The mass of the sample = 1.50 g
From the question, we have
q= 9.86 J
C = 0.90 J/g-K
temperature ΔT = ( 30.5 ºC - 23.2 ºC ) = 7.3 ºC = 7.3 K
The heat (q) absorbed is,
q = m x C x ΔT
m= q/ (C x ΔT)
m = 9.86 J / ( 0.90 J/g-K ) x 7.3 K ) = 1.50 g
The mass of the sample = 1.50 g
Heat :
Heat is energy that is transmitted from one body to another when temperatures are different. Heat travels from the hotter body to the colder body when two bodies at differing temperatures come in contact. Heat is the result of the movement of kinetic energy within a material or an item, or from an energy source to a material or an object. Radiation, conduction, and convection are the three mechanisms through which such energy can be transferred.
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located in the outermost energy level of the electron cloud with the most energy
Here the missing component is company group.
What is energy?Energy is the ability to do the work . scientist defines energy as the ability to do work.
We have to have a sample of people representative of the population to compare the experiment results on, because there may be other factors in the general population, in this case, improving memory, that they are saying is because of the energy drink. For example, if all of the population in the random sampling were having improved memory due to something else, then the experiment wouldn't be valid.
These groups of people are used to measure how the deviation from the improvement of memory, in this case, to an average of the population.
These are called control groups.
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What will be the change in internal energy when 12 kJ of work is done on the system and 2 kJ of heat is given by the system?
The change in internal energy when heat is released is 14000J.
The internal energy, U, of a well-defined system or body is the sum of the kinetic energy due to the motion of the molecules and the potential energy associated with the vibrational and electrical energies of the atoms within the molecule. Internal energy also includes the energy of all chemical bonds. From a microscopic point of view, internal energy can be seen in many forms. Because there is no material or repulsion between individual molecules.Internal energy is a state function of the system and is a large quantity. It can have a corresponding strong thermodynamic property called a specific internal energy. This is commonly denoted by a lowercase u, which is the internal energy per mass of the matter in question. So the SI unit for the given internal energy is J/g. When the internal energy is expressed in units of moles, it is called the molar internal energy and has units of J/mol.W=12000J
Q=2000J
Q=U+W
U=Q-W
U=14000J or 14kJ
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A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the bob's mass is doubled, approximately what will the pendulum's new period be?
The pendulum's new time period is T.
A bob suspended at the end of a thread that is so light as to be regarded massless makes up a simple pendulum. It serves as an example of a conservative oscillatory system. A point mass m anchored to one end of a massless rod of length L makes up this idealized representation of a pendulum.
The time period of a simple pendulum is calculated by the formula, [tex]T=2\pi\sqrt{\frac{L}{g}}[/tex] where T is the time period, L is the length of the pendulum, and g is the acceleration due to gravity. Since this formula is independent of mass, the change in the mass of the bob doesn't affect the time period. Therefore, the new time period will still be T. There is no change.
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how much work is required to push a crate at constant velocity with a force of 210 n across a floor a distance of 5 m?
Work done is calculated as the scalar product of force and displacement along the force's direction, so it should be zero because there is no net force acting on the object (hence the constant velocity). Thus, W is equal to 0.
How do you figure out an object's force with constant velocity?Newton's first law of motion states that any object moving at a constant speed experiences no net external forces, so the total amount of forces acting on the object must be zero. The mathematical expression for an object being under no net external force is Fnet=0 or F=0.
Acceleration equals zero when velocity stays the same. Therefore, an object moving at a constant speed does not require any force.
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a high or low tide that is more extreme than usual is a(n) tide; a weaker than usual tide is a(n) tide.
A high or low tide that is more extreme than usual is a(n) tide, it is stronger than usual tide.
The moon is the primary cause of high and low tides. The tidal force is produced by the moon's gravitational pull. Earth and its water protrude outward on both the side that is closest to and farthest from the moon as a result of the tidal force. These watery peaks are high tides.
Your part of the Earth spins around both of these bulges every day. You encounter a high tide while you're inside one of the bulges. The tide is low when you are not in one of the bulges. On the majority of the world's coastlines, this cycle of two high tides and two low tides occurs every day.
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true or false: the frictional resistance of a fault is higher when it is locked than when it is moving.
The answer is true: a fault's frictional resistance is higher when it is locked than when it is moving.
What is Frictional Force?Friction refers to the force that prevents two hard surfaces from rolling or sliding over each other. Although friction force, such as the traction required to walking avoid slipping, may be advantageous, they can provide a significant amount of resistance to motion.
The adhesion forces between the contact zones of a surface, which are constantly microscopic examination uneven, appear to be the main contributor to metal friction. The shearing of these "bonded" joints and the movement of the rougher surface's imperfections scrubbing against the softer surface cause friction.
When an object slide over a surface, as no surface is 100% smooth there are some microscopic irregularities are there on the surfaces of both object as well as the surface so when the sliding takes place on the surface the irregularities get interlocked and that causes friction between surfaces.
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a cart starting from a speed of 3 m/s moves down a slope and at the bottom has a speed of 7 m/s. what is the height of the slope?
A cart speed will often increase on a downhill slope while decreasing on an uphill section. A steeper gradient portion has a more pronounced impact on the acceleration or slowdown of a vehicle's speed.
What effect of slope on speed of car?The cart speed/velocity will progressively rise by the same amount each second. The rate of acceleration of the car increases with the slope's steepness (or the ramp's greater angle of inclination). This is so because the slope's angle determines how much gravity is felt.
Therefore, the more gravitational potential energy that can be turned into kinetic energy, the higher the ramp will be, and the more kinetic energy there is, the faster the car will move.
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What is the momentum of a car with a mass of 1200 kg moving at 25 m s?
The momentum of the moving car is 30000 kg m/s.
The momentum of a moving body is calculated as the product of mass and velocity. It is a vector quantity. In simple terms, it is the strength or force gained by a moving object.
Newton's second law is related to momentum. According to newton's second law, " The time rate of change of momentum is equal to force".
We have the formula for finding the momentum,
Momentum = Mass× Velocity
P = M × V
Put the value in the formula,
P = 1200 × 25 kg m/s
= 30000 kg m/s
So, the car is moving with a momentum of 30000 kg m/s.
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calculate the wavelength for an electron moving at 3.00x103 m/s in nanometers. (mass of an electron
The wavelength for an electron moving at 3.00x103 m/s is 244 nm
Given, Mass of electron = 9.1093 * [tex]10^{-31}[/tex]
velocity = 3.00 * [tex]10^{3}[/tex] m/s
wavelength λ = h / mv
λ = 6.626 * [tex]10^{-34}[/tex] / [tex]9.1093 * 10^{-31}[/tex] * [tex]3.00 * 10^{3}[/tex]
λ = 244 nm
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Where is IR on the electromagnetic spectrum?
Infrared Radiation lies on third place of electromagnetic spectrum in the increasing order of frequency.
In his experiments to measure temperature differences between colors in the visible spectrum, he placed a thermometer in the path of light within each color in the visible spectrum. He noticed that the temperature rose from blue to red, and found that just beyond the red end of the visible spectrum showed even higher temperatures. Within the electromagnetic spectrum, infrared waves occur at frequencies higher than those of microwaves and slightly lower than those of red visible light, hence the name "infrared".
Infrared radiation is an integral part of the electromagnetic spectrum.
It has wavelength of 700nm and has good application for earth sciences.
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When a weight W is hanging from a light vertical string, the speed of pulses on the string is V. If a second weight W is added without stretching the string, the speed of pulses on this string will now become Select one: a_ V/ V2 b. V/2 C V: d. 2V. e_ V V.
The pulse rate on a light straight string is V sqrt when a weight W is suspended from it (2V)
The correct answer is D
What the is physics' definition of speed, and how do you quantify it?A distance's rate of change over time is used to calculate speed. It has a dimension of distance via time. The Vernier scales of speed is made up of the fundamental units of distance and time. The unit of speed in the metric system is meters per second.
Exactly what is speed?What is considered speed? the rate at which an object's location changes in any direction. Speed is defined as the relationship between length and the time required to travel a distance. Speed is a scalar number because it has no magnitude and only a direction.
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Which is the internal energy of an object due to the kinetic energy of its atoms and or molecules?
Internal energy of equipartition energy is due to kinetic energy of molecules.
Some thermodynamic confusion. For simplicity we will assume an ideal gas.dU = n Cv dtIf a gas does some work adiabatically, heat change dQ = 0There are now two possible cases:
1) Expansion occurs at the expense of the gas's internal energy, so the gas temperature decreases as it expands. Therefore U decreases.
2) As the temperature decreases, so does the velocity of the gas molecules and the K of the gas decreases continuously.
This concept often takes into account what considers heat as internal energy. Molecular kinetic energy, vibrations, rotations, electron "shell" positions, molecular bending, crystal lattice vibrations, etc.
Generally, pressure should be considered part of the internal energy. Theoretically, matter can be expanded or heat can be transferred to do work.
At absolute zero temperature and pressure we can see that there is still internal energy. This can be seen as a result of the blurring principle. Particles cannot be confined to too small a volume and velocity.
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Does dilation change the vertices?
Dilation doesn't always change the vertices.
In mathematics, dilation is a type of transformation that changes the size of a shape or geometric figure, but keeps the relative proportions and shape the same. Magnification is defined as the ratio of the size of the new image to the size of the old image. The center of expansion is a fixed point in the plane. A dilation transform is defined based on the scale factor and dilation center.If the scale factor is greater than 1, the image will be stretched.If the scale factor is between 0 and 1, the image will be scaled down.If the scale factor is 1, the original image and the generated image are congruent.Some of the shape features that are not changed during the stretch deformation are:All angles of the shape are the same.The center of the sides of the shape remains the same as the center of the unfolded shape.Parallel and vertical lines of the shape Enlargement The parallel and vertical lines of remain the same. The image remains the same.To study about dilation transform -
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A 61. 7 kg carpenter at a construction site plans to swing in a circular arc from one roof top to an adjacent roof at the end of a 11. 5 meter rope suspended from a crane boom. If her wiry arms, toughened by years of driving spikes with a no. 22 framing hammer, are capable of exerting 1229 n of force on the rope, what is the maximum speed that she can tolerate at the low point of her swing?
The maximum speed she can tolerate at the low point of her swing is 10.78 m/s.
Given that,
Mass of the carpenter = 61.7 kg
Length of the rope = 11.5 m
Capable force = 1229 N
Centripetal force acting on the body, F = mv²/r = 61.7* v²/11.5 = 5.37 v²
Gravitational force acting on her is
F = mg = 61.7* 9.81 = 605.28 N
Equating the summation of centripetal force and gravitational force with total capable force,
5.37 v² + 605.28 = 1229
5.37 v² = 623.72
v² = 116.15
v = 10.78 m/s
Thus, the maximum speed she can tolerate at the low point of her swing is 10.78 m/s.
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an object 20-cm high is placed 1.0 m in front of a converging lens whose focal length is 1.5 m. determine the image height (in cm). a. 150 b. 75 c. 60 d. 80 e. 50
The image height of the given converging lens is 6.67 cm.
The focal length of an optical gadget is a degree of the way strongly the gadget converges or diverges light; it's miles the inverse of the gadget's optical energy. A effective focal length suggests that a system converges light, while a poor focal period shows that the gadget diverges mild.
The focal length is half of the radius of curvature and is as f=R2 f = R 2 , where f is the focal period, and R is the radius of curvature.
Calculation:-
object height = 20 cm
object distance = 1m = 100 cm
focal length = 1.5 m = 150 cm
image height = ?
height of image/height of object = f/ f - U
20/H = 150 / 150 - 100
20/H = 150/50
20/H = 3
H = 20/3
Height of object is = 6.67 cm.
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how much friction force must the brake apply to the rim to bring the he 3.40 kg , 32.0-cm-diameter disk to a halt in 2.50 s
We need to know angular acceleration α to give answer to this question. For completing the question, suppose the disc is spinning at 300 RPM.
Angular acceleration α = (300× 2/ 60)/2.50 = 4 m/square second
The required torque L is given by
L = I*alpha,
where,
I = the moment of inertia of the disc,
I = (1/2) M R^2
Therefore
L = (1/2) M R^2 *4 rad/s^2
The units will be Newton-meters
Once you have determined L, use
F = L/R for the required friction force, in Newtons.
Friction is the force that always resists motion of a moving object on the surface of other object.
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A 0. 2-kilogram red ball is thrown horizontally at a speed of 4 meters per second from a height of 3 meters. A 0. 4-kilogram green ball is thrown horizontally from the same height at a speed of 8 meters per second. Compared to the time it takes the red ball to reach the ground, the time it takes the green ball to reach the ground is.
The time takes for the green ball to reach the ground is equal to 0.78 s. As both balls are thrown from the same height they will take the same time to reach the ground irrespective of their velocity.
What is the equation of motion?The equations of motion can be described as the equations which establish the relationship between the time, velocity, acceleration, and displacement of a moving object.
The equations of motions as the mathematical expressions:
[tex]v = u +at\\S = ut +(1/2)at^2\\v^2-u^2= 2aS[/tex]
Given, the height from which the ball is thrown, h = 3
From the 2nd equation of motion, calculate the time taken by the ball reach to the ground:
H = ut + (1/2)gt²
3 = 0 + (1/2)× 9.8×t²
t = 0.78 s
As the time is independent of the velocity of a ball so both balls take the same time to reach the ground as they are thrown from the same height.
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5 pts what mass of 23592u must undergo fission to operate a 1000-mw power plant for one day if the conversion efficiency is 33 %? (assume 208 mev released per fission event.)
M = 2.99 kg≅ 3kg under goes fusion
Given,
P = 1000 M W = 1 x 10^9 J/s
efficiency = 33% ; E' = 208 MeV = 3.33 x 10^-11 J
Energy released in a day
E(day) = P x t
E(day) = 10^9 x 24 hrs x 60 min x 60 sec = 8.46 x 10^13 J
energy released in fission would be:
E(fission) = E(day)/0.33 = 8.46 x 10^13/0.28 = 2.56 x 10^14 J
We have Energy released per fission(E'), so the number of fission to release E(fission) would be:
N = E(fission)/E'
N = 2.56 x 10^14/3.33 x 10^-11 = 7.68 x 10^24
Number of moles = N/Avogadro's No
n = 7.68 x 10^24/6.023 x 10^23 = 12.75 moles
Mass of required 235U92 will be:
M = n x 235 g = 12.75 x 235 = 2996.25 grams = 2.99 kg≅ 3 kg
Hence, M = 2.99 kg≅ 3kg
Fission:
Nuclear fission is a response in which the nucleus of an atom splits into two or more smaller nuclei. The fission method frequently produces gamma photons, and releases a completely massive amount of power even through the lively requirements of radioactive decay.
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a block is placed on a spring, compressing it 0.30m. what height does the block reach when launched by the spring?
The height the block reachs when launched by the spring 0.917 m.
What is a box-spring system?Simply said, a spring-mass system is a spring system with a block hanging or fastened to the free end of the spring. The period of any item moving in a simple harmonic motion may often be determined using the spring-mass system. There are several other uses for the spring-mass system. For instance, the spring-mass system may be used to replicate foot skin deformation and the action of human tendons using computer images. There are two ways to arrange spring mass systems. These consist of: The parallel arrangement of springs , a series of springs combined.
m = 0.5 kg , K = 100 N/m , ∆x = 0.3 m
By conservation of energy :-
KEi + PEg + PEelastic = KEf + PEg + PEelastic
0 + 0 + 0.5*K*∆x^2 = 0 + mgh + 0
0.5*100*(0.3)^2 = 0.5*9.81*h
h = 0.917 m
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a car traveling 25 m/s begins to decelerate at a constant rate of 4 m/s^2. after how many seconds does the car come to a stop and how far will the car have travaled before stopping?
6.25 s does the car come to a stop and 78.125 m distance travelled before stopping.
Solution:
Given:
Initial velocity, v0 = 25 m/s
Acceleration, a = -4m/s2
Final velocity, vf = 0
Put these values in the formula,
To find time,
vf = v0 + a*t
0 = 25 - 4t
t = 25/4
t = 6.25 s
To find distance travelled,
d = ((vf + v0)/2)*t
d = 25/2 * 6.25
d = 12.5 * 6.25
d = 78.125 m
Hence, 6.25 s does the car come to a stop and 78.125 m distance travelled before stopping.
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the index of refraction of water and diamond are 1.33 and 2.42, respectively. in which medium does light travel faster? a. water b. diamond c. same speed in both water and diamond d. not enough information
The light travels faster in water medium with a density of 1.33 when compared to diamond medium with a density of 2.42.
A denser medium will have more matter compared to rarer medium. So, the scattering of light is higher in a denser medium resulting in lesser travel speed. Slower the speed higher will be the index of refraction. So light will travel more slowly in a dense medium.
Refractive index of Diamond = 2.42
Refractive index of water = 1.33
Since, refractive index is inversely proportional to speed of the wave, speed of light in water is higher than the speed of light in diamond.
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A blue car travels at a constant velocity of 24 m/s on a hot 100 degree summer day and has a momentum of 28,800 kg-m/s. What is the mass of the car? Data Formula Work
Answer:
the mass of the car is very big
Explanation:
its heavy
how does a sprinter sprint what is the forward force on a sprinter as she accelerates. where does that force come from
On the starting blocks, sprinters use their feet to push backward. The blocks respond by pressing forward with a force equal to this with their feet.
What drives the sprinter forward?Vertical forces must be larger than the pull of gravity in order to assist the sprinter in moving forward as gravity is pushing him or her downward. The propulsive force is the force that propelled the runner forward.
Basketball players must jump straight up into the air, but how?An interaction diagram and a free-body diagram should be included in your explanation. The player pushes down on the ground, which pushes up against him in return. As a result of his push being stronger than gravity, the player accelerates upward.
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Why did the team choose to measure the parallax of nearby stars, whose distances are already well known?
By utilizing the idea of parallax, we can decide how cosmologists decide distances to stars.
Presently, we perceive how parallax estimations can be utilized to decide the distances, one of the realities we know is that if we have any desire to gauge the distance of divine bodies, we are familiar with the parallax, first and foremost, point. That's what it intends assuming we can quantify tiny parallax points, we can gauge enormous distances moreover.
The purpose for why we can not make precise estimations of parallax past a specific distance is that as the distance of the star from earth builds the parallax point turns out to be tiny.
Subsequently, presently we comprehend how parallax estimations are utilized.
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The temperature at a point in a ball with conductivity is inversely proportional to the distance from the center of the ball. find the rate of heat flow across a sphere of radius with center at the center of the ball.
The heat flow of the thermal resistance is (r2 - r1) / 4πkr1r2).
Consider the diagram below, the heat flow will be
Fourier's law in radial coordinates
qr = -k.AdT/dr
Substituting the values of the area of sphere,
qr = -k (4πr²) dT/dr
Integrating we get
qr/4π∫dr/r^2 = ∫kdt
qr/4π ∫dr/r^2 = ∫kdt
qr/4π (1/r1 - 1/r2) = k(t2-t1)
qr = 4πkr1r2(t1-t2) / (r2 - r1)
The thermal resistance is expressed as
R = (r2 - r1) / 4πkr1r2)
Therefore, the heat flow of the thermal resistance is (r2 - r1) / 4πkr1r2).
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calculate the drift velocity of electrons in a 12-gauge copper wire (which has a diameter of 2.053 mm) carrying a 20.0-a current, given that there is one free electron per copper atom. (household wiring often contains 12-gauge copper wire, and the maximum current allowed in such wire is usually 20 a.)
The drift velocity of electron is 4.54 * 10⁻⁴ m/s.
Given that, Density of copper is 8.8* 10³ kg/m³
Charge of an electron is 1.6* 10⁻¹⁹ C
For the density of copper, the number of free electrons n can be calculated by
n = number of electrons per kg * ρ
⇒ (9.4776* 10²⁴ ) (8.8 * 10³ kg/ 1 m³) = 8.314 * 10²⁸ electrons per m³
Diameter of the wire is given as 2.053 mm
Let us calculate A for the provided diameter of wire
A = π * (d/2)² = π * (2.053 /2)² = 3.310* 10⁻⁶ m²
Given, I = 20 A
We know the expression for drift velocity as
Vd = I /(n* A* e) = 20 / (8.314 * 10²⁸ * 3.310* 10⁻⁶ * 1.6* 10⁻¹⁹) = 20 / (4.403 * 10⁴) = 4.54 * 10⁻⁴ m/s
Thus, the drift velocity of electron is 4.54 * 10⁻⁴ m/s.
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as you stand near a railroad track, a train passes by at a speed of 31.7 m/s while sounding its horn at a frequency of 218 hz. what frequency do you hear as the train approaches you? what frequency do you hear while it recedes? use 343 m/s for the speed of sound in air.
When the train approaches you, the Doppler's effect gives the frequency 240.12 Hz
When the train moves away from you, the Doppler's effect gives the frequency 199.6 Hz
Given that,
Frequency of train horn, f = 218 Hz
Speed of train, Vt = 31.7 m/s
The speed of the sound , V = 344 m/s
When the train approaches you, the Doppler's effect gives the frequency as follows :
[tex]f^{'} = f (V/ V-V_{0} )[/tex]
[tex]f^{'}[/tex] = 218 * ( 344/ 344 - 31.7)
= 240.12 Hz
When the train moves away from you, the Doppler's effect gives the frequency as follows :
[tex]f^{'} = f ( V / V+ Vt)[/tex]
= 218 * ( 344/ 344 + 31.7)
= 199.6 Hz
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an astronaut on the moon has a 110 kg crate and a 230 kg crate. how do the forces required to lift the crates straight up on the moon compare with the forces required to lift them on earth? (assume that the astronaut lifts with constant velocity in both cases.)
A lunar astronaut carries a 110 kg box and a 230 kg load. The forces required to move the containers straight up on the moon are enormous compared to the forces required to hoist them on Earth.
A forces is an influence with the capacity to change the motion of an object. When an object with mass moves away from rest, for example, a force can cause it to accelerate as its velocity increases. A push or a pull are two straightforward ways to demonstrate force. Since a force has both magnitude and direction, it is a vector quantity. It is computed using the SI unit of newton (N). The letter F stands for force (formerly P). The original wording of Newton's second law states that the net force acting on an item is equal to the rate of change of its momentum over time. This law states that if an object's mass stays constant, its acceleration should be directly proportional to the net force exerted on it and inversely proportional to the object's mass. Thrust, which increases an object's velocity; drag, which decreases an object's velocity; and torque, which modifies an object's rotational speed, are all ideas connected to force. Internal mechanical stress describes how these forces are distributed within the body. The adjacent regions are frequently put under stress by each expanded body part.
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What is the band gap energy in kilojoules per mole if blue diamonds absorb orange light with a wavelength of 675 nm?
The band gap energy in kilojoules per mole is 1.73×105 J.
The band gap is the distance between the valence band and the conduction band of an electron. Essentially, the bandgap represents the minimum energy required to excite an electron to a state in the conduction band where it can participate in conduction. Higher frequencies and lower wavelengths of light are absorbed.
In physics, especially for solids, the band gap is also called the energy gap. It is the range of energies that exist in solids where no other electronic state can exist. In the diagram of the electronic band structure of solids, the band gap is commonly called the energy difference.
Therefore, the band gap energy of wavelength 675 nm is 1.73×105 J.
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how far from the lens should an object be held so that its image is seen at the near-point distance of 25 cm ? assume that your eye is immediately behind the lens.
The distance of lens from the object is 4.16 cm, so that its image is seen at the near-point distance of 25 cm.
The near-point distance of a human eye, described to be s = 25 cm, is the shortest item distance that a typical or "normal" eye is capable of accommodate, or to photo onto the retina. The some distance point of a human eye is the farthest object distance that a standard eye is able to photo onto the retina.
The human eye can see objects genuinely with none pressure on the attention while an item is placed at the least 25 cm away. This distance of 25 cm is called the close to point of the eye. while the object is positioned at a distance between 25 cm and infinity, the photo of the object is fashioned on the retina and interpreted surely.
Calculation:-
for magnifier
magnification m = 25 cm /f
5 = 25/f
f = 25/5 = 5 cm
ten using lens equation
1/f = 1/do + 1/di
1/5 = (1/do)-(1/25)
1/do = (1/5)+(1/25)
do = 4.16 cm
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