a 13.7 g sample of a compound exerts a pressure of 2.01 atm in a 0.750 l flask at 399k. what is the molar mass of the compound

(a) The number of molecules of gas in the container will be 4.1583 x 10⁻⁵ moles

(b) The moles of gas remaining in the container will be 1.231482x 10⁻²⁰ moles

For a

Volume of gas = 1.0 x 10⁻⁶ m³

Temperature of gas = 20 °C or 293 K

Pressure = 1.013 x 10⁵ Pa

R = 8.3143 J/mol.K

We will calculate the number of molecules from the ideal gas equation.

    PV = nRT

Rearrange the equation for the number of moles

    n= PV / RT

Put the values

    n = (1.013 x 10⁵ Pa) (1.0x10⁻⁶ m³) / ((8.3143 J/mol.K) (293 K))

    n = 4.1583 x 10⁻⁵ moles

For b

Volume of gas = 1.0 x 10⁻⁶ m³

Temperature of gas = 20 °C or 293 K

Pressure = 1.0 x 10⁻¹¹ pa

We will calculate the number of moles from the ideal gas equation.

    PV = nRT

Rearrange the equation for the number of moles

   n = PV / RT

   n = (3.0 x 10⁻¹¹ Pa) (1.0 x 10⁻⁶ m³) / (8.3143 J/mol.K) (293 K)

   n = 1.231482 x 10⁻²⁰ mol

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The molecular formula is C₂H₄O₂ when molecular weight is 180 g having empirical formula of CH₂O.

The compound's empirical formula is CH₂O, which contains two hydrogen atoms and one oxygen atom for every carbon atom.

CH₂O has a mass of 30 (=12+2*1+16).The molecule has a molecular weight of about 180.As a result, the supplied molecule has the molecular formula C₆H₁₂O₆.

What is the chemical structure of the equation for water, CH₂O?

A substance that is organic and has a molar mass pf 60 grams / mole as well as an empirical formula of CH₂O also has a molecular formula or C₂H₄O₂.

How much CH₂O is in a mole?

A mol of CH₂O has a molar mass of 30.026 g.

The periodic chart must first be used to estimate its atomic mass of the each element in the compound.

Therefore, the molecular formula is C₂H₄O₂ with the empirical formula of CH₂O.

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The transition metals that are paramagnetic but can easily form ferromagnetic alloys with other metals are Iron, Cobalt, and Nickel.

Hence, the correct option is C: Transition metals in groups 8-10, periods 4 and 5.

Paramagnetic substances are substances that are weakly attracted to magnets. The atoms of paramagnetic substances contain electrons that mostly spin in the same direction. They include aluminum, gold, and copper.

Ferromagnetic substances are substances that are strongly attracted to magnets when placed near magnets. They include metals such as Iron, Cobalt, and Nickel.

Transition metals are metals that have partially filled D-orbitals. Hence, transition metals are paramagnetic as well as ferromagnetic.

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Answer:  C) Transition metals in groups 8-10, periods 4

Explanation:

The entropy of the system of bodies increases during the spontaneous process of heat being transferred from colder to hotter bodies.

Entropy-Entropy is a measure for energy quality, with a lower value indicating higher quality. Lower entropy energy is energy that has been precisely organized. Chaotic energy storage results in high entropy.

Since every particle and atomic structure accelerates through time and space, entropy is constantly increasing. The second law of thermodynamics results in expressions with inequalities. Entropy cannot be destroyed by any means, at any scale, and thus cannot decrease overall.Entropy is created everywhere and always, increasing overall entropy at any scale, including life processes, open systems, micro-fluctuations, gravity, and entanglement.

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Among the options that correctly describes an ideal gas is a gas that obeys the gas laws under all conditions.

Ideal gas, also known as perfect gas, is a gas that physically complies with the ideal, or general, gas law, a particular idealised relationship between pressure, volume, and temperature. This law states that for a given amount of gas, the sum of the volume V and pressure P is proportional to the absolute temperature T; in equation form, PV = kT, where k is a constant. It is a generalisation that includes both Boyle's law and Charles's law as special cases. Such a relationship is known as a substance's equation of state, and it is sufficient to explain its basic behaviour. The kinetic theory of gases, which makes the assumptions, can be used to derive the ideal gas law.

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The rate of disappearance of xe is 2.50×10-² atm/min.

What is rate of disappearance?

The rate of disappearance can be defined as the speed at which a reactant dissipates after being consumed in the process of the reaction.

2.50×10-² atm/min is the rate of disappearance of xenon(xe), if the initial rate of appearance of xef4 is 2.50 x 10^-2 atm/min

xe+ 2F2⇒ xef4

rate of disappearance of xe= 1( rate of disapperance of xe)

= 1( initial rate of appearance of xef4)

⇒1x= 2.50×10-² atm/min

⇒rate of disappearance of xe= 2.50×10-² atm/min

Therefore, the rate of disappearance of xe is 2.50×10-² atm/min.

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The volume of 3 mL evaporated unknown liquid is calculated to be 1.95 / 30.688 × Molar Mass

The volume in liters that 3 ml of the unknown liquid would occupy when vaporized can be calculated as follows;

as the boiling pressure at 1 atm is 100°C or 373°K and the standard STP temperature = 273°K and STP volume = 22.4 L

first, we calculate the temperature of the unknown as follows;

T = 373 °K ÷ 273°K  

T = 1.37 °K

Density = D = 0.65 g/mL

So,

volume = volume of unknown liquid × D / molar mass × V × T

volume = 3 × 0.65 /  molar mass × 22.4 × 1.37

volume = 1.95 / 30.688 × molar mass

Therefore the volume of 3 mL of the unknown liquid by using the accepted molar mass is 1.95 / 30.688 × molar mass

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Polar solute dissolve in polar solvent and non polar solute dissolve in non polar solvent. Therefore, Ksp for copper (II) hydroxide is 1.58x10⁻¹³.

Solubility shows the extent of solubility of a solute in solvent to make a solution. Solute is substances that is present in small amount. solvent is a substance that is present in large amount. Its SI unit is gram per litre or g/L.

Bond strength affect the solubility of a solute in solvent. weaker the bond strength is, more the solubility is. The weaker bond can be easily broken by water molecule.

pH= -log[H⁺]= 11.15

[H⁺]=7.07×10⁻¹²

[H⁺]×[OH⁻]=10⁻¹⁴

[OH⁻]=10⁻¹⁴÷7.07×10⁻¹²

        =0.141×10⁻²

        =0.00141M

                                                M(OH)[tex]_2[/tex][tex]\rightarrow[/tex]M+²+    2OH⁻

Initial concentration(M)                           0             0

Change in concentration(M)|                 +S           +2S

Equilibrium concentration(M)|                 S               2S

Ksp = [ Cu+² ] [ OH⁻] ²

=(S)(2S)²

=4S³

S= 3.41x10⁻⁵ g/L

Substituting the values, we get

Ksp =4(3.41x10⁻⁵)³

=158.6x10⁻¹⁵

=1.58x10⁻¹³

Therefore, Ksp for copper (II) hydroxide is 1.58x10⁻¹³.

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Ethanol contains a polar O-H Bond, and benzene does not. Ethanol C2H6O and Benzene C6H6

What is Benzene?

The simplest organic, aromatic hydrocarbon is benzene. One of the basic petrochemicals and a naturally occurring component of crude oil is benzoene. It is a colourless liquid with a smell that is similar to gasoline. The chemical benzene is very poisonous and carcinogenic. It is mostly employed in the manufacture of polystyrene.

Although benzene is a material that is formed naturally by volcanoes and forest fires and found in many plants and animals, it is also a significant industrial chemical that is manufactured from coal and oil. In its purest form, benzene is a transparent liquid without any color.

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The final temperature of the mixture assuming no heat loss to the surroundings is 311.25 K.

The final temperature of the water mixture is calculated by,  T(final) = (m1 T1 + m2 T2) / (m1 + m2), where m1 and m2 are the weights of the water in the first and second containers, T1 is the temperature of the water in the first container, and T2 is the temperature of the water in the second container.

Let the final temperature be 'T' k

heat lost by 50 g water = heat gained by 30 g water

50*C*(330-T) = 30*C*(T-280)

50*(330-T) = 30*(T-280)

16500 - 50*T = 30*T - 8400

80*T = 24900

T = 311.25 K

Therefore, the final temperature of the mixture is 311.25 K.

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Helium could only persist until the temperature dropped too low for heavier elements to develop.

Due to a bottleneck caused by the lack of a stable nucleus with 8 or 5 nucleons, Big Bang nucleosynthesis created extremely few nuclei of elements heavier than lithium. Additionally, the amount of lithium-7 created during BBN was constrained by this deficiency of bigger atoms.

Before few minutes into the expansion, the early cosmos was too hot for atoms to form. There were only a few minutes left before it was too cold to continue nucleosynthesis and no more elements could start to form.

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The question mentions the Oval window in the human ear. The vibration of oval window and ending with the depolarization of hair cells have a particular order.

The oval window is a connective tissue membrane located at the end of the middle ear and the beginning of the inner ear.

The following events in order starting with the vibration of the oval window and ending with the depolarization of hair cells are given:

1) Oval window vibrates or tip-link proteins open K+ channels

2)  Increased pressure in the perilymph of scala vestibuli

3) Pressure wave depresses basilar membrane

4) Inner hair cells move closer to the tectorial membrane

5) Stereocilia bend

6) K+ ions enter hair cells causing depolarization

Therefore, the vibration of oval window and ending with the depolarization of hair cells have a particular order.

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SDS documents provide information about chemicals used in the lab and where can these documents be found

An SDS is a crucial document that details the risks, safety precautions, and emergency procedures for a specific chemical-containing product. Should overexposure occur, an SDS also describes the appropriate medical or first aid care. The product provider provides SDSs, which are created by the manufacturer.

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As [Zn 2+] molar concentration increases, the E cell decreases. (Solvent of zinc sulphate) With a rise in [Cu 2+] molar concentration, the E cell grows. at various electrolyte concentrations, results.

A solute's molar concentration is the quantity of that solute in one unit of a solution. It can be measured in mol/L, mol/dm 3, or mol/m3. Molar concentration, also called molarity, is indicated by the letter M, or molar. Analyzing the health claims made for sports drinks and providing an overview of electrolytes. In chemistry and physics, an electrolyte is a material that conducts electricity after splitting into positively and negatively charged particles known as ions. Weak Electrolytes: Electrolytes that have not been fully dissolved into the solution.

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The noble gases of Group 8A argon a gas at room temperature and pressure  at room temperature (as the name of the group implies); since they are all unreactive, monatomic elements, their boiling points are extremely low.

The noble gases are, in decreasing order of mass, helium, argon, krypton, xenon, and radon. Since they are so magnificent and don't generally react with anything, they are known as noble gases. Because of this, they are also referred to as inert gases. Noble gases are distinct because, at normal temperature, they are gaseous. The least reactive element, they. Most of the time, they do not mix with other atoms. The noble gases are a group of chemical elements that share many characteristics. They are all monatomic, odourless, colourless gases with very little chemical reactivity under normal conditions. Historically, the term "noble gases" also applied to inert gases.

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The amount of time it takes for half of the radioactive atoms present to decay is known as the radioactive half-life. When a radioisotope changes into another radioisotope, the process is known as radioactive decay, and radiation of some kind is released. The integrated first-order rate law describes radioactivity.

First-order reactions include those in radioactive decay. The rate of decay, also known as activity, of a sample of a radioactive substance is the decrease in radioactive nuclei per unit of time.

The integrated rate rule for the first-order reaction A's products is ln[A] t = -kt + ln[A] 0. An illustration of the natural log of [A] as a function of time is given since this equation has the form y = mx + b.

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Entropy (+ S) increases noticeably when monodentate ligands are replaced by chelating ligands. This is what the Chelate Effect is mostly caused by.

To give one example, the total number of molecules rises from two to three when en takes the place of two ammonia ligands .Just one more molecule is all that is required to accelerate the reaction.

In the aforementioned example, there is only one bidentate ligand in play. The chelate action is further amplified when numerous bidentate ligands are involved or when denticity rises. Think about the two complexation equilibria between ammonia, NH3, and the cobalt (II) ion, Co2+(aq), ethylenediamine (en), on the one hand, and the cobalt (II) ion, Co2+(aq) and en.

the entropy caused by an increase or decrease in the number of freely moving molecules. The number of free molecules in the system rises when a chelating ligand takes the place of multiple monodentate ligands, leading to a sizable increase in entropy. The chelate effect is primarily driven by this energy component.

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At the transition stage, one form of matter starts getting converted into another form of matter.

Solid, liquid and gas are the three phases in which matter occur in nature. Matter is interconvertible in nature i.e it can be converted from one form to another.

Melting, freezing and evaporation are the three phases of transition.

Liquid water at low temperature freezes to form solid ice. This process is known as freezing. Whereas, liquid water when provided high temperature or heat releases vapours. This process is known as evaporation. Solid ice when brought at room temperature gets converted back into liquid water. This process is known as melting.

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25 percentage of a radioactive element will be left after 2 half-life time.

Time = n × t 1/2

After 1 half time time there will be 50 % original isotope and 50% of decay product. After 2 half time 25 % of original isotope and 75 % of decay product is there.

A quantity (of substance half-life )'s (symbol t12) is the amount of time needed for it to decrease to half of its original value. The phrase is frequently used in nuclear physics to refer to how long stable atoms last or how quickly unstable atoms decay radioactively. In a broader sense, the phrase is used to describe any exponential decay (or, very rarely, a non-exponential decay). For instance, the biological half-life of medications and other substances in the human body is discussed in the medical sciences. In exponential growth, doubling time is the opposite of half-life. A characteristic unit for the exponential decay equation, half-life is constant during the course of an exponentially decaying quantity's lifetime. The table below illustrates how a quantity decreases in relation to the number.

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Combining ratio of NaOH and H2SO4 is 2:1

The balanced chemical equation is ;                                              

2NaOH + H2SO4 → Na2SO4 + 2H2O.

Combining ratio is the ratio between moles of reactant required to form products it means how many moles of reactant is required to form product in chemical equation.

Here two moles of sodium hidroxide is required to react with one mole of sulphuric acid to form one moles of sodium sulphate and two moles of water.

So, combining ratio of reactant will be 2:1 and ratio fow product will be 1:2

Hence combining ratio of NaOH and H2SO4 is 2:1

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8.96 is the pH after 15.00 ml of hcl has been added.

What is pH?

The H+ ion concentration's negative logarithm is known as pH

We are aware that not every acid or base reacts with a chemical substance at the same pace. Other people respond extremely strongly, some people mildly, and some people don't react at all. We utilise a universal indicator that exhibits various colours at various concentrations of hydrogen ions in solution to objectively assess the strength of acids and bases

0 mL of NaOH has not been added, leaving a pH of 2.32.

Only HCOOH is present in the solution prior to the addition of any NaOH. The balance of the HCOOH in solution controls pH.

Ka = HCOO- concentration times H3O+ concentration divided by HCOOH concentration

8.96 is the pH after 15.00 ml of hcl has been added.

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The highest occupied molecular orbital for nitrogen is 2pπ. In the ground state, there are two electrons present.

What does "highest occupied molecular orbital" refer to?

The highest-occupied molecular orbital for carbon monoxide (CO) is an electron-dense molecular orbital that surrounds the carbon atom. Pi orbitals are the lowest available molecular orbital for CO. The CO molecule's non-bonding molecular orbitals exhibit some minor bonding.

What is the highest electron shell that is occupied?

The valence shell is the highest populated electron shell, and the electrons that inhabit this shell are referred to as valence electrons. The electron configurations of the elements are reflected in their chemical characteristics.

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The highest occupied molecular orbital for nitrogen is 2pπ. In the ground state, there are two electrons present.

The highest-occupied molecular orbital for carbon monoxide (CO) is an electron-dense molecular orbital that surrounds the carbon atom. Pi orbitals are the lowest available molecular orbital for CO. The CO molecule's non-bonding molecular orbitals exhibit some minor bonding.

The valence shell is the highest populated electron shell, and the electrons that inhabit this shell are referred to as valence electrons. The electron configurations of the elements are reflected in their chemical characteristics.

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For dimethylamine:

Acidity (pKa) 10.64

Basicity (pKb) 3.36

What is Buffer Solution?

The buffer solution, a water-based solvent solution, is created by combining a weak acid and its conjugate base, or a weak base and its conjugate acid. They can be diluted or have small amounts of acid or alkali added to them without the pH of the solution altering.

The pH of buffer solutions scarcely changes when a modest quantity of a strong acid or strong base is introduced. They are therefore used to keep the pH level constant.

Consider this for a moment: If the molar ratio of dimethylamine to dimethylammonium chloride were 1:1, pH would be equal to pKa. At that point, you would be at the half-equivalence point. 10.64 would be the pH.

However, you need a buffer whose pH is 10.43. A molar excess of dimethylammonium chloride must thus exist.

Applying the H-H equation

pH equals pKa plus log ([[base]/[salt]])

10.43 = 10.64 + log ([base[/salt]) log ([base[/salt]) = 10-43 - 10.64 log ([base]/[salt]) = -0.21 log ([base]/[salt]) = 10-0.21 log ([base]/[salt]) = 0.62

The buffer has to be made by combining 1.0mol of dimethylammonium chloride and 0.62mol of dimethylamine.

Mass to volume as necessary:

Dimethylammonium chloride, molar mass 81.55g/mol

Molar mass of dimethylamine is equal to 45.08g/mol minus 0.62mol, or 27.95g.

Dimethylamine to dimethylammonium chloride mass ratio is 81.55 to 27.95.

OR Ratio is 2.92:1.0 (81.55/27.95).

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Photosynthesis is a process that occurs in autotrophs, or organisms that can produce their own food. This process uses light energy from the sun to convert carbon dioxide and water into glucose and oxygen. This process is vital for life on Earth, as it is the primary source of energy for many organisms.

Photosynthesis is a chemical process that occurs in autotrophs, or organisms that can produce their own food. This process uses light energy from the sun to convert carbon dioxide and water into glucose and oxygen. The light energy is absorbed by specialized molecules called chlorophyll, which then use the energy to catalyze the conversion of carbon dioxide and water into glucose and oxygen. Photosynthesis is vitally important, as it is the primary source of energy for many organisms and is essential for life on Earth. In addition, photosynthesis provides oxygen to the atmosphere, which is used by other organisms. Without photosynthesis, the Earth would be a very different, much less hospitable place.

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Para product .In organic reactions, multiple substituents can bind with the aromatic ring and according to the number of substituents; we get the mono/di/tri-substituted products.

In phenyl acetate, there is an acetate group present on the benzene ring. Phenyl acetate will undergo nitration reaction to form ortho and para products, as acetate group is an electron donating group. The para product will be the major product as it involves lesser steric hinderance. Phenyl acetate is the ester of phenol and acetic acid. It can be produced by reacting phenol (Which can be produced by decarboxylation of aspirin with acetic anhydride or acetyl chloride.Phenyl acetate can be separated into phenol and an acetate salt, via saponification: heating the phenyl acetate with a strong base, such as sodium hydroxide, will produce phenol and an acetate salt (sodium acetate, if sodium hydroxide were used.

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the initial hydrogen isotopes in a nuclear fusion reaction have more mass than the fusion products.

Powering the Sun and other stars are nuclear fusion process. Two light nuclei combine to form one heavy nucleus during a fusion process. Because the mass of the single nucleus formed is less than the combined mass of the two initial nuclei, energy is released throughout the process. Energy is created from the remaining mass. The reason this happens is explained by Einstein's equation (E=mc2), which says that mass and energy can be transformed into one another. Fusion energy could play a significant role in the creation of energy if scientists can figure out how to use it in Earth-based machinery. Numerous elements from the periodic table can undergo fusion. However, the deuterium-tritium (DT) fusion reaction is of particular interest to scientists studying fusion energy applications. DT fusion generates a neutron and a helium nucleus.

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The final concentration of KOH, HF and KF are 0 M, 1.0 M and 1.0 M respectively.

                  HF ( aq ) + KOH ( aq ) ⟶ KF ( aq ) + H₂O ( l )

Initial conc.   2.0 M       1.0 M            0 M

Final conc.    1.0 M         0 M             1.0 M

When 1.0 M KOH reacts with 2.0 M HF, 1.0 M KOH fully reacted.

we used unity method 1 M KOH = 1 M HF

so 1.0 M KOH reacts with 1.0 M HF to form 1.0 M KF

1.0 M HF remains unreacted.

Therefore, the final solution contains 1.0 M HF and 1.0 M KF. This means that the solution contains equal amounts of weak acid and salt.

Therefore, the final concentrations of KOH, HF, and KF are 0 M, 1.0 M, and 1.0 M, respectively.

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For the post-obit, the Sn1 reaction, depicts the major organic product, identifies the nucleophile, substrate, and leaving grouping, and decides the rate-limiting step.

As shown in the diagram for the following Sn1 reaction, draw the major organic product, identify the nucleophile, substrate, and leaving grouping, and determine the rate-limiting steps.

Select the argument that properly identifies the reaction nucleophile, substrate, and leaving group. (CH3)2COH is the substrate, HCl (hydrochloric acid) is the nucleophile, and OH is the leaving group. (CH3)3COH is the substrate in the reaction, Cl is the nucleophile, and H20 is the leaving group in this reaction.

(CH3)3COH is the substrate, CF is the nucleophile, and OH is the leaving group in the reaction. The charge per unit limiting footsteps.

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