When the electrostatic force overcomes the
of the nucleus, it is called radioactive decay.
Answer here
force in at least part
(Apex answer)

If transverse waves travel at  38 m/s in an aluminum wire of 4.6 mm diameter, the tension on the wire is 64.72 N

The speed or the velocity of a transverse waves in a wire id given by:

v = sqrt ( T / μ)

Where:

T = Tension on the wire

μ = mass per unit length

In the given problem:

v = 38 m/s

d = diameter of the wire = 4.6 mm

Area of wire's cross section:

A = π x (2.3)²

   = 16.6 mm² = 16.6 x 10⁻⁶ m

μ = density x A

  = 2700 x 16.6 x 10⁻⁶  = 0.045 kg/m

Take the square of the equation:

v² = T / μ

T = μ x v² = 0.045 x 38² = 64.72 N

Your question is incomplete, but most probably your question was:

The density of aluminum is 2700 kg/m3. If transverse waves travel at  38 m/s in an aluminum wire of 4.6 mm diameter. What is the tension on the wire?

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The amount of work done in stopping a car with a mass of 1500 kg moving at 12m/s is 108000 j.

Work done is same as the change in kinetic energy of the moving car.

We will first calculate the initial kinetic energy of the car

Kinetic energy is due to motion and is equal to half the product of mass and square of velocity.

K.E. = 1/2× mass× [tex](velocity)^{2}[/tex]

Initial K.E. = 1/2 × 1500× 12×12

               = 108000 j

As the car finally stops, the final kinetic energy is zero.

Final K.E. = 0

So, work done = change in K.E. = 108000-0 j

= 108000j

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a) The car's engine needs 11500 W of power to move the vehicle on level terrain.

b) A car's engine needs 17,084 W of power to move the vehicle up a hill with a 2.0° grade.

a) The energy needed to run the car's engine is provided by

P = Fv

where

The force which the engine needs to exert is F.

The car's velocity is v = 23 m/s.

Since the automobile is driving at a constant speed and hence experiencing no acceleration, the net force acting on it must also be zero. Since there is a 500 N drag force against the car's velocity, this implies that the engine's force applied forward must likewise be 500 N:

F = 500 N

Consequently, the power lost by the engine is

P = (500 N)(23 m/s)= 11500 W.

b) Both the drag force and the weight component that is parallel to the gradient are working against the motion of the automobile in this scenario.

This element is provided by

[tex]W_p[/tex] = mgsin∅

where

m = 710 kg, g = 9.8 m/s2, and ∅ = 2°, respectively, are the mass, acceleration of gravity, and slope of the hill, respectively.

[tex]W_p[/tex] = 710 × 9.8 m/s² × sin2° = 242.8 N

The drag force (500 N) and so this force is now added to determine the total rearward force acting against the velocity of the car:

F = 500 N + 242.8 N = 742.8 N

Because the force the engine applies must be equal, the power that is revoked will also be equal.

P = (742.8 N)(23 m/s) = 17,084 W

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The question is -

A 710kg car drives at a constant speed of 23m/s. It is subject to a drag force of 500 N. What power is required from the car's engine to drive the car (a) on level ground? (b) up a hill with a slope of 2.0∘ ?

The maximum possible efficiency this engine can achieve is 41.9%.

The ratio between the total quantity of energy in the fuel and the amount of energy used to carry out productive work is known as the engine efficiency of thermal engines. Thermal engines may be divided into two categories:

Engines that burn fuel internally (such as gasoline, diesel, and gas turbines with Brayton cycles) and externally (steam piston, steam turbine, and the Stirling cycle engine). These engines each have distinct thermal efficiency characteristics.

here ,

T1 = -10 C = 263.15 K

T2 = 180 C = 453.15 K

Maximum efficiency of heat engine,

η = T2−T1 / T2

  = (453.15 − 263.15) / 453.15

  = 0.419 = 41.9 % ≈ 50%

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The values with (1/2)(9.8 m/s2) (4 - X)^2 = (1.7 × 10^8 m/s) (X) —> We discover with the calculator X = 4.40 × 10^-7. The depth of the ice is then calculated by multiplying by the speed 74.8 m. Through ice, radio waves move at a speed of 1.7 x 108 m/s.

What is radio waves?

A radio wave pulse that is delivered into the Antarctic ice returns after reflecting off the bottom rock. A radio wave pulse that is transmitted into the Antarctic ice bounces off the subsurface rock and resurfaces. ice in Antarctica Through ice, radio waves move at a speed of 1.7 108 m/s. The rock reflects the radio wave pulse that was transmitted into the Antarctic ice. The amount of time that passed between the signal being sent and being received by the earth station.

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If the charge of an electron were regarded as positive and the charge of a proton as negative, then coulomb's law appears to be

[tex]F = k\frac{q_{1}q_{2} }{r^{2} }[/tex]  ⇒ [tex]F = k\frac{-q_{1}(-q_{2}) }{r^{2} }[/tex] ⇒ [tex]F[/tex].

Suppose,

Electrons are positive, the charge can be written as q, and

Protons are negative, their charge can be seen as being -Q.

It would be akin to inverting the signs of all charges if protons had a negative charge and electrons had a positive charge. This makes it very easy to verify that Coulomb's Law adheres to charge symmetry by using the substitutions q1→−q1 and q2→−q2.

[tex]F = k\frac{q_{1}q_{2} }{r^{2} }[/tex] ⇒ [tex]k\frac{-q_{1}(-q_{2}) }{r^{2} }[/tex] ⇒ [tex](-1)^{2} k\frac{q_{1}q_{2} }{r^{2} }[/tex] [tex]= F[/tex]

Therefore, there would be no difference if we switched the sign convention of the charges.

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Because different visible light colors have distinct wavelengths and barely varying refractive indices, the wavelength of the light influences the angle of refraction.

For instance, you cannot tell the difference when white light passes through a flat piece of glass because it is so slight.

The reflected beam will always be refracted at the same angle that it impacted the surface since light will then continue to go through the same medium and at the same speed.

A periodic wave's wavelength is its spatial period, or the length over which its shape repeats. It is a property of both travelling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings.

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Body waves and surface waves are the two types of waves that an earthquake can produce.

What does an earthquake's sound wave look like?

Seismic waves, which are audible but undetectable to human eyes and hearing, pulse through the strata of the Earth beneath the surface of the planet as it trembles. Sound waves that can be monitored or even recorded to provide advance notice of an impending seismic catastrophe.

How far do seismic waves travel during an earthquake?

Through seismic waves, earthquakes unleash buried energy in the rocks. The seismic waves that result from an earthquake radiate from the epicenter outward.

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Angular momentum of moon = 2.88 × [tex]10^{34}[/tex]kg.[tex]\frac{m^{2} }{sec}[/tex]

The orbital angular momentum of the Moon is  1.22 × [tex]10^{5}[/tex]  times more than its rotating angular momentum.

Mass of moon = 7.35 × 10²²kg

        radius (r) = 1.74 × [tex]10^{6}[/tex]m

Time period (T) = 27.3days = 27.3 × 24 × 3600sec

distance from earth(R) = 3.84 × [tex]10^{8}[/tex] (= orbiting radius)

a) Angular momentum of moon in its orbit around earth is

[tex]L_{orb}[/tex] = [tex]I_{w}[/tex]

in where I = moment of inertia = m[tex]R^{2}[/tex] =  7.35 × 10²² ( 3.84 × [tex]10^{8}[/tex])²

                                                          = 1.084 × [tex]10^{40}[/tex] kg.m²

and ω = 2π/T

          = 2π/27.3 × 24 × 3600 = 2.66 × [tex]10^{-6}[/tex][tex]\frac{rad}{sec}[/tex]

[tex]L_{orb}[/tex] = [tex]I_{w}[/tex] =  1.084 × [tex]10^{40}[/tex] kg.m² × 2.66 × [tex]10^{-6}[/tex]

[tex]L_{orb}[/tex] = 2.88 × [tex]10^{34}[/tex]kg.[tex]\frac{m^{2} }{sec}[/tex]

b) Angular momentum of moon around it's axis is (due to rotation),

[tex]L_{m} = I_{m} W_{m}[/tex] = [tex]\frac{2}{5}[/tex] mr² × 2π/T = [tex]\frac{2}{5}[/tex] × 7.35 × [tex]10^{22}[/tex] × (1.74 × [tex]10^{6}[/tex])² × 2.66 × [tex]10^{-6}[/tex]kg.[tex]\frac{m^{2} }{sec}[/tex]

[tex]L_{orb}[/tex] = 2.37 × [tex]10^{29}[/tex] kg.[tex]\frac{m^{2} }{sec}[/tex]

c) The required fraction is:

[tex]\frac{L_{orb} }{L_{rot} }[/tex] = [tex]\frac{2.88(10^{34} )}{2.37(10^{29} )}[/tex] = 1.22 × [tex]10^{5}[/tex]

 [tex]\frac{L_{orb} }{L_{rot} }[/tex]   = 1.22 × [tex]10^{5}[/tex]

What in physics do you mean by orbital angular momentum?

An aspect of an electron's rotational motion called orbital angular momentum is connected to the orbital's geometry. If detection is attempted, the electron will be located in the orbital, which is the area surrounding the nucleus. The orbital around the nucleus has been been referred to as a "electron cloud."

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The width of central interference maximum is 16000×10⁻⁹m if wavelength 400nm passes through two narrow slits.

The width of the central maximum is two times as a significant part of the other maxima. For the m t h request the essential diffraction grinding condition is m λ = d sin θ m where d is the distance between adjoining cuts and the way contrast between neighboring cuts is m λ. Cut is enlightened by the illumination of wavelength 400 A ˚.

We know that width of central maximum is represented by β ,which is equal to=2λD/d

where λ is defined as the wavelength of the light wave,

D is defined as the distance of screen from central maximum

and d is defined between the slits.

So, we have  λ=400nm=400×10⁻⁹m, D=4m,d=0.200mm=0.200 ˣ 10⁻³m

Now,on putting the values in above formula, we get

=>β =2×400×10⁻⁹m×4m/0.200 ˣ 10⁻³m

=>β=3200×10⁻⁹m² / 0.200 ˣ 10⁻³m

=>β=3200000×10⁻⁹m²/200 ˣ 10⁻³m

=>β=16000×10⁻⁹m

Hence, width of central maximum is 16000×10⁻⁹m.

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2.06 second will the arrow heading downward at a speed of 7.9 m/s

Calculation :

As the arrow leaves the bow, it experiences a constant downward acceleration equal to the free fall acceleration g. Upwards, positive direction, the elapsed time/s it takes for the velocity to increase from an initial value of 15.0 m/s upwards (v₀= +12.3 m/s) to a value of 7 .9 m/s downwards change ( vf=−7.9m/s) is

ΔT = ΔV/a

= [tex]\frac{Vf-Vo}{g}[/tex]

=[tex]\frac{12.3-(-7.9)}{9.8}=[/tex] 2.06 sec

Just as distance and displacement (albeit similar) have distinctly different meanings, so do velocity and velocity.speed is a scalar quantity that describes how fast an object is moving. Velocity can be thought of as the speed at which an object travels a distance. A fast-moving object has a high speed and travels a relatively long distance in a short period of time. Compare this to slow, slow-moving objects. Covers a relatively short distance in the same amount of time. A motionless object has zero velocity.

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The angle (between the magnetic field and the area vector) will maximize the induced emf (voltage) for a rotating loop at 90 degree.

Consider a coil with N turns rotating with constant angular velocity θ in a magnetic field of flux density B, with its axis perpendicular to the magnetic field. If the coil normal is at an angle θ to the magnetic field, then θ = ωt, so the flux through the coil is BAN cosθ = BAN cos(ω)t.

Therefore, the electromotive force E generated across the coil is

The maximum value of the electromotive force (Eo) is for θ (= ωt) = 90o

maximum electromotive force (Eo) = BANω

Electromotive Force:

In electromagnetism and electronics, electromotive force is the transfer of energy through a circuit per unit charge, measured in volts. Devices called electrical converters provide EMF by converting other forms of energy into electrical energy.

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The wavelength of light is 0.433 x 10⁻⁶m.

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Dilation is centered a point is chosen in the given figure to draw a new figure of a given scale factor.

Dilation means drawing a geometrical figure like a triangle greater or smaller in size than the given figure. Two things are required to do dilation.

1) Scale factor of dilation, if the scale factor is more than 1, it is enlargement, and we get a figure greater in size than the given figure. If the scale factor is given less than 1, it is the reduction, and we get a figure smaller in size than the given figure.

2) Center of dilation, this is the point in the given figure which is chosen to draw a new figure greater or smaller in size.

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A type E0 galaxy would be a spherical galaxy. Therefore, the correct answer is option B.

Galaxies can be categorized by their shape. They can range from almost spherical to almost flat or even spiral. Here are each class's characteristics:

Attached below is a graph of how galaxies are classified by their shape made by Dr. T.H. Jarrett.

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(a) The gravitational potential energy  (GPE) of Bert is 14,112 J.

(b) The kinetic energy  of Bert is equal to the change in his potential energy.

(c) The velocity of Bert could reach at the bottom of the slide is 15.33 m/s.

The gravitational potential energy of Bert is calculated as follows;

GPE = mgh

where;

GPE = 120 x 9.8 x 12

GPE = 14,112 J

The velocity  Bert could reach at the bottom of the slide is calculated as follows;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √ (2gh)

v = √ (2 x 9.8 x 12)

v = 15.33 m/s

Based on the law of law of conservation of energy, the kinetic energy gained = potential energy lost.

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Sleep is very important in saving the person from injuries. Proper sleep helps person to perform well during the chaos work like riding a motor, crossing the road etc.

Sleep has been found to affect sports execution and generally prosperity. Late exploration has found proof relating persistent sub-par lay down with the gamble of outer muscle torment and sports injury. How much sleep that reliably has been viewed as related with expanded chance of injury is ≤7 h of sleep, which when supported for times of something like 14 d has been related with 1.7 times more serious gamble of outer muscle injury.

Be that as it may, it is obscure assuming that sleep misfortune inclines the competitor toward explicit kinds of outer muscle wounds. The job of sleep on outer muscle torment is essential to comprehend as concentrates in the two kids and grown-ups have found that sub-par rest all the more reliably predicts following day torment as contrasted and torment foreseeing ensuing rest misfortune.

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The heat associated with the combustion of 400 g of octane, assuming complete combustion, is -16859.9 kJ.

Given, the molar mass of octane is 114.33 g/mole.

Let's consider the following thermochemical equation.

C₈H₁₈ + 25/2O₂ ----- 8CO₂ + 9H₂O ΔHᵣₓₙ = -4819

For one mole of octane = -4819kJ

The number of moles in 400 g of octane will be = 400/114.33 = 3.49 moles

So the heat associated with the combustion of 3.49 moles will be

= {3.49 ×(-4819)} kJ

= -16859.9 kJ

Therefore, the heat associated with the combustion of 400g of octane, assuming complete combustion, is -16859.9kJ

The molar heat of combustion is the heat released when one mole of a substance is completely burned. Typical combustion reactions involve the reaction of a carbon-containing material with oxygen to form carbon dioxide and water as products.

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A total of -700 J worth of heat energy is transferred from the system.

Data provided

W = - 500 J is the amount of work the system has done. (A bad indication that the system needs work)

U = -100 J represents the reduction in thermal energy (internal energy). (A negative sign indicates a decrease)

Use the first law of thermodynamics, which states that the sum of the work done and the thermal energy is equal to the overall heat given to the system. Therefore,

Q = W + U

Q = - 500 + (-200)

Q = - 700 J.

A negative indication indicates that the system is losing heat energy.

As a result, -700 J of heat energy is transferred from the system.

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the output current of the transformer in amps is 2.58 A

Calculation :

Transformation ratio k=[tex]\frac{N2}{N1} = \frac{V2}{V1}=\frac{I1}{I2}[/tex]

N₁ = 412 , N₂ = 319

I₁ = 2 A

To find I₂,

[tex]\frac{I1}{I2} =\frac{N2}{N1}[/tex]

I₂ = (I₁)([tex]\frac{N1}{N2}[/tex])

I₂ = (4)([tex]\frac{412}{319}[/tex])

I₂ = 2.58 A

Electric current is the flow of charged particles, such as electrons and ions, that travel through a conductor or space. [1]: 2 [2]: 622 Moving particles are called charge carriers and can be one of several types depending on the particle. to the conductor. In electrical circuits, charge carriers are often electrons moving through wires. In semiconductors they can be electrons or holes. In electrolytes the charge carriers are ions and in plasmas ionized gases, ions and electrons.

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The platform should move at a rate of 48.3 m/s. This is calculated by taking the speed of sound, 344 m/s, and dividing it by the beat frequency of 7.00 Hz (which is equal to 7 beats/second). 344 m/s / 7 beats/second = 48.3 m/s.

Step 1: Calculate the wavelength of the sound wave with a frequency of 7 Hz. The wavelength is the distance a sound wave travels in a single cycle.

Wavelength = Speed of Sound (m/s) / Frequency (Hz)

Wavelength = 344 m/s / 7 Hz

Wavelength = 49.14 m

Step 2: Calculate the speed of the platform (vp) needed to detect the beat frequency of 7 Hz.

Speed of Platform (vp) = Wavelength (m) * Frequency (Hz)

Speed of Platform (vp) = 49.14 m * 7 Hz

Speed of Platform (vp) = 343.98 m/s

Therefore, the platform needs to move at a speed of 343.98 m/s for the person to detect a beat frequency of 7.00 Hz.

The speed of sound is the distance sound travels through a medium in a given amount of time. It is typically measured in meters per second (m/s). It is determined by the properties of the medium, such as temperature, pressure, humidity, and the medium itself. In air, the speed of sound is approximately 343 m/s (1,125 ft/s). In water, the speed of sound is much faster, around 1,484 m/s (4,887 ft/s).

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Answer: The pressure gets worse.

Explanation:

a 0.00120-nm photon scatters from a free electron -

a) λ₁ = 5.27 × 10⁻³  nm

b) E = 30 KeV

Free electrons are those that are not constrained by the atom and are hence free to travel. Since we now know that an electric current is just an electron moving, The ability to conduct electricity results from the free electrons' propensity for free motion. Because they are efficient electrical conductors, metals have free electrons.

a)

λ is the wavelength of the photon before scattering,

λ₁ is the wavelength of the photon after scattering,

m(e) is the mass of the electron,

θ is the angle by which the photon's heading changes,

h is Planck's constant, and

c is the speed of light

λ₁ - λ = [h/m(e)c] × [1 - cos θ]

Since we have energy for the incoming x-ray, we need to solve for frequency (f) and then for wavelength (λ) using the following two equations.

E = (h)×(nu),

where E is energy of the x-ray (265KeV),

h is planck's constant (4.14×10⁻¹⁵eV.s) and

nu = f (frequency).

Solving for freqency,

we get f = 6.408 × 10¹⁹ (1/s)

Frequency = c / λ,

and solving for λ,

we get the initial wavelength of the incoming x-ray to be:

λ = c/f

or, λ = [299792458 m/s] / [6.408 × 10¹⁹ 1/s]

or, λ = 4.68× 10⁻¹² m

or, λ = 4.68 × 10⁻³ nm

Going back to the Compton Scatter equation of:

λ₁ - λ = [h/m(e)c] × [1-cos θ]

we need to solve for λ₁:

λ₁  = [h/m(e)c] × [1-cos θ]  + λ

or, λ₁ = [2.43 × 10⁻¹² m][1-cos 41°] +  4.68× 10⁻¹² m

or, λ₁ = 5.27 × 10⁻¹² m

or,  λ₁ = 5.27 × 10⁻³  nm

b)

Going back, we can solve for the energy of the x-ray using the same two equations:

Frequency = c /  λ₁

or, f = 299792458 / 5.27 ×10 ⁻¹²

or, f = 5.68 × 10¹⁹ 1/s

Plugging that into the 2nd equation:

E=(h)×(nu),

= [4.14×10⁻¹⁵eV.s] × [5.68 × 10¹⁹ 1/s]

= 235KeV

and with the conservation of energy

E = 265 KeV - 235 KeV

E = 30 KeV

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A 2.00 m long guitar wire with a linear mass density of 12 g/m is under a strain of 8000 n, and the fundamental frequency of the resonant vibration of this wire is 204.1 Hz.

The frequency of an event is its repetitions per unit of time. As a contrast to spatial frequency, it is also sometimes referred to as temporal frequency, and as a contrast to angular frequency, it is sometimes referred to as ordinary frequency. A physical body's mass is its total amount of matter. Inertia, or the body's resistance to acceleration (change of velocity) when a net force is applied, is also measured by this property.

The formula for a string's fundamental frequency is f = 1/2*L(T/M)^1/2.

where L is the string's length and T is its tension.

M is the string's linear mass density, which is equal to 204.1Hz at f = 1/2*200(8000/0.012)^1/2.

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The wavelength of the laser (λ) = 192.4 nm

The energy of a laser pulse in terms of number of photons is

E = N*hc/λ

where,

λ = wavelength

N = Number of photons in each laser pulse

h = Planck constant

c = Speed of light

λ = n*hc/E

= (9.7*10^14 )(4.136*10^(-15) )(3*10^8 )/6.25*10^16

= 192.4 nm

The wavelength of the laser (λ) = 192.4 nm

Wavelength :

Wavelength is the distance between identical points (adjacent crests) in successive cycles of a waveform signal traveling through space or over a wire. In wireless systems, this length is typically expressed in meters (m), centimeters (cm), or millimeters (mm).

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(A) The wavelength of the laser is λ = 19.4 nm

(B) Average power delivered is 50000 W

A

Given,

Energy by laser pulse = 1 mJ

Time each pulse lasts = 20 ns

Photons in each pulse = 9.7*10¹⁴

Converting the unit the energy from J to eV, we have,

= E = 1 X 10⁻³ [ 1 eV / 1.6 X 10⁻¹⁹ ]

= E = 6.25 X 10¹⁵ eV

The energy of a laser pulse in terms of number of photons is

E = N*hc/λ

where,

λ = wavelength

N = Number of photons in each laser pulse

h = Planck constant

c = Speed of light

Now substituting the values in the formula, we get

wavelength = n*hc/E

λ = [ ( 9.7 X 10¹⁴ X 4.136 X 10⁻¹⁵ X 3 X 10⁸ ) /  6.25 X 10¹⁵ ]

λ = 19.4 nm

The wavelength of the laser (λ) comes out to be 192.4 nm.

B

To find average power we will use the formula:

average power = p = E/t

p = 1 X 10⁻³ / 20 X 10⁻⁹

p = 0.05 X 10⁶

p = 50000 W

The average power delivered to the eye is 50000 W.

Therefore, the wavelength of the laser is 19.4 nm and the average power of the laser is 50000 W.

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Just to be sure you understand how to use and interpret the interactive figure, start with the time slider set to zero.

Newton's second law states that force is proportional to mass and acceleration.

F = m a

The applied force creates an acceleration in the elephant a = F / m. If the mass of the elephant increases m2> m, the expression takes the form a = F / m2. With the denominator is greater the acceleration should decrease by the same factor that increases the mass.

The frequency of a wave depends on the properties of medium density and the elasticity properties change the amplitude depends on the energy carried by the wave, that is, the amplitude is proportional to the height of the wave (oscillation).

Therefore, Just to be sure you understand how to use and interpret the interactive figure, start with the time slider set to zero.

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The kind of evidence concerning radioactivity informed sweden’s nuclear power policy is Contaminated crops and cow's milk.

Almost 30% of Sweden's entire national electricity supply is currently generated using nuclear energy. The three nuclear power plants in the country currently have a total of six reactors in operation. The three NPPs in dispute are Forsmark, Oskarshamn, and Ringhals.

Sweden's nuclear power policy was influenced by radioactivity evidence found in contaminated crops and cow's milk.

Sweden is a non-nuclear state and a signatory to the Nuclear Non-Proliferation Treaty (NPT). The country stopped conducting nuclear weapons research after the Second World War when it ratified the Treaty in 1968.

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The car tires made 0.8 revolutions in 1 s from rest.

Assuming that angular acceleration is constant, the following kinematic equation is used.

θ = θ₀ + ω₀* t + 1/2* α* t²

where,

θ is final angular position in radians

θ₀ is initial angular position in radians

ω₀ is initial angular speed in rad/sec

α is angular acceleration

t is the time measured in seconds

Given that,

Radius = 0.2 m

Angular acceleration α = 10 rad/s²

Time t = 1 sec

If θ₀ = 0, ω₀ = 0, α = 10 rad/s², θ is

θ = 0 + 0* 1 + 1/2* 10 * 1² = 5 rad

Let us convert radians into revolutions:

We know that, 2π radians = 1 revolution

1 radian = 1/(2π) revolutions

5 radian = 5/(2π) revolutions = 5/6.28 = 0.8 revolutions

The tires did 0.8 revolutions in 1 second from rest.

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The boat’s speed when in water is = 20km/hr. The stream’s speed is = 3km/hr

The Riverboat

Downstream= 46km and 2 hours

Upstream= 51km and 3 hours

Speed of the boat?

Let

X= the boat’s speed when it is in the water

C= the stream’s speed

(X+C)= the boat’s speed downstream

(X-C)= the boat’s speed upstream

Distance/speed=time

46/(x+c) = 2

51/ (x-c) = 3

2x + 2c = 46

3x – 3c = 51

6x + 6c = 138 (×3)

6x – 6c = 102 (×2)

Add

12x= 240

x=20

2c = 46-2x = 46 – 40= 6

c = 3

Therefore;

The boat’s speed when in water is = 20km/hr

The stream’s speed is = 3km/hr

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The size of the eddy emf because when field is I = 0.5 A when a flat coil of wire with 200 turns and an area of 15 cm each is placed perpendicular to a consistent magnetic field and increases in strength at a rate of

The magnetic field is the area in which a magnet experience the effects of magnetism. The magnetic field is an effective tool for describing how the magnetic force is distributed within and around a magnet object in nature.

E=−NAd BdtE=−(50×10−4m2)×20××4.0T2.0sE=−0.2 VNow; Magnitude of the induced current

I=Induced emf ResistanceI=ERI=0.2V0.40ΩI=0.5A

The same poles were drawn from one another while the opposite poles were drawn toward one another. When brushed against a magnet, the north-seeking poles of the iron atoms align in the same direction. The force created by the aligned atoms results in the creation of a magnetic field.

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