STEP-BY-STEP EXPLANATION*
Given information*
[tex]\begin{gathered} \text{The number of moles of NO = 6.00 }\times10^{-2}\text{ moles} \\ \text{The number of moles of Cl2 = 6.7 }\times10^{-3}\text{ moles} \\ \text{The number of moles of NOCl = 4.00 moles} \\ K_c\text{ = 2 }\times10^5 \end{gathered}[/tex]The first step is to write the balanced equation of the chemical reaction*
[tex]2NO_{(g)}+Cl_{(2)(g)}\rightleftarrows2NOCl_{(g)}[/tex]The next step is to write the chemical equilibrium expression for the above reaction*
Which compound BH3 or BO3 would have polar covalent bonds? How do you know?These are the options in photo
To solve this problem, let's find the electronegativity difference that we have between each pair of elements. If we look for the electronegativity of B, H and O we might find these values:
B: 1.5 O: 3.4 H: 2.1
So the two bonds that are present in our molecules have a difference of:
O ---- B = 3.4 - 1.5 = 1.9
H ----- B = 2.1 - 1.5 = 0.6
We have two types of covalent bonds, polar and non-polar. When the electronegativity difference is between 1.5 and 0.4 the bond is covalent polar, when it is less that 0.4 is non-polar and when it is higher than 1.5 it is ionic.
In our case, the electronegativity difference between O and B is 1.9, it seems that it would be an ionic bond. But that's not an option. The difference between H and B is 0.6, the polarity of that bond is weak compared to the polarity of the bond between O and B (if we consider that it is covalent).
So the answer to our problem is the first one:
BO₃ would have polar covalent bonds because
A neutral atom of on element has two electrons
with n=1, eight electrons with n=2, eight electrons
with n=3 and one electron with n =4 and has mass
number of 39. Deduce the following from the above
information
i the atomic number of the element.
is number of neutrons in the nucleus
i total number of s electrons.
iv total number of p electrons .
v the group the element belongs to
A neutral atom of on element has two electrons with n=1, eight electrons with n=2, eight electrons with n=3 and one electron with n =4 and has mass number of 39 then the atomic number of element is 39 and number of neutron in the nucleus is 50 and total number of s electron is 2 and total number of p electron is 8 and the group is 3rd group
Yttrium is a metallic element with atomic number 39 usually included in the rare earth group that occur usually with other rare earth element in minerals and is used especially in phosphorous and YAG laser and alloy etc and element with mass number of 39 is yttrium and the atomic number of element is 39 and number of neutron in the nucleus is 50 and total number of s electron is 2 and total number of p electron is 8 and the group is 3rd group
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Using the Gay-Lussac LawIf I have 7.7 moles of gas at a pressure of 0.09 atm at a temperature of 56 C°, what is the volume of the container that the gas is in?
ANSWER
EXPLANATION
Given that;
The number of moles of the gas is 7.7 moles
The pressure of the gas is 0.09 atm
The temperature of the gas is 56 degrees Celcius
Follow the steps below to find the volume of the gas in the container
Step 1; Convert the temperature to degrees Kelvin
[tex]\text{ T K = t}\degree C\text{ + 273.15}[/tex][tex]\begin{gathered} \text{ T K = 56 + 273.15} \\ \text{ T K = 329.15K} \end{gathered}[/tex]Step 2; Apply the ideal gas equation
[tex]\text{ PV = nRT}[/tex][tex]\begin{gathered} \text{ Recall, that R = 0.08205 L atm mol}^{-1}K^{-1} \\ \text{ 0.09 }\times\text{ V = 7.7 }\times\text{ 0.08205 }\times\text{ 329.15} \\ \text{ 0.09V = 207.95} \\ \text{ Divide both sides by 0.09} \\ \text{ V = }\frac{\text{ 207.95}}{\text{ 0.09}} \\ \text{ V = 2310.58 Liters} \end{gathered}[/tex]Therefore, the volume of the container is 2310.58 liters
4.A gas occupies 8.7L at a temperature of 29.0°c. What is thevolume at 133°C? (Charles Law)
11.7L
Explanations
According to Charles law, the volume of a given mass of gas is directly proportional to its temperature provided that the pressure is constant. Mathematically;
[tex]\begin{gathered} v\alpha T \\ v=kT \\ k=\frac{v_1}{T_1}=\frac{v_2}{T_2} \end{gathered}[/tex]where:
• v1 and v2 are the ,initial and final ,volume
,• T1 and T2 are the, initial and final, temperature
Given the following parameters
v1 = 8.7L
T1 = 29.0°C = 29 + 273
T1 = 302K
T2 = 133+ 273 = 406K
Substitute the given parameters into the formula
[tex]\begin{gathered} v_2=\frac{v_1T_2}{T_1} \\ v_2=\frac{8.7L\times406}{302} \\ v_2=\frac{3532.2}{302} \\ v_2=11.7L \end{gathered}[/tex]Hence the volume of the gas at 133°C is 11.7L
This is a 6 mark question. Please spend some time explaining it, answering it and helping me.
Answer:
Explanation:
Here, we want to explain the factors responsible for the differences in the polymers presented
We proceed as follows:
a) High melting Point
Although the two polymers contain carbon and hydrogen atoms only, the presence of hydrogen bonding in Polymer Y may lead to it having a high melting point compared to Z.
Other factors that can cause this include the presence of double bonds, aromatic groups or the availability of bulky side groups or branches in the polymer molecule Y.
These and more are responsible for the differences
b) Rigidity and Flexibility
This is due to the existence of some degree of rotation around the atoms' valency. Polymer Z would be flexible due to this.
The absence of this in Polymer Y will make this a difficulty
c) Stretching
How entangled the chain of the polymers are could be responsible for the stretching of the polymers. Since polymer Z is easily stretched, there would be a low degree of entanglement in its chain compared to polymer Y.
Adding up all of the _______ of all of the individual atoms within one molecule of a compound will determine the molecular mass of the compound.A) atomic massesB) electronsC) atomic numbersD) protons
1) Subatomic particles. There are three main subatomic particles. These subatomic particles are the protons, the neutrons, and the electrons.
The protons and the neutrons are a lot heavier than the electrons. So, they represent most of the weight of an atom.
The protons and the neutrons added together are what we call the mass number.
The correct answer is option A, atomic masses.
what is the percent composition of h and o in H2O2
Percent compositions:
[tex]\begin{gathered} Hydrogen:\frac{2}{34}\times100=5.9\% \\ \\ Oxygen:\frac{32}{34}\times100=94.1\% \end{gathered}[/tex]A piece of sodium metal reacts completely with water. The hydrogen gas generated is collected over water at 25oC. The volume of the gas is 252mL measured at 1.00atm. Calculate the number of grams of hydrogen that was collected
The mass or number of grams of hydrogen that was collected in the experiment is 0.02 g.
What is the number of moles of hydrogen gas collected at the given conditions of temperature and pressure?The number of moles of hydrogen gas collected at the given conditions of temperature and pressure is calculated using the ideal gas equation as follows:
PV = nRT
Where;
P is pressure = 1.00 atm
V is volume = 252 mL or 0.252 L
n is the number of moles = ?
R is molar gas constant = 0.082 L.atm/K.mol
T is temperature = 273 + 25 K
T = 298 K
n = PV/RT
n = 1 * 0.252 / (298 * 0.082)
n = 0.01 moles
1 mole of hydrogen gas has a mass of 2.0 g
mass of 0.01 moles of hydrogen = 2 * 0.01
Mass of 0.01 moles of hydrogen = 0.02 g
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Based on Table H, what is the vapor pressure of CH3COOH at 90.°C?
A 150 kPa
B 114 kPa
40 kPa
48 k
The equilibrium vapor pressure provides information about the rate of evaporation of a liquid. The vapor pressure of CH₃COOH at 90.°C is 40 kpa.
What is vapor pressure ?
Pressure of vapor or equilibrium the pressure that a vapor exerts on its condensed phases in a closed system when they are in thermodynamic equilibrium with one another at a specific temperature is known as vapor pressure.
It is significant to remember that when a liquid boils, the pressure of its vapor equals the atmospheric pressure. For instance, water's vapor pressure is 1 atmosphere when it boils at sea level since the surrounding pressure is also 1 atmosphere.
Thus, the vapor pressure of CH₃COOH at 90.°C is 40 kpa.
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The mass number is used to calculate the numner of ____ in one atom of an element. In order to calculate the number of neutrons you must subtract the ___ from the ___
The half-life for the first order radioactive decay of lodine - 131 is 8.0 days. After 3 half lives, what percentage of a sample of locine-131)remains?O 50.%O 25%,O 12.5%O 1%
Answer:
12.5 %.
Explanation:
Let's see the half-life formula:
[tex]N(t)=N_0\cdot(\frac{1}{2})^{t\text{/h}}.[/tex]Where N₀ is the initial amount, t is time, and h is the half-life.
We want to know what would be the percentage of a sample of iodine-131 that remains. This is the same that N(t)/N₀, so we have to replace the given data in the formula and multiply it by 100 because it is a percentage.
The half-life of iodine-131 is 8.0 days, and 3 half-lives are equal to 24 days (8.0 x 3 = 24):
[tex]\begin{gathered} \frac{N(t)}{N_0}=(\frac{1}{2})^{t\text{/h}}, \\ (\frac{1}{2})^{24\text{/8}}=(\frac{1}{2})^3=\frac{1}{8}=0.125. \\ We\text{ want the result in percentage, so multiplying by 100}\%,\text{ we obtain:} \\ 0.125\cdot100\%=12.5\%. \end{gathered}[/tex]The answer would be 12.5 %.
How many total atoms are there in 19.3 g of hydrazine (N_{2}*H_{2})
Given the following parameters
Mass of hydrazine = 19.3 grams
Determine the moles of hydrazine
[tex]\begin{gathered} moles\text{ of N}_2H_2=\frac{mass}{molar\text{ mass}} \\ moles\text{ of N}_2H_2=\frac{19.3}{30.02928} \\ moles\text{ of N}_2H_2=0.6423moles \end{gathered}[/tex]According to the Avogadro's constant
[tex]1mole\text{ of a substance}=6.02\times10^{23}atoms[/tex][tex]\begin{gathered} atoms\text{ of N}_2H_2=0.643\times6.02\times10^{23} \\ atoms\text{ of N}_2H_2=3.87\times10^{23}atoms \end{gathered}[/tex]Therefore the total atoms that are there in 19.3 g of hydrazine is 3.87 * 10^23 atoms
how many litres of gas is in 8.3 mol N2O in STP
According to STP, and furthermore, we assume ideal gas conditions:
1 mol N2O = 22.4 L
Procedure:
1 mol N2O -------------- 22.4 L
8.3 moles N2O------------- X
X= 186 L (approx.)
Answer: 186 L
I need to know the answer to this science problem . Please and thank you
Step 1 - Understanding the types of heat transfer
There are three types of heat transfer: conduction, convection and irradiation. Let's see how each one works:
a) Conduction: is when a very hot substance enters in contact with a cooler substance. The atoms in the hotter substance are moving with a greater velocity and will therefore collide with the atoms of the cooler substance.
b) Convection: it happens especially in liquids and air (fluids). The liquid is warmed up at the bottom first, via conduction. The heated bottom thus changes its density: it becomes less dense, and go up. This process repeats itself several times, warming the whole liquid.
c) Irradiation: when something is put near a heat source, but do not touch it directly. In this case, there's no direct atom collision, but indirect: the rapid atoms of the heat source collide with atoms in the air which then collide with the atoms in the object that is being heated.
Step 2 - Discovering the type of heat transfer in each scenario
In the first scenario, the water at the bottom is in direct contact with the pan. Therefore, water molecules will directly collide with "pan" molecules (probably aluminum atoms or other materials). But there's also convection. The water is not heated only by conduction.
In the second scenario, the hands are near the Bunsen burner, but not directly touching it. What is happening here is then heat irradiation, not conduction.
In the third scenario, the hand is touching the object (the handle of the pan). Even though handles are made of material that poorly conduct heat, it will increase its temperature, at least a little bit. When we touch it, we can feel it is hotter than before. In this case, only conduction is involved (from the handle to our hand). In this case atoms are directly colliding and this is the only source of heat.
Finally, in the last scenario, we also have a case of irradiation: the pan with water is near the heat source, but not directly touching it.
Step 3 - How to set an experiment
In science in general, anytime we want to investigate some effect it is good manners to investigate a system controling all other effects. We want to investigate a variable at a time.
Therefore, while both scenario 1 and 3 involve conduction, scenario 1 also involves convection, which could be a problem to a experiment intending to study conduction only.
The best experiment would be then scenario 3, hands touchind the handle of pan siting in a Bunsen burner.
5. You have 7 moles of NaCl. How many particles are present?
1) List the known and unknown quantities.
Sample: 7 mol NaCl
Particles: unknown
2) Convert moles of NaCl to particles of NaCl.
Avogadro's number is 6.022*10^23
1 mol = 6.022*10^23
[tex]particles\text{ }NaCl=7\text{ }mol\text{ }NaCl*\frac{6.022*10^{23}\text{ }particles}{1\text{ }mol\text{ }NaCl}=4.21*10^{24}\text{ }particles[/tex]7 mol NaCl is equal to 4.21*10^24 parcicles.
What is the pH of a solution where [OH-] = 5.6 × 10-4 M?
The pH value indicates the concentration of H+ ions in the solution. We are given the value of the concentrations of the OH- ions, so we can find the pOH using the following equation:
[tex]pOH=-log\lbrack OH^-\rbrack[/tex]The sum of pH and pOH will always be equal to 14, so we find the pH by clearing it from the following relationship:
[tex]pH+pOH=14[/tex]So, pOH value will be:
[tex]pOH=-log\lbrack5.6\times10^{-4}\rbrack=3.3[/tex]The pH will be:
[tex]\begin{gathered} pH=14-pOH \\ pH=14-3.3=10.7 \end{gathered}[/tex]The pH of the solution will be 10.7
The energy of a photon that has a wavelength of 8.33 × 10^-6 m is ________ J.A) 2.20 × 10^-26 B) 3.60 × 10^13C) 2.39 × 10^-20 D) 2.7 × 10^9E) 4.5 × 10^-25
The energy of a photon can be found using the following equation:
What we're going to do is to replace the values of the constant and the value of the wavelength in the expression above. This is:
Therefore, the correct answer option is C. 2.39 × 10^-20 J.
What part of a cell provides instructions for the processes within the cell
DNA _ Chloroplasts _ Cell wall or Glucose
The information for the cellular process is provided by DNA. DNA has genes on it, so by expressing the gene, the characteristics are expressed in the cell.
What is a gene?
Genes are present in the DNA of both prokaryotes and eukaryotes. The information of the cell is present in the gene, and it is expressed by the processes of transcription and translation in the cell.
Because of differences in gene expression, different cells, such as the nerve cell, the cardiac cell, the epithelial cell contain different proteins. Not all genes are expressed in all cells of the body. Only those genes are expressed that are transcriptionally activated and make mRNA.
Hence, DNA provides the information to the cell for the cellular process.
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Answer the following question:Reminder R= .0821. If you have a gas at 6 Atm and 4 L, how many moles are present if the temp is 300 K?
Answer
0.975609756 mol
Explanation
Given:
Pressure, P = 6 atm
Volume, V = 4 L
Temperature, T = 300 K
Molar gas constant, R = 0.082
What to find:
The moles, n present.
Step-by-step solution:
The mole, n present can be calculated using the ideal gas equation, PV = nRT
6 x 4 = n x 0.082 x 300
24 = 24.6n
Diivide both sides by 24.6
24/24.6 = 24.6n/24.6
n = 0.975609756 mol
Hence, the moles that are present = 0.975609756 mol
which best corresponds to a strong base?I need to know
Assuming that the question is considering quantity of OH- ions as strength of base, the most basic compound will be the last one, as it has more OH- being released into the reaction, but the definition of strong base is a base that totally dissociates, but for the purpose of the question, letter D corresponds to a strong base.
A sample of an unknown gas with a molar mass of 85.74 is placed in a vessel with avolume of 1,681 mL at a temperature of 58.6 °C. If the pressure is 5.4 atm, howmany grams of this gas are present?
Answer
28.58 grams
Explanation
Given:
Molar mass of the gas, M = 85.74 g/mol
Volume, V = 1,681 mL = 1.681 L
Temperature, T = 58.6 °C = (58.6 + 273.15 K) = 331.75 K
Pressure, P = 5.4 atm
What to find:
The mass of the gas in grams present.
Step-by-step solution:
The mass in grams of the gas present can be calculated using the ideal gas equation:
[tex]\begin{gathered} PV=nRT \\ \\ n=moles=\frac{Mass}{Molar\text{ }mass} \\ \\ \Rightarrow PV=\frac{Mass}{Molar\text{ }mass}RT \end{gathered}[/tex]Putting the values of the given parameters and R = 0.0821 atm•L/mol•K into the formula:
[tex]\begin{gathered} 5.4atm\times1.681L=\frac{Mass}{85.74g\text{/}mol}\times0.0821atm•L/mol•K\times331.75K \\ \\ 9.0774atm•L=Mass(0.317665908atm•L/g) \\ \\ Divide\text{ }both\text{ }sides\text{ }by\text{ }0.317665908atm•L/g \\ \\ \frac{9.0774atm•L}{0.317665908atm•L/g}=\frac{Mass(0.317665908atm•L)}{0.317665908atm•L\text{/}g} \\ \\ \Rightarrow Mass=28.58\text{ }grams \end{gathered}[/tex]The mass of the gas in grams present = 28.58 grams.
PLEASE HELP
Balance the chemical reaction
using an atom inventory.
What is the coefficient for
oxygen?
4NH3 + ? O2 ---> ?NO + ? H2O
The balance chemical equation will be 4NH3 + 5 O2 → 4NO + 6H2O and the coefficient for water will be 5.
The given unbalanced chemical equation is :
4NH3 + O2 → NO + H2O
It can be seen that number of nitrogen atom in reactant side is 4. By multiplying by 4 as the coefficient of NO , multiplying by 5 as the coefficient of oxygen and multiplying by 6 as the coefficient of H2O. The equation will be balanced.
The balanced chemical equation will be :
4NH3 + 5O2 →4 NO + 6H2O
Therefore, the the coefficient for water will be 5.
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when 14.12 moles of mercury (ll) oxide decomposes, how many moles of oxygen gas will form ?
ANSWER
The number of moles of oxygen formed is 7.06 moles
EXPLANATION
Given that
The number of moles of mercury (II) oxide is 14.12 moles
Follow the steps below to find the number of moles of oxygen
Step 1; Write the balanced equation for the decomposition of the reaction
[tex]\text{ 2HgO }\rightarrow\text{ 2Hg}_{(s)}\text{ + O}_{2(g)}[/tex]In the reaction above, 2 moles HgO decompose to produce 2 moles Hg and 1 mole O2
Step 2; Find the number of moles of oxygen using a stoichiometry ratio
Let x represents the number of moles of oxygen
[tex]\begin{gathered} \text{ 2 moles HgO }\rightarrow\text{ 1 mole O}_2 \\ \text{ 14.12 moles HgO}\rightarrow\text{ x mole O}_2 \\ \text{ cross multiply} \\ \text{ 2 moles HgO }\times\text{ x mole O}_2\text{ }=\text{ 1 mole O}_2\times\text{ 14.12 moles HgO} \\ \text{ Isolate x} \\ \text{ x = }\frac{1\text{ mole O}_2\times14.12moles\cancel{HgO}}{2moles\cancel{HgO}} \\ \text{ x = }\frac{14.12}{2} \\ \text{ x = 7.06 moles} \end{gathered}[/tex]Therefore, the number of moles of oxygen formed is 7.06 moles
When reacting 5.00 g of MgCl2 with 15.0 g of AgNO3 , what is the limiting reagent based on the following equation?MgCl2 (aq) + 2 AgNO3(aq) --> 2 AgCl (s) + Mg(NO3)2 (aq)
Answer:
[tex]AgNO_3\text{ is the limiting reagent}[/tex]Explanation:
Here, we want to get the limiting reactant
The limiting reactant is the reactant that would produce less amount of the solid precipitate
Firstly, we need to get the number of moles of each of the reactants
To get this, we divide their masses by the molar masses
The molar mass of magnesium chloride is 95 g/mol
The number of moles would be:
[tex]\frac{5}{95}\text{ = 0.053 mol}[/tex]Now, from the equation of reaction, 1 mole of MgCl2 produced 2 moles of AgCl
Then: 0.053 mole of MgCl2 will produce 2 * 0.053 mol = 0.106 mol AgCl
For AgNO3, the molar mass is 170 g/mol
The number of moles would be:
[tex]\frac{15}{170}\text{ = 0.088 mol}[/tex]Now, looking at the equation of reaction:
2 moles of AgNO3 produce 2 moles of AgCl
0.088 mol AgNO3 will also produce 0.088 mol AgNO3
Now, looking at the values of the number of moles of AgCl produced, we can see that AgNO3 produces less of the product
This means that AgNO3 is the limiting reactant
6. A sample of nitrogen gas weighs 130 g. Write the chemical formula for nitrogen gas. Howmany molecules of elemental nitrogen is this? How many atoms of nitrogen are in this sample?
Chemical formula for nitrogen gas is N₂.
To find the number of molecules in the given sample, we have to convert the mass of the sample to moles by using the molecular mass of elemental nitrogen (N₂).
[tex]130gN_2\cdot\frac{1molN_2}{28gN_2}=4.64molN_2[/tex]Now, we have to use Avogadro's number (6.022x10^23) that indicates the number of molecules in one mole of substance:
[tex]4.64molN_2\cdot\frac{6.022\times10^{23}molecules}{1molN_2}=2.79\times10^{24}molecules[/tex]It means that there are 2.79x10^24 molecules of elemental nitrogen.
To find the number of atoms we just have to multiply the number of molecules by 2, which is the number of atoms of nitrogen per molecule of elemental nitrogen:
[tex]2.79\times10^{24}molecules\cdot\frac{2atoms}{1molecule}=5.59\times10^{24}atoms[/tex]There are 5.59x10^24 atoms of nitrogen in the sample.
How many moles are in 91.5 grams of Helium?
In order to find the number of moles with a given mass of Helium, we need to use its molar mass, which is 4.0026g/mol, therefore we will have:
4.0026g = 1 mol of Helium
91.5g = x moles of Helium
x = 22.86 moles of Helium in 91.5 grams
Question 2 of 10Which of the following substances is a chemical that is made only bychemists?A. BleachB. CopperOC. WaterO D. Nitrogen
Answer: The best option to answer the question is letter A (bleach)
Explanation:
The question requires us to choose, among the options given, which one corresponds to a chemical compound that is only made by chemists.
Nitrogen (N2) is a gas found in our atmosphere, corresponding to 78% (by volume) in dry air. Therefore, N2 is found in nature.
Water (H2O) is also found in nature, as it is present in our atmosphere, rivers, lakes and oceans (among others).
Copper (Cu) is a metal that is also found in nature, occuring naturally in metal form and being present in minerals.
On the other hand, bleach corresponds to a mixture of chemicals where the main ingredient is sodium hypochlorite.
Therefore, among the options given, bleach is the only one that is made only by chemists (and it is not found as it is in nature).
The best option to answer the question is letter A (bleach).
2. The following mistakes were made when carrying out the experiment. What effect does each have on the
calculated molar mass? Be specific. For example, too large because...
a. Only part of the pipet was immersed in the boiling water, so the temperature in part of the pipet was less
than that of the water bath.
b. The mass of the condensed liquid was not determined quickly. Instead, the pipet was allowed to stand for
a while before immersing it in room temperature water and then massing the pipet.
The actual volume of pipet is 23.8901 mL
Explanation:
The formula for the density of water can be used to calculate the volume of water transferred. For which, let us first calculate the mass of water transferred by taking the difference of mass of beaker.
Initial mass of the dry beaker:
initial mass of beaker (dry) = 57.5348 g
Mass of the water:
mass of the water = final mass of the beaker - initial mass of the beaker
mass of the water = 81.3743 - 57.5348
mass of the water = 23.8395 g
The density of water at 21.5°C is 0.997882 g/mL
From the above data
The above calculations show that the volume transferred by pipet is 23.8901 mL.
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I really need help on this problem for chemistry, please help!
answer and explanation
we are given the balanced reaction and so we begin by calculating the number of mols of each reactant
for Al
mols = mass/Molar mass
= 22.0g / 26.98g/mol
= 0.82 mols
for oxygen
mols = mass / Molar mass
= 26.0g / 16.00g/mol
= 1.6 mols
theerefore
a. the limiting reagent is Al
b. theoretical yield will be determine using the limiting reagent.
from the balanced reaction we see that the mol ratio between aluminum and aluminum oxide is 4:2
therefore
2/4 x0.82 = 0.41 mols of aluminum oxide will form
the mass will be
mass = n x M
= 0.41 mols x 101.96g/mol
= 41.8 grams
c. percentage yield is:
actual yield/ theorectical yield x 100
= 40.0/41.8 x 100%
= 95.7 %
Determine the molar mass of an unknown monoprotic acid to two decimal places if 16.98 mL of a 0.086 M NaOH solution were used to titrate 0.236 g of the unknown acid
1 ) Chemical equation
[tex]\text{NaOH + HX}\rightarrow H_2O+Na^++X^-[/tex]HX represents the unknown acid.
2) Moles of NaOH in the reaction
[tex]M=\frac{\text{moles of solute}}{\text{liters of solution}}[/tex]Convert mL into L
[tex]L=16.98mL\cdot\frac{1L}{1000mL}=0.01698L[/tex]Plug in known values in the equation and solve for moles.
[tex]0.086M=\frac{\text{moles of NaOH}}{0.01698L}[/tex][tex]\text{mol NaOH= 0.086M}\cdot0.01698L=0.00146028\text{ mol NaOH}[/tex]3) Moles of the unknown acid that reacted with 0.00146028 mol NaOH
Molar ratio
1 mol NaOH: 1 mol HX
[tex]\text{mol HX=0.00146028 mol NaOH}\cdot\frac{1\text{ mol HX}}{1\text{ mol NaOH}}=0.00146028\text{ mol HX}[/tex]4) Molar mass of the unknown monoprotic acid
[tex]\text{Molar Mass=}\frac{\text{mass of solute (g)}}{moles\text{ of solute}}[/tex]Plug in known values and solve
[tex]\text{Molar Mass}=\frac{0.236\text{ g HX}}{0.00146028\text{ mol HX}}=161.61\text{ g/mol}[/tex]The molar mass of the unknown monoprotic acid is 161.61 g/mol
.