the momentum of a car with a mass of 2,000 kg moving at a constant velocity is 40,000 kg. m/s
The kinetic energy is 400kJ
The kinetic energy is
K.E=(1/2)mv2
The mass is m = 2000kg
The velocity is v = 20ms−1
So, K.E = (1/2)x2000x202 = 400000J = 400kJ
In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force. Applying a force requires us to do work. After work has been done, energy has been transferred to the object, and the object will be moving with a new constant speed.
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What is the only force acting on a freely falling object?
The force acting on freely falling object is force of gravity and air friction.
Assuming you mean the ground, in a more realistic model there are two forces acting on the object.At rest without acceleration, two forces also act on the body. It has a force produced by its mass being pulled toward the center of the earth, namely its weight, and a force acting in the opposite direction to its weight called the reaction force. This prevents objects on the ground from falling off the surface and acts perpendicular to the plane.There are two possibilities when items drop. Both his weight still exists. In the simpler model this doesn't seem to change, but if you want to be more precise the weight decreases with the square of the distance. The magnitude of the other force depends on the object's velocity. This is air resistance. Initially, the object's acceleration is greater than 0 because drag is less than its weight. As an object accelerates toward the center of the earth, its velocity increases and the force exerted by air resistance on the object's weight increases. Eventually the drag will equal the weight of the object and the acceleration will be zero. This is terminal speed. Maintain this speed until you reach the surface. This condition is very similar to the behavior of an object resting on the ground. An object's resistance and weight are equal and cancel each other out, so there is no net force.To learn about terminal speed-
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how do you determine the number of degrees of freedom of a lumped-mass system?how do you determine the number of degrees of freedom of a lumped-mass system?
The number of degrees of freedom (DOF) of a lumped-mass system is determined by counting the number of independent coordinates that must be specified to describe the motion of the system.
The number of DOF is equal to the number of independent coordinates needed to describe the system. For example, a single point mass has two DOF because two coordinates (x and y) are needed to describe its motion. A point mass connected to a spring has three DOF because three coordinates (x, y, and z) are needed to describe its motion.
The number of degrees of freedom of a lumped-mass system can be determined by counting the number of independent coordinates that represent the system.
Step 1: Identify the number of bodies:
The first step in determining the number of degrees of freedom of a lumped-mass system is to identify the number of bodies in the system. For example, a system with two bodies would have two degrees of freedom.
Step 2: Identify the number of coordinates:
The second step is to identify the number of coordinates that are necessary to describe the motion of each body in the system. Typically, a body requires six coordinates to describe its motion: three coordinates to describe its position and three coordinates to describe its orientation.
Step 3: Calculate the number of degrees of freedom:
The number of degrees of freedom of the system is then calculated by multiplying the number of bodies by the number of coordinates required to describe the motion of each body. For example, a system with two bodies would have twelve degrees of freedom.
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Niagara falls is 51 meters high. If you dropped a ball off the ledge, how much time would it take it to hit the water?.
The time taken by the ball to hit the water is 3.22sec if it is dropped from a height of 51 meter .
We have height from which ball is dropped, now we need to find the time. So, we can use newton second equation of motion which states that displacement is equal to summation of the product of initial velocity with time taken plus the half product of acceleration with square of time taken.
S=ut+(1/2)at²
where S is the displacement of the body,
u is defined as the initial velocity of the body,
a is the acceleration due to gravity,
and t is the total time
We have S=51m,u=0m/sec, a=9.8m/sec²,t=?
So, putting the values, we get
=>51=(0×t) + (1/2)×(9.8)×(t)²
=>51=0 + 4.9×(t)²
=>(t)²=51/4.9
=>(t)²=10.40
=>t=√10.40
=>t=3.22sec
Hence, required time taken by ball is 3.22sec.
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A motorcycle is travelling at a constant velocity of 30ms. the motor is in high gear and emits a hum of 700hz. the speed of sound in air is 340ms , and there is no wind.a. What is the period of the sound waves emitted from the motorcycle?b. What is the distance travelled by the motorcycle during one period of the sound oscillation?c. What is the distance travelled by a sound wave in air during one period of oscillation?
Based on the accurate information provided in the context of Constant Velocity and sound speed, we can calculate certain answers.
a. The frequency of the sound wave emitted by the motorcycle is 700 Hz, so the period is
$T=\frac{1}{700}=0.0014 s.b. The motorcycle is travelling at a constant velocity of 30 m/s and the period of the sound wave is 0.0014 s, so the distance travelled by the motorcycle during one period of the sound oscillation is
$d=v\cdot t=30\text{ m/s}\cdot 0.0014\text{ s}=0.042 m.c. The speed of sound in air is 340 m/s and the period of the sound wave is 0.0014 s, so the distance travelled by the sound wave in the air during one period of oscillation is
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a meter stick balances horizontally on a knife-edge at the 50.0 cm mark. with two 3.78 g coins stacked over the 33.4 cm mark, the stick is found to balance at the 48.8 cm mark. what is the mass of the meter stick?
The meter stick weighs 204.11cm. A meter stick is a measurement tool that measures one meter (hundred centimeters) and is used to measure things in meters and centimeters.
What is the mass trying to say?In physics, mass is a way to measure inertia, a fundamental property of all matter. It essentially refers to a body of matter's resistance to changing its speed or position in response to the application of a force. The change produced by an applied force is smaller the more mass a body has.
Calculation:The computation of the mass of the meter stick is shown below:Let us assume the following items
x1 = 50 cm;
m2 = m3 = 3.78 g;
x2 = x3 = 33.4 cm;
xcm = 48.8 cm
Now, using the aforementioned presumption, we must use the center mass equation, which is provided below:Xcm = m₁x₁ + m₂x₂ + m₃x₃ / m₁ + m₂ + m₃
48.8cm = m₁ ₓ50 + 3.78 ₓ 33.4 + 3.78 ₓ 33.4 / m₁ + 3.78 + 3.78
48.8m₁ + 7.56 = 50m₁ + 126.25 + 126.25
48.8m₁ - 50m₁ = 244.94
₋1.2m₁ = 244.94
m₁ = ₋244.94/₍1.2
m₁ = 204.11cm.
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how much pressure (absolute) in kpa must a submarine withstand at a depth of 120.0 m in the ocean (1029 kg/m3)?
At a distance of 120.0 meters beneath the water surface, a submarine must resist pressure of 1200kPa.
h=120m
1 g/cm3 equals 1000 kg/m3 for p water.
P atmosphere equals 101.3 kPa
Total P =?
water = density *g*h
=1000*10*120
=1200000Pa
=1200kPa
P total = 1200 kPa plus 101.3 kPa equals 1301.3 kPa
The pressure on the hull increases by one atmospheric (1 bar, 14.7 psi, 101 kPa) for every 10 meters (33 feet) in depth, therefore at 300 meters (1,000 feet), the hull is able to resist 30 environments (30 bar, 441 psi, 3,000 kPa) with water pressure.
Therefore, gauge pressure plus atmospheric pressure add to the overall pressure, also known as absolute pressure:
Pabs=Pg+Patm Pabs is indeed the unconditional pressure, Pg is the gauge pressure, and Patm is the air pressure. P abs = P g + P atm
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what is the density (in kg/m3) of a woman who floats in fresh water with 4.00 % of her volume above the surface?
The density of the woman is approximately 993 kg/m3.
Step 1: Calculate the volume of the woman above the surface. Assuming the woman has a height of 1.7 meters, and the average body density of a woman is 890 kg/m3, the volume above the surface is 0.04 x 1.7 m3 = 0.068 m3.
Step 2: Calculate the total mass of the woman. Multiply the volume (0.068 m3) by the density (890 kg/m3) for a total mass of 60.12 kg.
Step 3: Calculate the woman's density in the water. Divide the total mass (60.12 kg) by the volume (1.7 m3) to get a density of 35.33 kg/m3.
Therefore, the density of a woman who floats in fresh water with 4.00% of her volume above the surface is 35.33 kg/m3.
The density of an object is the mass of the object divided by its volume. The density of a substance is a measure of how much matter is packed into a given volume of that substance. The higher the density, the more matter is packed into the same amount of space. For example, a rock has a higher density than a pillow because the rock is made up of more matter than the pillow.
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What is the change in the internal energy of the system if 2000 J of heat leaves the system and 2500 J of work is done on the system?
The change in the internal energy of the system will be 500J.
Internal energy is a state function. It depends only on the state of the system and not on the method used to achieve that state.
Let's change the internal energy of the system by doing adiabatic process. There are two ways to do this.
(1) By the mechanical work of turning a series of small paddles.
(2) By electrical work using a dipstick.
It is determined that the temperature rises from T1 to T2 by the same amount. Thus, the same work done, regardless of how it is done, produces the same change in state, measured as a change in temperature.
Q=u+w
u=Q-w
u=2000-2500=500 J
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Answer:500J
Explanation:
Q3. A space probe is traveling in outer space with a momentum that has a magnitude
of . A retrorocket is fired to slow down the probe. It applies a force to
the probe that has a magnitude of and a direction opposite to the probe’s
motion. It fires for a period of 12 s. Determine the momentum of the probe after the
retrorocket ceases to fire
The momentum of the probe after the retrorocket ceases to fire is 9.9 * 10^7 Kg m/s
What is the momentum?We know that the momentum of an object has to do with the product of the mass and the velocity of an object. The momentum of an object is a vector quantity and the direction of the momentum is the direction of the velocity of the object that is in motion.
According to the Newton second law of motion, we know that the rate of change of the momentum is equal to the impressed force that is acting on the body.
We know that;
[tex]F_{t}[/tex] = [tex]p_{f}[/tex] -[tex]p_{i}[/tex]
F = force
t = time taken
[tex]p_{f}[/tex]= final velocity
[tex]p_{i}[/tex] = initial velocity
[tex]p_{f}[/tex] = [tex]F_{t}[/tex] + -[tex]p_{i}[/tex]
[tex]p_{f}[/tex] = (2.0 * 10^6 * 12 s) + 7.5 * 10^7
[tex]p_{f}[/tex] = 2.4 * 10^7 + 7.5 * 10^7
[tex]p_{f}[/tex] = 9.9 * 10^7 Kg m/s
Hence, the momentum of the retrorocket is 9.9 * 10^7 Kg m/s.
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Missing parts;
A space probe is traveling in outer space with a momentum that has a magnitude of 7.5 * 10^7 kgm/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 2.0 * 10^6 N and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases fire.
a solenoid that is 95.0 cm long has a radius of 2.00 cm and a winding of 1200 turns; it carries a current of 3.60 a. calculate the magnitude of the magnetic field inside the solenoid.
The magnitude of the magnetic field inside the solenoid is 0.00571Tesla.
The radius of the solenoid = 95.00cm
The number of turns = 1200
the current flow = 3.60
The formula of the magnetic field inside the solenoid is
B = μ0.i.n=μ0i(N/L)
B = 4π × 10^(-7).(3.6).(1200/95)
B = 0.00571 Tesla
Hence, The magnitude of the magnetic field inside the solenoid is 0.00571Tesla.
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Julia puts two magnetic toy trains very close to each other on a track. What will happen next, and why?
A. The trains will move closer to each other, because the magnetic force will pull the trains together
B. The trains move away from each other, because the magnetic force will push the trains apart.
C. The trains will move away from each other, because the magnets
are not touching.
D. The transfer not move because the magnets are not touching.
Answer:
i think the option C is correct
a solenoid that is 85.0 cm long has a cross-sectional area of 17.0 cm2. there are 950 turns of wire carrying a current of 6.60 a. (a) calculate the energy density of the magnetic field inside the solenoid. (b) find the total energy stored in the magnetic field there (neglect end effects).
The magnetic field inside the solenoid has an energy density of 34.2 J/m3. A solenoid with a cross-sectional area of 17.0 cm2 and a length of 85.0 cm. A current of 6.60 is carried by 950 rounds of wire.
An electric charge, an electric current, and magnetic materials are all affected magnetically by a magnetic field, which is a vector field. A force perpendicular to the magnetic field and its own velocity acts on a moving charge in a magnetic field. A solenoid is a particular kind of electromagnet that produces a regulated magnetic field and is made of a helical coil of wire whose length is significantly higher than its diameter. When an electric current is sent through the coil, a consistent magnetic field can be created in a specific area of space.
u = B2Mo, u = (0.0092696)2/2*4*3.1416e-7, and u = 34.2J/m3.
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A 40.0-kilogram child exerts a 100.-newton force on a 50.0-kilogram object. the magnitude of the force that the object exerts on the child is: ________a. 0.0 Nb. 80.0 Nc. 100. Nd. 125 N
The magnitude of the force that the object exerts on the child is 100 N.
What is Newton's 3nd law of motion ?There is an equal and opposite reaction to every action, according to Newton's Third Law of Motion. Reaction and action always affect distinct items, it must be kept in mind.Understanding which forces are external to a system is possible with the aid of Newton's third law. Recall that while creating a problem, identifying external forces is crucial since they must be combined together to determine the net force. Looking at how people move around can help us understand how Newton's third law operates.F[tex]_a[/tex] = F[tex]_r[/tex]
where,
Fa is the applied force
F[tex]_r[/tex] is the reaction experienced by the object
The reaction of the item, or the upward force imposed on the child by the object, is 100 N in the opposite direction if the child applies 100 N of force to the object.
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if the density of your unknown liquid is 0.65 g/ml, calculate the volume in liters that 3 ml of your unknown liquid would occupy when vaporized at the barometric pressure and temperature of your boiling water bath in run 1. use the accepted molar mass of your suspected unknown.
As a result, temperature is equal to 373 divided by 273 and has a density of 0.65 gram per mel (1.37). As a result, 3 ml of liquid will evaporate into 0.65 ml, or 3 into 3.
What is a concrete instance of evaporation?When a liquid transforms into a gas, evaporation takes place. When rain puddles "disappear" on a sunny day or when wet clothing dries in the sun, it is simple to envision. The liquid water in these instances is evaporating it in to a gas known as water vapor rather than actually dissipating. On a global level, evaporation occurs.
What happens when evaporation happens?Condensation is the transition of matter from its gaseous state into its liquid state. It is the opposite of evaporation, which is the vaporization of the a liquid from its surface into a gaseous state.
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you wish to reflect sunlight from a mirror onto some paper under a pile of wood in order to start a fire. which would be the best choice for the type of mirror?
A concave mirror concentrates light from a wide area of the mirror onto a tiny region of the paper, resulting in an extremely high power input to the paper.
A mirror with an inward curvature in the middle is referred to as concave. You might find it useful to keep this in mind if you believe that staring into a concave mirror makes you feel as though you are peering into a cave. The mirror equation is the formula that we apply to concave mirrors. This formula is used to calculate how close an object is to the mirror (image distance) and how big or small it is (object size.)
For concave mirrors, the law of reflection still holds true, but because of the curved surface, the incidence angle—also referred to as the angle at which the light strikes the surface—varies depending on where part of the mirror the light hits.
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a grocery sack can withstand a maximum of 235 n before it rips. will a bag holding 18.5 kg of groceries that is lifted from the checkout counter at an acceleration of 5.0 m/s2 hold?
A grocery sack can withstand a maximum of 235 n before it rips. will a bag holding 18.5 kg of groceries that is lifted from the checkout counter at an acceleration of 5.0 m/s2 hold is 51.98N
Threshold force is 235N
Force or weight = mg
Where m = mass of object and g is the acceleration due to gravity
Mass of object it holds = 18.5kg
g = 9.81m/s^2
a = 7m/s^2
Because a is acceleration against gravity
Minimum force applied to lift the bag = (18.5 × (-7)) kgms^2
= -129.5N
Force of gravity, i.e its weight
= (18.5 × 9.81)N
= 181.48N
Net force acting on the bag from above =
(181.48 + (-129.5)) N
= 51.98N
Hence, An acceleration of 5.0 m/s2 hold is 51.98N
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water is moving at a speed of 1.95 m/s through a hose with an internal diameter of 1.6 cm. show answer no attempt 50% part (a) what is the flow rate in units of liters per second?
The flow rate of water moving at a speed of 1.95 m/s through a hose with an internal diameter of 1.6 cm is 0.39 L / s
Q = A v
Q = Flow rate
A = Area
v = Velocity
Since the outlet of water is through a hose,
A = π r²
A = π d² / 4
d = 1.6 cm = 0.016 m
A = ( 3.14 * 0.016² ) / 4
A = 0.0002 m²
The velocity of water is 1.95 m / s
Q = 1.95 * 0.0002
Q = 0.00039 m³ / s
Q = 0.00039 * 1000 L / s
Q = 0.39 L / s
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a hoop of mass 1.2 kg and radius 65 cm has a string wrapped around its circumference and lies flat on a horizontal frictionless table. the string is pulled with a constant force 7 n. how far does the center of the hoop travel in 4 s?
The middle of the hoop travels 46.4m in that time. A hoop with a radius of 65 cm and a mass of 1.2 kg is flatly resting on a frictionless table with a string wrapped around its circumference.
The body moves on the frictionless surface with constant velocity as represented by the term "frictionless surface acceleration." There is no net force that can stop an object from moving when the surface is frictionless. As a result, the body maintains its current speed. We translate "frictionless" as "moving without stopping" for this reason. A physical body's mass is its total amount of matter.
F = ma
F=1.2*a 7=1.2*a a =7/1.2 a = 5.8 m/s
2 s = ut+1/2at^
2\ss = 1/2(5.8)(16) (16)
s = 46.4m
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b. cavity detection: a metal ornament (gold) has a mass of 155-g in air and 142-g in water. does it have a cavity inside? if so what is the volume of the cavity? [density of gold
The volume of the cavity is 5cm³
Calculation :
Volume = [tex]\frac{Mass}{Density}[/tex]
= [tex]\frac{155}{19.3}[/tex]
= 8.03 cm³
Volume of Cavity = 13cm³ - 8.03cm³
Cavity quantum optics, for example, deals with the interaction of photons and molecules in an optical cavity confined between two closely spaced mirrors. A perfect optical cavity can only support light of a certain frequency and amplify the strength of the associated electromagnetic field
In a co-fired ceramic semiconductor package, the area intended for die attachment. The nominal area is defined by the bond finger limits.
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To find the volume of the cavity, the major parameter missing is the diameter of the cavity itself. we can obtain this using the following steps:
Weight of the cavity = Weight of sculpture in air - Weight of sculpture in water
Weight of cavity = 11.29N - 9.190N = 2.1N
Weight = mass x acceleration due to gravity
Mass 1 = 1.55kg
Mass 2 = 1.42 kg
So;
Volume of substance can be determined from the density.
Density = mass/volume
Volume = mass/density
Now insert the parameters and solve;
Volume = = 1.1 x 10⁻⁵m³
Therefore, the volume of the cavity inside is 1.1 x 10⁻⁵m³.
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Write a hypothesis about how the mass of the cylinder affects the temperature of the water. Use the “if”… then .. because… “format and be sure to answer the lesso: “How is potential energy converted to thermal energy in a system?”
If the mass of the cylinder decreases, the temperature of the water decreases, because lesser the mass means the cylinder has less potential energy that can be converted to thermal energy, decreasing the temperature of the water.
What is potential energy?Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases. If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy.
The temperature of the water falls as the cylinder's mass drops because a smaller cylinder has less potential energy that can be converted to thermal energy, which lowers the temperature of the water.
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The rationale underlying the use of projective personality tests, such as the Rorschach Test and the thematic apperception test, is that they
The idea behind projective personality tests, like the Rorschach Test and the thematic apperception test, is that they can reveal a subject's nature by evoking a response to ambiguous, hazy stimuli.
What justification exists for using projective tests?Projective tests are designed to reveal emotions, wants, and conflicts that are not readily apparent to conscious awareness. Psychoanalysts attempt to identify repressed emotions that may be the root of a person's issues in life by evaluating responses to ambiguous stimuli.
What serves as the projective test's primary purpose in psychology?A projective test, which is a type of personality test used in psychology, asks subjects to respond to ambiguous stimuli, with the hope of eliciting responses that disclose any hidden emotions or internal conflicts that the test subject may have projected onto the situation.
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which consumes more energy, a 1 kw hair dryer used for 10 min or a 10 w night light left on for 18 hr?
10 w night light left on for 18 hr is consumes more energy.
How do you calculate energy consumption per hour?You must multiply an appliance's wattage by the number of hours it is utilized to determine how much power it consumes (operational hours). For instance, running a 1000 watt electric iron for an hour will use up 1 kilowatt hour (kWh) of power (1000 watt x 1 hour).Power is the rate at which energy is produced or used. "Power and energy are not the same thing," repeat after me ten times. Energy as a unit of time is called power. The watt, which is characterized as a current of one amp driven by a voltage of one volt, is the common unit of electrical power.a 1 kw hair dryer used for 10 min.
energy consumes = 1kw * 10* 60 = 600kJ.
a 10 w night light left on for 18 hr
18Hr = 18 * 60 * 60 = 64800 sec
Energy consumes = 10 * 64800 =648000 J. = 648 kJ.
Since, 10 w night light left on for 18 hr consumes more energy.
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calculate the rotational energy of a segment given mass of the segment 4.59 kg, moment of inertia 0.057 kg*m^2, and angular velocity 1.90 rad/s.
Rotational energy of a segment is 0.102 JT.
What is rotational kinetic energy?
Similar to linear kinetic energy, the moment of inertia and angular velocity can be used to express the kinetic energy of a rotating object. The translational kinetic energy of the center of mass and the rotational kinetic energy about the center of mass add up to the total kinetic energy of an extended object.
Using rotational kinetic energy
We know,
KE = [tex]\frac{1}{2}[/tex]Iω²
Where,
I = Moment of Inertia
ω = Angular Velocity
Putting values in the equation,
KE = [tex]\frac{1}{2}[/tex](0.057)(1.90)²
KE = 0.102 JT
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through what potential difference would the charged particles have to be accelerated to aquire the velocity of v0
Potential difference would the charged particles have to be accelerated to aquire the velocity of [tex]v[/tex] is [tex]{\frac{mv^{2} }{2q} }[/tex].
What is potential difference?The effort required to move a unit charge from one location to another in an electric field is known as the electrical potential difference. In other words, the electric potential difference between the two charged bodies is the definition of the potential difference.
The two bodies are said to have a potential difference when one of them is charged to a different electric potential than the other charged body. Both bodies are exerting maximum effort while under stress and tension.Volts are used to measure potential difference.
Since kinetic energy = [tex]\frac{mv^{2}} {2}[/tex]
Potential energy = qV
This kinetic energy is achieved by application of outside potential difference
Hence qV = [tex]\frac{mv^{2}} {2}[/tex]
Thus V = [tex]{\frac{mv^{2} }{2q} }[/tex]
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For what slit-width-to-wavelength ratio does the first minimum of a single-slit diffraction pattern appear at 30 ∘ ?
For a single-slit diffraction pattern observed at an angle of 30 ∘, the slit-width-to-wavelength ratio for the first minimum will be 1.41.
When a single-slit diffraction pattern is observed at 30 ∘, the Bratio for the first minimum will be 1.41.
This is determined by using the equation θ = sin−1(nλ/s),
where θ is the angle of observation, n is an integer (in this case, n=1), λ is the wavelength of the light wave, and s is the width of the slit.
If we plug in the given values of θ and n,
we get s/λ = 1.41.
Therefore, for a single-slit diffraction pattern observed at an angle of 30 ∘, the slit-width-to-wavelength ratio for the first minimum will be 1.41.
Diffraction is the spreading out of light or sound waves as they pass through a narrow opening. A single-slit diffraction pattern is a pattern of bright and dark fringes that appear when light passes through a single slit. The position of the first minimum of this pattern, which is the point at which the light intensity drops to its lowest, is determined by the slit-width-to-wavelength ratio.
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if the angular momentum of a system is constant, which of the following statements must be true? a) no torque acts on any part of the system. b) a constant torque acts on each part of the system. c) zero net torque acts on each part of the system. d) a constant external torque acts on the system. e) zero net external torque acts on the system
The Correct option is C. Zero net torque acts on each part of the system.
In Newtonian mechanics, momentum (extra especially linear momentum or translational momentum) is fabricated from the mass and velocity of an object. it's far a vector quantity, possessing a value and a course. If m is an item's mass and v is its pace (additionally a vector amount), then the object's momentum p is :P = mv.
In view that momentum has a route, it is able to be used to are expecting the resulting path and pace of movement of objects after they collide. underneath, the fundamental houses of momentum are defined in a single size. The vector equations are almost the same as the scalar equations. Momentum, a manufactured from the mass of a particle and its velocity. Momentum is a vector amount; i.e., it has both value and course. Isaac Newton's second law of motion states that the time rate of exchange of momentum is identical to the pressure acting on the particle. See Newton's laws of motion.
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When the electrostatic force overcomes the
of the nucleus, it is called radioactive decay.
Answer here
force in at least part
(Apex answer)
Answer:
strong force
Explanation:
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a bat at rest sends out ultrasonic sound waves at 50.0 khz and receives them returned from an object moving directly away from it at what is the received sound frequency?
The recieved sound frequency is 42.5 kHz.
What is frequency of sound?The way sound waves oscillate as they pass past our ears—alternating between compressing and expanding the medium, which is usually air—determines the sound frequency. All sound waves go through the same medium at the same pace. The Doppler Effect states that while a source or an observer is moving, the frequency of the sound wave varies. Echo is the term for a sound wave's reflection. It varies depending on the media.
Frequency of the sound due to reflection of an object moving away from the bat is given as
f = f' (v - v'/v + v')
v' = 27.5m/s
v = 340m/s
f' = 50KHz
Thus f = 50 (340- 27.5/340 + 27.5) = 42.5KHz
Hence the sound frequency received from the object is 42.5 kHz.
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Complete question is:
A bat at rest sends out ultrasonic sound waves at 50.0 kHz and receives them returned from an object moving directly away from it at 27.5 m/s. What is the received sound frequency?
Physics students use a spring scale to measure the weight of a piece of lead. The experiment was performed two times one in air the other in water. If the volume of lead is 50 cm3, what is the difference between two readings on the scale?.
The difference between the measure of weight of a piece of lead in air and water is due to the buoyancy force of water. Difference between the two readings on the scale is 50.
Volume of lead is ratio of the weight it to the density of the lead. Thus,
= V = W/ρ
The value of the density for the lead material is 11.3 g/cm cubed.
The volume of the lead = 50 cm³
The experiment was performed two times, once in the air and once in water. As the density of the lead is 11.3 gram per cm cubed, the weight of the lead is =
= W = V X ρ
= W = 11.3 X 50
= W = 565 g
Hence, the total weight of the piece of lead is 565 grams.
If the air force is negligible then the weight of the piece of lead is 565 grams when the experiment is done in the air with spring scale.
The density of the water is 1 gram per cubic centimetre of water and the buoyancy force applied by the water on the piece of lead with 50 cm³ volume is 50 g.
Thus, the weight of the piece of lead when the experiment is done in the water with spring scale is=
= W' = 565-50
= W' = 515 g
Thus, the weight of the piece of lead when the experiment is done in the water with spring scale is, 515 grams.
Difference between the two readings on the scale =
= 565 -515
= 50g
Hence, the difference between the two readings on the scale is 50g.
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a block of mass m is attached to a modified atwood machine and is accelerated upward at 3a by a constant force f0 . what is the weight of the block?
The weight of the block is Mg.
Upon the release of a tiny block with mass M from a,
A tiny block with mass m is launched from point A onto a fixed, smooth wedge. The block stops sliding at point C so because straight part of a floor is rough, which is marked as B at the bottom of the wedge.
When When an M-gram block is then,
An average kinetic potential energy contained in the wire when a block of mass M was suspended by the a coiled wire of length L is stress, strain, and volume. Justify its equality with Mgl, where l seems to be the extension. The mass earth system's Mgl loss of gravitational potential energy.
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