Answers
We will have the following:
First, we can see that the function in the image will have a mother function:
[tex]y=\sqrt[3]{x}[/tex]Where the function has been moved 2 units left, and 2 units down:
[tex]y=\sqrt[3]{x+2}-2[/tex]Now, we known that the function has been expanded on the vertical, so:
[tex]y=a\sqrt[3]{x+2}-2[/tex]Now, we solve for "a" while we replace for a value of the function, we can see that (6, 4) belongs, so:
[tex]\begin{gathered} 4=a\sqrt[3]{6+2}-2\Rightarrow4=a\sqrt[3]{8}-2 \\ \\ \Rightarrow6=2a\Rightarrow a=3 \end{gathered}[/tex]So, the equation of the function will be:
[tex]g(x)=3\sqrt[3]{x+2}-2[/tex]This can be seeing as follows:
Related Questions
What is the length of the side opposite the 30° angle? Explain your reasoning.
Answers
Given the triangle ABC as shown below:
The length of the side opposite the 30° angle is evaluated as follows:
Step 1:
Given that the 30° angle is the focus angle, label the sides of the triangle.
Thus,
[tex]\begin{gathered} \text{where }\theta=30^{\circ} \\ AC\Rightarrow hypotenuse\text{ (the longest side of the triangle)} \\ AB\Rightarrow opposite\text{ (the side opposite the focus angle)} \\ BC\Rightarrow adjacent \\ \text{thus, } \\ AC\text{ = 44} \\ AB\text{ = x (unknown length)} \end{gathered}[/tex]Step 2:
Evaluate the unknown side using trignometric ratios.
By trigonometric ratios,
[tex]\begin{gathered} \sin \theta\text{ = }\frac{opposite}{hypotenuse}=\frac{AB}{AC} \\ \cos \text{ }\theta\text{ = }\frac{adjacent}{hyptenuse}=\frac{BC}{AC} \\ \tan \text{ }\theta\text{ = }\frac{opposite}{adjacent}=\frac{AB}{BC} \end{gathered}[/tex]From the above trigonometric ratios, sine θ is used to evaluate the value of the unknown side.
This because the sine θ gives the ralationship between the hypotenuse and the unknown side of the triangle.
Thus,
[tex]\begin{gathered} \sin \theta\text{ = }\frac{opposite}{hypotenuse}=\frac{AB}{AC} \\ AB\text{ = x} \\ AC\text{ = 44} \\ \theta\text{ = 30} \\ \Rightarrow\Rightarrow\sin 30\text{ = }\frac{x}{44} \\ 0.5\text{ = }\frac{x}{44} \\ \Rightarrow x\text{ = 0.5}\times44 \\ x\text{ = 22} \end{gathered}[/tex]Hence, the value of the unknown side is 22.
Are these triangles congruent? If they are, justify it which congruence statement. If not, say cannot be determined. *
Answers
According to the figure given
We are given triangle GFH and EFH
[tex]\begin{gathered} <\text{ H }\cong\text{ < F} \\ FE\text{ }\cong\text{ GH} \end{gathered}[/tex]Line FE is parallel to line GH
Therefore, the triangles are congruent by side and angle
PLEASE HELP!! ALGEBRA 1 HW I WILL GIVE BRAINLYEST
Answers
Answer:
answer Is -5/2 becouse if the line Is horizontal his equation Is y=k and in this case k= -5/2
Write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator.0.50 : 0.25
Answers
Answer:
2/1
Explanation:
Given the ratio:
[tex]0.50\colon0.25[/tex]Divide both sides by 0.25
[tex]\begin{gathered} \frac{0.50}{0.25}\colon\frac{0.25}{0.25} \\ =2\colon1 \\ =\frac{2}{1} \end{gathered}[/tex]Thus, the ratio as a fraction in simplest form is 2/1.
a line that passes through points (2, 40) and (20, 4)
Answers
Answer
y - 40 = -2 (x - 2)
We can simplify this
y - 40 = -2x + 4
y = -2x + 4 + 40
y = -2x + 44
Explanation
The general form of the equation in point-slope form is
y - y₁ = m (x - x₁)
where
y = y-coordinate of a point on the line.
y₁ = This refers to the y-coordinate of a given point on the line
m = slope of the line.
x = x-coordinate of the point on the line whose y-coordinate is y.
x₁ = x-coordinate of the given point on the line
We need to calculate the slope and to use one of the points given as (x₁, y₁)
For a straight line, the slope of the line can be obtained when the coordinates of two points on the line are known. If the coordinates are (x₁, y₁) and (x₂, y₂), the slope is given as
[tex]Slope=m=\frac{Change\text{ in y}}{Change\text{ in x}}=\frac{y_2-y_1}{x_2-x_1}[/tex](x₁, y₁) and (x₂, y₂) are (2, 40) and (20, 4)
[tex]\text{Slope = }\frac{4-40}{20-2}=\frac{-36}{18}=-2[/tex]Slope = m = -2
(x₁, y₁) = (2, 40)
x₁ = 2, y₁ = 40
y - y₁ = m (x - x₁)
y - 40 = -2 (x - 2)
We can simplify this
y - 40 = -2x + 4
y = -2x + 4 + 40
y = -2x + 44
Hope this Helps!!!
Please help me if you could if you can't I understand. what fractions are equivalent to 2/3 and 7/12 using the least common denominator?
Answers
2/3 ---->8/12
7/12 ----> 7/12
1) Equivalent fractions have the same value proportionally, so let's find out equivalent fractions:
[tex]\frac{2}{3}+\frac{7}{12}[/tex]2) To find equivalent fractions and sum those fractions, let's factorize 3 and 12 dividing them only by Prime Numbers, when one of those numbers can't be divided then we repeat it below:
As we can see on the first line, 12 can be divided by 2 and 3 cannot.
So we repeat 3 on the line below.
We then picked 6 and divided by 2, and then repeated below 3.
Then divided3 by 3
3) Now we can rewrite 2/3 + 7/12 as:
So using the Least Common Denominator we have 2/3 (8/12) and 7/12 (7/12) as their equivalent fractions. Note that 7/12 in this case is equivalent to itself.
Saira is using the formula for the area of a circle to determine the value of .
Answers
For this problem, we just have to use the values we're given to calculate the approximate value of pi.
The formula presented is
[tex]\pi=Ar^{-2}[/tex]When you have a negative exponent, we can use the following property
[tex]a^{-b}=\frac{1}{a^b}[/tex]Using this property, our problem turns out to be
[tex]\pi=\frac{A}{r^2}[/tex]Now, we just need to plug the given values on this equation
[tex]\pi=\frac{50.265}{4^2}=3.1415625\approx3.142[/tex]The approximated value for pi is 3.142.
Hello. I think that I'm overthinking this. I'm pretty sure it's a monomial?
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The expression 5x⁶ - x⁴ is a binomial because we have two terms.
Even if they have the same variable x, their exponents are not the same.
question number 1 and 2 and find measure of. angle 1
Answers
Explanation
Step 1
vertical angles:
Vertical angles are pair angles formed when two lines intersect
[tex]m\measuredangle x=m\measuredangle y[/tex]so, we need to find a vertical angle in
a)
Figure 1:
blue angles are vertical, so
[tex]m\measuredangle HML\text{ and m}\measuredangle JMK[/tex]Figure 2:
hence, a pair of vertical angle is
[tex]\begin{gathered} \\ m\measuredangle LQM\text{ and m}\measuredangle\text{PQN} \end{gathered}[/tex]Step 2
pair of adjacent angles:
Adjacent angles are two angles that have a common vertex and a common side but do not overlap
[tex]m\measuredangle x\text{ is adjacent to m}\measuredangle y[/tex]then
a)
for Figure 1
pair of adjacent angles
[tex]m\measuredangle HMJ\text{ and m}\measuredangle JMK[/tex]b) for Figure 2
pair of adjacent angles
[tex]m\measuredangle LQM\text{ and m}\measuredangle LQR[/tex]I hope this helps you
For what values of k will the sum of the solutions of x^2 - (k^2 - 3k)x + 24=0 be 10?
Answers
The Solution:
Given the equation below:
[tex]x^2-(k^2-3k)x+24=0[/tex]We are required to find the value of k that will make the sum of the solutions to be 10.
Step 1:
Let:
[tex]\begin{gathered} k^2-3k\text{ be represented with b} \\ \text{ So that we have} \\ k^2-3k=b\ldots eqn(1) \end{gathered}[/tex]So, the given equation becomes:
[tex]x^2-bx+24=0[/tex]We shall the Quadratic Formula Method to solve for x in terms of b.
In this case,
[tex]\begin{gathered} a=1 \\ b=-b \\ c=24 \end{gathered}[/tex]Substituting, we get
[tex]x=\frac{-b\pm\text{ }\sqrt[]{(-b)^2-(4\times1\times24)}}{2(1)}[/tex][tex]x=\frac{-b\pm\text{ }\sqrt[]{b^2-96}}{2}[/tex]So, the solutions to the given equation are:
[tex]\begin{gathered} x=\frac{-b+\text{ }\sqrt[]{b^2-96}}{2} \\ \text{ or} \\ x=\frac{-b-\text{ }\sqrt[]{b^2-96}}{2} \end{gathered}[/tex]Equating their sum to 10.
[tex]\begin{gathered} \frac{-b+\text{ }\sqrt[]{b^2-96}}{2}+\frac{-b-\text{ }\sqrt[]{b^2-96}}{2}=10 \\ \\ \\ \frac{-b+\text{ }\sqrt[]{b^2-96}+-b-\text{ }\sqrt[]{b^2-96}}{2}=10 \end{gathered}[/tex]Simplifying, we get
[tex]\begin{gathered} \frac{-2b}{2}=10 \\ \\ -b=10 \end{gathered}[/tex]Substituting for b, we get
[tex]\begin{gathered} -(k^2-3k)=10 \\ k^2-3k=-10 \\ k^2-3k+10=0 \end{gathered}[/tex]Solving for k by the Quadratic Formula method of solving quadratic equation, we get
[tex]k=\frac{-b\pm\text{ }\sqrt[]{b^2-4ac}}{2a}[/tex]Where
[tex]a=1,b=-3\text{ and c=10}[/tex]Substituting, we get
[tex]k=\frac{-(-3)\pm\text{ }\sqrt[]{(-3)^2-(4\times1\times10)}}{2(1)}[/tex][tex]k=\frac{3\pm\text{ }\sqrt[]{9^{}-40}}{2}=\frac{3\pm\text{ }\sqrt[]{-31}}{2}[/tex][tex]\begin{gathered} k=\frac{3+\text{ }\sqrt[]{-31}}{2}\text{ or }k=\frac{3-\text{ }\sqrt[]{-31}}{2} \\ \end{gathered}[/tex]Therefore, the correct answer is
[tex]k=\frac{3+\text{ }\sqrt[]{-31}}{2}\text{ or }k=\frac{3-\text{ }\sqrt[]{-31}}{2}[/tex]Alternatively,
We can use the sum of roots formula below:
[tex]\begin{gathered} \text{ Sum of roots = }\frac{-b}{a} \\ \text{if given a quadratic equation of the form ax}^2+bx+c=0 \end{gathered}[/tex]So, we get
[tex]\begin{gathered} a=1 \\ b=-(k^2-3k) \\ c=24 \end{gathered}[/tex]So,
[tex]\begin{gathered} \text{ Sum=}\frac{--(k^2-3k)}{1}=10 \\ \\ k^2-3k=10 \\ \\ k^2-3k-10=0 \end{gathered}[/tex]Then you can now solve from here as have done in the previous method.
Solve the quadratic equation above for k.
I need help with solving propotional segments in right triangles. I need help with number 4.
Answers
We have
AD=9 in
DB=4 in
find DC,AC and BC
we can do the next equivalences
[tex]\frac{AD}{DC}=\frac{DC}{DB}[/tex][tex]\frac{9}{DC}=\frac{DC}{4}[/tex]then we clear DC
[tex]\begin{gathered} DC=\sqrt[]{36} \\ DC=6 \end{gathered}[/tex]For AC we use the Pythagorean theorem
[tex]AC=\sqrt[]{9^2+6^2}=10.81[/tex]For BC we use the Pythagorean theorem
[tex]BC=\sqrt[]{6^2+4^2}=7.21[/tex]PLEASE just give me the answers and not a whole defintion of every single word. I just want quick answers so I can check my work. *don't worry, this is just a math practice
Answers
7. m and n are parallel because both alternate interior angles are equal.
8.m and n are parallel because Alternate exterior angles are equal.
9.m and n are parallel Because corresponding angles are equal.
10. m and n are parallel because corresponding and consecutive angles are equal.
11. m and n are parallel because alternate exterior angles are equal.
12.m and n are parallel because vertical (opposite) angles are equal.
Mike needs to calculate the angle a rafter makes a with a ceiling joist of a house. The roof has a rise of 5.5 for a run of 12’. What is the angle of the rafter ?
Answers
Let's illustrate the given information.
To determine the angle of this rafter, we can use the tangent function. The formula is:
[tex]\tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}}[/tex]Our angle in the illustration is the one colored in red. The opposite side of the angle measures 5.5 inches while the adjacent side measures 12 inches. Let's plug in this data to the formula above.
[tex]\tan \theta=\frac{5.5}{12}[/tex]To be able to get the measure of angle, let's get the arc tan of the angle.
[tex]\theta=\tan ^{-1}\frac{5.5}{12}\approx24.62[/tex]Hence, the rafter must be angled 24.62 degrees away from the ceiling joist of the house.
Given the dot product w•w = 29, find the magnitude of w.
Answers
Given the dot product expression as shown:
[tex]w\cdot w=29[/tex]Determine the value of 'w"
[tex]w^2=29[/tex]Take the square root of both sides to have:
[tex]\begin{gathered} \sqrt{w^2}=\pm\sqrt{29} \\ w=\pm\sqrt{29} \end{gathered}[/tex]Since we only need the magnitude of "w" and the magnitude is the positive value of the variable, hence;
[tex]|w|=\sqrt{29}[/tex]This gives the modulus of "w"
Find the equation of the line, in slope-intercept form, through (-4, 6)and parallel to y=-3x + 4. (Show work) (3 pts)
Answers
The given equation is
[tex]y=-3x+4[/tex]Notice that this equation represents a line in slope-intercept form, where its slope is -3.
Now, we have to find a new line parallel to the one above, which means the slope of the new line is also 3 because parallel lines have equal slopes.
Then, we use the given points (-4,6) and the slope -3 to find the equation
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-6=-3(x-(-4)) \\ y-6=-3x-12 \\ y=-3x-12+6 \\ y=-3x-6 \end{gathered}[/tex]Therefore, the equation of the parallel line is y = -3x - 6.I need help with this 6-9 should be matched with either A-H
Answers
Explanation
To answer the question, we will make use of some of the properties of a parallelogram
These are
The opposite sides are parallel.
Opposite sides are congruent.
Opposite angles are congruent.
Same-Side interior angles (consecutive angles) are supplementary.
Each diagonal of a parallelogram separates it into two congruent triangles.
The diagonals of a parallelogram bisect each other.
Therefore
For question 6
[tex]\begin{gathered} mTherefore, the answer to question 6 is AQuestion 7
[tex]mThe answer to question 7 is EQuestion 8
[tex]\begin{gathered} DF=FB \\ Diagonals\text{ bisect each other} \\ DF=17 \end{gathered}[/tex]The answer to question 8 is C
Question 9
[tex]\begin{gathered} mThe answer to question 9 is FWrite the nth rule for each geometric sequence.5) 7, 14, 28, 56...
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We have the next numbers
[tex]7,14,28,56[/tex]as we can see we have double of the previous number, so the rule is
[tex]a_n=a_{n-1}\cdot2[/tex]we need to prove the rule
[tex]a1=7[/tex][tex]a2=7\cdot2=14[/tex][tex]a3=14\cdot2=28[/tex][tex]a4=28\cdot2=56[/tex]as we can see the rule is appropriate for the geometric sequence
You earn a salary of $40000 per year and decide to save 20% of your gross pay. You then set a goal of creating $16000 and emergency fund. How long will it take you to achieve your goal?
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Gross pay amount = $40,000
Percentage of the gross pay saved = 20%
Amount of gross pay saved per year = 20% of 40,000
Amount of gross pay saved per year = 20/100 * 40,000
Amount of gross pay saved per year = 20*400 = $8000
This means that $8000 is saved per year.
Next is to calculate the number of years it will take to save $16,000
Let us use the equality postulate;
1 year = $8,000
x year = $16,000
cross multiply
8000x = 16000
x = 16000/8000
x = 2
This means that it will take 2 years for me to achive my goal.
20. A sequence is defined recursivelybelow:+4a, = 8,-1a, = -3Which function can be used to find the nthsequence?
Answers
A)
1) Let's insert the Recursive formula for a:
[tex]\begin{gathered} a_n=a_{n-1}+4 \\ a_1=-3 \\ f(n)=-3\text{ +(n-1)4} \\ f(n)=-3\text{ +4n-4} \\ f(n)=4n-7 \end{gathered}[/tex]When we apply the General formula f(n) we'll need the first term. for that sequence, and then rearrange it we find the function for the nth term of that Arithmetic Sequence.
All we need now is to plug into the formula the nth term we want to find out.
Help please look at the image and also use these terms recursive: f(1) = 2, f(n) = 2*f(n-1). explicit: we need to take 1st term/pattern.
Answers
The explicit formula for a geometric sequence is given by:
[tex]f(n)=f(1)r^{n-1}[/tex]where r is the common ratio of the sequence.
For this sequence the common ratio is 2 and the first term is 2, therefore its explicit formula is:
[tex]f(n)=2(2)^{n-1}[/tex]The recursive formula for a geometric sequence is given by:
[tex]\begin{gathered} f(1) \\ f(n)=rf(n-1) \end{gathered}[/tex]Therefore in this case we have:
[tex]\begin{gathered} f(1)=2 \\ f(n)=2f(n-1) \end{gathered}[/tex]An 8-pack of batteries cost $9.44.what is the price, in dollars , of one battery?A)- $0.85B)- $1.18C)- 1.44D)- 2.36
Answers
In order to determine the cost of only one battery, calculate the quotient in between the cost of 8 batteries over 8:
$9.44/8 = $1.18
Hence, one battery costs $1.18
For the school play, tickets cost $13.50 for adults and $5 for kids under 12. How
many total tickets would someone get if they purchased 6 adult tickets and 22 kids
tickets? How many total tickets would someone get if they purchased a adult tickets
and k kids tickets?
Total tickets, 6 adult tickets and 22 kids tickets:
Total tickets, a adult tickets and k kids tickets:
Answers
Answer
The adult-135 And the Kid-27:
Step-by-step explanation:
13.50 * 10=135
4.50 * 6 =27
In circle O, mPN= 131°. Solve for x if m
Answers
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: state the required theorem
The arc measure is equal to the angle at the center. Arc measure is a degree measurement, equal to the central angle that forms the intercepted arc.
STEP 2: Get the equation
[tex]131^{\circ}=6x+26[/tex]STEP 3: Solve for x
[tex]\begin{gathered} 131=6x+26 \\ 131-26=6x \\ 105=6x \\ \frac{6x}{6}=\frac{105}{6} \\ x=17.5 \end{gathered}[/tex]Hence, the value of x is
If y varies inversely as x and y = 41 when x = 28, find y if x = 27. (Round off your answer to the nearest hundredth.)Answer How to enter your answer (Opens in new window) 6 Pointsy = 0y
Answers
When y varies inversely as x:
[tex]y=\frac{k}{x}[/tex]y= 41 when x=28; uses the given data to find k:
[tex]\begin{gathered} 41=\frac{k}{28} \\ \\ k=41*28 \\ \\ k=1148 \end{gathered}[/tex]Use the next formula to the given variation:
[tex]y=\frac{1148}{x}[/tex]Find y if x=27:
[tex]\begin{gathered} y=\frac{1148}{27} \\ \\ y=42.52 \end{gathered}[/tex]Answer: y=42.52El producto de 2 por la diferencia de x y y
Answers
La diferencia de 'x' y 'y' se puede escribir asi:
[tex]undefined[/tex]Hi,I need help with this I tried and I can’t get the answer
Answers
Given
[tex]12000\div300[/tex]We can decompose the above expression below
Explanation
300 can be decomposed into
[tex]300=100\times3[/tex]Therefore,
Answer:
[tex]12000\div100\div3[/tex]This statement is false or true?Expression that contain one variable can be proven true or false by replacing the variable with a number.
Answers
The statement is false.
An expression has no value of true since it is not an equation.
donuts at Krispy Kreme are always perfectly round. The diameter of the circular donut is 6 inches. Which of the following is closest to the circumference of the donut?
Answers
The circumference of a donut is computed as follows:
[tex]C=\pi\cdot D[/tex]where D is the diameter of the donut. Substituting with D = 6,
[tex]\begin{gathered} C=\pi\cdot6 \\ C=18.85\text{ in} \end{gathered}[/tex]which methods correctly solve for variable x in the equation 3/4 (x - 8)=6?
Answers
SOLUTION
The equation given is
[tex]\frac{3}{4}(x-8)=6[/tex]Step1
Multiply both sides by
[tex]\frac{4}{3}[/tex]We have
[tex]\begin{gathered} \frac{4}{3}\times\frac{3}{4}(x-8)=\frac{4}{3}\times6 \\ \\ x-8=8 \end{gathered}[/tex]Step2
Add 8 to both sides of the equation
[tex]\begin{gathered} x-8+8=8+8_{} \\ x=16 \end{gathered}[/tex]Therefore, the correct method that solves the equation is
5. Multiply both sides by 4/3 and then add 8 to both sides of the equation
similarly,
Distribute 3/4 to (x-8)
[tex]\begin{gathered} \frac{3}{4}(x-8)=6 \\ \frac{3}{4}x-6=6 \end{gathered}[/tex]Then add 6 to both sides
[tex]\begin{gathered} \frac{3}{4}x-6=6 \\ \\ \frac{3}{4}x-6+6=6+6 \\ \frac{3}{4}x=12 \end{gathered}[/tex]Then multiply both sides by 4/3
[tex]\begin{gathered} \frac{3}{4}x\times\frac{4}{3}=12\times\frac{4}{3} \\ \\ x=16 \end{gathered}[/tex]Hence
2. Distribute 3/4 to (x-8), then add 6 to both sides and finally multiply both sides by 4/3
Therefore
Distribute 3/4 to (x-8), then add 6 to both sides and finally multiply both sides by 4/3
and
I’m having trouble with this calculus practice problem Below are the answer options A. -2B. 1C. 3D. The limit does NOT exist
Answers
Given
[tex]\lim _{x\to-3^+}h(x)[/tex]Solution
The limit is tending to -3 from the right, that is why it is written as
[tex]-3^+[/tex]From the graph, we will trace the graph from the right to -3
The final answer is -2