The mass of hydrogen present in 50.7 grams of ammonia is equal to 8.95 g.
What is a mole?A mole is a scientific unit that is used to determine the huge number of quantities of atoms, molecules, ions, etc. The mass of the 1 mole of any element is called atomic mass and that of one mole of any compound is called molar mass.
The number of entities present in 1 mole was found to be equal to 6.023 × 10 ²³ per mole which is known as Avogadro’s constant.
Given, the mass of ammonia = 50.7 g
The mass of the one mole of ammonia = 17 g/mol
17 g of ammonia contain the mass of hydrogen = 3 g
50.7 g of ammonia contains a mass of hydrogen = (3/17) × 50.7 = 8.95 g
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Which of the following minerals is the most resistant to being scratched?
Hematite
Calcite
Orthoclase
Garnet
37.In the compound MgO, what is the oxidation number of oxygen?Select one:a. +4b. +2c. +1d. -2
When we have to determine the oxidation number of compounds, we need to look at their specific and most common charges in their non neutral form, and Oxygen is an element that will usually present a -2 oxidation number and charge, the same way Hydrogen will almost always present a charge of +1, these fixed values for some elements is helpful for us to determine the oxidation number of other elements. For oxygen is -2, therefore letter D
3 Cu + 8HNO3 g 3 Cu(NO3)2 + 2 NO + 4H₂O
In the above equation how many moles of NO can be made when 75 moles of HNO3 are
consumed?
As per the given statement 0.297mol NO can be made when 75 moles of HNO3 are consumed
What is HNO3?The inorganic substance with the formula HNO3 is nitric acid. It is a mineral acid that is quite corrosive. The substance is colourless, but older samples have a tendency to have a yellow cast because of breakdown into nitrogen oxides..
'3 Cu + 8HNO3 3 Cu(NO3)2 + 2 NO + 4H₂O
Element Molar Mass
Hydrogen 1
Nitrogen 14
Copper 63.5
Oxygen 16
Referring the above table we get no of moles in HNO3
1(1.0) + 1(14) + 3(16) = 1 + 14 + 48 = 63 g/mol
75g HNO3 x 1 mol HNO3/63 g HNO3 = 1.190 mol HNO3
The coefficient of HNO3 is 8, and NO is 2
1.190 mol HNO3 x 2 mol NO/8 mol HNO3 = 0.297mol NO
Hence, 0.297mol NO can be made when 75 moles of HNO3 are consumed.
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A mixture of krypton and neon gas is compressed from a volume of 79.0L to a volume of 71.0L, while the pressure is held constant at 17.0atm. Calculate the work done on the gas mixture. Round your answer to 2 significant digits, and be sure it has the correct sign (positive or negative).
Using the fact that:
[tex]W=P\Delta V[/tex]We could replace our values as follows:
[tex]\begin{gathered} W=17atm\cdot(71L-79L) \\ W=17atm\cdot(-8L) \\ W=-136J \end{gathered}[/tex]As you can see, the work done is negative since the gas is being compressed. Therefore,
The work done is -136J.
In kJ, the answer is -0.136kJ. Rounded to 2 significant digits, this is -0.14kJ
A balloon is filled with a 0, gas and has a volume of 179mL at 2.00 atm pressure. What will its volume be if thepressure is changed to 5.50 atm?A) 29.2 mLB) 65.1 mLC) 17.9 mLD) 83.0 ml
In this case, we can use the Boyle's law to solve this problem:
[tex]P1\cdot v1=P2\cdot v2[/tex]We already know the values of P1, v1 and P2 and we have to find v2. Replace for the given values and solve for v2:
[tex]\begin{gathered} 179ml\cdot2.00atm=5.50atm\cdot v2 \\ v2=\frac{179ml\cdot2.00atm}{5.50atm} \\ v2=65.1ml \end{gathered}[/tex]The correct answer is B) 65.1ml.
11. Balance the following acid/base reaction: __Ca(OH)2 + __H2CO3 --> __CaCO3 + __H2O
Given the unbalanced acid/base reaction expressed as:
[tex]aC_{}a\mleft(OH\mright)_2+bH_2CO_3\longrightarrow cCaCO_3+dH_2O[/tex]The equation is balanced if the number of moles of element at the reactant is equal to that of the product.
Next is to determine the values of the constants a,b, c, and d by equating the number of moles of the element on both sides.
For the Calcium element:
a = c .................................. 1
For the Oxygen element
2a + 3b = 3c + d ......................... 2
For the Hydrogen element
2a + 2b = 2d
a + b = d .......................... 3
For the carbon element
b = c ....................... 4
Substitute equation 1 and 4 into 3 to have:
c + c = d
2c = d
d = 2c ...................... 5
Substitute equations 1, 4, and 5 into the unbalanced equation to have:
[tex]cC_{}a(OH)_2+cH_2CO_3\longrightarrow cCaCO_3+2cH_2O[/tex]Cancel out the constant "c" from both sides of the equation to have:
[tex]\begin{gathered} \cancel{c}C_{}a(OH)_2+\cancel{c}H_2CO_3\longrightarrow\cancel{c}CaCO_3+2\cancel{c}H_2O \\ C_{}a(OH)_2+H_2CO_3\longrightarrow CaCO_3+2H_2O \end{gathered}[/tex]This gives the balanced chemical equation
Properties:large brittle crystalhigh MPthigh BPtnon-conductorThe properties above would best describe a solid held together by.....ionic bondscovalent bondsintermolecular forces
In general, ionic compounds have the following characteristics:
• They are solid at room temperature;
,• Its atoms arrange themselves in such a way as to produce a crystalline lattice (a crystal).
,• They are soluble in water;
,• They are capable of performing the phenomenon of dissociation (ion release) when they undergo fusion, that is, when they change from the solid state to the liquid state, or when they are dissolved in water;
,• They have high melting and boiling points;
,• They have shine;
,• They conduct current when dissolved in water or after undergoing the melting process.
,• Non-conductor at solid state.
Covalent compounds have the following characteristics:
• Physical State at Room Temperature: Under ambient conditions, molecular and covalent compounds are found in three physical states (solid, liquid, and gas).
,• Melting and Boiling Point: In general, the melting and boiling points of these substances are lower than those of ionic substances.
,• Electric current: In their pure forms, both liquids and solids do not conduct electric current.
,• Solubility: Polar dissolves into polar and non-polar dissolves into non-polar.
,• Tenacity: The resistance of covalent substances to impact or mechanical shock is low.
,• In general, they are brittle solids, as shown in the case of glass, which is formed by sodium and calcium silicates.Hardness: In general, they have high hardness.
With this in mind...
Answer: ionic bonds
C*(UPQuestion 6 of 26šiWhich of the following sets of quantum numbers is not allowed?A) n = 1, l = 0, ml = 0B) n = 4, f = 0, ml = -1C) n = 3, l = 1, ml = 0D) n = 2,1 = 0, ml = 0E) n = 3, l = 2, ml = -2
Let's analyze option B:
Given that n=4, l=0 and ml=-1, we could draw:
If we have n=4, l=0, that means that the electron configuration ends at 4s. As you can notice, "s" orbital can only adquire one pair of electrons and ml can only be 0. In the answer option this is -1, so this option is not correct.
The answer is B.
Which of these characteristics would most help a city make long-term road
and infrastructure plans?
O A. Age structure
OB. Birthrate
C. Growth rate
OD. Death rate
The characteristics that would help a city to be able to make long term infrastructural plans is the growth rate. Option C
What is infrastructure?The term infrastructure has to do with the facilities that are put up in a city to aide life in a city. It is the process of development in a city that helps a city to be able to aide the inhabitants to live a comfortable life.
It is very important to see that there is a laid down plan for the development of a city or a place and this is very essential to the development of the place and the better life of the people that live in the city.
Now, the infrastructural plans that are made in a city has to factor in the growth rate of the city and this have to be based on the projected growth rate.
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What is the density of NH3 at 800 torr and 25 degree celsius?
To solve this question, we need to use the following formula:
[tex]\rho\text{ = }\frac{(MM_{NH_3})(P)}{(R)(T)}[/tex]where:
d = density
MMNH3 = molar mass of NH3 = 17 g/mol
P = pressure = 800 Torr = 1.05263 atm (just divide by 760)
T = 25 °C = 273.15 + 25 = 298.15 K
R = 0.082 atm
So:
d = 17 * 1.05263/0.082 * 298.15
d = 17.8947/24.4483
d = 0.7319 g/L
Answer: density = 0.7319 g/L
What type(a) of interparticle forces exist between molecules in a pure sample of CH2F2? A) induced dipole attractionsB) dipole-dipole forcesC) H-bonding
This molecule will have dipole-dipole forces.
Answer: B
Order the following elements from smallest to largest
Answer: F, O, N, C, B
Explanation: The element with the greatest electronegativity will have the smallest radius because it holds the electrons closest to the nucleus. Fluorine is the most electronegative element (it is in the upper right of the periodic table), Francium is the lease (it is the lower left of the periodic table). With this knowledge, you should be able to recognize a trend in the periodic table associated with atomic radius size and electronegativity.
A cube with 34.16 inch sides of an unknown material weighs 6.85 kg. What is this material'sdensity in g/mL? (Hint: 1 in = 2.54 cm)
From the calculations above, the density of the material is 0.01g/mL
To solve this problem, we have to calculate the volume of the cube, but first of all, we should convert the unit from in to cm.
Conversion from Inches to CentimeterLet us convert the unit of the side length from inches to centimeter.
[tex]\begin{gathered} 1in=2.54\operatorname{cm} \\ 34.16in=\text{xcm} \\ x=34.16\times2.54 \\ x=86.7664\operatorname{cm} \end{gathered}[/tex]Volume of a CubeThe volume of a cube is given as
[tex]\begin{gathered} v=l^3 \\ l=\text{side length} \end{gathered}[/tex]let's substitute the values and solve for the volume.
[tex]\begin{gathered} v=l^3 \\ v=(84.7664)^3 \\ v=653212.87\operatorname{cm}^3 \end{gathered}[/tex]Note;
[tex]\begin{gathered} 1\operatorname{cm}^3=1mL \\ 653212.87\operatorname{cm}^3=653212.87mL \end{gathered}[/tex]Now that we have the volume of the material, let us calculate it's density
Density of a materialThe density of a material can be calculated as
[tex]\rho=\frac{\text{mass}}{\text{volume}}[/tex]But the given mass is in kg and we are asked to find the density in g/mL
Conversion of mass from kg to g[tex]\begin{gathered} 1\operatorname{kg}=1000g \\ 6.85\operatorname{kg}=6850g \end{gathered}[/tex]We can substitute this information and calculate for the density.
[tex]\begin{gathered} \rho=\frac{\text{mass}}{\text{volume}} \\ \rho=\frac{6850}{653212.87} \\ \rho=0.010\text{ g/mL} \end{gathered}[/tex]From the calculations above, the density of the material is 0.01g/mL
Nitrogen dioxide reacts with water to produce nitric acid and nitrogen monoxide. How many grams of nitric acid can be prepared from 95.52 grams of nitrogen dioxide?
87.22grams
Explanations:The chemical reaction between Nitrogen dioxide and water to produce nitric acid and nitrogen monoxide is expressed as:
[tex]3NO_2+H_2O\rightarrow2HNO_3+NO[/tex]Determine the moles of nitrogen dioxide(NO2)
[tex]\begin{gathered} mole=\frac{mass}{molar\text{ mass}} \\ mole=\frac{95.52}{46.0055} \\ mole\text{ of NO}_2=2.076moles \end{gathered}[/tex]According to stoichiometric ratio, 3 moles of nitrogen dioxide produces 2moles of nitric acid, the moles of nitric acid required is expressed as;
[tex]\begin{gathered} moles\text{ of }HNO_3=\frac{2}{3}\times2.076 \\ moles\text{ of }HNO_3=1.384moles \end{gathered}[/tex]Determine the mass of nitric acid
[tex]\begin{gathered} mass\text{ of HNO}_3=mole\times molar\text{ mass} \\ mass\text{ of HNO}_3=1.384\times63.01 \\ mass\text{ of HNO}_3=87.22grams \\ \end{gathered}[/tex]Hence the mass of nitric acid required is 87.22grams
Which of the following can be calculated from the mass of the reactants used in a chemical reaction?Amount of limiting reactant used in a reactionActual yield of productsAmount of excess reactant from a reactionTheoretical yield of products
Explanation:
There are some options that are correct.
1) Amount of limiting reactant used in a reaction.
It can be calculated from the quantity of the reactants.
------
2) Amount of excess reactant from a reaction
It can be also calculated from the quantity of the reactants.
------
3) Theoretical yield of products
Answer:
Amount of limiting reactant used in a reaction
Amount of excess reactant from a reaction
Theoretical yield of products
The options for this question are vaporizing, condensing, freezing, and melting but I’m not sure where to put them. If anyone could help it would be greatly appreciated
Physical states are different in compounds if we have a change of temperature or pressure, and in certain temperatures we can see a compound undergo a physical change, going from solid to liquid or gas, and the reverse is also possible, as we will see now:
If liquid is turning into solid, then we have a freezing situation
Liquid to solid will be known as melting
Gas to liquid will be known as condensing
Liquid to gas will be known as vaporizing
Laboratory balances that measure to the hundredths (0.01g) are calleda) centigram balanceb) milligram balancec) analytical balance
Answer:
[tex]A[/tex]Explanation:
Here, we want to select the balance used to measure mass to a hundredth accuracy
The kind of balance used in this case is the centigram balance. The measure the mass of a substance to an accuracy of a hundredth which is 0.01g
What is the molarity of a 0.75 L solution that contains 9.2 g of NaCl?
The molarity of the solution is 0.209 M.
Molarity is an expression of the concentration of a compound and it is represented in mole/liter.
So, we need to know how many moles tha sample has.
- First, with the molar mass of the NaCl molecule we calculate the number of moles conteined in 9.2g of NaCl:
NaCl molar mass= 58.44g/mol
[tex]\frac{9.2g\text{ . 1mol}}{58.44g}=\text{ 0.157 moles}[/tex]- Second, molarity is expressed in 1 liter, so we calculate the number of moles that are conteined in 1 liter:
[tex]\frac{1L\text{ . 0.157moles}}{0.75L}=0.209\text{ moles}[/tex]- So, the molarity of the solution is 0.209 M.
A student drew a model of two liquids. One hot and one cold. How would the student draw this? Choose all that applies?
A. Models should show two separate containers of liquid.
B. Models should show one container of liquid.
C. There should be something to represent the molecules in the liquid.
D. There should be something to represent air in the liquid.
E. The student should put longer arrows on the cold liquid and short arrows on the warm liquid. The arrows show the speed of the molecular movement.
F. The student should put shorter arrows on the cold liquid and longer arrows on the warm liquid. The arrows show the speed of the molecular movement.
G. There should be a key to tell what the arrows represent and how the molecules are represented.
Please answer ASAP! Will reward.
Models should show two separate containers of liquid and There should be a key to tell what the arrows represent and how the molecules are represented.
It is the lowest point in the substance and has chemical elements. Atoms don't exist on their own; instead, they combine to create ions and molecules, which combine to create the substances that we can see, feel, and touch.
One or more atoms joined together by covalent (chemical) bonds make up molecules. Atoms may be seen as circles with a central nucleus (consisting of protons and neutrons) and one or more concentric circles around it that represent the "shells" or "levels" in which the electrons surrounding the atom's nucleus are placed as well as marks that distinguish the electron. every level
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what is functional group?write the functional group ofalcoholesteracid hydridealdehyde and mention an example of each compound containing these functional group
EXPLANATION:
A functional group is a collection of atoms within molecules that bind together to react in predictable ways.
The functional group tell us how a compound react and, also, the chemical properties of such compound
Below are the functional group of some compound
Alcohol
The functional group of alcohol is ---- OH
Example: Ethanol
Ester
The functional group of Ester is --O--
Example: Ethyl ethanoate
Aldehyde
The functional group of aldehyde is
Example: Vanillin
I need to see how to do 2 and 3
Answer:
Explanation:
a) Here, we want to get the limiting reactant
The limiting reactant forms less of the product
From the equation of reaction:
4 moles of aluminum gave 2 moles of product
0.32 mol will give x moles of product:
4 * x = 0.32 * 2
x = 0.16 moles
3 moles of oxygen gave 2 moles of product
0.26 mol will give x moles of product
3 * x = 0.26 * 2
x = 0.173 moles
That means that aluminum is the limiting reagent
b) From the question:
6.38 * 10^-3 mol oxygen gives x mol of product
3 moles of oxygen gives 2 moles of product
To get x:
[tex]x\text{ = }\frac{6.38\times10^{-3}\times2}{3}\text{ = }0.00213\text{ mole}[/tex]For aluminium, we do same process:
[tex]x\text{ = }\frac{9.15\times10^{-3}\times2}{4}\text{ = 0.004575 mole}[/tex]c) From the mass available, we need to get the number of moles that could be produced from each
To get the number of moles, we have to divide the mass by the atomic mass of the element
For Aluminium, the atomic mass is 27 amu
That means the number of moles is:
[tex]\frac{3.17}{27}\text{ = 0.1174 mole}[/tex]Now, from the equation of reaction:
4 moles aluminum gave 2 moles oxygen
0.1174 mole aluminum will give:
[tex]\frac{0.1174\times2}{4}\text{ = 0.0587 mole}[/tex]For oxygen, the atomic mass is 16 amu
For molecular oxygen, we have the molar mass as 32g/mol
The number of moles that will react is thus:
[tex]\frac{2.55}{32}\text{ = 0.0796875 mole}[/tex]From the equation of reaction:
3 moles of oxygen gave 2 moles of product,
0.159375 mole will give:
[tex]\frac{0.0796875\times2}{3}\text{ = 0.053125 mole}[/tex]Since the number of moles from oxygen is lesser, it translates to a lesser amount of product and that makes oxygen the limiting reactant in this case
How would you prepare 250 mL of 0.125 M HCl from concentrated HCl (aq) that is 38.0% by mass with a density of 1.19 g/mLnote: find moles in 250 mL of 0.125 HCl
Answer
250 mL of 0.125 M HCl can be prepared from concentrated HCl (aq) that is 38.0% by mass with a density of 1.19 g/mL by adding 2.49 mL of HCL(38%) into a small quantity of water, mix to disperse; then dilute with solvent water up to but not to exceed the total needed volume of solution (in this case 250 mL).
Explanation
The problem can be solve in four steps:
Step 1: Calculate the number of moles in 38.0% by mass of HCl.
[tex]\begin{gathered} \text{HCl (38.0}\%)\text{ }=(\frac{38g\text{ HCl}}{100\text{ g solution}})=(\frac{x\text{ moles HCl}}{1.0\text{ Liter Solution}}) \\ \\ \Rightarrow Moles\text{ of HCl in 38 grams }=\frac{38g\text{ HCl}}{36\text{ g/mol}}=1.06\text{ mole HCl} \end{gathered}[/tex]Step 2: The volume of the 38.0% by mass HCl solution.
Volume of solution in Liters containing 1.06 mole of HCl =
[tex]\frac{Mass}{D\text{ensity}}=\frac{100g}{1.19gmL^{-1}^{}}=84.03\text{ mL HCl(38.0}\%)\text{ }=0.084\text{ L HCl(38.0}\%)[/tex]Step 3: Calculate the molarity of HCl (38.0%)
[tex]\text{Molarity of HCl (38.0}\%)=\frac{Number\text{ of mole}}{Volume\text{ in liters}}=\frac{1.06\text{ mole HCl}}{0.084\text{ L HCl}}=12.62\text{ M}[/tex]Step 4: To calculate the volume of HCl (38.0%) required to prepare 250 mL of 0.125 M HCl.
Note: Formula weight of HCl = 36 g/mol
[tex]\begin{gathered} \text{Volume of HCl(38.0}\%)\text{ required }=\frac{(Molarity)(Volume)(Formula\text{ Weight)}}{(\text{Purity)(Specific Gravity)}} \\ \\ \text{Volume of HCl(38.0}\%)\text{ required }=\frac{(0.125\text{ M)})(250\text{ }mL)(36\text{ g/mol)}}{(0.38\text{)}(1.19\text{ g/mL)}} \\ \\ \text{Volume of HCl(38.0}\%)\text{ required }=\frac{(0.125\text{ M)})(0.250\text{ }L)(36\text{ g/mol)}}{(0.38\text{)}1.19\text{ g/mL)}} \\ \\ \text{Volume of HCl(38.0}\%)\text{ required }=\frac{1.125}{0.4522}=2.49\text{ mL} \end{gathered}[/tex]Therefore, 250 mL of 0.125 M HCl can be prepared from concentrated HCl (aq) that is 38.0% by mass with a density of 1.19 g/mL by adding 2.49 mL of HCL(38%) into a small quantity of water, mix to disperse; then dilute with solvent water up to but not to exceed the total needed volume of solution (in this case 250 mL).
Answer question number 13. The question is in the image.
Answer: One carbon atom can make a maximum of 4 covalent bonds. The best option to answer the question is number 4.
Explanation:
The question requires us to choose, among the options given, which one corresponds to the maximum number of carbon bonds that can be formed by one carbon atom.
To answer this question, we can consider the electronic configuration of a carbon atom. Carbon (C) presents atomic number 6, therefore it contains 6 electrons and its electronic configuration can be written as:
[tex]1s^22s^22p^2[/tex]Note that there are 4 electrons in carbon's valence shell (2s2 and 2p2), thus a carbon atom needs additional 4 electrons to achieve stability.
If the atom needs 4 electrons to achieve stability, it means it can make 4 covalent bonds to "acquire" these electrons.
Therefore, the best option to answer the question is number 4.
An equilibrium mixture, at 529°C in a 1208-mL container, involving the chemical system
N2(g) + 3H2(g) == 2NH3(g)
is found to contain 3.62 g of N2, 0.773 g of H2, and 0.498 g of NH3. Calculate the equilibrium constant (Keq expressed in terms of the molar concentrations) at the given temperature.
The equilibrium constant at the given temperature is equal to 0.1677.
What is the equilibrium of a chemical reaction?The chemical equilibrium can be described as the state of a chemical reaction where the concentration of the reactants and products does not change with respect to time.
The balanced chemical equation of the formation of ammonia:
[tex]N_2+3H_2\leftrightarrows 2NH_3[/tex]
The mass of the nitrogen gas = 3.62 grams
The moles of nitrogen gas = 3.62/28 = 0.1293 mol
The concentration of the nitrogen gas = (0.1293/1208)× 1000 = 0.107 M
The mass of the hydrogen gas = 0.773 grams
The moles of hydrogen gas = 3.62/2 = 0.386 mol
The concentration of the hydrogen gas = (0.386/1208)× 1000 = 0.32 M
The mass of the ammonia = 0.498 grams
The moles of ammonia = 0.498/17 = 0.029 mol
The concentration of the ammonia = (0.029/1208)× 1000 = 0.024 M
The equilibrium constant: [tex]K_{eq} = \frac{[NH_3]^2}{[H_2]^3[N_2]}[/tex]
[tex]K_{eq} = \frac{[0.024]^2}{[0.107][0.32]^3}[/tex]
[tex]K_{eq} =0.1677[/tex]
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Which element is most likely to behave as a metalloid?NaArZnAs
A metalloid is an elements that has some characteristics of metal and other of non-metals. In a periodic table, it is somewhere in between the metals and non-metals.
Looking to a periodic table, we have Na to the far left, so it must has metal characteristics.
Ar is to the far right, it is a noble gas, so not metalloid.
Zn is quite close to the right side, however it is in the groups of transition metals, so it is still a metal and must have metal characteristics.
As is even more to the right, exactly where the metal characteristics of elements start to change to non-metals, so As is probably the one with metalloid characteristics.
Calculate the [H+] given a pH of 2.80
Answer:
The [H+] is 1.6x10^-3 M.
Explanation:
1st) We can calculate the concentration of H+, using the pH formula:
[tex]\begin{gathered} pH=-log\lbrack H^+\rbrack \\ 2.80=-log\lbrack H^+\rbrack \\ 10^{(-2.80)}=\lbrack H^+\rbrack \\ 1.6*10^{-3}M=\lbrack H^+\rbrack \end{gathered}[/tex]So, the [H+] is 1.6x10^-3 M.
What is the %v/v when 17.8mL is Acetic Acid is dissolved in 40.8mL of water?
Answer:
30.4 %.
Explanation:
Let's see the volume percentage (% v/v) formula:
[tex]Percent\text{ volume=}\frac{volume\text{ of solute}}{volume\text{ of solution}}\cdot100\text{ \%,}[/tex]in this case, the solute is acetic acid and the solution is the solute and solvent (which is water). Based on this logic, the volume of solute is 17.8 mL, whereas the volume of solution is the sum of the volumes of solute and solvent ( 17.8 mL + 40.8 mL = 58.6 mL), so we just have to replace the values that we have in the formula:
[tex]\begin{gathered} Percent\text{ volume=}\frac{17.8\text{ mL}}{58.6\text{ mL}}\cdot100\%, \\ \\ Percent\text{ volume=30.4\%.} \end{gathered}[/tex]The answer would be 30.4 %.
what type of bonding results from the force of attraction between positively and negatively charged ions?
ANSWER
Ionic bonding
EXPLANATION
Ionic bonding is also known as electrovalent bond, this is a type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound
The charge are always negative and positive charge.
Therefore, the type of bonding is called ionic bonding
According the phase diagram for H₂0, what happens to the phaseswater at 0.5 atm pressure as the temperature is decreased from 110°C to -10°C?Pressure (atm)1-0.5-0.25--10Ice(solid)0.01Water(liquid)Water vapor(gas)100Temperature (°C)
Answer:
A. Water changes from a gas to a liquid to a solid.
Explanation:
We can see the following points in the diagram:
- Point A: water starts at 0.5 atm and 100°C, so it is vapor (gas).
- Point B: water changes from vapor to liquid.
- Point C: water changes from liquid to solid.
- Point D: water as a solid reaches a temperature of -10°C.
So, water changes from a gas to a liquid to a solid.
Which of the following statements is FALSE:O Density is a measure of how closely packed the atoms of a substance are.O The Density of a substance can change if its location changes.O The Density of steel is greater than the Density of cotton.O To calculate the Density of an object we must know its mass
Answer
The Density of a substance can change if its location changes.
Explanation
All the statements are TRUE except
The Density of a substance can change if its location changes.
This is because density is an intensive property, that is regardless of the object's shape, size, or quantity, the density of that substance will always be the same. Even if you cut the object into a million pieces, they would still each have the same density.
Therefore, the statement that is FALSE is
The Density of a substance can change if its location changes.