Which of the qqq-values satisfy the following inequality?6−3q≤16−3q≤16, minus, 3, q, is less than or equal to, 1Choose all answers that apply:Choose all answers that apply:(Choice A)Aq=0q=0q, equals, 0(Choice B)Bq=1q=1q, equals, 1(Choice C)Cq=2q=2q, equals, 2

Which Of The Qqq-values Satisfy The Following Inequality?63q163q16, Minus, 3, Q, Is Less Than Or Equal

Answers

Answer 1

Given -

6 - 3q ≤ 1

To Find -

The q-values that satisfy inequality =??w

Step-by-Step Explanation - ion

We will check for each of the given values;

A) q = 0

Putting q = 0, we get:

6 - 3(0) ≤ 1

6 ≤ 1

But, Six is greaterr than onee

So, this is the incorrect option.

B) q = 1

Putting q = 1, we get:

6 - 3(1) ≤ 1

3 ≤ 1

But, three is greater than one

So, this is the incorrect option.

C) q = 2

Putting q = 2, we get:

6 - 3(2) ≤ 1

0 ≤ 1

zero is less than one.

So, this is the correct option.

Final Answer -

Option (C) q = 2


Related Questions

Over the summer, Audrey had a job and earned $528. She spent $125.70 on a new bike and $85.09 for some new clothes. How much money does Audrey have left?

Answers

Step 1: Problem

Over the summer, Audrey had a job and earned $528. She spent $125.70 on a new bike and $85.09 for some new clothes. How much money does Audrey have left?​

Step 2: Concept

Word problem on subtraction

Step 3: Method

Audrey total earning = $528

Money spent on new bike = $125.7

Money spent on new clothes = $85.09

Money left = 528 - 125.7 - 85.09

= $317.21

Step 4: Final answer

Audrey money left = $317.21

A builder is buying boxes of nails. She has $187 to spend and each box of nails costs $4. How many boxes of nails can the builder buy?42503746

Answers

To find How many boxes of nails can the builder buy divide the total she has into the cost of each box:

Then, she can buy 46 boxes of nails

unsure about this one tried and couldn’t seem to figure it out

Answers

Given:

The figure contains the rectangle and half-circle.

The perimeter of the half-circle is,

[tex]\begin{gathered} \text{Half}-\text{circle}=\pi r+d \\ r=\frac{d}{2}=\frac{8}{2}=4 \\ \text{Half}-\text{circle}=\pi(4)+8 \\ =3.14\times4+8 \\ =20.56 \end{gathered}[/tex]

The perimeter of the figure is,

[tex]P=10+8+10+20.56=48.56[/tex]

Answer: P = 48.56 ft.

Options for all the three boxes are:neither student, Becky and Laura

Answers

The parent cosine function is given to be:

[tex]f(x)=\cos (x)[/tex]

The graph of this function is shown below:

Laura's Function:

Laura's function is given to be horizontally compressed by a factor of 1/3 and reflected over the x-axis.

The rule for horizontal compression by a factor of 1/a is given to be:

[tex]f(x)\Rightarrow f(\frac{1}{a}\cdot x)[/tex]

and the rule for reflection over the x-axis is given to be:

[tex]f(x)\Rightarrow-f(x)[/tex]

Therefore, Laura's function will be:

[tex]f(x)=-\cos (3x)[/tex]

The graph of the function will be:

Becky's Function:

Becky's function is given to be:

[tex]f\mleft(x\mright)=3\cos \mleft(x-\pi\mright)[/tex]

The graph is given to be:

ANSWERS:

BECKY's GRAPH is the FIRST GRAPH

The SECOND GRAPH belongs to NEITHER

LAURA's GRAPH is the THIRD GRAPH

Challenge The value of a baseball player's rookie card began to increase once the player retired. When he retired in 1996 his card was worth $9.17. The value has increased by $1.65 each year since then, Express the relationship relating the value of the card y in dollars and the number of years x the player has been in retirement with an equation. Is the relationship between x and y proportional? What was the value of the card in 2006? Express the relationship with an equation. y=?

Answers

$151.31. Not proportional.

y= 9.17 +1.65x

1) Gathering the data

1996 Retired $ 9.17

9.17(1.65)^x

2) Since the value of that card has been increasing 1.65 yearly, then we can write the following equation:

[tex]y=9.17+1.65x[/tex]

For y= Value, and x =years

Let's find out the value of the card in 2006, i.e. 10 years later. Plug x=10 into the above function:

[tex]\begin{gathered} y=9.17+1.65x \\ y=9.17+1.65(10) \\ y=9.17+16.5 \\ y=151.305\approx y=151.31 \end{gathered}[/tex]

3) Hence, the value of the card in 2006 is $151.31

(rounded off to the nearest hundredth)

And since the initial value is $9.17, then it is not a proportional relationship since an initial value of a proportional is always 0.

Simplify each expression using Product to a Power Property a. (9a)^2 b. ( 3x)^2

Answers

[tex]\begin{gathered} a)81a^2 \\ b)9x^2 \end{gathered}[/tex]

1) Let's simplify those expressions making use of exponents rules:

[tex](9a)^2=81a^2[/tex]

Note that the exponent outside the parenthesis is 'distributed' over each term inside.

2) Similarly for the second expression we can state that:

[tex](3x)^2=9x^2[/tex]

Please help me and explain how to find the result

Answers

A family consumes 1.2kg of rice a day

If the family have 30ky of rice

Let the number of days be x

The minimum number of days required for the amount of rice remaining not to be more than 6kg can be expressed below as

[tex]30-1.2x\le6[/tex]

Solve for x by collecting like terms

[tex]\begin{gathered} 30-1.2x\le6 \\ 30-6\le1.2x \\ 24\le1.2x \\ 1.2x\ge24 \\ \text{Divide both sides by 1.2} \\ \frac{1.2x}{1.2}\ge\frac{24}{1.2} \\ x\ge20\text{ days} \end{gathered}[/tex]

Hence, the minimum number of days required for the amount of rice remaining not to be more than 6kg is 20 days

The total annual sales for Herman's Hardware Store was $1,246,135 and the total accounts receivable was $41,728. What was the average collection period to the nearestwhole day?12 days14 days18 days24 daysNone of these choices are correct.

Answers

The average collection Period formula is

[tex]\text{Average collection period=}\frac{Account\text{ receivable}}{\frac{Annual\text{ sales}}{365}}[/tex][tex]\begin{gathered} \text{Annual sales=\$1,246,135} \\ \text{Account receivable =\$41,728} \end{gathered}[/tex]

Substitute the values above in the average collection period

[tex]\begin{gathered} \text{Average collection period =}\frac{41728}{\frac{1246135}{365}} \\ =\frac{41728}{3414.06} \\ =12.222 \\ \approx12days \end{gathered}[/tex]

Hence the average collection period to the nearest whole day is 12 days

What is the perimeter of the figure2x + 3 inchesX- 6 inches

Answers

Perimeter of the figure = 6x - 6

Explanation:

Perimeter = 2(length + width)

length = 2x + 3 inches

width = x- 6 inches

Perimeter = 2(2x + 3 + x- 6)

collect like terms in the bracket:

= 2(2x +x + 3 - 6)

= 2(3x - 3)

Expand the bracket:

Perimeter = 2 × 3x + 2× -3

Perimeter of the figure = 6x - 6

what is (x + 5)(2× - 3) = 0 in expanded form??

Answers

(x + 5)(2x -3) = 0

2x² - 3x + 10x - 15 = 0

2x² + 7x - 15 = 0

Answer:

2x² + 7x - 15 = 0

question will be in picture

Answers

Consider the guven system of equations,

[tex]\begin{gathered} x-y=-1 \\ 2x+y=4 \end{gathered}[/tex]

It is asked to find the correct graph which represent the solution of this system.

Logic: Find the solution and see which graph gives the same solution.

Add the equations,

[tex]\begin{gathered} (x-y)+(2x+y)=-1+4 \\ 3x+3 \\ x=1 \end{gathered}[/tex]

Substitute this value in the first equation,

[tex]\begin{gathered} 1-y=-1 \\ y=1+1 \\ y=2 \end{gathered}[/tex]

Thus, the given system has a unique solution (1,2).

Now, observe that only the graph given in option (c) shows the line intersecting at point (1,2).

Therefore, option (c) is the correct choice.

what does ☆ equal if the symbols below represents digits 0-9?

Answers

First, let's start from the sixth equation.

Since the parallelogram divided by the circle is equal the parallelogram, it means the circle has a value of 1.

Then, from the 7th equation, the pentagon minus the arrow is equal the pentagon, it means the arrow is equal 0.

From the 8th equation, the two curved arrows summed are equal 10, so the curved arrow is equal 5.

From the 2nd and 4th equations we can find that the triangle is equal 2.

Using the value of the pentagon from the 4th equation in the 3rd one, we have that 3 * moon is equal parallelogram, so the only option is:

moon = 3, pentagon = 6, parallelogram = 9.

From the 1st equation, the square is equal 8.

Finally, from the 5th equation, the arrow with circle is equal 7.

So we have:

pentagon = 6

parallelogram = 9

moon = 3

triangle = 2

arrow = 0

curved arrow = 5

arrow with circle = 7

circle = 1

square = 8

So the star is the missing algarism: 4

if y=3x+4 and y=2x+8, find the value of both x and y.

Answers

[tex]\begin{cases}y=3x+4 \\ y=2x+8\end{cases}\rightarrow3x+4=2x+8\rightarrow3x-2x=4\rightarrow x=4[/tex]

having that x=4, we get that

[tex]y=2\cdot4+8=16[/tex]

The diameters of ball bearings are distributed normally. The mean diameter is 125 mm and the standard deviation is 3 mm. Find the probability that the diameter of a selected bearing is greater than 127 mm. Round your answer to four decimal places.

Answers

Explanation

Given that the mean diameter is 125 mm and the standard deviation is 3 mm. We can find the probability that the diameter of a selected bearing is greater than 127 mm below.

We will first find the z score of the given value.

[tex]z=\frac{x-\mu}{\sigma}=\frac{127-125}{3}=\frac{2}{3}=0.66667[/tex]

Using the z score calculator,

[tex]P\left(x>127\right)=0.2525[/tex]

Answer: 0.2525

Solve for t and graph the solution.|t+ 4| < 2

Answers

The solution to the inequality is (-6, -2). The graph of the solution is attached below.

We are given an inequality. The inequality consists of a variable "t" and it also uses the modulus function. A function connects an input with an output. It is analogous to a machine with an input and an output. And the outcome is somehow connected to the input. The inequality is |t + 4| < 2. We can solve the inequality by expanding the modulus operator. The inequality becomes -2 < (t + 4) < 2. Now we will subtract 4 from all the sides in the inequality. The inequality is solved as -6 < t < -2. The interval notation for the solution is (-6, -2). The graph is attached below.

To learn more about modulus, visit :

https://brainly.com/question/13103168

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selecting among the numbers 1 through 8 and repeating none of them, fill in the boxes below to make the sum as close as possible to one but not equal to one

Answers

We need ti fill in the boxes below, selecting among the numbers 1 through 8 and repeating none of them to make the sum as close as possible to 1 but not equal to 1.

First fraction could be 1/2

Now, the second fraction should be closer to 1/2 to make the sum as close as possible to 1, but not equal to 1.

We know that 3/6 = 1/2

So, 3/7 would be closer to 1/2

Therefore, the boxes could be filled as;

[tex]\frac{1}{2}+\frac{3}{7}[/tex]

..

Side PV measures 35 meters. Find the value of VT rounded to thenearest tenth if necessary.

Answers

By definition,

sin(angle) = opposite/hypotenuse

From the picture,

sin(60°) = VT/PV

√3/2 = VT/35

√3/2*35 = VT

30.3 meters = VT

In which quadrant, or on which axis, does the terminal side of angle (- 100straight pi) lie?

Answers

The given angle is

[tex]\theta=-\frac{100}{\pi}[/tex]

First, we have to transform this angle into degrees. We know pi=180°, so

[tex]\theta=-\frac{100}{180}=-\frac{50}{90}=-\frac{5}{9}=-0.56[/tex]The given angle is placed on the first quadrant.

Assuming that the angle is starting on the positive x-axis.

Help with number one a and b is both parts of number one

Answers

Design A. The garden is 9 ft by 12 ft.

Design B. The garden is a circle of radius 5 ft

Area of garden A:

[tex]A_A=9\times12=108[/tex]

Area of garden B:

[tex]A_B=\pi\left(5\right)^2=25\pi\approx78.54[/tex]

The areas are:

Design A = 108 square ft

Design B ≈ 78.54 square ft

Note: The area of garden B can also be expressed in exact form as 25π square ft

A survey wanted to determine if there was a relationship between the number of joggers who used a local park for exercise and the temperature outside. The data in the table display their findings.Use graphing technology to create a scatter plot of the data.What is the slope of the line of best fit and what does it mean in this context? Is it realistic?

Answers

Step 1

In order to find the slope of the line of the best fit, we must graph the points given.

Step 2

From the image above we can conclude that the equation of the line is;

[tex]y=0.410045x-2.8757[/tex]

The slope is, therefore;

[tex]0.410045[/tex]

The Slope (or Gradient) we call m, represents the change in y-value per unit change in x-value. In the case of this survey, the slope represents the increase in the number of joggers per degree rise in temperature.

From the calculated slope, there are about 0.4 more joggers for every degree rise in temperature. Using whole numbers to represent this, we can multiply the slope by 5:

[tex]0.4\times5=2[/tex]

Therefore, there are 2 more joggers for every 5°F increase in temperature.

The note A has a frequency of 1,760 hertz. The note D has a period of 1,175 hertz. Find theratio of A to D to two decimal places. Express the answer in integer ratio form.

Answers

Ratios

Note A has a frequency of

fa=1,760 Hz

Note D has a period of 1,175 hertz

(the previous data should be frequency, not period)

We are required to find the ratio of A to D. Let's call it r:

[tex]r=\frac{1,760^{\prime}}{1,175}[/tex]

Dividing: r = 1.4978. Rounding to two decimal places:

r = 1.50

Now to express the answer in integer ratio form, we need to simplify the fraction.

First, we divide by 5 up and down:

[tex]r=\frac{352^{\prime}}{235}[/tex]

There are no more common divisors for both numbers, thus the integer ratio form is r = 352/235

The lines represented by the equations y = 1/2x-8 and 2y+4x=10

Answers

The first equation is in slope-intercept form but the second equation is not. Therefore, our first step is to bring 2y+4x=10 into slope-intercept form.

Subtracting 4x from both sides gives

[tex]2y=10-4x[/tex]

finally, dividing both sides by 2 gives

[tex]y=-2x+5[/tex]

Now, that we have the equation in slope-intercept form, let us compare their slopes to see how they relate to each other.

The lines are perpendicular if the slope of one line is negative of the reciprocal of the other.

Now, -2 is negative of the reciprocal of 1/2. Meaning if you take the reciprocal 1/2, then multiply it by -1 you will end up with -2.

Since the slope of a negative reciprocal of each other, the lines are perpendicular.

Question #10: A pizza restaurant sells a personal square pizza (5 inch side) for $4. What should the cost of a large square pizza (12 inch side) be, so that both pizzas cost the same amount per square inch?

Answers

The per square-inch cost of the first kind of pizza is $0.16 to maintain this ratio for 12-inch side pizza the cost must be $23.04.

What are the ratio and proportion?

The ratio is the division of the two numbers.

For example, a/b, where a will be the numerator and b will be the denominator.

Proportion is the relation of a variable with another. It could be direct or inverse.

As per the given,

Cost of first pizza = $4

Area = 5 x 5 = 25 square inch

Per square cost = 4/25 = $0.16

With this ratio,

Cost of 12 inches side = 12 x 12 x 0.16 = $23.04

Hence "The per square-inch cost of the first kind of pizza is $0.16 to maintain this ratio for 12-inch side pizza the cost must be $23.04".

For more information about ratios and proportions,

brainly.com/question/26974513

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J is the midpoint of HK, H has coordinates (5,-3), and J has coordinates (7,3). Find the coordinates of K.The coordinates of K are

Answers

Answer:

The coordinates of K is;

[tex](9,9)[/tex]

Explanation:

We want to find the coordinates of point K.

Given that J is the midpoint of HK and;

H has coordinates (5,-3)

J has coordinates (7,3).

The formula for calculating midpoint is;

[tex]\begin{gathered} x=\frac{x_1+x_2}{2} \\ y=\frac{y_1+y_2}{2} \end{gathered}[/tex]

where x1 and x2 are the x coordinates of the endpoints and y1 and y2 are the y coordinates of the endpoints.

To get the coordinates of one of the endpoints, we have;

[tex]\begin{gathered} x_2=2x-x_1 \\ y_2=2y-y_1 \end{gathered}[/tex]

substituting the given coordinates of the mid point and endpoint;

[tex]\begin{gathered} x_2=2(7)-5 \\ x_2=14-5 \\ x_2=9 \end{gathered}[/tex][tex]\begin{gathered} y_2=2(3)-(-3) \\ y_2=6+3 \\ y_2=9 \end{gathered}[/tex]

Therefore, the coordinates of K is;

[tex](9,9)[/tex]

Write the ratio as a fraction in simplest form without any units.9 gallons to 28 quarts

Answers

Given

The ratio, 9 gallons to 28 quarts.

To find:

The ratio as a fraction in lowest term.

Explanation:

It is given that,

The ratio, 9 gallons to 28 quarts.

That implies,

[tex]\begin{gathered} 9\text{ }gallons\text{ }to\text{ }28\text{ }quarts=\frac{9\text{ }gallons}{28\text{ }quarts} \\ =\frac{9\times4\text{ }quarts}{28\text{ }quarts} \\ =\frac{9}{7} \end{gathered}[/tex]

Hence, the simplest form of the ratio is 9/7.

A bag holds 5.8lb of corn. How many pounds do 2.5 bags hold

Answers

ANSWER:

14.5 pounds

STEP-BY-STEP EXPLANATION:

We know the capacity of each bag, therefore, we can calculate the capacity of 2.5 bags, multiplying by the capacity of one, like this:

[tex]\begin{gathered} c=5.8\cdot2.5 \\ \\ c=14.5\text{ lb} \end{gathered}[/tex]

Which means 2.5 bags contain a total of 14.5 lbs.

how do you dilate with a scale factor of -1/2Coordinates (-2,8)

Answers

Multiply the coordinates by the scale factor.

(-2,8) = (-2x-1/2, 8x-1/2) = (1,-4)

solve for x[tex] \frac{x + 3}{2} + \frac{2x}{7} = 7[/tex]just need some help with this

Answers

Here, we are to calculate for the value of x.

We start by finding the Lowest common multiples of both fractions. The lowest common multiple of both fractions is 14

Now, we can multiply each of the terms in the question by 14. Thus, we have;

14(x + 3)/2 + 14(2x/7) = (7 * 14)

7(x + 3) + 2(2x) = 98

Opening the brackets, we have;

7x + 21 + 4x = 98

Collect like terms;

7x + 4x = 98 - 21

11x = 77

x = 77/11

x = 7

I need help with this

Answers

Ok, so

We have the following expression:

We're going to multiply all terms inside the bracket by "-x", and we obtain:

So, the answer is B.

The function h is defined below.xh (x) =2+5x-- 142x- 81Find all values of × that are NOT in the domain of h.If there is more than one value, separate them with commas.

Answers

We want to find the value of x that is not in the domain of the function;

[tex]h(x)=\frac{x^2+5x-14}{x^2-81}[/tex]

The value of x that will make h undefined is the value that makes the denominator zero.

Therefore;

[tex]\begin{gathered} x^2-81=0 \\ x^2=81 \\ x=\pm9_{} \end{gathered}[/tex]

Therefore, the values not in the domain is +9 and -9

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