which shows a disaccharide

Explanation:

[tex]H _{2}O _{2(aq)} →H _{2}O _{(l)} + O _{2}(g) \\ solution : 2 \: and\: 2[/tex]

Answer:

It depends on the country you are coming from. For example, the human trafficking laws in the US are different from UK. If you need an essay on this contact me on (irenedavid at g mail dot com)

Explanation:

Answer:  pH is 1.6

Explanation: Explanation: HCl is strong acid and it protolyzes totally:

HCl + H2O  ⇒ H3O+ + Cl-

Concentrations are same:  [H3O+] = c(HCl)

pH = - log[H3O+] = - log(0.025) = 1.60

A.

Particles and energy in a system become more and more disordered.

Answer: The freezing point (in °C) of a 0.743 m aqueous solution of KCI is [tex]2.763^{o}C[/tex].

Explanation:

Given: Molality = 0.743 m

[tex]K_{f}[/tex] for water = [tex]1.86^{o}C/m[/tex]

The equation for dissociation of KCl when dissolved in water is as follows.

[tex]KCl \rightarrow K^{+} + Cl^{-}[/tex]

As it is giving 2 ions. Therefore, Van't Hoff factor for it is equal to 2.

Formula used to calculate the freezing point is as follows.

[tex]\Delta T_{f} = i \times K_{f} \times m[/tex]

where,

i = Van't Hoff factor

[tex]K_{f}[/tex] = molal depression constant

m = molality

Substitute the values into above formula as follows.

[tex]\Delta T_{f} = i \times K_{f} \times m\\= 2 \times 1.86^{o}C/m \times 0.743 m\\= 2.763^{o}C[/tex]

Thus, we can conclude that the freezing point (in °C) of a 0.743 m aqueous solution of KCI is [tex]2.763^{o}C[/tex].

Explanation:

Molarity = (# of moles)/(# of liters)

= 180 mol MgCl2/60 L

= 3.0M MgCl2

Answer:

oxygen and carbon dioxide.

hope this helps you

Explanation: they could be grouped by how they reproduce or they can be grouped by if there hetero or autotrophic

Answer:

Maximum safe operating temperature = 450 °C

Explanation:

First, the volume of the cylindrical vessel is determined using the formula:

v = πr²h

Radius, r, of stainless steel vessel = width or diameter / 2

r = 39.0 cm / 2 = 19.5 cm

height of vessel = 46.8 cm

volume of cylinder = 22/7 × 19.5² × 46.8 = 55929.343 cm³ = 0.05593 m³

Using the ideal gas equation to calculate the maximum safe temperature

PV = nRT

pressure, P = 5.30 MPa = 5.30 × 10⁶ Pa

R = 8.314 J/mol.K

n = mass of gas/ molar mass of gas

molar mass of SF₆ = 146 g/mol

mass of Sf₆ = 7.20 kg = 7200 g

n = 7200/146 = 49.315 moles

T = PV/nR

T = (5.30 × 10⁶ × 0.05593) / (49.315 × 8.314)

T = 722.98 K

T in °C = 714.98 - 273.15 = 449.83 °C

Therefore, maximum safe operating temperature = 450 °C

Answer:

Ag⁺, Ba²⁺,

Explanation:

We can solve this question using the solubility rules:

When an Halide as Br- is added to a solution, the ions that can be precipitate are Ag⁺, Hg₂²⁺ and Pb²⁺.

That means the first ion present is Ag⁺

When sulfates, SO₄²⁻ are added, the ions that precipitates are: Ag⁺, Ca²⁺, Sr²⁺, Ba²⁺, Hg₂²⁺ and Pb²⁺

The second ion present is Ba²⁺

Hydroxides of Cu²⁺ and Mn²⁺ are insolubles but as no precipitate are formed when the solution is strongly alkaline those ions are not present.

Answer:

D Fracture

Explanation:

jus took the test

Answer:

Atoms are kind of like building blocks.

Explanation:

Think of atoms as kind of like a mix between paint pigments and legos. The more legos that you have, the bigger the molecule but keep in mind that there are many different kinds of legos that all can come together to build numerous things. I hope that I answered your question and i apoligize if I didn't.

I'm gonna guess E on this one, but I think you should choose either E or A

Answer:

none of the above

Explanation:

A system is said to have attained dynamic equilibrium when the forward and reverse reactions proceed at the same rate. That is;

Rate of forward reaction = Rate of reverse reaction

The implication of this is that the concentrations of reactants and products remain constant when dynamic equilibrium is attained in a system. This does not mean that the reactant and product concentrations become equal; it rather means that their concentrations do not significantly change once dynamic equilibrium has been attained.

Answer:

The gases will expand to a volume of 2.37 L

Explanation:

Gases are able to do work when they expand or compress against an external constant pressure.

This work done by gases when they expand or compress against a constant external pressure is known as pressure-volume work or PV work.

The formula for calculating the work done by gases when they compress or expand against a constant pressure is given as W = PΔV

Where ΔV is change in volume given as V2 - V1

Where V2 is final volume, V1 is initial volume

By convention, W can either be negative or positive. When work is done by the system (ΔV > 0), W is negative and when work is done on the system (ΔV < 0), W is positive.

In the gas mixture above, W = PΔV

Remaining energy, W = (1885 - 311) J = 1574 J

P = 1.036 atm = 1.036 × 760 mmHg = 787.36 mmHg

ΔV = V2 - V1

ΔV = V2 - 0.37

1574 = 1.036 (V2 - 0.37)

V2 - 0.37 = 1574/787.36

V2 - 0.37 = 1.999 L

V2 = 1.999 + 0.37

V2 = 2.369 L

Therefore, the gases will expand to a volume of 2.37 L

Answer:

Option a (100 kPa) is the appropriate option.

Explanation:

The given value is:

Original pressure,

P₁ = 50 kPa

Let the new pressure be "x".

Now,

⇒  [tex]\frac{P1}{T_1} =\frac{P_2}{T_2}[/tex]

On substituting the values, we get

⇒  [tex]\frac{50}{T_1} =\frac{x}{2T_1}[/tex]

On applying cross-multiplication, we get

⇒  [tex]x = 50\times 2[/tex]

⇒     [tex]=100 \ kPa[/tex]

Thus the answer above is the right one.

Answer:

the answer is B:

Explanation:

I hope it help.

Answer:

All of the following statements are true regarding wood versus metal except:

c) Under sustained loads wood stops to deform

Explanation:

Wood is known to deform under stress.  It undergoes warping, thereby, losing its original straight shape when its moisture unevenly dries up.  Even concrete deforms under long-time loads.  Similarly, wood, under sustained loads, experiences faster deformation than it ordinarily warps.  To prevent further wood deformation, it must be treated, and its moisture dried up evenly.

Answer:

[tex]m_{NH_3}=0.0213gNH_3[/tex]

Explanation:

Hello there!

In this case, since it is known that the reaction between ammonia and acetic acid is:

[tex]CH_3COOH+NH_3\rightarrow CH_3COONH_4[/tex]

It is possible for us to realize that the mole ratio of acetic acid (vinegar) to ammonia is 1:1, that is why we can relate the concentrations as follows:

[tex]M_{acid}V_{acid}=M_{base}V_{base}\\\\[/tex]

In such a way, by knowing that the volume of these two are the same, we infer that their concentrations is also de same; and therefore, the mass of ammonia is calculated as:

[tex]m_{NH_3}=0.005L*0.25\frac{molNH_3}{L}*\frac{17.04gNH_3}{1molNH_3}\\\\m_{NH_3}=0.0213gNH_3[/tex]

Regards!

Answer:

A.

Explanation:

They'd probably want to know the conditions that usually produce fog

Answer:

solubility

Explanation:

Answer:d

Explanation:

Answer:

SO2

Explanation:

Dipole-Dipole exist between parmanent dipoles in a molecule. THis means that molecule must have a parmanent dipole moment in it.

Example - HCl

Hydrogen bonding is an attraction between lone pair of an electronegative element and H atom of same or different molecule. H must be covalantly attached to either F, N or O.

Example - H2O

Among the molecules given in the list only SO2 and H2O exihibits parmanent moment. As BCl3 , CBr4 and H2 are symmetric compounds.

Since, SO2 cannot exihibit H- bonding only dipole-dipole forces as its strongest intermolecular force.

The question is incomplete, the complete question is;

The rate of reaction was measured during a chemical reaction. After the first 3 seconds, the rate of reaction was 1.8 x10−6 M/s. Which of the following would you expect after another 3 seconds? a

The rate would be higher, and the concentration of reactants would be lower.

b

The rate would be higher, and the concentration of reactants would be higher.

c

The rate would be lower, and the concentration of reactants would be lower.

d

The rate would be lower, and the concentration of reactants would be higher.

Answer:

The rate would be lower, and the concentration of reactants would be lower.

Explanation:

The rate of reaction refers to how quickly or slowly the reactants disappear or the products appear in a given reaction. The rate of reaction depends on the concentration of the reactants. Thus, as concentration decreases with time, the rate of reaction decreases accordingly.

Therefore, reaction rates tend to decrease with time since the concentration of  the reactants decrease with time as the reactants are being converted into products. Thus after three seconds, the rate would be lower, and the concentration of reactants would be lower. Hence the answer above.

Answer:

The rate would be lower, and the concentration of reactants would be higher.

Explanation:

I took the test and i think i got it right

Answer:

B

Explanation:

Hope this helps! sorry if incorrect

Answer:0.074 L

Explanation:

Answer:

P_2 =0.51  atm

Explanation:

Given that:

Volume (V1) = 2.50 L

Temperature (T1) = 298 K

Volume (V2) = 4.50 L

at standard temperature and pressure;

Pressure (P1) = 1 atm

Temperature (T2) = 273 K

Pressure P2 = ??

Using combined gas law:

[tex]\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2} \\ \\ \dfrac{1 *2.5}{298} = \dfrac{P_2*4.5}{273}[/tex]

[tex]0.008389261745 \times 273 = 4.5P_2[/tex]

[tex]P_2 =\dfrac{0.008389261745 \times 273 }{4.5}[/tex]

[tex]P_2 =0.51 \ atm[/tex]

Answer:

B

Explanation:

The appropriate diagram of the question is shown in the first image attached below.

From the diagram, we see the reaction of Cyclopentanol taking place under Tscl pyridine. We are to show the reaction mechanism and determine from the options, which appropriate product fits in.

So, from the reaction, the hydroxyl substituent reacts with Tscl where cl is being lost. This process is followed by an attack of N substituent on the pyridine with the Hydrogen atom and cleaves off for the structure to form a stable structure. The stereochemistry of the compound remains unchanged and it maintains its stick formula.

Thus, X is the appropriate and the correct product.