axis
Where it crosses the x axis are also called the zeros of the function or the x intercepts. They can also be called the roots of the quadratic.
Without the choices, I am unsure of the words to fill in the blank.
what can you prove congruent from your given
Answers
Answer:
a. line OL bisects angle MLN
b. triangle MLO is congruent to triangle OLN
c. line OL proves that they are congruent through reflexive property.
Step-by-step explanation:
hope this helps!
Complete the table for the given rule. Rule:y is 2 more than 4 times x
Answers
We have been given the relationship between x and y to be
y = 4x + 2
To complete the table, we will substitute the value of x = 0, 2, and 4 into the equation
when x = 0
y = 4 x 0 + 2 = 0+ 2 = 2
when x = 2
y = 4 x 2 + 2 = 10
when x = 4
y = 4 x 4 + 2 = 18
The answer is given below
What is the positive solution for x^3 + 3x - 9 = x -1 + 2x?
Answers
Given:
[tex]\begin{gathered} x^3+3x-9=x-1+2x \\ x^3+3x-9=3x-1 \\ x^3+3x-3x=-1+9 \\ x^3=8 \\ x^3=2^3 \\ \text{Therefore, x=2} \end{gathered}[/tex]Hence, the postive solution for the gven equation is x=2
Round to the nearest whole number(I) 18.32 (li) 224.9 (ili) 3.511
Answers
I
Answer:
18
Explanation:
18.32
To round to the nearest whole number, we would consider the term immediately after the decimal point. If it is greater than or equal to 5, the last term before the decimal point increases by 1. If it is less than 5, the last term remains the same. In this case, 3 is less than 5. Thus, 8 remains the same. Thus, to the nearest whole number, the answer is
18
Simplify (3.8 x 10^-2)(5.14 x 10^-10). Write the final answer in scientific notation.
Answers
Answer:
1.9532×10⁻¹¹
Step-by-step explanation:
You want the product (3.8 × 10^-2)(5.14 × 10^-10) in scientific notation.
ProductThe product is computed in the usual way, making use of the rules of exponents.
(3.8 × 10^-2)(5.14 × 10^-10) = (3.8×5.14) × (10^-2)(10^-10)
= 19.532 × 10^(-2-10) = 19.532 × 10^-12
Moving a factor of 10 from the coefficient to the exponent gives ...
= 1.9532×10^-11 . . . . . . final answer in scientific notation
__
Additional comment
Scientific notation has 1 digit to the left of the decimal point in the coefficient.
Here, we had to divide by 10 to put the coefficient decimal point in the right place. To keep the number at the same value, we had to increase the exponent of 10 by 1 from -12 to -11.
Your calculator can display the product in scientific notation for you, as can any spreadsheet.
Sometimes it is convenient to adjust the exponents before the multiplication. Here, you can see the product of the coefficients will be greater than 10, so will ultimately need to be divided by 10. One way to get there is rewriting the problem as (0.38×10^-1)(5.14×10^-10). This will give a product coefficient between 1 and 10 with an exponent of -11.
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please help me find ALL of the questions this thing is asking :). Non helping (just to obtain points) questions will be reported.
Answers
Elizabeth wraps a gift box in the shape of a square pyramid. The figure below shows a net for the gift box. 6 in 6.8 in
Answers
The wrapping paper used by Elizabeth is equal to the area of the square pyramid which is 127.84 in.².
Dimension of the square base:
Side = 6.8 in.
Area of the base = 6.8 in. × 6.8 in.
A = 46.24 in.²
Dimension of the triangle:
Base = 6.8 in.
Height = 6 in.
Area of 1 triangle = 1/2 × 6.8 in. × 6 in.
A (triangle) = 20.4 in.²
Area of 4 triangles = 4 × 20.4 in.²
A' = 81.6 in.²
Total area of the square pyramid = A + A'
T = 46.24 in.² + 81.6 in.²
T = 127.84 in.²
Therefore, the wrapping paper used by Elizabeth is equal to the area of the square pyramid which is 127.84 in.².
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Your question is incomplete. Please refer the content below:
Elizabeth wraps a gift box in the shape of a square pyramid.
The figure below shows a net for the gift box.
How much wrapping paper did she use?
(a)The perimeter of a rectangular garden is 306m.If the width of the garden is 69m, what is its length?Length of the garden: m (b)The area of a rectangular window is 6364cm2.If the length of the window is 86cm, what is its width?Width of the window: cm
Answers
Answer
The length of the garden = 84 m
Explanation
Part (a)
The given parameters are:
Perimeter of the rectangular garden = 306 m
The width of the garden = 69 m
The length of the garden = ?
Solution:
Using the formula for the perimeter of a rectangle:
[tex]\begin{gathered} Perimeter=2(Length+Width \\ \\ 306m=2(L+69m) \\ \\ Divide\text{ }both\text{ }sides\text{ }by\text{ }2 \\ \\ \frac{306m}{2}=\frac{2(L+69m)}{2} \\ \\ 153m=L+69m \\ \\ L=153m-69m \\ \\ L=84\text{ }m \end{gathered}[/tex]The length of the garden = 84 m
Part (b):
The given parameters are:
The area of the rectangular window = 6364 cm²
The length of the window = 86 cm
The width of the window = ?
Solution:
The width of the rectangular window can be calculated using the formula for the area of a rectangle.
[tex]\begin{gathered} Area=Length\times Width \\ \\ 6364cm^2=86cm\times W \\ \\ Divide\text{ }both\text{ }sides\text{ }by\text{ }86cm \\ \\ \frac{6364cm^2}{86cm}=\frac{86cm\times W}{86cm} \\ \\ W=74\text{ }cm \end{gathered}[/tex]The width of the window = 74 cm
in circle R, mCB=73° and mAD=57° what is M
Answers
The measure of the angle ∠CEB is 65°.
We are given a circle. The center of the circle is denoted by R. There are two chords, AB and CD. The point of intersection of the chords is E. The angles subtended by the arcs CB and AD are 73° and 57°, respectively. We have to find the measure of the angle ∠CEB. We can see that there is no direct relationship between the angles, but it is certain that the angle ∠CEB lies between the measures of angles subtended by the two arcs. So, we can write it in the form of an inequality. The measure of the angle ∠CEB is more than 57° but less than 73°. We can take the average value of these angles as an approximation. The average is (57° + 73°)/2 = 65°.
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hi I don’t understand this question,can u do it step by step? Thanks!
Answers
The rule of the division of differentiation is
[tex]\frac{d}{dx}(\frac{u}{v})=\frac{u^{\prime}v-uv^{\prime}}{v^2}[/tex]The given function is
[tex]y=f(x)=\frac{x^2+3x+3}{x+2}[/tex]a)
Let u the numerator and v the denominator
[tex]\begin{gathered} u=x^2+3x+3 \\ u^{\prime}=2x+3 \end{gathered}[/tex][tex]\begin{gathered} v=x+2 \\ v^{\prime}=1 \end{gathered}[/tex]Substitute them in the rule above
[tex]\begin{gathered} \frac{dy}{dx}=\frac{(2x+3)(x+2)-(x^2+3x+3)(1)}{(x+2)^2} \\ \frac{dy}{dx}=\frac{2x^2+7x+6-x^2-3x-3}{(x+2)^2} \\ \frac{dy}{dx}=\frac{x^2+4x+3}{(x+2)^2} \\ \frac{dy}{dx}=\frac{(x+3)(x+1)}{(x+2)^2} \end{gathered}[/tex]We will differentiate dy/dx again to find d^2y/dx^2
[tex]\begin{gathered} u=x^2+4x+3 \\ u^{\prime}=2x+4 \end{gathered}[/tex][tex]\begin{gathered} v=(x+2)^2=x^2+4x+4 \\ v^{\prime}=2x+4 \end{gathered}[/tex]Then substitute them in the rule above
[tex]\begin{gathered} \frac{d^2y}{dx^2}=\frac{(2x+4)(x^2+4x+4)-(x^2+4x+3)(2x+4)}{(x^2+4x+4)^2} \\ \frac{d^2y}{dx^2}=\frac{(2x+4)\lbrack x^2+4x+4-x^2-4x-3\rbrack}{(x^2+4x+4)^2} \\ \frac{d^2y}{dx^2}=\frac{(2x+4)\lbrack1\rbrack}{(x^2+4x+4)^2} \\ \frac{d^2y}{dx^2}=\frac{(2x+4)}{(x+2)^4} \\ \frac{d^2y}{dx^2}=\frac{2(x+2)}{(x+2)^4} \\ \frac{d^2y}{dx^2}=\frac{2}{(x+2)^3} \end{gathered}[/tex]b)
The turning point is the point that has dy/dx = 0
Equate dy/dx by 0 to find the values of x
[tex]\begin{gathered} \frac{dy}{dx}=\frac{(x+3)(x+1)}{(x+2)^2} \\ \frac{dy}{dx}=0 \\ \frac{(x+3)(x+1)}{(x+2)^2}=0 \end{gathered}[/tex]By using the cross multiplication
[tex]\begin{gathered} (x+3)(x+1)=0 \\ x+3=0,x+1=0 \\ x+3-3=0-3,x+1-1=0-1 \\ x=-3,x=-1 \end{gathered}[/tex]Substitute x by -3 and -1 in f(x) to find y
[tex]\begin{gathered} f(-3)=\frac{(-3)^2+3(-3)+3}{-3+2} \\ f(-3)=\frac{3}{-1} \\ y=-3 \end{gathered}[/tex][tex]\begin{gathered} f(-1)=\frac{(-1)^2+3(-1)+3}{-1+2} \\ f(-1)=\frac{1}{1} \\ y=1 \end{gathered}[/tex]The turning points are (-3, -3) and (-1, 1)
c)
To find the inflection point equate d^2y/dx^2 by 0 to find x
[tex]\begin{gathered} \frac{d^2y}{dx^2}=\frac{2}{(x+2)^3} \\ \frac{d^2y}{dx^2}=0 \\ \frac{2}{(x+2)^3}=0 \end{gathered}[/tex]By using the cross multiplication
[tex]2=0[/tex]Which is wrong 2 can not be equal to zero, then
NO inflection point for the curve
d)
Since the denominator of the curve is x + 2, then
Equate it by 0 to find the vertical asymptote
[tex]\begin{gathered} x+2=0 \\ x+2-2=0-2 \\ x=-2 \end{gathered}[/tex]There is a vertical asymptote at x = -1
Since the greatest power of x up is 2 and the greatest power of down is 1, then there is an Oblique asymptote by dividing up and down
[tex]\begin{gathered} \frac{x^2+3x+3}{x+2}=x+1 \\ y=x+1 \end{gathered}[/tex]The Oblique asymptote is y = x + 1
No horizontal asymptote
e)
This is the graph of y = f(x)
This is the graph of y = f(IxI)
f)
For the curve
[tex]y=\frac{x^2-3x+3}{2-x}[/tex]Take (-) sign as a common factor down, then
[tex]\begin{gathered} y=\frac{(x^2+3x+3)}{-(-2+x)} \\ y=-\frac{(x^2-3x+3)}{(x-2)} \end{gathered}[/tex]Since the sign of y is changed, then
[tex]y=-f(x)[/tex]Then it is the reflection of f(x) about the y-axis we can see it from the attached graph
The red graph is f(x)
The purple graph is -f(x) which is the equation of the last part
There were 24 dinner tables with 8 chairs at each table.Each dinner ticket cost $12.50. If 3/4 of thr dinner tables were full,how much money was raised from the dinner ticket sales?
Answers
we have the next information
24 dinner tables
each has 8 chairs
First we need to calculate 3/4 of the tables
24 mesas ----- 4/4=1
x ----- 3/4
x = the number of tabl
Below is a sample space for a family with 3 children. BGG stands for the oldest child being a boy, the middle child a girl, and the youngest a girl. Use the sample space to answer the question: What is the probability (in simplest form) that the oldest child is a a girl? _____Sample Space BBB BBG BGB BGG GBB GBG GGB GGG
Answers
The probability that the oldest child is a girl is given by the quotient between two numbers:
- The number of combinations where a girl is the oldest child i.e. the number of elements in the sample space that start with a G.
- The total number of elements in the sample space.
The first number is 4 since we have 4 elements starting with G: GBB, GBG, GGB, GGG. The second number is 8. Therefore the probability that we are looking for is given by:
[tex]P=\frac{4}{8}=\frac{1}{2}[/tex]AnswerThen the answer is 1/2.
David and Victoria are playing ths integer card game. David drew three cards, -6, 12, and -4. What is the sum of the cards in his hands? Model your answer on the number line below. PLEASE HELP. Brainliest, will give.
Answers
The sum of -6 ,12 and -4 is,
[tex]\begin{gathered} S=-6+12-4 \\ S=2 \end{gathered}[/tex]Express it on number line implies,
The length of a 12 foot by 8 foot rectangle is increasing at a rate of 3 feet per second and the width is decreasing at 2 feet per second (a) How fast is the perimeter changing? (b) How fast is the area changing?
Answers
The rate of change of the perimeter of this rectangle is equal to 2 feet per second.
The rate of change of the area of this rectangle is equal to 20 feet per second.
How to calculate the perimeter of a rectangle?Mathematically, the perimeter of a rectangle can be calculated by using this formula;
P = 2L + 2W
Where:
P represents the perimeter of a rectangle.L represents the length of a rectangle.W represents the width of a rectangle.The rate of change for the perimeter of this rectangle is given by:
P = 2L + 2W
Differentiating with respect to t, we have:
dP/dt = 2dl/dt + 2dw/dt
Substituting the given parameters into the formula, we have;
dP/dt = 2(3) + 2(-2)
dP/dt = 6 - 4
dP/dt = 2 feet per second.
For the rate of change of the area of this rectangle, we have:
dA/dt = ldw/dt + wdl/dt
dA/dt = 8(-2) + 12(3)
dA/dt = -16 + 36
dA/dt = 20 feet per second.
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Determine the inverse of the function by interchanging the variables and solving for y in terms of X
Answers
We are required to find the inverse of the function
The first step is to interchange the variable x for y
[tex]x=\frac{y}{2}-\frac{3}{2}[/tex]The next step is to make y the subject of the formula
[tex]\begin{gathered} x=\frac{y}{2}-\frac{3}{2} \\ \frac{y}{2}=x+\frac{3}{2} \\ \text{ Multiply the equation throughout by 2} \\ y\text{ = 2x + 3} \end{gathered}[/tex]The answer is y = 2x + 3
Melissa won a week-long cruise in a contest and is working out the details of the trip. She can choose from 4 destinations and 5 departure dates. Since each cruise lets passengers pick one of 5 different day trips, Melissa also needs to choose one of those. How many different cruises can Melissa plan?
Answers
To solve this problem, it is necessary to use the fundamental counting principle, which is the multiplication counting rule.
It says that if we have two events, a and b. The total number of possible outcomes will be a times b (a*b).
In this case, a are the destinations she can choose and b are the departure dates. To find how many cruises can she plan, multiply the number of options of a and b, this is 4*5:
[tex]4\cdot5=20[/tex]In this case, she can plan 20 different cruises.
write as a product:y raised to the 3 - y raised to the 5
Answers
We will have the following:
[tex]y^3-y^5=y^3(1-y^2)[/tex]***Explanation***
In order to solve we factor the common values.
We can see that the smallest exponent is 3 and if we subtract y^3 from both values we will have that
[tex]y^3-y^5=y^3\cdot1-y^3\cdot y^2[/tex]So, we can see that they share the same common value, thus:
[tex]y^3(1-y^2)[/tex]We also must remember that:
[tex]y^a\cdot y^b=y^{a+b}[/tex]