Which of the following is/aresoluble in water?Alcohols with threecarbon atomsAlcohols with less thanthree carbon atomsAlcohols with six carbonatomsabсd Both A and B

Answer

This obey the law of definite proportion

Step-by-step explanation:

The Law of definite proportion states that any chemical compound will always contain a fixed ratio of elements by mass

According to the question,

Let the first oxide = x

Let the second oxide = y

x = 0.8g

y = 1.5g

For the first metal oxide, the amount of metal is 0.64 grams

Hence, the mass of oxygen is (0.8 - 0.64)

Mass of oxygen = 0.16g

Mass ratio = Mass of metal/mass of oxygen

Mass ratio = 0.64 / 0.16

Mass ratio = 4 : 1

For the second metal oxide, the amount of metal is 1.2g

Amount of oxygen = (1.5 - 1.2)

Mass of oxygen = 0.3

Mass of oxygen = 0.3g

Mass ratio = mass of metal/mass of oxygen

Mass ratio = 1.2 / 0.3

Mass ratio = 4: 1

Hence, the ratio of metals to oxygen is in the ratio of 4 to 1

Answer

Hence, this obey the law of definite proportion

Answer:

Explanation:

Here, we want to get the new pressure

According to the pressure law, temperature and pressure are directly proportional

Mathematically, we have that as:

where:

P1 is the initial pressure which is 65 KPa

P2 is the final pressure that we want to calculate

T1 is the initial temperature which we will convert to Kelvin by adding 273K:

We have T1 as 29 + 273 = 302K

T2 is the final temperature which is also 167 + 273 = 440K

Substituting the values, we have it that:

Answer:

The specific heat capacity of lead is 0.128 J/g°C.

Mass of lead block = (100.0 g)(26.2oC - 24.8oC)(0.128 J/g°C) / (58.5oC - 24.8oC)

Mass of lead block = 5.45 g

The word percent is telling us 'percent' is the amount of one part in every hundred (100), so the given statement of the question is false.

The twos are the subscript of each of element, those subscripts represent the number of atoms of each element that the molecule has. It means that the correct answer is Subscripts.

Li and Na two elements have chemical properties that are most similar

The element that have the most similar chemical properties are those in the same group or column of the periodic table and one such group includes lithium sodium potassium these element are all shiny and conduct heat and electricity well and have similar chemical properties and the element in a group have the same number of electron in the outermost shell hence they have similar chemical properties

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0.53L

According to dilution formula:

C1 and C2 are the initial and final concentrations

V1 and V2 is initial and final volume

Given the following parameters

• V1 = 45mL

• C2 = 0.2M

• V2 = 119.4mL

Substitute the given parameters into the formula

Hence the molarity of the nitric acid is 0.53L

A precipitate formed in a reaction or solution is when we have a solid salt that is not soluble in the reaction anymore, in our case we are dealing only with the compound formed with Sodium and another anion, so the one that is not soluble in water will be the one that will form a precipitate, therefore a solid salt not dissolvable. Out of the three ionic compounds: Na2CO3, Na2CrO4, NaI2, Sodium chromate (Na2CrO4) will present as the less soluble in water, since chromates in general are not very soluble in water, which is not the case for carbonates and iodides, they will readily dissolve in water, not forming any precipitates

Step 1

The He gas is assumed to be ideal. Therefore, the next equation is applied:

----------------------

Step 2

Information provided:

p = pressure = 1.13 atm

V = volume = 33.2 L

n = number of moles = unknown

T = absolute temperature = 652 K

R = gas constant = 0.082 atm L/mol K

---------------------

Step 3

Firstly, n is calculated from (1):

n = 0.702 moles

----------------------

Step 4

The mass of He is calculated as:

n = mass/the molar mass He

The molar mass of He = 4.00 g

So, n = mass/4.00 g/mol

n x 4.00 g/mol = mass

0.702 moles x 4.00 g/mol = 2.81 g

Answer: mass = 2.81 g

ANSWER

Ag+ is the oxidizing agent

Ag+ is reduced to Ag

Zn is oxidized to zn^2+

Zn is the reducing agent

option ABCD

STEP-BY-STEP EXPLANATION:

Given information

From the above redox reaction, you will see that there is a change in the oxidation number of zinc and silver.

Zn goes from 0 to 2+ in its oxidation state

Hence, zinc has been oxidized, therefore, it is a reducing agent

Ag goes from +1 to 0 in its oxidation state

Hence, Ag has been reduced, therefore, it is an oxidizing agent

Explanation:

A buffer is a mixture of a weak acid and its conjugate base, or a weak base and its conjugate acid. In our case we are reacting a strong acid (HCl) and a weak base (sodium acetate). So we don't have a buffer. The strong acid will neutralize the weak base. We have to determine which of them is in excess and find the pH of the resulting solution.

HCl (aq) + CH₃COONa (aq) ----> NaCl (aq) + CH₃COOH (aq)

First we have to determine the number of moles of each reactant. We added 275 ml of a 0.676 M solution of HCl and 500 mL of a 0.525 M solution of CH₃COONa. We can use the definition of molarity concentration to determine the number of moles of each reagent.

Molarity = moles of solute/volume of solution in L

moles of solute = molarity * volume of solution in L

moles of HCl = 0.676 M * 0.275 L

moles of HCl = 0.186 moles

moles of CH₃COONa = 0.525 M * 0.500 L

moles of CH₃COONa = 0.262 moles

HCl (aq) + CH₃COONa (aq) ----> NaCl (aq) + CH₃COOH (aq)

In the equation of the reaction all the coefficients are 1. So 1 mol of HCl will completely neutralize 1 mol of CH₃COONa. The molar ratio between them is 1 to 1.

1 mol of HCl = 1 mol of CH₃COONa

We mixed 0.262 moles of CH₃COONa with 0.186 moles of HCl. The 0.186 moles of HCl will neutralize 0.186 moles of CH₃COONa. And CH₃COONa will be excess.

Excess of CH₃COONa = 0.262 moles - 0.186 moles

Excess of CH₃COONa = 0.076 moles

Now we have to determine the concentration of this excess. We mixed 0.275 L with 0.500 L. Then the total volume of solution is 0.775 L. And the concentration of CH₃COONa after the reaction is:

total volume = 0.500 L + 0.275 L

total volume = 0.775 L

Resulting molarity of CH₃COONa = 0.076 moles/0.775 L

Resulting molarity of CH₃COONa = 0.098 M

Finally to get our answer we have to determine the pH of this resulting solution. To determine the pH of a weak base we have to use the ICE table. In solution

Answer:

According to the what was presented to me, to find the number of moles of a compound or element from a given mass, we need to use the molar mass of this element and do the following calculation:

Si = 28.0855g/mol

28.08g = 1 mol of Si

4.68g = x moles of Si

x = 0.17 moles of Si

O = 16g/mol

16g = 1 mol of O

5.32g = x moles of O

x = 0.33 moles of O

Answer:

Third option, because copper (Cu) is a stronger oxidizing agent than zinc (Zn).

Explanation:

The table shows the Oxidation Half-Reaction, so the elements oxidizes.

When an element is oxidized, it causes the other element in the reaction to be reduced, therefore the element being oxidized is a reducing agent.

In this case, the correct reaction is:

because, copper (Cu) is a stronger oxidizing agent than zinc (Zn).

Answer:

Answer:

Explanations:

The formula for calculating the percentage by mass of concentration is expressed as;

Answer

B. When bonds are formed, energy is released.

Explanation

The breaking of chemical bonds never releases energy to the external environment. However, energy is only released when chemical bonds are formed.

Therefore the only true statement about energy and bonds in the given options is:

B. When bonds are formed, energy is released.

Taking into account the reaction stoichiometry, the theoretical yield of Cu(NO₃)₂ is 8.9717 grams.

In first place, the balanced reaction is:

Cu + 4 NHO₃ → Cu(NO₃)₂ + 2 NO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

The following rule of three can be applied: if by reaction stoichiometry 63.55 grams of Cu form 187.55 grams of Cu(NO₃)₂, 3.04 grams of Cu form how much mass of Cu(NO₃)₂?

mass of Cu(NO₃)₂= (3.04 grams of Cu× 187.55 grams of Cu(NO₃)₂)÷ 63.55 grams of Cu

mass of Cu(NO₃)₂= 8.9717 grams

Finally, the maximum amount of Cu(NO₃)₂ is 8.9717 grams.

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Explanation

Given

2H2(g) + O2(g) ⇨ 2H2O(g)

Volume = 6.00 L

At STP: Temperature = 273K

Pressure = 1 atm

We know that R constant = 0.0821 L.atm/mol.K

Solution

Step 1: Calculate the number of moles of oxygen at STP

Use the ideal gas law equation:

PV = nRT where P is the pressure, V is the volume, n is the number of moles, R is the gas constant and T is the temperature.

n = PV/RT

n = (1 atm x 6.00 L)/(0.0821 L.atm/mol.K x 273 K)

n = 0.27 mol

Step 2: Use the stoichiometry to find the moles of H2

The molar ratio between oxygen and hydrogen is 1:2

Therefore the moles of H2 = 0.27 x (2/1) = 0.535 mol

Step 3: Calculate the volume of H2

V = nRT/P

V = (0.535 mol x 0.0821 L.atm/mol.K x 273 K)/1 atm

V = 12.0 L

Answer

Volume of hydrogen = 12.0 L

Answer

2.22 x 10⁻⁷ M

Procedure

To calculate the [OH⁻] concentration of blood we will consider the following pH formulas

pH=-log [H₃O⁺]

pH+pOH=14

The pH of blood will be

Then we do the rest

Lastly, we transform from pOH to concentration

Bond:

Bonds are forces that keep atoms together to make compounds or molecules.

In chemical bonds electrons are involved. And there are three kinds of bonds:

1. Covalent bonds: where the electrons are shared between the atoms.

2. Polar covalent bonds

3. Ionic bonds: happens when one atom gives to the other atom electrons.

Answer

4.22 atm

Explanation

Given that:

The initial pressure, P₁ = 6.1 atm

The initial temperature, T₁ = 2.0 °C = (2.0 + 273.15 K) = 275.15 K

The final temperature, T₂ = -83.0 °C = (-83.0 + 273.15 K) = 190.15 K

What to find:

The final pressure, P₂ (atm) of the gas at 83.0 °C.

Step-by-step solution:

The relationship between pressure and temperature of gaseous subtance was decribed by Amonton's gas law.

Amonton's Law states that the pressure of an ideal gas varies directly with the absolute temperature when the volume of the sample is held constant.

Mathematically, we have:

Putting the values of the parameters into the formula, we have:

Thus, the final pressure, (atm) of the gas at 83.0 °C is 4.22 atm.

In general, the ions of very late transition metals those towards the right-hand end of the transition metal block, such as copper, silver and gold have high reduction potentials. In other words, their ions are easily reduced.

Again, note that when calculating E∘cell E cell ∘ , standard reduction potentials always remain the same even when a half-reaction is multiplied by a factor. Standard electrode potential - When the concentration of all the species is taken as unity in the half-cell reaction, then the calculated electrode potential is called the standard electrode potential. The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced. The electrode potential depends upon the concentrations of the substances, the temperature, and the pressure in the case of a gas electrode.

Average atomic mass of newly discovered element X is 166

What is average atomic mass?

It is calculated by adding the masses of the element's isotopes each multiplied by its natural abundance on Earth

Given data

 Isotope                Mass              % abundance

   15                          71                       71.007

   21                          75                      74.996

   64                          77                       77.112

Contribution made by each isotope by multiplying natural abundance with mass

Average atomic mass

     =  (71 × 71.007 + 75 × 74.996 + 77 × 77.112) / 100

     = 166

Therefore average atomic mass is 166

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Answer:

a. 0.75 mol

Explanation:

From the balanced equation, we know that 1 mole of AgNO3 reacts with 1 mole of KCl to produce 1 mole of AgCl and 1 mole of KNO3.

Since the ratio between AgNO3 and KCl is 1:1, in this case potassium chloride will be the limiting reactant and silver nitrate will be the excess reactant.

So we have to use the initial moles of the limiting reactant to calculate the moles of product that will be produced.

From the stoichiometry of the reaction we know that from 1 mole of KCl, we can obtain 1 mole of AgCl, so here the ratio between KCl and AgCl is also 1:1, so the maximum amount of silver chloride that can be produced is 0.75moles, as we can see using a mathematical rule of three:

ANSWER

The molar concentration of NaOH is 0.0705 mol/L

STEP-BY-STEP EXPLANATION:

Given the balanced equation below

According to the balanced equation, 1 mole of KHP gives 1 mole of NaOH

Given parameters

Molar mass of KHP = 204.2 grams/mol

To find the mole of KHP, we will need to find the average grams of KHP used

• For flask 1; 0.55g of KHP was used

• For flask 2; 0.56g of KHP was used

• For flask 3; 0.56g of KHP was used

The average mass of KHP used can be calculated below using the average formula

The average mass of KHP used is 0.3886grams

The mole of KHP is 0.0019 mole

PART B

According to the balanced equation, the stoichiometry ratio of KHP to NaOH is 1: 1

Let the mole of NaOH be x

Hence, the mole of NaOH is 0.0019 mole

PART C

Given the following parameters

0. The volume of NaOH used in flask 1 = 26.70mL

1. The volume of NaOH used in flask 2= 27.09mL

2. The volume of NaOH used in flask 3 = 26.96mL

The next step is to convert the mL to L

For flask 1

Using the same conversion process

The volume of NaOH in L in flask 2 = 0.02709L

The volume of NaOH in L in flask 3 = 0.02696L

Hence, the molar concentration of the solution in each flask can be calculated as follows

For flask 1

Mole of NaOH = 0.0019 mole

Volume of NaOH = 0.0267L

For flask 2

Mole = 0.0019 mole

Volume = 0.02709L

For flask 3

Mole = 0.019mole

Volume = 0.02696 L

PART D

Average molar concentration can be found using the below formula

Answer: Potassium (K)

Explanation:

• +Aluminium forms a non- directional metalic bond.

• (bonding in chemistry is the lasting attraction between atoms , ions or molecule )... think of it like joining together of particles / elements

• This type of covalent bonding results in a metallic lattice structure.

• Since aluminium is a metallic solid, the maximum covalency of aluminium is three only.

See the drawing below:

1) First, let's rewrite the chemical equation here:

2 C7H6O3(s) + C4H6O3(l) → 2 C9H8O4(s) + H2O(l)

2) Let's find out how many moles of C9H8O4 have into 500 mg of it. For this, use ese the following equation:

mole = mass/ molar mass

mass = 500 mg = 0.5 g

molar mass of C9H8O4 = 180.16 g/mol (the question give it to us)

mole = 0.5/180.16

mole = 0.0028 moles of C9H8O4

3) Using the chemical equation proportion, we can discover the amount in moles of C4H6O3 needed to form 0.0028 moles of C9H8O4. So:

1 mol of C4H6O3 forms 2 moles of C9H8O4

x mol of C4H6O3 forms 0.0028 moles of C9H8O4

2x = 0.0028

x = 0.0014 moles of C4H6O3

4) We need to find the answer in grams. Let's transform 0.0014 moles of C4H6O3 into grams. For this, use ese the following equation:

mass = mole × molar mas

mass = 0.0014 moles × 102.09

mass = 0.142 grams or 1.42x10⁻¹

Answer: The amount of C4H6O3 that is needed is 1.42x10⁻¹ g.

Given that molar molar enthalpy of combustion of cyclohexanone is -3468.1 kJ/mol when liquid water is formed, what is the molar enthalpy of formation of cyclohexanone?

Answer

2.12872 grams of water

Explanation

Given:

Mass of copper (II) sulfate pentahydrate sample = 5.9 grams

What to find:

The grams of water that would be released if all of the water is removed from the 5.9 grams sample of copper (II) sulfate pentahydrate.

Step-by-step solution:

The chemical formula of copper (II) sulfate pentahydrate is: CuSO₄.5H₂O

Molar mass of CuSO₄.5H₂O = 249.68 g/mol

Mass of water in 1 mole of CuSO₄.5H₂O = 5 x molar mass of water = 5 x 18.01528 g/mol = 90.0764 g/mol

the percentage by mass of water in 1 mole of CuSO₄.5H₂O is

Hence, you can now use the % by mass of water in 1 mole of copper (II) sulfate pentahydrate to determine the mass of water that would be released in 5.9 grams of copper (II) sulfate pentahydrate as shown below.

Therefore, the grams of water that would be released if all of the water is removed from the 5.9 grams of copper (II) sulfate pentahydrate is 2.12872 grams